A 8 kg block moving to the right at 4 m/s collides with a 5 kg block moving to the left at -9 m/s, and the two stick together. Find the final velocity.

Pressure above the left beaker the pressure outcome of the current experimental circumstances.

Either the action of pressing or the state of pressing. A strain or force exerted against resistance in any direction. Force per unit of area is a measure of force exerted uniformly over a surface.

Pressure is the ratio of the force applied perpendicularly to an object's surface to its area. Its abbreviation is "p" or "P."

The force applied by one region of a gas, liquid, or solid to another, expressed as a function of area. A substance is said to have negative pressure if another substance exerts greater force per unit area on it than it does on it. Pressure is commonly measured in Pascal units, atmospheres, or pounds per square inch. Its value is just the opposite of the pressure the other substance is exerting.

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Answer:

your pretty no matter what others say

Explanation:

Answer:

two bros chillin in a hot tub five feet apart cuz there not gay

Explanation:

do you remember this vine

Answer:

Density= 2.78 g/cm³

Relative density=2.8

Explanation:

To calculate the density of the cube we have to use the formula ρ=mass/volume

ρ stands for density.

So now we don't have the volume of the cube and to find the volume of the cube we have to use the formula a³

3³= 9 cm³

Now plug in the values. ρ= 25 g/9 cm³

ρ= 2.78 g/cm³

To find the relative density, we have to use the formula ρsample/ρH20

The sample means the density of the substance earlier. We do not know the density of water but it is constant at 997 kg/m³.

Now we have to make the units same so you change the unit of the density of cube to kg/m³

So, 25/1000= 0.025 kg

9/100×100×100 (because cm³ which means that there should be 3 meters to change the unit and to conver cm to meter we need to divide by 100 so 9cm/100, 9cm²/100×100, 9cm³/100×100×100)

=0.000009 m³

The new density= 0.025 kg/ 0.000009 m³

= 2777.78 kg/m³

Now plug the values into the formula:

relative density= 2.777.78 kg/m³ / 997 kg/m³

=2.8

There is no unit since kg/m³ and kg/m³ cancels

The binding energy per nucleon for a 238U atom with a measured mass of 238.050785 u is approximately 7.6 MeV.

To calculate the binding energy per nucleon, first determine the mass defect by subtracting the measured mass (238.050785 u) from the total mass of its individual nucleons (protons and neutrons).

Next, convert the mass defect to energy using Einstein's mass-energy equivalence formula, E=mc², where E is the energy, m is the mass defect, and c is the speed of light.

Finally, divide the binding energy by the total number of nucleons (A = 238) to find the binding energy per nucleon.

Summary: By calculating the mass defect, converting it to energy, and dividing by the total number of nucleons, we find that the binding energy per nucleon for a 238U atom with a measured mass of 238.050785 u is approximately 7.6 MeV.

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Explanation:

Khi một hạt thực hiện SHM Đang chuyển động từ vị trí cực biên về vị trí trung bình, thì vận tốc và gia tốc cùng hướng, tức là hướng về vị trí trung bình

To estimate the properties of humid air at 30°C and 100% relative humidity, we can use a psychrometric chart. However, as a text-based AI model, I am unable to provide visual graphics or perform calculations based on a chart. Nonetheless, I can provide you with general information about the properties you mentioned.

Specific enthalpy: Specific enthalpy is the amount of heat energy per unit mass of air. It depends on the temperature, pressure, and moisture content of the air.

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The power required to move the automobile to the top of the hill is 130,666.67 watts or 175.41 horsepower.

The power required to move an object can be calculated using the formula: power = work / time.

First, let's calculate the work done in lifting the automobile to the top of the hill. The work done against gravity is given by the formula: work = force × distance.

The force required to lift the automobile is equal to its weight. The weight of an object is given by the formula: weight = mass × acceleration due to gravity.

Substituting the given values, we have: weight = 2,000 kg × 9.8 m/s^2 (acceleration due to gravity) = 19,600 N.

The distance the automobile is lifted is 100 meters.

Therefore, the work done against gravity is: work = 19,600 N × 100 m = 1,960,000 J (joules).

The time taken to reach the top of the hill is given as 15.0 seconds.

Now, we can calculate the power using the formula: power = work / time.

power = 1,960,000 J / 15.0 s = 130,666.67 W (watts).

To convert watts to horsepower, divide the power in watts by 746 (1 horsepower = 746 watts).

power in horsepower = 130,666.67 W / 746 = 175.41 hp (horsepower).

Rounding to two decimal places, the power required to move the automobile to the top of the hill is approximately 130,666.67 watts or 175.41 horsepower.

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The  to problem of calculating the power required to move a 2,000-kilogram automobile to the top of a 100-meter hill in 15.0 seconds is given

Given, Mass of the automobile, m = 2000 knight of the hill, h = 100 time, t = 15.0 the gravitational potential energy of the automobile when at the bottom of the hill is equal to the work done in lifting it up the hill

.W = mgh= (2000 kg) (9.81 m/s²)

(100 m)= 1,962,000 J

Power is defined as the rate at which work is done, or the work per unit time. Therefore,

Power = Work / Time= 1,962,000 J / 15.0 s

= 130,800 WIn horsepower, Power = (130,800 W) / (746 W/hp)

= 175.3 hp

Therefore, the required power to move a 2,000-kilogram automobile to the top of a 100-meter hill in 15.0 seconds is 130,800 W or 175.3 hp.

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The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A

The work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).

The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:

T = Y * (ΔL / L)

where Y is the Young's modulus of the material of the wire.

Now, let's calculate the work done to stretch the wire:

dW = T * dL

Integrating this expression from L to L + ΔL:

W = ∫ T * dL = ∫ Y * (ΔL / L) * dL

W = Y * ΔL * ∫ (dL / L)

W = Y * ΔL * ln(L) + C

Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.

Finally, the expression for the energy stored in the wire (E) is:

E = W = Y * ΔL * ln(L)

or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:

E = Y * e * ln(L) * A

Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:

E = Y * e * ln(L) * A

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-4m/s^2 the velocity of a ball that rolled to the right 20 cm in 3 seconds

Vi = 20m/s

Vf = 0

t = (t2 - t1) = 8s -3s = 5s

Vf - Vi = a*5s

a = (0- 20m/s)/5s = -4m/s^2

Velocity is a measure of speed in motion or activity. A more concise word for celerity is speed. Physics uses the word "velocity" specifically to describe how quickly and in what direction an object's location changes. It is a vector quantity that expresses the speed and direction of a body's motion.

Velocity is the term for the rate at which a displacement changes. Acceleration is the measure of a change in velocity. Velocity is a vector quantity because it comprises both magnitude and direction. Acceleration is a vector quantity because it is the speed at which velocity varies.

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A person would be 30 feet (y) 8 seconds (x) after the experiment begins.

The scatterplot shows a linear relationship between the distance (in feet) from the motion sensor and the time (in seconds) since the start of the experiment.

Using the two labeled points (8 seconds, 21 feet) and (15 seconds, 57 feet), we can use the line equation y = mx + b to create a linear model. The slope (m) equals (57 feet - 21 feet)/(15 seconds - 8 seconds) = 36 feet/7 seconds, and the y-intercept (b) equals 21 feet.

Using the linear model, we can estimate that a person would be 30 feet (y) 8 seconds (x) after the experiment begins.

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The best measurements of the mass of the black hole at the center of the Milky Way galaxy come from observations of the orbits of stars and gas clouds near the galactic center.

In particular, astronomers have been able to observe the motion of stars and gas clouds that are very close to the center of the galaxy, within a few light-days of the suspected black hole.

By measuring the speed and direction of these objects, and analyzing their orbital trajectories, scientists can calculate the gravitational force required to keep them in orbit. The size of this force depends on the mass of the central object, which is likely to be a black hole.

Through this method, astronomers have estimated that the black hole at the center of the Milky Way, known as Sagittarius A*, has a mass of about 4 million times that of the sun.

This estimate has been refined and confirmed over several years of observations, and is currently the most accurate measurement of the mass of a supermassive black hole.

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The acceleration of the object is 5 m/s². The result is obtained by using the Newton's second law.

The Newton's second law states that "The acceleration is directly proportional to the net force acting on an object and inversely proportional to the object's mass." It can be expressed as

a = ∑F/m

Where

An object with a mass of 12 kg is acted upon by a force of 60 N.

Find the acceleration of the object!

Using the Newton's second law formula, we get acceleration.

a = ∑F/m

a = 60/12

a = 5 m/s²

Hence, the acceleration of the object is 5 m/s².

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The work done to stretch the spring from 16m to 19m will be 18 Joules and the natural length with which a force of about 72 N is used to keep the spring stretched will be 7.5m.

Spring force can be defined as the force which acts in the opposite direction to the displacement of the object. In order to stretch or compress the spring some amount of work has to be done. Which is given as,

where k = spring constant of the spring

         x = compression of spring

         W= Work required or spring work

Initial length is given by 9m

final length is given by  11m

When spring is stretched change in the length occurs denoted by x

x = final length - initial length = (11 - 9) = 2m

W = 1/2Kx²

W = 1/2 K (2)²

8×2 = 4K

16/4 = K

K = 4 N/m

(a) work is needed to stretch the spring from 16m to 19m

stretching length from 16 to 19m will be 3m

stretching length from cm to 30 is 40 cm is 10 cm which is 0.1m

x = final stretch of the spring = 16 - 19 = 3m

Work needed to stretch the spring from 16m to 19m is given

W = (0.5)K(3²)

W = (0.5)(4)(3²)

W = 2.0 × 9

W = 18 Joules

x is stretch of the spring beyond natural length

F = force = 72 N

Spring force is given as

F = k x

30 = (4) x

x = 7.5m

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a) The flow rate will be Q = 84 cm³ per second.

b) The flow speed in the capillaries will be 0.028 cm /s.

The flow rate is defined as the volume of the fluid passing across the cross-section of the pipe in a unit of time.

To calculate the flow rate of blood in the aorta, we can use the equation:

Flow rate = Area x Velocity x Density

Where the area is the cross-sectional area of the aorta, the velocity is the flow speed of the blood in the aorta, and the density is the density of blood (p = 1.0 g/cm³).

Substituting the values we know, we get:

Flow rate = 2.0 cm²x 42 cm/s x 1.0 g/cm³

Flow rate = 84 g/s

Therefore, the flow rate of blood in the aorta is 84 grams per second.

b. According to the principle of continuity, the flow rate of blood must remain constant as it moves from the aorta to the capillaries. Therefore, we can use the equation:

Flow rate = Area x Velocity x Density

To calculate the flow speed in the capillaries, given the combined cross-sectional area of the capillaries.

We know that the flow rate in the capillaries must be the same as the flow rate in the aorta, which we calculated in part a:

Flow rate = 84 g/s

The combined cross-sectional area of the capillaries is given as 3.0 x 10³ cm². Substituting these values in the equation, we get:

84 g/s = 3.0 x 10³cm² x Velocity x 1.0 g/cm³

Solving for the velocity, we get:

Velocity = 84 g/s / (3.0 x 10³ cm² x 1.0 g/cm³)

Velocity = 0.028 cm/s

Therefore, the flow speed in the capillaries is 0.028 cm/s.

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The Earth's angular velocity for its daily rotation on its axis is in the counterclockwise direction (eastward).

The Earth's angular velocity for its daily rotation on its axis is in the eastward direction. From above, this movement would look like the Earth is moving counterclockwise. This means that the Earth rotates from west to east, causing the sun to appear to rise in the east and set in the west. This is also why time zones are arranged with earlier times to the east and later times to the west. The Earth's rotation on its axis is what causes the cycle of day and night.

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Answer:

Work is said to be done when a force applied to an object moves that object. We can calculate work by multiplying the force by the movement of the object.

Answer:

Work is done by a force on an object if (i) a force acts on the object and (ii) the object is displaced from its original position

It takes 79.4 s for a 1.57-a current to plate 0.1261 g of a metallic element from a solution containing m2 ions.  we need to determine the molar mass (M) and the number of moles of electrons transferred (n) for the metallic element (m). Since we don't have information about the specific element

To determine the metallic element (m) that is being plated from the solution, we need to use Faraday's law of electrolysis. According to Faraday's law, the amount of substance (m) that is deposited or plated on an electrode is directly proportional to the electric charge (Q) passed through the electrolyte. The equation is given by:

m = (Q * M) / (n * F)

where:

m is the mass of the substance plated,

Q is the electric charge,

M is the molar mass of the substance,

n is the number of moles of electrons transferred in the reaction,

F is Faraday's constant.

In this case, the electric charge Q is given by the product of the current (I) and time (t): Q = I * t.

From the information provided, the current is 1.57 A and the time is 79.4 s. Plugging these values into the equation, we have:

Q = (1.57 A) * (79.4 s) = 124.558 C

we cannot determine these values accurately. Therefore, we cannot determine the chemical symbol for the element without additional information about its molar mass and the number of moles of electrons transferred in the reaction.

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The linear velocity is v=0.810 m ×15.0 rad/s = 12.15 m/s.

Velocity is a vector quantity that measured the rate and direction of the change in an object position it is typically excelled in unit of meter per second velocity is equal to the distance traveled divided by the time it take to travel the distance velocity is also related to acceleration which is the rate of change of velocity.

(a) The linear velocity of the disc at the moment of release can be found by using the equation v=rω, where r is the radius of the circular arc, and ω is the angular velocity. Thus, the linear velocity is v=0.810 m ×15.0 rad/s = 12.15 m/s.

(b) The tangential acceleration of the disc at the moment of release can be found by using the equation at = rα, where r is the radius of the circular arc, and α is the angular acceleration. Since the angular acceleration is equal to the change in angular velocity divided by the time, the tangential acceleration is at = 0.810 m ×(15.0 rad/s)/(0.270 s) = \(55.9 m/s^{2}\)

(c) The centripetal acceleration of the disc at the moment of release can be found by using the equation ac = \(v^{2}\)/r, where v is the linear velocity, and r is the radius of the circular arc. Thus, the centripetal acceleration is ac = \((12.15 m/s^{2})\)/(0.810 m) = \(151.0 m/s^{2}\)

(d) The total acceleration of the disc at the moment of release can be found by adding the tangential and centripetal accelerations, thus a tot = at + ac = 55.9 \(m/s^{2}\) + 151.0 \(m/s^{2}\) = 206.9 \(m/s^{2}\)

(e) The angle of the total acceleration at the moment of release can be found by using the equation θ = \(tan^{-1}\)(at/ac), where at is the tangential acceleration, and ac is the centripetal acceleration. Thus, the angle of the total acceleration is θ = \(tan^{-1}\)(55.9 m/\(s^{2}\)/151.0 m/\(s^{2}\)) = 22.4°.

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The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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Answer:

I think C radiation only

Answer:

camels have humps to store fat which is then converted to energy when food is scarce ( the humps are not used for storing water )

Answer: camels have humps to store fat which is then converted to energy when food is scarce ( the humps are not used for storing water )

the electric field inside the dome of a highly-charged Van De Graaff Generator is zero.

A Van de Graaff generator is an electrostatic generator which uses a conveyor belt to accumulate electric charge in a hollow metal ball on top of an insulated pole, creating a high electric potential. Producing high voltage in direct current (DC) electricity at a low level. This generator was invented by the American physicist Robert J. Van de Graaff in 1929.

The Van de Graaff generator was originally used as a particle accelerator for physics research, because with its high potential it can be used to accelerate subatomic particles to very high speeds in an evacuation tube. This generator is also a type of powerful accelerator until the discovery of the cyclotron which existed in the early 1930s. The Van de Graaff generator is still used as an accelerator to produce energetic particles and X-rays for nuclear research and nuclear medicine.

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The kinetic energy of the 1.0 g particle with a speed of 0.500 c is approximately 11,235,331 joules.

KE = (1/2) * m * v²

v = (0.500 c) * (speed of light) = (0.500) * (299,792,458 m/s) ≈ 149,896,229 m/s

Now we can substitute the values into the kinetic energy equation:

KE = (1/2) * (0.001 kg) * (149,896,229 m/s)²

Calculating this expression, we get:

KE ≈ 11,235,331 joules

Kinetic energy is a fundamental concept in physics that describes the energy possessed by an object due to its motion. It is defined as the energy an object has by virtue of its mass and velocity. When an object is in motion, it possesses kinetic energy, which depends on two factors: its mass and the square of its velocity.

The equation for kinetic energy is KE = 1/2 mv², where KE represents kinetic energy, m represents the mass of the object, and v represents its velocity. This equation highlights that kinetic energy is directly proportional to both the mass and the square of the velocity of the object. The significance of kinetic energy lies in its ability to do work. When an object possesses kinetic energy, it can transfer that energy to other objects upon collision or exert a force to perform work.

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Answer:

The strength of gravity on Pluto is 0.6 m/s²

Explanation:

The given mass of the shoe = 0.5 kg

The weight of the shoe (on Pluto), W = 0.3 N

Therefore, given that weight, W = Mass × The acceleration due to gravity, We have;

The strength of gravity = The force gravity applies to each unit of mass = The acceleration due to gravity (in m/s²)

The weight of the shoe, W = The mass of the shoe × The strength of gravity on Pluto

Substituting the known values, gives;

0.3 = 0.5 × The strength of gravity on Pluto

∴ The strength of gravity on Pluto = 0.6 m/s².

To determine the diameter of the cylindrical rod that can withstand a load of 650 N, we need to consider the yield strength of the material and the applied load. the diameter of the rod is approximately 11.62 mm.

By using the formula for stress (force divided by area) and rearranging it to solve for the diameter, we can find the required diameter of the rod.

The stress experienced by the rod can be calculated using the formula:

Stress = Force / Area

Given that the yield strength of the steel is 310 MPa, we can set up the equation:

310 MPa = 650 N / (π * (diameter/2)^2)

We can rearrange the equation to solve for the diameter:

diameter = √(650 N / (310 MPa * π)) * 2

Substituting the given values, we find:

diameter ≈ √(650 / (310 * 10^6 * π)) * 2 ≈ 11.62 mm

Therefore, the required diameter of the rod to withstand the load is approximately 11.62 mm.

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The development of our current model of the atom evolved over centuries, starting with the ancient Greeks' conceptualization of the atom as an indivisible particle.

Around the fifth century BCE, the Greeks became the first people to put forth the idea of the atom. Democritus and other philosophers proposed the idea that matter is made up of tiny, indivisible pieces called atoms, but there was no experimental support for this theory at the time. Although it survived for centuries, this idea did not significantly change until the 19th century.

Scientific developments in the 19th century led to a deeper comprehension of atoms. With notable contributions from Michael Faraday's work on electromagnetic induction and Benjamin Franklin's electricity tests, scientists discovered the presence of electrical charges.

Groundbreaking investigations that transformed our understanding of the atom took place in the early 20th century. The electron, a negatively charged particle inside the atom, was discovered in 1897 as a result of J.J. Thomson's cathode ray tube studies. Atoms are shown to have a small, dense, positively charged nucleus that is around by negatively charged electrons in a large empty region by Ernest Rutherford's gold foil experiment in 1911.

The Rutherford model, sometimes known as the planetary model, was created in response to the discovery of the nucleus. This model, however, encountered problems since it was unable to explain the stability of atoms and the behavior of electrons. Researchers like Werner Heisenberg and Erwin Schrödinger made significant contributions to the development of quantum mechanics in the 1920s and 1930s.

The wave-particle duality and quantum mechanical concepts are both included in the current model of the atom, also referred to as the quantum mechanical model. In orbitals, which are areas of probability where electrons are most likely to be located, it says that electrons exist. Around the nucleus, these orbitals are arranged into energy levels or shells. The behavior of subatomic particles like protons and neutrons, which make up the nucleus, is also taken into consideration by the model.

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The focal point of parallel rays from the sun is actually outside the bowl.

When parallel rays pass through a convex lens like a fishbowl, they converge at a point called the focal point.

In this case, the friend advised the owner to keep the bowl out of direct sunlight to avoid blinding the fish because the focused rays of sunlight could potentially harm the fish's eyes.

However, it's important to note that the focal point is not within the bowl itself. So, while the fish might be at risk if exposed to direct sunlight, the actual focal point where the rays converge is outside the bowl.

In conclusion, the focal point of parallel rays from the sun is outside the fishbowl, not within it. This means that the fish's eyes are not at risk from the focused rays of sunlight inside the bowl.

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Answer: 1.76 m/s²

Explanation:

F = mass x acceleration

0.44 N = (0.25)(a)

0.44/0.25 = 1.76

a = 1.76