Newton's Laws of motion describe the motion of an object based on the applied force the relationships between the forces is the the option;
Fball on bat = Fbat on ball
Reason:
Force exerted on the bat by the ball =
Force exerted on the ball by the bat =
Given that the batter hits the ball with the bat, the force exerted by the bat on the ball is reacted to by the force of the ball acting on the bat,
Newton's Law of Motion:
Newton's Laws of Motion are the three fundamental laws of classical mechanics that describe the relationship between the motion of an object and the forces acting on it. These laws can be explained as follows:
(1) A body remains at rest or moves with constant speed in a straight line, unless it is subjected to a force.
(2) When an object is subjected to a force, the rate of change with time of its momentum is equal to the force.
(3) If two bodies exert forces on each other, the forces are equal in magnitude but opposite in direction
According to Newton's third law of motion, action and reaction are equal and opposite. Therefore, at the moment when the ball hits the bat, we have;
on bat = on ball
Complete Question:
A baseball thrown by a pitcher is hit by a batter. At the moment when the ball hits the bat, the force exerted on the bat by the ball is Fball on bat and the force exerted on the ball by the bat is Fbat on ball The relationship between these forces is
A. Fball on bat = -Fbat on ball
B. Fball on bat = -Fbat on ball
C. Fball on bat < Fbat on ball
D. Fball on bat > Fbat on ball
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A single-turn current loop, carrying a current of 3.66 A, is in the shape of a right triangle with sides 50.0,101. and 113 cm. The loop is in a uniform magnetic field of magnitude 65.9mT whose direction is paraliel to the current in the 113 cm side of the loop. What is the magnitude of the magnetic force on (a) the 113 cm side, (b) the 50.0 cm side. and (c) the 101 cm side? (d) What is the magnitude of the net force on the loop?
a. The force on the 113 cm side is 0N. b. The force on the 50.0 cm side is 0.120N. c. The 101 cm side force is 0.234N . d. The magnitude of the net force on the loop is 0.354 N
The magnitude of the magnetic force on each side of the loop can be determined using the formula F = I * L * B * sin(θ), where I is the current, L is the length of the side, B is the magnetic field magnitude, and θ is the angle between the magnetic field and the side of the loop. The net force on the loop can be obtained by summing the individual forces acting on each side.
(a) To calculate the magnitude of the magnetic force on the 113 cm side, we use the formula F = I * L * B * sin(θ). The current (I) is 3.66 A, the length (L) is 113 cm, the magnetic field magnitude (B) is 65.9 mT (converted to Tesla by dividing by 1000), and the angle (θ) is 0 degrees since the magnetic field is parallel to this side. Therefore, the force on the 113 cm side is F = 3.66 * 1.13 * 0.0659 * sin(0°) = 0 N.
(b) Similarly, for the 50.0 cm side, the force can be calculated using the same formula, but the length is 50.0 cm and the angle θ is 90 degrees since the magnetic field is perpendicular to this side. Thus, the force on the 50.0 cm side is F = 3.66 * 0.5 * 0.0659 * sin(90°) = 0.120 N.
(c) For the 101 cm side, the angle θ is also 90 degrees, so the force is F = 3.66 * 1.01 * 0.0659 * sin(90°) = 0.234 N.
(d) To find the net force on the loop, we sum the individual forces: 0 + 0.120 + 0.234 = 0.354 N.
Therefore, the magnitude of the net force on the loop is 0.354 N.
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In lab we applied the conservation of energy to a system to allow us to equate the initial energy to the final energy. How does the initial energy become stored in the system?.
The initial energy becomes stored in the system by the tension in the string.
What is energy in physic?Energy is the capacity to do work. Energy cаn exists in mаny different forms. Аll forms of energy аre either kinetic or potentiаl. The energy аssociаted with motion is cаlled kinetic energy. The energy аssociаted with position is cаlled potentiаl energy. Potentiаl energy is not "stored energy". Energy cаn be stored in motion just аs well аs it cаn be stored in position.
А tension force is а force developed in а rope, string, or cаble when stretched under аn аpplied force. It is the force generаted when а loаd is аpplied аt the ends of аn object, normаlly to the cross-section of it. It cаn аlso be cаlled the pulling force, stress, or tension. This type of force is only exerted when there is contаct between а cаble аnd аn object. Tension аlso аllows force to be trаnsferred аcross relаtively lаrge distаnces.
Your question is incomplete, but most probably your full options were
a. The energy is supplied by the tension in the string.
b. The energy is part of the mass.
c. The force of Gravity does work on the mass when it is displaced some height when the pendulum is displaced by some angle theta.
d. I did work on the mass by dispacing it some height when I displaced the pendulum by some angle theta.
Thus, the correct option is A.
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Which is one piece of evidence of seafloor spreading? help :(
Answer:
Mid ocean ridges are evidence of sea floor spreading as tectonic movement opens a gash or "fault" in the ocean floor.
Answer:
Eruptions of molten material, magnetic stripes in the rock of the ocean floor, and the ages of the rocks themselves; this evidence led scientists to look again at Wegener's hypothesis of continental drift.
base your answer to the question on the information given. a 1,000-kilogram car traveling with a velocity of 20 meters per second decelerates uniformly at -5.0 meters per second^2 until it comes to rest. what is the total distance the car travels as it decelerates to rest?
Answer:
40 meters
Explanation:
To solve this, we will use the motion formula \(v^{2} =u^{2} +2as\), where v is the final speed, u is the initial speed, a is the acceleration, and s is the distance. We know:
u= 20m/s
a= - 5m/s^2 (note the minus sign because we are decelerating)
v= 0m/s (our final speed will be 0 because we want to come to a stop)
Now plug in these values into the formula:
\(v^{2} =u^{2} +2as\)
\(0^{2} =20^{2} +2(-5)s\)
\(0 =400-10s\)
\(10s=400\)
\(s=40\\\)
Pairs of magnets are shown in the diagram. Bar magnets lined up vertically side by side in pairs. The first pair is labeled W with the north pole beside the south pole of the second. The second pair is labeled X and vertical with the north pole of one near the north pole of the other. The third pair is labeled Y with the south pole of one near the north pole of the other. The last pair is labeled Z and are lined up side by side. The south pole of one is beside the north pole of the second. Which pair of magnets is aligned so they will repel each other?
Answer:
X
North and South attract. North and North repel and same for South and South. It has to do with the positive electrons in the North and negative in the south.
Explanation:
B ON EDG:)
BARAINLIEST?
Any pair in which like poles face each other, there will be a repulsion.
What is magnetic field?The term magnetic field refers to the region of space in which the influence of a magnet is felt. Magnets have a north and south pole. Like poles of a magnet repel while the unlike poles of a magnet attract.
We do not have the images shown here so we don't know for sure which pair will repel but any pair in which like poles face each other, there will be a repulsion.
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Polly is pushing a box across the floor with a force of 30 N. The force of gravity is -8 N, and the normal force is 8 N. Whichvalue could describe the force of friction if Polly could not move the box?a. -30 Nb. 8Nc. 8Nd. 30 N
The force of friction that prevents Polly from moving the box is -30 N (option a).
To understand why the force of friction is -30 N, we need to examine the forces acting on the box. Since the box is not moving, the net force acting on it must be zero, according to Newton's first law of motion. The forces involved are:
1. Polly's pushing force: 30 N
2. Force of gravity: -8 N
3. Normal force: 8 N
4. Force of friction: Unknown
To find the force of friction, we must balance the forces in both the vertical and horizontal directions. In the vertical direction, the normal force (8 N) and force of gravity (-8 N) cancel each other out. In the horizontal direction, Polly's pushing force (30 N) must be counteracted by an equal and opposite force of friction. Therefore, the force of friction is -30 N, as it acts in the opposite direction to Polly's pushing force.
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An issue the students encountered is that the marble doesn't land on the launch pad all of the time. To remedy this, they consider constructing a funnel to help direct the marble. How do you suggest the students move forward with their design process in order to find a solution?
A Test funnels of the same size and material with varying sized openings.
B Test funnels of the same shape and size with varying materials.
C Test funnels with identical openings and material with varying size.
D Test all of the above funnels and then construct a funnel with the best design elements from each.
I suggest that the students move forward with option A.
Test funnels of the same size and material with varying sized openings. This will allow them to determine the optimal size for the opening that will help direct the marble to the launch pad. Once they have determined the optimal size, they can move forward with constructing the funnel with that size opening.
In physics, the displacement of a moving body represents its change in position over time while accelerating. - Given initial velocity Vo in m/s, acceleration a in m/s2, and elapsed time t in s, the displacement of the body is: - Displacement = Vot+ 1/2 at2 Write a method displacement that accepts Vo, a, and t and computes and returns the change in position. - example: displacement (3.0, 4.0, 5.0) returns 65. 0 22
The method "displacement" calculates and returns the change in position of a moving body with initial velocity (Vo), acceleration (a), and elapsed time (t) using the formula: Displacement = Vot + 1/2 at^2.
The displacement of a moving body can be determined using the equation: Displacement = Vot + 1/2 at^2. Here's a step-by-step explanation of how to compute the change in position:
Begin by multiplying the initial velocity (Vo) by the elapsed time (t): Vot.
Next, calculate the term 1/2 at^2 by multiplying the acceleration (a) by half of the square of the elapsed time: (1/2) * a * t^2.
Add the two computed values together: Vot + (1/2) * a * t^2.
The resulting value is the displacement, representing the change in the position of the body over time while accelerating.
For example, let's consider the input values Vo = 3.0 m/s, a = 4.0 m/s^2, and t = 5.0 s:
Displacement = (3.0 * 5.0) + (1/2 * 4.0 * 5.0^2)
= 15.0 + (1/2 * 4.0 * 25.0)
= 15.0 + (2.0 * 25.0)
= 15.0 + 50.0
= 65.0 m.
Therefore, for the given example, the displacement of the moving body is 65.0 meters.
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An ice pack is used to cool 0.25 kg of water. The specific heat capacity of water is 4.2kJ/(kg°C).
How much thermal energy (heat) must the ice pack extract from the water to reduce the water temperature by 15°C?
Answer:
The ice pack must extract 15.75 kJ of thermal energy from the water to reduce its temperature by 15°C.
Explanation:
The amount of thermal energy (heat) required to change the temperature of a substance is given by the equation:
Q = m * c * ΔT
Where Q is the amount of thermal energy, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature of the substance.
In this problem, we know the mass of the water (m = 0.25 kg), the specific heat capacity of water (c = 4.2 kJ/(kg°C)), and the change in temperature (ΔT = -15°C, since the temperature is decreasing). We want to find the amount of thermal energy (Q) that the ice pack must extract from the water to achieve this temperature change.
Plugging in the values, we get:
Q = (0.25 kg) * (4.2 kJ/(kg°C)) * (-15°C)
Q = -15.75 kJ
Since the temperature is decreasing, the thermal energy (heat) must be negative. Therefore, the ice pack must extract 15.75 kJ of thermal energy from the water to reduce its temperature by 15°C.
Alfredo makes a diagram to organize his notes about charging objects.
Which statement should he place in the region marked X?
It does not involve touching the objects together.
The objects develop opposite charges.
Electrons do not move between objects.
The objects have the same charge.
The region marked X in the diagram shows that the objects have the same charge.
What is conduction?
The term conduction has to do with the manner of charging in which charge is passed from one object to another. Induction involves charging objects without the objects touching each other.
The region marked X in the diagram shows that the objects have the same charge.
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Answer:
D
Explanation:
Which example is of researcher bias in interpreting data?
A scientist wishes to determine the area of an ice sheet. To do so, he relies on spectrographic images sent by satellite.
A health official investigates the spread of HIV in her city. She takes a census of the HIV status of every adult resident.
A geologist wants to determine whether the water level of an aquifer is declining. To find the answer, he digs a well.
A researcher seeks to prove that babies smile at two months old. She counts some confused expressions as smiles.
Answer:
A researcher seeks to prove that babies smile at two months old. She counts some confused expressions as smiles.
Explanation:
This is the answer because its not actual date due to the fact she's using her opinion to decided whether or not the expression a baby is making is a smile, whereas the other answers had factual data involved.
The _____________ experiences a temperature increase primarily due to the absorption of gamma rays and X-rays.
Answer:
The thermosphere experiences a temperature increase primarily due to the absorption of gamma-rays and X-rays.
Release an object from a distance of 2 meters. If the object reaches the ground at a speed of 20 m / s. Find the acceleration of the object?
Applicate formula:
Vf² = Vo² + 2ad
Clearing a:
a = (Vf² - Vo²) / 2d
Replacing:
a = ((20 m/s)² - 0 m/s)²) / 2 * 2 m
a = 400 m²/s² / 4 m²
a = 100 m/s²
The aceleration is 100 m/s²
What is the momentum of a 72 kg baseball player who slides into home plate
at 4.9 m/s?
A. 860 kg m/s2
B. 350 kg m/s
C. 68 kg m/s
D. 15 kg/m's
SUBMIT
Answer:
B) 350 kg m/s
Explanation:
momentum or p is given by the equation p= mxv
We have the mass and velocity so we can use the equation directly
p= 72kg x 4.9 m/s
p= 352.8 kg m/s
Find the distance an object traveled if a force of 350 n acted on it to produce 0 work?
Force(F) = 350 N
Work (W)= 0 J
Apply the formula:
Work = Force x Distance
Isolate distance(d)
Distance = Work/ Force
d = W/F = 0 /350 = 0 m
The distance that the object traveled is 0 (zero)
PLEASEEE HELPPP!!!!
A mover slides a refrigerator weighing 650 N at a constant velocity across the floor
a distance of 8.1 m. The force of friction between the refrigerator and the floor is
230 N. How much work has been performed by the mover on the refrigerator?
Answer: The work is 1863 N*m
Explanation:
We can define work as:
W = F*d
Where F is the force that the mover needs to apply to the refrigerator, and d is the distance that the refrigerator is moved.
To move the refrigerator, the minimal force that the mover needs to do is exactly the friction force (In this case, the refrigerator will move with constant speed).
Then we will have:
F = 230 N
and the distance is 8.1 meters, then the work will be:
W = 230N*8.1 m = 1863 N*m
what converts electrical energy into mechanical energy?
An electric motor is an electrical machine that converts electrical energy into mechanical energy.
It works on the principle of electromagnetic induction, where a current-carrying conductor placed in a magnetic field produces a mechanical force.
Electric motors are commonly used in applications such as household appliances, power tools, and vehicle propulsion systems. They come in a variety of sizes and power ratings, and are used in industrial, automotive, and consumer applications. The most common type of electric motor is the induction motor, which utilizes a rotating magnetic field to produce torque.
Other types of electric motors include brushless DC motors, direct current motors, and synchronous motors. Electric motors are able to generate high torque even at low speeds, making them efficient for a variety of applications. Their versatility and easy maintenance make them popular for both consumer and industrial applications.
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An ant travels 50.0 cm East, then turns 35 degrees North of East and moves for 40.0 cm. It then turns and moves another 30 cm North. What is the ant's total displacement (magnitude and direction)?
Please help :) I will also post questions similar to this so if you know how to solve them go ahead and look :)
The magnitude of ant's total displacement is 96.23 cm in a direction 41 degrees North of East.
What is the total displacement of the ant?The total displacement of the is obtained by resolving the displacement of the ant into x and y components as shown below.
horizontal displacement (x) = d cosθ
vertical displacement (y) = d sinθ
where;
θ is the direction of the displacementd is the magnitude of the displacementFirst displacement at 50 cm East; (θ = 0⁰)
x = 50 cm x cos(0) = 50 cm
y = 50 cm x sin(0) = 0
second displacement at 40 cm at 35 degrees North of East;
(θ = 90⁰ - 35⁰ = 55⁰)
x = 40 cm x cos(55) = 22.94 cm
y = 40 cm x sin(55) = 32.77 cm
third displacement at 30 cm North; (θ = 90⁰)
x = 30 cm x cos(90) = 0
y = 30 cm x sin(90) = 30 cm
Net horizontal displacement;
∑x = 50 cm + 22.94 cm + 0 = 72.94 cm
Net vertical displacement;
∑y = 0cm + 32.77 cm + 30 cm = 62.77 cm
The total displacement is calculated as;
D = √[ (∑x)² + (∑y)² ]
D = √[ (72.94)² + (62.77)² ]
D = 96.23 cm
The direction of the total displacement;
θ = arc tan (Σy/Σx)
θ = arc tan (62.77/72.94)
θ = 40.7⁰ ≈ 41⁰
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ii) a 920-kg sports car collides into the rear end of a 2300-kg suv stopped at a red light. the bumpers lock, the brakes are locked, and the two cars skid forward 2.8 m before stopping. the police officer, estimating the coefficient of kinetic friction between tires and road to be 0.80, calculates the speed of the sports car at impact. what was that speed?
When the 920-kg sports car collides into the rear end of the 2300-kg SUV stopped at a red light, both vehicles experience an equal and opposite force due to the law of conservation of momentum. The bumpers lock and the brakes are locked, causing both cars to skid forward 2.8 m before coming to a complete stop. The coefficient of kinetic friction between the tires and road is estimated to be 0.80 by the police officer. To calculate the speed of the sports car at impact, we can use the formula for kinetic energy: KE = 0.5mv^2, where m is the mass of the sports car and v is its speed. The kinetic energy of the sports car is equal to the work done by the frictional force to bring it to a stop. Therefore, KE = work done = frictional force x distance. The frictional force is equal to the weight of the SUV times the coefficient of kinetic friction, or Ff = m*g*μ = 2300*9.81*0.80 = 18048 N. Therefore, KE = 18048 N x 2.8 m = 50534.4 J. Solving for v, we get v = sqrt(2KE/m) = sqrt(2*50534.4/920) = 28.3 m/s or 101.8 km/h. The speed of the sports car at impact was approximately 101.8 km/h.
A 920-kg sports car collides into the rear end of a 2300-kg SUV stopped at a red light. After the collision, the bumpers lock and both vehicles skid forward 2.8 m before stopping. To find the speed of the sports car at impact, we can follow these steps:
1. Calculate the combined mass of the cars (m_total) after the collision:
m_total = m_sports_car + m_suv = 920 kg + 2300 kg = 3220 kg
2. Use the work-energy principle to determine the initial kinetic energy (KE_initial) of the cars:
KE_initial = work_done_by_friction = friction_force * distance_skidded
3. Calculate the friction force (F_friction) using the coefficient of kinetic friction (μ_k) and the normal force (F_n), which is equal to the total weight of the cars:
F_friction = μ_k * F_n = μ_k * (m_total * g)
F_friction = 0.80 * (3220 kg * 9.81 m/s^2) = 25296.12 N
4. Calculate the work done by friction:
work_done_by_friction = F_friction * distance_skidded = 25296.12 N * 2.8 m = 70869.14 J
5. Find the initial kinetic energy of the sports car:
KE_initial = 1/2 * m_total * v^2
6. Solve for the initial velocity (v) of the sports car:
v^2 = 2 * KE_initial / m_total
v = sqrt(2 * 70869.14 J / 3220 kg) = sqrt(43.978 m^2/s^2) = 6.63 m/s
So, the speed of the sports car at impact was approximately 6.63 m/s.
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What is another name for coal, natural gas, and oil? (two words)
The answer is fossil fuel
its formed from the remains of ancient plants and animalHope it helps!
The answer is fossil fuel
A piano has a mass of 99 kg. What is the weight of the piano?
Explanation:
weight of the piano = mg
w = 99 x 10 =990 N
You arrive in science class 45 seconds after leaving math which is 90 meters to the south. What is your velocity?
Explanation: Well, If you arrive in my class 45 seconds after leaving math, which is 90 meters away. you traveled 2m/s ( I hope this helped <3)
A) the wind is blowing directly towards the wind turbine at a speed of 12 m/s. at this wind
speed, 7500 kg of air passes every second through the circular area swept out by the
blades.
() calculate the kinetic energy of the air travelling at 12m/s, which passes through
the circular area in 1 second.
The kinetic energy of the air travelling at 12m/s, which passes through
the circular area in 1 second is 5.4 x 10⁵ J.
What is kinetic energy?The kinetic energy of an object is associated with its motion. It can be related to the mass and velocity as
K.E = 1/2 mv²
Given the wind is blowing directly towards the wind turbine at a speed of 12 m/s. At this wind speed, 7500 kg of air passes every second through the circular area swept out by the blades.
Substitute the values, we have
K.E = 1/2 x 7500 x (12)²
K.E = 5.4 x 10⁵ J
Hence, the kinetic energy of the air travelling at 12m/s, which passes through the circular area is 5.4 x 10⁵ J.
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what’s the equation for this
A projectile launched at an angle of 45 degrees above the horizontal travels through the air. Compared to the projectile's theoretical path with no air friction, the actual trajectory of the projectile with air friction is
A.) lower and shorter
B.) higher and shorter
C.) lower and longer
D.) higher and longer
Answer: A
Explanation:
A car is initially sliding backwards down a hill at -25 km/h. The driver guns the car. By the time the car's velocity is +35 km/h, it is +3.2 m from its starting point. Assuming the car was uniformly accelerated, find the acceleration. I NEED THIS WITH STEPS
Answer:
7.2375m/s^2
Explanation:
initial velocity=-25 km/h=-6.94m/s
final velocity=35 km/h=9.72m.s
distance=3.2m
v^2=u^2+2as
9.72^2=-6.94^2+2a*3.2
94.48=48.16+6.4a
(94.48-48.16)/6.4=a
7.2375m/s^2
Where does internal radiation come from?
☁️ Answer ☁️
Internal radiation exposure hazards result from radioactive material that gets inside the body when you breathe it
Hope it helps.
Have a nice day hyung/noona!~  ̄▽ ̄❤️
A brass measuring tape is correct at 20°C. The value obtained when the length of a field is measured with the rule at 50°C appears to be 70.5 m. What is the true length of the field? Linear expansivity of brass = 1.8 x 10-5 K-1,
Answer:
A 2kg block is moved a long a level floor by a horizontal force of 20N if the coefficient of sliding friction is 0.4
what is the acceleration of the blove
What must be known to determine the direction of the magnetic force on a change? Check all that apply.
What we must know to determine the direction of the magnetic force on a charge are;
The type of the charge.The direction of the magnetic field.The velocity of the charge.How to find the direction of magnetic force?The magnetic force is the force of attraction or repulsion that emerges between electrically charged particles since of their movement.
From right hand rule, to determine the direction of the magnetic force on a charge, we must know;
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El espectro visible en el aire está comprendido entre la longitud de onda 450 nm del color azul, Determina la velocidad de propagación.
Answer:
v = 2,99913 10⁸ m / s
Explanation:
The velocity of propagation of a wave is
v = λ f
in the case of an electromagnetic wave in a vacuum the speed that speed of light
v = c
When the wave reaches a material medium, it is transmitted through a resonant type process, whereby the molecules of the medium vibrate at the same frequency as the wave, as the speed of the wave decreases the only way that they remain the relationship is that the donut length changes in the material medium
λ = λ₀ / n
where n is the index of refraction of the material medium.
Therefore the expression is
v = \(\frac{\lambda_o}{n} f\)
Let's look for the frequency of blue light in a vacuum
f =\(\frac{c }{\lambda_o}\)
f = \(\frac{3 \ 10^8}{450 \ 10^{-9}}\)
f = 6.667 10¹⁴ Hz
the refractive index of air is tabulated
n = 1,00029
let's calculate
v = \(\frac{450 \ 10^{-9} }{1.00029} \ 6.667 \ 10^{14}\)450 10-9 / 1,00029 6,667 1014
v = 2,99913 10⁸ m / s
we can see that the decrease in speed is very small