Due to the heat generated by friction, around 0.0019 kg of ice melts as the ice-skater comes to a stop.
When a 62-kg ice-skater moving at 6.3 m/s comes to a stop, friction between the ice and the skates generates heat. To determine the amount of ice that melts due to this heat, we can calculate the energy transferred and use the heat of fusion for water.
The initial kinetic energy of the ice-skater is calculated using the formula (1/2) * mass * velocity^2. Substituting the values, we find the initial kinetic energy to be 1237.35 J.
Assuming that 50% of the heat generated by friction is absorbed by the ice, we calculate the heat generated by multiplying the initial kinetic energy by 0.5, resulting in 618.675 J.
To determine the mass of ice that melts, we divide the heat generated by the heat of fusion for water, which is 333 kJ/kg. The mass of ice melted is found to be approximately 0.001856 kg.
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A bug crawls 4 meters east across the kitchen floor in 20 seconds before someone steps on it and squishes it. What is its velocity?
Considering the definition of velocity, the velocity is 0.2 m/s due east.
Definition of velocityVelocity is a physical magnitude that relates the displacement of an object, the time it takes to make this change in position and direction, so it is considered a vector magnitude.
In other words, the velocity can be defined as the amount of space traveled per unit of time with which a body moves, considering the direction, and can be calculated using the expression:
velocity= distance traveled÷ time
Velocity has units of distance/time and includes direction of travel.
This caseIn this case, you know:
distance traveled= 4 meterstime= 20 secondsdirection= eastReplacing in the definition of velocity:
velocity= 4 meters÷ 20 seconds
Solving:
velocity= 0.2 m/s
Finally, the velocity is 0.2 m/s due east.
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The Doppler technique can be used to estimate the semimajor axis of a planet's orbit by
A. measuring the time it takes for the star's line-of-sight velocity to cycle from peak to peak, and using Newton's version of Kepler's Third law.
B. measuring the amount by which the starlight is reduced when the planet transits.
C. measuring the speed at which the star orbits the mutual center-of-mass of the star and planet, and using Newton's theory of gravity.
D. measuring the asymmetries in the velocity curve.
The Doppler technique can be used to estimate the semimajor axis of a planet's orbit by measuring the speed at which the star orbits the mutual center-of-mass of the star and planet, and using Newton's theory of gravity.
The Doppler technique, also known as the radial velocity method, is a common method for detecting exoplanets by measuring the slight wobble of a star caused by the gravitational pull of an orbiting planet. This wobble induces shifts in the star's spectral lines, which can be detected as changes in the star's line-of-sight velocity. By observing these velocity changes, astronomers can determine the speed at which the star is moving toward or away from us. This velocity change is directly related to the mass and orbital properties of the planet, including the semimajor axis of its orbit. Newton's theory of gravity provides the necessary mathematical framework to relate the observed velocity changes to the orbital parameters of the planet. By analyzing the pattern of the star's line-of-sight velocity changes over time, astronomers can estimate the semimajor axis of the planet's orbit, which represents the average distance between the planet and its host star. This information is crucial for understanding the orbital dynamics and characteristics of exoplanetary systems.
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in of the Solar System
When the ancient Greeks looked at the night sky they noticed that some points of light seem to wander" in the sky
Which term do we use for these wanderers today?
nebulae
moons
stars
1 planets
2 moons
3 stars
4 Planets
Answer:
stars #3
Explanation:
they didn't know it was stars
A massless rod is balanced on a pivot as shown below. If the rod is in static equilibrium, what
magnitude of force (x) must be exerted on the other end of the rod?
A. 7.5 N
B. 13 N
C. 20 N
D. 53 N
E. 80 N
If the rod is in static equilibrium, the magnitude of force (x)that must be exerted on the other end of the rod is C, 20 N.
In order for the massless rod to be in static equilibrium, the net torque about the pivot point must be zero. This means that the clockwise torque produced by the force exerted on the right end of the rod (x) must be equal and opposite to the counterclockwise torque produced by the weight of the rod and the force exerted on the left end of the rod (15 N).
The clockwise torque is given by
Tc = x(0.4 m),
where 0.4 m is the distance from the pivot point to the point where the force is exerted.
The counterclockwise torque is given by
Tcc = (15 N)(0.3 m) + (10 N)(0.6 m),
where 0.3 m and 0.6 m are the distances from the pivot point to the center of mass of the rod and the point where the weight is acting, respectively.
Setting Tc equal to Tcc and solving for x, we get:
x(0.4 m) = (15 N)(0.3 m) + (10 N)(0.6 m)
x = (15 N)(0.3 m + 0.6 m)/(0.4 m)
x = 20 N
Therefore, the magnitude of force (x) that must be exerted on the other end of the rod is 20 N.
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What will be the resistance Rstretched of the wire if it is stretched to twice its original length? Assume that the density and resistivity of the material do not change when the wire is stretched.
Answer:
Hence, the resistance of the stretched wire will be four times that of the original wire.Explanation:
The resistance of a material is expressed as R = ρL/A
Volume of the original material V = Area * Length = A*L
ρ is the resistivity of the material
R is the resistance
A is the cross sectional area
L is the length of the wire.
If the wire is stretched o twice its original length then new length of the wire L₂ = 2L. Note that an increase in the length of wire will affect its area but its volume and density will not change.
This means V = V₂
A*L = = A₂*L₂
A*L = A₂*(2 L)
A = 2 A₂
A₂ = A/2
The new resistance of the material Rf = ρL₂/A₂
R₂ = ρ(2 L)/(A/2)
Rf = 2ρL * 2/A
Rf = 4(ρL/A)
Since R = ρL/A
R₂ = 4R
Hence, the resistance of the stretched wire will be four times that of the original wire.
If the wire is stretched to twice its original length, the new resistance would be quadrupled.
The resistance (R) of a wire is given by:
\(R=\rho\frac{L}{A} \\\\where\ L\ is\ length\ of\ wire, A\ is\ the\ cross\ sectional\ area\ and\ \rho\ \\is\ the\ resistivity\)
Since the wire is stretched, the new length (L₁) is twice its original length, hence:
L₁ = 2L
An increase in length affects the area, the new area (A₁) is:
initial volume = volume after stretch
AL = A₁L₁
AL = A₁(2L)
A₁ = A/2
The resistance of the stretched wire (R₁) is:
\(R_1=\rho\frac{L_1}{A_1} \\\\R_1=\rho\frac{2L}{A/2} \\\\R_1=4\rho\frac{L}{A}=4R\)
Therefore if the wire is stretched to twice its original length, the new resistance would be quadrupled.
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A beaker containing 400g of water has 1200J of work done on it by stirring and 200cal of heat added to it from a hot plate.8.What is the temperature change of the water?A.1.2°C B.2.1°C C.1.4°C D.4.1°C
A.1.2°C
ExplanationThe First Law of Thermodynamics states that heat is a form of energy, and thermodynamic processes are therefore subject to the principle of conservation of energy.
To find internal energy, you have to add the heat added in the system and work done in the system because the work done is not lost but rather it is added in the system.
\(\begin{gathered} \Delta U=q+W \\ where\Delta U\text{ is the change in the internal energy} \\ q\text{ the heat added to the system} \\ W\text{ is the work done by the systeme} \end{gathered}\)Step 1
a)let
\(q=200\text{ cal}\)to add the energy it must have the same measure unit, so let's convert calories into Julies
remember that
\(\begin{gathered} 1\text{ cal}\Rightarrow4.184\text{ J} \\ so \\ 200\text{ cal}\Rightarrow200(4.814\text{ J})\Rightarrow836.8\text{ J} \end{gathered}\)b) now, replace in the formula
\(\begin{gathered} \Delta U= q+W \\ \Delta U=836.8\text{ J+1200 J} \\ \Delta U=2036.8\text{ J} \end{gathered}\)now, we have the change of internal energy
Step 2
now, let's find the change in temperature
Use the calorimetry formula.
\(\begin{gathered} Q=mc∆T \\ \end{gathered}\)where m is the mass, Q = heat energy, c = specific heat capacity, and ∆T = change in temperature
a)
let
\(mass=\text{ 0.4 kg}\)now,
\(\begin{gathered} Q=mC\Delta T \\ 2036.8\text{ j=0.4 kg*4184 }\frac{J}{Kg}|C*\Delta T \\ 2036.8=1673.6\Delta T \\ divide\text{ both sides by 1673.6} \\ \frac{2,036.8}{1673.6}=\frac{1,673.6\text{ }\Delta T}{1673.6} \\ 1.21=\Delta T \\ rounded \\ \Delta T=1.2\text{ \degree C} \end{gathered}\)so, the answer is
A.1.2°C
the hallway in kim's house is 4.63 m long. her kitchen is 0.0049 km long. which is longer, the hallway or the kitchen? how much longer?
By 0.27m, the kitchen is farther than the hallway. Because Kim's home's hallway is 4.63 metres long. The distance of her kitchen is 0.0049 kilometres. The distance is same in any velocity.
Distance is measured numerically or sporadically qualitatively. far apart certain things or points are. Distance in physics or common language can refer to a physical length or an assumption based on other factors. Purposes In disciplines that study human behaviour, such the social sciences, qualitative measurements are frequently used. The rate of change in an object's position relative to a frame of reference is called velocity, and it depends on time.
4.9m is equal to 0.0049 km;
the difference is equal to 4.9 - 4.63;
and the difference is equal to 0.27.
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An applied force of 20 N accelerates a block across a level,frictionless surface from rest to a velocity of 8.0 m/s in a time of 2.5 s. Calculate the work done by this force.
Answer:
workdone = force × distanceExplanation:
let's find the acceleration
\(v = u + at \\ 8 = 0 \times a \times 2.5 \\ \alpha = 3.2m {s}^{ - 2} \)
then distance
\( {v}^{2} = {u}^{2} + 2as \\ {8}^{2} = 2 \times 3.2 \times s \\ \\ s = 10m \)
w = f ×d = 20 × 10 = 200JIf you walk 17 m forward then turn around and walk 8 back what was your distance
Answer:
it would be nine
Explanation:
just subtract 8 from 17
How long will it take a rocket traveling at 8km/s to reach 20 km?
Answer:
2.5 seconds
Explanation:
20:8= 2.5 seconds
have a nice day! (^o^)
Answer:
2.5 seconds
Explanation:
20 ÷ 8 = 2.5
That's it.
At a point in a pipe, the section changes abruptly from a diameter of 1.20 meters to another of 60 cm. How much is the loss of load due to sudden contraction of the section worth when the flow rate is 850 Its/sec.
The loss of load due to the sudden contraction of the pipe section, where the diameter changes from 1.20 meters to 60 cm, can be calculated using the principles of continuity and Bernoulli's equation.
With a flow rate of 850 Its/sec, the loss of load can be determined by comparing the velocities at the two points of the pipe section. Additionally, the density of water is assumed to be 1000 kg/m^3. The calculated loss of load provides insight into the changes in fluid dynamics caused by the abrupt contraction. To calculate the loss of load, we first determine the cross-sectional areas of the pipe at the two points. At point 1, with a diameter of 1.20 meters, the radius is 0.60 meters, and the area is calculated using the formula A1 = π * r1^2. At point 2, with a diameter of 60 cm, the radius is 0.30 meters, and the area is calculated as A2 = π * r2^2.
Next, we calculate the velocity of the fluid at point 1 (V1) using the principle of continuity, which states that the mass flow rate remains constant along the pipe. V1 = Q / A1, where Q is the flow rate given as 850 Its/sec. Using the principle of continuity, we determine the velocity at point 2 (V2) by equating the product of the cross-sectional area and velocity at point 1 (A1 * V1) to the product of the cross-sectional area and velocity at point 2 (A2 * V2). Thus, V2 = (A1 * V1) / A2. The loss of load (ΔP) can be calculated using Bernoulli's equation, which relates the pressures and velocities at the two points. Assuming neglectable changes in pressure and equal elevations, the equation simplifies to (1/2) * ρ * (V1^2 - V2^2), where ρ is the density of the fluid.
By substituting the known values into the equation, including the density of water as 1000 kg/m^3, the loss of load due to the sudden contraction can be determined. This value quantifies the impact of the change in pipe diameter on the fluid dynamics and provides insight into the flow behavior at the given flow rate. The answer is 11.87
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HELP MEEEEEEEE PLEASEEEE
A) Compare the difference in the forces of impact for each of two helmets dropped form the same height in figure 2 and explain what this
difference suggests about the amount of time the force is applied to each helmet during the collision. Keep in mind that each helmet has
the same mass and that the crash pads slow down the helmets as they hit. You may use equation Fat mavto support your answer.
B) Explain why the relationship between force and time is important to a helmet designer.
During a collision, a skater will suddenly come to a complete stop. This is a foam of acceleration. A helmet can change the amount of
acceleration and the amount of force that a skater experiences during a collision
C) Compare two helmets in figure 3 and explain how helmet shape changes both the force and the acceleration on a skater's head, as the
skater hits the wall of the rink, using the formula Fema.
BI
SS.
Answer:
B Explain why the relationship between force and time is important to a helmet designer.
During a collision, a skater will suddenly come to a complete stop. This is a foam of acceleration. A helmet can change the amount of
hope you get a good grade
A 116 watt LED light bulb has a current of 11 amperes running through it. What is the
voltage in the lightbulb?
Answer:
Voltage = 10.54545
Given -
Current (I) - 11
Amps - 11
Resistance - 0.95868
Power - 116
We can conclude:
The voltage will be 10.54545, because of Ohm's Law:
Ohm's law states that:
Voltage (V) = Current (I) * Resistance (R)
Power (P) = Voltage (V) * Current (I)
Which statement describes an energy measurement?
A. Gravity applies 800 N to a person on Earth's surface.
B. A plane accelerates at 4.1 m/s2
C. An object has a mass of 250 kg.
D. One gram of wood stores 16,000 J.
The statement that describes an energy measurement is one gram of wood stores 16,000 J, therefore the correct answer is option D
What is thermal energy?It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.
Thermal energy can be produced with help of various means such as by burning fossil fuels, with the help of solar energy.
The Joule is the recognized unit of measurement for energy (J). Kilowatt/hour (kWh), which is used specifically for electric energy, should be listed among the most used units for measuring energy (in fact it is used to calculate electricity bills). The Terawatt/hour (TWh), or one billion kW/h, is used to calculate the output of big power facilities or the country's consumption.
Thus, The statement that describes an energy measurement is one gram of wood stores 16,000 J, therefore the correct answer is option D
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What angle is necessary to keep a 10 kg box motionless if the coefficient of static friction between the box and the ramp is 0.55?
a.33.4°
b.28.8°
c.56.6°
d.45.0°
The angle necessary to keep a 10 kg box motionless, given a coefficient of static friction of 0.55 between the box and the ramp, is 33.4°, which corresponds to Option A.
To determine the angle, we can use the relationship between the coefficient of static friction, the angle of the incline, and the gravitational force acting on the box. The maximum static friction force can be calculated using the formula:
Friction force = coefficient of static friction * Normal force
The Normal force can be found by decomposing the gravitational force acting on the box into components parallel and perpendicular to the incline. The perpendicular component (Normal force) is equal to the weight of the box (mass * gravitational acceleration).
Since the box is motionless, the friction force must be equal to the component of the gravitational force acting parallel to the incline:
Friction force = Component of weight parallel to incline
By substituting the given values and solving for the angle, we find:
coefficient of static friction = tan(angle)
angle = arctan(coefficient of static friction)
angle = arctan(0.55) ≈ 33.4°
Therefore, the correct answer is Option A, 33.4°.
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long straight wire lies along the z-axis and carries current in the positive z-direction. a positive point charge moves along the y-axis in the positive y-direction. the magnetic force that the wire exerts on the point charge is in : A. the positive x-direction.B. the negative x-direction.C. the positive y-direction.D. the negative y-direction.E. none of the above
The point charge is subject to a magnetic force from the wire that is present in the positive y-direction.
What is a good example of the magnetic force?The magnets are attracted to or repelling one another as a result of this force. A compass, the motor, the magnetic that hold items in refrigerators, railroad tracks, and modern roller coasters are examples of objects that use magnetic force. A magnetic field is created by all moving charges, and any charges that move across its regions feel a force.
What is an example of a Class 8 magnetic force?A magnet exerts a magnetic pull on certain materials such iron, steel, copper, and cobalt. This force can act from a distance, making it a sort of non-contact force. It does not needed that the objects be in direct contact. We saw how to utilize a magnet to collect coins in the example above.
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Explain why a steel boat floats on water but a steel block does not
A piece of steel sinks in water because steel is denser than water. However, a steel ship is a hollow object made of steel and contains a lot of air in it. Due to presence of a lot of air in it, the average density of the ship becomes less than the density of water. Hence a ship floats in water.
Answer:
Cause its a steel block
Explanation:
thats like putting a brick in the water and expecting it to float
What is a translucent object?
an object that isn't completely transparent or opaque kinda the middleground
it allows light through but it's not clear
a merry-go-round rotates at the rate of 0.30 rad/s with a(n) 80.0 kg man standing at a point 2.0 m from the axis of rotation. what is the new angular speed when the man walks to a point 1.0 m from the center? assume that the merry-go-round is a solid 6.50 x 102 kg cylinder with a radius of 2.00 m.
The new angular speed of the merry-go-round after the man walks to a point 1.0 m from the center is approximately 1.80 rad/s.
Let's denote the initial angular speed of the merry-go-round as ω₁, and the new angular speed after the man walks to a point 1.0 m from the center as ω₂.
Given:
Initial angular speed ω₁ = 0.30 rad/s
Mass of the man m = 80.0 kg
Initial distance of the man from the axis of rotation r₁ = 2.0 m
New distance of the man from the axis of rotation r₂ = 1.0 m
Mass of the merry-go-round (cylinder) M = 6.50 * 10² kg
Radius of the merry-go-round (cylinder) R = 2.00 m
The conservation of angular momentum can be applied in this scenario, where the initial angular momentum of the system is equal to the final angular momentum of the system.
The initial angular momentum of the system is given by:
Initial angular momentum L₁ = Moment of inertia of the man about the axis of rotation x initial angular speed of the merry-go-round
The moment of inertia of the man about the axis of rotation can be calculated using the formula for the moment of inertia of a point mass rotating about an axis at a distance r from the axis of rotation:
Moment of inertia of the man about the axis of rotation I₁ = m x r₁²
The final angular momentum of the system is given by:
Final angular momentum L₂ = Moment of inertia of the man about the new axis of rotation x new angular speed of the merry-go-round
The moment of inertia of the man about the new axis of rotation can be calculated using the same formula as above, but with the new distance r₂:
Moment of inertia of the man about the new axis of rotation I₂ = m x r₂²
Setting the initial and final angular momenta equal to each other, we can solve for the new angular speed ω₂:
L₁ = L₂
I₁ * ω₁ = I₁ * ω₂
Substituting the expressions for I₁, I₂, and the given values:
m * r₁² * ω₁ = m * r₂² * ω₂
Simplifying:
r₁² * ω₁ = r₂² * ω₂
Plugging in the given values for r₁, r₂, and ω₁, and solving for ω₂:
2.0² * 0.30 = 1.0² * ω₂
\(\omega_2 = \frac{(2.0^2*0.30)}{1.0^2}\)
ω₂ ≈ 1.80 rad/s.
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find the velocity, acceleration, and speed of a particle with the given position function. r(t) = 8 2 t i e8t j e−8t k
For the given position function r(t) = 8t^2i * e^(8t)j * e^(-8t)k, the velocity vector is (16t i + 64t^2 e^(8t)j - 64t^2 e^(8t)k), the acceleration vector is (16 i + 128te^(8t)j) .
The velocity, acceleration, and speed of a particle can be determined by differentiating the position function with respect to time. For the given position function r(t) = 8t^2i * e^(8t)j * e^(-8t)k, the velocity, acceleration, and speed can be calculated.
The velocity vector represents the rate of change of position, the acceleration vector represents the rate of change of velocity, and speed is the magnitude of the velocity vector.
To find the velocity vector, differentiate the position function r(t) with respect to time:
v(t) = dr(t)/dt = (16t i * e^(8t)j * e^(-8t)k) + (8t^2 i * 8e^(8t)j * e^(-8t)k) + (8t^2 i * e^(8t)(-8e^(-8t))k)
Simplifying this expression, we get:
v(t) = (16t i + 64t^2 e^(8t)j - 64t^2 e^(8t)k)
To find the acceleration vector, differentiate the velocity vector with respect to time:
a(t) = dv(t)/dt = (16 i + 128te^(8t)j + 64t(8e^(8t) - 8e^(8t))j + 64t^2(-8e^(8t))k)
Simplifying this expression, we get:
a(t) = (16 i + 128te^(8t)j)
The speed of the particle is the magnitude of the velocity vector. Using the velocity vector obtained earlier, we can calculate the speed at any given time t:
speed = |v(t)| = sqrt((16t)^2 + (64t^2 e^(8t))^2 + (64t^2 e^(8t))^2)
In summary, for the given position function r(t) = 8t^2i * e^(8t)j * e^(-8t)k, the velocity vector is (16t i + 64t^2 e^(8t)j - 64t^2 e^(8t)k), the acceleration vector is (16 i + 128te^(8t)j), and the speed is given by the magnitude of the velocity vector. The speed equation involves the square root of the sum of the squares of the components of the velocity vector.
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Which nucleus completes the following equation?
Cle+?
OA. S
OB. S
16
OC. Ar
18
OD. 39 y
18
The equation below is completed by the chromium nucleus.
Where can one locate chrome?Chromium is mostly found in chromite. The locations where this ore can be found include South Africa, India, Kazakhstan, and Turkey. In an electric arc furnace, chromite is often reduced with carbon to generate chromium metal, as is chromium(III) oxide when it is reduced with silicon or aluminum.
Why is chromium necessary?An important mineral called chromium helps insulin work properly in the body by regulating blood sugar levels. Your body uses the hormone insulin to convert sugar, starchy carbs, and other foods into the energy you require for daily activities.
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An ostrich is running with a velocity of 12.3 m/s and speeds up to 15.9
m/s in 5.2 seconds. What is the ostrich's acceleration?
A 0.69 m/s2
B 1.4 m/s2
C -0.69 m/s2
D -1.4 m/s2
The acceleration of the ostrich when running from 12.3 m/s to 15.9 m/s in 5.2 seconds is 0.69 m/s².
What is acceleration?This can be defined as the rate of change of velocity.
To calculate the acceleration of the ostrich, we use the formula below.
Formula:
a = (v-u)/t............ Equation 1Where:
a = Acceleration of the ostrichv = Final velocityu = Initial velocityt = TimeFrom the question,
Given:
v = 15.9 m/su = 12.3 m/st = 5.2 secondsSubstitute these values into equation 1
a = (15.9-12.3)/5.2a = (3.6)/5.2a = 0.69 m/s²Hence, the acceleration of the ostrich is 0.69 m/s². The right option is A. 0.69 m/s².
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LEVEL 2
A
Record the letters
in your triangle from
left to right.
с
B
D
Example:
ABCDEFGHI
F
H
E
G
I
Enter the correct 9 letter sequence (no spaces) Use all capital letters *
Your answer
O Keep Trying!
Back
Next
Triangle is a polygon with 3 sides. The record of the letters in your triangle from left to right is EGFBIHDCA.
How can we describe a triangle side?A triangle is a polygon with 3 sides. Also, It has three vertices.
As the example is given to us, ABCDEFGHI is the record of the letters that are when seen from top to bottom, therefore, if we rotate the triangle such that the left side of the triangle is on the upper side, then the triangle we will get is given below as attached below.
Therefore, the record of the letters in your triangle from left to right will now be "EGFBIHDCA" from the former arrangement which was "ABCDEFGHI".
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identify five ways you can help your respiratory system stay healthy.
Answer:
Don't Smoke, Check for mold, Exercise, Hydration, have a healthy diet!
Explanation
If you do these five things then your respiratory system will be in good shape. There are plenty of other things that you can do but these five will suffice for your question. Good luck!
Sitting on the table is a red book and a blue book. Which one is hotter?
A. Books are not blackbodies, so they do not emit radiation.
B. The red book
C. They are probably the same temperature
D. The blue book
C. They are probably the same temperature. it is likely that both the red book and the blue book are at the same temperature.
The color of an object does not inherently determine its temperature. The perceived color of an object is based on the wavelengths of light it reflects or absorbs. While different colors may have different abilities to reflect or absorb light, this does not necessarily indicate differences in temperature. Without additional information about the books or their exposure to external heat sources, it is reasonable to assume that both books sitting on the table would be at the same ambient temperature. In the absence of any specific heating or cooling mechanisms acting on the books, they would equilibrate with the surrounding environment and reach the same temperature over time.
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Which object would have the greatest kinetic energy? *
A car driving down a hill at a speed of 40 m/s A person walking on the street at 2 m/s A ball rolling across the field at 5m/s A leaf falling at 10 m/s
Why can water be used in the cooling system of a car?
provided the amplitude is sufficiently great, the human ear can respond to longitudinal waves over a range of frequencies from about 20.0 hz to about 20.0 khz.
a) The red dots marking the beginning of each complete wave pattern for the long-wavelength sound would be spaced apart by approximately 17.2 meters.
b) The blue dots marking the beginning of each complete wave pattern for the short-wavelength sound would be spaced apart by approximately 1.7 centimeters.
Find the distance between the red dots?To determine the distance between the red dots for long-wavelength sound, we need to find the wavelength corresponding to the lowest frequency of 20.0 Hz.
The speed of sound in air at room temperature is approximately 343 meters per second.
Using the formula v = ƒλ, where v is the speed of sound and ƒ is the frequency, we can rearrange the equation to solve for λ (wavelength). Substituting the given values, we have λ = v / ƒ = 343 m/s / 20.0 Hz ≈ 17.2 meters.
For the blue dots representing short-wavelength sound, we need to find the wavelength corresponding to the highest frequency of 20.0 kHz. Using the same formula, we get λ = v / ƒ = 343 m/s / 20.0 kHz = 0.0172 meters = 1.7 centimeters.
Therefore, the red dots for long-wavelength sound would be spaced approximately 17.2 meters apart, while the blue dots for short-wavelength sound would be spaced approximately 1.7 centimeters apart.
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Complete question here:
Provided the amplitude is sufficiently great, the human ear can respond to longitudinal waves over a range of frequencies from about 20.0 Hz to about 20.0 kHz.
a) If you were to mark the beginning of each complete wave pattern with a red dot for the long-wavelength sound, how far apart would the red dots be?
b) If you were to mark the beginning of each complete wave pattern with a blue dot for the short-wavelength sound, how far apart would the blue dots be?
A block of mass 0.246 kg is placed on top of a light, vertical spring of force constant 5 125 N/m and pushed downward so that the spring is compressed by 0.098 m. After the block is released from rest, it travels upward and then leaves the spring. To what maximum height above the point of release does it rise
The maximum height (h) above the point of release that the block rises is approximately 0.196 meters.
1. Determine the potential energy stored in the compressed spring using Hooke's Law: \(PE_{spring} = 0.5 * k * x^ {2}\), where k is the force constant (5,125 N/m) and x is the compression distance (0.098 m).
PE_spring = 0.5 * 5,125 * (0.098)^{2} \(PE_{spring} = 0.5 * 5,125* (0.098)^2\)
≈ 24.605 Joules
2. When the block leaves the spring, all the potential energy stored in the spring is converted to kinetic energy (KE) of the block: \(KE_{block} \) = \(PE_{spring}\).
3. At the maximum height, the block's kinetic energy is converted into gravitational potential energy
\(PE_{gravity}\) : \(PE_gravity = m * g * h\), where m is the mass of the block (0.246 kg), g is the acceleration due to gravity (9.81 m/s²), and h is the maximum height above the point of release.
4. Equate the kinetic energy of the block to the gravitational potential energy at the maximum height: \(KE_{block}\) = \(PE_{gravity}\).
24.605 J = 0.246 kg * 9.81 m/s² * h
5. Solve for the maximum height (h): h ≈ 0.196 meters.
The block rises to a maximum height of approximately 0.196 meters above the point of release after being released from the compressed spring.
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You are pushing a cart of groceries with a force of 368 N. The mass of the cart is 24 kg. What is the cart’s acceleration?
A. 0 m/s2
B. 15.3 m/s2
C. 8.9 x 103 m/s2
D. 0.7 m/s2
Answer:
B
Explanation: