Let's name the variables we know and those we need:
q1: first charge; q1 = 9.12*10^-9 C
q2: second charge; q2 = -2.78*10^-9 C
r: distance between midpoint and the charges; r = 0.0499/2 = 0.02495 m
k: Coulomb's constant; k = 8.99*10^9
B1: field strength caused by first charge
B2: field strength caused by second
B1 = k|q1|/r^2 = 8.99*10^9*9.12*10^-9/0.02495^2
B1 = 131708.387 N/C
B2 = k|q2|/r^2 = 8.99*10^9*2.78*10^-9/0.02495^2
B2 = 40147.951 N/C
B = B1+B2 = 131708.387+40147.951 = 171856.338 N/C = 1.71856*10^5 N/C
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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What is the fnet of the fbd in the middle
-200 N
Explanation
Step 1
we can see that on the object are acting vertical forces, if we assume the y-positive axis as positive ( upwards) then we have
\(\begin{gathered} \sum ^{\square}_{\text{xorce-in y}}=600N-800N \\ \sum ^{\square}_{\text{xorce-in y}}=-200\text{ N} \end{gathered}\)therefore, the answer is -200
Problem 05.086 - Water pumped from a lower reservoir to a higher reservoir Water is pumped from a lower reservoir to a higher reservoir by a pump that provides 21 kW of useful mechanical power to the water. The free surface of the upper reservoir is 45 m higher than the surface of the lower reservoir. If the flow rate of water is measured to be 0.03 m3/s, determine the irreversible head loss of the system and the lost mechanical power during this process. Take the density of water to be 1000 kg/m3. The irreversible head loss of the system is 26.35 m. The lost mechanical power in this process is kW.
Answer:
Lost Mechanical Power = 7.7565 KW
Head Loss = 26.35 m
Explanation:
First, we will find the useful mechanical power used to transport water to the higher reservoir:
\(P_{useful} = \rho ghV\)
where,
P_useful = Useful mechanical Power = ?
ρ = density of water = 1000 kg/m³
g = acceleration due to gravity = 9.81 m/s²
h = height = 45 m
V = Volume flow rate = 0.03 m³/s
Therefore,
\(P_{useful} = (1000\ kg/m^3)(9.81\ m/s^2)(45\ m)(0.03\ m^3/s)\\P_{useful} = 13243.5\ W = 13.2435\ KW\)
Now, the lost mechanical power will be:
\(Lost\ Mechanical\ Power = Total\ Mechanical\ Power - Useful\ power\\Lost\ Mechanical\ Power = 21\ KW - 13.2435\ KW\\\)
Lost Mechanical Power = 7.7565 KW
Now, for the head loss:
\(Lost\ Mechanical\ Power = \rho g(Head\ Loss)V\\Head\ Loss = \frac{Lost\ Mechanical\ Power}{\rho gV} \\\\Head\ Loss = \frac{7756.5\ W}{(1000\ kg/m^3)(9.81\ m/s^2)(0.03\ m^3/s)} \\\)
Head Loss = 26.35 m
A 500 g squirrel with a surface area of 895 cm2 falls from a 5.6-m tree to the ground. Estimate its terminal velocity. (Use the drag coefficient for a horizontal skydiver. Assume that the squirrel can be
approximated as a rectanglar prism with cross-sectional area of width 11.3 cm and length 22.6 cm. Note, the squirrel may not reach terminal velocity by the time it hits the ground. Give the squirrel's
terminal velocity, not it's velocity as it hits the ground.)
x m/s
What will be the velocity of a 50.0 kg person hitting the ground, assuming no drag contribution in such a short distance?
x m/s
8.3 m/s is the terminal velocity of the squirrel can be calculated using the equation for terminal velocity and 10.8 m/s is the velocity of a 50.0 kg person hitting the ground.
What is velocity?
Velocity is a measure of the speed of an object's motion in a particular direction. It is a vector quantity, meaning it has both magnitude and direction. Velocity is usually measured in meters per second (m/s).
The terminal velocity of the squirrel can be calculated using the equation for terminal velocity of an object in a fluid, which is given by Vt = (2×m×g)/(ρ×Cd×A). Here, m is the mass of the object, g is the acceleration due to gravity, ρ is the density of the fluid, Cd is the drag coefficient, and A is the reference area of the object. The drag coefficient for a horizontal skydiver is 0.8, and the density of air is 1.225 kg/m^3. Therefore, the terminal velocity of the squirrel can be calculated as Vt = (2×500×9.8)/(1.225×0.8×895) = 8.3 m/s.
The velocity of a 50.0 kg person hitting the ground can be calculated using the equation for the velocity at the end of a fall, which is given by Vf = sqrt(2×g×h). Here, g is the acceleration due to gravity and h is the height of the fall. Therefore, the velocity of the person hitting the ground can be calculated as Vf = sqrt(2×9.8×5.6) = 10.8 m/s.
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What is the gravitational potential energy of a 2100 kg car at the top of an 18 m parking garage?
\(\qquad\qquad\huge\underline{{\sf Answer}}♨\)
Gravitational Potential of an object with mass m, and height of h metre is :
\(\qquad \sf \dashrightarrow \:mgh\)
Now, if the mass of object is 2100 kg, height of 18 m is placed in there, then it's gravitational potential energy is ~
\(\qquad \sf \dashrightarrow \:2100 \times 10 \times 18\)
\(\qquad \sf \dashrightarrow \:378000 \: \: joules\)
\(\qquad \sf \dashrightarrow \:3.78 \times 10 {}^{5} \: \: joules\)
A 441 N crate is being pulled by a rope, up a frictionless
inclined plane, which meets the horizontal at an angle of 35°.
Find the magnitude of normal force acting on the crate.
The crane weighs 441 N. The horizontal component of the normal force at an angle of 35° is 361 N.
What is force?Force is physical quantity generating a displacement or deformation for a body. Force is having a magnitude and direction thus, it is a vector quantity.
The normal force acting on a body is mg, that is the product of its mass and acceleration due to gravity. Force can have a vertical and horizontal component.
vertical component of normal force = N sin ∅
horizontal component = N cos ∅.
Given the angle in the inclined plane is 35° in horizontal direction.
Thus normal force = 441 N × cos 35° = 361 N.
Therefore, the magnitude of normal force acting on the crane is 361 N.
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What is Moral subjectivism?
Answer:
What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.
How do you think the sock and underwear became charged?
How many days makes 20 years (show all workings).
Answer:
20*365=7300
Explanation:
1 Year=365day
20years = x days
Which medium will cause the light to bend the least when moving from water?
a. Glycerin b. Quartz c. Ruby
d. Acrylic
Answer:
B
Explanation:
Monucles work in different shapes
A proton is released from rest at the positive plate of a parallel-plate capacitor. It crosses the capacitor and reaches the negative plate with a speed of 45000 m/s.
What will be the final speed of an electron released from rest at the negative plate?
Express your answer to two significant figures and include the appropriate units
V=_________
Answer:
2.1x10^6m/s
Explanation:
One electron has a charge of –1.602e-19 C
mass of electron is 9.1e-31 kg
mass of proton is 1.6726e−27 kg
mass ratio is 1.6726e−27 / 9.1e-31 = 1838
The force is constant, F
distance is constant, d
a = F/m
a increases by a factor 1838, as m decreases by that factor
a = a₀1838
v₀² = 2a₀d
v² = 2a₀d1838
v²/v₀² = 2a₀d1838 / 2a₀d = 1838
v² = 1838v₀² = 1838(45000)²
v = 45000√1838 = 2.1e6 m/s
what is the 'Water Column"
Answer:a vertical expanse of water stretching between the surface and the floor of a body of water
Explanation:
What is the average power consumption in watts of an appliance that uses 5.00 KW.h of energy per day?
Find the unit vector of the vector F=(9.00i-8.00j)N
9\(\^{i}\)+8\(\^{j}\)/\(\sqrt{136}\)
F=(9.00i-8.00j)N
we are now to find the unit vector
according to formula
unit vector = \(\frac{vector of F}{Magnitude of F}\)
Now :
vector form of F = 9\(\^{i}\)+8\(\^{j}\)
magnitude of F =\(\sqrt{9^2+8^2}\)
magnitude of F=\(\sqrt{136}\)
now put that in formual
unit vector = 9\(\^{i}\)+8\(\^{j}\)/\(\sqrt{136}\)
When a normal vector's magnitude is one, or unit, it is said to be a unit normal vector.Normal vectors, often known as perpendicular to surfaces, are vectors that, at the provided coordinates, are normal to surfaces. The normal pointing inside and the normal pointing outside the surface are often identified when perpendiculars are obtained on closed surfaces.Normal vectors are often denoted by the letters "N" or "n," and occasionally with a cap to specifically denote the unit normal vector.To know more about unit vector visit : https://brainly.com/question/28028700
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The boiling point of nitrogen is -196°C. What is that on the absolute temperature scale?
Answer:
The boiling point of nitrogen on the absolute temperature scale is 77.15 K
Explanation:
Temperature in Kelvin(Absolute temperature) = Temperature in Celcius + 273.15.
You are grilling hamburgers for a neighborhood cookout. What type of energy transfer makes the grill marks on the hamburgers?
Group of answer choices
Convection
Conduction
Radiation
Answer: Radiation
Explanation:
Radiation refers to the transfer of heat from one source to another material. The transfer of heat energy from the sun to the earth is called radiation. The grilling of the hamburgers is an example of the radiation as in grilling no direct heat is involved instead the radiations or flames beneath the grilling barbeque burn or grill the hamburgers. Fumes or flames of a charcoal transfer radiations to the grilling hamburgers.
in 1-2 complete sentences define "opportunity cost " in your own words
Answer:
Here you go, hope this helps! :)
Explanation:
Opportunity cost is the value of the next best thing you give up whenever you make a decision. It is "the loss of potential gain from other alternatives when one alternative is chosen". ... For example, opportunity cost is how much leisure time we give up to work.
Two tiny objects with equal charges of 7.25 μC are placed at the two lower corners of a square with sides of 0.201 m, as shown.
Find the electric field at point B, midway between the upper left and right corners. If the direction of the electric field is upward, enter a positive value. If the direction of the electric field is downward, enter a negative value. answer in N/C
The electric field at point B, located at the midpoint between the upper left and right corners of the square, can be approximated as 3.244 x \(10^6\) N/C in the upward direction.
To find the electric field at point B, we can consider the contributions from the two charges placed at the lower corners of the square. Since the charges are the same and the distance to point B is the same for both charges, the magnitudes of the electric fields produced by each charge will be equal.
First, let's calculate the magnitude of the electric field produced by one of the charges at point B using Coulomb's Law:
Electric field due to a point charge (E) = (k * q) / \(r^2\)
Where:
- k is the electrostatic constant, approximately equal to 8.99 x 10^9 \(10^9\)N \(m^2/C^2\)
- q is the charge of the object, 7.25 μC (7.25 x \(10^-^6\) C)
- r is the distance from the charge to point B, which is half the length of the square's side, 0.201 m / 2 = 0.1005 m
Plugging in the values, we have:
E = (8.99 x \(10^9 N m^2/C^2\) * 7.25 x \(10^-^6\) C) / (0.1005 \(m)^2\)
E ≈ 1.622 x \(10^6\) N/C
Since the electric fields from the two charges at the lower corners have equal magnitudes and point in the same direction (upward), the total electric field at point B is twice the magnitude of the individual electric field:
Electric field at point B = 2 * E ≈ 2 * 1.622 x \(10^6\) N/C
Electric field at point B ≈ 3.244 x \(10^6\) N/C
Therefore, the electric field at point B, midway between the upper left and right corners of the square, is approximately 3.244 x \(10^6\)N/C upward.
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in an experiment to investigate the properties of a capacitor, students connect a parallel plate capacitor to a variable voltage source as shown. question without using the electron emitter, the variable voltage source is set at a fixed value, and the spacing between the plates is gradually increased without disconnecting the capacitor from the voltage source. which of the following is a correct claim about how this will affect the charge on the plates of the capacitor and provides evidence to support this claim?
As the distance between the parallel plates increases, the voltage between them increases leading to an increase in charge. Hence option C is correct.
What is capacitance ?Capacitance of an object is its ability to store electrical charge. The devices able to store massive charge for longer times are called capacitors. The unit of capacitance is faraday.
The relation between charge Q, potential difference v and the capacitance c of a parallel plate capacitance is:
Q = CV.
Here V = Ed.
where d is the distance between the plates of capacitor and E be the magnitude of electric field. Hence, as the voltage increases, capacitance decreases and charge increases. Therefore option c is correct.
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The vapor pressure of liquid ethanol, C2H5OH, is 100. mm Hg at 308 K.
A sample of C2H5OH is placed in a closed, evacuated 529 mL container at a temperature of 308 K. It is found that all of the C2H5OH is in the vapor phase and that the pressure is 67.0 mm Hg. If the volume of the container is reduced to 344 mL at constant temperature, which of the following statements are correct?
Choose all that apply.
a. The pressure in the container will be 103 mm Hg.
b. Some of the vapor initially present will condense.
c. Liquid ethanol will be present.
d. Only ethanol vapor will be present.
e. No condensation will occur.
B
The statements that apply are;
The pressure in the container will be 103 mm Hg. Some of the vapor initially present will condense.Liquid ethanol will be present.What is the new pressure?We know that the pressure can be taken as the force with which the molecules of the substance are able to hit the walls of the container in this case, we need to obtain the pressure of the ethanol vapor when the volume has been reduced.
Using
P1 = initial pressure
P2 = final pressure
V 1 = initial volume
V2 = final volume
By the use of the Boyle's law we have;
P1V1 = P2V2
P2 = P1V1 /V2
P2 = 67.0 * 529/344
P2 = 103 mmHg
Thus, as the volume is reduced there would be an increase in the pressure and some of the ethanol would condense and we would have liquid ethanol in the system.
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PLEASE HELP
At a circus, a human cannonball is shot from a cannon at 15m/s at an angle of 40° above horizontal. She
leaves the cannon 2m off the ground and lands in a net 1m off the ground. What height does she reach?
How much ground distance does she cover?
Answer:
Explanation:
\(a_{x}=0\) \(v_{xo}= v_{o}cos(delta)t\) \(a_{y}=-g\) \(v_{yo}=sin\)θ
X-direction | Y-direction
\(x=x_o+v_{xo}t\) ⇒ \(x=v_{xo}cos(delta)t\) |
If you stood atop a ladder on Earth that was as tall as Earth's radius (so you were twice as far from
Earth's center) your weight atop the ladder would be
a.half its normal value
b. one-eighth its normal value
C. one-quarter its normal value d.
d.none of the above
Your weight at the top of the ladder would be one-quarter of its normal value. The correct option is C.
What is the acceleration due to gravity?The gravitational pull of the Earth, denoted by g, is the net acceleration imparted to objects by the combined effect of gravitation and centrifugal force. It is a vector quantity whose direction corresponds to a plumb bob and whose strength or magnitude is determined by the norm.
The formula for gravity is,
g = GM / R²
g = 1 / R²
gt = 1 / (2R)²
gt / g = R² / 4R²
gt = 1 / 4g
Therefore, at the top of the ladder, your weight would be one-quarter of its normal value.
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An instrument that produces an electric current in the presence of
a radioactive substance is called a
a. particle accelerator.
b. Geiger counter.
c. cloud chamber.
d. bubble chamber.
Answer:
Option B, Geiger counter
Explanation:
According to the law of conservation of charge which statement can be true?A. A silk cloth gained charge. B. A metal rod lost charge.C. A peice of glass transferred electrons to felt. D. A balloon remains neutrally charged when rubbed.
Option D
Explanation:The law of conservation of charge states that the amount of charge in a system is constant
This means that as time changes, the amount of charge in a system does not change
By careful consideration of the options stated:
Each of options A to C either shows that charge is lost or gained
Only option D typifies the law of conservation of conservation of charges because charges are not lost or gained by the ballon so described.
A charge of 0.20uC is 30cm from a point charge of 3.0uC in vacuum. what work is required to bring the 0.2uC charge 18cm closer to the 3.0uC charge?
Answer:
The correct answer is "\(4.49\times 10^{10} \ joules\)".
Explanation:
According to the question,
The work will be:
⇒ \(Work=-\frac{kQq}{R}\)
\(=-\frac{1}{4 \pi \varepsilon \times (18-30)\times 3\times 0.2}\)
\(=-\frac{1}{4 \pi \varepsilon \times (-12)\times 3\times 0.2}\)
\(=\frac{0.3978}{\varepsilon }\)
\(=4.49\times 10^{10} \ joules\)
Thus the above is the correct answer.
We have that the workdone is mathematically given as
W=4.49*10e10 J
From the question we are told
A charge of 0.20uC is 30cm from a point charge of 3.0uC in vacuum. what work is required to bring the 0.2uC charge 18cm closer to the 3.0uC charge?WorkdoneGenerally the equation for the workdone is mathematically given as
W=-kQq/R
Therefore
0.3978/ε0 =-1/(4πε0*(18-30)*3*0.2
Hence
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A projectile is fired into the air at an angle of 50° above ground level and hits a target downrange. Neglecting air drag, it will also hit the target if fired at the same speed at an angle of
Answer:
18 m/s
Explanation:
Range of a projectile on level ground is:
R = v₀² sin(2θ) / g
14.3 m = v₀² sin(2×13°) / 9.8 m/s²
v₀ = 17.9 m/s
Rounded to two significant figures, the launch speed was 18 m/s.
If the bullet is launched at an angle of 50 degrees above ground level, the target will be struck. The angle remains the same. The launch angle obtained is 50 degrees.
Given:
The initial shot was fired at an angle of 50 degrees above ground.
The projectile's starting velocity (v) and magnitude of velocity will remain constant if it is shot at the same pace.
Let the angle of the projectile is x,
The horizontal component of velocity can be calculated as follows:
\(v(x) = v * cos(x)\)
We can write:
since the horizontal part of velocity remains constant:
\(v(x1) = v(x2)\)
\(cos(50) = cos(x)\)
\(50 = x\)
Therefore, if the projectile is launched at the same speed at a 50° angle above ground level, it will strike the target.
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The correct response is given when the angle is asked a question.
Accelerating car is a _______
•Law of inertia
•Law of universal gravitation
•Law of acceleration
•Law of conversation of energy
Acceleration is the rate of change of velocity as a function of time. For example a car traveling at 50 km/hr starts to accelerate, 10 seconds after, its speed changes to 100 km/hr then the acceleration of the car during the time can be calculated as below: initial speed = 50 km/hr.
Radio waves travel at the speed of light. What is the wavelength of a radio signal with a frequency of 9.45 x 10^7 Hz?
The wavelength of this radio signal is equal to 3.18 meters.
Given the following data:
Frequency = \(9.45 \times10^7\) Hz.Speed of light = \(3 \times 10^8\) m/s.What is wavelength?Wavelength can be defined as the distance between two (2) successive crests (troughs) of a wave.
How to calculate wavelength.Mathematically, the wavelength of a wave is given by this formula:
\(\lambda = \frac{V}{F}\)
Where:
F is the frequency of a wave.V is the speed of a sound wave.\(\lambda\) is the wavelength of a sound wave.Substituting the given parameters into the formula, we have;
\(\lambda = \frac{3 \times 10^8}{9.45 \times10^7}\)
Wavelength = 3.18 meters.
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The wavelength of the radio signal travel at speed of light is 3.17m.
Given the data in the question;
Frequency of the radio wave; \(f = 9.45 * 10^{7}Hz = 9.45 * 10^{7} s^{-1}\)Wavelength of a radio signal; \(\lambda = \ ?\)WavelengthWavelength the spatial period of a periodic wave. That is to say, when the shapes of waves are Wavelength , the distance over which they are repeated is called wavelength. Wavelength is expressed as;
\(\lambda = \frac{v}{f}\)
Where \(\lambda\) is wavelength, f is the frequency of the wave and c is the velocity or speed of light ( \(c = 3*10^8m/s\) )
We substitute our values into the expression above.
\(\lambda = \frac{c}{ f}\\ \\\lambda = \frac{3*10^8m/s}{9.45*10^7s^{-1}} \\\\\lambda = \frac{3*10^8ms/s}{9.45*10^7}\\\\\lambda = 3.17m\)
Therefore, the wavelength of the radio signal travel at speed of light is 3.17m.
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Observe the vertical and horizontal motion of lunar lander in the absence of thrust explain the reason for motion
Answer:
In the absence of thrust, the lunar lander moves downward toward the surface of the moon. At this point, the only force acting on the lunar lander is gravity, which is directed toward the center of the moon. Because the net force is in the downward direction, the lunar lander moves downward.
Explanation: plato
Answer: In the absence of thrust, the lunar lander moves downward toward the surface of the moon. At this point, the only force acting on the lunar lander is gravity, which is directed toward the center of the moon. Because the net force is in the downward direction, the lunar lander moves downward.
Explanation: edmentum sample answer
1. The kinetic energy of a car is 8 106 J as it travels along a horizontal road. How much work is required to stop the car in 10 s? (A) zero joules (B) 8 105 J (C) 8 107 J (D)8 104 J (E) 8 106 J
The power to stop the car with kinetic energy of a car is \(8*10^{6} J\) as it travels along a horizontal road is \(8*10^{5} watt\), option B
What is Kinetic energy ?Kinetic energy can be seen as one that is been recorded when an object is able to move from a place , in a broad term we can say this is the energy that can be attributed to that of someone leaving a place and go to another place hence we can see it as the one in the motion.
The definition of energy as the "power to accomplish work" refers to the capacity to apply a force that moves an object. Even if the word is vague, it is clear what energy actually means: it is the force that causes objects to move. The two types can be attributed to the one we know which are kinetic and potential energy.
\(Power \frac{Energy}{time}\)
\(Energy = 8*10^{6} J\)
\(time = 10 s\)
\(Power = \frac{8*10^{6} J}{10}\)
\(power = 8*10^{5} watt\)
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proper question;
The kinetic energy of a car is 8 × 106 J as it travels along a horizontal road. How much power is required to stop the car in 10 s? (A) zero joules (B) 8 105 J (C) 8 107 J (D)8 104 J (E) 8 106 J