The time taken for the boat to reach the dock is 2.19 s
Data obtained from the questionFrom the question given above, the following data were obtained:
Initial velocity (u) = 0 m/sDistance (s) = 12 mAcceleration (a) = 5 m/s² Time (t) = ?How to determine the timeThe time taken for the boat to reach the dock can be obtained as illustrated below:
s = ut + ½at²
12 = (0 × t) + (½ × 5 × t²)
12 = 0 + 2.5t²
12 = 2.5t²
Divide both side by 2.5
t² = 12 / 2.5
Take the square root of both side
t = √(12 / 2.5)
t = 2.19 s
Thus, the time taken is 2.19 s
Learn more about acceleration:
https://brainly.com/question/491732
Learn more about velocity:
https://brainly.com/question/3411682
#SPJ1
NEED HELP NOW
A picture of a person pulling a sled by a rope at an angle. A child is sitting on the sled. A free body diagram with 5 force vectors. The first vector is pointing downward, labeled F Subscript g Baseline = 58.8 N. The second vector is pointing right, labeled F Subscript f Baseline = 1.5 N. The third vector is pointing upward. The fourth vector is pointing left, labeled F Subscript p x Baseline. The fifth vector is pointing up to the left at an angle of 30 degrees, labeled F Subscript p Baseline = 10 N. The upward vector is shorter than the downward vector. The right vector is shorter than the left vector. Another vector starts at the tip of the left vector and points up to the tip of the 30 degree vector using the tip to tail method.
The force diagram represents a girl pulling a sled with a mass of 6.0 kg to the left with a force of 10.0 N at a 30.0 degree angle. There is a 1.5 N force of friction to the right. The force of gravity is 58.8 N.
What is the normal force acting on the sled? Round the answer to the nearest whole number. N
What is acceleration of the sled? Round the answer to the nearest tenth. m/s2
Answer:
54N, -1.2m/s^2
Explanation:
Edge
(sorry for lateness)
2kg watermelon is dropped from a 4m tall roof. how fast will the watermelon be moving as it strikes the ground below?
Scribes wrote on clay tablets with a/an ___________.
Scribes in ancient times wrote on clay tablets with a stylus, which was a sharp, pointed tool made from materials such as reed or bone.
The stylus was used to make impressions or incisions in the clay, which would then be dried in the sun or baked in a kiln to create a permanent record. Clay tablets were used extensively in ancient Mesopotamia, Egypt, and other cultures around the world, and were used for a variety of purposes including administrative records, legal documents, religious texts, and literature. Because clay tablets were durable and could withstand the elements, they have provided valuable insights into the lives and cultures of ancient societies.
The clay tablets were prepared by kneading and flattening wet clay, which provided a smooth surface for writing. Scribes then used the stylus to press symbols into the clay, forming lines of text. Once the writing was completed, the clay tablet would be left to dry in the sun or baked in a kiln to harden, making the text permanent. These clay tablets served various purposes, including record-keeping, communication, and literature, and have provided valuable insights into ancient societies and their way of life.
learn more about Scribes here
https://brainly.com/question/29523920
#SPJ11
the ratio of a substance's weight, especially a mineral, to an equal volume of water at 4°c is called its
The ratio of a substance's weight, especially a mineral, to an equal volume of water at 4°C is called it's specific gravity or relative density.
Specific gravity is the ratio of the density of a substance to the density of a reference substance, usually water. In simple terms, specific gravity is the density of a substance compared to the density of water. It's a dimensionless amount since it's a ratio. It is frequently used in geology to compare the densities of minerals to those of water.
Specific gravity is calculated by dividing the density of a substance by the density of water. The specific gravity formula is given by:
Specific gravity = (density of substance)
(density of water)The specific gravity of a substance can be calculated by comparing its weight to the weight of an equal volume of water at a particular temperature, such as 4°C.
To know more about geology please refer to:
https://brainly.com/question/29797074
#SPJ11
Discovering outer space had been an ancient goal of humanity. The first rocket launched ever was by the
American college professor and scientist Robert Goddard who built and flew the world's first liquid propellant
rocket on March 16, 1926. Its flight, though unimpressive (it climbed only 12.5 meters), was the forerunner of
the Saturn V Moon rocket 43 years later. Answer the following question using your math and science skills.
While launching a rocket into space, the rocket thrust (force) is calculated to be 20,000 N.
OOD
a) The mass of the rocket is approximately 3,000 kg, what would be the acceleration of the launched rocket?
b) The rocket starts from rest, what would be the final speed after 5 min?
The earliest known observations of the night sky date back to ancient civilizations such as the Babylonians, Egyptians, and Chinese, who recorded the positions of stars, planets, and other celestial bodies.
Explain about goal of humanity:Discovering outer space has been a goal of humanity for centuries. Throughout history, people have looked to the stars with a sense of wonder and curiosity, trying to understand the nature of the universe. a) To calculate the acceleration of the launched rocket, you can use the formula:However, it wasn't until the 20th century that humans were able to physically explore space. With the development of rocket technology, scientists were able to launch spacecrafts beyond Earth's atmosphere, allowing for the study of celestial bodies and the exploration of the Solar System and beyond.a = F / m
where F is the force (thrust) acting on the rocket and m is the mass of the rocket.
In this case, F = 20,000 N and m = 3,000 kg
So, a = 20,000 N / 3,000 kg = 6.67 m/s²
b) To calculate the final speed of the rocket after 5 minutes, you can use the formula:
v = a * t
where v is the final speed, a is the acceleration and t is the time.
In this case, a = 6.67 m/s² and t = 5 minutes = 300 seconds.
So, v = 6.67 m/s² * 300 seconds = 2,001 m/s
It's worth noting that the acceleration and final speed calculations are assuming that the rocket thrust is constant during the entire flight, which is not the case in reality, thrust changes during different stages of the rocket's flight.To learn more about goal of humanity refer to:
https://brainly.com/question/144508
#SPJ1
A sump pump is draining a flooded basement at the rate of 0.600 L/s, with an output pressure of 3.00 ? 105 N/m2. Neglect frictional losses in both parts of this problem.
(a) The water enters a hose with a 3.00 cm inside diameter and rises 2.50 m above the pump. What is its pressure at this point?
_____N/m2
(b) The hose then loses 1.80 m in height from this point as it goes over the foundation wall, and widens to 4.00 cm diameter. What is the pressure now?
_____N/m2
a. The pressure of the water that enters a hose with a 3.00 cm inside diameter and rises 2.50 m above the pump is 276,475 N/m².
b. The pressure after losing 1.80 m in height and widening to 4.00 cm diameter is 293,715 N/m².
To find the pressure of the water 2.50 m above the pump, we need to account for the change in potential energy. The pressure at this point can be calculated using the following formula:
P2 = P1 - ρgh
where P1 is the initial pressure (3.00 × 10^5 N/m²), ρ is the density of water (approximately 1000 kg/m³), g is the acceleration due to gravity (9.81 m/s²), and h is the height difference (2.50 m).
P2 = 3.00 × 10⁵ N/m₂ - (1000 kg/m³)(9.81 m/s²)(2.50 m)
P2 ≈ 276,475 N/m²
The pressure of the water 2.50 m above the pump is approximately 276,475 N/m².
To find the pressure after losing 1.80 m in height and widening to 4.00 cm diameter, we can use the same formula, adjusting the height difference accordingly:
P3 = P2 + ρgh'
where h' is the new height difference (1.80 m).
P3 = 276,475 N/m² + (1000 kg/m³)(9.81 m/s²)(1.80 m)
P3 ≈ 293,715 N/m²
The pressure after losing 1.80 m in height and widening to 4.00 cm diameter is approximately 293,715 N/m².
Learn more about pressure: https://brainly.com/question/14205367
#SPJ11
Calculate the volume fraction change of a fixed mass of gas whose pressure is tripled at a constant temperature.
The ideal gas equation is needed here. Since PV=nRT, we see that the volume is directly proportional to the temperature. We must, however use Kelvin temperatures in this equation. Since you want the volume tripled, you have to triple the temperature.initial temp is 273 K final temp should be 819 K819 K - 273 K = 546 degrees CRemember to get the Kelvin temperature one adds 273 to the Celsius number
The siemens, the SI derived unit of electric conductance and admittance (the reciprocal of resistance in ohms), is also known by what three-letter "semordnilap"?
The three-letter "semordnilap" for the siemens, the SI derived unit of electric conductance and admittance, is MES.
astronomers can characterize a planet's atmosphere in absorption via group of answer choices transits only transits and the doppler method the doppler method direct imaging astrometry and the doppler method
Astronomers can characterize a planet's atmosphere in absorption via Optioin d. astrometry and the doppler method
For transiting planets, astronomers can obtain valuable information about the atmosphere, surface temperature, and size of the planet. For most Sun-like stars, an orbiting planet that is itself the size of a brown dwarf only reduces the star's brightness to a few percent or less during transit.
Most known exoplanets have been discovered using the transit method. A transit occurs when a planet passes between a star and its observer. As Venus or Mercury moves between us and the Sun, transits within the solar system can be observed from Earth.
A transiting exoplanet's atmosphere can be observed backlit by the star as it passes its host star. Additional atmospheric observations can be made by watching exoplanets disappear and reappear behind their stars.
Learn more about planet's atmosphere here:-https://brainly.com/question/4208097
#SPJ4
Disclaimer:- your question is incomplete, please see below for the comlete question.
Astronomers can characterize a planet's atmosphere in absorption via group of answer choices
a. transits only
b. transits and the doppler method
c. the doppler method direct imaging
d. astrometry and the doppler method
the change in velocity over time is called acceleration
Answer:What' the question?
Explanation:
Answer:
Explanation:
Your answer is correct
POR FAVOR AYUDENME A RESOLVER ESTO:
Halla el coeficiente de dilatación lineal de una varilla que a 10 grados centígrados mide 125 metros y cuya longitud a 85 grados centígrados es 125.20 m. ¿De qué material será?
Answer:
α = 2.13 10⁻⁵ C⁻¹ , the closest material is ALUMINUM
Explanation:
The expression for thermal expansion is
ΔL = α L₀ ΔT
temperatures are
ΔT = 85 - 10 = 75 ° C
the length of the rod is L₀ = 125 m and L_f = 125.20 m
ΔL = 125.20 - 125 = 0.20 m
α = \(\frac{1}{L_o} \frac{\Delta L }{\Delta T}\)
α = \(\frac{ 1}{125} \ \frac{0.20 }{75}\)
α = 2.13 10⁻⁵ C⁻¹
When reviewing the table, the closest material is ALUMINUM
near the beginning of the movie, where does the helicopter refill its water tanks from? question 1 options: (a) a river (b) a swimming pool (c) a hose behind a shopping mall (d) a reservoir
In the movie Planes: Fire & Rescue, the helicopter refills its water tanks from a natural reservoir near the beginning of the movie. Therefore, option d, a reservoir is correct.
In this scene, the helicopter named Dipper flies over to the reservoir, dives down, and scoops up water into her water tanks before heading back to the fire to extinguish it. The reservoir is a significant source of water for the firefighters since it is too far for the fire trucks to drive to, which could take more time.
The fire was growing quickly, and Dipper, the helicopter, played a crucial role in containing it. When the fire gets out of control, and the fire brigade cannot handle it, the firefighters call in a team of aircraft firefighters who use helicopters that can scoop up huge amounts of water from the lake and drop it on the fire to extinguish it.
The Planes: Fire & Rescue is a movie that follows Dusty's journey as he navigates life as a firefighting plane after learning that his racing days are over. It's a family-friendly movie that is sure to keep everyone entertained.
To learn more about helicopter visit;
https://brainly.com/question/31182828
#SPJ11
7. Convert 746 days to centuries.
Answer: 0.0208 Centuries
Explanation:
There is 2.739*10^-5 centuries per 1 day.
We can take 746 days and multiply it by that 2.7 number to get how many centuries are in 746 days.
\(746 *(2.793*10^{-5})\) = 0.0208 centuries
Based on the information in the table, choose whether the magnetic field is weak or strong
Current Number of Coils Magnetic Field Strength 0. 2 A Many _______________
5. 0 A Many _______________
5. 0 A Few _______________
put weak or strong in the blanks
Answer:
Explanation:
Field characteristics
The strength of the field at the Earth's surface ranges from less than 30 microteslas (0.3 gauss) in an area including most of South America and South Africa to over 60 microteslas (0.6 gauss) around the magnetic poles in northern Canada and south of Australia, and in part of Siberia.
If the atomic mass of neon is 20 amu, how much neon would be needed to have an avogadro's number of neon atoms?
By Avogadro's number, the mass of Neon atom is 20 grams.
We need to know about Avogadro's number to solve this problem. Avogadro's number is the number that explains how many carbon atoms are in one mol. The Avogadro's number is
Na = 6,02 × 10²³ atoms / mol
From the question above, we know that
Mr = 20
N = 6,02 × 10²³ atoms
By using Avogadro's number, we can calculate how much Neon atoms
N = n . Na
6,02 × 10²³ = gr / Mr . 6,02 × 10²³
gr / 20 = 1
gr = 20 grams
Hence, the mass of Neon atom is 20 grams.
For more on Avogadro's number at: https://brainly.com/question/1581342
#SPJ4
Two point charges are placed at the following points on the x-axis. +2.0 C at
×=0, -3.0.C at 0.40m. Find the electric field strength at 1.20m?
The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:
\($$F=k\frac{q_1q_2}{r^2}$$\)
where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:
\($$E=\frac{kq}{r^2}$$\) where k is the Coulomb constant.
So, let's calculate the electric field due to each charge separately and then add them up:
For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)
For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:
\($$E_2=\frac{kq_2}{r^2}\)
\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)
The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.
To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)
Substituting the values of E1 and E2:
\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)
net comes out to be -1.5×10⁴ N/C.
Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
Know more about electric field here:
https://brainly.com/question/19878202
#SPJ8
What is exothermic .Is it a reaction?
Answer:(of a reaction or process) accompanied by the release of heat.
Explanation: trust moi
Look at this set of 8 numbers:
74 44 81 78 84 74 9942
which value would change the most if the number 27 were added to the set?
mean
median
mode
The value that would change the most if 27 were added to the set is the mean.
Determine the mean, median, mode?To determine the effect of adding 27 to the set on mean, median, and mode, let's calculate each measure before and after the addition.
Before adding 27:
Mean = (74 + 44 + 81 + 78 + 84 + 74 + 9942) / 7 = 1465.57
Median = 78
Mode = 74
After adding 27:
Mean = (74 + 44 + 81 + 78 + 84 + 74 + 9942 + 27) / 8 = 1479.5
Median = 78
Mode = 74
The mean value changed the most, increasing from 1465.57 to 1479.5. The median and mode remain the same because they are not affected by adding a value that is not larger than the current maximum value.
Therefore, the mean would change the most if 27 were added to the set.
To know more about mean, refer here:
https://brainly.com/question/31101410#
#SPJ4
what does x repressent on a motion map?
Answer:
The x represents the reference point on a motion map
Explanation:
-Motion maps are another way to represent the motion of an object. (other representations are graphical and mathematical models)
Answer:
The x represents the reference point on a motion map. Explanation; -Motion maps are another way to represent the motion of an object. (other representations are graphical and mathematical models).
Explanation:
What are the three stages of matter and how?
Answer:
Solid, Liquid and Gas
Explanation:
They are the 3 states or stages of Matter
A box is placed on a 30o frictionless incline. What is the acceleration of the box as it slides down the incline
Answer:
2.78m/s²
Explanation:
Complete question:
A box is placed on a 30° frictionless incline. What is the acceleration of the box as it slides down the incline when the co-efficient of friction is 0.25?
According to Newton's second law of motion:
\(\sum F_x = ma_x\\F_m - F_f = ma_x\\mgsin\theta - \mu mg cos\theta = ma_x\\gsin\theta - \mu g cos\theta = a_x\\\)
Where:
\(\mu\) is the coefficient of friction
g is the acceleration due to gravity
Fm is the moving force acting on the body
Ff is the frictional force
m is the mass of the box
a is the acceleration'
Given
\(\theta = 30^0\\\mu = 0.25\\g = 9.8m/s^2\)
Required
acceleration of the box
Substitute the given parameters into the resulting expression above:
Recall that:
\(gsin\theta - \mu g cos\theta = a_x\\\)
9.8sin30 - 0.25(9.8)cos30 = ax
9.8(0.5) - 0.25(9.8)(0.866) = ax
4.9 - 2.1217 = ax
ax = 2.78m/s²
Hence the acceleration of the box as it slides down the incline is 2.78m/s²
1
Which device can only be used for heating a space?
an air conditioner
a heat pump
a furnace
a heat engine
Explanation:
heat engine is correct answer
Answer:
The answer is:
C) A Furnace
Hubble’s observation that galaxies farther away from
us are receding
faster implies that:
universe is expanding.
universe is contracting.
are located at the center of the universe.
Answer:
That the universe is "expanding"
Consider dots painted on the surface of a balloon - if the dots are moving away from one another, the balloon must be expanding.
Electricity is distributed to neighborhoods at a relatively high AC voltage, often 7200 V. Transformers mounted on utility poles (Figure 1) then transform this high voltage down to the 120 V used in homes. A typical transformer of this kind can handle as much as 15 kWof electric power flowing through it from its primary to its secondary.
What is the primary current at this maximum power?
The primary current at maximum power is 2.08 A.
To determine the primary current at maximum power, we need to use the formula:
Power (P) = Voltage (V) x Current (I
Given that the transformer can handle a maximum power of 15 kW, and the voltage is 7200 V on the primary side and 120 V on the secondary side, we can solve for the primary current as follows:
15,000 W = 7200 V x I
I = 15,000 / 7200
I = 2.08 A
Therefore, the primary current at maximum power is 2.08 A. This means that the transformer can handle up to 2.08 amps of current flowing through it on the primary side while transforming the voltage from 7200 V down to 120 V on the secondary side. It's important to note that transformers play a critical role in the distribution of electricity from power plants to homes and businesses by allowing for efficient and safe voltage transformations.
To know more about primary current visit:
https://brainly.com/question/14509116
#SPJ11
Please help!!! I really need a solution to this question ASAP
Answer:
Please find attached the plot of distance against time created with Microsoft Excel
Explanation:
The table of the information about the train journey is presented here as follows;
\(\begin{array}{ccc}Station&Distance \ travelled/\,km&Time \taken \, / \, minutes \\Ayton&0&0\\Beeston&20&30\\Seatown&28&45\\Deeville&36&60\\Eton&44&70\end{array}\)
From the table data, the distance against time plot can be created by entering the data into a spreadsheet such as Microsoft Excel, then selecting a Chart option in the Ribbon under the Insert Menu after selecting the data
5. Forces have. And.
Answer:
Forces have magnitude and direction.
Explanation:
Force is a vector quantity.
why do yall think it is ok to judge ppl based on how they look bc from my point of view i dont think its ok i think ppl are beautiful in there own way
Answer:
hgggkwhhsvshwhhwbejshsbehe
Answer:
true!
Explanation:
I am happy to see some THINGS like this!
A tenis ball is thrown upwards from the edge of a cliff with a speed of 10m/s
Imagine a player throwing a football. Explain the action of what is happening to the hand and ball, as well as describe the action force and the reaction force
Answer:
Explanation:
When a player throws a football , he applies force on the ball , due to which ball accelerates in forward direction . This is the action force .
The ball also applies a force on the hand of the player . Due to it the player experiences a pushing force in backward direction . This is reaction force .
Due to this force , the player does not move in backward direction because of frictional force of the ground . The frictional force keeps him stationary .
What specific type of tide has the smallest difference between high and low tide?
Answer: Neap tides
Explanation: Neap tides are tides that have the smallest tidal range, and they occur when the Earth the Moon, and the Sun form a 90o angle. They occur exactly halfway between the spring tides when the Moon is at first or last quarter.