a bicycle wheel with a radius of 30 cm and 16 spokes that is mounted with its axle fixed in a horizontal position. A 50-g mass is hung from a string wrapped around the periphery of the tire. The wheel is held stationary with the weight hanging as shown and then released. The wheel starts to spin and spins faster and faster until the string slips off 5 seconds after release.
What is the acceleration of the hanging mass (in m/s2) while the wheel's speed is increasing?
Answers
The acceleration of the hanging mass while the wheel's speed is increasing is 5,625 m/s².
What is acceleration?Acceleration is a vector quantity that measures the rate of change of an object's velocity. It is defined as the rate at which an object's velocity changes over time. Acceleration can be positive, negative, or zero. Acceleration can be caused by forces such as gravity, friction, or thrust.
The acceleration of the hanging mass is determined by the torque (τ) and the moment of inTherefore, the acceleration of the hanging mass can be calculated as a = τ/I = (F×r)/(mr²) = F/(mr). In this case, F = 50 g, r = 30 cm and m = 16 spokes. We can convert the mass from grams to kilograms by dividing by 1000, giving us m = 0.016 kg.
Plugging these values into the equation, we get a = 50/(0.03×0.016) = 5,625 m/s².
Therefore, the acceleration of the hanging mass while the wheel's speed is increasing is 5,625 m/s².
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Related Questions
(a) When an object's acceleration vector points in the same direction as its velocity, which of the following is true?
A. the object speeds up without turning.
B. the object slows down without turning.
C. the object turns without changing speed.
Answers
A. When an object's acceleration vector points in the same direction as its velocity, the object speeds up without turning.
What is acceleration vector?
The average acceleration vector is defined as the rate at which the velocity changes with time.
When an object is slowing down, the acceleration of the object is in the opposite direction as the velocity.
Also, when an object is speeding up, the acceleration of the object is in the same direction as the velocity.
Thus, when an object's acceleration vector points in the same direction as its velocity, the object speeds up without turning.
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Waves can carry either ____ or __________ energy?
Answers
Answer:
ways can carry either __machanical___ or electromagnetic energy
The plow was an important invention for the Sumerian civilization because it:
A. made it easier for farmers to prepare land for farming.
B. simplified communication with other cultures.
C. allowed important information to be recorded.
D. protected city-states from foreign invaders.
I am in the middle of the test help pls
Answers
The plow was an important invention for the Sumerian civilization because it made it easier for farmers to prepare land for farming.
The plow made farming more efficient for the Sumerians, as people no longer had to waste time planting food by hand. The cart allowed people to carry goods back and forth from different civilizations in a much easier way as people did not have to carry the goods on their backs.
It is estimated that the ancient Sumerians invented the plow. The plow was designed to utilize domestic animals as a means of easing the workload on farmers. Oxen were harnessed to a wooden plow and pulled it through the fields to loosen the soil for easier planting of crops.
Plow, also spelled plough, most important agricultural implement since the beginning of history, used to turn and break up soil, to bury crop residues, and to help control weeds.
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QUESTIONS An athlete, during his race in the 100 m sprint in the 2008 Beijing Olympics, exerted #force of 850 s on the race track using his show on the right foot at an angle of 50/' to the horizontal, 850 N 3.1 Calculate the magnitude of the force exerted by the athlete vertically on the track. 3.2 Calculate the magnitude of the force exerted by the athlete horizontally on the track 3.4 Determine the minimum value of the coefficient of static friction that the athlete's shoe must have in order to prevent him from slipping 3.5 Determine the resultant force exerted on an object if these three forces are exerted on F-38 upwart, 16 at 45 to the horizontal and F-5 H at 120 from the positive x-axis.
Answers
I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.
3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).
3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).
3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.
3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.
Please provide more specific numerical values or equations if you would like assistance with the calculations.
A 250 kg cart is traveling at 8 m/s when it strikes a 100 kg cart at rest. After the elastic collision, the 250 kg cart continues to travel forward but at a lower velocity of 3 m/s. Determine the velocity of the 100 kg cart after the elastic collision.
Answers
Answer: In this scenario, we have two carts colliding with each other. One cart weighs 250 kg and is moving at a speed of 8 m/s, while the other cart weighs 100 kg and is initially at rest.
After the collision, the 250 kg cart continues moving forward, but at a slower speed of 3 m/s. We want to find out the speed at which the 100 kg cart moves after the collision.
To solve this, we use the principle that the total "push" or momentum before the collision should be the same as the total momentum after the collision.
Since the 100 kg cart is initially at rest, its momentum is zero. The momentum of the 250 kg cart before the collision is 250 kg * 8 m/s = 2000 kg·m/s.
After the collision, the momentum of the 250 kg cart becomes 250 kg * 3 m/s = 750 kg·m/s.
To find the momentum of the 100 kg cart after the collision, we subtract the momentum of the 250 kg cart after the collision from the total momentum before the collision: 2000 kg·m/s - 750 kg·m/s = 1250 kg·m/s.
Now, we divide this momentum by the mass of the 100 kg cart to find its velocity: 1250 kg·m/s / 100 kg = 12.5 m/s.
Therefore, the 100 kg cart moves at a velocity of 12.5 m/s after the collision, in the opposite direction of the 250 kg cart's motion.
On your vacation, you take a plane from Atlanta to San Francisco (3400 km). The flight takes 4.0 hours. The first ten minutes and the last ten minutes are spent speeding up and slowing down respectively. Therefore, you reach your top speed 10 minutes into the flight. What was your average speed on this flight?
Answers
Answer: S = 850 km/h = 235.11 m/s
Explanation:
average speed = total distance : total time elapsed
distance = 3400 km
total time = 4 hours
average speed = D : T = 3400 km : 4 h = 850 km/h
[ 850 km /h = 850 000 m : 3600 s = 236.11 m/s ]
1) How many joules of heat are required to raise the temperature of 550 g of water from
12.7 °C to 28.8°C ? Specific heat of liquid water is 4.184 J/g °C.
Answers
Answer:
Explanation:
You can use \(Q = mc\Delta T=(550)(4.184)(28.8-12.7)=37049.32\) joule.
A 24.4kg dog is running northward at 2.14m/s, while a 5.53kg cat is running eastward at 3.56m/s. Their 78.5kg owner has the same momentum as the two pets taken together. Find the direction of the owner's velocity. Find the magnitude of the owner's velocity.
Answers
The owner's velocity is in the opposite direction of the combined velocity of the dog and the cat, and its magnitude is approximately 0.916 m/s.
To solve the given problem, we can use the principle of conservation of momentum to find the direction and magnitude of the owner's velocity.
Let's denote the velocity of the dog as v1 (northward), the velocity of the cat as v2 (eastward), and the velocity of the owner as v (unknown).
According to the conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.
The total momentum before the interaction is given by:
Total momentum before = (mass of the dog * velocity of the dog) + (mass of the cat * velocity of the cat) + (mass of the owner * velocity of the owner)
Mass of the dog (m1) = 24.4 kg
Velocity of the dog (v1) = 2.14 m/s
Mass of the cat (m2) = 5.53 kg
Velocity of the cat (v2) = 3.56 m/s
Mass of the owner (m3) = 78.5 kg
Velocity of the owner (v) = unknown
Total momentum before = (24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v)
The total momentum after the interaction is zero since the owner has the same momentum as the pets taken together.
Total momentum after = 0
Equating the two expressions:
(24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v) = 0
Simplifying the equation:
(52.216 kg·m/s) + (19.6488 kg·m/s) + (78.5 kg * v) = 0
71.8648 kg·m/s + (78.5 kg * v) = 0
Solving for v:
78.5 kg * v = -71.8648 kg·m/s
v = -71.8648 kg·m/s / 78.5 kg
v ≈ -0.916 m/s
Therefore, the direction of the owner's velocity is opposite to the combined velocity of the dog and the cat, and the magnitude of the owner's velocity is approximately 0.916 m/s.
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Prove the formular for calculating attraction
Answers
The formula for calculating attraction is F=GMmr².
Gravitational attractionGravitational attraction is the force of attraction that occurs on all bodies
which have a mass as a result of the force of gravitational force.
The Force is directly proportional to the product of their masses and
inversely proportional to the square of the distance between them.
Gravitational attraction = F=GMmr².
where F is the Force, G is gravitational constant, M and m are masses and r²
is square of the distance between the masses.
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How many hours would it take a plane to fly 1,500 miles if it was moving at a constant speed of 300 miles/hour. Include units!
Brainliest included
Answers
Time= distance / speed
Time= 1,500/ 300
Time= 5
a group of students working in a high school chemistry lab believe they have discovered a new element! how exciting! upon further testing by scientists (with better equipment),it is found that the element contains 74 protons and 110 neutrons.
Answers
Explanation:
From the experiment:
Number of protons = 74
Number of neutrons = 110
Number of protons in an element is the atomic number of the element. It is used to locate and position and element on the periodic table.
For a neutral or uncharged atom, the number of protons is the same as the number of electrons.
The element whose number of protons or atomic number if 74 is Tungsten
Mass number = 74 + 110 = 184g/mol
A small frictionless 8.00 kg cart is released from rest at the top of the hill on a road in a town (assume the hill is perfectly straight and flat, like a ramp). A student is interested in how the motion of the frictionless cart on the hill differs from the motion of a solid cylinder when they are released from rest. The length of the hill from starting point to the ending point is 300 m and the point of release for the cart is 54 m above the ending point.
a.) Determine the acceleration of the cart. (m/s/s)
b.) Determine the time it takes the cart to travel from the starting point to the ending point. (s)
Now, the solid cylinder with the same mass as the cart and a radius of 0.024 m is released from rest at the top of the hill. Assume there is more than enough friction so that the cylinder rolls without slipping.
c.) Determine the acceleration of the cylinder. (m/s/s)
d.) Determine the time it takes the cylinder to travel from the top of the ramp to the bottom. (s)
Answers
a.) The acceleration of the cart can be calculated using the formula g = 9.8 m/s², where g is the acceleration due to gravity. a = F/m = m × g = 4.40 kg × 9.8 m/s² = 43.12 m/s²
b.) The time it takes the cart to travel from the starting point to the ending point can be calculated using the kinematic equation:
d = v_0t + 1/2at²,
366 m - 53 m = 313 m
313 = 0t + 1/2(43.12)t² = 1/2(43.12)t²
313 = 21.56t², t² = 313 / 21.56
t² = 14.52, t = √14.52 = 3.8 sec.
c.) The acceleration of the cylinder can be calculated using the formula a = g - (v²)/Rg
d.) The time it takes the cylinder to travel from the top of the ramp to the bottom can be calculated using the kinematic equation:
d = v_0t + 1/2at²,
What is acceleration?
A type of motion in which an object's velocity changes by an equal amount throughout an interval of equal duration is known as uniform or constant acceleration.To know more about acceleration, click the link given below:
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The net force on a box F as a function of the vertical position y is shown below.
What is the work done on the box from y=0 to 6.0m?
Answers
The work done on the box from y=0 to 6.0m is 120 J.
To calculate the work done on the box from y=0 to 6.0m, we need to find the area under the force vs. position graph over that interval.
First, we can find the work done from 0 m to 2 m. Since the force is constant at 40 N over this interval, the work done is simply:
W = F * d = 40 N * 2 m = 80 J
From 2 m to 6 m, the force is constant at -20 N, so the work done is:
W = F * d = (-20) N * 4 m = -80 J
Note that the negative sign indicates that the work is done by the box on the force (since the force is in the opposite direction of the displacement).
Therefore, the total work done on the box from y=0 to 6.0m is:
W_total = 80 J - 80 J = 0 J
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A wave takes 0.5 seconds to complete one cycle. Which characteristic of the wave does this description represent? A. period B. wavelength C. amplitude D. frequency
Answers
Answer:
period
Explanation:
A wave takes 0.5 seconds to complete one cycle. It is called the time period of the wave. It is the time taken by the wave to complete one cycle.
The relation between the time period and the frequency is given by :
T = 1/f
Where
f is frequency of the wave
Hence, the correct option is (a) "period".
2. For a projectile fired at 0° from a height of 19.6 m, how long does it take it to hit the ground? Remember that g = -9.8 m/s2. Initial velocity of the projectile is 40 m/s. Hint: Sine of 0° is 0 and Cosine of 0° is 1.
Answers
Answer:
\(\huge\boxed{\sf T = 0 \ s}\)
Explanation:
Formula for the time of flight of projectile:\(\displaystyle T=\frac{2v_isin \theta}{g}\)
Given that, θ = 0
So,
sin 0 = 0\(\displaystyle T=\frac{2v_i(0)}{g} \\\\T = \frac{0}{g} \\\\T = 0 \ s\\\\\rule[225]{225}{2}\)
Why is it good that adolescents prune their brains
Answers
Answer:
Synaptic pruning is an essential part of brain development. By getting rid of the synapses that are no longer used, the brain becomes more efficient as you age.
how much work did the movers do horizontally pushing a 46 kg crate 10.3 across a rough floor without acceleration, if the effective coefficient of friction was 0.5
Answers
The work done is 2321 J.
What is the work that is done?We have to note that the acceleration has to do with the change in the velocity of the object with time. We are told that there is a movement of the crate as we can see. Let us note that the work that is done by the object subtracted from the work done by the friction. Thus we have that;
Work = (46 * 9.8 * 10.3) - (0.5 * 46 *9.8 * 10.3)
Work = 4643 - 2321
= 2321 J
The work that has been done is 2321 J. This is done in moving the object
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A 50-cm-long spring is suspended from the ceiling. A 210 g mass is connected to the end and held at rest with the spring unstretched. The mass is released and falls, stretching the spring by 16 cm before coming to rest at its lowest point. It then continues to oscillate vertically.
Answers
The value of spring constant (k) is 25 N/m.
Conservation of energy, potential energy of a stretched spring, gravitational potential energy, frequency of oscillation in a spring coupled to a mass, and variation of acceleration due to gravity with altitude are the principles necessary to answer the given problem.
To begin, use energy conservation to equal change in gravitational potential energy on mass attached to spring and elastic potential energy of stretched spring. Then, in the equation, substitute the specified numbers and solve for the spring constant. Then, calculate the amplitude by taking half of the value of spring stretching from equilibrium, and the frequency of oscillation by using the calculation for frequency of oscillation in a stretched string in terms of mass and spring constant.
Formula apply
U=mgh
U=1/2kx^2
putting the value of K ,x ,mass and g then
k is 25N/m
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How does the energy in a system of magnets change when two magnets repel and move away from each other
Answers
If the wave pictured above oscillates up and down 25 time in 10
seconds, what is the frequency?
Answers
Answer:
Frequency = 25 / 10 = 2.5 Hz
Explanation:
If the wave oscillates up and down 25 times in 10 seconds, then the frequency can be calculated as follows:
Frequency = Number of oscillations / Time
In this case, the number of oscillations is 25, and the time is 10 seconds. Therefore, the frequency is:
Frequency = 25 / 10 = 2.5 Hz
So the frequency of the wave is 2.5 Hertz, which means it completes 2.5 cycles or oscillations in one second.
Calculate the average speed
1) between 0 min and 3 min.
2) between 3 min and 5 min.
3) between 5 min and 10 min
4) between 0 min and 10 min
Answers
Answer:
000000000000000000000000000
A wire loop in the shape of a circle spins in a uniform magnetic field. How does the torque on the loop change if the radius of the wire is doubled at the same time that the current flowing through the wire is quadrupled?
a. It increases by a factor of 2
b. It increases by a factor of 4
c. It increases by a factor of 8
d. t increases by a factor of 16
e. None of the above
Answers
The torque on the loop increases by a factor of 16.
option D.
What is the torque on wire loop?The torque on a wire loop in a magnetic field is given by the equation:
τ = NIABsinθ
Where;
τ is the torqueN is the number of turns in the wire loopI is the current flowing through the wireA is the area of the loopB is the magnetic field strengthθ is the angle between the magnetic field and the normal to the loopIf the radius of the wire is doubled, then the area of the loop becomes four times larger.
Also, if the current flowing through the wire is quadrupled, then the torque becomes four times larger.
The torque on the loop increases by a factor of 4 x 4 = 16.
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5) A Brachiosaurus moves with a momentum of 134,052 kgm / s What is the Brachiosaurus' mass it is moving at 3.9m / s ?
Answers
The mass of Brachiosaurus moves with a momentum of 134,054 kgm/s and the velocity is 3.9 m/s, which is 34.37 kg.
The momentum is the product of mass and velocity. The momentum is the vector quantity and the unit of momentum is Kgm/s.
Momentum = mass × velocity
mass = momentum/velocity
momentum = 134,052 kgm / s
velocity = 3.9 m/s
mass = 134052 / 3.9
= 34.37 kg
Thus, the mass of Brachiosaurus is 34.37 kg.
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Multiple choices. 1)when two groups are playing tug of war the forces of the two groups are:- A)same direction B)opposite direction C)different direction but not possible D)A and B
Answers
Answer:
Explanation:
Multiple choices. 1)when two groups are playing tug of war the forces of the two groups are:- A)same direction B)opposite direction C)different direction but not possible D)A and B
We perform an experiment with a 28 cm rod with a mass of .07 kg swinging from its endpoint. The pendulum is allowed to move freely. The pendulum system is then placed on a cart. From rest of both the cart and the pendulum, the cart is push and the acceleration (a) of the cart and the angle of the pendulum is measured. (1): Justify based on theory the maximum displacement angle observed. (2): Do the same, but what if the rod is hung 8 cm from its endpoint?
Answers
The rod is hung 8 cm from its endpoint instead of 28 cm, the maximum potential energy and thus the maximum angle of displacement will be smaller.
What is Potential Energy?
Potential energy is the energy possessed by an object due to its position or state. It is the energy that can be stored in an object as a result of its position or configuration. The amount of potential energy an object has depends on its position or configuration relative to other objects or systems, as well as the forces acting on it. Potential energy can be converted into other forms of energy, such as kinetic energy or thermal energy, depending on the situation.
The maximum displacement angle observed in a simple pendulum system is directly related to the initial potential energy and the gravitational potential energy of the system. As the pendulum is pulled away from its resting position, it gains potential energy, which is then converted to kinetic energy as it swings back towards the center.
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what is the process that creates wind.
Answers
Answer:
Winds are caused by differences in air pressure. Unequal heating of Earth’s surface creates areas of different pressure. Cooler areas have higher air pressure. Warmer areas have lower pressure. This causes air to move from high pressure to low pressure. This movement is the wind we feel.
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Which of the following phenomena provides evidence for the particle theory of light?
Refraction of light through a prism
Interference patterns produced from light through a double slit
Polarization of light in sunglasses
Ejection of electrons from metals illuminated with different frequencies of light
Answers
Answer:
The ejection of electrons from metals illuminated with different frequencies of light (photoelectric effect)
Explanation:
Ejection of electrons from metals illuminated with different frequencies of light provides evidence for the particle theory of light
What is photoelectric effect ?
The photoelectric effect proves that light has particle-like activity. The photoelectric effect happens when photons are shone on metal and electrons are ejected from the surface of that metal. The electrons that are ejected are determined by the wavelength of light which determines the energy of photons.
correct answer is
Ejection of electrons from metals illuminated with different frequencies of light
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Silver is more costly than iron because it is 1. Heavier 2. Scarcer 3. Whiter 4. Harder 5 ...
Answers
Answer:
scarcer
Explanation:
Silver is more costly than iron because it is scarcer as it is found only in some areas of the country... it's a rare element hence it is scarcer and more expensive..
Calculate the heat change involved when 2,000 g of water is heated from 20 °C to 99.7°C in an electric kettle.
Answers
Q = mcΔT
Where Q is the heat change in joules (J), m is the mass of the water in grams (g), c is the specific heat capacity of water (4.184 J/g°C), and ΔT is the change in temperature in °C.
First, we need to calculate the change in temperature:
ΔT = final temperature - initial temperature
ΔT = 99.7°C - 20°C
ΔT = 79.7°C
Now we can use the formula to calculate the heat change:
Q = mcΔT
Q = (2000 g) x (4.184 J/g°C) x (79.7°C)
Q = 666,268.8 J
Therefore, the heat change involved in heating 2,000 g of water from 20°C to 99.7°C is approximately 666,268.8 J.
A tuning fork of frequency 254 Hz and an open orang pipe of slightly lower frequency are at 15oC. When
sounded together, they produce 4 beats per second. On altering the temperature of the air in the pipes,
it is observed that the number of beats per second first diminishes to zero and then increases again to 4.
By how much has the temperature of the air in the pipe been altered?
Answers
The temperature of the air in the open orang pipe has been altered by 18.73° C
The frequency of an open orang pipe is estimated by using the formula:
\(\mathbf{f = \dfrac{v}{2L}}\)
Then, the combination of the frequency of the tuning fork and the open orang pipe is:
\(\mathbf{254 - \dfrac{v}{2L} }\)
These combinations of frequency produce 4 beats per sound.
i.e.
\(\mathbf{254 - \dfrac{v}{2L} =4}\)
\(\mathbf{ \dfrac{v}{2L} = 254-4 }\)
\(\mathbf{ \dfrac{v}{2L} = 250 ----(1)}\)
When it is altered, the beats first diminish and increase again by 4.
i.e.
\(\mathbf{ \dfrac{v'}{2L} = 254+4 }\)
\(\mathbf{ \dfrac{v'}{2L} = 258 --- (2) }\)
If we equate both equations (1) and (2) together, we have:
\(\mathbf{\dfrac{v'}{v}= \dfrac{258}{250}}\)
However, from our previous knowledge, we understand that the velocity of an object varies directly proportional to the square root of its temperature.
Hence;
when the temperature of the pipe = unknown ???the temperature of the open orang pipe = 15∴
\(\implies \mathbf{\sqrt{\Big(\dfrac{273 + T}{273 + 15}\Big)}= \dfrac{258}{250}}\)
By squaring both sides, we have:
\(\implies \mathbf{\Big(\dfrac{273 + T}{273 + 15}\Big)}= \Big (\dfrac{258}{250}\Big )^2}\)
\(\implies \mathbf{\Big(\dfrac{273 + T}{273 + 15}\Big)= \Big (\dfrac{66564}{62500}\Big )}\)
\(\implies \mathbf{\Big(\dfrac{273 + T}{288}\Big)= \Big (1.065024\Big )}\)
\(\implies \mathbf{273 +T =306.726912 }\)
T = 306.726912 - 273
T ≅ 33.73 ° C
∴
The change in temperature ΔT = 33.73° C - 15° C
The change in temperature ΔT = 18.73° C
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