A____ and _______ takes the shape of their containers

Combustion analysis of fluorene, a polycyclic aromatic hydrocarbon used to make dyes, plastics, and pesticides, produces 11.44 g CO2 and 1.80 g H2O. The empirical formula of fluorene C₆H₄.

CₓHₐ + O2 → CO2 + H2O Since the combustion is complete, so the total mass of the reactants is equal to the total mass of the reactants Therefore, Mass of O2 = (17.9 + 9.14) – 5.9 = 21.14 grams Here, the empirical formula for the hydrocarbon is CₓHₐ. So, now we have to need to determine the number of moles of the O2, CO2, and H2O :- Mole of CO2 = 17.9/44 = 0.4068 Mole of H2O = 9.14/18 = 0.5078 Mole of O2 = 21.14/32 = 0.6606. The empirical formula for the compound containing uranium and fluorine is UF6. Explanation: The empirical formula of a compound represents the lowest whole number ratio of elements in the compound. This ratio is represented by subscripts in the formula. by this information, we can consider that combustion analysis of fluorene, a polycyclic aromatic hydrocarbon used to make dyes, plastics, and pesticides, produces 11.44 g CO2 and 1.80 g H2O. The empirical formula of fluorene C₆H₄.

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Answer:

The two fish are of the same species because they can mate with each other. Also, the characteristics of the blind cave fish enable them to live in caves. Eyes need energy. So, developing bodies with no eyes allowed these fish to function more efficiently.

Explanation:

plato answer

Answer:  A change in the first second and third

Explanation:

An electron in the lowest energy state is called as ground state and is also known as stable energy level.  An electron in the upper energy state is called as excited state and is also known as unstable energy level.

Electronic configuration represents the total number of electrons that a neutral element contains. The electrons are filled according to Afbau's rule in order of increasing energies. As the atomic number of sodium is 11. The electronic configuration of sodium will be represented in ground state as:

\(Na:11:1s^22s^22p^63s^1\)

Thus any electron if occupies a higher shell, the atom is said to be in excited state.

The molecular formula for both cis-2-butene and trans-2-butene is C₄H₈. compounds that have the same molecular formula but have different structures are called isomers.

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Option B is correct which is Measurements of fossilized tree rings from the Cretaceous period is a paleoclimate proxy.

The study of past climates ("paleoclimatology"), climate proxies are preserved physical characteristics of the past that stand in for direct meteorological measurements and enable scientists to reconstruct the climatic conditions over a longer fraction of the Earth's history. Reliable global records of climate only began in the 1880s, and proxies provide the only means for scientists to determine climatic patterns before record-keeping began.

A large number of climate proxies have been studied from a variety of geologic contexts. Examples of proxies include stable isotope measurements from ice cores, growth rates in tree rings, species composition of sub-fossil pollen in lake sediment or foraminifera in ocean sediments, temperature profiles of boreholes, and stable isotopes and mineralogy of corals and carbonate speleothems.

Proxies can be combined to produce temperature reconstructions longer than the instrumental temperature record and can inform discussions of global warming and climate history. The geographic distribution of proxy records, just like the instrumental record, is not at all uniform, with more records in the northern hemisphere.[3]

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It causes freezing point depression which requires the gasoline to reach a much lower temperature before freezing. Hence, option C is correct.

Whenever a solute is added to a solution/solvent, it leads to depression in the freezing point of that solution/solvent. Depression in the freezing point of a solution on the addition of a solute is a colligative property.

A colligative property is a physical property which depends upon the number of solutes added not on the nature of solutes which means it does not matter whether we are adding 1000 particles of sugar or salt in water, the depression in the freezing point will occur by the same °C. Also, the more a solute is added the more will be the depression at the freezing point.

The formula for depression at the freezing point is mentioned as under:

             Δ T = K x m

where Δ T = freezing point depression;

                 K = cryoscopic constant;

                 m = molality of the solution.

For example, The freezing point of water is 0 °C but as soon as we add a 92 gm solute like NaCl (common salt) in 1000 gm of water, its freezing point will be lower to −3.72 °C.

Hence, option C is correct.

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Static charge is developed within a body temporarily with an induced polarization by rubbing on his leg . Electrons are exchanged from his hand  to the door when touched .

When two materials rub against each other in which one to be  good conductor, they will attract by the induced polarization. Rubbing causes the free electrons in the condutor to be transferred towards the surface in contact.

This will cause a deformation that, the random charges in the material get polarized where the electrons from one surface will repel to the opposite pol and positive charges will align in a pole close to the charged body.

This charge separation causes the positive pole of the metal gets attracted into the hand. Hence, the electrons from the hand move to the positive pole of metal and the spark  generate in the opposite direction.

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To increase the SO3/SO2 mole ratio at equilibrium, you can increase temperature, decrease pressure, remove SO3, or use a catalyst.



To increase the SO3/SO2 mole ratio in a reaction at equilibrium, you can employ several strategies. Firstly, increasing the temperature would favor the forward reaction (SO2 + O2 -> SO3), as it is exothermic. By applying Le Chatelier's principle, the equilibrium can be shifted towards the products, resulting in a higher SO3/SO2 ratio. Secondly, reducing the pressure can promote the formation of SO3. If the reaction involves gases, decreasing the pressure will favor the side with fewer moles of gas, driving the equilibrium towards the formation of SO3.

Another approach is to selectively remove the product SO3 from the reaction mixture. This prompts the equilibrium to shift in the forward direction, compensating for the loss and increasing the SO3/SO2 mole ratio. Finally, adding a catalyst can accelerate the rate of the reaction, although it does not directly impact the equilibrium position. Implementing these strategies should be done with caution, considering the specific reaction conditions and requirements.

To increase the SO3/SO2 mole ratio at equilibrium, you can increase temperature, decrease pressure, remove SO3, or use a catalyst.

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To determine the molar concentration of each ion present in the solutions, we need to calculate the total moles of each ion and divide it by the total volume of the resulting solution.

(a) Mixture: 54.1 mL of 0.33 M NaCl and 76.0 mL of 1.33 M NaCl

For NaCl, the number of moles (n) can be calculated using the formula:

n = M * V

n(NaCl) = 0.33 M * 54.1 mL + 1.33 M * 76.0 mL

Next, we need to determine the concentration of each ion. Since NaCl dissociates into Na+ and Cl- ions in solution, the molar concentration of each ion is the same as that of NaCl.

M(Na+) = M(Cl-) = n(NaCl) / (V1 + V2)

Where V1 and V2 are the volumes of the solutions used.

M(Na+) = M(Cl-) = n(NaCl) / (54.1 mL + 76.0 mL)

(b) Mixture: 134 mL of 0.66 M HCl and 134 mL of 0.17 M HCl

Similarly, we calculate the moles of HCl:

n(HCl) = 0.66 M * 134 mL + 0.17 M * 134 mL

The concentration of each ion is the same as that of HCl:

M(H+) = M(Cl-) = n(HCl) / (V1 + V2)

Where V1 and V2 are the volumes of the solutions used.

M(H+) = M(Cl-) = n(HCl) / (134 mL + 134 mL)

(c) Mixture: 36.3 mL of 0.340 M Ba(NO3)2 and 25.5 mL of 0.211 M AgNO3

For Ba(NO3)2, we calculate the moles:

n(Ba(NO3)2) = 0.340 M * 36.3 mL

For AgNO3, we calculate the moles:

n(AgNO3) = 0.211 M * 25.5 mL

The concentration of each ion is determined as follows:

M(Ba2+) = n(Ba(NO3)2) / (V1 + V2)

M(Ag+) = n(AgNO3) / (V1 + V2)

M(NO3-) = 2 * M(Ba2+) + M(Ag+)

Where V1 and V2 are the volumes of the solutions used.

M(Ba2+) = n(Ba(NO3)2) / (36.3 mL + 25.5 mL)

M(Ag+) = n(AgNO3) / (36.3 mL + 25.5 mL)

M(NO3-) = 2 * M(Ba2+) + M(Ag+)

(d) Mixture: 13.6 mL of 0.650 M NaCl and 22.0 mL of 0.131 M Ca(C2H3O2)2

For NaCl, we calculate the moles:

n(NaCl) = 0.650 M * 13.6 mL

For Ca(C2H3O2)2, we calculate the moles:

n(Ca(C2H3O2)2) = 0.131 M * 22.0 mL

The concentration of each ion is determined as follows:

M(Na+) = n(NaCl) / (V1 + V2)

M(Cl-) = n(NaCl)

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The pillar of sustainability broken by recycling electronics in India is environmental sustainability. Implementing a law that restricts electronics recycling to the US would not necessarily be the most effective solution, as it overlooks the complex global dynamics of electronic waste management.

Recycling electronics in India often involves improper disposal methods, such as burning or dismantling without proper safety measures. This leads to environmental pollution, including the release of hazardous substances into the air, soil, and water, thus violating the principle of environmental sustainability.

However, simply mandating that electronics can only be recycled in the US may not be the most optimal solution. Electronic waste is a global issue, and restricting recycling to a single country disregards the fact that electronic products are manufactured and consumed worldwide. A more comprehensive approach to addressing electronic waste would involve international cooperation, strict regulations, and monitoring of recycling practices to ensure they meet environmental standards.

Efforts should focus on improving recycling practices globally, including promoting responsible electronic waste management, developing sustainable recycling infrastructure in multiple countries, and encouraging the adoption of safe and environmentally friendly recycling practices. This approach would foster global sustainability and address the challenges associated with electronic waste disposal more effectively than a geographically limited restriction.

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Answer: The balanced equation is 4,3,2,  

Answer: Balanced equation = 4Fe + 3O2 => 2Fe2O3.

Explanation:

Answer:

True

Explanation:

Metal ions such as Zn²⁺ and Fe³⁺ are often needed by enzymes as cofactors or prosthetic groups that facilitate enzymatic reactions.

These metal ions assist enzymes by stabilizing their structure, enhancing substrate binding, and participating directly in chemical reactions to accelerate catalysis. They help the enzymes achieve the necessary specificity and efficiency required for various biological processes.

For instance, Zn²⁺ is involved in the active sites of several metalloenzymes, such as carbonic anhydrase and carboxypeptidase. It typically acts as a Lewis acid, accepting electron pairs from substrates and facilitating the nucleophilic attack on the substrate. On the other hand, Fe³⁺ is found in enzymes like cytochrome P450 and catalase. It plays a vital role in redox reactions, participating in the transfer of electrons and enabling the conversion of substrates to products.

Overall, metal ions such as Zn²⁺ and Fe³⁺ are essential for proper enzyme function, as they help ensure the precise and efficient execution of various enzymatic processes vital to maintaining biological systems.

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Answer: what materials transmits the most light waves?

Explanation:

Answer: There are 1.51 moles present in \(9.12 \times 10^{23}\) atoms.

Explanation:

According to the mole concept, there are \(6.022 \times 10^{23}\) atoms present in one mole of every substance.

Hence, moles present in \(9.12 \times 10^{23}\) atoms are calculated as follows.

\(Moles = \frac{9.12 \times 10^{23}}{6.022 \times 10^{23}}\\= 1.51 mol\)

Thus, we can conclude that there are 1.51 moles present in \(9.12 \times 10^{23}\) atoms.

Answer:

0.694 cents per second

Explanation:

25x100=2500 cents per hour, 2500/60 = 41.67 per minute and 41.67/60=0.694 cents per second

In a periodic table, the different columns are called "groups" or "families."

The groups are numbered from 1 to 18, and they are arranged in vertical columns from left to right. Each group contains elements with similar chemical properties and the same number of valence electrons.

The elements within a group exhibit similar trends in terms of their reactivity, electronegativity, and other properties.

Some groups have specific names or designations. For example, Group 1 is known as the "alkali metals," Group 2 as the "alkaline earth metals," Group 17 as the "halogens," and Group 18 as the "noble gases." These names reflect the characteristic properties of the elements within those groups.

The periodic table also has horizontal rows called "periods," which represent the number of electron shells or energy levels occupied by the elements' electrons. Each period is labeled with a number from 1 to 7.

Overall, the periodic table is a systematic arrangement of elements that allows scientists to organize and understand the properties and relationships of different elements based on their atomic structure and chemical behavior.

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Answer:

Atomic radii vary in a predictable way across the periodic table. As can be seen in the figures below, the atomic radius increases from top to bottom in a group, and decreases from left to right across a period. Thus, helium is the smallest element, and francium is the largest.

Answer:

Drinking water should have sufficiently low levels of dissolved salts or microbes.

Explanation:

If 18.4 g of ZnO and an unidentified amount of sulphur dioxide (SO2) are recovered from the reaction involving 46.5 g of ZnS and 13.3 g of oxygen, the percent yield is:  53.13%.

First, the chemical reaction needs to be balanced.

ZnS + 1.5O₂ → ZnO + SO₂

Find limiting reactant.

= 46.5 grams of ZnS * (1 mol ZnS / 97.4 g of ZnS) * (32 g O₂ / 1 mol O₂)

= 22.9158 g of O₂

We required 22.9158 g of O₂ and 20.42 grams are given.

It makes  O₂ limiting reactant.

Estimated mass of the ZnO recovered.

= 20.42 g of O₂ * (1 mol ZnO / 1.5 mol O₂) * (81.4 g of ZnO / 1 mol ZnO)

= 34.629 g ZnO

Theoretically, 34.629 grammes of ZnO were retrieved. The following equation can be used to get the percent yield:

Percentage yield = actual yield / theoretical yield  * 100

Put the values;

Percentage yield = 18.4 / 34.629 *100

Percentage yield =  53.13%

Thus, if 18.4 g of ZnO and an unidentified amount of sulphur dioxide (SO2) are recovered from the reaction involving 46.5 g of ZnS and 13.3 g of oxygen, the percent yield is:  53.13%.

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To calculate the ratio of uranium-235 to lead-207 atoms in the mineral sample, we can use the atomic masses and the concept of radioactive decay.

The ratio of uranium-235 to lead-207 atoms in the mineral sample is 1:3.The atomic mass of uranium-235 (U-235) is approximately 235 atomic mass units (amu), while the atomic mass of lead-207 (Pb-207) is approximately 207 amu.

Given:

Number of uranium-235 atoms = 50,000

Number of lead-207 atoms = 150,000

To find the ratio, we divide the number of uranium-235 atoms by the number of lead-207 atoms:

Ratio = Number of uranium-235 atoms / Number of lead-207 atoms

Ratio = 50,000 / 150,000

Simplifying the ratio:

Ratio = 1/3

Therefore, the ratio of uranium-235 to lead-207 atoms in the mineral sample is 1:3.

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The ion with an [Ar]3d6 electron configuration among Co₂⁺, Fe₂⁺, and Ni₂⁺ is Fe₂⁺ only.

So, the answer is option B.

Co₂⁺ has an electron configuration of [Ar]3d7. Its atomic number is 27, and after losing 2 electrons, it has 25 electrons remaining.

Fe₂⁺ has an electron configuration of [Ar]3d6. Its atomic number is 26, and after losing 2 electrons, it has 24 electrons remaining, which results in the [Ar]3d6 configuration.

Ni₂⁺ has an electron configuration of [Ar]3d8. Its atomic number is 28, and after losing 2 electrons, it has 26 electrons remaining.

Based on the given information, option b) Fe₂⁺ only is the correct answer, as it has the [Ar]3d6 electron configuration.

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When we have an acid-base reaction, the acid will be that substance that donates protons, in the form of H+ ions. The base will be the one that accepts the H+ ions. Now, the base that accepts the protons becomes a potential proton donor, thus becoming a conjugate acid. This is the case with H3O+.

H2O accepts H+ ions, so it is a base and when it becomes H3O+ it becomes a potential H+ proton donor, that is, a conjugate acid.

so, the answer will be B. Conjugate acid

Answer:

Frog, shark, snake, Lion, tortoise, salamander, ostrich

Answer:

The person above me is correct it is frog, shark, snake, Lion, tortoise, salamander, ostrich

Explanation:

Answer:

A. The total mass of the reactants in a reaction equals the total mass of the product(s).

Explanation:

The law of conversation of matter tells us that in a chemical reaction, matter is never created or destroyed, it's simply converted from one form to another. So the mass of reactants should always equal the mass of the products in a chemical reaction.

The mass of the mixture is 95.8 g and the percentage by mass of cyclohexane in the mixture is 81.33%.

To calculate the percentage by mass of cyclohexane in the mixture, you need to use the formula:

Percentage by mass = (mass of component / total mass of mixture) × 100

Given that you have a mixture of cyclohexane and water and the density of the mixture is 0.958 g/mL,

1. To determine the mass of the mixture, you need to know the volume of the mixture and the density of the mixture. Since the density of the mixture is given, you can use the following formula to determine the mass of the mixture:

mass of mixture = density of mixture × volume of mixture

The mass of the mixture is: mass of mixture = 0.958 g/mL × 100 mL = 95.8 g

2. Since the density of cyclohexane is given as 0.779 g/mL, you can use the following formula to determine the mass of cyclohexane:

mass of cyclohexane = density of cyclohexane × volume of cyclohexane = 0.779 g/mL × 100 mL = 77.9 g

3. Using the formula given above, you can calculate the percentage by mass of cyclohexane in the mixture:

percentage by mass of cyclohexane = (mass of cyclohexane / mass of mixture) × 100

percentage by mass of cyclohexane = (77.9 g / 95.8 g) × 100 = 81.33%

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D. Able to answer for one's conduct and obligations

The amygdala is a pair of almond-shaped structures located in the brain's temporal lobes. It is part of the limbic system, which is involved in the processing of emotions and memory. The amygdala is involved in the formation of memories associated with emotional events, as well as the reaction to those memories.

The amygdala also plays a role in the regulation of the body's fight-or-flight response, which is the autonomic nervous system's response to danger or perceived danger. It is thought to be involved in the formation of fears and phobias, as well as the development of aggressive behaviors. In addition, the amygdala is believed to be involved in the processing of social cues, such as facial expressions and body language.

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The main difference between brittle and ductile deformation is brittle deformation involves sudden fracturing, while ductile deformation involves permanent deformation without fracturing.

Brittle deformation refers to the breaking or fracturing of a material without significant plastic (permanent) deformation.

Ductile deformation, on the other hand, involves the gradual and permanent deformation of a material without fracturing.

The main difference between brittle and ductile deformation is brittle deformation involves sudden fracturing without significant plastic deformation, while ductile deformation involves gradual, permanent deformation without fracturing.

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