A ball on a string is swung in a horizontal circle at a constant speed of 4.3m/s. The centripetal acceleration of the ball is 24.7 m/s^2. The mass of the ball is 3.2kg.

What is the length of the string?

Please show all work thank you so much!

The only moon in our solar system to spin in a direction opposite of its planet's rotation is Triton. Triton is the largest moon of Neptune and has a retrograde orbit, meaning it orbits in the opposite direction of Neptune's rotation. This makes Triton unique among the large moons in our solar system.

There are a few theories about how Triton came to be in a retrograde orbit. One theory is that Triton was once a dwarf planet that was captured by Neptune's gravity. Another theory is that Triton and Neptune formed together from the same cloud of dust and gas.

Whatever the reason for Triton's retrograde orbit, it is a fascinating and unique object in our solar system.

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'''In a series circuit, the sum of the voltages consumed by each individual resistance is equal to the source voltage. Components connected in parallel are connected along multiple paths so that the current can split up; the same voltage is applied to each component.''

Answer: Pitch of the sound depends on the frequency of the sound wave. The pitch is affected by the source of production of sound wave. It also depends on the shape of the medium in which it travels.

Explanation:

Answer:

D. A contrast between the power of a black hole and the power of a whirlpool is being made.

Answer:

D

Explanation:

The speed at which a 1300 kg compact car has the same kinetic energy as a 1.70×\(10^4\) kg truck going 25.0 km/h is 157 km/h.

Kinetic energy (KE) is directly proportional to the square of the velocity of an object, i.e., KE ∝ v². So we can use this formula to determine the speed of the compact car that has the same kinetic energy as the truck.

The kinetic energy of the truck can be found using the formula KE = (1/2)mv², where m is the mass of the truck and v is its velocity.

KE of truck = (1/2)(1.70×\(10^4\) kg)\((25.0 km/h)^2\) = 5.31×\(10^6\) J

Now we can set the kinetic energy of the compact car equal to the KE of the truck and solve for the velocity of the car:

KE of car = (1/2)(1300 kg)

v² = 5.31×\(10^6\) J

V² = (5.31×\(10^6\) J) / (0.5 x 1300 kg) = 8184.62

v = √(8184.62) ≈ 90.43 m/s

Converting to km/h:

90.43 m/s x (3600 s/1 h) x (1 km/1000 m) ≈ 325.55 km/h

Therefore, the speed at which a 1300 kg compact car has the same kinetic energy as a 1.70×\(10^4\) kg truck going 25.0 km/h is 157 km/h (rounded to the nearest whole number).

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Answer:

He should report his findings to a reputable science journal.

The change in the momentum of the bus is 10600 kg-m/s, if bus of 1600 kg crashes with a SUV of 600 kg.

The mass of the bus, m₁ = 1600 kg

The mass of the SUV, m₂ = 600 kg

Initial velocity of the bus, v₁ = 10 m/s

initial velocity of the SUV, v₂ = 0 (at rest)

Velocity of the bus after collision, v₃ = 3 m/s

Velocity of the SUV after collision, v₄ = 1 m/s

The change in momentum(Δp) is given by,

Δp = (m₁v₁ + m₂v₂) - (m₁v₃ + m₂v₄)

Δp = (1600 × 10 + 600 × 0) - (1600 × 3 + 600 × 1)

Δp = 16000 - 5400

Δp = 10600 kg-m/s

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Answer: 9.79m/s2

Explanation: Just did a quiz with this question

The activity of the source in Becquerel is 333.3Bq

The number of nuclei that disintegrate or decay per unit time is known as Activity.

Given that a sample of radioactive material emits 400000 particles over a period of 20 minutes.

Activity A = dN/dt

A = 400000 / 1200

A = 333.3 particles / s

A = 333.3 Bq

Therefore,

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Answer:

X: Absorbs energy from the core.

Y: Releases energy to the photosphere.

Explanation:

Convection is a mode of heat transfer through fluids (liquids or gas), and it requires material medium for its propagation.

The energy absorbed from the core of the Sun, is transferred through X (convection zone) by convectional process, and it flows to Y (radiative zone). Since the regions X and Y have different functions, the heat propagates from X causing photons to traverse through Y where it get released into the photosphere or the Sun's surface.

Therefore;

X: Absorbs energy from the core.

Y: Releases energy to the photosphere.

Answer:

X: Takes longer for photons to move through

Y: Releases energy to the photosphere

Explanation:

Answer:

Explanation:The Hertzsprung-Russell Diagram is a graphical tool that astronomers use to classify stars according to their luminosity, spectral type, color, temperature and evolutionary stage. Stars in the stable phase of hydrogen burning lie along the Main Sequence according to their mass.

hoped this helped

Answer:

87 km/h

Explanation:

720/90=8 8 Hours

285/95=3 3 hours

720-285=435 436 km left

8-3=5 5 hours left

435/5=87

87 km/H

Answer:

9.39 m/s

Explanation:

Using the y-direction, we can solve for the time t it takes for the cart to reach the ground.

Assume the up direction is positive and the down direction is negative.

Find the constant acceleration equation that contains these four variables.

Substitute known values into this equation.

Multiply and simplify.

Divide both sides of the equation by -4.9.

Square root both sides of the equation.

Now we can use this time t and solve for v₀ in the x-direction. Time is most often our link between vertical and horizontal components of projectile motion.  

List out known variables in the x-direction.

Find the constant acceleration equation that contains these four variables.

Substitute known values into the equation.

Multiply and simplify.

Divide both sides of the equation by 3.194382825.

The cart was rolling at a velocity of 9.39 m/s (initial velocity) when it left the ledge.

Answer:

9.39 m/s

Explanation:

Using the y-direction, we can solve for the time t it takes for the cart to reach the ground.

Assume the up direction is positive and the down direction is negative.

v₀ = 0 m/s

a = -9.8 m/s²

Δy = -50 m

t = ?

Find the constant acceleration equation that contains these four variables.

Δy = v₀t + 1/2at²  

Substitute known values into this equation.

-50 = (0)t + 1/2(-9.8)t²

Multiply and simplify.

-50 = -4.9t²

Divide both sides of the equation by -4.9.

10.20408163 = t²

Square root both sides of the equation.

t = 3.194382825

Now we can use this time t and solve for v₀ in the x-direction. Time is most often our link between vertical and horizontal components of projectile motion.  

List out known variables in the x-direction.

v₀ = ?

t = 3.194382825 s

a = 0 m/s²

Δx = 30 m

Find the constant acceleration equation that contains these four variables.

Δx = v₀t + 1/2at²  

Substitute known values into the equation.

30 = (v₀ · 3.194382825) + 1/2(0)(3.194382825)²

Multiply and simplify.

30 = v₀ · 3.194382825

Divide both sides of the equation by 3.194382825.

v₀ = 9.391485505

The cart was rolling at a velocity of 9.39 m/s (initial velocity) when it left the ledge.

The book value of the car washing machine at the end of year 3 would be $3,266.66.

The book value of an asset at the end of its useful life can be calculated using the MACRS depreciation method. MACRS stands for Modified Accelerated Cost Recovery System, which is a tax depreciation method used in the United States.

To calculate the book value at the end of year 3, we need to know the depreciation rate for a 3-year asset under MACRS. The depreciation rate for a 3-year asset is 33.33% for each year.

Using this depreciation rate, we can calculate the depreciation expense for each year. In this case, the machine cost $9,800. So, the depreciation expense for year 1 would be $9,800 * 33.33% = $3,266.67. Similarly, the depreciation expense for year 2 would be $9,800 * 33.33% = $3,266.67.

To find the book value at the end of year 3, we need to subtract the total depreciation expense for the first 3 years from the original cost of the machine. The total depreciation expense for 3 years would be $3,266.67 + $3,266.67 = $6,533.34.

Therefore, the book value at the end of year 3 would be $9,800 - $6,533.34 = $3,266.66.

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Answer:

Her linear velocity on the outer edge is 3 m/s

Her rotational velocity, is constant at 2 RPM

Explanation:

The given parameters are;

The radius of the rotating platform = r

The linear velocity  v(t) = 1 m/s

The position Emily is riding = 1/3 the distance from the center

The rotational velocity = 2 RPM = 2 Revolutions per minute

The formula for angular velocity, ω is given as follows;

ω = θ/t

Where;

θ = The angle rotated

t = The time taken for the rotation

Given that the rotational velocity = 2 RPM

1 revolution = 2·π radians

The angular velocity, ω = 2×π×(2 RPM) = 4·π rad/min = 4·π/60 rad/seconds

ω = 4·π/60 rad/seconds

The linear velocity, v = r₁×θ/t = r₁×ω

Where;

r₁ = 1/3 × r

v = 1 m/s = 1/3 × r  × 4·π/60 rad/seconds

∴ r = 1/(1/3 × 4·π/60) = 45/π meters

r = 45/π meters

Therefore her linear velocity, v₂ and her rotational velocity if she moves to the outer edge will be given as follows;

v₂ = r × ω = 45/π × 4·π/60 = 3 m/s

Her linear velocity on the outer edge, v₂ = 3 m/s

Her rotational velocity, remains at 2 RPM.

The ratio of the greater intensity to the smaller intensity is 3.16.

The ratio of the greater intensity to the smaller intensity can be calculated using the formula:

I1/I2 = 10^(ΔL/10)where I1 is the greater intensity, I2 is the smaller intensity, and ΔL is the difference in sound level in decibels (dB).Given that two sounds differ in sound level by 5.00 dB, we can use the above formula to find the ratio of the greater intensity to the smaller intensity.

Using the formula: I1/I2 = 10^(ΔL/10)I1/I2 = 10^(5.00/10)I1/I2 = 10^(0.50)I1/I2 = 3.16

Therefore, the ratio of the greater intensity to the smaller intensity is 3.16.

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Answer:

B

Explanation:

your answer is B. 2. 5 m/s to the left

A student with a mass of 50 kg is standing in a canoe the initial velocity of the canoe is 2.5 m/s to the left. The correct option is option (B).

Given that the mass of the student is 50 kg, the mass of the canoe is 30 kg, and the velocity of the student is 1.5 m/s to the right, we can calculate the velocity of the canoe.

Before the jump, the total momentum is the sum of the momentum of the student and the momentum of the canoe, since they are initially at rest.

Total momentum before the jump = (mass of the student + mass of the canoe) × (initial velocity)

= (50 + 30) × 0 = 0

After the jump, the total momentum is the sum of the momentum of the student and the momentum of the canoe.

Total momentum after the jump = mass of the student × velocity of the student + mass of the canoe × velocity of the canoe

Total momentum after the jump = (50 ×  1.5) + (30 × velocity of the canoe)

0 = (50 × 1.5) + (30 ×  velocity of the canoe)

-75  = 30 ×  velocity of the canoe

velocity of the canoe = -75  / 30 = -2.5 m/s

Therefore, the initial velocity of the canoe is 2.5 m/s to the left. Hence, the correct option is (B).

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i hate this question.

Conservation of momentum - is when the total momentum before and after collision is equal.

Here is the formula darling,

p = p

mv = mv

See the pic for example. HmpH

Answer: Through a series of collisions between the gas molecules and dust particles, this material became organized in the form of a circumstellar disk. The circumstellar disk is where the planets formed. ... Not shown, eventually the star blows away the excess gas and some of the dust to become visible.

Explanation: Google

Answer:

It can be reused in another star because the law of conservation of matte states that matter is neither created nor destroyed.

Explanation:

hope this helps

Answer:

the branch currents are as follows:

  top left: I2 = 0.625 A

  middle left: I1 = 2.500 A

  bottom left: I1-I2 = 1.875 A

  top center: I2+I3 = 2.500 A

  bottom center: I2+I3-I1 = 0 A

  right: I3 = 1.875 A

Explanation:

You can write the KVL equations:

Top left loop:

  I2(4) +(I2 +I3)(2) +I1(1) = 10

Bottom left loop:

  (I1-I2)(4) +(I1-I2-I3)(2) +I1(1) = 10

Right loop:

  (I2+I3)(2) +(I2+I3-I1)(2) = 5

In matrix form, the equations are ...

  \(\left[\begin{array}{ccc}1&6&2\\7&-6&-2\\-2&4&4\end{array}\right]\cdot\left[\begin{array}{c}I_1\\I_2\\I_3\end{array}\right] =\left[\begin{array}{c}10\\10\\5\end{array}\right]\)

These equations have the solution ...

  \(\left[\begin{array}{c}I_1\\I_2\\I_3\end{array}\right] =\left[\begin{array}{c}2.500\\0.625\\1.875\end{array}\right]\)

This means the branch currents are as follows:

  top left: I2 = 0.625 A

  middle left: I1 = 2.500 A

  bottom left: I1-I2 = 1.875 A

  top center: I2+I3 = 2.500 A

  bottom center: I2+I3-I1 = 0 A

  right: I3 = 1.875 A

_____

This can be worked almost in your head by using the superposition theorem. When the 5V source is shorted, the 10V source is supplying (I1) to a circuit that is the 4 Ω and 2 Ω resistors in parallel with their counterparts, and that 2+1 Ω combination in series with 1 Ω for a total of a 4Ω load on the 10 V source. That is, I1 due to the 10V source is 2.5 A, and it is nominally split in half through the upper and lower branches of the circuit. There is no current flowing through the (shorted) 5 V source branch.

When the 10V source is shorted, the 5V source is supplying a 4 +4 Ω branch in parallel with a 2 +2 Ω branch, a total load of 8/3 Ω. This makes the current from that source (I3) be 5/(8/3) = 15/8 = 1.875 A. There is zero current from this source through the 1 Ω resistor.

Nominally, the current from the 5V source splits 2/3 through the 2 Ω branch and 1/3 through the 4 Ω branch.

Using superposition, I2 = I1/2 -I3/3 = (2.5 A/2) -(1/3)(15/8 A) = 0.625 A. This is the same answer as above, without any matrix math.

  (I1, I2, I3) = (2.5 A, 0.625 A, 1.875 A)

__

It helps to be familiar with the formulas for resistors in series and parallel.

Answer:

C

Explanation:

(C) Positively charged particles moved upward, causing the top of the rod to have a positive charge and the bottom of the rod to have a negative charge.

When a neutral and non-polarized conducting rod moves through a magnetic field, it will experience a force known as the Lorentz force. This force acts on the moving charges within the rod, and causes them to move perpendicular to both the direction of motion and the magnetic field. In this case, since the rod is moving to the right, and the magnetic field is pointing into the screen, the Lorentz force will act upward on the positively charged particles within the rod. This motion will cause a separation of charges in the rod, with the top having a positive charge and the bottom having a negative charge.

If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.

To find the mass of ore, the given values are,

The radius of the lead sphere is r = 7.0 cm,

The lead can be extracted with, η = 92.5% = 0.925 efficiency.

Density is the substance's mass per unit of volume.

We know the density of lead as,

⇒ p = 11.4 g/cm³ .

The volume of the lead sphere is,

V = 4/3πr³

   = 4/3π(7)³

V = 1436.7 cm³.

Mass of the lead present in the lead sphere is,

m = p . V

    = 11.4  × 1436.7

    = 16379 g

m = 16.379 kg

From the expression of efficiency, we calculate the mass of the ore,

η = Mass of lead obtained / Mass of the ore to be taken

0.925 = 16.379 kg / Mass of the ore to be taken

Mass of the ore to be taken = 17.707 kg

If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.

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Answer:

The AMOUNT of oxygen and carbon atoms released by photosynthesis are EXACTLY EQUAL to the atoms of these material contained in carbon-dioxide converted. In this way photosynthesis has conserved the mass or material, and in this way followed the law of conservation of mass.

Answer:

Explanation:

A capacitor is an electronic component that stores and releases electrical energy. It consists of two conductive plates separated by an insulating material called a dielectric. When a voltage is applied across the plates, charge accumulates on them, creating an electric field between the plates.

The capacitance of a capacitor is a measure of its ability to store charge. It is typically represented by the symbol 'C' and is measured in farads (F). In your case, you mentioned a 55-μF (microfarad) capacitor, indicating its capacitance value.

When a voltage waveform is applied across a capacitor, the capacitor charges and discharges in response to the changes in voltage. The rate at which the capacitor charges and discharges depends on the capacitance and the resistance in the circuit

Since there is no figure provided in the text, I am unable to reference it for the specific details of the voltage waveform. However, I can explain the general behavior of a capacitor when a voltage waveform is applied.

When a voltage waveform is applied across a capacitor, the capacitor charges and discharges in response to the changes in voltage. The behavior of the capacitor is determined by its capacitance, which is given as 55 μF in this case.

As the voltage waveform varies, the capacitor stores and releases electrical charge. During the rising portion of the waveform, the capacitor charges and accumulates energy. During the falling portion, the capacitor discharges and releases the stored energy.

The exact behavior and characteristics of the voltage waveform and the charging/discharging process depend on the specific shape and frequency of the waveform. Without the specific details of the voltage waveform provided in the figure, it is challenging to provide a more detailed analysis.

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Atp, or Adenosine triphosphate, provides energy for nerve impulse conduction, muscle contraction, and many other chemical reactions necessary for life.

Adenosine triphosphate is an essential molecule in cellular energy production such as protein phosphorylation and RNA production. It is produced during photophosphorylation and cellular respiration, and is consumed by many enzymes in the catalysis of numerous chemical processes.

It is composed in the center of the molecule by: a five-carbon sugar (ribose), which binds to the nitrogenous base adenine and a chain of three phosphates. Its molecular formula is C₁₀H₁₆N₅O₁₃P₃

It is the science or branch of biology that studies the structure of living beings in their evolutionary stages. Anatomy is subdivided into: plant and animal.

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Answer:

asteroid belt

Explanation:

The asteroid belt is a torus-shaped region in the Solar System, located roughly between the orbits of the planets Jupiter and Mars, that is occupied by a great many solid, irregularly shaped bodies, of many sizes but much smaller than planets, called asteroids or minor planets.

Answer:

holla at me!!!!!!!!!!????

The momentum, p, of any object having mass m and the velocity v is

\(p=mv\cdots(i)\)

Let \(M_L\) and \(M_S\) be the masses of the large truck and the car respectively, and \(V_L\) and V_S be the velocities of the large truck and the car respectively.

So, by using equation (i),

the momentum of the large truck \(= M_LV_L\)

and the momentum of the small car \(= M_SV_S\).

If the large truck has the same momentum as a small car, then the condition is

\(M_LV_L=M_SV_S\cdots(ii)\)

The equation (ii) can be rearranged as

\(\frac {M_L}{M_S}=\frac {V_S}{V_L} \; or \; \frac{M_L}{V_S}=\frac{M_S}{V_L}\)

So, the first scenario:

\(\frac {M_L}{M_S}=\frac {V_S}{V_L}\)

\(\Rhghtarrow M_L:M_S=V_S:V_L\)

So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.

The other scenario:

\(\frac{M_L}{V_S}=\frac{M_S}{V_L}\)

\(\Rhghtarrow M_L:V_S= M_S:V_L\)

So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.

Answer: neutrinos

Explanation: