a bouncy ball is released from a height h and rebounds after hitting the ground to a height \frac{3}{4}h 4 3 ​ startfraction, 3, divided by, 4, end fraction, h. what is true about the collision with the ground?

Answer:

First of all, what is acceleration? — Acceleration is the rate of change of velocity per unit of time.

Now, we know that velocity is a vector quantity i.e we need both magnitude and direction to define it and so is acceleration. We can now say that in acceleration, the direction of motion is very important or to define acceleration we need both the magnitude of motion (here it is the speed) and its direction.

Now coming to your question. There are two possible answers to this question.

more

,Case 2 — When the body is not moving in a straight line or is constantly changing its direction. In this cas the speed still is constant but the direction is constantly changing, for example in the case of a circular motion the direction of motion constantly changes (the direction of a moving body in a circular path at any point is the direction of the tangent of the circle at that point). Hence the velocity changes as the body move along the circular or curved path.

Now, as  I earlier mentioned to define acceleration we need to know it's magnitude and it's direction, and acceleration is the rate of change of velocity per unit of time — the speed remaining constant the direction constantly changing, and the velocity changes at different time intervals or rate of change of velocity is ≠ 0 unlike in case 1. Since there is the of and a change in velocity (speed constant but the direction is changing) there is some acceleration.

To sum everything up — in the case of linear motion i.e motion in a straight line when the speed is constant and direction is not changing, velocity will be zero and hence acceleration would be zero. In case of a non-linear motion i.e motion not in a straight line, in a circle or any path where the speed is constant but the direction is constantly changing, velocity will not be zero and hence the acceleration would not be equal to zero. Either it would be greater or less than zero.

Answer: B

Explanation:

Answer:

\(50\:\mathrm{m\: North}\\50\sqrt{3}\:\mathrm{m\: East}\)

Explanation:

We can create a 30-60-90 triangle. The distance she walked is then the hypotenuse of the triangle, and using 30-60-90 triangle rules, we have the following:

The North leg is opposite to the \(30^{\circ}\) angle. Therefore, if we call this distance \(y_N\), we have the following:

\(\sin 30^{\circ}=\frac{y_N}{100},\\\frac{1}{2}=\frac{y_N}{100},\\y_N=\fbox{$50\:\mathrm{m}$}\).

The East leg is opposite to the \(60^{\circ}\\\) angle. If we call this distance \(x_E\), we have:

\(\sin 60^{\circ}=\frac{x_E}{100},\\\frac{\sqrt{3}}{2}=\frac{x_E}{100},\\x_E=\fbox{$50\sqrt{3}\:\mathrm{m}$}\).

Answer:

636.4 J

Explanation:

The potential energy between one of the charges at the corner of the square and the fifth identical charge is U = kq²/r where q = charge = +50 × 10⁻⁶ C  and r = distance from center of square. = √2 m (since the midpoint of the sides = 1 m, so the distance from the charge at the corner to the center is thus √(1² + 1²) = √2)

Since we have four charges, the additional potential energy to move the charge to the centre of the square is U' = 4U = 4kq²/r

U' = 4kq²/r

= 4 × 9 × 10⁹ Nm²/C² (+50 × 10⁻⁶ C)²/√2 m

= 900 Nm²/√2 m

= 636.4 J

The total external energy required is 636.4 J.

According to the question, a square of side a = 2m has 4 identical charges on the corners with charge Q = 50×10⁻⁶C.

A fifth identical charge is brought at the geometric center of the square. The geometric center is at the center of the diagonal:

\(r=\frac{a}{\sqrt{2} }=\sqrt{2}\;m\)

The potential energy is a state function which means that it depends on the initial and final position.

Now the energy required is equal to the change in potential energy

\(\Delta U=\frac{1}{4\pi\epsilon_o}\frac{4Q^2}{r}\\\\\Delta U=\frac{4\times9\times10^9\times(50\times10^{-6})^2}{\sqrt{2} } \\\\\Delta U=636.4\;J\)

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Answer:The electrostatic force is directly related to the product of the charges and inversely related to the square of the separation distance.

Explanation:

The galactic halo or corona is believed to contain mostly dark matter.

Dark matter is a hypothetical form of matter that does not interact with light or electromagnetic radiation, making it difficult to directly detect and observe. However, its presence is inferred through its gravitational effects on visible matter.

Observations and simulations suggest that galaxies, including our Milky Way, are embedded in large halos of dark matter. These halos extend well beyond the visible regions of the galaxies and are thought to contribute significantly to their total mass. The galactic halo or corona refers to the outer regions of a galaxy where the density of stars and gas is much lower compared to the central region.

The dominant presence of dark matter in the galactic halo is deduced from measurements of the rotational velocities of stars and gas in galaxies. The observed velocities indicate that there is more mass present than can be accounted for by visible matter alone. Dark matter is believed to play a crucial role in providing the gravitational pull required to explain the observed motions of stars and galaxies.

While the exact nature of dark matter remains unknown, it is thought to be a fundamental component of the universe, constituting a significant portion of its mass.

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Note- The complete question is

What is believed to be the main component or composition of the galactic halo or corona?

The highest order dark fringe for a 561 nm light incident on a 1420 nm wide slit is the 3rd order.

Diffraction occurs when light passes through a narrow opening or slit, causing the wave to bend and interfere with itself. The pattern of bright and dark fringes produced by this interference is called a diffraction pattern. The position of these fringes can be determined using the equation d sin θ = mλ, where d is the width of the slit, θ is the angle of diffraction, m is the order of the fringe, and λ is the wavelength of the light.

Using this equation, we can calculate that the 3rd order dark fringe corresponds to an angle of approximately 5.68 degrees for a 561 nm light incident on a 1420 nm wide slit. Therefore, the highest order dark fringe in this situation is the 3rd order.

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Answer:

(b) A convex mirror can form a magnified real image.

Explanation:

A convex mirror only forms diminished/highly diminished, virtual and erect image.

Hope it helps.

The correct answer is :

Mirror Parabola A mirror with a parabola-shaped reflecting surface is referred to as a parabolic mirror. The mirror is employed in search lights because it can precisely converge a broad parallel beam of light at the focus. Therefore, even at a great distance, the intensity of the reflected beam is unaffected.

Parabolic In search lights, concave mirrors with sizable apertures are utilized. For searching items in search light, we require a powerful parallel beam of light. The reflected rays from an object placed at a concave mirror's focus are parallel to one another and likewise parallel to the main axis. So, we position a light source at the concave mirror's focal point.

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To create a scenario where a marble causes a cup to slide equally as far as a gold ball, several factors need to be taken into account:

1) Surface friction

2) Initial velocity

3) Size and weight

To create a scenario where a marble causes a cup to slide equally as far as a gold ball, several factors need to be taken into account:

Surface friction: Ensure that both the marble and the gold ball are placed on a surface with the same level of friction. This can be achieved by using a uniform and smooth surface, such as a wooden table.

Initial velocity: Give the marble an initial velocity that matches the velocity of the gold ball. This can be done by placing both objects at the same height and giving them a push or releasing them from the same height simultaneously.

Size and weight: Ensure that the marble and the gold ball have similar size and weight. This can be achieved by using marbles and gold balls of similar dimensions and weights. By carefully controlling these factors, such as surface friction, initial velocity, and size and weight of the objects, it is possible to create a scenario where the marble causes the cup to slide equally as far as the gold ball caused it to slide.

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Answer:

Explanation: Afdjkldjf

Gamma rays widely used in medical sector mostly in radio pathy and scientific research laboratories for sterilization.

Define gamma rays:

Electromagnetic energy which is emitted after disintegration or decaying of two different radioactive nuclei is considered as gamma rays.

Uses of gamma rays:

Gamma rays have high penetration power with particular matter and go through ionization process mostly by photoelectric effect. The impact of gamma rays can be hazardous upon human body due to high penetration and increases health risk.

Gamma rays mostly used for sterilization process which mostly use to destroy microorganism and sterilize the surgical equipment and different laboratory equipment. Food industries also use this ray to maintain quality and hygiene of food.

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The momentum of the kid weighing 30kg is 210kgm/s.

Momentum in physics refers to the tendency of a body to maintain its inertial motion i.e. the product of its mass and velocity, or the vector sum of the products of its masses and velocities.

According to this question, a 30kg kid on a bike is moving in the positive direction at 7 m/s. The momentum is calculated thus;

Momentum = 30kg × 7m/s = 210kgm/s

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In conclusion, when a point particle collides with a uniform stick on a frictionless horizontal surface, the common velocity of the stick and the particle after the collision can be determined using the equation v' = mv / (m + M).

In this scenario, we have a uniform stick with length l and mass m placed on a frictionless horizontal surface. A point particle of mass m is approaching the stick with a speed v on a straight line that is perpendicular to the stick and intersects it at one end.
When the particle collides with the stick, momentum is conserved. This means that the total momentum before the collision is equal to the total momentum after the collision.
Since the stick is initially at rest, its momentum is zero.

Therefore, the momentum of the particle before the collision is mv.
After the collision, both the stick and the particle will move together as a single system.

Let's assume that the stick and particle move with a common velocity v'. By applying the conservation of momentum, we have:
mv = (m + M) * v'
Here, M represents the mass of the stick.
We can rearrange this equation to solve for v':
v' = mv / (m + M)
This equation shows that the common velocity of the stick and particle after the collision is determined by the mass of the particle, the mass of the stick, and the initial velocity of the particle.
In conclusion, when a point particle collides with a uniform stick on a frictionless horizontal surface, the common velocity of the stick and the particle after the collision can be determined using the equation v' = mv / (m + M).

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A.

Smooth-skinned earthworms have a body made up of numerous tiny segments. The lines designating the segments are visible on the body. Each segment possesses tiny, stiff hairs that aid in the worm's movement; occasionally, the hairs are difficult to perceive. They lack a skeleton yet have a large number of muscles.

B.

Because they lack lungs, earthworms breathe through their skin. For dissolved oxygen to enter their bloodstream, their skin must be damp. The mucus-coated skin of earthworms makes them dependent on a wet, moist environment to survive.

C.

The earthworm's characteristic crawling movement is caused by the action of muscles in the body wall. These lengthen and shorten the body in wavelike motions. Four pairs of tiny hard bristles on each segment help the worm grip the ground and hold onto the side of the burrow.

D.

Blackbirds, robins, and song thrushes are ground feeders, and for them, a worm is the only food that compares to it in taste. Large eyes and powerful bills let all of them to see in the early morning light, when earthworms are most active close to the surface. Their strong bills also allow them to pull struggling earthworms from the soil.

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The probability of the stops including Boston and Chicago is 1/100 when an airline tracks each of its airplanes' stops for the day.

To calculate the probability of an airplane making stops in both Boston and Chicago, we need to know the total number of possible cities that the airplane can stop in. Let's say there are 10 possible cities.
The probability of the airplane stopping in Boston on any given stop is 1/10 (since there are 10 possible cities). The same goes for Chicago.
To calculate the probability of the airplane stopping in both Boston and Chicago, we need to multiply the probabilities of each stop. So, the probability of the airplane stopping in both Boston and Chicago on any given day is:
1/10 * 1/10 = 1/100

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Answer: 17 hours

Explanation:

The position of the center of mass of the Earth-Moon system is located 4,676 kilometers from the center of the Earth.

First, let us recall the formula for the center of mass, which is:

center of mass = (m1r1 + m2r2)/(m1 + m2)

where,

m1 and m2 are the masses of the two objects

r1 and r2 are their distances from the reference point

Earth: m1 = 5.97 x 10^24 kg,

r1 = 0 km

Moon: m2 = 7.35 x 10^22 kg,

r2 = 384,400 km (3.84 x 10^8 m)

We can ignore the radii of the two objects because they are negligible compared to their orbital radii. So the center of mass of the Earth-Moon system can be calculated as follows:

center of mass = (m1r1 + m2r2)/(m1 + m2)

= [(5.97 x 10^24 kg)(0 km) + (7.35 x 10^22 kg)(3.84 x 10^8 m)]/(5.97 x 10^24 kg + 7.35 x 10^22 kg)

= 4.67 x 10^6 m or 4,676 km from the center of the Earth

Therefore, the position of the center of mass of the Earth-Moon system is located 4,676 kilometers from the center of the Earth.

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The length of the rubber band that the boy must use is 0.024 m or 24 mm.

To determine the length of the rubber band, we can use the formula for the potential energy stored in a stretched spring, which is also applicable to a stretched rubber band:

where U is the potential energy stored in the rubber band, k is the spring constant (or in this case, the rubber band constant), and x is the displacement of the rubber band from its natural length.

Since the rubber band is stretched by 0.25 of its natural length, the displacement x is 0.25 times the natural length of the rubber band.

We can solve for the rubber band constant k by using the formula for the velocity of a projectile launched by a spring (or in this case, a rubber band):

where v is the velocity of the projectile, m is the mass of the rubber band, M is the mass of the projectile, and k is the spring constant. We can rearrange this equation to solve for k:

k = (v² M) / (2 m)

We can now combine the two equations to solve for the length of the rubber band, L:

U = 1/2 k x²

U = 1/2 ((v² M) / (2 m)) (0.25 L)²

U = (v² M L²) / (32 m)

The potential energy stored in the rubber band must be equal to the kinetic energy of the projectile when it is launched:

U = 1/2 M v²

(v² M L²) / (32 m) = 1/2 M v²

L = ((16 m v²) / (k M))

L = ((16 m v²) / ((v² M) / (2 m) M))

L = √(32 m^2 / M)

L = (0.032 M)

Substituting the given values, we get:

L = √(0.032 * 0.006)

L = 0.024 m

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which of the following is a vector quantity?

Weight is the only quantity that is vector among the others. Power, density, volume all are scalar quantities.

Weight is a scalar quantity because it has a direction. Weight is the force applied by earth on an object. Now, the force must have a direction so it is a vector quantity!!~

Answer:

D) The weight of an elephant

Explanation:

Weight, acceleration, and velocity are all considered vector quantities because gravitational forces of the Earth are required to push them in certain directions. Always remember:

\(\displaystyle Vector \hookrightarrow Speed\:AND\:Direction \\ Scalar \hookrightarrow Speed\)

I am joyous to assist you at any time.

Diamond at 20°C is expected to have the greatest index of refraction.

The index of refraction is a property that describes how light propagates through a medium. It is a measure of how much the speed of light is reduced when passing through a particular material. The higher the index of refraction, the slower light travels through that material.

Among the given options, diamond is known for having a very high index of refraction. This is due to its dense molecular structure and high refractive index value, which is approximately 2.42. Diamond's unique crystal lattice and high optical density result in a substantial bending of light as it passes through the material.

Carbon dioxide at 0°C, liquid water at 20°C, and other materials generally have lower indices of refraction compared to diamond. While carbon dioxide and liquid water can refract light to some extent, their refractive indices are significantly lower than that of diamond.

Among the given options, diamond at 20°C is expected to have the greatest index of refraction. Its dense molecular structure and high refractive index value allow for a significant bending of light as it passes through the material.

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Answer:

Because they have already made an impact within our atmosphere

Answer:

Go ogle

Explanation:

lol :)))))))))))))))

The effective resistance  of a car's starter motor is: Resistance = 0.0729 Ω

Using Ohm's law, we can find the effective resistance of the car's starter motor. Ohm's law states that resistance is equal to voltage divided by current.

\(Resistance = Voltage / Current\\Resistance = 10.5 V / 144 A\\Resistance = 0.0729\ ohm\)

Therefore, the effective resistance of the car's starter motor is 0.0729 Ω. This means that the starter motor will draw a large amount of current from the battery when it is running, but only a small voltage is required to keep the current flowing through the motor. The low resistance of the starter motor allows it to draw a large amount of power from the battery, which is necessary to turn the engine over and start the car.

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The power dissipated by the bathroom heater is 1.26 kW or 1260 W.

Given data:
1. Current (I) = 10.5 A
2. Potential difference (V) = 120 V

Unknown:
1. Power (P)

Equation used: P = IV

Now, let's solve the problem step-by-step:

Step 1: Recall the formula for power, which is P = IV.

Step 2: Plug in the given values for current (I) and potential difference (V) into the equation.

P = (10.5 A) × (120 V)

Step 3: Perform the multiplication to calculate the power.

P = 1260 W

Step 4: Check the significant digits. Both given values have three significant digits, so our answer should also have three significant digits.

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Answer:

9.6 minutes

Explanation:

We have that it takes Claire \(t=0.16h\) amount of time to get to school

\(t=0.16h\)

From the Question we are told that

Velocity\(v= 25 km/h.\)

Distance \(d=4km\)

Generally the equation for Time  is mathematically given as

\(v=\frac{d}{t}\\\\t=\frac{4}{25}\\\\t=0.16h\)

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Answer:

Georgium Sidus

Explanation:

Because he wanted to name it after King George three I am pretty sure

Answer: 660 N.

Explanation: Force on a free falling body is F=mg.

Therefore, Force =66×10 =660

(g is gravitational acceleration, taking it as 10)

If a mountain goat starts a rock slide and the rocks crash down the slope 100 m. If the rocks reach the bottom in 5 s, then the acceleration of the rock would be 8 meters/second².

The rate of change of the velocity with respect to time is known as the acceleration of the object.

As given in the problem a mountain goat starts a rock slide and the rocks crash down the slope 100 m. If the rocks reach the bottom in 5 s,

initial velocity of rock = 0 m/s

displacement = 100 meters

time = 5 seconds

s = ut + 0.5at²

100 = 0 + 12.5a

a = 100/12.5

  = 8 meters/second²

Thus, the acceleration of the rock would be 8 meters/second².

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Sternberg might argue that Sophie has (b) "practical intelligence" or "tacit knowledge" that is not typically assessed on traditional measures of intellectual functioning.

According to Robert J. Sternberg's theory of intelligence, there are different forms of intelligence beyond the traditional measures of intellectual functioning, such as IQ tests. One of these forms is practical intelligence, also known as "street smarts" or "common sense." Practical intelligence involves the ability to adapt, solve real-life problems, and navigate complex and dynamic situations effectively.

In the given scenario, Sophie's ability to work around impediments, rise above obstacles, and adapt to demanding environments demonstrates practical intelligence. Her capacity to apply her knowledge and skills in practical and real-world situations goes beyond the scope of traditional measures of intellectual functioning, which primarily assess cognitive abilities and academic knowledge.

Therefore, Sternberg might argue that Sophie possesses practical intelligence, allowing her to succeed in challenging environments where adaptability and problem-solving skills are crucial, even if those abilities may not be captured by conventional measures of intellectual functioning.

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Complete question :

Sophie has the ability to work around impediments, rise above obstacles, and adapt to the most demanding environments. Sternberg might argue that Sophie has ________________ intelligence, which is not assessed on traditional measures of intellectual functioning.

a. analytical

b. practical

c. creative

d. logical-mathematical

Answer:

\(0.361\ \text{m}\)

Explanation:

\(f_s\) = Frequency of source = 375 Hz

\(\Delta f\) = Difference between the maximum and minimum sound frequencies = 2.75 Hz

v = Speed of sound in air = 343 m/s

T = Time period = 1.8 s

\(v_m\) = Maximum speed of the microphone

We have the relation

\(\Delta f=2f_s\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f_s}\\\Rightarrow v_m=\dfrac{2.75\times 343}{2\times 375}\\\Rightarrow v_m=1.26\ \text{m/s}\)

Amplitude is given by

\(A=\dfrac{v_mT}{2\pi}\\\Rightarrow A=\dfrac{1.26\times 1.8}{2\pi}\\\Rightarrow A=0.361\ \text{m}\)

The amplitude of the simple harmonic motion is \(0.361\ \text{m}\).