A ball of mass m is attached to the end of a string of length L. If the ball is swung in a vertical circle with uniform speed v, calculate the ratio of the tension Tt in the string when the ball is at the top of its path to Tb when the ball is at the bottom of its path. A) TbTt=1(LO:4,21,24) B) TbTt=Lv2+gLv2−g(LO:4,13,16,19,21,23,24) C) TbTt=Lv2−gLv2+g(LO:13,16,19,21,23,24) D) TbTt=1−v2gL(LO:4,13,16,21,23,24) E) TbTt=1+v2gL(LO:4,13,16,21,23,24) F) TbTt=Lv2−gLt2 G) TbTt=Lv2+gLν2

Answer:

1/2 M V^2 = .1 M g H       where 10% of PE goes into KE

V^2 = .2 g H = .2 * 9.8 * (2100 - 1600) = 980 m^2 / s^2

V = 31.1 m/s       increase in speed during descent

1 km / hr = 1000 m / 3600 sec = .278 m/s

V = 31.1 m/s / (.278 m/s / km /hr)= 112 km/hr

Potential energy plus kinetic energy are combined to form mechanical energy. According to the principle of mechanical energy conservation, mechanical energy is constant in an isolated system when only conservative forces are acting on it.

E mechanical = U + K

E mechanical = mechanical energy

U = potential energy

K = kinetic energy

Mechanical energy, also known as kinetic energy or potential energy, is the energy that an object possesses when it is in motion or the energy that an object stores due to its location.

Renewable energy is also fueled by mechanical energy. In order to efficiently produce electricity or convert energy, many sources of renewable energy depend on mechanical energy.

Applying,

Mechanical Energy (M.E.) = ((1/2)mv²) + (m × g × h)

                                          = ((1/2)*100*45²)+(100*9.8*12)

                                          = 101250+ 11760

                                          = 113010 J

m is the object's mass, v is its speed, g is its gravitational acceleration, and h is its height above the ground.

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The circuit directory shows the load/area in a vocabulary that would be clear for "nonelectrical" people to decipher and determine the circuit number for luminaires, receptacles, appliances, or tools.

True stress is the spread load divided by the actual cross-sectional scope of material. Engineering strain is the applied load separated by the original cross-sectional area of material. Also known as nominal stress.

As expected by the units, stress is assigned by dividing the force by the location of its generation, and since this area (“A”) is either sectional or axial, the basic stress formula is “σ = F/A”.

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 False. The main product is responsible for providing the steak, which represents the core value and substance of the product, while the sizzle represents the marketing and promotional elements.

In the steak and sizzle analysis, the main product provides the steak, not the sizzle. The steak refers to the actual substance or value of the product, while the sizzle represents the marketing and promotional aspects that create excitement and appeal around the product.

The main product is responsible for providing the steak, which represents the core value and substance of the product, while the sizzle represents the marketing and promotional elements.

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The two-dimensional curl of the vector field F(x, y) = (-2xy, x²) is computed to be 4x - 2. The region R bounded by y = 0 and y = x(2-x) is sketched as a triangular region in the xy-plane. By applying Green's Theorem in the circulation form, the integrals are evaluated and shown to be equal, confirming the consistency of the computations.

(a) To compute the two-dimensional curl of the vector field F(x, y) = (-2xy, x²), we need to find the partial derivatives of the components of the vector field and take their difference. The curl is given by the expression:

\(\[\nabla \times \textbf{F} = \left( \frac{\partial}{\partial x} (x^2) - \frac{\partial}{\partial y} (-2xy) \right) \textbf{i} + \left( \frac{\partial}{\partial y} (-2xy) - \frac{\partial}{\partial x} (x^2) \right) \textbf{j}\]\)

Simplifying this expression yields:

\(\[\nabla \times \textbf{F} = (0 - (-2x)) \textbf{i} + (4x - 0) \textbf{j} = 2x \textbf{i} + 4x \textbf{j} = \boxed{2x \textbf{i} + 4x \textbf{j}}\]\)

(b) The region R is bounded by the y-axis (y = 0) and the curve y = x(2-x). Sketching this region in the xy-plane, we find that it forms a triangular region with vertices at (0, 0), (1, 0), and (2, 0).

(c) Applying Green's Theorem in the circulation form, which states that the line integral of a vector field around a closed curve is equal to the double integral of the curl of the vector field over the region enclosed by the curve, we can evaluate both integrals. Let C be the boundary of the region R.

Using the circulation form of Green's Theorem, the line integral becomes:

\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (\nabla \times \textbf{F}) \cdot d\textbf{A}\]\)

The first integral is evaluated over the boundary curve C, and the second integral is evaluated over the region R. Substituting the given vector field and the computed curl, we have:

\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (2x \textbf{i} + 4x \textbf{j}) \cdot d\textbf{A}\]\)

Integrating this expression over the triangular region R will yield a specific result. By evaluating both integrals, it can be verified that they are equal, confirming the consistency of the computations.

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Answer:

It would spin ifintely

Explanation:

Answer:Never stand or move around while music is being performed.

Explanation:

F =

t = 0.17 s

Impulse (J) = 20,000 N

J = F x t

F = J / t = 20,000 Ns / 0.17 s = 117,647.0588 N

To find the current in the resistor, we can use Ohm's Law and the concept of equivalent resistance. Thus, option A is correct.

First, let's calculate the equivalent resistance of the three cells connected in parallel. When resistors are connected in parallel, the reciprocal of the equivalent resistance is equal to the sum of the reciprocals of the individual resistances:

1/Req = 1/R1 + 1/R2 + 1/R3

Given that R1 = R2 = R3 = 22 Ω (internal resistance of each cell), we can substitute the values:

1/Req = 1/22 + 1/22 + 1/22

1/Req = 3/22

Taking the reciprocal of both sides, we find:

Req = 22/3 Ω

Now we can use Ohm's Law to calculate the current (I) in the resistor. Ohm's Law states that the current flowing through a resistor is equal to the voltage across it divided by its resistance:

I = V/R

Given that V = 1.1 V (emf of each cell) and R = 32 Ω (resistance), we can substitute the values:

I = 1.1/32

Calculating this value, we find:

I ≈ 0.034375 A

Therefore, the current in the resistor is approximately 0.034375 A.

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Answer:

isn't it the first one

Answer:

The object in figure C is a planet, so it is the largest object. Planets are larger than comets and asteroids.

Explanation:

Answer:

Standing wave,Also called stationary wave,combination of two waves moving in opposite direction,each having the same amplitude and frequency.They phenomenon is the result of interference;that is when waves are superimposed,their energies are either added together or cancelled out.

Explanation:

hpe it hlps u<°>

The combination of two waves is  "mechanical waves". The correct option is A.

A mechanical wave is a type of wave that requires a medium to travel through. In a mechanical wave, energy is transferred through the motion of particles in the medium, rather than the transfer of matter. Examples of mechanical waves include sound waves, water waves, and seismic waves.

In a mechanical wave, energy is initially added to a small region of the medium, which creates a disturbance that propagates outward as a wave. As the wave travels, particles in the medium oscillate back and forth around their equilibrium positions, transferring energy to neighboring particles. The wave continues to travel until it encounters a boundary, where it may be absorbed, transmitted, or reflected.

Mechanical waves can be classified as transverse waves or longitudinal waves, depending on the direction of particle motion relative to the direction of wave propagation. In a transverse wave, particle motion is perpendicular to the direction of wave propagation, while in a longitudinal wave, particle motion is parallel to the direction of wave propagation.

Mechanical waves are an important aspect of many natural phenomena and technological applications. They play a crucial role in fields such as acoustics, optics, and seismology, and have applications ranging from medical imaging to telecommunications.

Here in the Question,

A combination of two waves can be any type of wave, but it is most commonly a type of mechanical wave. Mechanical waves are waves that require a medium to travel through, such as sound waves or water waves.

The other three types of waves mentioned - longitudinal waves, surface waves, and transverse waves - are all specific types of mechanical waves.

Longitudinal waves are waves in which the particles of the medium vibrate back and forth parallel to the direction of wave propagation. Examples include sound waves and seismic waves.

Transverse waves are waves in which the particles of the medium vibrate perpendicular to the direction of wave propagation. Examples include light waves and electromagnetic waves.

Surface waves are waves that occur at the interface between two different media, such as the interface between air and water. Examples include ocean waves and seismic waves.

Therefore, the most appropriate answer to the question would be "mechanical waves".

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Answer:

2.34

Explanation:

Answer:

2.34

Explanation:

Hope this helps! :D

Answer:

The mass of object is 300g.

Its weight on earth is W×0.3kg×9.8m/s2=2.94 N

Its weight on moon is A 300 g would be 48 g on the moon

GOOD LUCK!

Answer:

\(a=32\ m/s^2\)

Explanation:

Given that,

The velocity of an astronaut in a circular path, v = 16 m/s

The radius of the accelerator, r = 8 m

We need to find his centripetal acceleration. The formula that is used to find the centripetal acceleration is given by :

\(a=\dfrac{v^2}{r}\\\\a=\dfrac{(16)^2}{8}\\\\a=32\ m/s^2\)

So, the required centripetal acceleration is \(32\ m/s^2\).

Answer:

No acceleration. All of the forces are acting equally on the paper air plane therfore It isn't going to move any where.

Answer:

Real Image

Explanation:

Images which are formed on the screen by the actual intersection of light rays are called real images.

Answer:

Explanation:

hope this helps you.

will give the brainliest!

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The maximum power of the pump is 24,000 W.

To determine the maximum power of the pump, we need to calculate the work done by the pump in lifting the water to a height of 60m.

First, we need to find the weight of the water that is pumped per minute:

40 litres of water * 1 kg/litre = 40 kg

Next, we can calculate the work done by the pump using the formula for work done by a force:

W = F * d

Where W is the work done, F is the force applied and d is the distance moved.

Since the weight of the water is the force acting on it, we can use that in the above formula:

W = 40 kg * 10 m/s^2 * 60 m = 24,000 J/minute

Finally, we can convert the work done per minute to power, using the formula:

P = W / t

Where P is the power and t is the time taken.

Since we know that 40 litres of water are pumped in 1 minute, we can use that as t:

P = 24,000 J/minute / 1 minute = 24,000 W

So, the maximum power of the pump is 24,000 W.

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The work done by a constant force acting on an object is equal to the product of the magnitudes of the displacement and the component of the force parallel to that displacement.

Work is a measure of energy transfer, and it is calculated as the product of the force applied on an object and the distance over which the force is applied. However, when the force is not applied in the same direction as the object moves, only the component of the force parallel to the displacement of the object will contribute to the work done.

This principle is known as the work-energy theorem and is commonly used in physics to calculate the amount of work done on an object in a particular situation.

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Newton's second law does apply to a situation in which there is no net force as having a net force of zero will produce an acceleration having 0.  

According to Newton's second law, the acceleration of an object depends upon two variables- the mass of the object and the net force acting on the object. Here, the acceleration of an object is directly proportional to the force acting on it and inversely proportional to the mass of that object. The net force applied is equal to the sum of all the forces acting on an object.

In a situation where the net force applied is zero, the object having a mass would have zero acceleration. This means that the object would have zero velocity and would be constant.

This depicts that Newton's second law can be applied to every situation where there is a net force applied, or not. Even if there is no net force, this law can still be applied.

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Planes primarily operate in the troposphere because this is the layer of the atmosphere that is closest to the Earth's surface and it's where most of our weather occurs. The troposphere extends from the Earth's surface up to about 7-20 km (5-12 miles) and it contains about 80% of the total mass of the atmosphere. The air is also denser in this layer, making it easier for planes to generate lift and fly efficiently. Additionally, the troposphere is where the majority of commercial and civilian air traffic occurs, as it is the layer that is best suited for takeoff, landing and cruising of planes. Planes are able to fly in higher layers of the atmosphere, but the conditions become more challenging and it's less common for commercial planes to operate in those layers because it would require specialized equipment and training.

I hope this helps :)

Answer:

because they are underaged and prob dont care and also the gov thinks that the youth cant make a reasonable decision for them selves for sum like that and the media influnces them to by saying whats going on and who supports who

Answer:

"Scientist use radioactive decay to measure the age of a rock or fossil."

Explanation:

"To establish the age of a rock or a fossil, researchers use some type of clock to determine the date it was formed. Geologists commonly use radiometric dating methods, based on the natural radioactive decay of certain elements such as potassium and carbon, as reliable clocks to date ancient events."

To study change over time psychologists use cross-sectional, longitudinal, and sequential designs.

These research designs allow researchers to investigate different aspects of development and gather valuable insights into how individuals change and develop across various stages of life.

Each design offers unique advantages and can provide valuable information for understanding psychological processes and developmental patterns. In addition to cross-sectional and longitudinal designs, psychologists also employ the sequential design to study change over time.

The sequential design combines elements of both cross-sectional and longitudinal approaches. It involves studying multiple age groups at different points in time and tracking them longitudinally. This design allows researchers to examine both age-related and cohort-related effects, providing a more comprehensive understanding of developmental changes.

Cross-sectional studies involve comparing different groups of individuals at a single point in time. This design allows researchers to gather data from individuals of different ages or developmental stages simultaneously.

It provides insights into age differences but does not account for individual changes over time. Longitudinal studies involve following the same individuals or groups over an extended period. Researchers collect data at multiple time points, enabling them to examine individual trajectories of development and detect patterns of change over time.

Longitudinal studies provide valuable information about within-individual changes and can identify factors influencing development. Sequential designs integrate elements of cross-sectional and longitudinal designs.

They involve studying different cohorts at multiple time points, combining both age-related and time-of-measurement effects. Sequential designs offer a more nuanced understanding of developmental processes by considering both age and cohort influences.

By employing these three research designs, psychologists gain a comprehensive understanding of developmental changes, individual trajectories, and the interplay of various factors affecting psychological development over time.

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To find the magnitude of the response at 6 rad/s for a first-order lag transfer function with a break frequency of 3 rad/s, we can use the formula:

|H(jω)| = 20log(1/√(1+(ω/ωb)^2))

where |H(jω)| is the magnitude of the transfer function, ω is the frequency of interest (in this case, 6 rad/s), and ωb is the break frequency (in this case, 3 rad/s).

Plugging in the values, we get:

|H(j6)| = 20log(1/√(1+(6/3)^2))
|H(j6)| = 20log(1/√(1+4))
|H(j6)| = 20log(1/√5)
|H(j6)| = 20log(0.447)
|H(j6)| = -8.5 dB

Therefore, the magnitude of the response at 6 rad/s for a first-order lag transfer function with a break frequency of 3 rad/s is -8.5 dB.

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Given that the mass of the ball is m = 0.57 kg.

The speed of the ball is

A) The kinetic energy at point A will be

B) Given that the kinetic energy,

The ball's speed at point B will be

C) The total work done on the ball to move from point A to B is

The work done by the force on the particle is 39J and  the angle between F and s is 19.7 degree.

An item with mass is pulled or pushed which alters its velocity. A material that has the ability to change a body's rest or motion state is referred to as an external force. It possesses a magnitude and a direction.

Force F = (Fx, Fy)

Displacement S = (Sx,Sy)

Fx=10N

Fy=-1N

Sx=4m

Sy=1m

F=(10,-1)N and S=(4,1)m

Work done is calculated by taking dot product of force and displacement vector:

W=F·S

W=10×4 + (-1)×1

W=40+(-1)=39J

W = 39 J

To find angle between F and s:

\(|F|=\sqrt{10^2+(-1)^2}\)

|F| = √101

|S| = √(4² + 1²)

|S| = √17

W  = |F| |S| cosθ

39 = √101 √17 cosθ

θ = 19.7.

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Answer:

cellar·⇔⇔⇔⇔⇔ A

Explanation:

i took it