A bell produces sound energy at a rate of 4.00*10^-3W and radiates it uniformly in all directions. What is the intensity of the wave 100.0m from the bell?

Considering the definition of weight, on Earth's surface at sea level, the weight of an object with a mass of 180 kg is 1764 N.

Mass is the amount of matter that a body contains and weight is the action exerted by the force of gravity on the body.

The mass of an object will always be the same, no matter where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.

The weight is calculated as the product of the mass of the object and the value of the gravitational acceleration or gravity:

Weight= mass× gravity

The value of the acceleration constant on Earth is 9.8 m/s². The weight is proportional to the mass of the object. The unit of weight is expressed in Newton (N).

In this case, you know:

Replacing on the definition of weight:

Weight= 180 kg× 9.8 m/s²

Solving:

Weight= 1764 N

Finally, on Earth's surface at sea level, the weight of an object with a mass of 180 kg is 1764 N.

Learn more about weight:

https://brainly.com/question/17490356

#SPJ1

The information about weather factors such as temperature, wind speed, humidity, and dew point should be presented to the astronaut in a clear and organized format, possibly using a table or a simple list. This will ensure easy understanding and accurate entry into the computers right before lift-off, thus contributing to a successful launch for NASA (National Aeronautics and Space Administration).

To present the weather information to the astronaut in a clear and concise manner, it is important to use easy-to-read visual aids and simple language. One approach could be to display the weather information on a screen or monitor in a format that is easy to understand, such as a chart or graph. The information should be organized logically and labeled clearly so that the astronaut can quickly find the data they need. Additionally, it may be helpful to provide a brief explanation of how each piece of weather data affects the launch, so that the astronaut can understand the importance of each input. Overall, the goal should be to present the information in a way that is easy to digest and that allows the astronaut to make quick, accurate inputs into the computer system.

Learn more about astronaut here:-

https://brainly.com/question/24262534

#SPJ11

Newton's laws helped him mathematically describe the motion of the planets.

An object in motion will remain in motion unless something acts upon it. Because a planet is moving in an ellipse this law states that there must be some “force” acting upon the planet.

The second law tells how the motion will change when a force acts upon the object. An accelerating object can either change how fast it is moving, the direction it is moving, or both.

The third law describes, when the sun pulls on a planet with the force of gravity, the planet pulls on the sun with a force of equal magnitude. But, because the sun is so much more massive than the planet.

To know more about the Newton's three laws of motion, here

brainly.com/question/8880900

#SPJ4

--The complete question is, Newton's three laws of motion and his law of gravity have helped us better understand and describe the behavior of objects on Earth. How have they also been instrumental in helping us understand the Solar System?

Choose one:

Newton's laws helped prove that we are part of the Milky Way Galaxy.

Newton's laws helped him mathematically describe the motion of the planets.

Newton's laws helped prove that the Sun is at the center of the Solar System.

Newton's laws helped describe the formation of the Solar System.--

The surface area (SA) volume and the surface-sree-to-volume mbi (SAV) of two different sized cubes Surface area (cm^2) Volume (cm^3) Surface-area-to-volume ratio (cm^(-1))  is 2.4/ 0.923

To calculate the surface area (SA), volume, and surface-area-to-volume ratio (SAV) of the two different sized cubes, let's use the following formulas:

Surface Area (SA) of a cube: SA = 6 * (side length)^2

Volume of a cube: V = (side length)^3

Surface-Area-to-Volume ratio (SAV) of a cube: SAV = SA / V

Let's calculate them for the two cubes:

For the 2.5 cm cube:

Side length = 2.5 cm

Surface Area (SA) = 6 * (2.5 cm)^2 = 6 * 6.25 cm^2 = 37.5 cm^2

Volume (V) = (2.5 cm)^3 = 15.625 cm^3

Surface-Area-to-Volume ratio (SAV) = 37.5 cm^2 / 15.625 cm^3 ≈ 2.4 cm^(-1)

For the 6.5 cm cube:

Side length = 6.5 cm

Surface Area (SA) = 6 * (6.5 cm)^2 = 6 * 42.25 cm^2 = 253.5 cm^2

Volume (V) = (6.5 cm)^3 = 274.625 cm^3

Surface-Area-to-Volume ratio (SAV) = 253.5 cm^2 / 274.625 cm^3 ≈ 0.923 cm^(-1)

Placing these values in the table:

Surface area (cm^2) Volume (cm^3) Surface-area-to-volume ratio (cm^(-1))  is(  2.4 cm^(-1))/(0.923 cm^(-1))

To learn more about Volume of a cube  visit: https://brainly.com/question/19891526

#SPJ11

The maximum safe depth of the submarine in saltwater is approximately 446 meters.

Here, the diameter of the window, d = 40 cm, Radius, r = 20 cm. The thickness of the window, t = 8.1 cm. The force that the window can withstand, is F = 1.2 × 106 N. The pressure of the inside of the submarine, P1 = 1.0 atm. Pressure at the maximum safe depth, P2 =?

The water pressure at a depth of h meters can be calculated using the formula: P = hρg + P0 where,ρ = density of salt water = 1025 kg/m3g = acceleration due to gravity = 9.8 m/s2P0 = atmospheric pressure at the surface = 1.013 × 105 N/m2At the maximum safe depth, the force due to the pressure outside the window must be less than or equal to the force the window can withstand.

Therefore, P2 = F/ (πr2) + P1= 1.2 × 106 / [(3.14)(0.2)2] + 1 × 105= 1.14 × 107 N/m2. At this pressure, the depth h can be calculated as follows: 1.14 × 107 = h × 1025 × 9.8 + 1.013 × 105h = 446 meters. Therefore, the maximum safe depth of the submarine in saltwater is approximately 446 meters.

Learn more about pressure here:

https://brainly.com/question/12946544

#SPJ11

Answer:

c

Explanation:

a. To determine the gas volume after the isobaric expansion, we can use the ideal gas law:

PV = nRT

Where P is the pressure, V is the volume, n is the amount of substance (in moles), R is the ideal gas constant, and T is the temperature (in Kelvin).

Since the pressure remains constant during the expansion, we can write:

(V1)(P1) = (V2)(P2)

where V1 and P1 are the initial volume and pressure, respectively, and V2 and P2 are the final volume and pressure, respectively. We can solve for V2:

V2 = (V1)(P1)/(P2) = (5 g)/(28.0134 g/mol)(3.0 atm) x 3 = 6.39 L

Therefore, the gas volume after the isobaric expansion is 6.39 L.

b. To determine the gas temperature after the isobaric expansion and subsequent decrease in pressure at constant volume, we can use the combined gas law:

(P1)(V1)/(T1) = (P2)(V2)/(T2)

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

Since the volume remains constant during the pressure decrease, we can write:

(P1)/(T1) = (P2)/(T2)

Solving for T2:

T2 = (P2)/(P1)(T1) = (1 atm)/(3.0 atm)(293 K) x 20 + 273 = 300.8 K

Therefore, the gas temperature after the isobaric expansion and pressure decrease is 300.8 K (27.65 °C).

For more details about isobaric click here:

https://brainly.com/question/30733197#

#SPJ11

The small-signal resistance of a silicon p-n junction diode biased at 1 mA is approximately 26 ohms.

The small-signal resistance of a p-n junction diode is the reciprocal of the slope of the diode's current-voltage (I-V) curve at a particular bias point. At low bias currents, such as 1 mA, the I-V curve of a silicon p-n junction diode is nearly exponential, and the small-signal resistance is approximately equal to the dynamic resistance of the diode.

The dynamic resistance of a silicon p-n junction diode can be approximated using the following equation:

rd = (n * VT) / ID

where rd is the dynamic resistance in ohms, n is the ideality factor of the diode (typically between 1 and 2 for a silicon diode), VT is the thermal voltage (approximately 26 mV at room temperature), and ID is the bias current in amperes.

Plugging in ID = 1 mA and assuming an ideality factor of 1, we get:

rd = (1 * 26 mV) / (1 mA) = 26 ohms

Therefore, the small-signal resistance of a silicon p-n junction diode biased at 1 mA is approximately 26 ohms.

For more such questions on Small-signal resistance

https://brainly.com/question/31218151

#SPJ11

The horizontal distance traveled  by the snowball is 4.11 m.

your question is not complete, it seems to be missing the following information;

how far does the ball travel horizontally ?

The given parameters;

The time of flight of the snowball is calculated as;

\(h_y = v_0_yt + \frac{1}{2} gt^2\\\\14 = (4\times sin(44))t + 0.5\times 9.8t^2\\\\14 = 2.78t + 4.9t^2\\\\4.9t^2 +2.78t - 14 = 0\\\\solve \ the \ quadratic \ equation \ using \ formula \ method;\\\\a = 4.9, \ b = 2.78 ,\ c = -14\\\\t = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-2.78 \ \ +/- \ \ \sqrt{(2.78)^2 - 4(4.9\times -14)} }{2\times 4.9}\\\\t = 1.43 \ s\)

The horizontal distance traveled  by the snowball is calculated as;

\(X = v_0_x \times t\\\\X = (4 \times cos(44) ) \times 1.43\\\\X = 4.11 \ m\)

Thus, the horizontal distance traveled  by the snowball is 4.11 m.

Learn more here: https://brainly.com/question/15502195

Answer:

Hey, bro here is the explanation....

Explanation:

Hope it helps...

Answer:

D. Electric energy into mechanical energy

Explanation:

hope it helps

#CarryOnLearning

Answer:

The answer for cos(30°) is 0.87

One minute has 60 seconds, One hour has 60 minutes and one day has 24 hours. Thus, 80 x 60 x 24 = 86,400 seconds in a day.

To learn more about days to seconds refer to:

https://brainly.com/question/11947673

#SPJ1

Answer:

3.36 Joules

Explanation:

Work done= Force × distance

F=4.2 N

distance= 0.8 m

work done= 4.2 × 0.8

work done= 3.36 Joules

Answer:

D. Wind and solar energy help save money and reduce air pollution.

Explanation:

Answer:

d

Explanation:

edge 2021

Answer: (a) The magnitude of the magnetic field at a point midway between the two wires is 1.20 × 10⁻⁵ T and the direction of the magnetic field is out of the page.

(b) The magnitude of the magnetic field at a point that is 2.00 m below the point of part (a) is 2.93 × 10⁻⁷ T and the direction of the magnetic field is out of the page.

(a) The magnitude of the magnetic field at a point midway between the two wires is 1.20 × 10⁻⁵ T and the direction of the magnetic field is out of the page.  Between two parallel current-carrying wires, the magnetic field has a direction that is perpendicular to both the direction of current flow and the direction that connects the two wires.

According to the right-hand rule, we can figure out the direction of the magnetic field. The right-hand rule says that if you point your thumb in the direction of the current and curl your fingers, your fingers point in the direction of the magnetic field. As a result, the northern wire's magnetic field is directed up, while the southern wire's magnetic field is directed down. Since the two magnetic fields have the same magnitude, they cancel each other out in the horizontal direction.

The magnetic field at the midpoint is therefore perpendicular to the plane formed by the two wires, and the magnitude is given by: B = (μ₀I)/(2πr) = (4π × 10⁻⁷ T · m/A) × (250 A) / (2π × 0.600 m) = 1.20 × 10⁻⁵ T.

The magnetic field is out of the page because the two magnetic fields are in opposite directions and cancel out in the horizontal direction.

(b) The magnitude of the magnetic field at a point that is 2.00 m below the point of part (a) is 2.93 × 10⁻⁷ T and the direction of the magnetic field is out of the page.

The magnetic field at a point that is 2.00 m below the midpoint is required. The magnetic field is inversely proportional to the square of the distance from the wires.

Therefore, the magnetic field at this point is given by: B = (μ₀I)/(2πr) = (4π × 10⁻⁷ T · m/A) × (250 A) / (2π × √(1.20² + 2²) m) = 2.93 × 10⁻⁷ T. The magnetic field at this point is out of the page since the wires are so far apart that they can be treated as two separate current sources. The field has the same magnitude as the field created by a single wire carrying a current of 250 A and located 1.20 m away.

Learn more about magnetic field : https://brainly.com/question/7645789

#SPJ11

Answer:

The Total Mechanical Energy

The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy. This sum is simply referred to as the total mechanical energy (abbreviated TME).

Thermal energy and mechanical energy describes the sum of potential energy and kinetic energy of objects or systems. Correct option is D.

Potential Energy: This is the energy that an object possesses due to its position or condition. For example, a book placed on a shelf has potential energy because it can potentially fall down. The higher the object is positioned, the more potential energy it has.

Kinetic Energy: This is the energy of motion. An object that is moving has kinetic energy. The kinetic energy of an object depends on its mass and its velocity (speed).

Thermal Energy: This is the energy associated with the random motion of particles within a substance. It's related to temperature and is a form of kinetic energy at the microscopic level.

Mechanical Energy: This is the sum of potential energy and kinetic energy in a mechanical system. In other words, it accounts for both the energy an object has due to its position and the energy it has due to its motion.

To know more about Thermal energy:

https://brainly.com/question/3022807

#SPJ3

a)  The weight of the wagon can be -249.6 N (negative because the force is acting downwards)

b) The x component of the applied force is 410cos(38°) ≈ 318.7 N and the y component is 410sin(38°) ≈ 252.6 N.

c) The normal force acting on the wagon is 436.5 N, which is greater than the wagon's weight. This means there is a net upward force on the wagon, reducing the force of friction.

d), The acceleration of the wagon in the x direction is\(6.505 m/s^2.\)

a) The weight of the wagon can be calculated as:

Weight = mass x gravity

= 45 kg x 9.8 \(m/s^2\)

= 441 N

The angle of the applied force with the horizontal is 380, so the x and y components of the applied force can be calculated as:

F_x = F_applied * cos(380)

= 410 N * cos(380)

= 327.2 N

F_y = F_applied * sin(380)

= 410 N * sin(380)

= -249.6 N (negative because the force is acting downwards)

b) The normal force, N, acting on the wagon can be calculated as:

N = Weight + F_y

= 441 N - 249.6 N

= 191.4 N

The normal force is less than the wagon's weight, which means that the wagon is experiencing a net force downwards. This impacts the kinetic friction force, which will act in the opposite direction to the wagon's motion to resist this downward force.

c) The coefficient of kinetic friction, μ_k, is given as 0.18. The force of kinetic friction, F_k, can be calculated as:

F_k = μ_k * N

= 0.18 * 191.4 N

= 34.452 N

The acceleration of the wagon in the x direction, a_x, can be calculated using Newton's second law, which states that:

ΣF_x = m*a_x

d) The only force in the x direction is the applied force, so we have:

F_x - F_k = m*a_x

Substituting the values, we get:

327.2 N - 34.452 N = 45 kg * a_x

Simplifying:

292.748 N = 45 kg * a_x

a_x = \(6.505 m/s^2\)

Therefore, the acceleration of the wagon in the x direction is\(6.505 m/s^2.\)

Learn more about Newton's second law

https://brainly.com/question/13447525

#SPJ4

Answer:

1. Seat belts stop your tumbling around inside the car if their is a collision. This increases the time taken for the body's momentum to teach zero, and so reduces the force on it.

2. Their is nothing wrong with the assumption, the only thing is that you are not sure if the dash of the car will bring you to a sudden stop or not so you have to use the seat belt.

Answer:

75 west

Explanation:

I think not sure lucky guess

\(velocity = \frac{distance}{time} \)

\( \frac{(30 + 10 + 80) \times 1000}{83 \times 60} \)

\( = 0.024m.{s}^{ - 1} \)

Since the kinetic energy is equal to the potential energy then the speed of the object is √2gh.

The term work refers to the product of force and distance moved by force while energy is the ability to do work. The question is incomplete as the figure is not shown.

We know that the kinetic energy is equal to the potential energy hence;

mgh = 1/2mv^2

gh= 1/2v^2

v = √2gh

Learn more about kinetic energy: https://brainly.com/question/999862

26.0898 rad/s is the angular velocity of a rotor in a blender.

Given

Initial velocity (ω₁) = 55.0 rad/s

Deceleration (α) = -40.7 rad/s²

Angle (θ) = 28.8 rad

Final angular velocity (ω₂) =?

According to the angular kinematic equation

ω₂² = ω₁² + 2αθ

Put the values of ω₁, α, and θ in the equation

We get,
ω₂² = (55)² + 2(₋40.7)(28.8)

ω₂² = √680.68

ω₂ = 26.0898 rad/s

Hence, 26.0898 rad/s is the angular velocity of a rotor in a blender after turning 28.8 rad.

Learn more about angular velocity here https://brainly.com/question/6860269

#SPJ1

Solve the given problem as

v

Convert the given temperatures from celsius to kelvin since we are dealing with gas.

To convert to kelvin, add 273.15 to the temperature in celsius.

T1 = 22 + 273.15 = 295.15 k

T2 = 4 + 273.15 = 277.15 k

V1 = 0.5 L

Let's find the final volume (V2).

To solve for V2 apply Charles Law formula below:

If the charge on one object was doubled and the charge on the other object was tripled then the electrostatic force of attraction between the two charged object will increased by a factor of 6.

The electrostatic force of attraction F between two bodies of charges Q and q is given by the relation,

F = KQq/r²

r is the distance between them.

Now, letter say that the charge on one object was doubled and the charge on the other object was tripled, so, we can write,

Q' = 3Q and q = 2q,

Now, the new force of attraction,

F' = K(3Q)(2q)/r²

Putting F = KQq/r²,

F' = 6F

So, the new force of attraction between the two bodies will be increased by 6 times.

To know more about electrostatic force, visit,

https://brainly.com/question/20797960

#SPJ4

Answer:

The answer is D!

Explanation:

The sentence says it all

Hydrogen bonding does not occur in a pure sample of dimethyl ether.

A hydrogen bond is an interaction between a hydrogen atom bonded to an electron-rich region elsewhere in the same molecule or in a different molecule with a very electronegative atom (like O, N, or F), resulting in an attractive force. However, dimethyl ether contains only C and H atoms, which have low electronegativities and cannot participate in hydrogen bonding, resulting in a repulsive force. In dimethyl ether, hydrogen is bonded to a low electronegative atom (like C), which does not allow for hydrogen bonding to take place.

Learn more about Hydrogen bonding at  brainly.com/question/30885458

#SPJ11

The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

For more such questions on time, click on:

https://brainly.com/question/26046491

#SPJ8

The density of CO at 1140 torr and 75.0°C is 1.44 g/L.
.

To find the density of CO at 1140 torr and 75.0°C, we can use the ideal gas law equation:

PV = nRT

Where P is the pressure in torr, V is the volume in liters, n is the number of moles, R is the ideal gas constant (0.08206 L·atm/mol·K), and T is the temperature in Kelvin.

First, we need to convert the pressure from torr to atm:

1140 torr = 1.50 atm

Next, we need to convert the temperature from Celsius to Kelvin:

75.0°C + 273.15 = 348.15 K

Now, we can rearrange the ideal gas law equation to solve for the density:

n/V = P/RT

To find the density, we need to divide the number of moles (n) by the volume (V). We can assume that we have 1 mole of CO, so n = 1.

Substituting the values we have:

1/V = (1.50 atm)/(0.08206 L·atm/mol·K × 348.15 K)

1/V = 0.0516 L/mol

V = 19.36 L/mol

Now we have the volume, but we need to find the density. Density is mass per unit volume, so we need to find the mass of 1 mole of CO. The molar mass of CO is 28.01 g/mol.

Density = (28.01 g/mol) / (19.36 L/mol) = 1.44 g/L

Therefore, the density of CO at 1140 torr and 75.0°C is 1.44 g/L.

Know more about  density   here:

https://brainly.com/question/1354972

#SPJ11

.