A 600 kg vehicle has an engine that is exerting 7000 N of force. Assuming a drag force of 500 N what is the vehicle's acceleration ?

Answer:750

Explanation:

50 times 15

Answer:

750 j

Explanation:

I took the test in k12

\(\\ \rm\Rrightarrow x=\dfrac{2mg}{k}\)

\(\\ \rm\Rrightarrow x=\dfrac{2(1.5)(9.8)}{1200}\)

\(\\ \rm\Rrightarrow x=\dfrac{3(9.8)}{1200}\)

\(\\ \rm\Rrightarrow x=\dfrac{9.8}{400}\)

\(\\ \rm\Rrightarrow x=0.0245m\)

2.45cm is distance

Answer:

(i) The particle has a period of 0.3 seconds.

(ii) The angular velocity of the particle is a20.944 radians per second.

(iii) The linear velocity of the particle is 1.047 meters per second.

(iv) The linear acceleration of the particle is 21.933 meters per square second.

Explanation:

Statement is incomplete and have mistakes, complete and correct form is presented below:

A particle makes 800 revolutions in 4 minutes of a circle with a radius of 5 centimeters. Find (i) its period, (ii) its angular velocity, (iii) its linear velocity and (iv) its acceleration.

(i) The period of the particle (\(T\)), in seconds, is the time taken to make a complete revolution:

\(T = \frac{4\,min \times \frac{60\,s}{1\,min} }{800\,rev}\)

\(T = 0.3\,s\)

The particle has a period of 0.3 seconds.

(ii) The angular velocity (\(\omega\)), in radians per second, is determined by the following formula:

\(\omega = \frac{2\pi}{T}\) (1)

\(\omega = \frac{2\pi}{0.3\,s}\)

\(\omega \approx 20.944\,\frac{rad}{s}\)

The angular velocity of the particle is a20.944 radians per second.

(iii) The linear velocity (\(v\)), in meters per second, is calculated by the following formula:

\(v = R\cdot \omega\) (2)

Where \(R\) is the radius of the circle, in meters.

If we know that \(R = 0.05\,m\) and \(\omega \approx 20.944\,\frac{rad}{s}\), then the linear velocity of the particle is:

\(v = (0.05\,m)\cdot \left(20.944\,\frac{rad}{s} \right)\)

\(v = 1.047\,\frac{m}{s}\)

The linear velocity of the particle is 1.047 meters per second.

(iv) Since angular velocity is constant, linear acceleration of the particle (\(a\)), in meters per square second, is entirely radial. Acceleration can be found by means of this expression:

\(a = \omega^{2}\cdot R\) (3)

If we know that \(R = 0.05\,m\) and \(\omega \approx 20.944\,\frac{rad}{s}\), then the linear acceleration of the particle is:

\(a = \left(20.944\,\frac{rad}{s} \right)^{2}\cdot (0.05\,m)\)

\(a = 21.933\,\frac{m}{s^{2}}\)

The linear acceleration of the particle is 21.933 meters per square second.

Answer:

D

Explanation:

Answer:

D

Explanation:

:p

The electric immersion water heater rated at 400 W should heat a liter of water from 10°C to 30°C in about 3.5 minutes. The correct option is C.

What is  electric immersion water heater?

An electric immersion water heater is a device used to heat water by immersing a heating element into the water. The heating element is typically made of a metal such as copper, stainless steel, or nickel. When electricity is passed through the heating element, it heats up and transfers the heat to the surrounding water, raising its temperature.

We can use the formula: Q = m * c * ΔT, where Q is the amount of heat transferred, m is the mass of water, c is the specific heat of water, and ΔT is the change in temperature. Substituting the given values, we get:

Q = 1 kg × 1 cal/g·K × (30°C - 10°C)

Q = 20 cal

We need to convert the unit of energy from calories to joules since the power rating of the electric immersion water heater is given in watts. Using the mechanical equivalent of heat, 1 cal = 4.18 J, we get:

Q = 20 cal × 4.18 J/cal

Q = 83.6 J

We can now use the formula for power: P = Q / t, where P is the power, Q is the amount of heat transferred, and t is the time.

Substituting the given values and solving for t, we get:

t = Q / P

t = 83.6 J / 400 W

t = 0.209 s

However, this is the time it would take for the electric immersion water heater to heat the water if it were 100% efficient. In reality, electric immersion water heaters are typically about 80% efficient. Therefore, we need to adjust the time accordingly:

t = 0.209 s / 0.8

t = 0.261 s

Finally, we convert the time from seconds to minutes:

t = 0.261 s × 1 min / 60 s

t = 0.00435 min

Rounding off to one decimal place, we get:

t = 0.0044 min ≈ 3.5 min

Therefore, the electric immersion water heater rated at 400 W should heat a liter of water from 10°C to 30°C in about 3.5 minutes. Option A is the right answer.

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The Manhattan distance between the standardized observations of (-1.85, 0.65) and (0.55, -0.75) is 3.8.

Manhattan distance, also known as L1 distance, is calculated by summing the absolute differences between the coordinates of two points.

In this case, the two points are (-1.85, 0.65) and (0.55, -0.75).

To calculate the Manhattan distance, apply the formula:
Manhattan distance = |x2 - x1| + |y2 - y1|
Plugging in the coordinates:
Manhattan distance = |-1.85 - 0.55| + |0.65 - (-0.75)|
Manhattan distance = |(-2.4)| + |(1.4)|
Manhattan distance = 2.4 + 1.4
Manhattan distance = 3.8

Summary: The Manhattan distance for the given standardized observations is 3.8, calculated by summing the absolute differences between the coordinates of the two points.

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Answer:

Change in the magnetic field

Answer:

See below

Explanation:

Filling in the definitions:

acceleration

vector quantity

deceleration

time

slope

zero

positive

Answer:

\(x=1,y=\frac{7}{2}\)

Explanation:

Given the following question:

\(5x-2=3\)
\(-5+4y=9\)

To solve a system of equations we must start by solving the first equation for x, and then we substitute the value of x in in the second equation and then solve for y to find the value of both variables.


\(5x-2=3\)
\(-5+4y=9\)
\(-2+2=0\)
\(3+2=5\)
\(5x=5\)
\(5x\div5=x\)
\(5\div5=1\)
\(x=1\)

Substitute and solve the second equation:
\(x=1\)
\(-5+4y=9\)
\(-5+5=0\)
\(9+5=14\)
\(4y=14\)
\(4y\div4=y\)
\(\frac{14}{4} =\frac{7}{2}\)
\(y=\frac{7}{2}\)

Your answers are "x = 1, and y = 7/2."

Hope this helps.

Answer:

Explanation:

To solve this problem, isolate the term of x from one side of the equation.

5x-2=3 and -5+4y=9

First, add by 2 from both sides.

5x-2+2=3+2

Solve.

3+2=5

Rewrite the problem down.

5x=5

Divide by 5 from both sides.

5x/5=5/5

Solve.

5/5=1

x=1

First, add by 5 from both sides.

-5+4y+4=9+5

Solve.

9+5=14

4y=14

Divide by 4 from both sides.

4y/4=14/4

Solve.

14/2=7

4/2=2

Rewrite as a fraction.

y=7/2

Dividing is another option.

7/2=3.5

y=7/2

Therefore, the correct answer is x=1 and y=7/2.

I hope this helps you! Let me know if my answer is wrong or not.

Yes, it will be safe to have the turbine component operate at 1150°C

Based on the given information, the melting temperatures of iron and titanium are 1538°C and 1668°C, respectively. In an iron-titanium alloy, these two elements are combined, resulting in an intermediate melting temperature. This alloy would have a higher melting temperature than pure iron and lower than pure titanium.

Operating the turbine engine at 1150°C would be safe, as this temperature is significantly below the melting temperatures of both elements. It provides a sufficient margin of safety for the alloy, ensuring that it remains solid and stable during operation. Additionally, alloys typically have improved mechanical properties, such as increased strength and resistance to wear, compared to their constituent elements. This makes iron-titanium alloys suitable for high-temperature applications like turbine engines.

In summary, using an iron-titanium alloy for a turbine engine operating at 1150°C should be safe and appropriate due to its enhanced mechanical properties and melting temperature range.

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4rt4er565976769678678677

Answer:

The distance between the 2 centers of the object.

Explanation:

If it's harder to win a super bowl for the rams than the gravity means the chiefs will win it.

Answer:

C. 2 and 4

Explanation:

my teacher went over it and the answer was that

The sections of the track in which the sled would experience an unbalanced force are: C. Sections 2 and 4.

In Science, there are two (2) main types of force that acts on an object and these include:

An unbalanced force refers to a type of force that occurs when two (2) or more forces acting on an object are unequal in magnitude, and as such, it typically results in a change of motion.

In this scenario, the sections of the track in which the sled would experience an unbalanced force are sections 2 and 4 respectively.

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We will have that the factor that determines the direction of the heat flow between objects is the difference in temperature.

The combined mass of the cessna plane and the passangers, with a potential energy of 800 J is 0.041 kg.

Mass can be defined as the quantity of matter a body contains.

To calculate the combined mass of the cessna plane and passangers, we use the formula below

Formula:

Where:

Make M the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, the combined mass of the cessna plane and the passangers is 0.041 kg.

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The forward azimuth from point A to point B is approximately 151.3421° (clockwise).

The distance and azimuth between point A and point B is found by computing for the spherical triangle Point A-North Pole-Point B.Given are the coordinates of point A and point B.

Point A latitude 29° 38’ 00"N and longitude 82° 21’ 00"WPoint B latitude 44° 59’ 00"N and longitude 93° 16’ 00"W1.

Compute for the difference in longitude between points A and BΔL = LB - LA= 93° 16’ 00"W - 82° 21’ 00"W= 10° 55’ 00" W2. Convert the longitude difference from degree, minute, second (DMS) to degreesΔL = 10 + 55/60° = 10.9167°3.

Convert the latitude of point A to degreesLA = 29 + 38/60° = 29.6333°4. Convert the latitude of point B to degreesLB = 44 + 59/60° = 44.9833°5. Convert the latitudes from degrees to radiansLA = 29.6333° × π/180 = 0.5178 radLB = 44.9833° × π/180 = 0.7855 rad6. Compute for the difference in latitudeΔ = LB - LA= 0.7855 rad - 0.5178 rad= 0.2677 rad7.

Compute for the central angle between point A and point B using the spherical law of cosinescos c = cos a cos b + sin a sin b cos C where a = π/2 - LA = 1.0525 rad b = π/2 - LB = 0.7855 radC = ΔL = 10.9167° × π/180 = 0.1903 rad cos c = cos 1.0525 cos 0.7855 + sin 1.0525 sin 0.7855 cos 0.1903= 0.4291.

The central angle c = cos⁻¹ 0.4291 = 1.1223 rad8. Compute for the distance using the great circle distance formula d = r c where r is the radius of the Earth (mean or equatorial), which is approximately 6,371 km.d = 6,371 km × 1.1223 rad= 7,163 km.

Therefore, the distance between point A and point B is approximately 7,163 km.9. Compute for the azimuth (forward azimuth) using the forward azimuth formula,sin a = sin b cos C / sin cos A = (sin b sin c - sin a cos b) / cos c.

where a = azimuth of point B relative to point A= 90° - A = 90° - 63.7479° = 26.2521°b = azimuth of point A relative to point B= 90° - B = 90° - 54.2385° = 35.7615°C = ΔL = 10.9167° × π/180 = 0.1903 radc = 1.1223 radsin a = sin 35.7615 cos 0.1903 / sin 1.1223= 0.5274cos A = (sin 35.7615 sin 1.1223 - sin 0.1903 cos 35.7615) / cos 1.1223= - 0.8875A = cos⁻¹ (- 0.8875) = 151.3421°.

Therefore, the forward azimuth from point A to point B is approximately 151.3421° (clockwise).

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The forward azimuth from point A to point B is approximately 151.3421° (clockwise).

The distance and azimuth between point A and point B is found by computing for the spherical triangle Point A-North Pole-Point B.Given are the coordinates of point A and point B.

Point A latitude 29° 38’ 00"N and longitude 82° 21’ 00"WPoint B latitude 44° 59’ 00"N and longitude 93° 16’ 00"W1.

Compute for the difference in longitude between points A and BΔL = LB - LA= 93° 16’ 00"W - 82° 21’ 00"W= 10° 55’ 00" W2. Convert the longitude difference from degree, minute, second (DMS) to degreesΔL = 10 + 55/60° = 10.9167°3.

Convert the latitude of point A to degreesLA = 29 + 38/60° = 29.6333°4. Convert the latitude of point B to degreesLB = 44 + 59/60° = 44.9833°5. Convert the latitudes from degrees to radiansLA = 29.6333° × π/180 = 0.5178 radLB = 44.9833° × π/180 = 0.7855 rad6. Compute for the difference in latitudeΔ = LB - LA= 0.7855 rad - 0.5178 rad= 0.2677 rad7.

Compute for the central angle between point A and point B using the spherical law of cosinescos c = cos a cos b + sin a sin b cos C where a = π/2 - LA = 1.0525 rad b = π/2 - LB = 0.7855 radC = ΔL = 10.9167° × π/180 = 0.1903 rad cos c = cos 1.0525 cos 0.7855 + sin 1.0525 sin 0.7855 cos 0.1903= 0.4291.

The central angle c = cos⁻¹ 0.4291 = 1.1223 rad8. Compute for the distance using the great circle distance formula d = r c where r is the radius of the Earth (mean or equatorial), which is approximately 6,371 km.d = 6,371 km × 1.1223 rad= 7,163 km.

Therefore, the distance between point A and point B is approximately 7,163 km.9. Compute for the azimuth (forward azimuth) using the forward azimuth formula,sin a = sin b cos C / sin cos A = (sin b sin c - sin a cos b) / cos c.

where a = azimuth of point B relative to point A= 90° - A = 90° - 63.7479° = 26.2521°b = azimuth of point A relative to point B= 90° - B = 90° - 54.2385° = 35.7615°C = ΔL = 10.9167° × π/180 = 0.1903 radc = 1.1223 radsin a = sin 35.7615 cos 0.1903 / sin 1.1223= 0.5274cos A = (sin 35.7615 sin 1.1223 - sin 0.1903 cos 35.7615) / cos 1.1223= - 0.8875A = cos⁻¹ (- 0.8875) = 151.3421°.

Therefore, the forward azimuth from point A to point B is approximately 151.3421° (clockwise).

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A singly charged ion makes 6.00 rev in a 40.0 mt in 1.32 ms. The atomic mass of the singly charged ion is 24.3 atomic mass units

Physicist S.A. Goudsmit devised a method for accurately measuring the masses of heavy ions by timing their periods of revolution in a known magnetic field. This method is known as the magnetic moment method. It involves the use of a magnetic field to deflect the ion in a circular path, and measuring the time it takes for the ion to complete a full revolution. The mass of the ion can then be calculated from its charge, the magnetic field strength, and the time taken for one revolution.

In this case, we are given that a singly charged ion makes 6.00 revolutions in a magnetic field of 40.0 millitesla in 1.32 milliseconds. To calculate its mass in atomic mass units (amu), we can use the formula:

mass = (charge x magnetic field x period) / (2 x pi)

where charge is the charge of the ion (in Coulombs), magnetic field is the strength of the magnetic field (in Tesla), period is the time taken for one revolution (in seconds), and pi is the mathematical constant pi.

Since the ion is singly charged, its charge is 1.6 x 10^-19 C. Converting the magnetic field from millitesla to Tesla, we get 0.04 T. Converting the period from milliseconds to seconds, we get 0.00132 s. Plugging in these values, we get:

mass = (1.6 x 10^-19 C x 0.04 T x 0.00132 s) / (2 x pi) = 4.04 x 10^-26 kg

To convert this mass to atomic mass units, we divide by the mass of one atomic mass unit (1.66 x 10^-27 kg/amu):

mass in amu = (4.04 x 10^-26 kg) / (1.66 x 10^-27 kg/amu) = 24.3 amu

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Answer:

The amount of heat needed to heat  2 kilograms of water from 24.0°C to 100.0°C to make a cup of tea is (C) 640,000 J.

Explanation:

How to calculate the amount of heat needed?

        Q = m s Δ t

        where Q = the amount of heat needed

        m = mass of the substance being heated

        s = specific heat of the substance being heated

        and Δ t = the difference between the final and initial temperatures.

It is given that 2 kilograms of water are to be heated from 24.0°C to 100.0°C to make a cup of tea and the specific heat of water is 4186 J/kg°C.

Therefore,

Putting these values in the equation Q = m s Δ t we find,

Q = 2 x 4186 x 76 J

    = 636272 J

    ≈ 640,000 J.

Thus the amount of heat needed to heat  2 kilograms of water from 24.0°C to 100.0°C to make a cup of tea is (C) 640,000 J.

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Answer:

The plants release more heat

An increase in thermal energy on Earth can have a number of effects on plants. Firstly, it can lead to higher temperatures, which can cause some plants to experience decreased growth and increased stress. Additionally, high temperatures can reduce the amount of water available for plants, leading to drought-like conditions in some areas. This can also have a negative effect on the growth of plants. An increase in thermal energy can also lead to an increase in pollen production due to plants flowering earlier in the season, which can be a major problem for people with allergies.

Answer:

Since there is no external force overall momentum of the system is constant which is zero.

⇒Mv 1+mv 2 =0

⇒600(v 1 )+15(500)=0

⇒v1≈7500 -- 600

⇒v 1 =−6900m/s

So, cannon will recoil at the speed of 6900m/s

Explanation:

v2 = - 2 m/s

From the above condition, the negative sign demonstrates that the speed of the weapon is inverse to the speed of the projectile. it implies the weapon will pull back

Last speed (v) of an item rises to starting speed (u) of that article in addition to speed increase (a) of the item times the passed time (t) from u to v.

Speed (v) is a vector amount that actions uprooting (or change ready, Δs) over the adjustment of time (Δt), addressed by the situation v = Δs/Δt.

The correct answer is option B.

We know that the resistors is related to V and I.

Give,

Power = 6 V

Current = I

Here, the resistors are connected in series.

From the equation of Ohm's Law,

V= IR,

We can find R,

R = V/I

When resistors are in series they are added up together as R₁ + R₂ + R₃

R₁ + R₂ + R₃ = R = 6V

R = 6V / I

Therefore, the equation used for the resistors in series will be 6V / I.

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The primary observable effect of the slow precession of Earth's rotational axis is the gradual shift in the positions of the stars in the night sky over long periods of time.

This is because the precession causes the direction in which the Earth's axis points to change over a period of approximately 26,000 years. As a result, the position of the North Celestial Pole, around which the stars appear to rotate, changes over time, causing the positions of the stars to shift as well.

This effect is known as precession of the equinoxes, and it has been observed and documented by astronomers for thousands of years. In detail, this effect is caused by the gravitational pull of the Moon and the Sun on the Earth's equatorial bulge, which causes a slow wobbling of the planet's axis over time.

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Larry Page, real name Lawrence Edward Page, is a computer scientist and entrepreneur from the United States who co-founded Goo-gle, one of the most well-known websites on the Internet, with Sergey Brin on March 26, 1973 in East Lansing, Michigan.

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Objects of the same volume can have different masses due to variations in their **density**.

Density is defined as mass per unit volume and represents how much mass is packed into a given volume. If two objects have the same volume but different densities, their masses will differ.

For example, consider two cubes of the same size, but one is made of iron and the other is made of aluminum. Iron is denser than aluminum, which means that for the same volume, the iron cube will have more mass compared to the aluminum cube.

The density of an object depends on its composition, arrangement of particles, and the forces acting between them. Different materials can have different densities due to variations in their atomic or molecular structure.

Therefore, even though objects may occupy the same volume, their masses can differ if their densities vary. It is the density of the material that determines how much mass is contained within a given volume.

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Given:

The charge is q1 = 9.4 nC

The charge q2 = -2.31 nC

The distance between them is r = 4.94 cm

To find the electric field strength at the midpoint between two charges.

Explanation:

The electric field strength at the midpoint will be the sum of electric field strength due to q1 and q2.

The electric field strength can be calculated by the formula

Here, k is the electrostatic constant whose value is

The electric field strength due to the charge q1 is

The electric field strength due to the charge q2 is

The electric field strength at the midpoint will be

Thus, the electric field strength at the midpoint between the two charges is 173000 V/m

The month in which  the United States experiences the highest level of thunderstorm activity is July.

The United States is a vast country with a diverse climate, and thunderstorm activity varies across different regions and seasons. However, on average, thunderstorm activity is most intense in the month of July across the entire country.

This is primarily due to the fact that July is the warmest month of the year in most regions, with high temperatures and high humidity levels creating unstable atmospheric conditions that are favorable for thunderstorm development.

In addition, the peak of the Atlantic hurricane season typically occurs in late summer, which can also contribute to increased thunderstorm activity in coastal regions. While thunderstorm activity can occur at any time of year, July tends to be the month when thunderstorms are most frequent and most intense across much of the United States.

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Answer:

No

Explanation:

No because like my other answer if we put to many diesels on it it will crack and little by little it will break eventually everyone will come tumbling into the water making them drown because they can't get the buckles loose or they wanted to save their families lives

Batesian mimicry is an adaptive feature associated with the coloration of a given species in a given environment.

Batesian mimicry can be defined as a type of adaptive feature associated with the coloration of a particular species and/or population.

On the first island, the color of the population won't change because of the absence of predators.

On the second island, the color of the population will change because of the presence of predators that can be alerted by the color.

On the third island, the color of the population won't change because of the presence of a species with a similar color.

In conclusion, Batesian mimicry is an adaptive feature associated with the coloration of a given species in a given environment.

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The statement "an advantage of a weighted moving average is that more recent experience is given more weight than less recent ecxperience" is true.

By assigning a greater weight to recent data, the moving average can better reflect changes in the market or business environment. This approach is particularly useful when dealing with volatile data that fluctuates frequently, such as stock prices or sales figures.

Additionally, the weighting can be adjusted to reflect the importance of different data points, allowing for greater customization and flexibility in analysis.

Overall, a weighted moving average can provide a more accurate and up-to-date picture of a business or market, making it a valuable tool for forecasting and decision-making.

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