A 60-kilogram individual ascends an 80 m-high building's roof by walking up from the ground. Once at the peak, the human has a potential energy of 44027.28 J.
This is our formula
Gravitational ability strength = mgh
here (GPE = mgh)
mg = 60.0 kg
h = 80
mg = 60.0 kg
in view that we're searching for pressure and the SI Unit for force is "N," we must convert this to force (N).
consequently, we will multiply 60.0 via nine.81.
60.0 × 9.81 = 588.6
Now that will be
⇒ mg = 588.6 N
⇒ h = 80
GPE = (588.6) × (80) = 47088 J
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A ‘can-chiller’ is used to make a can of drink colder. The initial temperature of the liquid in the can was 25.0 °C. The can-chiller decreased the temperature of the liquid to 20.0 °C. The amount of energy transferred from the liquid was 6930 J. The mass of liquid in the can was 0.330 kg.
Calculate the specific heat capacity of the liquid. Give the unit.
Please help :)
Answer:
4200 J/°C/kg
Explanation:
The formula for heat transfer is given by :
Q= m*c*ΔT where;
Q= heat transferred = 6930 J
m=mass of the liquid = 0.330 kg
c= specific heat capacity=?
ΔT = 25-20 = 5.0°C
Applying the values in the formula as;
Q= m*c*ΔT
6930 = 0.330 * c * 5
6930 = 1.65 c
6930/1.65 = c
4200 = c
c= 4200 J/°C/kg
After 42 days the activity of a sample of phosphorus-32 has decreased from 400 Bq to 50 Bq what is the half life of phosphorus-32
The half-life of phosphorus-32 is approximately 52.78 days. The half-life of a radioactive isotope is the time it takes for the amount of the isotope to decrease by half. It is given by the formula:
t1/2 = ln(2) / lambda
where t1/2 is the half-life, ln(2) is the natural logarithm of 2, and lambda is the decay constant.
We can use the given values to find the decay constant:
ln(2) = 0.69314718056
lambda = ln(2) / 0.69314718056 = 0.91773272786
We can then use the decay constant to find the half-life:
t1/2 = ln(2) / lambda = 0.69314718056 / 0.91773272786 = 0.78671274328
t1/2 = 42 days / 0.78671274328 = 52.78 days
Therefore, the half-life of phosphorus-32 is approximately 52.78 days.
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6. Find the acceleration of a 25kg crate man pushing it with 45N force?
Answer:
1.8m/s2
Explanation:
force=mass x acceleration
so,
acceleration=force /mass
=45/25
=1.8
Required information A grating is made of exactly 8000 slits; the slit spacing is 1.50 um. Light of wavelength 0.600 um is incident normally on the grating. What is the distance on the screen between the first-order maxima and the central maximum that appear on a screen 3.40 m from the grating??
On a screen 3.40 m from the grating, the distance between the first-order maxima and the centre maximum is 1.31 metres.
How do you gauge the separation of gratings?This may be expressed by the equation d = 1/N, where N is the number of groves per unit length (in this case, millimetres). The above graphic shows that "d" stands for the grating spacing and "" for the angle of diffraction.
Since m = 1 is the first-order maximum, we may write: d sin = m sin = /d.
θ = sin^-1(λ/d)
θ = sin^-1(0.600 μm / 1.50 μm) = 23.58°
As a result, the first-order maximum is located at y1 = Ltan = (3.40 m) tan(23.58°) = 1.31 m.
"y0 = 0" "y = y1" "0 = 1.31 m
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How to integrate 1/ 1 + x2
The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.
Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.
Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:
∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du
The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.
Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.
Let us work through the steps:
Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x
Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du
Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.
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25. A cup contains 177.44 ml. of chocolate milk. How many gallons of chocolate milk does it hold?
(Given: 1 ml. 0.001 L; 1 gal = 3.78 L.)
Answer:
0.0469 gal
Explanation:
177.49 ml is 0.17749 L.
So, 0.17749/3.78 gives the answer
The answer is 0.0469 gallons of chocolate milk a cup can hold which contains 177.44 ml of chocolate milk.
A liquid volume measurement that is equivalent to 231 cubic inches or four quarts is known as Gallon.
To calculate gallons of chocolate milk a cup can hold:
Given,
1 ml = 0.001 L
1 gal = 3.78 L
Convert 177.44 ml to liters:
1 Liter = 1000 ml
177.44 ml * 0.001 L/ml = 0.17744 L
Convert liters (L) to gallons (gal):
= 0.17744 L / 3.78 L/gal
= 0.0469 gal
Thus, a cup that contains 177.44 ml. of chocolate milk holds 0.0469 gal.
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Which of the following substances is the closest to a neutral pH? O A. milk
Answer:
The answer is water
Explanation:
it has a netural ph of 7.0
why is the only option milk?
The Ph for milk is about 6.5 to 6.7, it varies becauses milks gets sour when it rots.
got the ans thanks neede coz i had doubt but got clarified
Answer:
i. 170 m
ii. 850 m
Explanation:
Question
Arjun and his son Arav were standing ‘x’ m away from each other. They are equidistant (Y m) from a vertical cliff. Arjun burst a balloon and Arav heard the direct sound 0.5 seconds later and the echo after 2 seconds. If the speed of sound in air is 340m/s ,calculate
i. the distance between Arjun and Arav
ii. the distance between the cliff and Arjun
The parameters given are;
The time for the sound to reach Arav, \(t_D\) = 0.5 s
Time for the echo to echo to reach Arav, \(t_E\) = 2 s
The distance between Arjun and Arav = \(D_D\)
The distance between Arav and the cliff = \(D_E\)
The speed of sound in air, s = 340 m/s
The formula for speed, s, is \(s = \dfrac{Distance, D}{Time, t}\), therefore;
\(s = \dfrac{D_D}{t_D} = \dfrac{D_D}{0.5} = 340\)
\(D_D\) = 0.5 s × 340 m/s = 170 m
The distance between Arjun and Arav = 170 m
ii. Since Arav hears the direct sound before the echo, he is closer to the cliff than Arjun, therefore, we have;
\(s = \dfrac{D_E}{t_E} = \dfrac{D_E}{2} = 340\)
\(D_E\) = 2 s × 340 m/s = 680 m
Therefore, the distance between Arav and the cliff = 680 m
Which gives the distance between the cliff and Arjun, \(D_{cliff}\) = The distance between Arav and the cliff + The distance between Arjun and Arav
\(D_{cliff}\) = 680 + 170 = 850 m.
an object travels 8 m in the 1st second of travel, 8 m again during the 2nd second of travel, and 8 m again during the 3rd second. its acceleration is
Based on the information provided, we can determine that the object's acceleration is constant and equal to zero.
This is because the object is traveling the same distance in each second, indicating that its speed is constant. Acceleration is defined as the rate at which an object changes its velocity, and since the velocity of the object is not changing (it's constant), its acceleration is zero.
It's important to note that even though the object's acceleration is zero, it is still moving. This is because acceleration is only one aspect of an object's motion, and velocity and displacement are also important factors to consider. In this case, the object's displacement (total distance traveled) is 24 meters, and its velocity is constant.
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A man with mass m1 = 51 kg stands at the left end of a uniform boat with mass m2 = 168 kg and a length L = 3.3 m. Let the origin of our coordinate system be the man’s original location as shown in the drawing. Assume there is no friction or drag between the boat and water.
What is the location of the center of mass of the system? (1.26m)
If the man now walks to the right edge of the boat, what is the location of the center of mass of the system? (1.26m)
After walking to the right edge of the boat, how far has the man moved from his original location? (What is his new location?) (2.53m)
After the man walks to the right edge of the boat, what is the new location the center of the boat?
Now the man walks to the very center of the boat. At what location does the man end up?
(a) The center of mass of the system is 1.26 m.
(b) If the man walks to the right edge of the boat, the center of mass of the system is unchanged, 1.26 m.
(c) After walking to the right edge of the boat, the man has moved 2.53 m from his original location.
(d) After walking to the right edge of the boat, the new location center of the boat is 0.88 m.
(e) The man ends up at 1.26 m.
Man on a boatA man stands at the left end of a uniform boat. The coordinate system is the man's original location as shown in the picture and we assume that there is no friction or drag between the boat and water. The picture is in the attachment.
Mass of a man, m₁ = 51 kgMass of the boat, m₂ = 168 kgLength of the boat, L = 3.3 mThe man's location is at x₁ = 0.
The center of the boat is at x₂ = L/2 = 1.65 m.
(a) The center of mass of the system would be
x₀ = (m₁x₁ + m₂x₂)/(m₁ + m₂)
x₀ = [51(0) + 168(1.65)]/(51 + 168)
x₀ = 277.2/219
x₀ = 1.26 m
(b) If the man walks to the right edge of the boat, the center of mass of the system would remain the same. This is because there is no friction between the boat and water. So, it would be 1.26 m.
(c) After walking to the right edge of the boat, the illustration of the man's location is shown in the attachment!
x₂ = x₁ - 1.65
The man's location (x₁) is at
x₀ = (m₁x₁ + m₂x₂)/(m₁+m₂)
1.26 = (51x₁ + 168(x₁ - 1.65)/(51+168)
1.26 = (51x₁ + 168x₁ - 277.2)/219
275.94 = 219x₁ - 277.2
553.14 = 219x₁
x₁ = 2.53 m
(d) The new location of the center of the boat is
x₂ = x₁ - 1.65
x₂ = 2.53 - 1.65
x₂ = 0.88 m
(e) If he walks to the very center of the boat, he would end up at the center of mass of system, at 1.26 m. The center of mass is unchanged as explained in point b.
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How far did a crane lift a 65,000 N beam using 2,340,000J of work ?
Answer:
Distance = 36 meters
Explanation:
Given the following data;
Work done = 2,340,000 Joules
Force = 65,000 Newton
To find the distance covered by the crane;
Mathematically, work done is given by the formula;
\( Workdone = force * distance\)
Substituting into the formula, we have;
\( 2340000 = 65000 * distance \)
\( Distance = \frac{2340000}{65000}\)
Distance = 36 meters
all free fall equations
A falling object's velocity is given by the formula v = gt, while its displacement is given by d = (1/2). gt2, the final velocity of a falling item from a given height v² = 2gh, A falling object's time of flight is given by the formula t = ((2h/g)).
What is the equation for free fall?According to Newton's second law, F = ma, the force acting on a body is equal to the mass m times the acceleration an of its centre of mass.
Is the equation for free fall quadratic?All things are pulled towards the earth at a constant acceleration. According to this physics rule, the height of every free-falling item can be represented by a quadratic function.
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define balanced force
Answer:
two forces are acting on an object but both forces are equal making the object still
Explanation:
Answer:
When two forces acting on an object are equal in size but act in opposite directions, we say that they are balanced forces . If the forces on an object are balanced (or if there are no forces acting on it), this is what happens: ... a moving object continues to move at the same speed and in the same direction.
Explanation:
Which accurately explains concave and convex lenses?
a - With both concave and convex lenses, placement of the object dictates which side of the lense the image will appear.
b - With both concave and convex lenses, placement of the object does not dictate which side of the lense the image will appear.
c - With concave lenses, placement of the object does not dictate which side of the lense the image will appear, but with convex lenses, they do.
d- With convex lenses, placement of the object does not dictate which side of the lense the image will appear, but with concave lenses, they do.
Answer:
c
Explanation:
on edg
two objects have a 1d head-on collision. object one has a mass m and velocity 2v to the right while object two has mass 4m and velocity v to the left. the final velocity of object two is v/5 to the right. let the right be the positive direction. determine the final velocity of object one and identify the type of collision.
The final velocity of object one is 2v/5 to the right, and the collision is an elastic collision.
What are the final velocities of the objects in the head-on collision with different masses?In a head-on collision between two objects, object one has a mass of "m" and an initial velocity of "2v" to the right, while object two has a mass of "4m" and an initial velocity of "v" to the left. We are given that the final velocity of object two is "v/5" to the right.
To determine the final velocity of object one, we can apply the law of conservation of momentum.
In a collision, the total momentum before the collision is equal to the total momentum after the collision, provided no external forces are acting on the system. The momentum is given by the product of mass and velocity.
Initially, the total momentum is given by (2m)(2v) - (4m)(v) since object one is moving to the right and object two is moving to the left. This simplifies to 4mv - 4mv = 0.
After the collision, the total momentum is given by (2m)(v1) + (4m)(v2/5), where v1 and v2 are the final velocities of object one and object two, respectively.
Applying the law of conservation of momentum, we have:
0 = (2m)(v1) + (4m)(v2/5)
0 = 2mv1 + (4m)(v/5)
0 = 2mv1 + 4mv/5
0 = 10mv1 + 4mv
0 = 14mv1 + 4mv
To solve for v1, we isolate it on one side of the equation:
-4mv = 14mv1
v1 = -4mv / 14m
v1 = 2v/5
Therefore, the final velocity of object one is 2v/5 to the right. The collision between the two objects is an elastic collision since both momentum and kinetic energy are conserved.
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A loaded spring launches a 2.50 kg block, using a force of 450 N. If the change in
momentum is 12.0 kg*m/s, how long was the block in contact with the spring?
Answer:
37.5 seconds
Explanation:
The given parameters are;
The mass of the block on the spring, m = 2.50 kg
The force with which the loaded spring launches the block, F = 450 N
The change in momentum of the block, Δp = 12.0 kg·m/s
We have;
Let the force with which the block was launched = The net force, \(F_{NET}\)
By Newton's second law of motion, we have;
F = \(F_{NET}\) = Δp × Δt
Where;
Δt = The time the block is in contact with the spring
Therefore;
\(\Delta t = \dfrac{F_{NET}}{\Delta p}\)
By plugging in the values for \(F_{NET}\) and Δp, we have;
\(\Delta t = \dfrac{450 \ N}{12.0 \ kg \cdot m/s} = 37.5 \ s\)
The time duration the block is in contact with the spring, Δt = 37.5 seconds.
5 uses of capillarity in daily life.
Answer: 1. As pen nib is split at the tip to provide the narrow capillary and the ink is drawn upto the point continuously.
2. In oil lamps, the oil is drawn up through the capillary of the wick.
3. Clay soils are damped as the water rises quickly to the surface through the capillaries.
4. Water and minerals rise in the plants through the fine capillaries.
5. Blotting paper absorbs ink through the pores.
a capacitor in an rc circuit is initially fully charged to a voltage of 12 v. it is then discharged through a resistor with a resistance of 100 . after 5 seconds, the voltage across the capacitor has decreased to 4 v. what is the time constant r of the circuit?
The time constant R of the circuit is calculated to be approximately 14.43 s. The time constant R of the circuit can be calculated as follows; \(V(t) = V(0) * e^(-t / R)\) .
We are given that :A capacitor in an RC circuit is initially fully charged to a voltage of 12 V.A capacitor is then discharged through a resistor with a resistance of 100 Ω.After 5 seconds, the voltage across the capacitor has decreased to 4 V.
The time constant R of the circuit can be calculated as follows; \(V(t) = V(0) * e^(-t / R)\) Where, V(0) = 12 V (the initial voltage across the capacitor)V(t) = 4 V (the voltage across the capacitor after 5 seconds)t = 5 sec And, R = time constant
Therefore, substituting the given values in the above formula;
\(4 V = 12 V * e^(-5 / R)\)
Dividing both sides of the equation by 12 V, we get; \(e^(-5 / R) = (1/3)\)
Take natural logarithm (ln) of both sides of the equation to eliminate e from the equation;
-5 / R = ln(1/3)
Multiplying both sides by R, we get; R * (-5 / R)
= R * ln(1/3)-5
= R * ln(1/3)
Dividing both sides by ln(1/3), we get; R = -5 / ln(1/3)
Therefore, the time constant R of the circuit is approximately 14.43 s.
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11. (a) Priya connects an electrical circuit. Ø What type of circuit is shown in the diagram? Circle the correct answer. Walls parallel circuit with closed switch series circuit with closed switch parallel circuit with open switch parallel and series circuit with open switch series circuit with open switch
Answer:
parallel circuit with switch closed
Explanation:
The two circles with X's ( the load) are wired side-by-side ...in parallel.
The switch ( between the two dots at the top) is CLOSED
A child attempts to move a 90.01 kilogram refrigerator in order to retrieve a rubber
ball from behind it. If she is able to slide the refrigerator across the floor with 55
Newtons of force (ignoring friction), what would be its acceleration?
Answer:
\(a=0.611\ m/s^2\)
Explanation:
Given that,
Mass of a refrigerator, m = 90.01 kg
She is able to slide the refrigerator across the floor with 55 N of force.
We need to find the acceleration of the refrigerator.
Let it is a. Using second law of motion:
F = ma
\(a=\dfrac{F}{m}\\\\a=\dfrac{55\ N}{90.01\ kg}\\\\a=0.611\ m/s^2\)
So, its acceleration is \(0.611\ m/s^2\).
The slope of a straight line displacement - time graph indicates
Answer: velocity
Explanation:
Your slope is calculated as \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}} =\frac{displacement}{time}\), which equals velocity.
A dog chases a skateboarder travelling at 10.4\,\dfrac{\text{m}}{\text{s}}10.4 sm 10, point, 4, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. The skateboarder speeds up with a constant acceleration for 39\,\text{m}39m39, start text, m, end text over 3.3\,\text{s}3.3s3, point, 3, start text, s, end text. We want to find the acceleration of the skateboarder over the 3.3\,\text{s}3.3s3, point, 3, start text, s, end text time interval
Answer:Δx=v0t + 1/2 at 2
PLEASE ANYONE CAN HELP ME !E.x/A block of metal has a volume of 0.09 m3
Calculate the buoyant force when it's Completely
immersed in brine ? density = 1200 kg/m3
Answer:
B = 1058.4 N
Explanation:
Given that,
The volume of a metal block, V = 0.09 m³
The density of fluid, d = 1200 kg/m³
We need to find the buoyant force when it's Completely immersed in brine. The formula for the buoyant force is given by :
\(B=\rho gV\)
g is acceleration due to gravity
\(B=1200\times 9.8\times 0.09\\\\B=1058.4\ N\)
So, the required buoyant force is 1058.4 N.
A loop of a wire has the shape shown in the drawing. The top part of the wire is bent into a semicircle of radius r= 0.24 m. The normal to the plane of the loop is parallel to a constant magnetic field of magnitude 0.77 T. What is the magnitude of the change in the magnetic flux that passes through the loop when, starting with the position shown in the drawing, the semicircle is rotated through quarter of a revolution? x 27867 Wb X .27867 Wb B (into paper)
The magnitude of the change in the magnetic flux that passes through the loop when the semicircle is rotated through a quarter of a revolution is 0.27867 Wb.
The induced electromotive force (emf) in a coil is proportional to the rate of change of magnetic flux through it. This is also known as Faraday's law of electromagnetic induction.
The formula for magnetic flux is given by
Φ = BANcosθ
Where,
Φ = magnetic fluxB = magnetic field strengthA = area of the loopN = number of turnscosθ = angle between the magnetic field and the normal to the plane of the loopIf the angle between the magnetic field and the normal plane of the loop is 0°, the maximum magnetic flux is achieved. If the angle is 90°, the flux is zero.
The area of the loop is given by
A = πr²
Therefore, the magnetic flux through the semicircular part of the loop is
Φ = (0.77)(πr²)cos0°
= (0.77)(π × 0.24²)
= 0.13636 Wb
When the semicircle is rotated through a quarter of a revolution, the angle changes from 0° to 90°. Therefore, the magnetic flux becomes zero. Hence, the change in the magnetic flux is given by
0 - 0.13636 = -0.13636
Wb = -136.36 m
Wb = -0.13636 × 10⁻³
Wb= -0.13636 mV
Therefore, the magnitude of the change in the magnetic flux that passes through the loop when the semicircle is rotated through a quarter of a revolution is 0.27867 Wb.
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IS IT CORRECT I'LL MARK U BRAINLIST !!!
Answer:
Volume is to be calculated by L×H×W
Given:
Lenght=5.35
Width= 3.80
Height= 3.25
Therefore,
Volume=5.35×3.80×3.25
⇒66.0725 [this can be estimated to 6.1 as there is only minute gap betwen 66.0725&66.1]
⇒So from the given options we can use 66.1 as the asnwer u need to choose
in a grocery store, you push a 15.5 kg shopping cart, such that it feels a horizontal net force of 14.0 n. if the cart starts at rest, how far does it move in 3.00 s?
The shopping cart moves a distance of 4.57 meters in 3.00 seconds.
Using Newton's second law, which relates force, mass, and acceleration we can solve this problem
F = ma
where F is the net force acting on the object, m is its mass, and a is its acceleration.
In the given problem, the net force acting on the shopping cart is 14.0 N, and its mass is 15.5 kg. We can rearrange the equation above to solve for the acceleration of the cart:
a = F/m
a = 14.0 N / 15.5 kg
a = 0.9032 \(m/s^2\)
Now we can use the kinematic equation that relates distance, acceleration, and time:
d = 1/2 * a * \(t^2\)
where d is the distance traveled, a is the acceleration, and t is the time.
Plugging in the values we have:
d = 1/2 * 0.9032 \(m/s^2\) * \((3.00 s)^2\)
d = 4.57 meters
Therefore, the shopping cart moves a distance of 4.57 meters in 3.00 seconds.
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A 1100-kg car moving on a horizontal surface has speed v = 65 km/h when it strikes a horizontal coiled spring and is brought to rest in a distance of 3.1 m . What is the spring stiffness constant of the spring?
The spring stiffness constant of the coiled spring is 22955.91 N/m.
How we calculated spring stiffness?The conservation of energy to determine the spring stiffness constant.
Initially, the car has kinetic energy equal to:
K1 = (1/2) × m × v²
where m is the mass of the car and v is its speed. When the car is brought to rest by the spring, its kinetic energy is converted into elastic potential energy stored in the spring.
The elastic potential energy stored in a spring is given by:
U = (1/2) × k × x²
where k is the spring stiffness constant and x is the displacement of the spring from its equilibrium position.
At the maximum compression of the spring, the car comes to a stop, so all of the initial kinetic energy is stored as elastic potential energy:
K1 = U
Substituting the expressions for K1 and U and solving for k, we get:
k = 2 × K1 / x²
where x is the maximum compression of the spring. We are given the initial speed of the car, v = 65 km/h, which is equal to:
v = 65 km/h × (1000 m/km) / (3600 s/h) = 18.06 m/s
We are also given the distance the car comes to rest, x = 3.1 m. Substituting these values and solving for k, we get:
k = 2 × (1/2) × m × v² / x²
= m × v² / x²
= 1100 kg× (18.06 m/s)² / (3.1 m)²
= 22955.91 N/m
Therefore, the spring stiffness constant of the coiled spring is 22955.91 N/m.
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We can determine the
of a wave when given the frequency and the wavelength.
• amplitude
• velocity
•equilibrium
•crest
We can determine the velocity of a wave when given the frequency and the wavelength.
What are the effects of wavelength on velocity?
The velocity of the wave is said to be obtained by multiplying the wavelength by the wave's frequency for any wave. The wave velocity formula mathematically provided this formula. An increase in frequency will result in an increase in the wave's velocity for a constant wavelength.
How does wavelength change affect velocity?
The wave's velocity doesn't change. Therefore, the wave's new wavelength is half of its previous one. Consequently, a wave's wavelength shrank as its frequency rose.
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A surface has a work function 1. 70 ev and has light of wavelength 400 nm shone on it. What is the kinetic energy of the photoelectrons emitted?.
The kinetic energy of the photoelectrons emitted is calculated as 2.23 *10^-19 J .
What is meant by photoelectron?Photoelectrons are the electrons which are produced when energetic photon of radiation strikes a molecule. Photoelectron is an electron ejected from atom, molecule, or solid by an incident photon.
In terms of behavior and properties, photoelectrons are no different from other electrons.
E= h c/λ
= 6.6 *10^-34 * 3 * 10^8/400 * 10^-9
= 4.95 *10^-19 J
Work function = 1.7 eV= 1.7 * 1.6 *10^-19
= 2.72 *10^-19 J
Hence, kinetic energy of photo electrons emitted will be;
= 4.95 *10^-19 J - 2.72 *10^-19 J
kinetic energy = 2.23 *10^-19 J
To know more about photoelectrons, refer
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EZ POINTS
20. An object's kinetic energy is a combination of its: A. mass and weight B. distance and direction C. mass and velocity D. volume and direction
Answer:
A.
Explanation:
B,C,D is not right because those do not pay a factor on kinectic energy