Answer:
8.4
Explanation:
Water flow at the rate of 0.1500kg/m through a tube and is heated by a heater dicsipating 25.2w. the in flow and out flow water temperatures are 15.2 degree Celsius and 17.4 degree Celsius respectively.when the rate of is increased to 0.2318kg/m and the rate of heating to 37.8w,the inflow and out flow temperatures are unaltered. find specific heat capacity of water and rate of loss of heat from tube
The specific heat capacity of water is 960 J/(kg·°C).
The rate of heat loss from the tube is 21.1 W.
How to solve this problem ?First we can use the formula for heat energy (Q) to solve this problem:
Q = m * c * ΔT
Where
Q is the heat energy transferredm is the mass of the water flowing through the tube per unit timec is the specific heat capacity of waterΔT is the change in temperature of the waterFor the first scenario, we have:
m = 0.1500 kg/m
Q = 25.2 W
ΔT = 17.4 °C - 15.2 °C = 2.2 °C
Substituting these values into the formula, we get:
25.2 W = 0.1500 kg/m * c * 2.2 °C
c = 960 J/(kg·°C)
Therefore, the specific heat capacity of water is 960 J/(kg·°C).
For the second scenario, we have:
m = 0.2318 kg/m
Q = 37.8 W
ΔT = 17.4 °C - 15.2 °C = 2.2 °C
Substituting these values into the formula, we get:
37.8 W = 0.2318 kg/m * 960 J/(kg·°C) * 2.2 °C + P
Where
P is the rate of heat loss from the tubeSimplifying, we get:
P = 37.8 W - 0.2318 kg/m * 960 J/(kg·°C) * 2.2 °C
P = 21.1 W
Therefore, the rate of heat loss from the tube is 21.1 W.
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How much momentum does a 2500 kg mass moving at21. m/s have?kg*m/s (Round to 2 significant figures)
The momentum can be calculated with the following formula:
\(p=mv\)Where m is the mass and v is the velocity.
So, for m = 2500 kg and v = 21 m/s, we have:
\(\begin{gathered} p=2500\cdot21 \\ p=52500 \end{gathered}\)Rounding to 2 significant figures, we have a momentum of 53000 kg*m/s
A particle starts with a speed of 12m/s and moves in a straight line in such a way that its speed increases by 4m/s every second. Find the speed of the particle just after 8 seconds.
Answer:
44m/s is the speed of that particle after 8 seconds
can an object have kinetic energy if there is no motion.
No. The object has to have motion for it to have kinetic energy.
which type of energy is the energy of a moving tennis ball
Answer:
Kinetic energy.
The explanation never existed
Answer: Kinetic Energy
An iron ball weighs 80 N on the surface
of Earth. How much will it weigh after
being moved to a height equal to the
radius of the Earth?
Answer:
2√5N will be the weight.
Explanation:
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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1. (2) Which quantum state can not exist?
A
(1, 0, 0, 1/2)
B
(2, 0, 0, -1/2)
c
(2, 1, 0, 1/2)
D
(2,0, 1, -1/2)
Answer:
A
Explanation:
(A is the quantium state which cannot exist
3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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A dinner plate falls vertically to the floor and breaks up into three pieces, which slide horizontally along the floor. Immediately after the impact, a 320-g piece moves along the x-axis with a speed of 2.00 m/s and a 355-g piece moves along the y-axis with a speed of 1.50 m/s. The third piece has a mass of 100 g. In what direction relative to the x-axis does the third piece move
Answer:
Explanation:
There will be conservation of momentum along horizontal plane because no force acts along horizontal plane.
momentum of first piece = .320 kg x 2 m/s
= 0.64 kg m/s along x -axis.
momentum of second piece = .355 kg x 1.5 m/s
= 0.5325 kg m/s along y- axis .
Let the velocity of third piece be v and it is making angle of θ with x -axis .
Horizontal component of its velocity = .100 kg x v cosθ = .1 v cosθ
vertical component of its velocity = .100 kg x v sinθ = .1 v sinθ
For making total momentum in the plane zero
.1 v cosθ = 0.64 kg m/s
.1 v sinθ = 0.5325 kg m/s
Dividing
Tanθ = .5325 / .64 = .83
θ = 40⁰.
The angle will be actually 180 + 40 = 220 ⁰ from positive x -axis.
Answer:
8.3 m/s, 2196 degree from + X axis
Explanation:
m = 320 g , u = 2 m/s along X axis
m' = 355 g, u' = 1.5 m/s along Y axis
m'' = 100 g, u'' = v
Let the speed of the third piece is v makes an angle A from the X axis.
use conservation of momentum along X axis
0 = 320 x 2 + 100 x v cos A
v cos A = - 6.4 ..... (1)
Use conservation of momentum along Y axis
0 = 355 x 1.5 + 100 x v sin A
v sinA = - 5.3 ... (2)
Squaring and adding
\(v^2 = (-6.4)^2 +(-5.3)^2\\\\v= 8.3 m/s\)
The angle is given by
\(tan A = \frac{-5.3}{-6.4}\\\\A = 219.6 degree\) from + X axis
You put your book on the bus seat next to you. When the bus stops suddenly the book slides forward off the seat. Why?
A.) The book received a push from the seat hitting it.
B.) The force applied by the bus caused it to accelerate forward.
C.) The book's inertia carried it forward.
D.) The book could never slide forward to begin with.
Answer:
C) The book's inertia carried it forward.
When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.
state the two motion equations.
Answer:
Equations of motion relate the displacement of an object with its velocity, acceleration and time. s=vt where s is the displacement, v the (constant) speed and t the time over which the motion occurred. ...
Displacement with negative acceleration: s, equals, v, t, minus, one half, a, t, square...
Displacement with positive acceleration: s, equals, u, t, plus, one half, a, t, squared,s...
Velocity squared: v, squared, equals, u, squared, plus, 2, a, s,v2=u2+2as
Velocity: v, equals, u, plus, a, t,v=u+at
9. If you increase the velocity of an object moving in a circle, does it require more centripetal
force or less?
Yes, more centripetal force is required to to sustain an object in circular motion that is moving at a greater velocity.
Answer:
Explanation:
Force:
Fₙ = m*V² / R
m - const
R - const
V ↑
Fₙ ↑
The drawing shows an arrangement in which a block (mass = 21.6 kg) is held in position on a frictionless incline by a cord (length = 0.700 m). The mass per unit length of the cord is 0.960 x 10-2 kg/m so the mass of the cord is negligible compared to the mass of the block. The cord is being vibrated at a frequency of 142 Hz (vibration source not shown in the drawing). What is the maximum value of the angle ?in degrees at which a standing wave pattern exists on the cord?
The value of θ does not exist for the given data in the above problem as the sin θ value is not in range.
Given that,
Frequency of the cord = 142 Hz
Mass of the block = 21.6 kg
Length of the cord = 0.7 m
Density μ = 0.96* 10⁻² kg/m
The tension opposing the movement of the block is given by,
T = W sinθ = m* g sin θ = 21.6* 9.81 sin θ = 211.9 sin θ ----(1)
We know the formula for the frequency of the stretched string as,
f = 1/(2L)* (√T/μ)
Substituting the values in the above equation, we have,
142 = 1/(2* 0.7)* [√(211.9*sin θ)/(0.96* 10⁻²)]
142 = 1/(1.4)* [148.57√sin θ]
(142* 1.4)/148.57 = √sin θ
√sin θ = 1.34
sin θ = 1.8
The range of sin θ -1 ≤ y ≤ 1.
So, the θ does not exist.
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. Acylinder contains 1 mole of oxygen at
a temperature of 27 °C. The cylinder
is provided with a frictionless piston
which maintains a constant pressure
of 1 atm on the gas. The gas is heated
until its temperature rises to 127 °C.
(a) How much work is done by the
piston in the process?
(b) What is the increase in internal
energy of the gas?
(c) How much heat was supplied
to the gas?
(C = 7.03 calmol-¹°C¯¹;
R = 1.99 calmol-¹°C-¹;
1cal = 4.184 J)
a}The work is done by the piston in the process is 199 cal.
b) The increase in internal energy of the gas is 703 cal
c) The heat was supplied to the gas is 3771 J
(a) To calculate the work done by the piston, we can use the formula:
Work = P * ΔV
Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:
Work = P * (\(V_2 - V_1\))
Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:
PV = nRT
\(V_1 = (nRT_1) / P_1\)
\(V_2 = (nRT_2) / P_2\)
Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).
Substituting the values into the equation, we have:
V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal
V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal
Therefore, the work done by the piston is:
Work = 1 atm * (796 cal - 597 cal) = 199 cal
(b) The increase in internal energy of the gas can be calculated using the equation:
ΔU = n * C * ΔT
Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).
Substituting the values into the equation, we have:
ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal
(c) The heat supplied to the gas can be calculated using the equation:
Q = ΔU + Work
Substituting the values calculated in parts (a) and (b), we have:
Q = 703 cal + 199 cal = 902 cal
Since 1 cal = 4.184 J, the heat supplied to the gas is:
Q = 902 cal * 4.184 J/cal ≈ 3771 J
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an object with an initial velocity of 5m/s has a constant acceleration of 2m/s2 when it is speed is 15m/s how far has us travelled
An object with an initial velocity of 5m/s has a constant acceleration of \(2m/s^2\) .The object has traveled a distance of 50 meters when it is speed is 15m/s how far has us travelled
To find the distance traveled by the object, we can use the equation:
\(v^2 = u^2 + 2as\)
where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.
Given:
Initial velocity (u) = 5 m/s
Acceleration (a) = 2\(m/s^2\)
Final velocity (v) = 15 m/s
We need to solve for s.
Rearranging the equation, we have:
s =\((v^2 - u^2)\) / (2a)
Substituting the given values, we get:
s = \((15^2 - 5^2)\)/ (2 * 2)
s = (225 - 25) / 4
s = 200 / 4
s = 50 m
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A cyclist and his bicycle have a combined mass of 88 kg and a combined
weight of 862.4 N. The cyclist accelerates at 1.2 m/s2. After 2 seconds he
reaches a speed of 2.4 m/s. What is his momentum at this point?
A. 36.7 kg m/s
B. 359.3 kg:m/s
C. 105.6 kg-m/s
D. 211.2 kg:m/s
The cyclist accelerates at 1.2 m / s² after 2 seconds he reaches a speed of 2.4 m / s, then the momentum at this point would be 211.2 kg-m/s, therefore the correct answer is option D.
What is momentum?It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.
As given in the problem a cyclist and his bicycle has a combined mass of 88 kg and a combined weight of 862.4 N. The cyclist accelerates at 1.2 m/s2. After 2 seconds he reaches a speed of 2.4 m/s.
The momentum of the cyclist = 88 × 2.4
= 211.0 kgm/s
Thus, the momentum of the cyclist would be 211.0 kgm/s.
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Looking at the position of the house and the tree, if the man ran starting from the house going
to
the tree in 8 seconds, the average velocity would be?
Average velocity of man is 2 m/s
Given that;
Distance between tree and house = 16 m
Time taken = 8 seconds
Find:
Average velocity
Computation:
Average velocity = Total distance cover / Time taken
Average velocity = Distance between tree and house / Time taken
Average velocity = 16 / 8
Average velocity = 2 m/s
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A chopper’s speed increases from 35 m/s to 60 m/s in 5 seconds. What is the acceleration of this helicopter?
A chopper’s speed increases from 35 m/s to 60 m/s in 5 seconds. Therefore, the acceleration of this helicopter is 5m/s².
What do you mean by an acceleration ?The term an acceleration is the name we supply to any process where the velocity changes.
Therefore, velocity is a speed and a direction, there are only two ways for you to accelerate is change your speed or change your direction or change both.
Given:
Initial speed = 35 m/s
Final speed = 60 m/s
Time = 5 s
v = u + at
60 = 35 + a(5)
60 - 35 = 5a
25 = 5a
a = 5
Thus, the acceleration of this helicopter is 5m/s².
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A pitching machine is programmed to pitch baseballs horizontally at a speed of 134 km/h. The machine is mounted on a truck and aimed forward. As the truck drives toward you at a speed of 85 km/h, the machine shoots a ball toward you. A pickup truck moves to the left at a constant velocity. A pitching machine sits in the bed of the pickup truck. The pitching machine launches a baseball to the right with a different constant velocity. A man with a baseball mitt stands at rest some distance to the right of the truck. For each of the object pairings listed, determine the correct relative speed. The speed of the pitching machine relative to the truck The speed of the pitched ball relative to the truck The speed of the pitching machine relative to you The speed of the pitched ball relative to you
Answer: 134 = 143 = 151 = 166 = 176
Hope this helps!!
Sorry if it's incorrect!!
:'(
A student repeats a reaction several times to test the effects of various
changes on the reaction rate. The data table shows the results. How does
increasing the temperature of the system change thereaction rate?
A. Increasing the temperature decreases the reaction rate.
B. Increasing the temperature increases the reaction rate.
C. More information is needed to determine what happens to the reaction rate.
D. Increasing the temperature has no effect on the reaction rate.
Answer:
B. Increasing the temperature increases the reaction rate.
Explanation:
This is as with a higher temperature the particles have more kinetic energy, this is the consequece of the increase in reaction rate as the frequency of particles colliding is increased.
Answer: B
Explanation:
A system consists of two uncharged metal spheres, each suspended on an insulating string and connected to the other by a thin
conducting wire. A positively charged rod is brought near, but does not touch, the left sphere, and the sphere is attracted to the rod. Which
of the following is correct about the net charge on the right sphere as a result?
The right sphere will acquire an equal and opposite net positive charge to balance the negative charge on the left sphere.
Electrostatic attractionSince the left sphere is attracted to the positively charged rod, it means that the left sphere acquires a temporary negative charge due to induction.
The positive charge on the rod repels electrons in the left sphere, causing them to move away from the rod side and accumulate on the opposite side, resulting in a net negative charge on the left sphere.
According to the principle of charge conservation, the net charge on the system must remain zero. Therefore, the right sphere acquires an equal and opposite net positive charge to balance the negative charge on the left sphere.
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Several planets in our solar system have a magnetosphere. Describe what is required, in general, for a magnetosphere to exist (not just Earth). Also comment on what you see as the impact to us if we had no magnetosphere.
Answer:
The formation of a magnetosphere requires that the dipolar field is strong enough for the obstacle effective size to be larger (Dp > 20λi) than ion scales. In this case, a bow shock, magnetosheath, and magnetospheric system are driven, and the flow is modified far upstream.
what exercises most beneficial for your overall health
Answer:
Endurance, or aerobic
Strength, or resistance training
Balance
Flexibility
Explanation:
Answer:
Walking. Walking is simple, yet powerful. It can help you stay trim, improve cholesterol levels, strengthen bones, keep blood pressure in check, lift your mood, and lower your risk for a number of diseases (diabetes and heart disease, for example).
The components of the displacement A
are A=-1.00 m and A-1.732 m. Find
the magnitude of A
OA 1.90m
O B.2.00 m
OC. 2.30 m
O D. 1.00 m
Answer:1.93
Explanation:
The magnitude of a vector can be found using the Pythagorean theorem, where the components of the vector are the sides of a right triangle.
In this case, the components of displacement vector A are given as A = -1.00 m and A-1.732 m.
The magnitude of A can be calculated as follows:
A = √(-1.00 m)^2 + (1.732 m)^2 = √3.732 m^2 = 1.93 m
So, the magnitude of displacement vector A is 1.93 m.
The values of A, B, C, and D are not related to the displacement vector A, so they cannot be used to find the magnitude of A.
What force (in N) must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2100 kg car (a large car) resting on the slave cylinder
Complete Question:
What force (in N) must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2100 kg car (a large car) resting on the slave cylinder ? The master cylinder has a 2.00-cm diameter and the slave has a 24.0-cm diameter
Answer:
\(F_1 = 142.92N\)
Explanation:
Given
\(m = 2100kg\) --- mass
\(D_1 = 2.00\ cm\) --- diameter of the large cylinder
\(D_2 = 24.0\ cm\) --- diameter of the slave cylinder
To do this, we apply Archimedes' principle of buoyancy which implies that:
\(P = \frac{F_1}{A_1} = \frac{F_2}{A_2}\)
Where
\(F_1 = Force\ on\ the\ master\ cylinder\)
\(F_2 = Force\ on\ the\ slave\ cylinder\)
\(A_1 = Area\ of\ the\ master\ cylinder\)
\(F_2 = Area\ of\ the\ small\ cylinder\)
Calculating the area of the master cylinder.
\(A_1 = \pi r_1^2\)
\(r_1 = \frac{1}{2}D_1 = \frac{1}{2} * 2.00cm = 1.00cm\)
\(A_1 = \pi* 1^2\)
\(A_1 = \pi * 1\)
\(A_1 = \pi\)
Calculating the area of the slave cylinder.
\(A_2 = \pi r_2^2\)
\(r_2 = \frac{1}{2}D_2 = \frac{1}{2} * 24.00cm = 12.00cm\)
\(A_2 = \pi* 12^2\)
\(A_2 = \pi* 144\)
\(A_2 = 144\pi\)
Substitute these values in:
\(P = \frac{F_1}{A_1} = \frac{F_2}{A_2}\)
\(\frac{F_1}{\pi} = \frac{F_2}{144\pi}\)
Multiply both sides by \(\pi\)
\(\pi * \frac{F_1}{\pi} = \frac{F_2}{144\pi} * \pi\)
\(F_1 = \frac{F_2}{144}\)
The force exerted on the slave cylinder (F2) is calculated as:
\(F_2 = mg\)
\(F_2 = 2100 * 9.8\)
\(F_2 = 20580\)
Substitute 20580 for F2 in \(F_1 = \frac{F_2}{144}\)
\(F_1 = \frac{20580}{144}\)
\(F_1 = 142.92N\)
Hence, the force exerted on the master cylinder is approximately 142.92N
Which piece of evidence, if found to be true, would disprove the current theory of Mercury's formation?
O Certain impact craters on the surface of Mercury are as old as the planet itself.
O Debris in the inner planets region appears to have come from Mercury's original crust.
O Tectonic motion on Mercury is driven by the planet's shrinking size.
O The crust on Mercury is younger than the crust on Mars or Venus.
The crust on Mercury is younger than the crust on Mars or Venus.
option D.
What theory of mercury formation?
If the evidence that the crust on Mercury is younger than the crust on Mars or Venus is found to be true, it would disprove the current theory of Mercury's formation.
The current theory proposes that Mercury was formed from the solar nebula, which led to the differentiation of its core and mantle. This theory suggests that Mercury's crust should be older than that of Mars or Venus since Mercury is the closest planet to the Sun and should have formed first.
Therefore, if it is discovered that the crust on Mercury is younger than the crust on Mars or Venus, it would be inconsistent with the current theory of Mercury's formation.
A, B, and C are not relevant to Mercury's formation theory as they do not directly relate to the processes that occurred during the planet's formation.
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Answer:
A-certain impact crators on the surface of Mercury are as old as the planet itself.
Explanation:
Edmentum
In an investigation, the atoms of a certain substance lose energy during a change of state. Before the change, the atoms are far apart and move constantly at high speeds and in all directions. After the change, the atoms are close together but are able to slide past one another. Use the diagram that shows changes of state between solid, liquid, and gas to answer the question. A diagram has a triangle at center with gas on top, liquid on bottom right, solid on bottom left. An arrow from gas to liquid is labeled O, and an arrow from liquid to gas is labeled N. An arrow from solid to liquid is labeled P, and an arrow from liquid to solid is labeled Q. An arrow from solid to gas is labeled L, and an arrow from gas to solid is labeled M. Which arrow represents the substance’s change of state? L N O P
The arrow that represents the change of state of the substance is gaseous to liquid (O).
What is change of state?A change of state occurs when a matter gains or losses energy.
A liquid can change into solid or gas. A gas change into liquid or solid, depending on the average change in temperature.
Change of state of gaseous substanceThe initial state of the substance is gas, because the atoms of the substance are far apart.
When the atoms are close together but are able to slide past one another, the state is liquid.
Note: atoms of solid substance are fixed.
Thus, the arrow that represents the change of state of the substance is gaseous to liquid (O).
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Considering the investigation and the observation made we can say the arrow that represents the change of state is: O
Meaning Change of state from gas to liquidA change of state is the process by which a matter changes from one physical form to another.
in change of state we have mainly three states: Liquid, Gas and Solid.
Changing from gas to liquid is called condensation, because the atoms of gases move freely and faster. but once the speed reduces and their movement becomes restricted, then we say a condensation has occurred.
In conclusion, from the observation made, we can say the arrow that represents the change is Arrow O. which is from gas to liquid.
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A spring has a force constant of 570.8 N/m. Find the potential energy stored in the spring when the spring is
Given that,
The force constant of a spring, k = 570.8 N/m
It is stretched 4.12 cm from the equilibrium.
To find,
The potential energy stored in the spring.
Solution,
The potential energy stored in the spring is given by the formula as follows :
\(E=\dfrac{1}{2}kx^2\)
Put all the given values,
\(E=\dfrac{1}{2}\times 570.8 \times (4.12\times 10^{-2})^2\\\\E=0.484 J\)
So, the required potential energy is 0.484 J.
Why is it that when riding in a car, you don't feel like you're moving?
This may shock you:
We NEVER feel speed, velocity, or motion, as long as it's constant.
We only feel CHANGES in speed, velocity, or motion.
That means speeding up, slowing down, or changing direction.
As long as we're moving in a straight line at a constant speed, we don't feel anything.