Answer:
The value is \(f = 0.05 \ Hz\)
Explanation:
From the question we are told that
The mass of the car is \(m = 615 \ kg\)
The period of the circular motion is \(T = 20 \ s\)
The radius is \(r = 80 \ m/s\)
Generally the frequency of the circular motion is
\(f = \frac{1}{T }\)
=> \(f = \frac{1}{ 20 }\)
=> \(f = 0.05 \ Hz\)
How many neutrons are in the nucleus of an atom with an atomic mass of 80 A.M.U. and an atomic number of 35?
Answer:
45
Explanation:
The mass number is 80
Proton number is 35
A-P=n
80-35=45
How is the answer D?
The graph that corresponds to 0.1 s in one complete cycle is graph D.
option D is the correct answer.
What is the period of a wave?The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years.
Also, the period of a wave is the amount of time it takes for a wave to complete one wave cycle or wavelength.
From the given parameter, the coil rotates 10 times in one second. The period of the coil is calculated as;
Period = 1 s / 10
Period = 0.1 s
From the graphs, the only option that has one complete cycle in one second is option D.
Check option D, half cycle is 0.05 s and one full cycle is 0.1 s.
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1. A 1.33-kg physics textbook is initially at rest on a steel table.
The textbook is then pushed with a constant force of 4.0 N.
Friction with a magnitude of 2.0 N is exerted on the moving
book by the surface of the table.
Determine the final velocity of the textbook after it has been
pushed 0.75 meter across the table.
The acceleration of the textbook is a = F/m = 2.0 N/1.33 kg = 1.5 m/s². and the final velocity of the textbook is v = 0 + (1.5 m/s²)(0.75 s) = 1.125 m/s.
What is acceleration?Acceleration is the rate at which an object changes its velocity over time. It is a vector quantity, meaning it has both magnitude and direction. An object's acceleration can be calculated by measuring the change in its velocity over time.
The net force acting on the textbook is the difference between the pushing force of 4.0 N and the frictional force of 2.0 N, which is 2.0 N.
According to Newton's Second Law, this net force of 2.0 N will cause an acceleration of the textbook given by the equation F = ma, where m is the mass of the textbook (1.33 kg) and a is the acceleration.
Therefore, the acceleration of the textbook is a = F/m = 2.0 N/1.33 kg = 1.5 m/s².
The final velocity of the textbook can then be calculated using the equation v = v0 + at, where v0 is the initial velocity (0 m/s, since the textbook was initially at rest), a is the acceleration (1.5 m/s²), and t is the time the textbook was pushed (0.75 m).
Therefore, the final velocity of the textbook is v = 0 + (1.5 m/s²)(0.75 s) = 1.125 m/s.
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4
Students are using an air rocket to investigate the relationship
between force and an object's motion.
Students pump air into the rocket, then release the rocket, and the
compressed air pushes the rocket upward.
A. The length of the hose attached to the pump
B. The distance traveled by the rocket
C. The amount of air pumped into the rocket
D. The height of the rocket from fins to cone
ESS(Earth Space Science)
As scientists took rock samples from the Moon, they determined that these samples were composed of anorthosite, an igneous rock. Knowing how igneous rocks form on Earth, what can you conclude about the Moon’s past geology?
1. There must have been tectonic activity, including active volcanoes, on the Moon.
2. The deep craters on the Moon's surface were created by erosion.
3. These rocks must have been taken to the Moon during the first Moon landing.
4. There is an inactive island chain on the far side of the Moon.
1. There must have been tectonic activity, including active volcanoes, on the Moon.
A significant rock of the lunar highlands is called lunar anorthosite, which developed as a result of plagioclase flotation in the lunar magma ocean (LMO). A key to understanding the early magmatic history of the terrestrial planets is to place restrictions on the necessary circumstances that led to the creation of a thick pure anorthosite (mode of plagioclase >95 volume%). Plagioclase must have separated from the magma ocean with a low crystal percentage in order to produce pure lunar anorthosite.
The worldwide magma ocean and the formation of a hot, youthful Moon are both suggested by the massive impact theory for the genesis of the Moon. A floatation crust made of plagioclase crystals or anorthosite crust might result from such a magma ocean. Because they anticipated interstitial melt would freeze, early predictions of the projected anorthosite concentration of the lunar highlands crust did not match first observations of Apollo samples, and more subsequent calculations have not matched Clementine measurements or SELENE data. We examine a physical model of a magma ocean with an accumulating floatation lid and discover that, even when credible compaction viscosities are taken into account as a potential inhibitor, considerable melt escape is still possible for appropriate physical parameters and melt migration durations.
This model supports data by allowing more nearly pure lunar anorthosites. This suggests that impact mixing and tidal heating are required to account for the disparity. The model has considerable trouble describing the ejection of melt for the near-surface crust (up to five kilometers in depth).
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On that same 30. °C day, you blow the same whistle with a frequency of
3.5x10^4 Hz. What is the wavelength of the sound?
The sound would have a wavelength of about 9.8 * 10^-3 m.
What is the wavelength?The wavelength is a characteristic of a wave that describes the distance between two successive points in the wave that are in phase, or the distance over which the wave's shape repeats. It is typically denoted by the Greek letter lambda (λ) and is measured in meters (m) or other units of length.
Given that the speed of sound in air is 343 m/s
v= λf
λ = v/f
λ = 343 m/s/3.5x10^4 Hz
λ = 9.8 * 10^-3 m
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the answer is b :)
Samples of different materials, A and B, have the same mass, but the sample
of A is higher in density. Which statement could explain why this is so?
A. The particles that make up material B are more closely packed
together than the particles that make up material A.
B. The particles that make up material A have more mass than the
particles that make up material B.
C. The sample of material A has greater volume than the sample of
material B.
D. The particles that make up material B have more mass than the
particles that make up material A.
Answer:
Answer is letter B
Answer: THE CORRECT ANSWER IS : The partiles that make up material B are more closely packed together than the partiles that make up material A
Explanation: I TOOK THE TEST apex
4. Un móvil lleva una velocidad de 75 m/s, en dicho momento aplica los frenos durante tiempo de 15 segundos hasta detenerse. ¿cuál será la aceleración del frenado? ¿cuál es la distancia que recorre hasta detenerse?
Answer:
a = 5 m / s² and x = 562.5 m
Explanation:
Let's apply the kinematics relations
v = v₀ + at
v² = v₀² + 2a x
In this case, as the car stops, its final speed is zero (v = 0) and the acceleration must be opposite to the speed, that is, negative
0 = v₀ - a t
a = v₀ / t
let's calculate
a = 75/15
a = 5 m / s²
let's look for the distance
0 = v₀² - 2a x
x = v₀² / 2a
let's calculate
x = \(\frac{75^2}{2 \ 5 }\)
x = 562.5 m
what is newtons to kg?
Answer:
Below
Explanation:
They are not equivalent. but to find out the mass which weighs Newtons
divide Newtons by 'g ' Newtons/ (9.81 m/s^2) = KG (on earth)
Consider mechanical energy to find the coefficient of friction between the sledge and the ground
Answer:
0.08
Explanation:
We can represent the situation with the following figure
Now, by the conservation of energy, we can write the following equation
\(\begin{gathered} K_i+U_i-Wnc=K_f \\ \frac{1}{2}mv_i^2+mgh-F_fd=\frac{1}{2}mv_f^2 \end{gathered}\)Where m is the mass, vi is the initial velocity, g is the gravity, h is the height, Ff is the force of friction, d is the distance traveled by the sledge, and vf is the final velocity.
Using the free body diagram, we get that the force of friction is equal to
\(\begin{gathered} F_n=mg\sin60 \\ \text{ Then} \\ F_f=\mu F_n \\ F_f=\mu mg\sin60 \end{gathered}\)Now, we can replace the expression for Ff in the equation above and solve for the coefficient of friction μ
\(\begin{gathered} \frac{1}{2}mv_i^2+mgh-(\mu mg\sin60)d=\frac{1}{2}mv_f^2 \\ \\ \frac{1}{2}v_i^2+gh-\mu gd\sin60=\frac{1}{2}v_f^2 \\ \\ \mu gd\sin60=\frac{1}{2}v_i^2+gh-\frac{1}{2}v_f^2 \\ \\ \mu=\frac{1}{gd\sin60}(\frac{1}{2}v_i^2+gh-\frac{1}{2}v_f^2) \\ \end{gathered}\)Replacing g = 9.8 m/s², d = 16 m, vi = 3 m/s, h = 8 m, and vf = 12 m/s, we get
\(\begin{gathered} \mu=\frac{1}{(9.8)(16)\sin60}(\frac{1}{2}(3)^2+(9.8)(8)-\frac{1}{2}(12)^2) \\ \\ \mu=0.08 \end{gathered}\)Therefore, the coefficient of friction is 0.08
A box is being pulled to the right. The free body diagram is shown.What is the magnitude of the kinetic frictional force?
Answer:
A - 0 N
plz mark 5 stars, thanks, and brainliest
P9. Consider the discussion in Section 1.3 of packet switching versus circuit switching in which an example is provided with a 1 Mbps link. Users are generating data at a rate of 100 kbps when busy, but are busy generating data only with probability . Suppose that the 1 Mbps link is prop trans t=0 t= trans prop trans t=dtrans prop trans to trans s=2.5⋅108 L=120 bits R=56 kbps. prop trans p=0.1 replaced by a 1 Gbps link. a. What is N, the maximum number of users that can be supported simultaneously under circuit switching?
Answer:
hello your question is not properly structured below is the complete question
. Consider the discussion in Section 1.3 of packet switching versus circuit switching in which an example is provided with a 1 Mbps link. Users are generating data at a rate of 100 kbps when busy, but are busy generating data only with probability . Suppose that the 1 Mbps link is replaced by a 1 Gbps link. a. What is N, the maximum number of users that can be supported simultaneously under circuit switching?
answer : N = 1000 users
Explanation:
The maximum number of users (n) that can be supported simultaneously under circuit switching
N = Total transmission / rate of data generation by users
Total transmission = 1 Gbps = 1 * 10^9 bps
rate of data generation by user = 100 kbps = 10 * 10^4 bps
hence the maximum number of users that can be supported simultaneously
= ( (1* 10^9) / (10 * 10^4) )
= 10000 users
1. A rocket is fired vertically from the launch pad with a
net accelevation of 20m/s². If the atmosphere is
approximately 100km thick and considering that the
acceleration is constant....
a) what is the time it takes for the rocket to leave the
atmosphere?
b) What speed does the rocket reach at that time?
Answer:
Max height= 36000 meters
Total Time = 120 seconds
Explanation:
0 = U - at
U = at
U= 20*60
U= 1200 m/s
MAX altitude would be
(U²Sin²tita)/2g
Max height= 1200² *( SIN90)²/(2*20)
Time of FLIGHT
2 * 1200/20
2400/20
120 sec onds
Which of the following statement/s is/are true? Check all that apply. Jupiter's Great Red Spot is in the southern hemisphere of the planet The fastest wind speed recorded in our solar system is on the dwarf planet Pluto Neptune's Great dark spot is in the northern hemisphere of the planet Water geyser is located on the South Pole of Saturn's Moon Enceladus The Hexagon hurricane is on the North Pole of the planet Uranus
The true statements are:Jupiter's Great Red Spot is in the southern hemisphere.The fastest wind speed recorded in our solar system is on Neptune.
Among the given statements, only two are true. Jupiter's Great Red Spot, a massive storm, is indeed located in the southern hemisphere of the planet. The Great Red Spot is a prominent feature on Jupiter, visible as a giant swirling storm system. On the other hand, the fastest wind speed recorded in our solar system, reaching speeds of up to 2,100 kilometers per hour (1,300 miles per hour), is found on Neptune.
The strong winds on Neptune contribute to its dynamic atmosphere and the formation of features like the Great Dark Spot. The remaining statements about Pluto, Saturn's moon Enceladus, and Uranus are not true according to our current understanding.
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When electrons are lost, a ( )
ion is formed.
When electrons are
gained, a ( )
ion is formed.
When electrons are lost a positive ion is formed. When electrons are gained, a negative ion is formed. I hope this helps
The muscles in the human body that are connected to bones and aid in the movement of the.
The muscles in the human body which connect to bones and aid in the movement are called the skeletal muscles.
Skeletal muscle, also called voluntary muscle, is the most common of the three muscle types found in vertebrates. Skeletal muscles are attached to bones by tendons and generate all movements of body parts in relation to each other. Skeletal muscle makes up 30-40% of the body. They are muscles that connect to bones and allow them to perform various movements and functions. Skeletal muscles are voluntary. This means you can control when and how it works. Two muscles, flexors, and extensors are involved in bone movement.
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- Approximately what are the coordinates of the Hawaii Hot
Spot?
(1) 50 N, 120 W
(3) 25 N, 158 W
(2) 25 N, 158 €
(4) 25 S, 158 E
Answer: (3) 25°N, 158°W
Explanation:
The Hawaii Hotspot is one of the most popular on the planet and is the reason the Hawaii islands were created as it created volcanoes under the Hawaii islands that erupted as the Pacific plate moved over them and then the lava cooled thereby forming the different Hawaii islands.
The approximate location of the hotspot is 25°N, 158°W in the pacific ocean.
Use this formula m=W/g, What is the mass of an object if its weight on earth is 1150N?
Using this formula m=W/g, the mass of an object if its weight on earth is 1150N is 117.347 kg
Let mass of an object be m, weight be W and acceleration due to gravity is g.
From the formula m=W/g
mass m =?
weight w = 1150N
g=9.8 m/\(s^{2}\)
So, the mass of an object if its weight on earth is 1150N will be calculated as:
m=1150/9.8
m=117.347 kg
Hence using the formula m=W/g, the mass of an object if its weight on earth is 1150N will be 117.347 kg.
This is in acceptance with Newton's laws of motion as well and thus calculated according to given formula.
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Wrich of the following statements is cerrect? They both experience the same force. The force enperienced by the sister is less than the force experienced by Ton. The fecce experienced by Tom is less than the force experienced by his sister, (b) which of the folisning statements is correct? Teais acceleration in less than the sistee's accrieration: Tomis acceleration is more than the swier's acceieration. They both have the same acceleration. (c) If the wivter's accelerabian is 3.0 m
s
2
in magnitast, what is the magntude of Tomis accetention? msc
2
a = 150 / ma is the magnitude of Tom's acceleration. So, the answer is m/s²
(a) The force experienced by the sister is less than the force experienced by Tom.
(b) Tom's acceleration is more than the sister's acceleration. They both have the same force and different acceleration. (c)Given that:Water skier's acceleration = 3.0 m/s²
Acceleration is defined as the rate at which the velocity of an object changes with time. Acceleration = Change in velocity / Time
Therefore, if Tom's acceleration is "a," we can find it using the following formula:Force = Mass × Accelerationa = F / m
We are given that the force experienced by Tom is 150 N.
Also, Tom's mass is not given, but we can assume it to be "m." Therefore,a = 150 / ma is the magnitude of Tom's acceleration. So, the answer is m/s².
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Types of Spectra 5) Stars like our Sun have low-density, gaseous atmospheres surrounding their hot, dense cores. If you were looking at the spectra of light coming from the Sun (or any star), which of the three types of spectrum would be observed? Explain your reasoning.
The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.
In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.
The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.
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A current of 5 A passes through a variable resistor set to 15 Ω. Calculate the voltage
Answer:
75 volt
Explanation:
Current (I) = 5 A
Resistance (R) = 15 Ω
Voltage (V) = ?
We know
R = V/I
15 = v / 5
v = 75 Volt
what is the definition of energy in scientific terms?responses a force used on an object a force used on an object a change in temperature a change in temperature the motion of an object the motion of an object the ability to do work
Answer: The ability to do work.
Explanation: Scientists define energy as the ability to do work. There is potential energy (where an object at rest has the capacity to have motion) and kinetic energy (where an object is in motion).
since the moon cooled sooner than the earth, it is reasonable to assume that it no longer has a molten metal core. if that is the case, what conclusion would you draw about the magnetic fields around the moon?
The conclusion that could be drawn about the magnetic fields around the moon is that "the moon no longer has a magnetic field."
What causes magnetic fields around celestial objects?Planets like Earth that have a liquid metal outer core produce magnetic fields. It's said that the planet's rotation causes the magnetic field. When the planet spins, the molten metal in the core moves, producing an electric current. As a result of the moving electric current, a magnetic field is formed around the planet.
Moons that do not have a molten metal core cannot produce magnetic fields. The moon's magnetic field is significantly weaker than Earth's magnetic field. The surface of the moon is scorched by the sun's radiation due to the absence of a magnetic field. So, the conclusion that can be drawn about the magnetic fields around the moon is that the moon no longer has a magnetic field.
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QUESTION 11 What is the phase of the moon when the moon is on the opposite side of the earth from the sun? a. The full moon. b. The new moon The crescent moon d. The gibbous moon. e. The quarter moon.
The phase of the moon when the moon is on the opposite side of the earth from the sun is the full moon. This happens when the sun, earth, and moon are aligned, with the earth in the middle.
The full moon appears when the sun’s light reflects off the entire surface of the moon, making it appear completely illuminated from our perspective on earth.Therefore, option A is the correct answer: The full moon.
When the moon is on the opposite side of the Earth from the sun, it is in the full moon phase. During this phase, the sun illuminates the entire side of the moon facing the Earth, making it appear fully lit and round. This occurs because the sun, Earth, and moon are aligned in a straight line, with the Earth in the middle. The full moon phase is characterized by a bright, round shape and is often considered the most visually striking lunar phase. It occurs approximately once every 29.5 days as the moon orbits around the Earth.
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F = 1400 kg x 2 m/s/s
Answer:
F = 2800 kg*m /s^2
Or F = 2800 N
A puck is sliding on the ice with 25 J of kinetic energy. After 3 seconds, the puck comes to a stop and has no more kinetic energy. Find the work done on the puck.
The work done on the puck is -25 J, after 3 seconds, the puck comes to a stop and has no more kinetic energy.
What is work done?Work done is described as the amount of force needed to move an object a certain distance.
The work-energy principle states that the work done on an object is equal to the change in its kinetic energy.
The change in kinetic energy is:
ΔK = Kf - Ki = 0 - 25 = -25 J
Note that the negative sign indicates that the kinetic energy of the puck decreased.
W = ΔK = -25 J
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A video surveillance camera is used to determine the speed of cars entering a tunnel. Assuming that the road is flat and that the lane markings are clearly visible, describe how the image position of a car can be used to estimate its position in the lane, and how this information can then be processed to give an estimate of the cars speed. State clearly any assumptions made.
By analyzing the change in a car's position on a video surveillance camera image between frames, its displacement can be estimated, allowing for the calculation of its position in the lane and speed, assuming clear lane markings and a constant distance from the camera.
The position of a car can be estimated in a lane with the help of a video surveillance camera. When a car moves from one frame of a video to the next, the change in the position of the car on the camera image is proportional to its actual displacement, which can be used to estimate its position in the lane. The image position of a car can be used to estimate its position in the lane with the following process:
When a car enters the field of view of the camera, its position on the camera image is identified. The position of the car in the next frame is then identified. The change in the position of the car in the image between the two frames is proportional to the car's actual displacement. The distance of the car from the lane marking can be estimated from the position of the car in the image. The center of the car is assumed to be at an equal distance from the two lane markings. The distance of the car from the camera can be assumed to be constant to get an estimate of the car's speed.
The process to calculate the speed of the car is given below:
Distance of the car from the lane marking is calculated.The displacement of the car in the image is determined.The distance between the car and the camera is assumed to be constant, and this distance is determined.The time difference between the two frames of the video is determined.The speed of the car is calculated by dividing the displacement by the time difference.The assumptions made in this estimation process are that the road is flat and that the lane markings are clearly visible.To know more about displacement, refer to the link below:
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4. what is the predicted resistance for a resistor that has the color bands yellow, red, blue, gold, in that order?
Answer:
Check something like "Radio Amateurs Handbook" for table
position 1 - Yellow - 4 first significant figure
position 2 - Red - 2 second significant figure
position 3 - Blue - 1 megohm multiplier
position 4 - gold tolerance
The resistor is 42 megohms with a tolerance of 5%
The predicted resistance of a resistor with yellow, red, blue, and gold color bands in that order is 42 megaohms +/- 5%.
Resistors are electronic components used in circuits to limit the flow of current. They come in different shapes, sizes, and values, and their values are usually indicated by color-coded bands. In this question, we are asked to determine the predicted resistance of a resistor with yellow, red, blue, and gold color bands in that order.
To determine the predicted resistance of a resistor, we need to decode the color bands and use a resistor color code chart. The color bands on the resistor are read from left to right, starting with the band closest to the end that has a wider separation between the color bands.
In this case, the first band is yellow, which represents the digit 4. The second band is red, which represents the digit 2. The third band is blue, which represents the multiplier 10^6. The fourth band is gold, which represents the tolerance of the resistor.
Using these values, we can calculate the predicted resistance of the resistor. The first two digits (4 and 2) represent the significant figures, which are 42. The third digit (blue) represents the multiplier, which is 10^6. Therefore, the resistance of the resistor is:
R = 42 x 10^6 Ω
We can also determine the tolerance of the resistor from the fourth gold band. Gold represents a tolerance of +/- 5%, which means that the actual resistance of the resistor can be within 5% of the predicted resistance.
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A boat travels at 15 m/s in a direction 45° east of north for an hour. The boat then turns and travels at 18 m/s in a direction 5° north of east for an hour.
What is the magnitude of the boat’s resultant velocity? Round your answer to the nearest whole number.
Answer:
16 m/s
Explanation:
First, find the displacement in the east direction.
x = (15 m/s sin 45°) (3600 s) + (18 m/s cos 5°) (3600 s)
x = 102,737 m
Next, find the displacement in the north direction.
y = (15 m/s cos 45°) (3600 s) + (18 m/s sin 5°) (3600 s)
y = 43,831 m
Find the magnitude of the displacement.
d = √(x² + y²)
d = √((102,737 m)² + (43,831 m)²)
d = 111,697 m
Finally, find the resultant velocity.
v = d / t
v = (111,697 m) / (7200 s)
v = 15.5 m/s
Rounded to the nearest whole number, the resultant velocity is 16 m/s.
Predict what happens to the mechanical advantage of a machine if friction is reduced through the use of oil or some other means.
A big machine is composed of several moving and stationary parts. Some of these parts are in a state of constant motion hence they periodically rub against each other.
Explain about mechanical advantage:The Mechanical Advantage (MA) of a machine is the ratio between the output force produced by the machine divided by the input force exerted on it:The MA is generally a number larger than 1, since machines are used to "multiply" the force applied.There are actually 2 values of the mechanical advantage for a machine:The Ideal Mechanical Advantage (IMA), which is the MA when there are no frictional force acting on the machine, and so when all the work done in input is transferred as energy in output The Actual Mechanical Advantage (AMA), which is the MA when taking into account the frictional forces, which cause a dissipation of part of the energy; so, not all the work done in input is transferred as energy in outputThe efficiency of a machine is defined as the ratio between the two:A machine cannot have an efficiency of 100% because there are always some frictional/resistive forces acting on the system, so part of the energy in input is always dissipated, and therefore AMA < IMA, and so the efficiency is not 100%.As we know that friction force is the resistive force due to relative motion of two surface. When one surface is moving relative to other surface then the motion is resisted by the interaction force between two surface which is known as friction force.To learn more about mechanical advantage refer to:
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