A bicycle rides in a straight line at 1 km at 10
km/h and then another 1 km at 25 km/h

The lighter block will also accelerate to the right with an acceleration of -0.82 m/s².

(a) μ = 0

The heavier block will accelerate to the right with an acceleration of:

a = F / m = k x / m = (3.70 N/m) (0.0864 m) / 0.261 kg = 1.22 m/s²

The lighter block will also accelerate to the right with an acceleration of 1.22 m/s².

(b) μ = 0.110

The heavier block will accelerate to the right with an acceleration of:

a = F - μk / m = k x / m - μk / m = (3.70 N/m) (0.0864 m) / 0.261 kg - (0.110)(0.261 kg)(9.80 m/s²) = 0.68 m/s²

The lighter block will not accelerate because the force of friction is greater than the force of the spring.

(c) μ = 0.480

The heavier block will accelerate to the right with an acceleration of:

a = F - μk / m = k x / m - μk / m = (3.70 N/m)(0.0864 m) / 0.261 kg - (0.480)(0.261 kg) (9.80 m/s²) = -0.82 m/s²

Therefore, the lighter block will also accelerate to the right with an acceleration of -0.82 m/s².

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Answer:

D

Explanation:

as you can see D may be the answer because the force is being applied strongly to the right side rather then left and moving at constant speed

Answer:

this relationship to be true the value  x ’must be positive, so it must move to the right.

Explanation:

En este ejercicio debemos utilizar la relacion de equilibrio rotacional.

Fijemos un sistema de referencia situado en el eje de jiro del sistema y la rotación antihoraria es positiva.

Las esferas estan a la izquierda y el contrapeso ala derecha

                W d = w_contrapeso  x

donde W es el peso de las esferas de d su distancia hasta eleje de giro

Ahora colocamos la carga negativa debajo de la esfera A, como las cargas son de diferente signo  las dos esferas se atraen, lo que crea una fuerza hacia bajos de magnitud

       F =k q₁ q₂/r²

       F =8,9 10⁹  1 2/ (2d)²

       F = 4,45/d²  N

volvamos escribir la ecuación de equilibrio rotacional con esta fuerza

          F d + W d = W_contrapeso (x+x’)

          (4,45 10⁹ /d²) d + W d = W_conrapeso x+ W contrapesos x’

en la primera ecuación vimos que  dos terminos se igualan ,por lo cual se anulan quedando  

          4,45 10⁹/d = W contrapeso x’

para que esta relación sea cierta el valor e x’ debe ser positivo, por lo cual debe moverse a la derecha.  

Traduction

In this exercise we must use the relationship of rotational equilibrium.

Let's fix a frame of reference located on the system's axis of rotation and the counterclockwise rotation is positive.

The spheres are on the left and the counterweight on the right

                W d = w_counterweight x

where W is the weight of the spheres of d its distance to the turning axis

Now we place the negative charge under sphere A, as the charges are of different sign the two spheres attract, which creates a downward force of magnitude

       F = k q₁ q₂ / r²

       F = 8.9 10⁹ 1  2 / (2d)²

       F = 4.45 / d² N

let's rewrite the rotational equilibrium equation with this force

          F d + W d = W_ counterweight (x + x ’)

          (4.45 10⁹ / d²) d + W d = W_counterweight x + W counterweights x’

In the first equation we saw that two tenunos are equal, which is why they cancel, leaving

          4.45 10⁹ / d = W counterweight  x ’

for this relationship to be true the value  x ’must be positive, so it must move to the right.

Answer:

True Edg2020

Explanation:

Answer: true

Explanation:

because I say so :P

A branch of physics called kinematics, which originated in classical mechanics, defines how points, bodies, and systems of bodies move without taking into account the forces that are responsible for their motion.

Let's go over the four basic kinematic equations of motion with constant acceleration:

s = ut + ½at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where an is acceleration, s is distance, u is beginning velocity, v is final velocity, and t is time.

To determine the horizontal distance traveled in this instance, we first need to determine the time it takes for the ball to fall vertically to the ground.

Knowing u = 0, a = g = 9.81 m/s2, and s = 5 m for the vertical drop, we can use equation (1) to obtain

s = ut + ½at^2

5 = 0 +4.905t^2

t = √(5/4.905) = 1.01s

Now that we have t, we can calculate the horizontal distance.

s = ut + ½at^2

s = 35(1.01) + 0 (no horizontal acceleration) (no horizontal acceleration)

s = 35.35m

The ball thus travels 35.35 meters before striking the ground.

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Answer:

29400 N/m².

Explanation:

Pressure: This is defined as the force acting normally per unit area.

From the question,

P = ρgh........................ Equation 1

Where P = pressure, ρ = density of water, g = acceleration due to gravity, h = height.

Given: h = 3 m.

Constant: g = 9.8 m/s², ρ = 1000 kg/m³

Substitute this values into equation 1

P = 100(9.8)(3)

P = 29400 N/m².

Kirk's use of math skills in organizing, analyzing, and presenting data is essential for the success and integrity of his scientific investigation.

The correct answer is option B.

Kirk is using his math skills to organize and present his data (Option B). Math skills are integral to the scientific investigation process, particularly when it comes to data analysis, interpretation, and visualization. Here's an explanation of how Kirk is using math skills in his investigation:

1. Organizing Data: Kirk likely collects raw data during his investigation, such as measurements, observations, or experimental results. To make sense of this data, he needs to organize it systematically. This involves using math skills to categorize, sort, and arrange the data in a structured manner, such as in tables or spreadsheets.

2. Analyzing Data: Once Kirk has organized his data, he needs to analyze it to draw meaningful conclusions. This often involves applying various mathematical techniques, such as calculating averages, percentages, standard deviations, or performing statistical analyses. These calculations help identify patterns, trends, and relationships within the data, enabling Kirk to make informed interpretations.

3. Presenting Data: Kirk uses his math skills to visually represent his data through graphs, charts, or diagrams. By selecting appropriate types of graphs (e.g., bar graphs, line graphs, scatter plots), he can effectively communicate the relationships and trends observed in the data to others. Additionally, he may employ mathematical principles, such as scaling the axes, determining appropriate intervals, and using labeling or legends, to ensure accurate and clear representation.

4. Drawing Conclusions: Kirk's mathematical skills are crucial in drawing conclusions from his data. He may use mathematical models, equations, or formulas to analyze the data and test hypotheses. By applying mathematical reasoning, Kirk can determine if his data supports or contradicts his initial hypotheses or research questions.

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Answer:

Proper nouns

hope this helps =3

The man moves to the left with a speed of 0.084 m/s (or about 8.4 cm/s) after he throws the shoe to the right.

To solve this problem, we need to apply the law of conservation of momentum, which states that the total momentum of a system is conserved if no external forces act on it. In this case, the man and the shoe form a closed system, and their initial momentum is zero because they are at rest. After the man throws the shoe to the right, the system's momentum remains zero, but the man will move to the left to conserve the momentum.

We can use the formula for momentum, which is given by:

\(p = m .v\)

Where p is momentum, m is mass, and v is velocity.

Before the man throws the shoe, the total mass of the system is:

\(m_{total} = m_{man} + m_{shoe}\\\\m_{total} = \frac{720 N}{9,81 m/s^2} + \frac{4,0 N}{9,81 m/s^2} \\\\m_{total} = 73.4 kg\)

The initial momentum of the system is:

\(p_{initial} = m_{total} . 0\\p_{initial} = 0 kg m/s\)

After the man throws the shoe, the shoe's momentum is:

\(p_{shoe} = m_{shoe} . v_{shoe}\\\\p_{shoe} = \frac{4,0 N}{9,81 m/s^2}. 15 m/s \\\\p_{shoe} = 6.10 kg m/s\)

To conserve the momentum, the man's momentum must be equal and opposite:

\(p_{man} = -p_{shoe}\\p_{man} = -6.10 kg m/s\)

Finally, we can solve for the man's velocity using the formula for momentum:

\(p_{man} = m_{man} . v_{man}\\\\v_{man} = \frac{p_{man}}{m_{man}} \\\\v_{man} = \frac{(-6).10 kg m/s}{\frac{720 N}{9,81 m/s^2} } \\\\v_{man} = -0.084 m/s\)

Therefore, the man moves to the left with a speed of 0.084 m/s (or about 8.4 cm/s) after he throws the shoe to the right.

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Answer:

wait what do you mean? And why is this in physics?

Is this about the iron dome or something biblical?

Explanation:

Answer:

the story of Israel is part of the Bible that's what what you're your lesson is

Explanation:

The image distance (v) is 26.25 cm. We can use the formula for focal length of a concave mirror:  1/f = 1/do + 1/di
Where f is the focal length, do is the object distance, and di is the image distance.

We know that the focal length is 15 cm, and the object distance is 35 cm. Plugging these values into the formula:
1/15 = 1/35 + 1/di
Now we can solve for di:
1/di = 1/15 - 1/35
1/di = (7 - 3)/105
1/di = 4/105
di = 26.25 cm
So the image distance is 26.25 cm.

Using the formula for focal length of a concave mirror, we can calculate that the image distance is 26.25 cm when the object is 35 cm from the mirror. To find the image distance for a concave mirror, you can use the mirror formula:
1/f = 1/u + 1/v
where f is the focal length, u is the object distance, and v is the image distance.
Given the focal length (f) is 15 cm and the object distance (u) is 35 cm, we can substitute these values into the formula:
1/15 = 1/35 + 1/v
To solve for the image distance (v), first find the common denominator and then subtract 1/35 from both sides:
(35 - 15) / (15 * 35) = 1/v
20 / 525 = 1/v
Now, take the reciprocal of both sides to find v:
v = 525 / 20
v = 26.25 cm

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Answer:

18.75 °C

Explanation:

Q = mcΔT

ΔT = Q / (mc)

convert g → kg

200 g = 0.20 kg

ΔT = (1500 J) / (0.20 kg)(400 J/kg·°C) = 18.75 °C

Taking into account the definition of calorimetry,  the increase in temperature is 18.75°C.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

In this way, between heat and temperature there is a direct proportional relationship, where the constant of proportionality depends on the substance that constitutes the body and its mass.

The equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

In this case:

Replacing in the definition of calorimetry:

1500 J= 400  J/(kg °C)× 0.200 g× ΔT

Solving:

1500 J÷ [400  J/(kg °C)× 0.200 g]= ΔT

18.75 °C= ΔT

In summary, the temperature variation is 18.75°C.

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Answer:

75%(TT,Tt,tt) Hope that helps

The next force on the box is approximately 154.17 N, and the kinetic energy of the box is approximately 700.45 J.

To calculate the next force on the box, we need to consider the forces acting on it. The forces involved are the gravitational force, the normal force, and the force of friction.

Given:

Mass of the box (m) = 33.67 kg

Angle of inclination (θ) = 39.8°

Force of friction (F_friction) = 45.83 N

Time (t) = 0.67 s

First, let's calculate the gravitational force acting on the box:

Force_gravity = m * g

Force_gravity = 33.67 kg * 9.8 m/s²

Force_gravity = 330.3 N

Next, we can calculate the component of the gravitational force acting parallel to the ramp:

Force_parallel = Force_gravity * sin(θ)

Force_parallel = 330.3 N * sin(39.8°)

Force_parallel = 200.0 N

The next force on the box will be the difference between the force parallel and the force of friction:

Next_force = Force_parallel - F_friction

Next_force = 200.0 N - 45.83 N

Next_force = 154.17 N

To calculate the kinetic energy of the box, we need to calculate its velocity:

v = g * t

v = 9.8 m/s² * 0.67 s

v = 6.566 m/s

The kinetic energy (KE) of the box is given by the formula:

KE = (1/2) * m * v²

KE = (1/2) * 33.67 kg * (6.566 m/s)²

KE = 700.45 J

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Answer:

Los 11 colores básicos (negro, azul, marrón, gris, verde, naranja, rosa, púrpura, rojo, blanco y amarillo) y los 28 adicionales (turquesa, verde oliva, verde menta, borgoña, lavanda, magenta, salmón, cian, beige, rosado, verde oscuro, verde oliva, lila, amarillo pálido, fucsia, mostaza, ocre, trullo, malva, púrpura

hope that helps bby<3

Answer:

10 millones

Explanation:

En primer lugar, los científicos han determinado que en el laboratorio podemos ver unos 1.000 niveles de luz oscura y unos 100 niveles de rojo-verde y amarillo-azul. Eso es alrededor de 10 millones de colores ahí mismo.

The work required to bring the third charge from very far away to the point P is approximately 36 millijoules (to two significant figures). The units are joules (J).

To calculate the work required to bring the third charge q3 from very far away to the point P, we need to know the electric potential at point P due to the other two charges q1 and q2. The electric potential at point P is given by:

V = kq1/r1 + kq2/r2

U = q3 V

where q3 is the charge of the third charge.

r1 = 0.1 m

r2 = 0.2 m

q1 = -2 μC = -2 × 10^-6 C

q2 = 3 μC = 3 × 10^-6 C

Substituting these values into the electric potential formula, we get:

V = kq1/r1 + kq2/r2

V = (9 × 10^9 N m^2/C^2) × [(-2 × 10^-6 C)/0.1 m + (3 × 10^-6 C)/0.2 m]

V ≈ 9000 V

final = q3 V

final = (4 μC) × (9000 V)

final = 36000 μJ

final = 36 mJ

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The charge contained in a section of the line of length 2.50 cm is 8.87 × 10⁻¹⁰ C.

The formula for electric field intensity of a line charge is given by:E= λ/2πε₀rwhere,λ is the linear charge density of the line.ε₀ is the permittivity of free space.r is the perpendicular distance of the point from the line charge.

Electric field intensity, E = 810 N/CandDistance, r = 0.385 mUsing the above formula, we can find the value of linear charge density of the line.λ = 2πε₀Erλ = 2 × π × 8.85 × 10⁻¹² × 810 × 0.385λ = 3.55 × 10⁻⁸ C/mLength of the section of the line, L = 2.5 cm = 0.025 mWe need to find the charge present in a section of the line of length 2.50 cm.Since the linear charge density of the line is 3.55 × 10⁻⁸ C/m,Charge in a section of the line of length 0.025 m = λLq = λLq = 3.55 × 10⁻⁸ × 0.025q = 8.87 × 10⁻¹⁰ C

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Answer:

2

Explanation:

1+x/4+x = 1/2

4+x = 2 + 2x

x = 2

Answer:

Temperature decreases because fewer air molecules allow the air mass to expand.

Explanation:

Temperature of air mass decreases as it rises . It is so because at upper strata

of atmosphere , air is sparse and therefore air molecules there is relatively less . It results in lower pressure around air mass going up . This results in expansion of gas . Molecules have to do work against mutual attractive force for expansion so their energy becomes less . This cools down the air.

The peak current through the 500 W room heater is approximately 5.89 amperes

we can use the formula for peak current in an AC circuit:

I_p = V_p / R

where I_p is the peak current, V_p is the peak voltage, and R is the resistance of the heater.

We know that the heater has a power rating of 500 W, and operates on 120 V AC power. The RMS voltage of the AC power is given by:

V_RMS = V_p / sqrt(2)

where V_RMS is the RMS voltage.

Therefore:

V_p = V_RMS * sqrt(2) = 120 V * sqrt(2) = 169.7 V (rounded to one decimal place)

The resistance of the heater can be calculated using the formula:

P = V^2 / R

where P is the power and V is the voltage.

Therefore:

R = V^2 / P = 120^2 / 500 = 28.8 ohms

Finally, we can use the formula for peak current to find:

I_p = V_p / R = 169.7 V / 28.8 ohms = 5.89 A (rounded to two decimal places)

Therefore, the peak current through the 500 W room heater is approximately 5.89 A.

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Answer:

0.085m/s²

Explanation:

Use v²=v0²+2a(d)

solve for a

v²-v0²/2d=a

Plug in givens

1.89²-0.78²/2*17.5=a

Plug into calculator

a=0.085m/s²

Answer:

all of the above

Explanation:

because I know

Answer: all of the above

Explanation:

Each answer - choice has a reasonable relevance when using a website.

Answer:

D

Explanation:

It can be moved 0.01 toward the negative plate

Answer:the answer is 18.297m/s

Explanation:

The most scientific guess (hypothesis) based on what is known about the behavior of galaxies is that Galaxies are continuously moving away from each other. This hypothesis can be tested using Hubble's Law.

Hubble's law indicates that almost all galaxies are moving apart from one another because the universe as a whole is expanding. Choose any two galaxies at arbitrarily, and they're most likely traveling apart from each other.

Hubble discovered that galaxies move away from us at a rate proportionate to their distance: more distant galaxies move away faster than closer ones. The accompanying graphic shows Hubble's classic graph of measured velocity vs. distance for neighboring galaxies.

The graph shows a linear relationship between galaxy velocity (v) and distance (d).

The equation for the above linear relationship is:

                                          v = H₀ x d

Where:

H₀ is the expansion rate

v = velocity of the galaxy; and

d = distance.

Using the above formula, the astronomer can measure or test to know whether indeed the new galaxy is moving relative to the Milky Way galaxy and at what rate.

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Where θ 1 is the angle of the first line, and θ 2 is the angle of the second line.

Angle is the measure of a turn or displacement between two intersecting lines. Angles are typically measured in degrees, with 360 degrees in a full circle. acute angles are smaller than 90 degrees, while obtuse angles are larger than 90 degrees. Straight angles are exactly 180 degrees, while reflex angles are greater than 180 degrees.

The equation for the diffraction grating for the sodium is:
nλ = d sinθ
Where n is the order of the spectrum, λ is the wavelength of the light, d is the distance of the spectrum, and θ is the angle of the light.
For the first order, the initial angular position is:
nλ = d sinθ
θ = sin-1 (λ/d)
For the first order, the final angular position is:
nλ = d sinθ
θ = sin-1 (λ/d)
The angular separation of the two closely spaced yellow lines of sodium is:
Δθ = θ 1 - θ 2
Where θ 1 is the angle of the first line, and θ 2 is the angle of the second line.

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Answer: 2

Explanation:

The average force exerted on the ball by the golf club is 490 N.

Thus,  F = p/t = 0.49 * 10³ N = 490 N.

Momentum is a metric for power and how challenging it is to stop an object. Zero momentum applies to any object that is not moving. tremendous, slow-moving objects have tremendous amounts of momentum.

A small, swiftly moving object also possesses a significant momentum. A bowling ball, for instance, has more momentum than a ping-pong ball if their velocities are equal.

This is because bowling balls are larger in mass than ping-pong balls.

Thus, The average force exerted on the ball by the golf club is 490 N.

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