A 750-Hz plane sound wave in seawater (13 degree C) is normally incident on a stone seawall. The sound field is found to have a maximum at the wall; the SPL there is 190 dB re 1 muPa. The SPL 0.5 m from the wall is 177 dB. (a) Use the information given about the sound field to find the impedance of the wall. (b) Find the SPL of the incident wave.

Answers

Answer 1

(a) The impedance of the seawall is approximately 2.13 MRayl.

(b) The SPL of the incident wave is approximately 147 dB re 1 μPa.

How to measure sound pressure levels?

(a) The impedance of the seawall can be found using the measured sound pressure levels at the wall and at a distance from the wall, as follows:

First, we can use the sound pressure level (SPL) at 0.5 m from the wall to calculate the sound pressure amplitude (p0) of the incident wave:

SPL0.5m = 177 dB

p0 = 20 μPa (for a reference pressure of 1 μPa)

Next, we can use the maximum SPL at the wall to find the sound pressure amplitude at the wall (p_wall):

SPLwall = 190 dB

p_wall = 200 μPa

The impedance of the seawall (Z_wall) can then be calculated using the formula:

Z_wall = p_wall / v + vρ

where v is the speed of sound in seawater at 13°C (approximately 1532 m/s), and ρ is the density of seawater at 13°C (approximately 1025 kg/m³):

Z_wall = (200 μPa) / (1532 m/s) + (1532 m/s)(1025 kg/m³) = 2.13 MRayl (megarayls)

Therefore, the impedance of the seawall is approximately 2.13 MRayl.

(b) To find the SPL of the incident wave, we can use the formula for sound intensity (I):

I = p^2 / (2ρv)

where p is the sound pressure amplitude, ρ is the density of seawater at 13°C, and v is the speed of sound in seawater at 13°C. Solving for p:

p = sqrt(2ρvI)

We can find the sound intensity (I) using the measured SPL at 0.5 m from the wall, since the incident wave should have the same intensity everywhere in the absence of any reflections or absorption:

SPL0.5m = 177 dB

I = 10^((SPL0.5m - 120) / 10) = 2.51 x 10^-4 W/m²

Using the formula for p above:

p = sqrt(2(1025 kg/m³)(1532 m/s)(2.51 x 10^-4 W/m²)) = 0.00785 Pa

Finally, we can convert the sound pressure amplitude to an SPL using the formula:

SPL = 20 log10(p / p_ref)

where p_ref is the reference sound pressure (1 μPa):

SPL = 20 log10(0.00785 Pa / 1 μPa) = 147 dB re 1 μPa

Therefore, the SPL of the incident wave is approximately 147 dB re 1 μPa.

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Related Questions

What is dual convex lenses rules?

Answers

Dual convex lenses follow a set of rules that govern their behavior when light passes through them. These rules include:

1. The incoming light rays are refracted (bent) at the first lens surface, causing them to converge towards the optical axis.

2. The converging light rays then pass through the second lens surface and are refracted again, causing them to diverge away from the optical axis.

3. The point where the refracted light rays converge or diverge is known as the focal point.

4. The distance between the lens and the focal point is known as the focal length.

5. The magnification of the image formed by the lens is determined by the ratio of the distance between the object and the lens (object distance) to the distance between the image and the lens (image distance).

Overall, dual convex lenses are powerful tools for bending and focusing light, and they play a crucial role in many fields, from medicine to astronomy.

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A ball of mass m is hung from the end of a vertical, unstretched spring of negligible mass and force constant k, then released from rest. After it has fallen a vertical distance l it is momentarily at rest again. What is l in terms of m, g, and k?.

Answers

Answer:

PE = m g I      change in potential energy of object

PE = 1/2 k I^2      change in potential energy of spring

m g I  = 1/2 k I^2

I = 2 m g / k

Air flows along a 1500 ft rectangular duct measuring 12 x 18 in at a pressure and temperature of 15.2 psia and 68oF at a speed of 9.75 ft/s. Calculate the head loss and pressure drop if the line is la

Answers

The head loss in the duct is 27.39 ft and the pressure drop is 56.9 psi.

In order to calculate the head loss and pressure drop in the rectangular duct measuring 12 x 18 in, and is 1500ft long, given that the air flows along at a pressure and temperature of 15.2 psi and 68oF at a speed of 9.75 ft/s, the following procedure can be followed:Calculate the cross-sectional area of the duct: A = width x height. A = 12 x 18A = 216 in²= 0.125 ft². Find the flow area: Flow area = speed x areaFlow area = 9.75 ft/s x 0.125 ft²= 1.21875 ft³/s. Determine the hydraulic diameter:D = (4A)/pD = (4 x 0.125 ft²)/pD = 0.450 ft. Find the Reynolds number: Re = (velocity x D)/viscosity. The kinematic viscosity of air at 68oF is 1.662 x 10^-5 ft²/sRe = (9.75 ft/s x 0.450 ft)/1.662 x 10^-5 ft²/sRe = 2.638 x 10^5Determine the friction factor: The Moody chart can be used to determine the friction factor using the calculated Reynolds number and the relative roughness of the duct. Assuming the duct to be smooth, the relative roughness is negligible and the friction factor is approximately 0.019.Estimate the head loss: hL = (f x (L/D) x (velocity²/2g))where L is the length of the duct, and g is the acceleration due to gravity. hL = (0.019 x (1500 ft/0.450 ft) x (9.75 ft/s)²/(2 x 32.2 ft/s²))hL = 27.39 ftCalculate the pressure drop using the head loss:∆P = density x g x hL, where density of air at 15.2 psi and 68oF = 0.0735 lb/ft³∆P = 0.0735 lb/ft³ x 32.2 ft/s² x 27.39 ft∆P = 56.9 psiTherefore, the head loss in the duct is 27.39 ft and the pressure drop is 56.9 psi.

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an artificial satellite revolves around the earth in circular orbit which quantity remains constant

A. angular momentum
B. linear velocity
C. angular displacement
D. non of the above​

Answers

Answer:

Angular Momentum = M * V * R

Angular momentum is constant if there is no force applied along the direction of motion, A is correct here

Earth travels fastest in January and slowest in July. What is the most likely explanation for this?
A. Earth is nearest the Sun in July and farthest away in January.
B. Earth is nearest the Sun in January and farthest away in July.
C. Earth is nearest the Sun in April and farthest away in October.
D. Earth is nearest the Sun in October and farthest away in April.

Answers

Answer:

Earth is nearest the Sun in July and farthest away in July.

Explanation:

Answer:

Correct Answer: B.

Explanation:

Earth is nearest the Sun in January and farthest away in July. Explanation: According to Kepler's Second Law, a planet travels fastest when it is nearest its sun. This means that Earth is actually closest to the Sun in January, when it is winter in the northern hemisphere!

What is overtraining?
A.
overloading the muscles too often
B.
progressing through exercises too quickly
C.
muscles that aren't adapting quickly enough
D.
when muscles start atrophying

What is overtraining?
A.
overloading the muscles too often
B.
progressing through exercises too quickly
C.
muscles that aren't adapting quickly enough
D.
when muscles start atrophying

Answers

Answer:

A. overloading the muscles too often

Overtraining is overloading your muscles.

What is overtraining?

Overtraining refers to a process when a person continue to exercise despite that he has reach the limit of his ability and ignores the signs of and continues to train. Many believe they need to stress their muscles to be morefit and improve their performance.

Therefore, Overtraining is overloading your muscles.

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A magnifying glass with focal length 15 cm is placed 10 cm above a stamp. The image of the stamp is located a. 15 cm from the magnifying glass. b. 30 cm above the stamp. c. 30 cm above the magnifying glass. d. 30 cm below the stamp. e. 30 cm below the magnifying glass.

Answers

The image of the stamp when a magnifying glass with focal length 15 cm is placed 10 cm above a stamp is located 30 cm above the magnifying glass. The correct answer is Option C.

Let the object distance, u be -10cm (since the stamp is placed 10 cm above the magnifying glass).

Let the focal length of the lens, f be 15cm.

So, the magnification, m is given as:

m = v/u (where v is the image distance)

Using the lens formula, we can say that:

1/f = 1/v - 1/u (where v is the image distance and u is the object distance)

Plugging in the given values into the formula we have:

1/15 = 1/v + 1/10

Multiplying both sides of the equation by 30v, we have:

2v = 3(30 - v)

Solving for v, we have:

v = 30/2 = 15 cm

Since v is positive, it means that the image of the stamp is formed on the other side of the lens (on the side of the lens where the image of the stamp is formed, we measure the distance from the lens from this side). Hence, the image is located 15cm from the lens. Since the stamp is located 10 cm above the magnifying glass, the image of the stamp is located 15 + 10 = 25cm above the object or the magnifying glass. Thus, the correct option is c. 30 cm above the magnifying glass.

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A current I starts at z = -~ and flows up the z-axis as a linear filament until its hits an origin-centered sphere of radius R. The current spreads out uniformly over the surface of the sphere and flows up lines of longitude from the south pole to the north pole. The recombined current flows thereafter as a linear filament up the z-axis to z = +0. (a) Find the current density on the sphere. (b) Use explicitly stated symmetry arguments and Ampère's law in integral form to find the magnetic field at every point in space. (c) Check that your solution satisfies the magnetic field matching conditions at the surface of the sphere.

Answers

The current density on the sphere is:

              J = I / (4πR²),

The magnetic field inside the sphere is

             B(r) = μ0 I / (2πr),

The magnetic field Outside the sphere is

              B(r) = μ0 I r² / (2 R³),

The magnetic field is continuous across the surface of the sphere.How to find magnetic field on spherical surface using Ampère's law?

(a) The current density on the sphere can be found by dividing the total current by the surface area of the sphere.

The total current is equal to the current flowing through the linear filament, which is given by I. The surface area of the sphere is given by 4πR². Therefore, the current density on the sphere is:

               J = I / (4πR²)

(b) Due to the symmetry of the problem, the magnetic field will have no φ-component, and will only depend on the radial distance r and the polar angle θ.

By Ampère's law,

     The magnetic field at a point P inside the sphere of radius R can be found by integrating the current density J over a circular path C around the z-axis passing through P:

             ∮C B · dl = μ0 Ienc

where,

B is the magnetic field, dl is the infinitesimal element of path length along C, μ0 is the permeability of free space, and Ienc is the current passing through any surface bounded by C.

Since the current is distributed uniformly over the surface of the sphere, we can take a surface S with the same circular path C as its boundary.

Then, Ienc is equal to the total current passing through the sphere, which is equal to I.

By symmetry,

The magnetic field will be perpendicular to the circular path C at every point, and its magnitude will only depend on the distance r from the z-axis. Therefore, we can write

                         B = B(r) ẑ,

where,

ẑ is the unit vector in the z-direction. The integral can be evaluated as:

                       B(r) ∫C dl = B(r) 2πr = μ0 I

Solving for B(r), we obtain:

               B(r) = μ0 I / (2πr)

This is the magnetic field at every point in space inside the sphere.

(c) At the surface of the sphere, the magnetic field must be continuous across the boundary.

Therefore, we need to evaluate the magnetic field both inside and outside the sphere and make sure they match at r = R.

For r < R, we have:

                  B(r) = μ0 I / (2πr)

For r > R, the magnetic field is due to the current flowing on the surface of the sphere.

By Ampère's law,

we can take a circular path C of radius r centered on the z-axis, passing through the point P outside the sphere, and evaluate the magnetic field due to the current passing through the surface bounded by C. Since the current is flowing up lines of longitude, the current passing through the surface bounded by C is equal to the current passing through a circular disk of radius r on the surface of the sphere. The current density on the disk is:

               J = I / (4πR²),

The current passing through the disk is:

             Ienc = J π r²

Therefore, we have:

               B(r) ∫C dl = B(r) 2πr = μ0 Ienc

Solving for B(r), we obtain:

           B(r) = μ0 I r² / (2 R³)

At r = R, the magnetic field is:

          B(R) = μ0 I / (2πR) = μ0 I R / (2πR²) = μ0 J R

which is the same as the magnetic field due to the current density on the surface of the sphere.

Therefore, the magnetic field is continuous across the surface of the sphere, and our solution satisfies the magnetic field matching conditions.

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suppose aliens from a planet in another star system come to visit our solar system. what patterns of motion will the aliens notice about most of the planets in the solar system? (select all that apply.)

Answers

The aliens will notice the rotational motion of planets on their axis and revolution of the planets around the sun (star).

The sun and the planets are roughly in the same plane .

The first motion aliens will notice will be the rotation of the planets on their vertical axis. Each planet have different rotational speed , which results in the formation of day and night on each planet

The second motion they will notice will be the revolution of the planets around the sun(star) and the revolution of the moons of the planets around the planets. The path of revolution of each planet is fixed and is elliptical in shape also known as an orbit . During one single revolution each planet comes near the sun twice. Also the size of the elliptical path of each planet is not the same .

One more special motional observation that they will see , will be the helical motion of the planets as the entire solar system moves at an angle of 60 degree between the galactic plane and the planetary orbital plane

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how much energy does this wave carry through the window during a 30.0-s commercial?

Answers

To calculate the amount of energy carried by a wave through a window during a 30.0-s commercial, we need to know the power of the wave and the time for which it is passing through the window.

The power of a wave is given by the formula P = E/t, where P is power, E is energy, and t is time. Therefore, to calculate the energy carried by the wave, we can rearrange this equation to E = P x t. However, we need to know the power of the wave first. This information is not provided in the question, so we cannot calculate the energy carried by the wave without additional data.

If the intensity (I) and area (A) are provided, we can calculate the power (P) of the wave using the formula P = I * A. Then, we can find the energy (E) carried by the wave during the 30.0-s commercial by using the formula E = P * t, where t is the time in seconds.

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The conversion of sugar to energy in the presence of oxygen is
A.
respiration
B.
protein synthesis
C.
binary fission
D.
photosynthesis

Answers

Answer:

A. respiration.

Explanation:

Cellular respiration can be defined as a series of metabolic reactions that typically occur in cells so as to produce energy in the form of adenosine triphosphate (ATP). During cellular respiration, high energy intermediates are created that can then be oxidized to make adenosine triphosphate (ATP). Therefore, the intermediary products are produced at the glycolysis and citric acid cycle stage.

Additionally, mitochondria provides all the energy required in the cell by transforming energy forms through series of chemical reactions; breaking down of glucose into Adenosine Triphosphate (ATP) used for providing energy for cellular activities in the body of living organisms.

Basically, oxygen goes into the body of a living organism such as plants, humans and animals when they breathe while glucose is absorbed by the body when they eat.

Hence, the conversion of sugar to energy in the presence of oxygen is respiration.

A stretched string fixed at both ends is
2.0 m long. What are three wavelengths
that will produce standing waves on this string? Name at least one
wavelength that would not produce a standing wave pattern, and explain
your answer.

Answers

The three wavelengths that will produce standing waves on this string are 4 m, 2 m, and 1.33 m.

How did we get the values?

To find the wavelengths that will produce standing waves on a stretched string fixed at both ends, we can use the formula:

λn = 2L/n

where λn is the wavelength of the nth harmonic, L is the length of the string, and n is the harmonic number.

For the fundamental frequency (n = 1), the wavelength would be:

λ1 = 2L/1 = 4 m

For the second harmonic (n = 2), the wavelength would be:

λ2 = 2L/2 = L = 2 m

For the third harmonic (n = 3), the wavelength would be:

λ3 = 2L/3 ≈ 1.33 m

So, the three wavelengths that will produce standing waves on this string are 4 m, 2 m, and 1.33 m.

Now, for a wavelength that would not produce a standing wave pattern, we can consider the case where the wavelength is equal to the length of the string, i.e., λ = L. In this case, the wave will not produce a standing wave pattern because the ends of the string are fixed nodes, and the only possible standing wave pattern is one that has a node at each end. If the wavelength is equal to the length of the string, the only possible pattern would be a single wave with an antinode at the center, which is not a standing wave.

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In a parallel circuit, the total current flow is equal to the _____ of the currents through all the branches.

Answers

In a parallel circuit, the total current flowing through the circuit is equal to the sum of the currents through all the individual branches.

In a parallel circuit, the current has multiple paths or branches to flow through. Each branch provides a separate path for the current to follow. The total current flowing into the circuit is divided among these branches, with each branch carrying a portion of the total current.

To calculate the total current in a parallel circuit, you simply add up the currents flowing through each branch. Mathematically, it can be expressed as:

Total Current = Current in Branch 1 + Current in Branch 2 + ... + Current in Branch n

In a parallel circuit, the total current flowing through the circuit is equal to the sum of the currents through all the individual branches. This is because the current has the freedom to divide and flow through multiple paths in parallel, resulting in the sum of currents being equal to the total current.

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wavelength of red light is 700 nanometers, and its frequency is 4.285 x 1014 hz. what is the speed of red light in m/s. (note: 1 nanometer is

Answers

Answer:

Speed = 3·10⁸ m/s

Explanation:

Given:

λ = 700 nm = 700·10⁻⁹ m

ν = 4.285·10¹⁴ Hz

_______________

V - ?

The speed of red light:

V = λ·ν

V = 700·10⁻⁹·4.285·10¹⁴ ≈ 3·10⁸ m/s

electromagnetic radiation with a wavelength of 745 nm appears as red light to the human eye. the energy of one photon of this light is 2.67 × 10-19 j. thus, a laser that emits 1.3 ×10-2 j of energy in a pulse of light at this wavelength produces photons in each pulse. electromagnetic radiation with a wavelength of 745 nm appears as red light to the human eye. the energy of one photon of this light is 2.67 × 10-19 j. thus, a laser that emits 1.3 ×10-2 j of energy in a pulse of light at this wavelength produces photons in each pulse. 3.6 × 1019 6.5 × 1013 4.9 ×1016 4.7 × 10-24 2.1 × 10-17

Answers

Photons are massless.

What is electromagnetic radiation?

Electromagnetic radiation consists of electromagnetic field-propagating waves that carry electromagnetic radiant energy. Radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays are included. All of these electromagnetic waves comprise the electromagnetic spectrum.

Given that:

E= Energy

h= Plank's constant = 6.6*10^-34 Js

c= speed of light = 3*10^8 m/s

E=hv = hc/λ

λ=745 nm = 745*10^-9 m

E=6.6*10^-34 * 3*10^8/745*10^-9

E= 2.657* 10^19 = 2.66* 10^19 J

hence, the energy of one photon of this light is 2.66* 10^19 J

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Correct question:

Electromagnetic radiation with a wavelength of 745 nm appears as a red light to the human eye. The energy of one photon of this light is...............  A) 2.67 x 10-28 B) 2.67 x 10-19 C) 1.48 x 10-22 D)1.48 × 10-31 E) 3.75 × 1018

F is a 20N vector directed 65 north of east and G is a 30N vector directed east. Find the magnitude of the direction of the resultant vector R = F+G.

Answers

The magnitude of the direction of the resultant vector R = F+G is 38.47 N, which is the length of the hypotenuse formed by the components of the two vectors.

To find the magnitude of the direction of the resultant vector R = F + G where F is a 20N vector directed 65 north of east and G is a 30N vector directed east, we will use Pythagoras theorem as well as some trigonometric ratios.Let's first find the x and y components of each vector:We can get the x and y components of vector F using trigonometry:$$\begin{aligned} F_x &= F \cos \theta \\ F_x &= 20 \cos (65^\circ) \\ F_x &= 20 \times 0.4226 \\ F_x &= 8.45 \ \text{N} \\ F_y &= F \sin \theta \\ F_y &= 20 \sin (65^\circ) \\ F_y &= 20 \times 0.9063 \\ F_y &= 18.126 \ \text{N} \end{aligned} $$We can also get the x and y components of vector G, noting that it has no y component since it is directed east:$$\begin{aligned} G_x &= G \cos \theta \\ G_x &= 30 \cos (0^\circ) \\ G_x &= 30 \times 1 \\ G_x &= 30 \ \text{N} \\ G_y &= G \sin \theta \\ G_y &= 30 \sin (0^\circ) \\ G_y &= 30 \times 0 \\ G_y &= 0 \ \text{N} \end{aligned} $$Next, we add the x and y components to get the components of the resultant vector:$$\begin{aligned} R_x &= F_x + G_x \\ R_x &= 8.45 + 30 \\ R_x &= 38.45 \ \text{N} \\ R_y &= F_y + G_y \\ R_y &= 18.126 + 0 \\ R_y &= 18.126 \ \text{N} \end{aligned} $$Finally, we use the Pythagorean theorem to get the magnitude of the resultant vector:$$\begin{aligned} R &= \sqrt{R_x^2 + R_y^2} \\ R &= \sqrt{38.45^2 + 18.126^2} \\ R &= \sqrt{1481.2901} \\ R &= 38.47 \ \text{N} \end{aligned} $$

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When connecting two wires to a PCBA what are ways to prevent the wires from being installed incorrectly?

Answers

Some ways to prevent incorrect installation of wires on a PCBA include colour-coding, labelling, using keyed connectors, and providing clear documentation and instructions for proper wire routing.

Colour-coding, labelling, and keyed connectors are three common ways to prevent incorrect installation of wires on a PCBA. Colour coding can be used to designate which wire goes to which terminal or connector, and can be especially helpful when working with multiple wires. Labels can be affixed to the wires or the PCB to provide additional guidance on proper wire routing and connections. Keyed connectors can also be used to prevent incorrect installation by ensuring that the connector can only be inserted one way. Clear documentation and instructions can also be provided to aid in proper wire routing and installation. These methods can help reduce the likelihood of errors during the installation process and improve the overall reliability and functionality of the PCB.

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PLEASE HELP FAST!!!
WILL MARK BRAINLIEST!!!!
This is a Earth Science course 4.02
2. Mariner 4 and 9 and Viking 1 and 2 probes needed enhanced cameras and wireless communication equipment to take images of Mars's surface and send them back to Earth. According to the video, how did improving our technology lead to new discoveries about Mars?
3. Using internet resources, describe how advances in imaging and wireless communication for space exploration have led to changes in imaging devices and communication on Earth.
4. Mars Odyssey and Mars Express required spectrometric equipment that could analyze Mars's atmosphere and surface composition and temperatures. Using internet resources, describe some home or business technologies that use spectrometric equipment to analyze atmosphere or temperature.
5. Using internet resources, research one space probe described in the video. Describe its goals and justify its purpose by explaining how it helped advance our understanding of the universe.

Answers

Answer:

1.It improved by using the Mars survey probe, that took a portrait of the planet that helped us see the climate of Mars.

Explanation:

I watched the video.

PLEASE HELP ANSWER THIS WORKSHEET IT'S DUE TODAY WILL GIVE BRAINLIEST BALANCED AND UNBALANCED WORKSHEET

Answers

Answer:The net force for A. Is 2 and the resultant motion is up

B. NET force: 2 resultant motion: left

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C. Net force: 3 Resultant motion: Left

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D. Net Force: 7 Resultant motion: right

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E. Net Force:0 resultant motion: NO MOTION

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F. NET Force: 3 resultant motion: Down

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G. NET FORCE: 10 resultant motion: up

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H. Net force: 3 Resultant motion: left

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I. Net force: 50 Resultant motion: right

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J. NET FORCE: 75 Resultant motion: down

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K. Net force :200 Resultant motion: Right

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L. force: 0 resultant motion:No motion

Explanation:

a student designing an electric scooter uses a simple column type load cell with two strain gauges

Answers

A load cell is an essential sensor device used for converting a force, torque, pressure, or displacement into an electrical signal. It is a key component in electronic scales, force measuring instruments, and weighing devices. A student who designs an electric scooter uses a simple column type load cell with two strain gauges.

The load cell measures force or weight by converting the tension or compression acting on the load cell into an electrical signal. A load cell typically comprises four strain gauges that are arranged in a Wheatstone bridge configuration. A column type load cell is cylindrical in shape and is designed to measure loads in compression. It typically comprises two columns that are connected by a metal diaphragm. Two strain gauges are attached to the columns, one for measuring the compressive strain and the other for measuring the tensile strain.

The student designing an electric scooter uses a load cell to measure the weight of the rider and other loads on the scooter. The load cell is typically placed at the bottom of the scooter's frame, and the weight of the rider and the scooter is applied to it. The load cell measures the weight by converting the compression force acting on it into an electrical signal. The two strain gauges attached to the columns of the load cell measure the compressive and tensile strains, respectively. These strains are converted into an electrical signal using a Wheatstone bridge circuit, and the output of the bridge is proportional to the weight applied to the load cell.The student designing the electric scooter needs to select the right load cell for the application. The load cell must be able to measure the maximum weight that the scooter can carry. The column type load cell is suitable for measuring loads in compression, which is ideal for measuring the weight of the rider and the scooter. The two strain gauges attached to the columns of the load cell help to increase the sensitivity and accuracy of the load cell. The Wheatstone bridge circuit helps to convert the strain measurements into an electrical signal that can be processed by the scooter's control system.

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Pushing a baby on a swing is easier than pushing an adult on the same swing.

Water spills from a glass carried by someone who is walking steadily and suddenly stops short.

When thrown with the same force, a soccer ball accelerates more than a bowling ball.

A magician pulls a tablecloth out from under a dish on a table without disturbing the dish.

A rocket launches into space, pushing fuel exhaust in one direction and the rocket in the opposite direction.

A book rests on top of a shelf and does not move until a student accidentally knocks it off.

Answers

Answer:

Law 2:

Pushing a baby on a swing is easier than pushing an adult on the same swing. Water spills from a glass carried by someone who is walking steadily and suddenly stops short.

Law 2:

When thrown with the same force, a soccer ball accelerates more than a bowling ball.

Law 1:

A magician pulls a tablecloth out from under a dish on a table without disturbing the dish.

Law 3:

A rocket launches into space, pushing fuel exhaust in one direction and the rocket in the opposite direction.

Law 1:

A book rests on top of a shelf and does not move until a student accidentally knocks it off.

Explanation:

Newton's laws of motion:

Law 1: Law of inertia

Law 2: Law of force (F = mass x acceleration)

Law 3: Law of Action & Reaction

The laws followed by the given situations are Newton's law of force, Law of inertia and Newton's third law.

What is meant by inertia ?

Inertia is defined as the tendency of an object to continue its state of rest or motion.

Here,

Considering the situations given,

1. Pushing a baby on a swing is easier than pushing an adult on the same swing.

This is because, the mass of the baby is lesser than that of the adult. So, according to Newton's force equation,

Force, F = ma

Therefore to push a body with more mass, more force should be applied.

Another situation that follows this law from the given situations is:

When thrown with the same force, a soccer ball accelerates more than a bowling ball.

2. Water spills from a glass carried by someone who is walking steadily and suddenly stops short.

This is due to the inertia of the water in the glass. This can be explained by law of inertia.

Another situation that follows this law from the given situations is:

A magician pulls a tablecloth out from under a dish on a table without disturbing the dish.

A book rests on top of a shelf and does not move until a student accidentally knocks it off.

3. A rocket launches into space, pushing fuel exhaust in one direction and the rocket in the opposite direction.

This is according to Newton's third law of motion. The law of action and reaction.

Hence,

The laws followed by the given situations are Newton's law of force, Law of inertia and Newton's third law.

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What happens to the wavelength of a wave if the frequency quadruples, but the wave is in the same medium?

A. The wavelength will go down to half the original amount.

B. The wavelength will go down to one-fourth of the original amount.

C. The wavelength will be quadruple.

D. The wavelength will double.

Answers

Answer:

I think C? I'm not sure totally though...

Explanation:

Question 4: In a city the traffic lights on the main road are set up so that traffic lights are green for 55 seconds, red for 48 seconds, and amber for 17 seconds (the city is in California, so no one stops on amber).
(a) What is the chance that you will have to stop at a particular traffic light?
(b) Suppose that there are 10 traffic lights in the main street. What is the expected amount of time you are likely to be stopped at traffic lights if you drive all the way down the main street?

Answers

The probability of stopping at a traffic light is about 47.22%.

With 10 traffic lights, expect to be stopped for approximately 5 minutes and 45 seconds along the main street.

(a) To calculate the probability of stopping at a particular traffic light, we need to consider the cycle time of the traffic lights. The cycle time is the total time taken for one complete sequence of green, amber, and red signals. In this case, the cycle time is 55 + 17 + 48 = 120 seconds.

The probability of stopping at a particular traffic light can be calculated by dividing the red signal duration by the cycle time. Therefore, the probability is 48/120 = 0.4 or 40%.

However, in California, no one stops on amber, so we need to exclude the amber duration from the calculation. Therefore, the probability becomes 48/(55 + 48) ≈ 0.4722 or 47.22%.

(b) If there are 10 traffic lights on the main street, we can calculate the expected amount of time spent stopped at traffic lights by multiplying the probability of stopping at each traffic light by the average duration of being stopped.

The average duration of being stopped at a traffic light is the sum of the red signal duration and half of the amber signal duration. So, the average duration is (48 + 17/2) = 56.5 seconds. To find the expected amount of time stopped at traffic lights, we multiply the average duration by the number of traffic lights: 56.5 seconds * 10 = 565 seconds.

Therefore, if you drive all the way down the main street, the expected amount of time you are likely to be stopped at traffic lights is approximately 565 seconds, which is equivalent to 5 minutes and 45 seconds.

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ill mark as brainliest if given the option

ill mark as brainliest if given the option

Answers

Answer:

\(36 g/cm^{3}\)

Explanation:

In order to find the density, the problem says we need to find the volume first.

Since we know that the sample of gold is a perfect cube, we know that the side lengths will all be the same. Since all the side lengths will be 3, we can take that value and cube it to find the volume.

\(3^{3} = 27\)

Now that we know the volume is 27 cm³, we can solve find the density.

\(Density = \frac{Mass}{Volume}\)

\(Density = \frac{972g}{27cm^{3} } = 36 g/cm^{3}\)

Therefore, the density of the sample is 36 g/cm³.

Which sequence lists types of materials in order from least conductive to most conductive?
-superconductor conductor semiconductor insulator
-insulator conductor semiconductor superconductor
-conductor superconductor semiconductor insulator
-insulator semiconductor conductor superconductor

Answers

Answer:

D). Insulator —> semiconductor —> conductor—> superconductor

Explanation:

The sequence list of types of materials in order from least conducive to the most conductive is: the insulator, semiconductor, conductor, and superconductor. Conductors are materials where electric current can flow freely; whereas, in insulators, electric current cannot. Examples of conductors are metals and water. Examples of insulators are plastics, papers, and rubbers.

Answer:

ya its D

Explanation:

The coldest clouds in the ISM are molecular clouds, so named because their temperatures are low enough and their densities high enough for atoms to join together into molecules. These clouds are capable of collapsing to form new stars, in a stellar nursery like the one in the left image. The Pleiades (right image) is an example of stars that formed recently within such a nursery.
Molecular clouds range in mass from a few times the mass of our Sun (solar masses) to 10 million solar masses. Individual stars range from 0.08 to about 150 solar masses.
What does all of this imply about how stars form from molecular clouds?

Answers

Stars form from molecular clouds through a process known as stellar formation.

These clouds, characterized by low temperatures and high densities, provide the ideal conditions for atoms to combine and form molecules. With a mass range spanning from a few solar masses to millions of solar masses, molecular clouds serve as the birthplaces of new stars. The Pleiades cluster serves as a notable example of stars that have recently formed within such a stellar nursery.

The formation of stars from molecular clouds involves several key steps. Firstly, gravitational forces acting on regions of higher density within the cloud cause them to collapse under their own gravity. As the cloud collapses, it begins to fragment into smaller, denser clumps called protostellar cores. These cores continue to collapse, and their central regions become increasingly dense and hot. At this stage, they are known as protostars.

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A bicycle wheel is rotationally accelerated at a constant rate of 1.5 rev/s^2.
a)if it starts from rest, what is its rotational velocity after 4 seconds?
b) Through how many revolutions does it turn in this time?

Answers

The bicycle wheel will rotate at a rotational velocity of 6 revolutions per second after 4 seconds. The wheel will turn 12 revolutions during this time.

a) If a bicycle wheel is rotationally accelerated at a constant rate of 1.5 rev/s², and it starts from rest, then its rotational velocity after 4 seconds is 6 revolutions per second.  

Angular acceleration is calculated by the formula

α = Δω/Δt = (ωf - ωi)/t

where α is angular acceleration, Δω is the change in angular velocity, and Δt is the change in time.

ωi = initial angular velocity

    = 0

ωf = final angular velocity

α = 1.5 rev/s²

t = 4 s

ωf = αt + ωi

    = 1.5 rev/s² x 4 s + 0

    = 6 rev/s

b) Through how many revolutions does it turn in this time

Angular displacement is calculated by the formula

θ = ωit + ½αt²

Where θ is angular displacement, ωi is the initial angular velocity, t is time, and α is angular acceleration.

ωi = 0

α = 1.5 rev/s²

t = 4 s

θ = ωit + ½αt²

θ = 0 + ½ x 1.5 rev/s² x (4 s)²

  = 12 revolutions.

Hence, the bicycle wheel will rotate at a rotational velocity of 6 revolutions per second after 4 seconds. The wheel will turn 12 revolutions during this time.

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How are solar flares different from solar prominences.

Answers

A prominence is a loop of cool incandescent gas that extends above the photosphere. A solar flare is an explosive release of energy that comes from the sun and causes magnetic ditrubances.

Answer:

What is the difference between a prominence and a solar flare? A prominence is a loop of cool incandescent gas that extends above the photosphere. A solar flare is an explosive release of energy that comes from the sun and causes magnetic ditrubances.

Explanation:

what is the hydrogen-fusing lifetime of a star with a mass 1.3 times that of the sun, which shines with a luminosity that is 3.2 times that of the sun? report your answer in millions of years (myr).

Answers

The hydrogen-fusing lifetime of a star with a mass 1.3 times that of the sun, which shines with a luminosity that is 3.2 times that of the sun is about 225 million years (Myr).

The hydrogen-fusing lifetime of a star with a mass 1.3 times that of the sun, which shines with a luminosity that is 3.2 times that of the sun is about 225 million years (Myr).Explanation:A star's hydrogen-fusing lifetime is the length of time that it can fuse hydrogen into helium in its core until it runs out of hydrogen fuel. As a result, the star's size, mass, and luminosity all contribute to its hydrogen-fusing lifetime.Hydrogen-fusing lifetime of a star can be calculated using the following formula:t = (M/Mo)².5 (L/Lo)^-3.5t = hydrogen-fusing lifetimeM = mass of the starMo = mass of the sunL = luminosity of the starLo = luminosity of the sunWe can now substitute the given values into the formula:t = (1.3/1)^2.5 (3.2/1)^-3.5t = 225 MyrTherefore, the hydrogen-fusing lifetime of a star with a mass 1.3 times that of the sun, which shines with a luminosity that is 3.2 times that of the sun is about 225 million years (Myr).

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Two charged bodies exert a force of 3.2×10×10N on each other.what will be the force between them if their separation is:a.double

b.halved

Answers

a. If the separation between two charged bodies is doubled, then the force between them will become one-fourth of its initial value. According to Coulomb's law, the force (F) between two charged bodies is given by: `F = (kq₁q₂)/r²`Where k is the Coulomb's constant, q₁ and q₂ are the magnitudes of charges, and r is the separation distance between the charges.

Now, if the separation distance is doubled, then the new separation distance would be 2r. Hence, the new force between them will be: `F' = (kq₁q₂)/(2r)²` = `(kq₁q₂)/4r²`Therefore, the force between them if the separation is doubled will be one-fourth of its initial value. b. If the separation between two charged bodies is halved, then the force between them will become four times of its initial value. Now, if the separation distance is halved, then the new separation distance would be r/2. Hence, the new force between them will be: `F'' = (kq₁q₂)/(r/2)²` = `(kq₁q₂)/(r²/4)` = `4(kq₁q₂)/r²`Therefore, the force between them if the separation is halved will be four times its initial value.

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