A block of mass 5 kg is pulled across a horizontal bench by a horizontal force. the acceleration of the block is 2.5 m/s2 when the friction force is 10 n. calculate the horizontal pulling force.

The maximum velocity of a particle on the string is approximately 0.98 m/s.

To find the maximum velocity of a particle on the string, we can use the given tension, linear density, amplitude, and wavelength values.

Given:

- Tension (T) = 55.0 N

- Linear density (μ) = 4.70 g/m = 0.00470 kg/m (converted to kg/m)

- Amplitude (A) = 3.00 cm = 0.03 m (converted to meter)

- Wavelength (λ) = 2.10 m

First, we can find the wave speed (v) using the equation v = √(T/μ):

v = √(55.0 N / 0.00470 kg/m) ≈ 34.66 m/s

Next, we can find the angular frequency (ω) using the equation ω = 2πv/λ:

ω = (2π * 34.66 m/s) / 2.10 m ≈ 32.74 rad/s

Finally, we can find the maximum velocity of a particle on the string (v_max) using the equation v_max = Aω:

v_max = 0.03 m * 32.74 rad/s ≈ 0.98 m/s

So, the maximum velocity of a particle on the string is approximately 0.98 m/s.

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Answer:

About 17,500 miles per hour.

Explanation:

KE = ½ mv²

KE = ½ (2 kg) (150 m/s)²

KE = 22,500 J

Answer:

A. 22,500

Explanation:

Answer:

E.  All of the Above

Explanation:

By doing any kind of exercise or physical activity, you are increasing your overall health.  Your muscle strengthen because of the jumping and movement of arms.  You are more alert because you have to time each jump right in order to keep going.  By breathing evenly while jumping, you do help your Cardiorespiratory fitness as well.  And of course, you increase your athletic ablility over all with much endurance and practice.

Answer:  Kinetic energy is energy that an object has as a result of its motion. Potential energy is stored energy that has not yet been released.

Explanation:  All moving objects possess kinetic energy, which is determined by the mass and speed of the object. Potential energy is the energy an object has as a result of its position.

Answer:

17.565 kgm/s

Explanation:

Momentum = mass × velocity

I = mv..................... Equation 1

But we can calculate the value of v  using the equation of motion under gravity.

v² =  u²+2gs............. Equation 2

Where u = initial velocity, s = maximum heigth, g = acceleration due to gravity.

Given: u = 0 m/s (at the maximum heigth), s = 7.0 m.

Constant: g = 9.8 m/s²

Substitute these values into equation 2

v² = 0²+ 2×7×9.8

v² = 137.2

v = √137.2

v = 11.71 m/s.

Also given: m = 1.50 kg

substitute these values into equation 1

Therefore,

I = 1.5×11.71

I = 17.565 kgm/s

The ball travelled  234.33 meter in the x direction before it hits the ground.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Horizontal speed of the ball is 30.0 m/s.

Acceleration due to gravity is = 9.8 m/s²

Time taken to fall 299 m is = √( 2 × 299/9.8) second = 7.81 second.

Hence, in this interval of time, the ball travelled in x-direction =

30.0  ×  7.81 meter

= 234.33 meter.

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Answer: B. Yes; a false hypothesis gives a scientist new information to use.

Explanation:

      Let us take a look and break down all the question's answer options.

✗ A.

Yes; now he knows that the exact opposite of his hypothesis must be true.

➜ This is not the case. He must look at this data and decide what is true.

✓B.

Yes; a false hypothesis gives a scientist new information to use.

➜ Yes! We learn from our research and looking back at our hypothesis.

✗ C.

No; a false hypothesis makes a scientist look silly.

➜ This isn't true. You cannot expect to be right all the time, and scientists make incorrect hypotheses frequently.

✗ D.

No; false hypotheses are a waste of time.

➜ Tying back into B and C, this isn't true. We learn from comparing our hypotheses with our data.

The mother can push the 20.0 kg baby carriage a distance of approximately 47.1 meters using a force of 62.0 N.

To determine the distance the mother can push the baby carriage, we need to use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy. In this case, the work done by the mother is given as 2920 J.

The work done can be calculated using the formula: work = force × distance. Rearranging the formula to solve for distance, we have distance = work / force.

Substituting the given values, distance = 2920 J / 62.0 N = 47.1 meters (rounded to one decimal place).

Therefore, the mother can push the 20.0 kg baby carriage a distance of approximately 47.1 meters using a force of 62.0 N.

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Plasma is made up of about 90% water. It also has salts and enzymes.

Plasma has:

Answer:

Answer:

I HAD THE SAME QUESTION AND SEARCHED IT UP AND GOT THE ANSWERS.

Explanation:

To find the period of oscillation of the object when the elevator accelerates upward with an acceleration of 2g, we need to consider the effect of the acceleration on the equilibrium position and the spring constant.

Let's assume the original equilibrium position of the object is at a distance x from the ceiling of the elevator. When the elevator accelerates upward with an acceleration of 2g, the apparent gravitational force acting on the object will be reduced. The net force acting on the object will be the difference between the spring force and the apparent gravitational force.

The spring force, according to Hooke's law, is given by F_spring = -kx, where k is the spring constant and x is the displacement from the equilibrium position.

The apparent gravitational force, considering the reduced weight due to the acceleration, is given by F_gravity = m(g - 2g), where m is the mass of the object and g is the acceleration due to gravity.

The net force acting on the object can be written as:

F_net = F_spring + F_gravity

F_net = -kx + m(g - 2g)

F_net = -kx - mg

Now, let's apply Newton's second law, F_net = ma, where a is the acceleration of the object.

-mgx - kx = ma

Rearranging the equation, we have:

a = -g(x + (k/m)x)

Since the acceleration is proportional to the displacement, the object will still undergo simple harmonic motion (SHM). The angular frequency (ω) of the object's oscillation can be expressed as:

ω = sqrt(k/m)

However, since the acceleration is modified due to the elevator's acceleration, the angular frequency will also be affected. The new angular frequency (ω') can be calculated by adjusting for the modified acceleration:

ω' = sqrt(k/m + g(x + (k/m)x)/x)

The period of oscillation (T') is the inverse of the angular frequency:

T' = 2π/ω'

Substituting ω' into the equation, we get:

T' = 2π / sqrt(k/m + g(x + (k/m)x)/x)

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Answer:

ac = 72 m/s²

Fc = 504 N

Explanation:

We can find the centripetal acceleration of the hammer by using the following formula:

\(a_c = \frac{v^2}{r}\)

where,

ac = centripetal acceleration = ?

v = constant speed = 12 m/s

r = radius = 2 m

Therefore,

\(a_c = \frac{(12\ m/s)^2}{2\ m}\)

ac = 72 m/s²

Now, the centripetal force applied by the athlete on the hammer will be:

\(F_c = ma_c\\F_c = (7\ kg)(72\ m/s^2)\)

Fc = 504 N

The magnitude of the change in momentum is therefore 6.12 kg*m/s, and the direction is downward and the floor exerts an average net force of 51 N upward on the ball during the collision.

(a) To find the magnitude and direction of the ball's change in momentum, we need to first find the initial and final momenta of the ball. The initial momentum is given by:

\(p_i = m*v_i\)

where m is the mass of the ball, and \(v_i\) is the initial velocity of the ball before it hits the floor. Substituting the given values, we get:

\(p_i\) = (0.60 kg)(6.0 m/s) = 3.6 kg*m/s

The final momentum is given by:

\(p_f = m*v_f\)

where \(v_f\) is the velocity of the ball after it rebounds from the floor. Substituting the given values, we get:

\(p_f\)= (0.60 kg)(-4.2 m/s) = -2.52 kg*m/s

Note that the negative sign indicates that the direction of the final momentum is opposite to that of the initial momentum.

The change in momentum is given by:

Δp = \(p_f - p_i\)

Substituting the calculated values, we get:

Δp = -2.52 kgm/s - 3.6 kgm/s = -6.12 kg*m/s

The magnitude of the change in momentum is therefore 6.12 kg*m/s, and the direction is downward.

(b) To find the average net force that the floor exerts on the ball, we can use the impulse-momentum theorem:

Δp = \(F_avg\) * Δt

where Δt is the time duration of the collision. Substituting the calculated value of Δp and the given value of Δt, we get:

-6.12 kg*m/s = \(F_avg\) * 0.12 s

Solving for \(F_avg\), we get:

\(F_avg\) = -6.12 kg*m/s / 0.12 s = -51 N

Note that the negative sign indicates that the direction of the average net force is opposite to that of the change in momentum, i.e., upward. Therefore, the floor exerts an average net force of 51 N upward on the ball during the collision.

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Answer:

The new Coulomb force is q₁q₂/9πε₀r²

Explanation

The coulomb force between the two charges q₁ and q₂ at a distance r in air is given by F = q₁q₂/4πε₀r².

Now, let us assume the material of dielectric constant κ = 9 is placed between them on the side of the q₁ charge. The value of its effective charge is now q₃ = q₁/κ at a distance of d = r/2 from the q₂ charge.

Since we have air between q₂ and q₃, the coulomb force between them is

F' = q₂q₃/4πε₀d²

= q₂(q₁/κ)/4πε₀(r/2)²

=  4q₂q₁/κ4πε₀r²

= 4/κ(q₂q₁/4πε₀r²)

= 4/9 × (q₂q₁/4πε₀r²)

= q₁q₂/9πε₀r²

So, the new Coulomb force is q₁q₂/9πε₀r²

the mass of the pill is 5 x 10^-3 g in scientific notation or 5 mg.

A pain-relieving pill has a mass of 0.005 g.

We need to express the pill's mass in grams using scientific notation or in milligrams.

1. In scientific notation:

0.005 g can be expressed in scientific notation as: 5 x 10^-3 g.2.

In milligrams:

1 g = 1000 mg.

Therefore, 0.005 g can be expressed in milligrams as:

0.005 g x 1000 mg/g = 5 mg.

Hence, the mass of the pill is 5 x 10^-3 g in scientific notation or 5 mg.

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The acceleration of the 2.50 kg mass when a tension of 35.0 N is applied to the right is 14.0 m/s²

To find the acceleration of a 2.50 kg mass with a tension of 35.0 N applied to the right, we will use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration (F = ma). In this case, the force (F) is the tension applied to the mass.
1. First, write down the given values:
Tension (F) = 35.0 N
Mass (m) = 2.50 kg
2. According to Newton's second law of motion, F = ma. We need to solve for acceleration (a). Therefore, we will rearrange the formula as follows: a = \frac{F}{m}

3. Plug in the given values into the formula: a = \frac{(35.0 N) }{ (2.50 kg)}
4. Calculate the acceleration:
a = 14.0 m/s²
So, the acceleration of the 2.50 kg mass when a tension of 35.0 N is applied to the right is 14.0 m/s². This means that the mass will increase its velocity by 14.0 meters per second every second in the direction of the applied force.

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complete question:

A tension of 35.0N is applied to the right on a 2.50kg mass. What is the acceleration of the mass?

A. 59.5m/s2 B. 4.20m/s2 C. 23.8m/s2 D. 14.0m/s2

When a tension of 35.0 N is applied to the right, the acceleration of the 2.50 kg mass is 14.0 m/s^2.

Use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration (F = ma), to calculate the acceleration of a 2.50 kg mass when 35.0 N of right-side tension is applied. The tension put on the mass in this situation constitutes the force (F).

1. First, write down the given values:

Tension (F) = 35.0 N

Mass (m) = 2.50 kg

2.F = ma, says Newton's second law of motion We need to solve for acceleration (a).So, we'll change the formula's order as follows.:  \(a = \frac{F}{m}\)

3. Add the specified values to the formula. \(: a = \frac{(35.0 N) }{ (2.50 kg)}\)

4. Calculate the acceleration:

a = 14.0 m/s²

Therefore, when a tension of 35.0 N is applied to the right, the acceleration of the 2.50 kg mass is 14.0 m/s^2. This indicates that the mass will accelerate in the direction of the applied force by 14.0 metres per second per second.

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complete question:

A tension of 35.0N is applied to the right on a 2.50kg mass. What is the acceleration of the mass?

A. 59.5m/s2 B. 4.20m/s2 C. 23.8m/s2 D. 14.0m/s2

The speed of the  Toyota Corolla would have  been 143.9 mph.

The acceleration of the F-15 can be calculated as follows:

Acceleration = Velocity Change / Time = (Take-off Speed) / Time

where;

Take-off Speed = √(2dg /t²)

Take-off Speed = √(2 x  (270 ft)  x 32.2 ft/s² / (2 s)²)

T  = √(17496) = 131.6 ft/s

Acceleration = Velocity Change / Time

= (131.6 ft/s) / (2 s) = 65.8 ft/s²

We can use the same acceleration to launch the Toyota Corolla, and calculate its final velocity:

Final Velocity = Initial Velocity + Acceleration x Time

where;

Final Velocity = 0 + (65.8 ft/s²) * (2 s) = 131.6 ft/s

Finally, we can convert the velocity from feet per second to miles per hour:

Velocity (mph) = Velocity (ft/s) x (1 hour/3600 s) x (5280 ft/mile)

= 131.6 ft/s x  (1 hour/3600 s)  x (5280 ft/mile)

= 143.9 mph

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Answer:

Moving-iron instruments are generally used to measure alternating voltages and currents.

Explanation:

In moving-iron instruments the movable system consists of one or more pieces of specially-shaped soft iron, which are so pivoted as to be acted upon by the magnetic field produced by the current in coil.

Change in the momentum of the object with mass 4.9 kg on which force of 6.36 N acts for 20.4 s is 31.164kgm/s and change in velocity is 6.36m/s

As we know Force acting on any object is

F = m.a...........(1)

where m ⇒ mass

and a ⇒ acceleration

Also \(a=\frac{v}{t}\)..........(2)

where v ⇒ velocity

t ⇒ time

so equation (1) can be written as:

\(F=\frac{m.v}{t}\)..........(3)

Change in Momentum is equal to

p=m.v.......(4)

where m ⇒ mass

v ⇒ velocity

Now as per the question:

Force, F = 6.36 N

Mass, m = 4.9 kg

Time, t = 20.4s

putting the values in equation (3),

we get \(6.36=\frac{4.9*v}{20.4}\)

by solving this we get a value of v=6.36m/s

putting the values in equation (4)

we get, Change in momentum

\(p=4.9*6.36\\p=31.164kg m/s\)

so the change in velocity is 6.36m/s and change in momentum is 31.164kgm/s

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The magnitude of the force F experienced by a charge q that moves in a direction perpendicular to a magnetic field B with a speed v is given by:

Isolate B from the equation:

Replace F=22.394N, q=0.049C and v=272.4m/s to find the strength of the magnetic field:

Therefore, the magnetic field strength is approximately 1.7T.

Answer:

D - Mia is incorrect because machines and engines can never be 100 percent efficient.

Explanation:

someone said this on quizlet i’ll come back to verify once i finish my exam review lol

Answer:

d

Explanation:

edge 2021

Answer:398.5 watts

Explanation:

In order to determine which layer represented by the canyon wall at this location would have been deposited first in geologic time, we must first understand the principle of superposition.

This principle states that in an undisturbed sequence of rock layers, the oldest rocks are at the bottom and the youngest rocks are at the top. Therefore, the layer closest to the bottom of the canyon wall would have been deposited first in geologic time. However, it's important to note that this is only true for undisturbed rock layers. If there has been any type of tectonic activity or erosion, the sequence of the layers may have been disrupted. Additionally, determining the exact age of the layers may require the use of radiometric dating methods.

This law states that in undisturbed sedimentary rock layers, the oldest layers are found at the bottom and the layers progressively become younger as you move upward. In a canyon setting, the sedimentary layers are exposed along the canyon walls, enabling geologists to study the history of deposition and geological events. The first layer to be deposited at this location formed the base of the canyon wall, serving as the foundation for subsequent layers. As time progressed, new sedimentary layers were deposited on top of older layers, creating the visually distinct strata that you see along the canyon wall today.

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Answer: 1.72J

Just figured this out a while ago

We cannot determine the speed at which a star in the galaxy is moving away from us based on its mass, luminosity, age, or color alone. it is false

The speed at which a star in the galaxy is moving away from us is determined through the measurement of its spectrum using a technique known as redshift.

When a star or galaxy moves away from us, its light is shifted towards longer wavelengths, resulting in a redshift. By analyzing the degree of redshift, astronomers can estimate the speed at which the star is receding.

However, factors such as mass, luminosity, age, and color do not provide direct information about the star's motion away from us.

These characteristics are important for studying other properties of stars, such as their composition, brightness, evolutionary stage, and temperature. To determine the motion of a star in the galaxy, redshift measurements are essential.

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a) To balance the gravitational attraction between Earth and the Moon, the electrostatic force between their net negative charges (-Q) needs to be equal to the gravitational force between them. Mathematically, we can equate these two forces:

k(Q^2/r^2) = G(Mm/r^2),

where k is the electrostatic constant, G is the gravitational constant, M is the mass of Earth, m is the mass of the Moon, and r is the distance between their centers.

Canceling out the common terms and solving for Q, we get:

Q = sqrt(GMm/k).

b) The distance between the Earth and the Moon does not affect the value of Q. The gravitational force and electrostatic force both depend on the distance squared (1/r^2), so as long as the distance remains the same, the value of Q required to balance the forces remains constant.

c) To find the number of electrons needed to produce a net charge of -Q, we need to know the charge of a single electron. The elementary charge, e, is approximately -1.602 x 10^-19 Coulombs. Therefore, the number of electrons required can be calculated as:

Number of electrons = Q/e.

In summary, the value of Q required to balance the gravitational attraction between Earth and the Moon can be calculated using the equation Q = sqrt(GMm/k). The distance between the Earth and the Moon does not affect this value. To determine the number of electrons needed to produce this charge, we divide Q by the charge of a single electron, e.

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Answer:

Here you go, look at the pic. It's labeled

Answer: Nia could measure the temperature of the bottom floor of a house to see if the heat had risen in the house due to convection.

Explanation:

Answer:

Nia could measure the temperature of the bottom floor of a house to see if the heat had risen in the house due to convection.

Explanation:

Because energy transferred by the mass motion of molecules.