Answer:A)u =4.295m/s , B)a = 29.746m/s² C) F=3,153N
Explanation:
Using the kinematic expression
v² = u² - 2as
where
u = initial velocity
v = final velocity
s = distance
g = acceleration due to gravity .
Given that he reaches a height of 0.940 m above the floor,
the final velocity = 0
Here, acceleration due to gravity is acting in opposite the initial direction of motion. So, a=-9.81 m/s.
v² = u² + 2as
0² - u² = 2 (- 9.81) × 0.940
- u² = 2 × - 9.81 × 0.920
- u² = -18.4428
cancelling the minus in both sides , we have that
u² = 18.4428
u = √18.4428
u =4.295m/s
(b) His acceleration (in m/s2) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.310 m. m/s2
Using v² = u² + 2as
where u = initial speed of basketball player before lengthening = 0 m/s,
v = final speed of basketball player after lengthening = 4.295m/s,
a = acceleration while straightening his legs
s = distance moved during lengthening = 0.310m
v² = u² + 2as
a = (v² - u²)/2s
a = (4.29m/s)² - (0 m/s)²)/(2 × 0.310m)
a = (18.4428 m²/s² - 0 m²/s²)/(0.62 m)
a = (18.4428 m²/s²/(0.62 m)
a = 29.746m/s²
c) The force (in N) he exerts on the floor to do this, given that his mass is 106 kg. N
Force= mass x acceleration.
F = 106 kg X 29.746m/s²
F = 3,153.076 rounded to 3,153N
What is the potential gravitational energy of a 2 kg ball thrown up in the air to a height of 7 m?
Answer:
PE = 137.2931 J
Explanation:
PE = 137.2931 J
Question 3 of 25The pitch of a sound is most closely associated with theof the wave.A. wavelengthO B. amplitudeO C. speedO D. frequencySUBMIT
The pitch of a sound can be determined in sounds that have a distinguished frequency. Therefore, it depends on the frequency.
Answer:
The pitch of a sound is most closely associated with the frequency of the wave
Refer to the Bohr model and the periodic table to answer the following
questions.
Element #2
00
O
o
00
21
What element does this Bohr Model representa
(A) Lithium
B Potassium
Magnesium
(D) Sodium
The Bohr atom model represents the element called Sodium. Thus, the correct option is D.
An atom consists of protons, electrons, and neutrons. Protons and neutrons present inside the atom form the nucleus. The electrons are negatively charged and they revolve around the nucleus.
Atom has mass and atomic number. The mass number of an atom equals the sum of protons and neutrons. The atomic number is the number of protons or electrons. In the periodic table, the elements are arranged in the form of increasing order of protons or electrons.
From the given diagram, the number of electrons revolver around the nucleus is 11. Thus, the atom has 11 electrons or 11 protons is sodium. The Bohr atom model represents the element Sodium.
Hence, the ideal solution is option D.
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Mark throws a ball upward at 64 feet per second. Sean is on top of a building 48 feet in height. He catches the ball on the way down. A) how long was the ball in the air?B)how high did the ball go?
ANSWERS
(a) 3 seconds
(b) 63.66 feet
EXPLANATION
First we have to find how long does it take for the ball to reach its maximum height, which will allow us to find what is that maximum height. That way we will be able to determine the time until Sean catches the ball on the way down.
We know that when the ball reaches its maximum height, its velocity is zero - this is because the ball stops for a moment before changing its direction. Thus we have the final velocity after a time t,
\(v=u-gt\)u is the initial velocity, u = 64 ft/s and g = 9.81m/s². At the maximum height v = 0. But first we have to change the meters into feet, knowing that 1m = 3.28 ft,
\(9.81\frac{m}{s^2}\cdot\frac{3.28ft}{1m}\approx32.17ft/s^2\)Back to the equation for velocity,
\(0=64ft/s-32.17ft/s^2\cdot t_{\max }\)Solving for tmax,
\(t_{\max }=\frac{64ft/s}{32.17ft/s^2}\approx2s\)This means that initially, the ball was in the air for 2 seconds while going upward.
The height of the ball at this time is determined by the equation,
\(y_{\max }=u\cdot t_{\max }-\frac{1}{2}gt^2_{\max }\)Replacing the values,
\(y_{\max }=64\frac{ft}{s}\cdot2s-\frac{1}{2}\cdot32.17\frac{ft}{s^2}\cdot2^2s^2\)\(y_{\max }=63.66ft\)The ball went 63.66 ft before coming down.
Now, Sean catches the ball at a height of 48 feet,
\(63.66ft-48ft=15.66ft\)Sean is 15.66 ft below the maximum height of the ball. We know that when it comes down, the ball has initial velocity of zero - remember it changes its direction, so the vertical displacement is,
\(\Delta y=\frac{1}{2}gt^2_{\text{sean}}\)We have to find the time from the maximum height until Sean catches the ball,
\(t_{\text{sean}}=\sqrt[]{\frac{\Delta y\cdot2}{g}}\)\(t_{\text{sean}}=\sqrt[]{\frac{15.66ft\cdot2}{32.17ft/s^2}}\approx1s\)So if it took 2 seconds for the ball to reach its maximum height and then another 1 second for Sean to catch it, then,
\(2s+1s=3s\)This means that the ball was in the air for a total time of 3 seconds.
Determine the angular momentum of a 74- g particle about the origin of coordinates when the particle is at x = 4.3 m , y = -5.5 m , and it has velocity υ=(3.1i^−8.1k^)m/s .
Find the x -component.
Find the y -component.
Find the z -component.
The x -component of the angular momentum of the particle is 0.99 kgm²/s.
The y -component of the angular momentum of the particle is 3.3 kgm²/s.
The z -component of the angular momentum of the particle is 0.
What is angular momentum?
Angular momentum is the property of any rotating object given by moment of inertia times angular velocity.
Mathematically, the formula for angular momentum is given as;
L = mvr
where;
m is the mass of the objectv is the velocity of the objectr is the radius of the objectThe given parameters include the following;
the velocity of the particle = ( 3.1i - 8.1 k) m/s
the mass of the particle = 74 g = 0.074 kg
the displacement of the particle, x = 4.3 m, y = - 5.5 m
The x -component of the angular momentum of the particle is calculated as;
Lx = 0.074 x 3.1 x 4.3
Lx = 0.99 kgm²/s
The y -component of the angular momentum of the particle is calculated as;
Ly = 0.074 x ( -8.1) x (-5.5)
Ly = 3.3 kgm²/s
The z-component of the angular momentum of the particle is calculated as;
Lz = 0.074 x ( 0 ) x (0)
Lz = 0
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A rigid body is rotating with constant angular speed 3 radians per second about a fixed axis through the points A. (4, 1, 1), B. (2, -1; 0), distances being measured in centimeters. The rotation is in the left-handed sense relative to the direction AB
1, Determine the unit vector pointing in the direction BA.
2, What is the angular velocity () of the of the body?
3, Write the position vector of point P: P .
Find the instantaneous velocity of particle P [hint v = w×r)
4, What is meant by left-handed rotation (left-handed coordinate system)?
5, Write the position vectors of points A and B The rotation axis AB has direction BA. Write the direction BA in terms of the components given above.
1.Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)
2.The angular velocity (ω) of the body is given as 3 radians per second.
3.Without the position of point P given, it is not possible to write the position vector of P.
4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule.
5.Position vector of point A: (4, 1, 1)
Position vector of point B: (2, -1, 0)
The direction vector BA = (-2, -2, -1)
1.To determine the unit vector pointing in the direction BA, we subtract the coordinates of point B from the coordinates of point A and normalize the resulting vector.
The direction vector BA is given by:
BA = (4 - 2, 1 - (-1), 1 - 0) = (2, 2, 1)
To obtain the unit vector in the direction of BA, we divide the direction vector by its magnitude:
|BA| = √(2^2 + 2^2 + 1^2) = √(4 + 4 + 1) = √9 = 3
Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)
2.The angular velocity (ω) of the body is given as 3 radians per second.
3.Without the position of point P given, it is not possible to write the position vector of P. Please provide the position of point P to proceed with the calculation.
4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule. In a left-handed coordinate system, if you curl the fingers of your left hand in the direction of rotation, your thumb will point in the direction of the rotation axis. It is the opposite direction to a right-handed rotation.
5.The position vectors of points A and B are:
Position vector of point A: (4, 1, 1)
Position vector of point B: (2, -1, 0)
The direction vector BA can be obtained by subtracting the coordinates of point A from the coordinates of point B:
BA = (2 - 4, -1 - 1, 0 - 1) = (-2, -2, -1)
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what heavy element was the chernobyl nuclear accelarators supposed to make?
Answer
plutonium
Explanation:
brainliest please
An object with a kinetic energy of 250j has a mass of 32 kg what is the velocity of the object?
Taking into account the definition of kinetic energy, the velocity of the object with a kinetic energy of 250 J and a mass of 32 kg is 3.95 m/s².
Deinition of Kinetic energyKinetic energy is the energy possessed by a body or system due to its movement.
Kinetic energy is defined as the amount of work necessary to accelerate a body of a certain mass and in a position of rest, until it reaches a certain speed. Once the final speed is reached, the amount of kinetic energy accumulated will remain constant, that is, it will not vary, unless another force acts on the body again.
Kinetic energy is represented by the following expression:
Ec = 1/2×m×v²
Where:
Ec is kinetic energy, which is measured in Joules (J).m is mass measured in kilograms (kg).v is velocity measured in meters over seconds (m/s).Velocity of the objectIn this case, you know:
Ec= 250 Jm= 32 kgv= ?Replacing in the definition of kinetic energy:
250 J = 1/2× 32 kg×v²
Solving:
250 J÷ (1/2× 32 kg) = v²
15.625 J÷kg = v²
√15.625 J÷kg = v
3.95 m/s² = v
Finally, the velocity of the object is 3.95 m/s².
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Samir is waiting for a slow reaction to finish. What is the best way to make the reaction go faster?
Question 12 options:
Put it in the fridge where it is cold
Cover it with a blanket so it's dark
Warm it up on the stove
There is nothing you can do to change the speed of the reaction
In general, option c - warming it up on the stove - is often an effective method to increase the reaction rate.
Increasing the temperature of a reaction generally leads to faster reaction rates. This is because higher temperatures provide more thermal energy to the reactant particles, causing them to move faster and collide more frequently. The increased collision frequency and energy lead to more successful collisions and a higher likelihood of effective molecular interactions, which speeds up the reaction. On the other hand, options a and b - putting it in the fridge where it is cold or covering it with a blanket to make it dark - are unlikely to have a significant effect on the reaction rate. While temperature can influence reaction rates, cooling the reaction or making it dark typically reduces the kinetic energy of the particles, resulting in slower reaction rates. Option d - there is nothing you can do to change the speed of the reaction - is not accurate. The reaction rate can be influenced by various factors such as temperature, concentration, catalysts, and surface area, among others. By manipulating these factors, it is often possible to control and change the speed of a reaction. Hence option c, is correct
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What is the typical treatment for Hodgkin's disease?
desensitization treatments, bone marrow transplant, and biopsy
desensitization treatments, chemotherapy, and thymectomy
radiation, biopsy, and desensitization treatments
radiation, chemotherapy, and bone marrow transplant
Answer:
Pretty sure its D.
radiation, chemotherapy, and bone marrow transplant
Explanation:
Radiation, chemotherapy, and bone marrow transplant are the typical treatment for Hodgkin's disease. Therefore, option (D) is correct.
What is Hodgkin lymphoma?Hodgkin lymphoma can be described as a type of lymphoma, in which cancer forms from a specific type of white blood cell known as lymphocytes, where multinucleated Reed-Sternberg cells are present in the lymph nodes.
The most common symptom of Hodgkin's lymphoma is the painless enlargement of lymph nodes. Hodgkin lymphoma can be treated with radiation therapy, chemotherapy, and stem cell transplantation. The treatment generally depends on how advanced cancer has favorable features.
Radiation and chemotherapy drugs increase the risk of other cancers, lung disease, or heart disease over the subsequent decades.
Hodgkin lymphoma can be distinguished from non-cancerous causes of lymph node swelling and from other cancer. Definitive diagnosis is by lymph node biopsy. Blood tests are performed to assess the function of major organs and safety for chemotherapy.
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What kind of reasoning is most often used to form hypotheses?
inductive
deductive
detective
invective
Two 3.24 kg masses are 3.88 m apart on a frictionless table. Each has 96.852 microCoulombs of charge. What is the initial acceleration of each mass if they are released and allowed to move?
Given:
The mass is m1 = m2 = 3.24 kg
The distance between them is r = 3.88 m
The charge on each mass is q1 = q2 = 96.852 micro Coulombs
To find the acceleration of the mass.
Explanation:
The acceleration can be calculated by the formula
\(a=\frac{F}{m}\)The force can be calculated by the formula
\(F=\frac{kq1q2}{r^2}\)Here, k is the Coulomb's constant whose value is
\(k=\text{ 9}\times10^9\text{ N m}^2\text{ /C}^2\)
On substituting the values, the force will be
\(\begin{gathered} F=\frac{9\times10^9\times(96.852\times10^{-6})^2}{(3.88)^2} \\ =5.61\text{ N} \end{gathered}\)The acceleration will be
\(\begin{gathered} a=\frac{5.61}{3.24} \\ =1.73\text{ m/s}^2 \end{gathered}\)Thus, the acceleration of each mass is 1.73 m/s^2
Two planets, Dean and Sam, orbit the Sun. They each have with circular orbits, but orbit at different distances from the Sun. Dean orbits at a greater average distance than Sam. According to Kepler's Third Law, which planet will have a longer orbital period? Group of answer choices Dean Sam Since they both have circular orbits, they will have the same orbital periods. There isn't enough information to tell.
Answer:
The correct answer is Dean has a period greater than San
Explanation:
Kepler's third law is an application of Newton's second law where the force is the universal force of attraction for circular orbits, where it is obtained.
T² = (4π² / G M) r³
When applying this equation to our case, the planet with a greater orbit must have a greater period.
Consequently Dean must have a period greater than San which has the smallest orbit
The correct answer is Dean has a period greater than San
Answer:
According to the law of universal gravitation, any two objects are attracted to each other. The strength of the gravitational force depends on the masses of the objects and their distance from each other.
Many stars have planets around them. If there were no gravity attracting a planet to its star, the planet's motion would carry it away from the star. However, when this motion is balanced by the gravitational attraction to the star, the planet orbits the star.
Two solar systems each have a planet the same distance from the star. The planets have the same mass, but Planet A orbits a more massive star than Planet B.
Which of the following statements is true about the planets?
A.
Planet B will keep orbiting its star longer than Planet A.
B.
Planet A has a longer year than Planet B.
C.
Planet A orbits its star faster than Planet B.
D.
Planet B is more attracted to its star than Planet A.
Explanation:
Classify the different devices as to first-, second-, or third-class levers.%0D%0A%0D%0A %0D%0A broom
According to the question, the different devices as to broom is a first-class lever.
What is broom?Broom is an implement used for sweeping. It consists of a set of bristles attached to a long handle. Brooms have been used for centuries to keep floors and other surfaces clean. The bristles are usually made from plant fibers or plastic. They are also sometimes made from metal or wire. Brooms can be used to sweep up dirt and dust, collect small particles, and even push larger items. They are perfect for quick cleanups and can be used on almost any type of floor or surface. They are also great for removing cobwebs and other debris from corners and other hard-to-reach places. Brooms are a convenient and easy-to-use tool that can help keep your home or workspace clean.
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Please hellpppppppppppppppp thank you
Answer:
Heres on ex.
When the driver of a bus applies brake suddenly, the lower part of the body comes to rest as the bus comes to rest but, the upper part of the body continues to move forward due to inertia of motion.
Explanation:
ECONOMICS !!!!
Which situation best illustrates the concept of absolute advantage?
O A. The total value of Japanese imports is greater than the total value
of the country's exports.
O B. A German factory can build more sports cars than foreign
factories.
O C. Most of the world's largest companies have operations in many
different countries.
D. A French restaurant buys food from nearby farms to support the
local economy
Answer:
B
Explanation:
Absolute advantage is the capability of a commercial entity to produce goods using fewer resources compared to rivals. Using the same inputs, an entity with an absolute advantage produces a larger output compared to competitors. It means the firm has a lower marginal cost of production. Therefore, its products will have the lowest prices in the market.
The best example of absolute advantage is when a German plant produces more sports cars than a foreign factory. So, the correct option is B.
What is Absolute advantage?A company's capacity to manufacture items with fewer resources than competitors is known as absolute advantage. An organization with just an absolute advantage generates more output in comparison to rivals with the same inputs. It indicates that the company's marginal cost of manufacturing is lower. As a result, its products will be the most affordable on the market.
Absolute advantage in economics refers to a party's capacity to deliver a service or product more effectively than its rivals. Adam Smith, a Scottish economist, originally introduced the idea of comparative advantages in 1776 while discussing international trade and utilizing labor as the sole input.
Therefore, the correct option is B.
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Is frictional force the only example of non-conservative force?
Answer: NO, there are many examples of non-conservative forces.
Explanation: Conservatives forces are special forces whose work is zero in a closed path.
Magnetic and Electric fields are Non- Conservative.6. During an impact time casting 5 x 10-45 a gulf club exerts an average impar
force of 5000N on the ball. What linear impulse is delivered to the ball as a result?
Answer:
2.5 × 10-⁴¹ Ns
Explanation:
Impulse
I = F × t
I = 5000 N × 5 × 10-⁴⁵ s
I = 25 × 10-⁴² Ns
I = 2.5 × 10-⁴¹ Ns
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Which equation describes the sum of the vectors plotted below?
The equation describes the sum of the vectors plotted below is: \(\vec{r} = 4 \vec{x}+2 \vec{y}\)
What is vector quantity?A physical quantity that has both directions and magnitude is referred to as a vector quantity.
A lowercase letter with a "hat" circumflex, such as "û," is used to denote a vector with a magnitude equal to one. This type of vector is known as a unit vector.
According to the final position of the vector as shown in the figure, The final x co-ordinate is 4 and the final y co-ordinate is 2.
the equation describes the sum of the vectors plotted below is: \(\vec{r} = 4 \vec{x}+2 \vec{y}\)
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If a 9000kg water flows in a minute through a pipe of cross sectional area 0.3m², what is the speed of water in the pipe?
Answer:
5 m/s
Explanation:
We are given that 9000 kg of water flows through the pipe in 1 minute. Mass flow rate = mass/time
So, mass flow rate = 9000 kg / 1 minute = 150 kg/s
We know the cross sectional area of the pipe is 0.3 m2. From continuity equation, mass flow rate = density * area * velocity
So, 150 = 1000 * 0.3 * v (Density of water is approximately 1000 kg/m3)
Solving for v (velocity):
v = 150/(1000*0.3) = 5 m/s
Therefore, the speed of water in the pipe is 5 m/s.
i
e. network executives make hasty
When winding an old clock, it is important not to overwind it. Over-
winding occurs when the mainspring is almost fully wound, but the
operator continues to turn the winding key. This causes the main
spring to coil too tight, and might even break it.
110. This paragraph best supports the statement that
a. clocks have changed over the years.
b. old-fashioned clocks become fragile with age.
c. old-fashioned clocks were operated by an internal spring.
d. overwinding clocks used to be a common mistake.
e. time flies when you're having fun.
The paragraph primarily discusses the concept of overwinding old clocks and its consequences, indicating that overwinding clocks used to be a common mistake. Here option D is the correct answer.
The paragraph explains that overwinding occurs when the mainspring is almost fully wound, but the operator continues to turn the winding key, resulting in the spring coiling too tightly or even breaking.
This suggests that overwinding was a mistake commonly made in the past when operating old-fashioned clocks. The other options, such as clocks changing over the years or clocks becoming fragile with age, are not directly addressed in the paragraph and are therefore less supported.
The option e. "time flies when you're having fun" is unrelated to the paragraph and can be disregarded as an irrelevant answer choice. Hence option D is the correct answer.
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A student is provided with a rubber cylinder and a patch of synthetic fur. The rubber cylinder and the patch are electrically neutral. The student rubs the cylinder back and forth along the fur. A short time later, after the cylinder and fur have been placed on insulating stands, the student determines that the fur has a net negative electric charge. Before the patch of fur attained its net negative charge, it was considered to be electrically neutral. Which of the following claims, with appropriate evidence, is correct about the distribution of charge in the patch of fur before the charging process?
a. It is an isolated system.
b. It is a closed system.
c. It is an open system.
d. The type of system cannot be determined unless information is known about the net force exerted on the system at any given time.
Answer:
Option b ( It is a closed system) is the appropriate answer.
Explanation:
The mass transfer isn't made on a platform. There seems to be no mass transfer, the mechanism can't be separated as power lines will interfere beyond the physical boundaries including its fur patch.The mechanism can't however be separated and, while the mass transfer is indeed not present, several field lines will communicate well outside the mechanism.The other options are not linked to the situation in question. Thus, the answer is correct.
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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a cell phone is released from the top with the speed of 10ms what is the speed 3s after?
Answer:
30ms
Explanation:
you need to multiple the 10ms by 3s which gives you 30ms
if a projectile travels in the air for 6 seconds when does the projectile reach its highest point
This question deals with projectile motion, which is a motion on both the x-axis and y-axis, simultaneously. The total time of flight of the projectile trajectory is given, while the time to reach the highest point of the projectile is required to be found.
The projectile will reach the highest point in "3 seconds".
The total time of flight of a projectile is the time during which the projectile remains in the air. For a projectile motion that ends up on the same horizontal level, from where it started, the time to reach the highest point, is equal to half of the total time of flight.
In other words, the projectile motion takes the same time, to go from the starting level to the highest point (i.e upward motion), as the time taken to reach the starting level from the highest point (i.e downward motion).
\(t = \frac{1}{2}T\)
where,
t = time to reach the highest point = ?
T = total time of flight = 6 seconds
Therefore,
\(t - \frac{1}{2}(6\ seconds)\)
t = 3 seconds
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Two concurrent forces have maximum resultant of 45N anda minimum resultant of 5N.What is magnitude of each of these forces
Hi
Please help on question asap if the answer is correct I'll rate you five stars a thanks and maybe even brainliest!
When two light bulbs are connected in series, the resistance in the circuit is increase compared to that with one lightbulb. The increased resistance opposes the flow of current so far fewer electrons pass per second , transferring less energy. The lightbulbs are therefore not as bright as In a circuit with same voltage but only one bulb.
However, when Two lightbulbs are connected in parallel, each loop behaves like a separate circuit . The resistance in each branch is the same as if there were just one light bulb in the whole circuit.there is the same current in each branch of the circuit ,so the bulbs Will light up with the same brightness as a single bulb circuit. The energy stored in the battery will decrease twice as quickly and battery will run out faster than I series circuit.
6) explain the advantages and disadvantages of arranging components in series or parallel.
You are sitting on a Ferris wheel moving at a constant speed of 8 m/s. When you are at the bottom of the rotation, what is the normal force of the seat on you if you have a mass of 50 kg and the radius of the Ferris wheel is 10 m
Answer:
40NExplanation:
Formula for calculating normal force is expressed as:
\(F = ma\\since \ a = \frac{v^2}{r} \\F = \frac{mv^2}{r}\)
m is the mass of the body = 50kg
v is the velocity of the Ferris wheel = 8m/s
r is the radius of the Ferris wheel
Substitute into the formula:
\(F = \frac{50 \times 8}{10}\\ F = \frac{400}{10}\\ F = 40N\\\)
Hence the normal force of the seat is 40N
A car moving at a speed of 23 m/s travels around a curve with a circular curvature 42.1 m in diameter. Determine the acceleration (in m/s/s) of the car
The acceleration of the car moving with a velocity of 23 m/s is 25.13 m/s².
What is acceleration?Acceleration is the rate of change of velocity.
To calculate the acceleration of the car, we use the formula below.
Formula:
a = v²/r..................Equation 1Where:
a = Acceleration of the carv = Velocity of the carr = Radius of the curveFrom the question,
Given:
v = 23 m/sr = 42.1 m = 21.05 mSubstitute these values into equation 1
a = (23²)/21.05a = 25.13 m/s²Hence, the acceleration of the car is 25.13 m/s².
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A ball of mass M and speed of V collides head on with a ball of mass 2M and a speed of v/2, as
shown above. If the two balls stick together, their speed after the collision is
Answer:
2/3V
Explanation:
Given that a ball of mass M and speed V collides with another ball of mass 2M and velocity v/2 . After collision they stick together and we need to find their speed after collision . According to Law of Conservation of Momentum , The total momentum of the system before and after collision is constant .That is ;
\(\sf\qquad\longrightarrow m_1u_1+m_2u_2=m_1v_1+m_2v_2\\ \)
\(\sf\qquad\longrightarrow MV + 2M\bigg(\dfrac{V}{2}\bigg) = (2M + M)(v)\\ \)
\(\sf\qquad\longrightarrow MV +MV= 3Mv\\\)
\(\sf\qquad\longrightarrow 2MV = 3Mv\\ \)
\(\sf\qquad\longrightarrow v =\dfrac{2M}{3M}V\\ \)
\(\sf\qquad\longrightarrow \pink{ v_{after\ collision}=\dfrac{2}{3}V }\)
Hence the velocity after the collision ia 2/3V .