When a ball is hit by a racket, its momentum changes. Momentum is conserved in this case by the principle of action and reaction.
Momentum is the product of an object's mass and its velocity. It is a vector quantity with direction determined by the direction of the object's motion. The momentum of an object can be calculated using the formula p = mv, where p is momentum, m is mass, and v is velocity.
The principle of action and reaction, also known as Newton's third law of motion, states that for every action, there is an equal and opposite reaction. This means that when one object exerts a force on another object, the second object exerts an equal and opposite force on the first object.When a ball is hit by a racket, the racket exerts a force on the ball in one direction, and the ball exerts an equal and opposite force on the racket in the other direction. These two forces have the same magnitude and opposite directions, which means that the total momentum of the ball and racket system remains constant. Therefore, momentum is conserved in this case.
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a woman stands near the edge of a cliff and drops a stone over the edge. exactly one second later she drops another stone. one second after that, how fast is the distance between the two stones changing?
The two stones will fall at the different time. But the difference between the time is just of one second.
The distance of the cliff is also considered. Here, the speed or velocity is asked. To calculate this we have to use the equation of motion.
There are three equations of motion.
We have;
The kinematic equation of motion that can be used is s = ut - (1/2)·gt²
For the first stone, we have, s₁ = ut₁ - (1/2)·gt₁²
For the second stone, we get; s₂ = ut₂ - (1/2)·gt₂²
g = The acceleration due to gravity ≈ 9.81 m/s²
s = The distance below the cliff top
The initial velocity of the stones, u = 0
To calculate the change of distance between the two stones,
we will subtract the two equation of motions are
s₁-s₂
With all the values kept together in the equation of motion, we can easily find the change of distance between the two stones.
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Two 0.55-kg basketballs, each with a radius of 19 cm , are just touching. You may want to review (Pages 399 - 401) . Part A How much energy is required to change the separation between the centers of the basketballs to 1.4 m ? (Ignore any other gravitational interactions.)
Answer:
ΔU = - 9,179 10-11 J
Explanation:
For this exercise the two basketballs are linked by gravitational interaction, so we can use gravitational energy
U = - G m₁m₂ / R
In this case the mass is equal and the initial distance is r₁ = 19 cm = 0.19 m
U₁ = - G m² / r₁
let's calculate
U₁ = - 6.67 10⁻¹¹ 0.55² / 0.19
U₁ = - 10,619 10⁻¹¹ J
when its centers are separated it is at r₂ = 1.4 m
U₂ = - 6.67 10⁻¹¹ 0.55² / 1.4
U₂ = - 1.44 10-11 J
the energy between these two points is
ΔU = U₂ - U₁
ΔU = (-1.44 +10.619) 10-11
ΔU = - 9,179 10-11 J
Last Thursday, I went for a walk through my neighborhood. I started at my house. My smart watch told me that I walked a total of 3.5 miles. I started my walk at 5 pm and ended at 8 pm. At the end of my walk, I was 50 meters north of my house visiting a neighbor. I wanted to find my average velocity on the trip. My distance walked was 3.5 miles. My time was 3 hours. To find velocity, I used my calculator to find 3.5 miles divided by 3 hours which equaled 1.16 miles per hour. Did I accurately calculate my velocity? If not, what did I do wrong and what was my correct velocity?
Answer:
Yes, that is correct, although most velocity is calculated via m/s and therfore you would multiply your 3 hours by 60 twice. Much of the information given is irrelevant and just trying to confuse.
Explanation:
Cart A has a mass of 2 kilograms and a speed of
3 meters per second. Cart B has a mass of 3
kilograms and a speed of 2 meters per second.
Compared to the inertia and magnitude of
momentum of cart A, cart B has
Cart B has more inertia and the same amount of momentum compared to Cart A's inertia and magnitude of momentum.
What impact does the cart's bulk have on how it moves?The cart moves more slowly because a greater mass with higher inertia must be moved by the same force. This cart's momentum also rises as a result of its increasing bulk. Due to its larger momentum, it pushes the other cart harder.
How is impulse determined?p is equal to F net t. The impulse-momentum theorem refers to the relationship between the expressions F net t and F net t. We can observe that the impulse is equal to the average net external force times the length of time that force is in effect.
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Proved that
V = u+at
Answer:
\(\sf Proof \ below\)
Explanation:
We know that acceleration is change in velocity over time.
\(\sf a=\frac{\triangle v}{t}\)
\(\sf a=\frac{v-u}{t}\)
v is the final velocity and u is the initial velocity.
Solve for v.
Multiply both sides by t.
\(\sf at=v-u\)
Add u to both sides.
\(\sf at + u=v\)
Answer:
Acceleration = v-u/t when we flip -u and t to right hand side
then -u changes to plus and denominator t changes to numerator
then then this equations becomes v=u+at
Explanation:
A ray of white light moves through the air and strikes the surface of water in a beaker. The index of refraction of the water is 1.33 and the angle of incidence is 30º. All of the following are true EXCEPT:I. the angle of reflection is 30º.II. the angle of refraction is 30º.III. total internal reflection will result, depending on the critical angle.
Answer:
La frecuencia será la misma en los dos medios, y en el vacio, no varia.
b) Vacío : n = 3,684 10 m 1,33 = 4 900 Å ,3161 10 m 55,1 n
,6 105 10 Hz
3,161 10 m
v 1,93 10 m/s 193548,38 km/s =
1,55
10 3 m/s
n
c
Vidrio v: =
,6 107 10 Hz
3,684 10 m
v 2,25 10 m/s 225 000km/s =
33,1
10 3 m/s
n
c
a
Which speed is the greatest? Speed 1: 25 m/s Speed 2: 45 mi/h Speed 3: 85 km/h a. Speed 1 b. Speed 2 c. Speed 3 d. All the same Submit
Speed 3 (85 km/h) is the greatest of the three speeds given. To compare the three given speeds, we need to convert them to the same unit of measure.
Speed 1 is given in meters per second, Speed 2 is given in miles per hour, and Speed 3 is given in kilometers per hour.
To convert Speed 2 from miles per hour to kilometers per hour, we use the conversion factor 1 mile = 1.60934 kilometers.
Therefore, Speed 2 is equal to 45 miles per hour x 1.60934 kilometers per mile = 72.42 kilometers per hour. Now that all three speeds are in kilometers per hour, we can easily compare them.
Among the three speeds, Speed 3 has the highest value of 85 kilometers per hour. Therefore, Speed 3 is the greatest of the three speeds given.
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acceleration is the rate at which what happens?
Answer:
Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity.
may be it helped you
Directions: Follow the steps below to help you understand electrical charges.
Materials
You will need: a plastic bag, two long rubber bands, a thin aluminum pie tin, a wool scarf or glove, and a friend or family member to assist you.
• STEP 1: Stretch the rubber bands across the pan-they should cross one another. Lay the bag flat on the table and rub it several times with the wool.
• STEP 2: With one hand, lift the pan by the rubber bands; be sure to keep your fingers from touching the pan,
• STEP 3: Bring the pan and the bag together. While they are together, ask someone to touch the pan quickly. What happens?
• STEP 4: Now take the pan away from the bag, still keeping your fingers from touching the pan. Right away, bring the pan up to your nose. What do you feel?
What do you hear?
• STEP 5: Now complete Steps 1-4 again, but do them in a dark room or closet. Ask a friend or family member to be in the room with you-what did he or she see
when you brought the pan to your nose?
Using the Text Editor, explain your observations and what happened during this experiment. What was happening to the electrical charges during the experiment and
why?
In this experiment, rubbing a plastic bag against wool allowed electrons to move back and forth between the two, creating a negative charge on the bag. When the negatively charged bag was brought close to the neutral PAN, the bag's negative charge attracted the PAN's electrons, separating the two charges and leaving the PAN with a positive charge. On touching the pan the surplus positive charge was neutralized, creating a spark.
When the pan was brought up to the nose a slight jolt was felt and a crackling sound was heard. This resulted in the excess charge in the pan being carried through the air to the nearest conductor, the person holding the pan.
The spark and shock were easy to see in a dark environment as there was no ambient light to obstruct the view. The blow was more pronounced and distinct, and the spark appeared as a bluish glow.
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Which of the following scenarios demonstrates a transfer
between kinetic energy and potential energy?
Answer:
what scenarios? but kinetic is energy in motion (like a ball rolling) and potential is stored energy (ball laying on ground)
example (kinetic to potential) : baseball flying and and lands on the ground then stops rolling
roller coaster rolling down a hill then stopping (kinetic to potential)
roller coaster on top of a hill and then going down (potential to kinetic)
Explanation:
An object that is a good radiator of electromagnetic waves is also a good...
1) insulator from heat
2) reflector of heat
3) absorber of electromagnetic energy
4) refractor of electromagnetic energy
An object that is a good radiator of electromagnetic waves is also a good absorber of electromagnetic energy.
Electromagnetic waves are a type of radiation that travels through space in the form of a transverse wave.
These waves are made up of two primary components: electric fields and magnetic fields.
They're also known as light waves.
An electromagnetic wave's properties are determined by its frequency and wavelength.
Electromagnetic waves with longer wavelengths have lower frequencies, whereas those with shorter wavelengths have higher frequencies.
An object that is a good radiator of electromagnetic waves is also a good absorber of electromagnetic energy.
The amount of energy an object absorbs or radiates is determined by a number of factors, including its temperature, surface area, and composition.
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a certain waffle iron is rated at 1.00 kw when connected to a 120-v source. (a) what current does the waffle iron carry? (b) what is its resistance?
The waffle iron has a rate of 1 kW and 120 v sources carrying a current of 8.33 Amperes and the resistance of the waffle iron is 14.41 ohms.
Electric current is a term used to describe how much electricity flows across a circuit and how it flows in an electronic circuit. Amperes are used to measure it (A). The more electricity flowing across the circuit, the higher the ampere value.
Given : Rating of waffle iron(P) = 1 kW, Potential of source (V) = 120 Volt,
(A) We know that Current(I) is equal to power divided by potential, which means
I = P / V, I = 1000 / 120 Volt
I = 8.33 Volt
(B) For resistance(R), we know that R = V / I (BY Ohms Law),
R = 120 / 8.33 ohm
R = 14.41 ohm
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how long would it take to get to jupiter at the speed of light
Answer:
Below
Explanation:
Here are the values we know :
Speed of light : 299 792 458 m/s
Distance from Earth to Jupiter : 634,290,000 km
Step 1. Convert km to m by multiplying it by 1,000
634,290,000 km x 1,000 = 634290000000 m
Step 2. Use t = d/v to find the time it would take for light to reach jupiter
t = 634290000000 m / 299 792 458 m/s
t = 2115.76369943 seconds
Now you can convert this to whatever measure of speed you would like. I'm going to convert this to minutes just because :
2115.76369943 / 60 = 35.26272832383334 minutes
= 35.263 minutes (rounded to 5 sig figs)
Therefore it takes 35.263 minutes to reach Jupiter at the speed of light
*This is the distance of jupiter as of today, however this distance is always changing*
Hope this helps! Best of luck <3
1) Suppose you place an object in front of a concave mirror. Which of the following statements must be true? (There could be more than one correct choice.) A) The image of the object will always be smaller than the object. B) No matter where you place the object, a real image of the object will be formed. C) The image of the object will always be inverted. D) If you position the object between the mirror and the focal point of the mirror, its image must be upright and virtual. E) No matter where you place the object, the image of the object will always be virtual and upright.
Answer:
C
Explanation:
because the concave mirror is always inverted
d ) when object is between focus and mirror , image formed is always virtual and erect
What is a Concave mirror ?
A concave mirror has a reflective surface that is curved inward and away from the light source .
a) Incorrect because image can be equal to , smaller then , and bigger then the object
b) and c) Incorrect when object is between focus and mirror , image formed is virtual and erect
d ) Correct option when object is between focus and mirror , image formed is always virtual and erect
e) Incorrect except one case in all other cases nature is real and inverted
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Based on the excerpt, what does the speaker most likely think about the wall? The wall protects his orchard. The wall is in the wrong place. The wall is too difficult to repair. The wall is unnecessary.
The speaker most likely think about the wall that The wall protects his orchard. Hence option A is correct.
The term wall is derived from the Latin word vallum, which denotes "...an earthen wall or rampart set with palisades, a row or line of stakes, a wall, a rampart, fortification...", whereas murus is a defensive stone wall. The same word is used in English to refer to an exterior wall and the inside sides of a room, but this is not ubiquitous. Many languages differentiate between the two. Some of this contrast may be observed in German between Wand and Mauer, and in Spanish between pared and muro.The wall protects his orchard.
Hence option A is correct.
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Pelo nossa observaçao do cotidiano,podmos perceber facilmente que se uma pedra for largada do alto de um predio , ele ira se deslocar em direçao ao solo ,enquanto que a fumaça produzida pela queima da madeira sobe para os ceus. Como aristosteles explicava estes movimentos?
Answer:
Esses movimentos são movimentos naturais.
Explicação:
Se uma pedra cair do topo de um telhado ou edifício, a pedra se moverá em direção à terra, enquanto a fumaça produzida devido à queima da madeira vai para cima, então de acordo com Aristosteles esses tipos de movimento são chamados de movimento natural porque de acordo à definição de movimento natural que não requer nenhuma força, então esses dois movimentos também se movem na direção para baixo e para cima sem usar qualquer força, então podemos dizer que esses movimentos são naturais.
What would it take to get the stone slab to move? Propose an
idea and explain how it would work in the context of Newton's
laws.
In order to get a stone slab to move, one would have to apply force to it. This can be done in a number of ways, depending on the situation. Here are a few possible laws that could be proposed for moving a stone slab:1. Newton's first law of motion: This law states that an object at rest will stay at rest unless acted upon by an external force. Therefore, to move a stone slab, one would need to apply a force to it.
This could be done by pushing it, pulling it, or applying a force from a lever or other mechanical device. Newton's second law of motion: This law states that the force required to accelerate an object is directly proportional to its mass. Therefore, to move a stone slab, a greater force would be required if it is more massive. This could be accomplished by using more people to push or pull the slab, or by using a larger lever or other mechanical device.. Friction: Friction is the force that opposes motion between two surfaces that are in contact with each other. In order to move a stone slab, one would need to overcome the friction between it and the surface it is resting on. This could be accomplished by reducing the friction (for example, by using rollers or lubricant), or by applying a greater force to overcome the friction.Work: Work is defined as the product of force and distance. Therefore, in order to move a stone slab, one would need to apply a force over a certain distance.This could be accomplished by pushing or pulling the slab over a distance, or by using a lever or other mechanical device to apply force over a greater distance.These are just a few possible laws that could be proposed for moving a stone slab. Ultimately, the best approach will depend on the specific situation and the resources available.For such more question on Newton's second law
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A 7.40-kg object initially has 347 J of gravitational potential energy. Then an elevator lifts the object a distance of 20.6 m above its previous position. How much work did the elevator perform on the object?
Answer:
W = 1493.9 J = 1.49 KJ
Explanation:
The work done by the elevator on the object will be equal to the gain in is potential energy:
W = ΔP.E
W = mgΔh
where,
W = Work = ?
m = mass of object = 7.4 kg
g = 9.8 m/s²
Δh = gain in height = 20.6 m
Therefore,
W = (7.4 kg)(9.8 m/s²)(20.6 m)
W = 1493.9 J = 1.49 KJ
What is an example of a chemical change
Answer:
Hello, Rotting, burning, cooking, and rusting are all further types of chemical changes because they produce substances that are entirely new chemical compounds. For example, burned wood becomes ash, carbon dioxide, and water. When exposed to water, iron becomes a mixture of several hydrated iron oxides and hydroxides.
Explanation:
I hape this helps remember to make someone smile today
A train travels a 400-km route and makes five stops in seven hours. Which equation is used to calculate the train’s average speed?
A.
Average speed = Sum of instantaneous speeds
B.
Average speed = Total distance x Total time
C.
Average speed = Total distance + Total time
D.
Average speed = Total distance ÷ Total time
Figure out the volume of the cheese.
Answer:
volume of cheese=l×b×h=5×6×4=120cm³
density=mass/volume=(467/120)=3.89g/m³
A recipe gives the instructions below.
What type of separation methods are described in the
recipe?
After browning the meat, pour off the fat from the pan.
To further reduce fat, use a strainer.
O decantation and screening
O distillation and screening
O decantation and centrifugation
O distillation and filtration
N
<
O
a
2:28 PM
002
Answer: It’s A
Explanation:
A man standing on the top of a tower 60m high throws a ball with a velocity of 20m/s in the vertically u[wards direction.
(a) How long will it take the ball to pass the man moving in the downwards direction ?
(b) What is the maximum height attained by the ball ?
(c) How long will it take the ball to hit the ground ? ( Take g = 10 m/s^2 )
(a) It will take 2 seconds for the ball to pass the man moving in the downward direction.
(b) The maximum height attained by the ball is 20 meters.
(c) The ball will take 2+2\sqrt{2} seconds to hit the ground.
(a) How long will it take the ball to pass the man moving in the downward direction?
We can use the equation of motion:
v = u + at,
where:
v = final velocity (0 m/s since the ball will momentarily stop when passing the man),
u = initial velocity (20 m/s upwards),
a = acceleration (due to gravity, -10 m/s²),
t = time.
Substituting the known values we get:
0 = 20 - 10t.
Simplifying the equation:
10t = 20,
t = 20/10,
t = 2 seconds.
Therefore, it will take 2 seconds for the ball to pass the man moving in the downward direction.
(b) What is the maximum height attained by the ball?
To find the maximum height attained by the ball, we can use the following equation:
v² = u² + 2as,
where:
v = final velocity (0 m/s at the maximum height),
u = initial velocity (20 m/s upwards),
a = acceleration (acceleration due to gravity, -10 m/s²),
s = displacement.
The maximum height will be achieved when v = 0. Rearranging the equation, we get:
0 = (20)² + 2(-10)s.
Simplifying the equation:
400 = -20s.
Dividing both sides by -20:
s = -400/-20,
s = 20 meters.
Therefore, the maximum height attained by the ball is 20 meters.
(c) How long will it take the ball to hit the ground?
To find the time it takes for the ball to hit the ground, we can use the following equation:
s = ut + (1/2)at²,
where:
s = displacement (60 meters downwards),
u = initial velocity (20 m/s upwards),
a = acceleration (acceleration due to gravity, -10 m/s²),
t = time.
Rearranging the equation, we get:
-60 = 20t + (1/2)(-10)t².
Simplifying the equation:
-60 = 20t - 5t².
Rearranging to form a quadratic equation:
5t² - 20t - 60 = 0.
Dividing both sides by 5:
t² - 4t - 12 = 0.
Solving the equation using the quadratic formula, we get:
t = (4 ± sqrt(16 + 4 x 12)) / 2
t = (4 ± 4sqrt(2)) / 2
t = 2 ± 2sqrt(2)
Since time cannot be in negative terms, we ignore the negative value of t. Therefore, the time it takes for the ball to hit the ground is:
t = 2 + 2sqrt(2) seconds
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\( \\\)
(a) How long will it take the ball to pass the man moving in the downwards direction ?
Using Equation of Motion:-
\( \large\bigstar \: \: \: { \underline { \overline{ \boxed{ \frak{v = u + at}}}}}\)
where:-
→ v denotes final velocity→ u denotes initial velocity→ a denotes acceleration→ t denotes timePlugging in Values:-
\( \large \sf \longrightarrow \: v = u + at\)
\( \large \sf \longrightarrow \: 0 = 20 + ( - 10)t \: \)
\( \large \sf \longrightarrow \: 0 - 20=( - 10)t \: \)
\( \large \sf \longrightarrow \: - 10t = - 20\: \)
\( \large \sf \longrightarrow \: t = \frac{ - 20}{ - 10} \\ \)
\( \large \sf \longrightarrow \: t = 2 \: secs \\ \)
Therefore, it will take 2 seconds for the ball to pass the man moving in the downward direction.
________________________________________
\( \\\)
(b) What is the maximum height attained by the ball ?
→ To solve the given problem, we can use the equations of motion
Using Equation of Motion:-
\( \large\bigstar \: \: \: { \underline { \overline{ \boxed{ \frak{ {v}^{2} = {u}^{2} + 2as}}}}}\)
where:
→ v denotes final velocity→ u denotes initial velocity→ a denotes acceleration→ s denotes displacementPlugging in Values:-
\( \large \sf \longrightarrow \: {v}^{2} = {u}^{2} + 2as\)
\( \large \sf \longrightarrow \: {(0)}^{2} = {(20)}^{2} + 2( - 10)s\)
\( \large \sf \longrightarrow \: 0 = 400 + 2( - 10)s\)
\( \large \sf \longrightarrow \: 400 + (- 20)s = 0\)
\( \large \sf \longrightarrow \: 400 - 20 \: s = 0\)
\( \large \sf \longrightarrow \: - 20 \: s = - 400\)
\( \large \sf \longrightarrow \: \: s = \frac{ - 400}{ - 20} \)
\( \large \sf \longrightarrow \: \: s = 20 \: metres\)
Therefore, the maximum height attained by the ball is 20 meters.
________________________________________
\( \\\)
(c) How long will it take the ball to hit the ground ?
Using Equation of Motion:-
\( \large\bigstar \: \: \: { \underline { \overline{ \boxed{ \frak{ s= ut + \frac{1}{2}a{t}^{2}}}}}}\)
where:
→ s denotes Displacement → u denotes initial velocity→ a denotes acceleration→ t denotes timePlugging in Values:-
\( \large \sf \longrightarrow \: s= ut + \frac{1}{2}a{t}^{2}\)
\( \large \sf \longrightarrow \: -60= 20t + \frac{1}{2}(-10){t}^{2}\)
\( \large \sf \longrightarrow \: -60= 20t + \frac{-10}{2}\times{t}^{2}\)
\( \large \sf \longrightarrow \: -60= 20t + (-5)\times{t}^{2}\)
\( \large \sf \longrightarrow \: -60= 20t-5\times{t}^{2}\)
\( \large \sf \longrightarrow \: 20t-5{t}^{2}+60\)
\( \large \sf \longrightarrow \: {t}^{2}-4t-12\)
\( \large \sf \longrightarrow \: t=\frac{-b \pm\sqrt{{b}^{2}-4ac}}{2a} \)
\( \large \sf \longrightarrow \: t=\frac{-(-4) \pm\sqrt{{(-4)}^{2}-4(1)(-12)}}{2(1)} \)
\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{16-4(-12)}}{2} \)
\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{16-(-48)}}{2} \)
\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{16+48}}{2} \)
\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{64}}{2} \)
\( \large \sf \longrightarrow \: t=\frac{4 \pm 8}{2} \)
\( \large \sf \longrightarrow \: t=\frac{4 + 8}{2} \qquad or \qquad t=\frac{4 - 8}{2} \)
\( \large \sf \longrightarrow \: t=\frac{12}{2} \qquad or \qquad t=\frac{-4}{2} \)
\( \large \sf \longrightarrow \: t=6 \qquad or \qquad t= -2 \)
Since time cannot be negative , Therefore, it will take 6 secs to hit the ground!!
________________________________________
\( \\\)
✅
Describe how computer climate models help scientists understand possible future climate changes. How reliable are these computer models in making predictions about global warming? Discuss any limitations in these models.
Answer:
To predict future climate, scientists use computer programs called climate models to understand how our planet is becoming different. Climate models work like a laboratory in a computer. They allow scientists to study how the unlike factors interact to influence a region's climate.
Now a new evaluation of global climate models used to project Earth's future global average surface temperatures over the past half-century answers that question: most of the models have been reasonably accurate.
Explanation:
I got a 100% on this assignment copy it and put it on your notes then go sentence by sentence copy but dont highlight any "." you will not be able to paste it into the box add the "." after you paste it, it one sentence.
ONE SENTENCE AT A TIME NO ". ' - or :" AT ALL
Qué esperas que pase cuando las partículas alfa de poca energía se acerquen a un núcleo con muchos protones?
Answer:
Sufrirá una deflección en su recorrido.
Explanation:
Las partículas alfa son nucleos de He (dos protones mas dos neutrones), por lo tanto tienen una carga neta positiva.
Ahora, al acercarse al nucleo de un átomo con muchos protones y con baja energía, la partícula alfa sufrirá una deflección en su recorrido debido a las fuerzas de repulsión electrostática que siente la partícula, ya que el nucelo posee caraga positiva.
Espero te haya sido de ayuda.
Explain how inductive reasoning is inferior to deductive reasoning in establishing theory.
Answer: Created Fall 2016 by Ronald Wilson Inductive reasoning uses a set of specific observations to reach an overarching conclusion; it is the opposite of deductive reasoning. So, a few particular premises create a pattern which gives way to a broad idea that is likely true.
Explanation: No explanation lol. But I hope this is helpful!
HELP PLEASE QUICK QUICK QUICK I’ll give BRAINLIEST
Answer:
Dude this is based on some egg you have
Explanation:
Calcula la fuerza que tiene que realizar el brazo sobre el punto medio del mango de la pala para levantar la tierra situada en la cuchara que pesa 8kg
Explanation:
1- El primer paso para calcular la fuerza del brazo en el punto medio de la excavadora para levantar la tierra, es averiguar dónde está el fulcro, que en este caso está en las manos.
2- El segundo paso es calcular el brazo de potencia, al que llamaremos Bp, y el brazo de resistencia, que estará representado por Br.
Si Bp es igual a la distancia de la potencia al fulcro, Bp = 60cm
y si Br es igual a la distancia desde la resistencia al fulcro, entonces
Br = 40 + 60 = 100cm
3- Ahora aplicamos la fórmula de la ley de la palanca. Nosotros
piden que se aplique la fuerza en manos de
en el medio, es decir, la potencia P. La fórmula sería:
Y en el tercer paso, aplicaremos la fórmula de la ley de la palanca, que es:
P = R x Br / Bp
P = 8 x 100/60
P = 13,33 Kgf
Entonces la respuesta final es:
P = 13,33 Kgf
A ball is kicked off of a roof at 23 m/s [R 25° U]. What is the height of
the building if it lands 2.8 s later?
Answer:
Explanation:
Considering the fact that we ave been given an angle of inclination here, we best use it! That means that the velocity of 23 m/s is actually NOT the velocity we need; I tell my students that it is a "blanket" velocity but is not accurate in either the x or the y dimension of parabolic motion. In order to find the actual velocity in the dimension in which we are working, which is the y-dimension, we use the formula:
\(v_{0y}=v_0sin\theta\) and filling in:
\(v_{0y}=23sin(25)\) which gives us an upwards velocity of 9.7 m/s. So here's what we have to work with in its entirety:
\(v_{0y}=9.7m/s\)
a = -9.8 m/s/s
t = 2.8 seconds
Δx = ?? m
The one-dimensional motion equation that utilizes all of these variables is
Δx = \(v_0t+\frac{1}{2}at^2\) and filling in:
Δx = \(9.7(2.8)+\frac{1}{2}(-9.8)(2.8)^2\) I am going to do the math according to the correct rules of significant digits, so to the left of the + sign and to 2 sig fig, we have
Δx = 27 + \(\frac{1}{2}(-9.8)(2.8)^2\) and then to the right of the + sign and to 2 significant digits we have
Δx = 27 - 38 so
Δx = -11 meters. Now, we all know that distance is not a negative value, but what this negative number tells us is that the ball fell 11 meters BELOW the point from which it was kicked, which is the same thing as being kicked from a building that is 11 meters high.
How far away from the surface of earth does the acceleration due to gravity will be inclined by 36% of its value on the surface of earth? Radius of earth is 6400 km
Answer:
1,600 km
Explanation:
since the acceleration due to gravity reduces by 36%, it means that (1 - 36%) of acceleration still remains:
g' = 64g/100
using the acceleration formula:
g' = g x [R² / (R + height)²]
64g/100 = g x [R² / (R + height)²]
64/100 = R² / (R + height)²
√(64/100) = √[R² / (R + height)²]
8/10 = R / (R + height)
8 (R + height) = 10R
8R + 8height = 10R
8height = 2R
height = 2R / 8 = R / 4
R = 6,400 km
height = 6,400 km / 4 = 1,600 km
Answer:
The acceleration due to gravity will be inclined 1600 KM by 36% of its value on the surface of earth