a bowling team consists of 34 members, and 18 are male. if 4 females leave the team, what percent of the remaining members are male?

Answer: 125 ft.

Step-by-step explanation:

Assuming the perimeter of the park is 400 ft, the equation can be represented as

2l + 2w = 400

Since we know that the width is 50 ft shorter than the length, using algebra, you replace the variable w, with

2l + 2(l-50) = 400

Then, solve for variable l, or length

2l +2l - 100 = 400

4l = 500

l = 125

Now, plug in l and solve for w

2(125) + 2w = 400

250 + 2w = 400

2w = 150

w = 75

2(125) + 2(75) = 400

250+150 = 400

400=400

l = 125, w = 75

So the length is 125 ft

Answer:

125

Step-by-step explanation:

400 is perimeter!

50+w = Length

w = width

Solve:

50+ w + w +w + w + 50 = 400

100 + 4w = 400

4w = 300

w = 75

if w is 75, then length is = 75 +50

Length = 125

Answer:

-5

Step-by-step explanation:

f(x)=x2-x

f(-5)=(-5)2-(-5)

f(-5)=-10-(-5)

f(-5)= -5

The answer choices and context provided do not allow for a specific answer or explanation.

The given prompt consists of several drop-down menus with incomplete options and missing context. Without the complete options or additional information about the triangle ABC, it is not possible to determine the values of sin(A), cos(A), or e. The values 40 and 41 seem to be potential side lengths of the triangle, but their relationship to the trigonometric functions or the variable e is unclear.

The prompt lacks necessary information to provide a meaningful answer or explanation. To provide a valid response, complete and relevant options or additional context regarding the triangle ABC and its properties would be required.

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The statement '15 more than the sum of 5 and a number' is equivalent to the mathematical expression (5+n)+15.

Therefore the answer is (5+n)+15.

The statement "15 more than the sum of 5 and a number" is asking for an expression that represents the value that is 15 greater than the result of adding 5 and a number together. The mathematical way to express this is:

15 + (5 + n)

Where n is the number that we are adding to 5.

15 is being added to the sum of 5 and n. The parentheses around the 5 and n indicate that those two values are being added together before the 15 is added to them.

In other forms of representation

15+(5-n) or (5+n)+15 or (5-n) +15 or 15+5n does not convey the meaning you want it to convey as these forms does not represent "15 more than the sum of 5 and a number"

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Answer:

96.6feet

Step-by-step explanation:

,

From the attachment, we can see that a triangle is formed.

From trigonometry,

Sin(X)= opposite/hypothesis

Where Opposite sides=25feet

Hypotenuse sides= X feet

Sin(15)= 25/X

Cross multiply

Sin(15)= 0.2588

0.2588=25/X

X= 25/0.2588

X=96.6feet

Hence, the wire is 96.6 feet high

CHECK THE ATTACHMENT FOR THE FIQURE.

Answer:

0.535

Step-by-step explanation:

The place value when rounded to 2 significant figure of this number is hundredth ( 0 . 5 3 )

Find the half of a hundredth.

0.01 ÷ 2 = 0.005

Now add 0.005 to 0.53

0.53 + 0.005 = 0.535

Upper bound = 0.535

The best linear approximation to the function f(x) = e^x near x = 0 is L(x) = x + 1.

The given function is f(x) = e^x near x = 0.

To find the best linear approximation, L(x), we use the formula:

L(x) = f(a) + f'(a)(x-a),

where a is the point near which we are approximating.

Let a = 0, so that a is near the point x = 0.

f(a) = f(0) = e^0 = 1

f'(x) = d/dx (e^x) = e^x;

so f'(a) = f'(0) = e^0 = 1

Substituting these values into the formula: L(x) = 1 + 1(x-0) = x + 1

Therefore, the best linear approximation to f(x) = e^x near x = 0 is L(x) = x + 1.

For instance, linear approximation is used to approximate the change in a physical quantity due to a small change in another quantity that affects it.

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Answer: The differential equations is

y3 3x3logx = 8x3.

Step-by-step explanation:

break the given original- value problem. The DE is homogeneous. xy2dy/ dx = y3- x3; y( 1) = 2.

result

Given a homogenous discriminational equation, xy2 dy/ dx = y3- x3

xy2dy/ dx = y3- x3

dy/ dx = ( y3- x3)/ xy2

dy/ dx = (( y/ x) 3- 1)/( y2/ x2)---( 1)

Put y/ x = v ⇒ y = xv

separatew.r.t x

dy/ dx = x.dv/ dx v

Equation( 1) becomes,

⇒ dv/ dx v = ( v3- 1)/ v2

⇒ dv/ dx = (( v3- 1)/ v2)- v

⇒ dv/ dx = ( v3- 1- v3)/ v2

v2. dv = -1/x.dx

Integrate on both sides, we get

∫ v2. dv = ∫- 1/x.dx

v3/ 3 = - logx C

1/3( y3/ x3)) log x = C( 2)

Now, given that y( 1) = 2

Substituting y = 2 and x = 1 in equation( 2)

(1/3) ×(23/13)) log 1 = C

C = 8/3

From equation( 2), we get

⇒( y3/ 3x3) logx = 8/3

thus, the needed differential equation is y3 3x3logx = 8x3.

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Data

• Morning: 156 times

• Lunch: x times

• Afternoon: 201 times

• Whole day: 562 times

Procedure

To know how many times did it ring at lunch, we have to build a relation, in which we know that the addition of the times in the morning, lunch, and afternoon equal the times it rang the whole day:

Then, we have to solve for x considering that it represents the times it rang during the lunch.

Answer: It rang 205 times during the afternoon.

Rounded to one decimal place, the average annual rate for Australia's kangaroo population is -23.1%. So, the population of kangaroos has been decreasing at an average annual rate of 23.1% per year.

To determine the average annual rate of change, we need to find the difference in the population between 2001 and 2011 and divide that by the number of years (2001 - 2011 = 10 years).

The difference in population between 2001 and 2011 is: 57,430,030 - 34,303,680 = 23,126,350

To get the average annual rate of change, we divide that difference by the number of years: 23,126,350 ÷ 10 = 2,312,635

To convert the annual rate to a percentage, we multiply by 100: 2,312,635 x 100 = 231,2635%

Rounded to one decimal place, the average annual rate for Australia's kangaroo population is -23.1%.

Compound interest is the interest on a loan or deposit calculated based on both the initial principal and the accumulated interest from previous periods. It is the interest on a deposit that is calculated not only on the initial principal, but also on the accumulated interest from previous periods. In other words, it refers to the interest on a loan or deposit, where the interest is added to the principal, so that interest is also earned on the interest for the next period.

This results in the interest compounding, or growing at an accelerating rate over time, as the interest earned in each period is added to the principal, and the interest is calculated on the new, higher principal amount. Compound interest is different from simple interest which is only calculated on the original principal.

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Using the probability concept, the proportion of times do we expect the practitioner to guess the correct hand is of 0.44.

The probability of an event in an experiment is calculated as the number of desired outcomes of the experiment divided by the number of total outcomes of the experiment.

The probability can be interpreted as the proportion of times that we expect a trial to happen.

In the context of this problem, this probability is of 44%, as stated for Emily's model, that is, out of 100 trials, the correct answer was obtained in 44 of them, hence the proportion of times do we expect the practitioner to guess the correct hand is of 0.44.

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The best diagram to use to display data dispersion is a box plot. A box plot is a diagram that shows how a dataset is distributed and helps to identify any outliers.

The diagram that is best at displaying data dispersion is a box plot. Here's the main answer:When there is a need to compare the distribution of data, a box plot is often the best method.

A box plot is a diagram that shows how a dataset is distributed. It shows how data is spread out and helps to identify any outliers. It is most effective for comparing data sets that have a large number of data points and when the data is not normal (not evenly distributed).

A box plot is a great way to summarize large amounts of data and it is also very easy to read and interpret. It shows a number of statistical values, including the median (the middle value of the data set), the quartiles (the values that divide the data set into four equal parts) and the range (the difference between the maximum and minimum values).

Additionally, it can identify any outliers in the data, which are values that are significantly different from the rest of the data.A box plot is created by drawing a rectangle between the first and third quartiles (the middle 50% of the data) with a line drawn inside it to show the median.

Lines are then drawn from the edges of the rectangle to the minimum and maximum values. Any outliers are marked with a point outside of the rectangle.

The box plot is a great way to compare data sets and to visualize the dispersion of the data

The best diagram to use to display data dispersion is a box plot. A box plot is a diagram that shows how a dataset is distributed and helps to identify any outliers. It is most effective for comparing data sets that have a large number of data points and when the data is not normal. A box plot is created by drawing a rectangle between the first and third quartiles with a line drawn inside it to show the median.

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Answer:

C

Step-by-step explanation:

The Scale factor was used to enlarge the picture is 7/ 31.5.

A scale factor is a numerical value that can be used to alter the size of any geometric figure or object in relation to its original size. It is used to find the missing length, area, or volume of an enlarged or reduced figure as well as to draw the enlarged or reduced shape of any given figure. It should be remembered that the scale factor only affects how big a figure is, not how it looks.

Given:

A picture is 7 inches wide and 9 inches long.

A photographer enlarges it so it is 31.5 inches wide and 40.5 inches long.

So, scale factor is

= Original dimension / Enlarged dimension

= 9/ 40.5

= 90/ 405

= 10/45

= 2/9

Now, simplifying the scale factor 7/31.5 because it has Nr < Dr.

= 7/ 3.15

= 70/31.5

= 2/9

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Answer:

x = 23

Step-by-step explanation:

if line j is parallel to line k then

5x + 9 + 33 + x = 180 add like terms

6x + 42 = 180 subtract 42 from both sides

6x = 138 divide both sides by 6

x = 23

The value of x is 11, and the value of FH is 38

A rectangle is a quadrilateral that has 4 straight lines, of which the opposite sides are parallel.

The given parameters are:

\(EI = 3x + 5\)

\(FH = 5x - 17\)

To calculate the value of x, we make use of:

\(FH =EI\) ---- the opposite sides of the rectangle

So, we have:

\(5x - 17 = 3x + 5\)

Collect like terms

\(5x -3x = 5+17\)

\(2x = 22\)

Divide both sides by 2

\(x = 11\)

Substitute 11 for x in \(FH = 5x - 17\)

So, we have:

\(FH = 5 \times 11 - 17\)

\(FH = 38\)

Hence, the value of x is 11, and the value of FH is 38

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Answer:

b

5

​

b

2

​

​

=

4

1

​

⇒

ar

4

ar

​

=

4

1

​

Where a is the first term & r is the common ratio.

⇒

r

3

1

​

=

4

1

​

⇒r

3

=4

⇒r=

3

4

​

=4

3

1

​

And,b

2

​

+b

5

​

=216

⇒ar+ar

4

=216

⇒ar(1+r

3

)=216

Replacing, r=4

3

1

​

⇒ar[1+(4

3

1

​

)

3

]=216

⇒ar[1+4]=216

⇒ar=

5

216

​

⇒a=

5r

216

​

=

5

3

4

​

216

​

∴ The first term is  5 34

​

216

​

The value of x is \( \frac{1}{4} \)

Step-by-step explanation:

Given:

\( \sqrt{x} + \sqrt{x + 2} = 2\)

Rearranging the radical on left side,

\(\sqrt{x + 2} = 2 - \sqrt{x}\)

Power on both sides,

\((\sqrt{x + 2})^{2} = (2 - \sqrt{x})^{2} \)

Simplifying the left,

\(x + 2 = (2 - \sqrt{x} )^{2}\)

For the RHS equation, use the property of (a-b)² = (a²-2ab+b²),

\( = > x + 2 = {2}^{2} - (2 \times 2 \sqrt{x}) + ( \sqrt{x})^{2} \)

Now calculating its powers,

\( = > x + 2 = 4 - 4\sqrt{x} + x\)

Now sending -4√x to the LHS (left side), its sign becomes plus (+),

\( = > 4 \sqrt{x} = 4 + x - x - 2\)

Now the +x and -x will be cancelled,

\( = > 4 \sqrt{x} = 4 - 2\)

\( = > 4 \sqrt{x} = 2\)

Bringing 4 to the right side, it becomes the denominator,

\( = > \sqrt{x} = \frac{2}{4} \)

\( = > \sqrt{x} = \frac{1}{4} \)

Now powering both sides,

\( = > ( \sqrt{x})^{2} = ( \frac{1}{2})^{2}\)

\( = > x = \frac{1}{4} \)

Answer:

A statistical question is a question that can be answered by collecting data that vary. For example, “How old am I?” is not a statistical question, but “How old are the students in my school? and "how old are you?" are statistical questions.

Step-by-step explanation:

the measurement of the short side of the rectangle is approximately 8.09 cm.

Let's assume that the rectangle's sides are x and y, where x is the short side and y is the long side. We know that the area of the rectangle is 106.92 cm², so we can write:

x * y = 106.92

We also know that the long side measurement is 13.2 cm, so we can substitute y with 13.2 in the equation above:

x * 13.2 = 106.92

Solving for x, we get:

x = 106.92 / 13.2

x = 8.09

Therefore, the measurement of the short side of the rectangle is approximately 8.09 cm.

To explain this solution in 200 words, we can say that the area of a rectangle is equal to the product of its length and width. In this case, we are given the area and the length of the rectangle, but we need to find the width (short side). We use the formula for the area of a rectangle to write an equation in terms of the unknown width and the known length. Then, we substitute the known length with its value and solve for the unknown width. The resulting value is the measurement of the short side of the rectangle.

It's important to note that in some cases, there may be multiple possible solutions for the width of the rectangle, depending on the dimensions of the rectangle. However, in this particular case, there is only one possible solution, as the length and area of the rectangle are fixed.

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Answer:

The answer is C. Quadrant 3.

Step-by-step explanation:

Looking up a Unit Circle. We can see that 5pi/4 is in quadrant 3.

5pi/4 is also if in degree angle as 225°

Answer:

8

Step-by-step explanation:

15 of 75 estimated raccoons in the area were tagged. So think of this as a ratio, 15:75.

Divide 75 by the 40 racoons that were captured and you get 1.87500. 75 divided by 1.87500 is the 40 raccoons captured. So 15 divided by the same amount is the number of raccoons with tags. Divide 15 by 1.87500 to find the missing value, which is 8.

Both homotopy invariants of braided commutative algebras and the Deligne conjecture for finite tensor categories are active areas of research, with ongoing investigations and developments by mathematicians in their respective fields.

Homotopy invariants of braided commutative algebras and the Deligne conjecture for finite tensor categories are two separate topics within algebraic topology and category theory, respectively. Let's briefly discuss each of them:

Homotopy invariants of braided commutative algebras:

In algebraic topology, a braided commutative algebra is an algebraic structure that combines the properties of braided monoidal categories and commutative algebras. It is a type of algebraic structure that arises in the study of topological and geometric objects. Homotopy invariants are algebraic invariants that capture topological properties and remain unchanged under continuous deformations known as homotopies. Homotopy invariants are important tools in the classification and study of topological spaces and algebraic structures.

The Deligne conjecture for finite tensor categories:

The Deligne conjecture is a mathematical conjecture in the field of category theory, specifically related to tensor categories. It was formulated by Pierre Deligne and addresses the existence of certain natural isomorphisms in finite tensor categories. The conjecture states that for a finite tensor category, certain higher coherences (i.e., isomorphisms between isomorphisms) hold. These higher coherences are crucial for understanding the behavior and structure of tensor categories, which are mathematical structures that generalize the concept of a vector space.

The Deligne conjecture has important implications for various areas of mathematics, including representation theory, algebraic geometry, and mathematical physics. It has been extensively studied and has connections to other important conjectures and results in category theory and related fields.

Both the Deligne conjecture for finite tensor categories and the homotopy invariants of braided commutative algebras are active areas of research, with ongoing studies and developments by mathematicians in their respective domains.

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Answer:

3^4=81 and 3^5= 243 and 243 x 81 is 19,683

 10,000+9,000+600+80+3  

The primary code we use to signal identity, according to Remland, is nonverbal communication.

Nonverbal communication refers to the transmission of messages without the use of words. It involves various forms of communication such as facial expressions, body language, gestures, posture, eye contact, and tone of voice. Remland, a researcher in the field of communication, emphasizes the significance of nonverbal cues in signaling identity.

Nonverbal cues play a crucial role in expressing our cultural, social, and personal identities. They can convey information about our emotions, attitudes, status, and affiliations. For example, the way we dress, our choice of accessories, and our body language can communicate aspects of our identity such as our gender, social group, or profession.

Nonverbal communication is particularly powerful because it often operates at an unconscious level and can convey messages that are difficult to express through words alone. These nonverbal signals can shape impressions, establish connections, and influence how others perceive and respond to us.

According to Remland, nonverbal communication is the primary code we use to signal identity. Understanding and interpreting nonverbal cues are essential for effective communication and for navigating social interactions, as they provide valuable insights into the identities and intentions of individuals.

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The answers to the questions involving trigonometry are: 90, BC/AB ÷ BC/AB = 1, g = 6.5, <I = 62 degrees, h= 13.8, 12.0, x = 6.8, x = 66.4, 160.6, The pole = 6.7

Trigonometric ratios are special measurements of a right triangle, defined as the ratios of the sides of a right-angled triangle.  There are three common trigonometric ratios: sine, cosine, and tangent

For page 3 question 3,

a) <A + <B = 90 since <C = right angle

b) SinA = BC/AB and CosB = BC/AB

The ratio of the two angles BC/AB ÷ BC/AB = 1

I notice that the ratio of sinA and cosB gives 1

b) The ratio of CosA and SinB will give

BC/AB ÷ BC/AB

= BC/AB * AB/BC = 1

For page 5 number 3

Tan28 = g/i

g/12.2 = tan28

cross multiplying to have

g = 12.2*tan28

g = 12.2 * 0.5317

g = 6.5

b) the angle I is given as 90-28 degrees

<I = 62 degrees

To find the side h we use the Pythagoras theorem

h² = (12.2)² + (6.5)²

h² = 148.84 +42.25

h²= 191.09

h=√191.09

h= 13.8

For page 6

1) Sin42 = x/18

x=18*sin42

x = 18*0.6691

x = 12.0

2) cos28 = 6/x

xcos28 = 6

x = 6/cos28

x [= 6/0.8829

x = 6.8

3)  Tan63 = x/34

x = 34*tan63

x= 34*1.9526

x = 66.4

4) Sin50 123/x

xsin50 = 123

x = 123/sin50

x = 123/0.7660

x =160.6

5)  Sin57 = P/8

Pole = 8sin57

the pole = 8*0.8387

The pole = 6.7

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