a blackbody is at temperature of 500°C . What would be its temperature in Kelvin for it to radiate twice as much energy per second?​

Answer:

endorphins

Explanation:

Answer:

Explanation:

Please post if there is a graph showing the data.

Without a graph, in general the trend can be described as:

"positive" when the dependent variable increases with an increase in independent variable

"negative" when the dependent variable decreases with an increase in independent variable

"neutral" when the dependent variable remains the same with an increase or decrease in independent variable

Answer:

Variance is 25

Explanation:

Recall that the standard deviation is defined as the square root of the variance. therefore, if you know the standard deviation \((\sigma)\), square it and you get the variance:

\(Variance= \sigma^2\\Variance= 5^2= 25\)

Answer:

The velocity is \(v_b = 20.17 \ m/s\)

Explanation:

From the question we are told that

   The mass of the ball is  \(m = 0.245 \ kg\)

   The radius is  \(r =  59.8 \  cm  =  0.598 \ m\)

   The force is  \(F =  30.9 \ N\)

   The speed of the ball is  \(v = 16.0 \ m/s.\)

Generally the kinetic energy at the top of the circle is mathematically represented as

    \(K_t  =  \frac{1}{2} *  m  *  v^2\)

=> \(K_t  =  \frac{1}{2} *  0.245   *  16.0 ^2\)  

=> \(K_t  =  31.36 \ J\)  

Generally the work done by the force applied on the ball from the top to the bottom  is mathematically represented as

       \(W =  F *  d\)

Here  d is the length of  a semi - circular arc which is mathematically represented as

       \(d =  \pi * r\)

So

      \(W =  30.9 *  0.598  \)

      \(W = 18.48 \ J \)

Generally the kinetic energy at the bottom is mathematically represented as

      \(K_b  =  \frac{1}{2} *  m *  v_b^2\)

=>    \(K_b  =  \frac{1}{2} *  0.245  *  v_b^2\)

=>   \(K_b  =  0.1225  *  v_b^2\)

From the law of energy conservation

     \(K_t +  W  =K_b\)

=>    \(31.36+  18.48 = 0.1225  *  v_b^2\)

=>    \(v_b = 20.17 \ m/s\)

Hello and Good Morning/Afternoon:

What makes a unit a fundamental SI unit:

Thus the seven fundamental S.I. units are:

Hope that helps!

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Answer:

The can was dropped from a height of 0.74 meters.

Explanation:

We can use the Conservation of Energy to evaluate the height.

The formula for the Conservation of Energy is

\(\frac{1}{2} mv^2=mgh\)

Lets solve for \(h\).

Cancel the common factor of \(m\).

\(\frac{1}{2} v^2=gh\)

Rewrite \(\frac{1}{2} v^2\) as \(\frac{v^2}{2}\) .

\(\frac{v^2}{2}=gh\)

Multiply both sides by 2.

\(v^2=2gh\)

Divide both sides by \(2g\).

\(\frac{v^2}{2g}=h\)

Numerical Evaluation

We are given

\(v=3.8\\g=9.81\)

Substituting our values into our equation for height gives us

\(h=\frac{3.8^2}{2*9.81}\)

Evaluate \(3.8^2\).

\(h=\frac{14.44}{2*9.81}\)

Multiply \(2\) and \(9.81\).

\(h=\frac{14.44}{19.62}\)

\(h=0.736235\)

Note: We also could have solved this using the kinematics equations. Both methods give you the same answer.

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The skydiver is accelerating upward with an upward orientation with an acceleration of 0.556 m/s².

The pace at which a speed changes over time is called acceleration. In other words, it is a measurement of how quickly an object's velocity alters. It is a vector quantity with a direction and magnitude.

Finding the net force affecting the skydiver can be our first step. The vector sum of all forces acting on the skydiver is known as the net force. Weight and drag force are the two forces at play here as they affect the skydiver.

The skydiver's weight is determined by:

Weight= mass x acceleration due to gravity

Weight: 82.0 kg x 9.81 m/s² (acceleration due to gravity)

Weight= 804.42 N

The skydiver is under the following net force:

net force = weight - drag force

850 N - 804.42 N = Net force

45.58 N of net force (upwards)

The skydiver will accelerate upwards since the net force is upward. The magnitude of the acceleration can be determined by applying Newton's second law of motion:

Net force is calculated as follows:

Net force = mass x acceleration

45.58 N = 82.0 kg x acceleration

Acceleration = 0.556 m/s².

As a result, the skydiver is accelerating upward with an upward orientation with an acceleration of 0.556 m/s².

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Answer:Near Earth's North Pole

Explanation:

Answer:

The speed of light traveling through a vacuum is exactly 299,792,458 meters (983,571,056 feet) per second. That's about 186,282 miles per second — a universal constant known in equations as "c," or light speed.

\(s\frac{d}{t}\)

Explanation:

hope this helps you my friend

(a) When m₂ is released, its acceleration will be approximately -3.27 m/s².

(b) The tension in the string is approximately -13.08 N.

To determine the acceleration of m₂ when it is released and the tension in the string, we need to consider the forces acting on the system.

(a) Acceleration of m₂:

Since the pulley is assumed to be frictionless, the tension in the string is the same on both sides of the pulley. We can consider the system consisting of m₁ and m₂ as one body. The net force acting on this system is the difference between the weight of m₁ and the weight of m₂:

Net force = m₁g - m₂g

Applying Newton's second law, F = ma, where F is the net force and a is the acceleration, we have:

m₁g - m₂g = (m₁ + m₂)a

Rearranging the equation to solve for the acceleration, we get:

a = (m₁g - m₂g) / (m₁ + m₂)

Substituting the given values, m₁ = 2.00 kg and m₂ = 4.00 kg, and the acceleration due to gravity, g = 9.8 m/s², we can calculate the acceleration:

a = ((2.00 kg)(9.8 m/s²) - (4.00 kg)(9.8 m/s²)) / (2.00 kg + 4.00 kg)

a = (19.6 N - 39.2 N) / 6.00 kg

a = -19.6 N / 6.00 kg

a = -3.27 m/s²

Therefore, when m₂ is released, its acceleration will be approximately -3.27 m/s². The negative sign indicates that the acceleration is in the opposite direction of the gravitational force.

(b) Tension in the string:

The tension in the string can be determined by considering the forces acting on m₂. The net force on m₂ is equal to its mass multiplied by its acceleration:

Net force = m₂a

Substituting the given values, m₂ = 4.00 kg and a = -3.27 m/s², we can calculate the tension:

Tension = (4.00 kg)(-3.27 m/s²)

Tension = -13.08 N

Therefore, the tension in the string is approximately -13.08 N. The negative sign indicates that the tension acts in the opposite direction of the weight of m₂.

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Answer:

35m

Explanation:

25m + 10m = 35m east.

*(adding since it's in the same direction)

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematic equations are a set of equations that can derive an unknown aspect of the motion of a body if the other aspects are provided.

Answer:

Hi ??? what is your question

Answer:

F = 1.638 x 10⁸ N = 163.8 MN

Explanation:

The total force exerted by the molasses is given as:

F = PA

where,

F = Force exerted by the molasses = ?

P = Pressure = ρgh

ρ = density of molasses = 1600 kg/m³

g = acceleration due to gravity = 9.81 m/s²

h = height of tank = 17.7 m

A = cross-sectional area of tank = πr²

r = radius of tank = 27.4 m/2 = 13.7 m

Therefore,

\(F = \rho ghA = \rho gh(\pi r^2)\\\\F = (1600\ kg/m^3)(9.81\ m/s^2)(17.7\ m)(\pi)(13.7\ m)^2\)

F = 1.638 x 10⁸ N = 163.8 MN

Answer:

0.23 J

Explanation:

k*(36 - 28) = 23

so k = 23/8 N/cm

W = k(32 - 28)²/2 = 23/8 * 4²/2 = 23 N-cm = 0.23 J

The volume of snow on the lawn is 6331.625 cm³

Volume is the area occupied inside the confines of an item in three dimensions. It is frequently known as the object's capacity. An object's capacity is expressed in terms of volume. The quantity of space filled by a three-dimensional object may also be used to describe volume. The basic equation for volume is length, width, and height, as opposed to the fundamental equation for the area of a rectangular shape, which is length, breadth, and height. For examples, one could use "depth" rather than "height."

The shape of the snow is assumed to be a cube

Therefore, the volume of the snow is the cube of its uniform depth.

Given that,

Uniform depth = 18.5 cm

Volume = (uniform depth)³

Volume = (18.5 cm)³

Volume = 6331.625 cm³

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It as dangerous to be hit by the gun as by the bullet because of the following;

(A) The butt distributes the recoil force over an area much larger than that of the bullet.

(B) The rifle has a much lower speed than the bullet.

The principle of conservation of linear momentum states that in an isolated system, the total momentum of the system is conserved.

That is the sum of the initial momentum is equal to the sum of the final momentum.

momentum of the gun = momentum of the bullet

Mu = mU

where;

If the forward momentum of a bullet is the same as the backward momentum of the gun, the speed of the gun will be smaller than the speed of the bullet since the mass of the gun is bigger than mass of the bullet.

We cannot conclude on the kinetic energy, since it depends on both mass and velocity.

Finally, the butt distributes the recoil force over an area much larger than that of the bullet, since the butt has a larger surface area and will hit more surface area than the bullet.

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Answer:

Explanation:

See the file attached .

b ) Range of projectile

= u²sin2θ / g

= 42² sin32 x 2 / g

= 42² sin64 / 9.8

= 161.8 m

c )

Max height = u² sin²32 / 2 g

= 42² sin²32 / 2x 9.8

= 25.27  m .

Answer:

Below

Explanation:

Near side is lit up by reflecting sunlight ......the sun is on opposite side of the earth from J's perspective

Answer: NEAR SIDE YALLL

Explanation:

The speed at aphelion is mathematically given as

v2 = 21.43 km/s

Question Parameter(s):

At perihelion a planet in another solar system is 175 x 106 km from its sun at traveling at 40 km/s.

At aphelion it is 250 x 106 km distant.

Generally, the equation for the angular momentum conservation is mathematically given as

I1*w1 = I2*w2

Therefore

(0.5*m*R1^2)*v1/R1 = (0.5*m*R2^2)*v2/R2

Where

v1*R1 = v2*R2

v2 = v1*(R1/R2) = (30*10^3)*(2.50*10^11)/(3.50*10^11)

v2 = 2.1428*10^4 m/s

v2 = 21.43 km/s

In conclusion, speed is

v2 = 21.43 km/s

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Answer:

Explanation:

Wavelength = 100m. Speed = V. 2.) Frequency = 20 Hz. Wavelength = 200 m. Speed = ... 2=1.7m. F=Y/2 f=2×10. 5.) Wavelength = 502 km. Speed= 100 m/s.

the order of average normal stress developed on cross section through B, C and D c) B>C>D.

When examined at constant levels of the applied shear stress s, the initial stress distribution differences N1 (cv) show a decreasing trend as the solid fraction cv increases.In other words, the shear stress increases more quickly than the usual stress differential does with filler volume fraction.

How is the typical soil stress determined?

EF is the area, and is the stress, hence F1 = EF.EF = EF = θ θ θ θ θ θ = θ θ θ θregular stress on the plane's EF.We can select the value of from this equation in a way that it equals zero.The primary plane is the one that forms this angle with block, which only experiences normal stress.

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Answer:

The graph of the velocity of an object in free fall would look like a straight line sloping downward. As the object falls, its velocity increases at a constant rate, so the graph of its velocity versus time will be a straight line with a negative slope. This is because acceleration due to gravity is a constant -9.8 meters per second squared, so the velocity of a free-falling object will increase by 9.8 meters per second every second.

Therefore, the graph that shows the change in velocity of an object in free fall is a straight line with a negative slope. Here is an example of such a graph:

Free Fall Velocity Graph

Answer: 1/gk

Explanation: 15(22/330kg) (330/330gk) = 1/gk

The difference in the path of a ball tossed straight up in the air by a passenger on a a bus from the view point of the passenger, and the person on the street is that the ball would appear to the passenger to be making an up and down movement when the ball is thrown up, while the stationary observer will actually see the ball moving along a parabolic path.

A parabolic path is described as a Kepler orbit with the eccentricity equal to 1 and is an unbound orbit that is exactly on the border between elliptical and hyperbolic.

The Parabolic path is also defined as the angle of trajectory of a projectile.

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The minimum coefficient of static friction with the floor is 0.3846.

To find the minimum coefficient of static friction with the floor, we need to consider the forces acting on the couch. In this case, the force of gravity is pulling the couch downward with a magnitude of mg, where m is the mass of the couch (40 kg) and g is the acceleration due to gravity (9.8 m/s²).

Since the couch does not move, the force of static friction between the couch and the floor must be equal in magnitude but opposite in direction to the horizontal pushing force of 150 N.

Therefore, we have the equation F_friction = F_push, where F_friction is the force of static friction.

The force of static friction can be calculated using the formula F_friction = μ_s * N, where μ_s is the coefficient of static friction and N is the normal force.

Since the couch is on a level floor and is not accelerating vertically, the normal force N is equal in magnitude but opposite in direction to the force of gravity, which is mg.

Substituting the values into the equation, we have μs * mg = 150 N.
Solving for μs, we get μs = 150 N / (mg).
Substituting the given values, we have μ_s = 150 N / (40 kg * 9.8 m/s²).
Simplifying, we find that μs = 0.3846.

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