4600 j work is done.
To find the amount of work done, the equation for work must be used. This equation is Work = Force x Distance. Force is equal to the mass of the box multiplied by the acceleration due to gravity, and the distance is 18 meters. The angle of 24 degrees above the horizontal must also be taken into account, therefore the cosine of 24 degrees must be used. The mass of the box is 64 kg and the acceleration due to gravity is 9.8 m/s2. After plugging in all the values, the work done is 4600 J.
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A 300 g football is kicked with an initial velocity of 140 m/s in a direction that
makes a 30° angle with the horizon. Find the peak height of the football.
Answer:
Explanation:
Assuming that air resistance is negligible, we can use the following kinematic equations to solve for the peak height:
v_f^2 = v_i^2 + 2ad
where v_f = 0 m/s (at the peak height) and a = -9.8 m/s^2 (acceleration due to gravity)
and
d = v_i t + (1/2)at^2
where d is the displacement or the peak height we want to find, v_i is the initial velocity, t is the time it takes to reach the peak height.
First, we need to resolve the initial velocity into its vertical and horizontal components:
v_i_x = v_i cos(30°) = 121.1 m/s
v_i_y = v_i sin(30°) = 70.0 m/s
Next, we can use the vertical component of the initial velocity to find the time it takes to reach the peak height:
v_f = v_i_y + at
0 m/s = 70.0 m/s + (-9.8 m/s^2)t
t = 7.14 s
Finally, we can use the time we found and the kinematic equation for displacement to find the peak height:
d = v_i_y t + (1/2)at^2
d = (70.0 m/s)(7.14 s) + (1/2)(-9.8 m/s^2)(7.14 s)^2
d = 247.5 m
Therefore, the peak height of the football is 247.5 meters.
A force of 1.50 N acts on a 0.20kg trolley so as to accelerate it along an air track
The track and force are horizontal and in line . How fast is the trolley going after acceleration from rest through 30cm , if friction is negligible
Answer:
2.12m/s
Explanation:
Given parameters:
Force on trolley = 1.5N
Mass of trolley = 0.2kg
Unknown:
Velocity of the trolley = ?
Solution:
To solve this problem, we first find the acceleration of the trolley;
Force = mass x acceleration
Acceleration = \(\frac{Force }{mass}\)
Insert the parameters and solve;
Acceleration = \(\frac{1.5}{0.2}\) = 7.5m/s²
Now to find the acceleration;
Initial velocity = 0m/s
v² = u² + 2aS
v is the final velocity
u is the initial velocity
a is the acceleration
S is the distance
Distance = 30cm and this is 0.3m
v² = 0² + 2(7.5)0.3 = 4.5
v = √4.5 = 2.12m/s
A body dropped over a fixed rough inclined plane of inclination 45 from height h. If after collision velocity of body becomes horizontal
then co-efficient of restitution if co-efficient of friction is 1/2
As per the given scenario, in this case, the coefficient of friction () is half and the coefficient of restitution (e) is zero.
Identify the body's starting velocity:
We may use the equation of motion to get the body's initial velocity (u)
\(v^2 = u^2 + 2as\)
\(0 = u^2 + 2(-9.8)m/s^2 * h\)
\(u^2 = 19.6h\)
u = √(19.6h)
Determine the coefficient of restitution (e):The body's initial velocity (u) and initial relative velocity (u_rel) are the same.
The body's horizontal velocity immediately following the collision, which is zero, is the final relative velocity (v_rel).
\(e = v_{rel }/ u_{rel}\)
e = 0 / u_rel = 0 / u
Now, one can investigate the forces affecting the body: When a body is on an inclined plane.
There are two main forces at work on it: the frictional force that prevents the body from moving and the gravitational force that pulls it downward (mg).
The gravitational force has two components that act perpendicular to and parallel to the inclined plane, respectively: m*g*cos(45°) and m*g*sin(45°).
Determine the conditions for the body to stop:
μ * N = m * g * sin(45°)
μ * (m * g * cos(45°)) = m * g * sin(45°)
μ * cos(45°) = sin(45°)
(1/2) * cos(45°) = sin(45°)
Simplifying further, we have:
√2 / 4 = √2 / 2
Thus, the body will come to rest following the collision if the equation is valid.
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A convex spherical mirror has a radius of curvature of magnitude36.0cm.
(a) Determine the position of the virtual image and the magnification for object distances of25.0cm. Indicate the location of the image with the sign of your answer.
image location =cm
magnification =
(b) Determine the position of the virtual image and the magnification for object distances of47.0cm. Indicate the location of the image with the sign of your answer.
image location =cm
magnification =
(c) Are the images in parts (a) and (b) upright or inverted?
The image in part (a) is---Select---uprightinverted
The image in part (b) is---Select---uprightinverted
Answer:
Explanation:
a )
focal length of convex spherical mirror
f = 36/2 cm = 18 cm
object distance u = - 25 cm
mirror formula
\(\frac{1}{v} + \frac{1}{u} = \frac{1}{f}\)
\(\frac{1}{v} + \frac{1}{- 25} = \frac{1}{18}\)
\(\frac{1}{v} = \frac{1}{25} + \frac{1}{18}\)
v = 6.28 cm .
It is positive hence the image will be erect / upright and formed on the back of the mirror.
For object distance of 47 cm
u = - 47 cm
Putting the values in the mirror formula
\(\frac{1}{v} + \frac{1}{- 47} = \frac{1}{18}\)
\(\frac{1}{v} = \frac{1}{ 47} + \frac{1}{18}\)
v = 13 cm
It is positive hence the image will be erect / upright and formed on the back of the mirror.
A snowboarder on a slope starts from rest and reaches a speed of 3.1 m/s after 6.7 s.
What is the magnitude (in m/s2) of the snowboarder's average acceleration?
a) The magnitude of the snowboarder's average acceleration is approximately 0.463 m/s². b) The snowboarder travels approximately 10.39 meters in the given time of 6.7 seconds.
To determine the magnitude of the snowboarder's average acceleration, we can use the formula:
average acceleration = (final velocity - initial velocity) / time
Given that the initial velocity (u) is 0 m/s, the final velocity (v) is 3.1 m/s, and the time (t) is 6.7 s, we can substitute these values into the formula:
average acceleration = (3.1 m/s - 0 m/s) / 6.7 s
Calculating this expression, we find:
average acceleration = 3.1 m/s / 6.7 s ≈ 0.463 m/s²
Therefore, the magnitude of the snowboarder's average acceleration is approximately 0.463 m/s².
To determine the distance traveled by the snowboarder in this time, we can use the equation of motion:
distance = initial velocity * time + (1/2) * average acceleration * time²
Since the initial velocity is 0 m/s, we can simplify the equation to:
distance = (1/2) * average acceleration * time²
Substituting the given values:
distance = (1/2) * 0.463 m/s² * (6.7 s)²
Calculating this expression, we find:
distance ≈ 0.5 * 0.463 m/s² * 44.89 s² ≈ 10.39 meters
Therefore, the snowboarder travels approximately 10.39 meters in the given time of 6.7 seconds.
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1. Which of the following does not affect the resistance of a wire?
a) Length
b) Temperature
c) Usage time
d) Cross-sectional area
2. If a 12V battery is passing current through a resistor with a current of 2A, what is the value of the resistor?
a 24resistance
b) 14resistance
c) 10resistance
d) 6resistance
3. Describe the differences between series and parallel circuits.
4. A circuit contains resistors of 8resistance and 4resistance,what is combined resistance if the resistors are combined:
a) In series
b) In parallel
5. A 0.5A current is passing across three resistors of 8resistance, 4resistance and 12resistance that are linked in series.
What is the potential difference of the circuit?
6. Wire A has a resistance of 24resistance. If wire B is double the length and has a diameter four times as large as wire A, what is the resistance of wire B?
What is the total amount of force needed to keep a 6.0 kg object moving at speed
of 5.0 m/s? (F=ma)
A. 30 N
B. 60 N
C.ON
D. 10 N
Can blind people dream?
Just wondering because I've always wanted to know.
Answer:
yea yes they can they lose their retina but they can dream
Consider 5.00 mol of liquid water. (a) What volume is occupied by this amount of water? The molar mass of water is 18.0 g/mol. (b) Imagine the molecules to be, on average, uniformly spaced, with each molecule at the center of a sma11 cube. What is the length of an edge of each sma11 cube if adjacent cubes touch but don't overlap? (c) How does this distance compare with the diameter of a molecule?
This question involves the concepts of density, volume, and mass.
(a) The volume occupied by this amount of water is "90 m³".
(b) The length of an edge of each small cube is "83 μm".
(c) The length of the edge of each small cube is "equal" to the diameter of a molecule.
(a)
The volume can be found using the following formula:
\(V = \frac{nM}{\rho}\)
where,
V = volume occoupied = ?
n = no. of moles = 5 mol
M = molar mass = 18 g/mol
\(\rho\) = density of water = 1 g/m³
Therefore,
\(V=\frac{(5\ mol)(18\ g/mol)}{1\ g/m^3}\\\\\)
V = 90 m³
(b)
First, we will find the volume of an individual molecule:
\(V_i =\frac{V}{nN_A}\)
where,
\(N_A\) = Avogadro's number = 6.02 x 10²³ molecules/mol
Therefore,
\(V_i=\frac{90\ m^3}{5\ mol(6.02\ x\ 10^{23}\ molecules/mol)}\)
Vi = 3 x 10⁻²³ m³
This volume can be given as a volume of the sphere:
\(V_i=\frac{4}{3}\pi r^3\\\\r=\sqrt[3]{\frac{3(3\ x\ 10^{-23}\ m^3)}{4\pi}}\)
r = 4.15 x 10⁻⁷ m
Diameter = d = 2r = 2(4.15 x 10⁻⁷ m)
d = 8.3 x 10⁻⁷ m = 83 μm
since the cubes are adjacent to each other. Therefore, the diameter will be equal to the edge length.
Edge Length = L = d
L = 8.3 x 10⁻⁷ m = 83 μm
(c)
The edge length is equal to the diameter of the molecule.
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A flat sheet of paper of area 0.450 m2 is oriented so that the normal to the sheet is at an angle of 600 to a uniform electric field of magnitude 18 N C-1. What is the magnitude of the electric flux through the sheet? A. 3.22 N m2 C-1 B. 21.42 N m2 C-1 C. 5.04 N m2 C-1 D. 11.72 N m2 C-1 E. 4.05 N m2 C
The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).
The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.
In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²
(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:
Electric flux = Electric field strength × Area
Electric flux = 18 N C⁻¹ × 0.450 m²
Electric flux = 8.1 N m² C⁻¹
In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.
The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).
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Harmonic Motions of Similar Models. The unifying power of mathematical methods results to a large extent from the fact that different physical (or other) systems may have the same or very similar models. Illustrate this for the following three systems (a) Pendulum clock. A clock has a 1-meter pendulum. The clock ticks once for each time the pendulum completes a full swing, returning to its original position. How many times a minute does the clock tick
Answer:
tick = 30
Explanation:
The angular velocity in a simple pendulum is
w² = g / L
the angular velocity is related to the period
w = 2π/ T
let's substitute
\(\frac{4 \pi }{T^2} = \frac{g}{L}\)
T = \(2 \pi \sqrt{\frac{L}{g} }\)
indicate that the length is m = 1, if we assume that the acceleration of gravity is g = 9.8 m / s²
T = 2π \(\sqrt{\frac{1}{9.8} }\)
T = 2.0 s
the clock has a tick each period and since the period is 2.0 s, to complete the minute (60 s) you need
tick = 1 60 / T
tick = 1 60/2
tick = 30
The clock ticks 30 times in a minute.
Given that the clock ticks only when the pendulum makes one full swing and complete on cycle and returns to its original position. To calculate how many times the clock ticks we need to calculate the time period of the pendulum swing.
For a pendulum, the time period (T) is given by:
\(T=2\pi \sqrt\frac{L}{g}\)
where g is the acceleration due to gravity = 9.8\(m/s^{2}\),
and L is the length of the pendulum = 1m (given)
\(T=2*3.14 \sqrt\frac{1}{9.8}\)
\(T=2s\)
So, the pendulum takes 2 seconds to complete a cycle.
2s = 1 tick
60 second = 60/2 = 30 ticks
It will tick 30 times in a minute.
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How do you calculate the total pressure?
Answer:
You could put a pressure stick against the pressure and see the pressure or estimate it from the power its coming out.
Explanation:
A volleyball that has an initial momentum of
−
1.0
kg
⋅
m
s
−1.0kg⋅
s
m
minus, 1, point, 0, start text, k, g, end text, dot, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction changes direction after a hand hits it with a force of
150
N
150N150, start text, N, end text for
0.01
seconds
0.01seconds0, point, 01, start text, s, e, c, o, n, d, s, end text.
A hand hits a volleyball. An arrow points to the right, in the directio
Answer:
10-
Step-by-Step Explanation:
A sound wave is traveling with a frequency of 880Hz. It has a wavelength of 0.75. What is the speed of the sound wave
The speed of the sound wave is 660 meters per second.
To calculate the speed of the sound wave, we need to use the formula:
Speed = Frequency x Wavelength
Here, the frequency of the sound wave is given as 880Hz, and the wavelength is given as 0.75. To get the answer, we just need to plug these values into the formula and solve for the speed:
Speed = 880 x 0.75
Speed = 660 meters per second
It's important to note that the speed of sound depends on the medium through which it is traveling. In air, the speed of sound is approximately 343 meters per second at standard temperature and pressure. However, this value can change depending on factors such as temperature, humidity, and altitude.
Understanding the speed of sound is important in various fields, such as music, engineering, and physics. For example, in music, the speed of sound determines the pitch of a note, while in engineering, it can be used to design and optimize acoustic systems. In physics, it's used to study the properties of waves and to explain phenomena such as Doppler effect and sonic booms.
Therefore, the speed of the sound wave is 660 meters per second.
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1. According to paragraph 3 in the text, MOST of the electromagnetic waves from
the sun that reach Earth are: *
O A. microwaves, x rays and visible light
O B. radio waves, infrared waves and visible light
O C. infrared waves, visible light and ultra-violet radiation
D. gamma rays, ultra-violet radiation and microwaves
Answer:
Most of the EM waves from the sun that reach Earth are infrared waves, visible light, and UV radiation.
Explanation:
I hope this helps! Have a good day!
An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid has a
mass of 3.8x 104 kg, and the force causes its speed to change from 6700 to 4600m/s. (a) What is the work done by the force? (b) If the
asteroid slows down over a distance of 2.4x 10 m determine the magnitude of the force.
The work done by the force is 7. 89 * 10^8 Joules and the magnitude of the force is 3. 3* 10 ^7 Newton
How to determine the work done
a. Work done = force * change in velocity = Impulse
Note that:
Force = mg
mass = 3.8x 104 kg
g = 10m/s²
Substitute into the formula for force
Force = 3.8* 10^4 * 10= 3.8* 10^5 Newton
Change in velocity = 6700 - 4600 = 2100 m/s
Work done = force *change in velocity
Work done = 3.8* 10^5 * 2100
Work done = 7. 89 * 10^8 Joules
b. Magnitude of the force = work done ÷ distance
Force = \(\frac{7. 89 * 10^8 }{2.4* 10}\)
Force = 3. 3* 10 ^7 Newton
Therefore, the work done by the force is 7. 89 * 10^8 Joules and the magnitude of the force is 3. 3* 10 ^7 Newton
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By what factor will the ratio^Q/V increase for a capaci-
tor whose capacitance is doubled?
(a) No change
(b) 2
(d) 1/2
(c) 4
There will be no change in the ration of Q/V. Therefore the correct answer is (a).
How to proof there is no change in the Q/VThe ratio of charge Q to voltage V across a capacitor is given by:
Q/V = C
Where C is the capacitance of the capacitor.
If the capacitance is doubled, the new capacitance C' becomes 2C. Substituting into the equation, we get:
Q/V = C
Q/V = 2C/2 = C'
So the ratio of Q to V remains the same, and there is no change in the ratio Q/V when the capacitance is doubled.
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The following table lists the speed of sound in various materials. Use this table to answer the question.
Substance Speed (m/s)
Glass 5,200
Aluminum 5,100
Iron 4,500
Copper 3,500
Salt water 1,530
Fresh water 1,500
Mercury 1,400
Hydrogen at 0°C 1,284
Ethyl Alcohol 1,125
Helium at 0°C 965
Air at 100°C 387
Air at 0°C 331
Oxygen at 0°C 316
Sound will travel fastest in air at _____.
-5°C
0°C
10°C
15°C
Sound will travel fastest in air at 15°C.
Speed of sound in air
The speed of sound in air, given in the range of 100 degrees Celsius and 0 degree Celsius include;
Air at 100°C 387 m/s
Air at 0°C 331 m/s
From the date above, the speed of sound in air increases with increases in temperature. Thus, Sound will travel fastest in air at 15°C.
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What is the direction of the magnetic field at the location of the charge due to the current-carrying wire
Answer: please find the answer in the explanation.
Explanation:
The direction of the magnetic field at the location of the charge due to the current-carrying wire can be determined by using right hand rule.
The thumb points in the direction of current while the fingers curl around in the direction of the magnetic field.
The right hand rule applies to a current in a straight wire. The thumb is pointed in the direction of the current and the fingers then give the direction of the magnetic field lines.
Question 2 of 10
According to the law of conservation of energy, which statement must be
true?
A. The total energy in a system can only increase over time.
B. Energy that is transformed is neither destroyed nor created.
C. Energy can change only from nuclear to chemical.
O D. There is only one form of energy.
Answer:
B: Energy that is transformed is neither created or destroyed
Explanation:
Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.
The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J
How do i determine the quantity of heat energy?First, we shall list out the given parameters from the question. This is shown below:
Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?The quantity of heat energy that must be transferred can be obtained as follow:
Q = MCΔT
= 2.25 × 394 × 220
= 195030 J
Thus, we can conclude quantity of heat energy that must be transferred is 195030 J
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James is planning on registering for a course in electrical engineering which of the following sub disciplines could he opt for instrumentation engineering prosthetics plant design or signal processing
Answer:
Instrmentation engineering
Explanation:
Hope this helps!
a lens which is thicker in the middle than at the edges is a group of answer choices diverging lens. achromatic lens. antireflection lens. converging lens.
A converging lens is one that is thicker in the centre than it is at the edges.
Converging Lens
Light is directed to a point at the optical centre or axis of a convergent lens. a lens that creates a true image by converting parallel light beams to convergent light rays. The image is actual and inverted as long as the object is outside of the focal point. The image becomes virtual and upright when the object is inside the focal point. A lens is a transmissive optical tool that refracts light to change how sharply it focuses. The lens in this instance is referred to as a positive or converging lens.
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A student pushes a 12 N book to the
right with a force of 10 N. The book
experiences a frictional force of 3 N.
Answer:
Explanation:
My name is Jeff
During which type of change should you expect to see different chemical
symbols before and after the change?
A. Chemical
B. Phase
C. Nuclear
D. Physical
During the nuclear change we can expect to see different chemical symbols before and after the change
Chemical and nuclear reactions are quite different from one another. Atoms can share electrons with other atoms or participate in an electron transfer to increase their stability in chemical reactions. In nuclear reactions, the atom's nucleus stabilizes itself by going through some sort of alteration. Compared to the energies involved in chemical reactions, the energies produced in nuclear reactions are many orders of magnitude higher. Environmental factors like temperature or pressure do not significantly affect nuclear reactions like they do with chemical ones.
Nuclear reactions involve a change in an atom's nucleus, usually producing a different element. Chemical reactions, on the other hand, involve only a rearrangement of electrons and do not involve changes in the nuclei
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50
1. Force = ? N mass = 65 kg acceleration = 25 m/s2 (Record your answer
by number only and don t.include units...)
Answer: el pepe
Explanation:
Answer:
8125 N.
Explanation:
F = M A
M is mass
A is acceleration
F = 65 X 25
F = 8125 N.
Is the acceleration change or constnt?
A solid sphere of radius R, a solid cylinder of radius R, and a rod of length R all have the same mass, and all three are rotating with the same angular velocity The sphere is rotating around an axis through its center. The cylinder is rotating around its long axis, and the rod is rotating around an axis through its center but perpendicular to the rod. Which one has the greatest rotational kinetic energy? a. the sphere b. the cylinder c. the rod d. the rod and the cylinder have the same rotational kinetic energy e. they all have the same kinetic energy
Answer:
b. the cylinder
Explanation:
From the information given:
We understood that the mass of the sphere, cylinder, and rod length is the same with the same angular speed.
Taking their moments:
For the solid sphere; \(\text{The moment of inertia :}\) \(I_s\) = \(\dfrac{2}{5} \times m \times r^2\)
The moment of inertia of the cylinder, \(I_c = 0.5\times m \times r^2\)
The moment of inertia of rod, \(I_r =\dfrac{ m * r^2 }{12}\)
The rotational kinetic energy is directly corresponding to the moment of inertia.
Thus, the cylinder has the greatest rotational kinetic energy.
An airplane takes off at an acceleration of 2m/s2. If it continues accelerating at that rate what will the airplane change in velocity be, in m/s, 60 seconds after take off
The airplane change in velocity be 120 m/sec
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.
The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.
acceleration = velocity/time
Velocity = acceleration * time
Velocity = 60*2
Velocity = 120 m/sec
The airplane change in velocity be 120 m/sec
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I NEED HELP PLZZZZZZ