A bicycle is originally priced at $80 the store owner gives a discount in the bicycle is know priced at $60 enter the percent markdown for the cost of the bicycle

Please make your question more specific

Answer:

the solution to the trigonometric inequality cos(0.65x) > 0.44 over the interval 0 ≤ x < 4.834.

Step-by-step explanation:

The given inequality is:

cos(0.65x) > 0.44

To solve this inequality, we need to isolate the variable x.

First, let's take the inverse cosine (arccos) of both sides to remove the cosine function:

arccos(cos(0.65x)) > arccos(0.44)

Since the range of the inverse cosine function is limited to [0, π], we can rewrite the inequality as:

0 ≤ 0.65x < π

Now, let's solve for x by dividing each part of the inequality by 0.65:

0/0.65 ≤ x < π/0.65

Simplifying, we have:

0 ≤ x < π/0.65

Now, let's calculate the approximate value of π/0.65 to determine the interval for x:

π/0.65 ≈ 4.834

i hope i helped!

Answer:

530

Step-by-step explanation:

870-340 = 530

___________

Answer:

7,300

Step-by-step explanation:

6900x2 years=13,800 total tuition.

13800-2500-4000 (2000x2)=7,300

Answer:

Angle ABD= 132 degrees

Step-by-step explanation:

We know this because the angles are supplementary meaning they add up to equal 180.

180-48= 132

Answer:

132

Step-by-step explanation:

i took the test]

Answer:

B is not correct. rational numbers can be negative

Step-by-step explanation:

\( = - 14x + 12\)

\( = - 2 \times 7x + ( - 2) \times 6\)

\( = - 2(7x - 6)\)

No Option Solution.

The scale factor is: 1.8

because of :

\(\frac{36}{20}=1.8\\ \\\\\frac{25.2}{14}=1.8\)

Answer:

m = -3 ; c = 1

Step-by-step explanation:

y = -3x + 1

y = mx + c

m = -3

c = 1

Answer:

v(x)=x^3+2x^2-11x-12

Step-by-step explanation:

Answer:

answer is 390 which is even number

any number you see has 0,2,4,6,8 at the end of a number is considered as an even number.

any number you see has 1,3,5,7,9 at the end of a number is considered as an odd number.

(A) Let A(t) denote the amount (in grams, g) of the chemical present in the pond at time t (in hours, h). The starting amount is unknown; call it a, measured in g, so that A(0) = a.

Water containing 0.01 g/gal of the chemical flows in at a rate of 300 gal/h, which increases the amount of the chemical in the pond at a rate of

(0.01 g/gal) • (300 gal/h) = 3 g/h

and flows out at the same rate, so the amount decreases by

(A(t)/1,000,000 g/gal) • (300 gal/h) = 3A(t)/10,000 g/h

Then the net rate of change of the amount of chemical in the pond is given by the ODE,

dA(t)/dt = 3 - 3/10,000 A(t)

(B) Solve the ODE for A(t). There are several ways to do that. For instance, itt's separable, so we have

dA(t) / (3 - 3/10,000 A(t)) = dt

Integrate both sides to get

-10,000/3 ln|3 - 3/10,000 A(t)| = t + C

Solve for A(t) :

ln|3 - 3/10,000 A(t)| = -3/10,000 t + C

3 - 3/10,000 A(t) = exp(-3/10,000 t + C )

3 - 3/10,000 A(t) = exp(-3/10,000 t ) • exp(C )

3 - 3/10,000 A(t) = C exp(-3/10,000 t )

3/10,000 A(t) = 3 - C exp(-3/10,000 t )

A(t) = 10,000 - C exp(-3/10,000 t )

Since A(0) = a, we have

a = 10,000 - C exp(-3/10,000•0)   →   C = 10,000 - a

→   A(t) = 10,000 - (10,000 - a) exp(-3/10,000 t )

As t grows to infinity, the exponential term will vanish, leaving a limiting amount of 10,000 g of the undesirable chemical in the pond, which does not depend on the original amount.

The only possible value of "a" that satisfies the given equations is a = 5.

The possible values of "a" that satisfy the given equations, let's solve the system of equations:

a + ab = 250 ---(1)

a - ab = -240 ---(2)

We can solve this system by using the method of substitution. Rearranging equation (2), we get:

a = ab - 240 ---(3)

Substituting equation (3) into equation (1), we have:

(ab - 240) + ab = 250

2ab - 240 = 250

2ab = 250 + 240

2ab = 490

ab = 490/2

ab = 245

Now we have the value of "ab."

We can substitute this back into equation (3) to solve for "a":

a = (245) - 240

a = 5

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The fraction of the class that is sophomores is \(35/43\).

The fraction of the class that is sophomores, divide the number of sophomores by the total number of students in the class.

Number of sophomores = 35

Total number of students = 43

Fraction of sophomores = (Number of sophomores)/(Total number of students Fraction of sophomores)

Fraction of sophomores  \(= 35 / 43\)

Therefore, the fraction of the class that are sophomores is = \(35/43\).

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Answer:

m<wzx = 71

Step-by-step explanation:

Assuming these are interior angles of a triangle.

The sum of all three interior angles of a triangle is always 180 degrees, therefore:

m<xyz + m<wxz + m<wzx = 180

Substitute our values:

58 + 51 + m<wzx = 180

m<wzx = 180 - 58 - 51

m<wzx = 71

Answer: 336

Step-by-step explanation:

The numbers are all multiples of 6

Answer: the only thing there is 1x29

Step-by-step explanation: hope it helps

The total cost of the pita bread and hummus dips will be $305.00.

To determine the cost of the pita bread and hummus dips, Toula can use the following expressions:

Cost of pita bread:

Number of crates needed = (150 bags) / (50 bags/crate) = 3 crates

Cost of each crate = $15.00

Total cost of pita bread = (Number of crates needed) × (Cost of each crate) = 3 crates × $15.00/crate = $45.00

Cost of hummus dips:

Number of boxes needed = (65 containers) / (5 containers/box) = 13 boxes

Cost of each box = $20.00

Total cost of hummus dips = (Number of boxes needed) × (Cost of each box) = 13 boxes × $20.00/box = $260.00

Therefore, the expressions Toula can use to determine the costs are:

Cost of pita bread = 3 crates × $15.00/crate

Cost of hummus dips = 13 boxes × $20.00/box

The total cost will be the sum of the costs of pita bread and hummus dips:

Total cost = Cost of pita bread + Cost of hummus dips

Total cost = $45.00 + $260.00

Total cost = $305.00

Therefore, the total cost of the pita bread and hummus dips will be $305.00.

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The temperature at the bottom of the mountain is 50.9 °C.

Let's work through the given information step by step to find the temperature at the bottom of the mountain.

The temperature in the hotel is 21 °C.

The temperature in the hotel is 26.7 °C warmer than at the top of the mountain.

Let's denote the temperature at the top of the mountain as T_top.

So, the temperature in the hotel can be expressed as T_top + 26.7 °C.

The temperature at the top of the mountain is 3.2 °C colder than at the bottom of the mountain.

Let's denote the temperature at the bottom of the mountain as T_bottom.

So, the temperature at the top of the mountain can be expressed as T_bottom - 3.2 °C.

Now, let's combine the information we have:

T_top + 26.7 °C = T_bottom - 3.2 °C

To find the temperature at the bottom of the mountain (T_bottom), we need to isolate it on one side of the equation. Let's do the calculations:

T_bottom = T_top + 26.7 °C + 3.2 °C

T_bottom = T_top + 29.9 °C

Since we know that the temperature in the hotel is 21 °C, we can substitute T_top with 21 °C:

T_bottom = 21 °C + 29.9 °C

T_bottom = 50.9 °C

Therefore, the temperature at the bottom of the mountain is 50.9 °C.

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The time spent higher than 26 meters above the ground is 0.42 minutes. Answer: 0.42

A Ferris wheel is 30 meters in diameter and boarded from a platform that is 4 meters above the ground.

The six o'clock position on the Ferris wheel is level with the loading platform.

The wheel completes 1 full revolution in 2 minutes.

We have to find how many minutes of the ride are spent higher than 26 meters above the ground.

So, let's start with some given data,Consider the height of a person at the six o'clock position = 4 meters

So, the height of a person at the highest point = 4 + 15 = 19 meters (since the diameter is 30 meters, the radius will be 15 meters)

Also, the height of a person at the lowest point = 4 - 15 = -11 meters

Therefore, the Ferris wheel completes one cycle from the lowest point to the highest point and back to the lowest point.

So, the total distance travelled will be = 19 + 11 = 30 meters.

Also, we are given that the wheel completes 1 full revolution in 2 minutes.

We need to calculate the time spent higher than 26 meters above the ground.

So, the angle between the 6 o'clock position and 2 o'clock position will be equal to the angle between the 6 o'clock position and the highest point.

This angle can be calculated as follows:

Angle = Distance travelled by the Ferris wheel / Circumference of the Ferris wheel * 360 degrees

Angle = 30 / (pi * 30) * 360 degrees

Angle = 360 degrees / pi

= 114.59 degrees

So, the total angle between the 6 o'clock position and the highest point is 114.59 degrees.

Now, we need to find out how much time is spent at an angle greater than 114.59 degrees.

This can be calculated as follows:

Time = (Angle greater than 114.59 degrees / Total angle of the Ferris wheel) * Total time taken

Time = (180 - 114.59) / 360 * 2 minutes

Time = 0.42 minutes

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Based on the net present value profile, Project H has a higher NPV than Project E.

To compare the net present value (NPV) of Project E and Project H, we need to calculate the present value of cash flows for each project and determine which one has a higher NPV. The cash flow patterns for the two projects are as follows:

Project E:

Initial investment: -$100,000

Cash flows for Year 1: $40,000

Cash flows for Year 2: $50,000

Cash flows for Year 3: $60,000

Project H:

Initial investment: -$120,000

Cash flows for Year 1: $60,000

Cash flows for Year 2: $50,000

Cash flows for Year 3: $40,000

To calculate the present value of cash flows, we need to discount them using an appropriate discount rate. The discount rate represents the required rate of return or the cost of capital for the company. Let's assume a discount rate of 10%.

Using the formula method, we can calculate the present value (PV) of each cash flow and sum them up to obtain the NPV for each project:

For Project E:

PV = $40,000/(1 + 0.10)^1 + $50,000/(1 + 0.10)^2 + $60,000/(1 + 0.10)^3

PV = $36,363.64 + $41,322.31 + $45,454.55

PV = $123,140.50

For Project H:

PV = $60,000/(1 + 0.10)^1 + $50,000/(1 + 0.10)^2 + $40,000/(1 + 0.10)^3

PV = $54,545.45 + $41,322.31 + $30,251.14

PV = $126,118.90

Using the financial calculator method, we can input the cash flows and the discount rate to calculate the NPV directly. By entering the cash flows for each project and the discount rate of 10%, we find that the NPV for Project E is approximately $123,140.50 and the NPV for Project H is approximately $126,118.90.

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The intervals in which the function is decreasing. \([-\pi , -\frac{\pi }{3} ], [\frac{\pi }{3}, \pi ]\). Option 3

We're given a function f(x) = 2 sin x - x, which describes a curve on a graph. We want to find the intervals where this curve is decreasing (going down) within the range of -π to π.

To find when the function is decreasing, we look at its slope. The slope tells us if the curve is going up or down. We find the slope by taking the first derivative of the function: f'(x) = 2 cos x - 1.

We now have an equation for the slope, f'(x) = 2 cos x - 1. A negative slope means the function is decreasing. So, we want to find where f'(x) is less than 0 (negative).

We set up the inequality: 2 cos x - 1 < 0. We solve it to find the x-values where the slope is negative. The solution is cos x < 1/2.

From the inequality cos x < 1/2, we find the intervals within the range of -π to π where the function is decreasing. These intervals are [-π, -π/3] and [π/3, π].

The above answer is in response to the question below as seen in the picture.

Determine the interval(s) in \([-\pi, \pi ]\) on

which f(x) =  2 sin x - x

is decreasing.

1. \([-\frac{\pi }{3}, \frac{\pi }{3} ]\)

2. \([-\frac{\pi }{6}, \frac{\pi }{6} ]\)

3. \([-\pi , -\frac{\pi }{3} ], [\frac{\pi }{3}, \pi ]\)

4. \([-\pi , -\frac{-2\pi }{3} ], [\frac{2\pi }{3}, \pi ]\)

5. \([-\pi , - \frac{5x}{6} ], [\frac{\pi }{6}, \pi ]\)

6. \([-\frac{\pi }{6}, \frac{5\pi }{6} ]\)

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Let's denote the three numbers A, B, and C.

Given that the highest common factor (HCF) of these three numbers is 8 and their sum is 80, we can consider possible combinations of numbers that satisfy these conditions.

Since the HCF is 8, all three numbers must be divisible by 8. Additionally, the sum of the numbers is 80, so we need to find combinations of three numbers that satisfy both conditions.

Let's list the possible combinations:

These are the four possible sets of three numbers that satisfy the given conditions: (8, 16, 56), (16, 8, 56), (24, 8, 48), and (8, 24, 48).

The slant height of the cone is 12.6 units

What are solids ?

A three-dimensional object that is closed (which may, according to some terminology conventions, be self-intersecting). A solid is any constrained area of space that is bounded by surfaces, according to Kern and Bland (1948, p. 18). The sphere, cube, cone, and cylinder, as well as the polyhedra more broadly, are some of the most basic solids.

h= 12

diameter = d = 8

so, radius, r = d/2 = 8/2 = 4

Formula for slant height , l is:

l = √(h² + r²) = √(12² + 4² )

 = √(144 + 16) = √160 = 12.649 ≈ 12.6 units

The slant height of the cone is 12.6 units

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Answer:

x > 81

In interval notation: (81, ∞)

Step-by-step explanation:

Inequality is
\(\dfrac{X}{9} > 9\)

Multiply both sides by 9:

\(\dfrac{X}{9}\cdot 9 > 9 \cdot 9\\\\\implies X > 81\\\)

The solution set expressed in interval notation is (81, ∞)