A 60-Ohm resistor is connected in parallel with a 20-Ohm resistor. What is the equivalent resistance of the combination?

Answers

Answer 1

The equivalent resistance of a 60-Ohm resistor connected in parallel with a 20-Ohm resistor is 13.3 Ohms.

To determine the equivalent resistance of a combination of resistors connected in parallel, the following formula can be used:

Req=1/(1/R1+1/R2+...+1/Rn)

where Req is the equivalent resistance and R1, R2, ..., Rn are the resistances of the individual resistors connected in parallel.

Given that a 60-Ohm resistor is connected in parallel with a 20-Ohm resistor.Using the above formula we have;

Req=1/(1/60 + 1/20)

Calculate the individual reciprocals first.

1/60 = 0.01671/20 = 0.05

Substitute into the formula;Req = 1/(0.0167 + 0.05)Req = 13.3 ohms

Therefore, the equivalent resistance of the combination is 13.3 Ohms.

In summary, the equivalent resistance of a 60-Ohm resistor connected in parallel with a 20-Ohm resistor is 13.3 Ohms. The formula used in solving for the equivalent resistance is Req=1/(1/R1+1/R2+...+1/Rn).

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Related Questions

Describe P-waves and S- waves and how they are different

Answers

Answer:

P-waves and S-waves are types of seismic waves that are generated during an earthquake. Seismic waves are waves of energy that travel through the Earth's interior and can be detected by seismometers.

P-waves, also known as primary waves or pressure waves, are compressional waves that move through the Earth by alternately squeezing and stretching the material through which they pass. They can travel through solid, liquid, and gaseous materials, and are the fastest type of seismic wave. P-waves are often the first waves to be detected during an earthquake, and are used to locate the epicenter of the earthquake.

S-waves, also known as secondary waves or shear waves, are transverse waves that move through the Earth by causing the material through which they pass to vibrate at right angles to the direction of the wave. S-waves can only travel through solid materials, and are slower than P-waves. They are used to determine the depth and intensity of an earthquake, as well as the composition and structure of the Earth's interior.

One way to differentiate between P-waves and S-waves is by the way they move through the Earth. P-waves move in the same direction as the wave, while S-waves move at right angles to the direction of the wave. Another way to differentiate between the two types of waves is by their frequency and wavelength. P-waves have a higher frequency and shorter wavelength than S-waves.

Explanation:

P waves are longitudinal waves and S waves are transverse waves

Why do scientists interested in Earth’s magnetic field collect cores from rocks at the Mid-Atlantic Ridge?

Answers

Ocean drilling cores have been used to confirm the age of the oldest oceanic crust, which was formed about missing years ago.

What is magnetic field ?

An electric charge, an electric current, and magnetic materials are all affected magnetically by a magnetic field, which is a vector field. A force perpendicular to the magnetic field and its own velocity acts on a moving charge in a magnetic field.

Because it shields the planet from dangerous radiations such solar winds, which have high radiation levels, the magnetic field of the Earth is crucial. The sun's solar energy includes solar winds.

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Find Acceleration 10:55 to 11:05 in kmph

Find Acceleration 10:55 to 11:05 in kmph

Answers

Considering the table the acceleration is 2.72 Km/hr

What is acceleration?

Acceleration is defined as the rate of change of velocity with respect to time.

This means that if an object's velocity changes by a certain amount over a certain period of time, then the object is said to have experienced acceleration during that time.

The formula is

= Final velocity - initial velocity / time taken

plugging in the values

= (65 - 60) / (11:55 - 10:05)

= 5 / 1:50

converting 50 minutes to hour = 50 / 60

= 5 / 1 50/60

= 2 6/11

= 2.72 Km/hr

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on june 9, 1988, sergei bubka broke the world pole-vaulting record for the 8th time in four years by attaining a height of 6.10 m. how long did it take bubka to return to the ground from the highest part of his vault?

Answers

On june 9, 1988, Sergei Bubka broke the world pole-vaulting record for the 8th time in four years by attaining a height of 6.10 m. It took Bubka 1.11 seconds to return to the ground from the highest part of his vault.

Sergei Bubka broke the world pole-vaulting record for the 8th time in four years by attaining a height of 6.10 m on June 9, 1988. It is required to determine how long it took Bubka to return to the ground from the highest point of his vault. In order to determine the time taken for Bubka to return to the ground, we need to consider the concepts of kinetic energy and potential energy. The pole vaulter gains potential energy during the ascent phase of the vault as he gains altitude. When he reaches the highest point, he has the maximum potential energy. During the descent phase of the vault, the potential energy is converted into kinetic energy.

Based on this principle, we can use the conservation of energy equation to find the time taken by Bubka to return to the ground. The equation for conservation of energy is given as: Potential energy (P.E) = Kinetic energy (K.E)

P.E = mgh where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above the ground.

K.E = 1/2 mv² where v is the velocity of the object.

The velocity of Bubka when he reached the highest point can be assumed to be zero since he had to come to a stop before starting his descent. Therefore, the initial kinetic energy is zero.

P.E at the highest point = K.E at the lowest point

Let t be the time taken by Bubka to return to the ground. We can assume that Bubka moves with uniform acceleration. Using the kinematic equation, we have: v = u + at where u is the initial velocity and a is the acceleration.

When Bubka reaches the ground, his final velocity is zero.

Therefore, we have: v = 0u = at

Substituting the value of u in the equation for K.E, we have: K.E = 1/2 mv² = 1/2 ma²t²

Substituting the value of P.E and K.E in the equation for conservation of energy, we have:

mgh = 1/2 ma²t²

Simplifying, we get: t = sqrt(2h/g)

Substituting the values of h and g, we have:

t = sqrt(2 x 6.10 / 9.81)t = sqrt(1.240)t = 1.11 seconds

Therefore, it took Bubka 1.11 seconds to return to the ground from the highest part of his vault.

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For a series circuit, as lights are added, the voltage across each bulb increases/ decreases/ remains the same ?

For a series circuit, as lights are added, the current across each bulb increases/ decreases/ or remains the same ?


Answers

For a series circuit, as lights are added, the current across each bulb decreases.  

Jessica stretches her arms out 0.60 m from the center of her body while holding a 2.0 kg mass in each hand. She then spins around on an ice rink at 1.1 m/s.
a. What is the combined angular momentum of the masses?
b. If she pulls her arms into 0.15 m, what is her new linear speed?

I'm really confused ab the explanations behind this. help, please

Answers

Answer:

a.) L = 2.64 kgm^2/s

b.) V = 4.4 m/s

Explanation: Jessica stretches her arms out 0.60 m from the center of her body. This will be considered as radius.

So,

Radius r = 0.6 m

Mass M = 2 kg

Velocity V = 1.1 m/s

Angular momentum L can be expressed as;

L = MVr

Substitute all the parameters into the formula

L = 2 × 1.1 × 0.6 = 1.32kgm^2s^-1

the combined angular momentum of the masses will be 2 × 1.32 = 2.64 kgm^2s-1

b. If she pulls her arms into 0.15 m,

New radius = 0.15 m

Using the same formula again

L = 2( MVr)

2.64 = 2( 2 × V × 0.15 )

1.32 = 0.3 V

V = 1.32/0.3

V = 4.4 m/s

Her new linear speed will be 4.4 m/s

A force is applied to stop a moving shopping cart. explain how increasing the time of impact would change the force required to stop the cart. enter your answer in the space provided.

Answers

By increasing the time of impact a smaller amount of force would be required to stop the cart. The force of the impact decreases as the impact of time increases. Therefore, the force on the body decreases as time increases with a constant change in momentum.

What is force?

The push or pull on a massed object changes its velocity is defined as force. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

Force = Mass × Acceleration

How is force related to change in time?

The change in momentum over time is measured by force. In real life, when a force is applied to an object, it accelerates and rises in velocity, which increases the momentum of the object.

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Basic design elements include (Check 7)
What are the 3 properties of color? Immersive Reader

depth, shade, fragrance
value, hue, depth
saturation, hue, chroma
hue, value, intensity

Answers

Answer: depth, shade, fragrance

Explanation:

Which statement explains how planets move in orbit as supported by Newton’s first law of motion?

Planets can change the direction of their own orbital path.
Planets can change orbits due to their inertia.
Planets in motion will have a constant speed unless acted on by an outside force.
Planets with a greater mass will orbit more quickly than smaller planets.

Answers

Answer:

C

Explanation:

When the planet in motion should have the same speed so until it should be acted by an outer force. This statement explained the movement of the planets.

The information regarding the first law of motion is as follows:

In the case when the body is at rest or moves at the same speed on the straight line so it should be the same at rest or a movement until it is acted by an outside force. It is also called as law of inertia.

Therefore, the third option is correct.

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Joey is performing an experiment in science class. He mixes two liquids in a test tube, and gas bubbles
appear at the surface of the test tube. Which of the following describes what is most likely taking place?
a.) A physical change is causing a change the phase from liquid to gas.
b. A chemical change has caused the liquids to undergo combustion and gas is escaping.
c. A physical change is causing the isolation to exhibit different properties than the original
substances.
d. A chemical change has resulted in the production of a new substance, which is being given off
as gas.

Answers

Answer:

The answer is D

Explanation:

Gas is made when chemical change happens. The chemical change has made a new substance gas. It cannot be combustion unless it is hot or was on fire.

A chemical change has resulted in the production of a new substance, which is being given off.

The correct option is D.

What is called chemical change?

A chemical change is any process that converts one material into another, produces new compounds with unique features, or combines any of these processes. When two compounds combine to generate a new material, it takes place (synthesis or either decomposes to form more substances).

What takes place when chemicals change?

Breaking covalent bond between reactant molecules (particles) and creating new bond between atoms in product particles are two aspects of chemical reactions (molecules). While there are the same number of atoms both before and after the biochemical transition, there will be a change in the number of molecules.

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PLEASE PLEASE PLEASE HELP ME ASAP I NEED IN FIVE MINUTES!!!!!! I WILL MARK BRAINLYEST AND WILL GIVE 10 EXTRA POINTS!!!!!
How does knowing how the Earth is structured help you decide where you would like to live in terms of temperature?

Answers

Answer:

Much of our understanding of the basic structure and composition of Earth and the other planets in our solar system is not strenuously debated. We can infer a surprising amount of information from the size, mass and moment of inertia of the planets, all of which can be determined from routine astronomical observations. Measurements of surface chemical composition, either by direct sampling (as has been done on Earth, the moon, and Mars) or through spectroscopic observations, can be used to estimate elemental abundances and the degree of chemical differentiation that occurred as the planets condensed from the solar nebula. Remote observations of the gravitational field can be used to understand how a planet's mass is distributed, whereas the strength and shape of the magnetic field provides some constraint on the structure of a metallic core. The specifics of structure and composition, however, are much more debatable. And it is these details that tell us a much more extensive and ultimately more interesting story about the internal dynamics of the planets and their evolution. As a result, trying to determine them is frontier research in almost all fields of earth and planetary science.

Even on Earth, many of these details have to be inferred from remote observations. Because we cannot sample the deep Earth, we must deduce its composition either by looking at the clues hidden in igneous and metamorphic rocks, or by examining proxies for composition and structure such as the three-dimensional variation of the velocity of seismic waves produced by earthquakes and sampled by networks of seismometers on the surface. The late Francis Birch, the eminent Harvard geophysicist, and his colleagues and students worked out the basic methodology that brings these distinct observations together. Birch showed how the stiffness of rocks changes under the extreme conditions of pressure and temperature deep within planets, as well as with chemical composition. Because the speed of seismic waves depends on the stiffness of the medium through which they propagate, it is possible to calculate temperature and composition from maps of seismic velocity. Most current research is based on Birch's work and it has even been extended to the most extreme temperature and pressure conditions of Earth's core. For example, much of our understanding of the large- and small-scale convection patterns driving plate tectonics has come about by using Birch-type proxies for temperature and composition.

Explanation:

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A brass rod is encased in aluminum. What happens to the speed of a sound
wave when it passes through the rod and moves from the brass into the
aluminum?
Aluminum
Copper
Lead
Brass
(70% Cu,
30% Zn)
6,420
4,700
5,010
1,960
Speed of
sound
(m/s)
A. Its speed decreases.
OB. Its speed increases.
ООО
O C. Its speed falls to zero.
OD. Its speed stays the same.
PREVIOUS

A brass rod is encased in aluminum. What happens to the speed of a soundwave when it passes through the

Answers

Answer:

B. its speed increases

Explanation:

A brass rod is encased in aluminium. The speed of a sound wave in this decreases when it moves from the aluminium into the brass medium. Thus, the correct option is A.

What factors affect speed of sound?

Sound travels in different mediums in the form of waves. The speed of sound is the speed with which the sound wave travels in a medium. The speed of the wave depends on the density and the elasticity of the medium through which the sound waves travel. In general, the sound wave travels faster in the liquid mediums in comparison to the gas medium and these are quicker in solid mediums than in liquid mediums. Thus, the greater the elasticity and the lower the density of the waves, the faster the sound waves travel in that medium.

The speed of sound in aluminium is 5100m/s and in the brass medium, it is 6,923. So, if the sound wave is moving from aluminum metal to the brass medium, we can clearly observe that there is decrease in the speed of sound. So, we can say here that is the speed is decreases.

Therefore, the correct option is A.

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why do cars accelerated up the slopes at the same speed but required different amounts of force

Answers

Answer:

The same way Newton’s apple fell from the tree and failed to “fall” back up. The steeper the slope the faster the pull of gravity will act. Assuming you are providing the exact same power to a car an upslope will slow the car and a down slope will speed the car. The greater the slope, the greater effect. Until you reach vertical, you should never operate a vehicle in such a manner.

Explanation:

a simple pendulum is swinging back and forth through a small angle, its motion repeating every 1.25 s. how much longer should the pendulum be made in order to increase its period by 0.20 s?

Answers

The pendulum will need to be 0.13432m made in order to increase its period by 0.20s.


How to calculate how much longer should the pendulum be made in order to increase its period by 0.20s?

Pendulum is a weight hung from a fixed point so that it can swing freely backward and forward, especially a rod with a weight at the end that regulates the mechanism of a clock.

period of pendulum (T) = 1.25s

earth gravity (g) = 9.8m/s²

π = 3.14
using the time period of simple pendulum

T = 2 * π √L / g
L = (T² * g) / (4 * π²)

= 1.25² * 9.8 / 4 * 3.14²

= 0.38866m

Now, the period of pendulum increased by 0.20s

T' = 1.25s + 0.20s = 1.45s

so the length (L') will be

= (T'² * g) / (4 * π²)

= (1.45² * 9.8) / (4 * 3.14²)

= 0.52298m

ΔL = L' - L

= 0.52298 - 0.38866

= 0.13432m

Therefore, the pendulum needs to be 0.13432m longer to increase its period by 0.20s.

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Select the compensator zero to cancel one pole of GHP(z) {other than z=1}. α = Determine 3 based on the angle condition: zeros - 4poles = 180° You need to draw a figure as the Figure below to calculate ß = Im z-plane z = a + ib Zero of GHP(Z) Zzero Zpole(B) 0 B Figure: Determine ß Zpole(1) pole 1 of GHP(z) Re
The angle condition is: Zzero- (pole(1) + 4pole(B))= 180º Zzero = Zpole(1) = Zpole(B) = Determine the compensator gain k based on magnitude condition: z-α Gc (2) GHP (2)|2=a+ jb = 1 → k Ghp(2) = 1 z-ß |z=a+jb 1 k z-α GHP(z) |z-ß |z=a+jb Write down the final compensator (PID Controller) transfer function Gc(z)=kz-a z-ß

Answers

Analyze system dynamics and design compensator to achieve desired response by selecting compensator zero and canceling one pole of GHP(z).

How to select the compensator zero cancel one pole of GHP(z)?

To select a compensator zero to cancel one pole of GHP(z), we need to use the given angle condition:

Zzero - (pole(1) + Zpole(B)) = 180°

Here, Zzero represents the compensator zero, pole(1) represents the first pole of GHP(z), and Zpole(B) represents the compensator pole.

Let's proceed with the solution step by step:

1. First, we need to determine the value of Zzero. The angle condition states that Zzero = Zpole(1), which means the compensator zero is equal to the first pole of GHP(z).

2. Now, we need to find the value of Zpole(B). We can rewrite the angle condition as follows:

Zpole(B) = Zzero - pole(1) + 180°

Since we already know that Zzero = Zpole(1), we can substitute Zzero in the above equation:

Zpole(B) = Zpole(1) - pole(1) + 180°

Simplifying further:

Zpole(B) = 180°

Therefore, the value of Zpole(B) is 180°.

To summarize, we can select the compensator zero (Zzero) to cancel one pole of GHP(z) as Zpole(1), and the compensator pole (Zpole(B)) is determined to be 180° based on the given angle condition.

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Please help if you can!

Please help if you can!

Answers

Answer:

Illuminated

Explanation:

I think but not sure

Calculate the rms currents for an ac source is given by v(t) = V0 sinÏt, where V0 = 100V and Ï = 200Ï rad/s when connected across
(a) a 20-μF capacitor,
(b) a 20-mH inductor, and
(c) a 50-Ω resistor.

Answers

the RMS currents are:/Capacitor: 0.0707  , Inductor: 5.639  and Resistor: 1.414 A

(a) The rms current through the capacitor can be found using the formula IRMS = VRMS/XC, where XC is the capacitive reactance given by XC = 1/(2πfC) = 1/(2π(200)(20×10^-6)) = 39.79Ω. Therefore, IRMS = VRMS/XC = (100V)/39.79Ω = 2.51A.

(b) The rms current through the inductor can be found using the formula IRMS = VRMS/XL, where XL is the inductive reactance given by XL = 2πfL = 2π(200)(20×10^-3) = 25.13Ω. Therefore, IRMS = VRMS/XL = (100V)/25.13Ω = 3.98A.

(c) The rms current through the resistor can be found using the formula IRMS = VRMS/R = (100V)/50Ω = 2A.
To calculate the RMS currents for each component, we'll first find their impedance (Z) and then use Ohm's law (I = V/Z) to find the current. The RMS voltage (Vrms) is V0/√2.

(a) For a 20-μF capacitor:
Impedance, Zc = 1/(ωC) = 1/(200π * 20 * 10^(-6)) ≈ 795.77 Ω
Irms (capacitor) = Vrms / Zc = (100 / √2) / 795.77 ≈ 0.0707 A

(b) For a 20-mH inductor:
Impedance, Zl = ωL = 200π * 20 * 10^(-3) ≈ 12.57 Ω
Irms (inductor) = Vrms / Zl = (100 / √2) / 12.57 ≈ 5.639 A

(c) For a 50-Ω resistor:
Impedance, Zr = 50 Ω
Irms (resistor) = Vrms / Zr = (100 / √2) / 50 ≈ 1.414 A

So, the RMS currents are:
(a) Capacitor: 0.0707 A
(b) Inductor: 5.639 A
(c) Resistor: 1.414 A

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A 20 cm
B 15 cm
C 10 cm
D 5 cm
E 0 cm
If potential energy at point A is 12 joules, what is the potential energy at B?

Answers

Answer:

\(Ebp=9J\)

Explanation:

Potential energy:

\(Ep=mgh\)

m - mass

h - altitude = 20cm = 0.2 m

\(Epa=12=0.2(mg)\)

Thus:

\(mg=\frac{12}{0.2}\)

\(mg=60n\)

In Point B:

\(Epb=mg(0.15)\)

\(Epb=60(0.15)\)

\(Epb=9J\)

In terms of π, what is the length of an arc
which subtends an angle of 30° at the centre
of a circle of radius 3 cm?​

Answers

Answer:

Since 2 pi = 360 deg and pi equals 180 deg, 30 deg = pi / 6.

S = theta * R = pi / 6 * 3 cm = 1.57 cm

In any thermodynamic system that deals with the transfer of thermal energy, which of thefollowing is the most ideal state for that system?

In any thermodynamic system that deals with the transfer of thermal energy, which of thefollowing is

Answers

Thermodynamics can be said to be a branch of Physics which involves the transfer of heat and other energy forms.

Thermal energy is the energy possesed by a system due to its temperature.

In thermodynamics, during the transfer of thermal energy, energy is wasted due to entryopy. And entropy is the measure of disorder of a system.

Therefore, in amy thermodynamic system that deals with the transfer of thermal energy, the most ideal state for that system is Entropy

ANSWER:

A. Entropy

a ball with mass m travels in positive x-direction with a speed v and collides with two other balls (also of mass m). the two struck balls move with equal speeds at 45 degrees up and down with respect to the x-axis after the collision. what is the final speed of all three balls?

Answers

The final speed of all three balls is v \(\sqrt{m/2k}\).

What is speed?

Speed is the rate of movement along a path as opposed to velocity, which represents the speed and direction of an object's movement. As opposed to speed, which is a scalar quantity, velocity is a vector.

What is collision?

When two objects briefly make contact with one another physically, they collide. Or, to put it another way, a collision is an extremely brief reciprocal encounter between two masses that modifies momentum and energy.

Pxi= MV

Pyi= 0

Pxf= mv₁ + 2 mv₂ cos (45°)

Pyf = mv₂ sin (45°)-  mv₂ sin (45°) = 0

now

Pxi=Pyi

v= v₁ + 2v₂  cos (45°)

v= \(\sqrt{2}\) v₂ ⇒1

1/2 mv²= 1/2mv₁² + 1/2 (2m) V₂²

V²= v₁² +2 V₂²

V²= (V- \(\sqrt{2}\) v₂)² +2 V₂²

4 V₂² +\(\sqrt[2]{2}\) V V₂

1/2 = 1/\(\sqrt{2}\) v

v₁= v- \(\sqrt{2}\)V₂

v₁= v-v =0

so find the speed will be v, 1/\(\sqrt{2}\) v,  1/\(\sqrt{2}\) v

now , energy conservation,

1/2 mv²- 1/2 2m (v/2)² = 1/2 kx²

mv²- mv²/2 =  kx²

mv²/2k = x²

x= v \(\sqrt{m/2k}\)

Therefore, the final speed of all three balls is v \(\sqrt{m/2k}\).

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Which of the following is not an example of transverse wave
a. earthquake
b. ucking a guitar string
c. a break dancer doing the worm
d. a girl holding a jump rope moving her arm up and down​

Answers

Among the option which is not transverse wave is earthquake because it constitute longitudinal wave.

The orderly, planned transfer of disturbances from one location to another is known as a wave. There are waves in sound, light, and the movement of subatomic particles in addition to the waves that move across the water's surface, which are the most well-known waves. The disturbance oscillates periodically (see periodic motion) with a set frequency and wavelength in the simplest waves. In contrast to electromagnetic waves, which do not require a medium to move and can do so in a vacuum, mechanical waves, like sound, require one (see electromagnetic radiation). The characteristics of a medium determine how a wave travels through it.

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A motorcyclist covers 150m in 10 seconds. The speed is: Select one: a. 1.5m/s b. None c. 15m/s d. 1500m/s

Answers

Answer:

c.15mls

Explanation:

speed is the total distance cover by body .i

speed:total c covered distance(d)/time taken(t)

at an instant when a soccer ball is in contact with the foot of a player kicking it, the horizontal or x component of the ball’s acceleration is 810 m/s2 and the vertical or y component of its acceleration is 1100 m/s2 . the ball’s mass is 0.43 kg. what is the magnitude of the net force acting on the soccer ball at this instant

Answers

Answer:

487.13N

Explanation:

According to Newton's second law;

F = ma

F is the net force

m is the mass of the object

a is the acceleration

First we need to find the resultant of the acceleration

a =√810²+910²

a = √656,100+828,100

a =√1,484,200

a = 1218.28m/s²

Ball mass = 0.40kg

Next is to get the magnitude of the net force

F = 0.4 × 1218.28

F = 487.31N

Hence the magnitude of the net force acting on the soccer ball at this instant is 487.13N

When a golfer tees off, the head of her golf club which has a mass of 151 g is traveling 43.9 m/s just before it strikes a 46.0 g golf ball at rest on a tee. Immediately after the collision, the club head continues to travel in the same direction but at a reduced speed of 28.2 m/s. Neglect the mass of the club handle and determine the speed of the golf ball just after impact

Answers

Answer:

51.54 m/s

Explanation:

Applying,

Law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = mv+m'v'.................... Equation 1

Where m = mass of the head of the golf club, m' = mass of the gulf ball, u = initial velocity of the head of the gulf club, u' = initial velocity of the gulf ball, v = final velocity of the head of a gulf club, v' = final velocity of the gulf ball

From the question,

Given: m = 151 g = 0.151 kg, u = 43.9 m/s, m' = 46 g = 0.046 kg, u' = 0 m/s (at rest), v = 28.2 m/s

Substitute these values into equation 1

0.151(43.9)+0.046(0) = 0.151(28.2)+0.046(v')

solve for v'

6.6289+0 = 4.2582+0.046v'

0.046v' = 6.6289-4.2582

0.046v' = 2.3707

v' = 2.3707/0.046

v' = 51.54 m/s

Calculate the force needed to move a 2kg mass with an acceleration of 5ms-2

Calculate the force needed to move a 2kg mass with an acceleration of 5ms-2

Answers

Answer:

\(\Huge \boxed{\mathrm{10 \ N}}\)

Explanation:

\(\sf Force \ (N)=mass \ (kg) \cdot acceleration \ (ms^{-2})\)

\(F=ma\)

The mass is 2 kg.

The acceleration is 5 ms⁻².

\(F = 2 \cdot 5\)

\(F=10\)

The force is 10 N.

what is its speed at the end of a 400 m long runw from rest and accelerates at a constant template miles per second was a speed at the end of the

Answers

The speed at the end of a 400 m run, starting from rest and accelerating at a constant rate of 1.47 m/s^2, is 10.4 m/s.

To find the final speed, we need to use the kinematic equation: vf^2 = vi^2 + 2ad, where vf is the final velocity, vi is the initial velocity (which is zero in this case), a is the acceleration (given as 1.47 m/s^2), and d is the distance (given as 400 m).

Solving for vf, we get vf = sqrt(2ad) = sqrt(2 x 1.47 m/s^2 x 400 m) = 10.4 m/s. Therefore, the speed at the end of the 400 m run, starting from rest and accelerating at a constant rate of 1.47 m/s^2, is 10.4 m/s.

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briefly explain what EMF of a cell cell is​

Answers

Answer:

The emf of a cell is the sum of the electric potential differences (PDs) produced by a separation of charges (electrons or ions) that can occur at each phase boundary (or interface) in the cell. The magnitude of each PD depends on the chemical nature of the two contacting phases.

Explanation:

pls mark brainliest

Write some harms of friction.

Answers

Answer:

Friction produces unnecessary heat leading to the wastage of energy. The force of friction acts in the opposite direction of motion, so friction slows down the motion of moving objects. Forest fires are caused due to the friction between tree branches. However, friction can also cause problems in a car. Friction between moving engine parts increases their temperature and causes the parts to wear down. Friction can be both harmful and helpful, so it may be necessary to decrease or increase friction.

Answer:

Friction had many disadvantages and these are the har,s of friction too.

Explanation:

Disadvantages of friction are mainly forest fires, decreasing life expectancy of vehicles, damages many machines, generates heat, wear and tear, wastage of force/energy, etc. When two things in a forest rub against each other through an amount of force, friction will be present and it will cause a spark. This spark will be continued into a fire because of other materials like wood in the forest causing a forest fire. Secondly, vehicles work through moving many internal machines in them; this again includes friction and friction can damage the machines so to prevent it ppl grease the machines. decreasing life of vehicles is just a larger view of damaging the machines as this disadvantage of friction can be used anywhere. Wastage of force/ energy because when we roll a ball on a surface we have to put force on the ball to make it move forward but because friction moves in the opposite direction energy/force will be wasted there. Generating heat and wear & tear are some factors of friction which is also a harm.

Which additional information would be required to determine the velocity of the train?

a: the total distance covered by the train
b: the mass of the train
c: the time the train is traveling
d: the direction of the train

Answers

To determine this same train's velocity, you would require to understand it's own direction.

What is the response to velocity?

The pace at which a material's position changes in relation to a frame of reference is known as its velocity, and it depends on time. The definition of velocities is the determination of a moving object's rate and direction (for example, 60 km/h to the north).

Why is velocity employed?

Velocity is a unit of measurement for motion that begins in one location and moves to another. There are countless practical uses for velocity, one of the more frequent ones is figuring out how quick you (or something that is motion) will get somewhere from somewhere.

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