a 50kg astronaut is training in human centrifuge to prepare for a launch. the astronaut uses the centrifuge to practice having a 5.20g force (5.20 times his own weight) on his back.

Answers

Answer 1

A 50kg astronaut practising in a human centrifuge to get ready for a launch will experience a net centripetal force of 2499N. The astronaut practises being supported by a 5.20g strain on his back.

A force that causes a body to follow an arc is known as a centripetal force (from the Latin centrum, "centre," and petere, "to pursue"). It always moves in the opposite direction of the body's motion and in the direction of the immediate centre of the path's curvature. It was defined as "a force by which bodies are attracted, compelled, or gravitate, towards a point as to a centre" by Isaac Newton.

Net centripetal force = 5.10 * 50 * 9.8 = 2499 N

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The complete question is-

a 50kg astronaut is training in human centrifuge to prepare for a launch. the astronaut uses the centrifuge to practice having a 5.20g force (5.20 times his own weight) on his back. Find the net centripetal force?


Related Questions

A surface on which all points are at the same potential is referred to as
A a constant electric force surface
B a constant electric field surface
C an equipotential surface
D an equivoltage surface

Answers

A surface on which all points are at the same potential is referred to as equipotential surface.

When all of the points on a surface have the same electric potential, the surface is said to have an equipotential potential.

An equipotential surface is a surface on which all points are at the same potential. It is a surface of constant potential and a surface where the electric field is always perpendicular to it. It does not necessarily imply a constant electric field, just a constant potential.

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If 7kg of onions costs 140 rupees then how much would we pay for 12kg of onions?

Answers

Answer:

240 rupees

Explanation:

As 7 kg of onions costs 140 rupees, each kg costs 20 rupees, and 12x20=240 rupees.

Answer:  7kg = 140 Rupees. Now we had the cost of one onion is 20 Rupees. = 240 Rupees.

Two out of phase loudspeakers are some distance apart. A person stands 5.40 m from one speaker and 2.70 m from the other. What is the fourth-lowest frequency at which constructive interference will occur? The speed of sound in air is 340 m/s.

Answers

Two out of phase loudspeakers are some distance apart. The third lowest frequency is 377.78 Hz.

Distance of person from one speaker = 5.4 m

Distance of person from the other = 2.7 m

The longest wavelength has the shortest frequency.

We need to calculate the difference between the speakers.

The difference between the speakers = 5.4 - 2.7 = 2.7 m

We know that, the longest wavelength is such one wavelength

λ = d

So, the third longest wavelength is

3* λ = d

Put the value of d,

λ = 2.7/3 = 0.9 m

Now, let us calculate the lowest frequency.

We know the expression for frequency as,

f = v / λ = 340/0.9 = 377.78 Hz.

Thus, the third lowest frequency is 377.78 Hz.

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An air puck of mass m1 = 0.21 kg is tied to a string and allowed to revolve in a circle of radius R = 0.9 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of m2 = 1.0 kg is tied to it (see the figure below). The suspended mass remains in equilibrium while the puck on the tabletop revolves.

Answers

The speed of the puck is 3.67 m/s.

To find the speed of the puck, we can use the concept of centripetal force. The tension in the string provides the necessary centripetal force to keep the puck moving in a circle. At the same time, the tension in the string also supports the weight of the suspended mass.

Using Newton's second law, we can write two equations of motion: one for the puck and one for the suspended mass. For the puck, the net force acting on it is the tension in the string, which is equal to the centripetal force required to keep it moving in a circle. Thus, we can write:

= m1 * v^2 / R

where T is the tension in the string, v is the speed of the puck, and R is the radius of the circle.

For the suspended mass, the net force acting on it is its weight minus the tension in the string, which must be zero since the mass is in equilibrium. Thus, we can write:

T = m2 * g

where g is the acceleration due to gravity.

Combining these two equations, we can solve for the speed of the puck:

v = sqrt(T * R / m1) = sqrt(m2 * g * R / m1)

Substituting the given values, we get:

v = sqrt(1.0 kg * 9.81 m/s^2 * 0.9 m / 0.21 kg) = 3.67 m/s

Therefore, the speed of the puck is 3.67 m/s.

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A car travels 20 Km north. It then turns around and travels 30 Km south. what is the resultant displacement and distance covered by the car ?

Answers

Answer:

The distance is 50km and the displacement is 10km south

Explanation:

For the distance, you just have to add and for the displacement, it's saying how far are you from your starting point. If you go forward 20 ad backwards 30, your result is -10 but distance can't be negative so it's 10

the answer is 10. 30-20= 10 and they’re going backwards so there’s more land the care is going over because they went 10 more kilometers south

I put Frank at a position directly between the Earth and the Moon such that he is stuck there at rest…equally pulled in two wdirections. I then make the moon disappear. How fast is Frank moving when he hits the Earth? You may assume there is no air friction when he re-enters the atmosphere

Answers

Frank would be moving at approximately 86,784 meters per second (m/s) when he hits the Earth.

In the scenario you described, Frank is initially placed at rest in a position directly between the Earth and the Moon, being equally pulled by their gravitational forces. When the Moon disappears, the only gravitational force acting on Frank is the Earth's gravitational pull.

As there is no air friction in this scenario, Frank would fall freely toward the Earth, accelerating under the influence of the Earth's gravity. The acceleration due to gravity near the surface of the Earth is approximately 9.8 meters per second squared (m/s²).

To determine the speed at which Frank hits the Earth, we need to know the distance between Frank and the Earth. If we assume Frank is initially positioned at the Earth-Moon distance (approximately 384,400 kilometers), we can calculate his speed when he reaches the Earth's surface using the laws of motion.

Using the kinematic equation:

v² = u² + 2as

where:

v = final velocity (speed when Frank hits the Earth)

u = initial velocity (zero in this case, as Frank is initially at rest)

a = acceleration due to gravity (9.8 m/s²)

s = distance fallen (Earth-Moon distance)

Converting the Earth-Moon distance to meters:

s = 384,400,000 meters

Plugging the values into the equation:

v² = 0 + 2 * 9.8 m/s²* 384,400,000 m

v²= 7,528,480,000 m²/s²

Taking the square root of both sides:

v ≈ 86,784 m/s

Therefore, When Frank collides with the Earth, he will be traveling at a speed of approximately 86,784 meters per second (m/s).

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Radio waves travel at the speed of light. What is the wavelength of a radio signal with a frequency of 9.45 x 10^7 Hz?

Answers

The wavelength of this radio signal is equal to 3.18 meters.

Given the following data:

Frequency = \(9.45 \times10^7\) Hz.Speed of light = \(3 \times 10^8\) m/s.

What is wavelength?

Wavelength can be defined as the distance between two (2) successive crests (troughs) of a wave.

How to calculate wavelength.

Mathematically, the wavelength of a wave is given by this formula:

\(\lambda = \frac{V}{F}\)

Where:

F is the frequency of a wave.V is the speed of a sound wave.\(\lambda\) is the wavelength of a sound wave.

Substituting the given parameters into the formula, we have;

\(\lambda = \frac{3 \times 10^8}{9.45 \times10^7}\)

Wavelength = 3.18 meters.

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The wavelength of the radio signal travel at speed of light is 3.17m.

Given the data in the question;

Frequency of the radio wave; \(f = 9.45 * 10^{7}Hz = 9.45 * 10^{7} s^{-1}\)Wavelength of a radio signal; \(\lambda = \ ?\)

Wavelength

Wavelength the spatial period of a periodic wave. That is to say, when the shapes of waves are Wavelength , the distance over which they are repeated is called wavelength. Wavelength  is expressed as;

\(\lambda = \frac{v}{f}\)

Where \(\lambda\) is wavelength, f is the frequency of the wave and c is the velocity or speed of light ( \(c = 3*10^8m/s\) )

We substitute our values into the expression above.

\(\lambda = \frac{c}{ f}\\ \\\lambda = \frac{3*10^8m/s}{9.45*10^7s^{-1}} \\\\\lambda = \frac{3*10^8ms/s}{9.45*10^7}\\\\\lambda = 3.17m\)

Therefore, the wavelength of the radio signal travel at speed of light is 3.17m.

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A stunt car traveling at 20 m/s flies horizontally off a cliff and lands 39.2 m from the base of the cliff. How tall is the cliff?

Answers

Answer:

18.82 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 20 m/s

Horizontal distance (s) = 39.2 m

Height (h) of the cliff =?

Next, we shall determine the time taken for the car to get to the ground. This can be obtained as follow:

Initial velocity (u) = 20 m/s

Horizontal distance (s) = 39.2 m

Time (t) taken to reach the ground =?

s = ut

39.2 = 20 × t

Divide both side by 20

t = 39.2 / 20

t = 1.96 s

Finally, we shall determine the height of the cliff as follow:

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) taken to reach the ground = 1.96 s

Height (h) of the cliff =?

h = ½gt²

h = ½ × 9.8 × 1.96²

h = 4.9 × 3.8416

h = 18.82 m

Therefore, the cliff is 18.82 m high

A Ping-Pong ball is shot into a circular tube that is lying flat (horizontal) on a table-top.
Figure attached.

When the Ping-Pong ball exits the tube, which path will it follow in the figure?
d
a
c
b
e

Answers

Answer:

e

Explanation:

URGENT 50 POINTS
Show all Steps of your work.
7. Mohammed whose mass is 50kg swings back and forth on a long vine makes an angle 45 from the vertical resting position. His friend Abdella notices in amazement that he makes 30 complete swings in 2.0 minuies.
(a) What is the frequency (in hertz) of Tarzan's swing?
(b) What is the period of oscillation?
(c) How long is the vine he is using?
(d) Calculate the Restoring force on Mohammed?

Answers

The frequency of oscillation of the swing is 0.25 Hz.

The time period of oscillation of the swing is 4 s.

The length of the vine of the swing is 3.97 m.

The restoring force acting on Mohammed is 692.9 N.

Mass of Mohammed, m = 50 kg

Angle made by the vine with the vertical, θ = 45°

Number of complete swings made by Mohammed, n = 30

Time taken for this swing, t = 2 minutes = 120 seconds

a) The frequency of the swing is defined as the number of complete oscillations in one second.

So, the frequency of oscillation of the swing is,

f = n/t

f = 30/120

f = 0.25 Hz

b) The time period of oscillation of the swing is,

T = 1/f

T = 1/0.25

T = 4 s

c) The expression for the time period is given by,

T = 2π√(l/g)

T² = 4π² x (l/g)

l/g = T²/4π²

Therefore, the length of the vine of the swing is,

l = T²g/4π²

l = 4² x 9.8/4 x (3.14)²

l = 3.97 m

d) The restoring force acting on Mohammed,

F = mg sinθ

F = 50 x 9.8 x sin 45°

F = 490 x 1/√2 = 490/1.414

F = 692.9 N

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Which vector is the sum of vectors à and b?

Answers

The vectors addition permits locating the perfect result for the sum of the two vectors in option B).  See attached and the vector is directed to the right and up.

Vector addition is the operation of adding or extra vectors together into a vector sum. The so-known as parallelogram regulation gives the rule for vector addition of or greater vectors. for two vectors and, the vector sum is received via placing them head to tail and drawing the vector from the loose tail to the unfastened head.

A vector is an amount or phenomenon that has impartial residences: importance and direction. The time period also denotes the mathematical or geometrical representation of the sort of quantity. Examples of vectors in nature are velocity, momentum, force, electromagnetic fields, and weight.

Vectors are used in technological know-how to describe something that has a direction and a magnitude. they're commonly drawn as pointed arrows, the length of which represents the vector's importance

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Which vector is the sum of vectors à and b?

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Which vector is the sum of vectors and b?

pls help!!

An object is placed 3.0 cm away from a convex lens of focal length 2.0 cm as shown in fig.


1. Use the lens equation to calculate the image distance.

2. Is the image real or virtual? how do you know ?

pls help!!An object is placed 3.0 cm away from a convex lens of focal length 2.0 cm as shown in fig.

Answers

(1) The distance of the image formed by the lens is determined as 6 cm.

(2) The image formed is real.

What is the image distance?

The distance of the image formed by the lens is calculated by applying the following formula as follows;

1/f = 1/v + 1/u

where;

v is the image distanceu is the object distancef is the focal length of the lens

The distance of the image formed by the lens is calculated as;

1/v = 1/f - 1/u

1/v = 1/2 - 1/3

1/v = 1/6

v = 6 cm

Since the sign of the image of the image is positive, the image formed is real.

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8. Combine the ice and the room-temperature water. Stir the mixture until the thermometer stays at the
same temperature for at least 1 minute. This means the thermometer is at the same temperature as the
mixture.
9. Record the temperature.
10. Stir the ice-water mixture occasionally for another 5 minutes. Then, record its temperature.
Table B: Part 2 Observations
Initial temperature (in "C) of the room-temperature water
Initial temperature (in "C) of the warm water
Temperature (in "C) of mixed warm water and room-temperature water
Temperature (in "C) of mixed warm water and room-temperature water after 5 min
Temperature (in "C) of mixed warm water and room-temperature water after 10 min
Initial temperature (in "C) of the ice
Temperature (in °C) of mixed ice and room-temperature water
Temperature (in "C) of mixed ice and room-temperature water after 5 min
Physical Science page

8. Combine the ice and the room-temperature water. Stir the mixture until the thermometer stays at thesame

Answers

The answer for the experiment is obtained by the principle of Newton's law of cooling. The initial temperature of the Room is taken as 32°C.

The ice cubes are mixed with room-temperature water, the ice starts to melt and the water becomes cold. This is because the ice and water have two different temperatures and when they are mixed there is an exchange of heat is taken place. When the ice cubes mixed with water the room temperature is decreases from 32°C. After stirring the mixture because of the heat released, the temperature increases.

When the ice-water mixture is stirred, the heat energy is evolved which melts the ice in the mixture, and therefore the temperature increases gradually. And stirring of water for every 5 minutes leads ice cubes to melt completely to form water and the level of water increases in the final stage. This was given by Newton's law of cooling.

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Use Kepler's third law to determine how many days it takes a spacecraft to travel in an elliptical orbit from a point 6 590 km from the Earth's center to the Moon, 385 000 km from the Earth's center.

Answers

Answer:

1.363×10^15 seconds

Explanation:

The spaceship travels an elliptical orbit from a point of 6590km from the earth center to the moon and 38500km from the earth center.

To calculate the time taken from Kepler's third Law :

T^2 = ( 4π^2/GMe ) r^3

Where Me is the mass of the earth

r is the average distance travel

G is the universal gravitational constant. = 6.67×10-11 m3 kg-1 s-2

π = 3.14

Me = mass of earth = 5.972×10^24kg

r =( r minimum + r maximum)/2 ......1

rmin = 6590km

rmax = 385000km

From equation 1

r = (6590+385000)/2

r = 391590/2

r = 195795km

From T^2 = ( 4π^2/GMe ) r^3

T^2 = (4 × 3.14^2/ 6.67×10-11 × 5.972×10^24) × 195795^3

= ( 4×9.8596/ 3.983×10^14 ) × 7.5059×10^15

= 39.4384/ 3.983×10^14 ) × 7.5059×10^15

= (9.901×10^14) × 7.5059×10^15

T^2 = 7.4321× 10^30

T =√7.4321× 10^30

T = 2.726×10^15 seconds

The time for one way trip from Earth to the moon is :

∆T = T/2

= 2.726×10^15 /2

= 1.363×10^15 secs

What is the average acceleration of an
automobile moving from 0 to 60 m/s in 3.0
seconds?
a. 90 m/s²
b. -20 m/s²
c. -90 m/s²
d. 20 m/s²

Answers

Answer:

D

Explanation:

Using the formula for average acceleration, which is:

average acceleration = (final velocity - initial velocity) / time

Where the initial velocity is 0 m/s and the final velocity is 60 m/s, and the time is 3 seconds, we get:

average acceleration = (60 m/s - 0 m/s) / 3 s = 20 m/s²

Therefore, the answer is (d) 20 m/s².

The figure shows the system of three very thin conductors, loaded with charges of constant longitudinal density. The third conductor with longitudinal charge Q is placed on the x axis . Determine the position of the load, so that the force acting on its maximum.

The figure shows the system of three very thin conductors, loaded with charges of constant longitudinal

Answers

The system of three very thin conductors, loaded with charge density. There is surface charge on any steady current carrying conductor of uniform conductivity (i.e. the conducting wires for a simple battery resistor circuit). This surface charge is required in order to ensure that the electric field within the conducting wires is such that we have a steady uniform current throughout the circuit.

What is Charge Density?

Charge density is a measure of charge per unit area of ​​a surface or per unit volume of an object or field. Charge density indicates how much charge is stored in a particular field. Charge density can be determined by volume, area, or length.

Therefore, The system of three very thin conductors, loaded with charge density. There is surface charge on any steady current carrying conductor of uniform conductivity (i.e. the conducting wires for a simple battery resistor circuit). This surface charge is required in order to ensure that the electric field within the conducting wires is such that we have a steady uniform current throughout the circuit.

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How many significant figures does the following number have: 0.002040?

Answers

Answer: 4

Explanation: because 0s aren’t significant and after the decimal point, there was to be a value greater than 0 than the rest are sig figs.

Jupiter's Great Red Spot is
1.slowly shrinking
2.a large storm
3.smaller than Saturn's spot
4.a large area of liquid hydrogen

Answers

Answer:    

2 : A large storm

Explanation: I hope this helps

An object is moving forward along a straight path. Find the object’s position relative to it’s starting point if it moves 12.8 cm/s for 0.5 min.

Answers

The distance traveled by the object from its initial position is 384 cm.

Distance is the sum of an object's movements, regardless of direction. Without respect to the object's starting or finishing positions, distance can be defined as the amount of space it has traveled.

An object is moving in a straight path.

The speed of the object from its initial position is 12.8 cm/s.

The object is moving for 05 minutes.

Then, t = 0.5 min = 0.5 × 60 = 30 seconds.

Now, the speed of an object is the distance of the object per unit time.

Therefore,

s = d / t

d = s × t

d = ( 12.8 cm/s ) × ( 30 s )

d = 384 cm

Hence, the object's position from its initial position is 384 cm.

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PLS HELP!! This question was never fully solved!

An object moving at 13 m/s has a kinetic energy of 426 J. What is the mass of the object?
1.26 kg
2.52 kg
5.04 kg
65.5 kg

Answers

To find the mass of the object, we can use the formula for kinetic energy:

Kinetic energy (KE) = (1/2) * mass * velocity^2

Given that the kinetic energy is 426 J and the velocity is 13 m/s, we can rearrange the equation to solve for the mass:

mass = (2 * KE) / (velocity^2)

Substituting the given values:

mass = (2 * 426 J) / (13 m/s)^2

mass = (2 * 426 J) / (169 m^2/s^2)

mass = 852 J / 169 m^2/s^2

mass = 5.04 kg

Therefore, the mass of the object is 5.04 kg.

The right eye and right lung are __________.

A)ipsilateral
B)lateral
C)bilateral
D)proximal

Answers

The correct answer is A) Ipsilateral

Explanation:

The term ipsilateral is commonly used to describe objects or structures that are on the same side of a body or structure. This term is correct to describe the right eye and the right lung because these two organs are on the same side of the body (the right side). This can also be used to describe other organs such as the left humerus and the left hand or the right ear and the right feet because these pairs are also on the same side. According to this, the correct answer is A.

Which elements are not noble gases?

Answers

Answer:

All the elements except for the ones on the last column (at the left of the periodic table)

Explanation:

Helium ,Neon ,Argon ,Krypton,Xenon and Radon

A rod with a length of 1.6 m is made of aluminum, which has a coefficient of linear expansion of 2.40 ✕ 10−5 (°C)−1. It is initially at a temperature of 25°C.
(a)
What is the change in length of the rod if the temperature drops to 0.0°C? (Give the absolute value in units of mm.)
mm
(b)
How does the rod's length change with lower temperature?
The rod shrinks with lower temperature.
The rod expands with lower temperature.
The rod's length does not change with lower temperature.
(c)
Find the absolute value of the fraction by which the rod's length changes between the two temperatures.

ΔL
L0

=

Answers

Answer:

(a) To calculate the change in length of the rod, we can use the formula:

ΔL = αLΔT

where:

α = coefficient of linear expansion

L = initial length of the rod

ΔT = change in temperature

Substituting the given values, we get:

ΔL = (2.40 ✕ 10^-5 (°C)^-1) x (1.6 m) x (25°C - 0.0°C)

ΔL = 0.0096 m

Converting meters to millimeters, we get:

ΔL = 9.6 mm

Therefore, the change in length of the rod is 9.6 mm.

(b) The rod shrinks with lower temperature.

(c) The absolute value of the fraction by which the rod's length changes between the two temperatures can be calculated using the formula:

ΔL

L0

where:

ΔL = change in length of the rod

L0 = initial length of the rod

Substituting the given values, we get:

ΔL

L0

= 0.0096 m / 1.6 m

= 0.006

Therefore, the absolute value of the fraction by which the rod's length changes between the two temperatures is 0.006.

the discussion section in a research report includes a summary of the findings of the study in the context of prior research and theory, an overview of study limitations, future directions, and implications.

Answers

The discussion section of a research report serves as a critical analysis of the study's results and their implications.

This section includes a summary of the study findings in relation to prior research and theory, highlighting the original contributions made by the current study. It also identifies the limitations of the study, such as sample size or design flaws, and suggests future directions for research. Finally, the discussion section analyzes the practical and theoretical implications of the findings and may recommend changes in policy or practice.

Overall, the discussion section provides a comprehensive analysis of the study results and their significance in advancing the field.

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Question 11 of 15
When hydrogen is attached to the more highly electronegative oxygen atom in
a water molecule,
A. the electronegative atom becomes strongly positive
B. the hydrogen atom becomes partially positive
O C. the oxygen atom becomes partially negative

If answer is right WILL GIVE BRAINLIEST
D. the hydrogen atom becomes partially negative

Answers

Answer:

I'm leaning twards A

Explanation:

I think B but I’m not sure

Which option correctly describes a model of methanol. URGENT

Which option correctly describes a model of methanol. URGENT

Answers

The last one.

One grey sphere, Four white spheres, and One red spheres

Question 1

Describe the path light takes as it travels through air and into glass

Question 2

Explain the brightness of light using the wave model of light

Answers

Answer:

here is answer!

Explanation:

Question 1:

Light bends when it transitions from air to glass due to differences in refractive indices. It follows an incident path in air, refracts at the air-glass boundary, and continues through the glass as a transmitted ray. Total internal reflection may occur if the angle of incidence is large enough.

Question 2:

Brightness in the wave model of light is determined by the amplitude and intensity of the light waves. Higher amplitudes and intensities correspond to brighter light. When multiple light waves overlap, their amplitudes add up, resulting in increased brightness

Question 1 :
The path light bends as it travels through air and into glass.
What is light?
The light is the ray form of energy obtained from the Sun.
The path of light will look like bended when it has crossed the interface of two medium.
As. the light ray falls on the surface of glass travelling through air, the ray appears to bend after refraction.
Thus, the path of light bends as it travels through air and into glass.
———————
Question 2 :
According to the wave theory of light, the energy of radiation depends only on the intensity or wave amplitude (brightness), not the frequency (what type of light; e.g red light or green light; visible light or gamma) According to the particle theory of light states the energy of radiation depend only on the frequency

imagine a single charge creating an electric field. what is the relationship between electric field strength and the distance from the charge?
a. direct
b. inverse
c. inverse squared
d. indirect

Answers

Answer:

b. inverse

Explanation:

\(E = \frac{V}{d} \\ d \: is \: the \: distance \\ \)

If the kinetic and potential energy in a system are equal, then the potential energy increases. What happens as a result?
-Total energy increases.
-Stored energy decreases.
-Energy of motion decreases.
-Total energy decreases.

Answers

Answer:

energy of motion decrease

Explanation:

yes

Answer:

C

Explanation:

If a 1.5-Kg physics book measures 0.260 m x 0.210 m x 0.040 m, calculate the pressure applied by the standing book on the table. (Round off answer to two sig figs)
*

Answer choices:
P = 1,600 N/m^2
P = 1,800 N/m^2
P = 1,500 N/m^2
P = 1,700 N/m^2

Answers

The pressure applied by the standing book on the table is 1,800 N/m².

option B is the correct answer.

What is the pressure applied by the book?

The pressure applied by the standing book on the table is determined from the ratio of weight of the book and the area of the standing book.

Mathematically, the formula for the pressure of a material is given as;

P = F / A

where;

F is the applied force or weight of the object standing on another surfaceA is the area of the object in contact with another surface

The weight of the book , F = mg

where;

m is the mass of the bookg is acceleration due to gravity

F = 1.5 kg  x  9.8 m/s²

F = 14.7 N

The dimension of the book include;

height of the book, h = 0.26 mwidth of the book, w = 0.21 mthickness of the book, b = 0.04 m

The height of the book is not in contact with the surface of the table, so the area of the book in contact with the table becomes;

A = w x b

W = 0.21 m  x  0.04 m

W = 8.4 X 10⁻³ m²

P = F / A

P = ( 14.7 N ) / ( 8.4 X 10⁻³ m² )

P = 1,750 N/m² ≈ 1,800 N/m²

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