Explanation:
Givens:
\(h = 20 \: m\)
\(v _{ix} = 15 \cos(37) = 11.97\)
\(v _{iy} = 15 \sin(37) = 9.03\)
\(a _{y} = - 9.8\)
Let t=2 be the final velocity. Since Velocity stays the same horizontal , acceleration due to gravity changes the vertical direction
Use this equation
\(v _{y} = v _{iy} + a _{y}(t) \)
Plug in the knowns
\(v _{y} = 15 \sin(37) +2 ( - 9.8)\)
\(v _{y} = - 10.57\)
So the velocity in the y direction at 2 seconds is -10.57
The velocity in the x direction at 2 seconds is 11.97
Use the Pythagorean theorem to find the total velocity
\(v = \sqrt{( - 10.57) {}^{2} + (11.97) {}^{2} } \)
\(v = 15.97\)
b. The range at which it strike the ground.
We need to find when the velocity at the top is zero.
Using the y direction,
\(0 = v \sin( 37 ) - 9.8(t)\)
\(t = 0.921\)
Next, find the height of the max.
\(h = \frac{1}{2} ( 9.8)(0.921) {}^{2} = 4.16\)
So the total distance is 4.16+20= 24.16
Next to find the total time it falls
\(24.16 = \frac{1}{2} (9.8) {t}^{2} \)
\(t = 2.2\)
So our total flight time is
\(3.141\)
Range is
\(v \cos(37) (3.141) = 37.63\)
An electron has a charge of 1.602 X 10-19.coulomb. When two electrons are separated by 1.2 X 10-9m, what force will they exert on each other?(-19 & -9 are exponents)
6.2 X 10-6N
1.6 X 10-10N
3.4 X 10-9N
5.3 X 10-7 N
Answer:
The force they will exert on each other is 1.6*10⁻¹⁰ N
Explanation:
The electromagnetic force is the interaction that occurs between bodies that have an electric charge. When the charges are at rest, the interaction between them is called the electrostatic force. Depending on the sign of the interacting charges, the electrostatic force can be attractive or repulsive. The electrostatic interaction between charges of the same sign is repulsive, while the interaction between charges of the opposite sign is attractive.
Coulomb's law is used to calculate the electric force acting between two charges at rest. This force depends on the distance "r" between the electrons and the charge of both.
Coulomb's law is represented by:
\(F=k*\frac{q1*q2}{r^{2} }\)
where:
F = electric force of attraction or repulsion in Newtons (N). Like charges repel and opposite charges attract. k = is the Coulomb constant or electrical constant of proportionality. q = value of the electric charges measured in Coulomb (C). r = distance that separates the charges and that is measured in meters (m).In this case:
k= 9*10⁹ \(\frac{N*m^{2} }{C^{2} }\)q1= 1.602*10⁻¹⁹ Cq2= 1.602*10⁻¹⁹ Cr= 1.2*10⁻⁹ mReplacing:
\(F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{1.602*10^{-19} C*1.602*10^{-19} C}{(1.2*10^{-9} )^{2} }\)
and solving you get:
F=1.6*10⁻¹⁰ N
The force they will exert on each other is 1.6*10⁻¹⁰ N
Revlew Millikan's Photoelectric Experiment Robert A. Mlkan (1868 1953). although best known for his "oil-drop experiment," which measured the charge of an electron, also perfomed pioneering research on the photoelectric effect. In experiments on lithium, for example, Millikan observed a maximum kinetic energy of 0.550 eV when electrons were ejected with 433.9-nm light. When light of 253.5 m was used, he observed a maximum kinetic energy of 2.57 eV.
Part A What is the work function,W, for lithium, as determined from Milikan's results? Express your answer to three significant figures and include appropriate units.
Part B What maximum kinetic energy do you expet illikan found when he used light with a wavelength of 362.4 TIm? Express your answer to three significant figures and include appropriate units Value Units
Answer:
A.) Work function = 2.3 eV
B.) Max. K.E observed = 1.1 eV
Explanation:
A.) Millikan observed a maximum kinetic energy of 0.550 eV when electrons were ejected with 433.9-nm light. When light of 253.5 m was used, he observed a maximum kinetic energy of 2.57 eV.
work function (f) is the minimum energy required to remove an electron from the surface of the material.
hf = Ø + K.E (maximum)
Where
h = Plank constant 6.63 x 10-34 J s
Ø = work function
hc/λ = Ø + K.E (max)
(6.63×10^-34 × 3×10^8)/433.9×10^-9 = Ø + 0.550 × 1.6×10^-19
4.58×10^-19 = Ø + 8.8×10^-20
Ø = 4.58×10^-19 - 8.8×10^-20
Ø = 3.7 × 10^-19 J
Converting Joule to eV
Ø = 3.7 × 10^-19/1.6×10^-19
Ø = 2.3 eV
B.) When light of wavelength 362.4 m is used
The maximum K.E observed = incident light K.E - (the work function).
Incident K.E = hf = hc/λ
Incident K.E =
(6.63×10^-34 × 3×10^8)/362.4
Incident K.E = 5.5 × 10^-28J
Let's convert joule to eV
Incident K.E = 5.5×10^-28/1.6×10^-19
Incident K.E = 3.4 × 10^-9
Max. K.E observed = 3.4 - 2.3
Max. K.E observed = 1.1 eV
Hurry please
The distance from wave to wave is called what
Answer:
Wavelength
Explanation:
Help please ! Ill give brainliest !! ☁️✨
Rock X is released from rest at the top of a cliff is on earth. A short time later, Rock y is released from rest from the same point as rock X. Both rocks fall for several seconds before landing on the ground directly below the cliff. Frictional forces are considered to be negligible.
Which of the following graph correctly shows the vertical velocity of rock X as a function of time? Take the positive direction to the upward.
The graph of the velocity and the time can be shown by option D.
What is the correct graph?We know that the movement of an object as it is falling under gravity would have a constant acceleration. The constant acceleration means that the velocity of the object is also held a constant.
We now have to look at the graphs as we have them here. The graph as it has been shown has the the velocity on the vertical axis and it has the time on the horizontal axis. The gradient of the slope is what we would refers to as the acceleration of the body.
We also need to recall that the acceleration has to be a constant since tje tow object would have to reach the ground at the same time if they are released from the same height at the same time.
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What is the powder taking the shape of?
The magnetic field
The poles
A snowman
A star
The powder takes the shape of a magnetic field.
What is the particle shape of powder?Powder morphology is connected to the shape and size of powder particles and is strongly dependent on the manufacturing methods. For example, mechanical alloying/mechanical milling leads to unevenly shaped powder particles, while gas dissipation leads to spherically shaped particles.
Atomized metal powder particles come in two basic particle shapes: those that are almost superbly round called spherical, and those that have lopsided, rounded shapes, called spheroidal.
So we can conclude that Powders are a group of particles of different sizes.
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A pipe of constant radius carried water at 3.25 m/s. Please answer in PA.
Pipe of constant radius, we can use Bernoulli's equation, which relates the pressure, velocity, and height of a fluid at two points in a flow system.the pressure of water in the pipe is approximately 105,142 Pa.
What is a system?System refers to a collection of related components or parts that work together to achieve a specific goal or purpose. The concept of a system can be applied to a wide range of fields and disciplines, including science, engineering, economics, and social sciences.
In science, a system is often defined as a portion of the universe that is being studied or analyzed. This can include anything from a single atom or molecule to an entire ecosystem or planet. By defining the boundaries of a system, scientists can focus their attention on understanding the interactions and relationships between the various components within that system.
In engineering, a system refers to a collection of components that are designed to work together to perform a specific function or task. This can include everything from simple mechanical systems like gears and pulleys to complex electrical or computer systems.
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Modernity is a result of groups becoming more connected because of common beliefs and the strengthening of social ties ?
Answer:
Modernity is the belief in the freedom of the human being – natural and inalienable, as many philosophers presumed – and in the human capacity to reason combined with the intelligibility of the world, that is, its amenability to human reason
Explanation:
What is the frequency of a wave that has a period of 0.5 seconds?
A. 0.5 Hz
B. 2 Hz
C. 200 Hz
D. 20 Hz
Answer:
B. 2 Hz
Explanation:
Given parameters:
Period of the wave = 0.5Hz
Unknown:
Frequency of the wave = ?
Solution:
Frequency is the number of waves that passes through a point.
Period is the time taken for a number of waves to pass through a point.
Period is the inverse of frequency
Frequency = \(\frac{1}{t}\)
t is the period
Frequency = \(\frac{1}{0.5}\) = 2Hz
Answer:2
Explanation:
Jack sits in the chair of a Ferris wheel that is rotating at a constant 0.150 rev/srev/s . As Jack passes through the highest point of his circular part, the upward force that the chair exerts on him is equal to one-fourth of his weight.
What is the radius of the circle in which Jack travels? Treat him as a point mass.
Answer:
Explanation:
At the top of the arc, 3/4 of the acceleration of gravity is use to supply the necessary centripetal acceleration.
0.75g = ω²R
R = 0.75g/ω²
R = 0.75(9.81) / (0.15 rev/s)(2π rad/rev)²
R = 8.283006...
R = 8.28 m
Olympic swimmer, Micheal Phelps, swam a 200 meter race in 1 minute and 54 seconds. What would his velocity be in meters/seconds
During the 200-meter race, Michael Phelps moved at a speed of 1.75 metres per second.
What is famous about Michael Phelps?More than any other swimmer in history, he won Olympic medals, world titles, US national titles, and set world records. Phelps has made it a priority to support the growth of swimming at all levels during his career. With a total of 28 medals, he is the most successful and decorated Olympian of all time.
Velocity = Distance / Time
In this case, the distance swum is 200 meters and the time taken is 1 minute and 54 seconds, or 114 seconds.
Velocity = 200 meters / 114 seconds
Velocity = 1.75 meters/second (rounded to two decimal places)
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A small, 300 gg cart is moving at 1.80 m/sm/s on a frictionless track when it collides with a larger, 5.00 kgkg cart at rest. After the collision, the small cart recoils at 0.810 m/sm/s . Part A What is the speed of the large cart after the collision
The velocity of the large cart after the collision is approximately 0.0486 m/s in the opposite direction of its initial motion.
We can use the principle of conservation of momentum to find the speed of the large cart after the collision. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
The momentum (p) of an object is calculated by multiplying its mass (m) by its velocity (v). Therefore, the momentum of the small cart before the collision is:
p_small_before = (mass_small) * (velocity_small) = (0.300 kg) * (1.80 m/s) = 0.540 kg·m/s.
Since the large cart is at rest before the collision, its initial momentum is zero:
p_large_before = 0 kg·m/s.
After the collision, the small cart bounces back at a speed of 0.810 m/s. According to the law of conservation of momentum, the total momentum after the collision should equal the total momentum before the collision. Therefore, the momentum of the small cart after the collision is:
p_small_after = (mass_small) * (velocity_small_after) = (0.300 kg) * (-0.810 m/s) = -0.243 kg·m/s.
The momentum of the large cart after the collision is labeled p_large_after. Since the initial momentum of the large cart is zero and the momentum after the collision is determined by the momentum of the small cart, we can write:
p_large_after = -0.243 kg·m/s.
To find the speed of the large cart after the collision, we divide the momentum by its mass:
velocity_large_after = p_large_after / (mass_large) = (-0.243 kg·m/s) / (5.00 kg) = -0.0486 m/s.
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When an alpha particle is emitted from an unstable nucleus, what happens to the atomic number of the nucleus
Answer:
The answer to your question is the number decreases by 4.
Explanation:
I hope this helps and have a great day!
A. 101/ B. 20Hz If 25) is taken away by heat from a sys in internal energy of the system? A. SA B..SJ SJ The amount of damping force that allow shortest possible time is called
The amount of damping force that allow shortest possible time is called critical damping of the system.
What is critical damping?Critical damping is the threshold between overdamping and underdamping at which the oscillator returns to the position of equilibrium quickly as possible.
Critical damping is frequently desired because such a system returns to and maintains equilibrium quickly. Furthermore, a constant force applied to a critically damped system moves the system to a new equilibrium position as quickly as possible without overshooting or oscillating around the new position.
Critical damping thus provides the rapid approach to zero amplitude for a damped oscillator.
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PLEASE HELP ME WITH THIS ONE QUESTION
The specific heat of aluminum is 899 J/kg*C. How much aluminum is changed by 1.00°C assuming 1000. J of heat is added to the piece of aluminum?
Answer:
Q = c * m * T where c = specific heat, m = mass, T = temperature change
m = Q / (c * T) = 1000 J / (899 J / kg deg C * 1 deg C)
m = 1000 / 899 kg = 1.11 kg
PLS HELP (ASAP)
Acutely give me the answer no links
There is a box on your desk that
acts as a paperweight. Its
measurements are 1 cm by 3 cm
by 7cm. The block has a mass
of 220.5g. What is the
substance?
Answer:
10.5 g/cm^3
Explanation:
d = mass/volume
V= 1cm x 3cm x 7cm = 21 cm^3
d = (220,5g) / (21cm^3)
d = 10.5 g / cm^3
In your own words, explain the difference between dry friction and drag due to fluid friction
Answer:
Follows are the difference to this question:
Explanation:
Dry friction:
Its force which prevents any solid surface moving over another flat substrate, and all substances which move compared to each other are often opposed by dry friction and could have the impact from either opposing movement or inducing movement throughout the body.
drag due to fluid friction:
It also is known as Skin Friction Drag, which is indeed a drag created by a liquid's friction against the surface of the object which passes thru it. In fluid mechanics, drag sometimes alluded to as air resistance, a form of friction, or fluid resistance, another form of resistance is a force acting contrary to any entity's gravitational attraction about the external fluid.
Questions of the experiment: 1. The force required to stretch Hooke's Law spring varies from ON to 65 N as we stretch the spring by moving one end 6.3 cm from its unstressed position. Find the force constant of the spring. Answer in units of N/m.
2. An object with mass of 630 g is hung on a spring. What is theforce of the object acting on the spring?
3. Will a strong spring have a big or small constant? a) Small b) Big lamic trver
From Hooke's law F=k×Δx, the force constant of springk= 1032 N/m. If object with m of 630g is hung on spring then force of the object acting on the spring is 6.17 N. A greater spring constant implies a tougher spring.
Describe Hooke's law.According to Hooke's law, the amount of force used to stretch an elastic item is proportional to that force. The object won't return if it is stretched very far, though.
Why does Hooke's law have a negative K?The spring constant K is a constant that is always positive. As seen by the negative sign, the restoring force is acting in the opposite direction to that of the applied force.
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If a = 30 cm, b = 20 cm, q = +2.0 nC, and Q = –3.0 nC in the figure, what is the magnetude of the potential difference between A and B is
The magnitude of the potential difference between A and B is 195 V.
Potential of charge A
The potential of charge A is calculated as follows;
Va = kq/r
where;
k is Coulomb's constantq is magnitude of the charger is the position of the chargeVa = (9 x 10⁹ x 2 x 10⁻⁹) / (0.3)
Va = 60 Volts
Potential of charge BVb = kq/r
Vb = (9 x 10⁹ x -3 x 10⁻⁹) / (0.2)
Vb = -135 Volts
Potential between A and BVAB = VB - VA
VAB = -135 V - 60 V
VAB = -195 V
Thus, the magnitude of the potential difference between A and B is 195 V.
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what is the most effortless walking speed for a person with 90cm long legs if the length of each step is 90cm
Answer:
75 cm/second.
Explanation:
Formula:
Walking speed = stride length / time per step
Walking speed = 90cm/time per step
= 90cm/1.2 seconds (a common estimate time per step)
= 75cm/second.
For the ballistic missile aimed to achieve the maximum range of 9500 km, what is the maximum altitude reached in the trajectory
Explanation:
The range R of a projectile is given the equation
\(R = \dfrac{v_0^2}{g}\sin{2\theta}\)
The maximum range is achieved when \(\theta = 45°\) so our equation reduces to
\(R_{max} = \dfrac{v_0^2}{g}\)
We can solve for the initial velocity \(v_0\) as follows:
\(v_0^2 = gR_{max} \Rightarrow v_0 = \sqrt{gR_{max}}\)
or
\(v_0 = \sqrt{(9.8\:\text{m/s}^2)(9.5×10^6\:\text{m})}\)
\(\:\:\:\:\:\:\:=9.6×10^3\:\text{m/s}\)
To find the maximum altitude H reached by the missile, we can use the equation
\(v_y^2 = v_{0y}^2 - 2gy = (v_0\sin{45°})^2 - 2gy\)
At its maximum height H, \(v_y = 0\) so we can write
\(0 = (v_0\sin{45°})^2 - 2gH\)
or
\(H = \dfrac{(v_0\sin{45°})^2}{2g}\)
\(\:\:\:\:\:\:= \dfrac{[(9.6×10^3\:\text{m/s})\sin{45°}]^2}{2(9.8\:\text{m/s}^2)}\)
\(\:\:\:\:\:\:= 2.4×10^6\:\text{m}\)
A plank AB 3m long weighing 20kg and with center of gravity 2m from the end A carries a load of mass 10kg at the end A it rests on two supports CandD.
1, compute the values of the reaction forces R1 and R2 at C and D.
2, how far from D and on which side of it must a mass of 24kg be placed on the plank so as to make the reactions equal? What are their values.
3,without this 24kg what vertical force applied at B will just lift the plank clear of D? What is then the reaction at C.
The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.
1) R1 and R2 at C and D respectively are given by the equation R2 = (m1 + m2)g - R1, where m1 and m2 are the masses of the plank and load, respectively, and g is the acceleration due to gravity. Hence, substituting values R2 = (20 + 10) × 9.81 - R1 = 294.3 - R1. Now, taking moments about D, the following equation can be obtained: (20 × 1 + 10 × 3)g = R1 × 2 + R2 × 3 = 2R1 + 3 × (294.3 - R1) = 882.9 - R1, from which R1 = 343.7 N and R2 = 294.3 - 343.7 = -49.4 N. Since the support at D can only push the plank upwards and cannot pull it downwards, a negative value for R2 implies that the plank is actually being pulled downwards by an external force. Therefore, the value of R2 is not relevant. 2) The total weight of the plank and the load acting at the end A is 20 + 10 = 30 kg. For the reactions at C and D to be equal, the 24 kg mass must be placed at a distance x from D such that x × 30 = 24 × 6, from which x = 12/5 = 2.4 m. Since the 24 kg mass is being placed to the left of the plank, it will cause the reaction at C to decrease and that at D to increase. Thus, if R is the vertical force applied at B, then taking moments about D gives 20g × 1 - 10g × 3 + R × 6 = 0, from which R = 90 N. Taking moments about C gives R × 3 - 10g × 2 = 0, from which R = 66.3 N. 3) The vertical force applied at B that will just lift the plank clear of D is the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D. The weight of the plank and the load acting at the end A is 20 + 10 = 30 kg, and the weight of the part of the plank that is to the right of D is 24 × 1.6 = 38.4 kg. Therefore, the vertical force applied at B that will just lift the plank clear of D is (20 + 10 + 38.4)g = 686.4 N. The reaction at C is zero because the plank is not being supported there anymore. The reaction at D is the same as the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D, which is 20 + 10 + 24 × 1.6 = 61.4 kg.For more questions on acceleration
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There are 9,000 houses in Elizabeth's town. Last summer, 7,020 of the houses were for sale. What percentage of the houses in the town were for sale last summer?
78% of the houses in Elizabeth's town were for sale last summer.
To find the percentage of houses that were for sale last summer in Elizabeth's town, we need to divide the number of houses for sale by the total number of houses and then multiply by 100.
The total number of houses in Elizabeth's town is given as 9,000. Last summer, 7,020 houses were for sale. To calculate the percentage, we divide 7,020 by 9,000:
Percentage = (7,020 / 9,000) * 100
Simplifying the calculation:
Percentage = 0.780 * 100
Percentage = 78.0%
To explain further, we take the number of houses for sale (7,020) and divide it by the total number of houses (9,000) to get the ratio of houses for sale to the total. Multiplying this ratio by 100 gives us the percentage. In this case, 78.0% indicates that a significant portion of the houses in Elizabeth's town were available for sale during the summer.
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Driving in your car that has a mass of 480kg, you travel with a constant speed of 12 m/s. You encounter a hill in the road with a certain circular curvature that causes your car to lose contact with the road. Calculate the maximum radius of curvature of the bump.
Answer:
The maximum radius of curvature of the bump is approximately 14.5 meters.
Explanation:
To calculate the maximum radius of curvature of the bump, we need to use the centripetal force equation:
F = mv²/r
where F is the force required to keep the car moving in a circle of radius r, m is the mass of the car, and v is the speed of the car.
At the instant when the car loses contact with the road, the normal force between the car and the road becomes zero. Therefore, the centripetal force required to keep the car moving in a circle is provided entirely by the force of gravity acting on the car.
The maximum radius of curvature occurs when the centripetal force required to keep the car moving in a circle is equal to the force of gravity acting on the car.
The force of gravity acting on the car is given by:
Fg = mg
where g is the acceleration due to gravity (9.81 m/s²).
Therefore, we can set F = Fg and solve for r:
mv²/r = mg
r = v²/g
Substituting the given values, we get:
r = (12 m/s)² / 9.81 m/s²
r ≈ 14.5 meters
Therefore, the maximum radius of curvature of the bump is approximately 14.5 meters.
...........................
Answer: kooi kooi
how r u and thanks for the free points :)
Consider the two vectors A and B. You know the magnitudes of these vectors (lmand 10 m respectively), but you do not know anything about their directions ca ment Status here for 9 H a vector is defined to be the sum of these two vectors CHA+B) which of the following are true about the magnitude of C7 Choose all that apply C. cannot be determined Grade Summary Cain
A. The magnitude of C can be determined.
D. The magnitude of C is between 1m and 10m.
When two vectors are added, the magnitude of the resulting vector can be found using the law of cosines. For the vectors A and B, the magnitude of their sum C is given by:
|C|² = |A|² + |B|² + 2|A||B|cosθ,
where θ is the angle between the vectors A and B. Since the directions of A and B are unknown, θ could take any value between 0 and 180 degrees. However, the minimum value of cosθ is -1, which occurs when θ = 180 degrees. Therefore, the minimum magnitude of C is:
|C|min = |A| - |B| = 1 m - 10 m = 9 m.
The maximum value of cosθ is 1, which occurs when θ = 0 degrees. Therefore, the maximum magnitude of C is:
|C|max = |A| + |B| = 1 m + 10 m = 11 m.
Therefore, the magnitude of C is between 1m and 10m, and it can be determined.
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correct question
Which of the following statements are true about the magnitude of the vector C, which is defined as the sum of two given vectors A and B with magnitudes 1m and 10m respectively, but unknown directions? (Choose all that apply.)
A. The magnitude of C can be determined.
B. The magnitude of C is less than 10m.
C. The magnitude of C is less than 1m.
D. The magnitude of C is between 1m and 10m.
E. The magnitude of C is greater than 11m.
The water in a lake is at 5 °C. A diver measures the pressure of the water at two different depths in the lake. He repeats the measurements on a different day when the water is at 15°C. The density of the water decreases when its temperature increases. Which combination of depth and temperature produces the greatest water pressure?
Answer:
The combination of depth and temperature that produces the greatest water pressure is the greatest water density.
As the temperature of the water increases, its density decreases. Therefore, at the colder temperature of 5°C, the water will have a higher density than at the warmer temperature of 15°C.
According to the hydrostatic pressure equation, pressure is directly proportional to the density of the fluid and the depth at which the fluid is located. Therefore, the greatest water pressure will be produced at the greatest water density, which occurs at the colder temperature of 5°C.
Therefore, the combination of the greatest depth and the colder temperature of 5°C will produce the greatest water pressure.
) Describe how the pith-ball and copper rod interact before the ball touches the rod. What does their interaction tell you about the movement of charge in the copper rod
Please help. Its due tomorrow. I’m not really surr what to do.
The gravitational force F between two bodies of respective masses M and m and distance R is
\(F = G\dfrac{Mm}{R^2}\)
where G ≈ 6.7 × 10⁻¹¹ m³/(kg•s) is the universal gravitational constant.
8.1.1. Let M = mass of Earth, m = mass of person, and R = radius of Earth. At point C, the distance between the center of the Earth and the person is 3R, so the gravitational force has magnitude
\(F = G \dfrac{\left(6.0\times10^{24}\,\mathrm{kg}\right) \left(50\,\mathrm{kg}\right)}{3\times6.4\times10^6\,\mathrm m} \approx \boxed{1.0\times10^9 \,\mathrm{N}}\)
8.1.2. Using the same values for M and m, now take R = radius of Earth + 10³ m. Then the gravitational force is
\(F = G \dfrac{\left(6.0\times10^{24}\,\mathrm{kg}\right) \left(50\,\mathrm{kg}\right)}{\left(6.4\times10^6+10^3\right)\,\mathrm m} \approx \boxed{3.1\times10^9 \,\mathrm{N}}\)
Elvis and Noah want to move the piano in their living room. Elvis pushes from behind with a force of
400 N, and Noah pulls from the front using a rope with a force of 150 N. The piano has a mass of 225 kg,
and the friction force of the floor and the piano is 100 N.
Calculate the acceleration of the piano.
Round your answer to the nearest tenth.
Answer:
2.0 m/s
Explanation:
Remember that F = maF=maF, equals, m, a, where FFF is the net force, mmm is the mass of the object, and aaa is its acceleration. To solve this problem, we will need to first find the net force acting on the piano and then use F = maF=maF, equals, m, a to find the piano’s acceleration.
Hint #22 / 4
The net force is the sum of all of the forces on the piano. In this circumstance, Elvis's and Noah's forces are in the same direction, and the friction force is in the opposite direction. So, our net force equation would be:
=400 N+150 N−100 N
=450 N
Now, we can use F = maF=maF, equals, m, a and solve for the acceleration:
225 kg
450 N
=2.0
The acceleration of the piano is 2.0 m/s
The acceleration of the piano is 2m/s².
We know the formula for force is
F =ma
where f is force, m is mass and a is acceleration.
We need to calculate the total force used in moving the piano
F= Total force- Frictional force
F= 400N+150N-100N= 450N.
We have F=450N and m= 225kg
F=ma
450N= 225ˣ a
a= 450/225
a= 2m/s²
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