A 4.86 g piece of metal is placed in a graduated cylinder containing 15.5 mL of water the water level rose to 17.3 mL what is the density of the metal

Molarity can be defined as the moles of solute in a liter of solution. The molarity of the salt solution is \(\rm \bold{3.99\;\times\;10^{-4}\;M}\).

The moles are the mass of substance with respect to the molar mass. The moles and volume relationship can be expressed in terms of molarity.

The molarity can be expressed as:

\(\rm Molarity=\dfrac{Moles}{Volume}\)

The given solution has,

Substituting the values for molarity as:

\(\rm Molarity=\dfrac{5.99\;\times\;10^{-6}}{1.50\;\times\;10^-^2\;L}\\ Molarity=3.99\;\times\;10^{-4}\;M\)

The molarity of the solution is \(\rm \bold{3.99\;\times\;10^{-4}\;M}\). Thus, option C  is correct.

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Answer:

Option C is correct

Explanation:

EDGE 2022

Explanation:

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When H₂S gas is removed from the system at equilibrium, the reaction shifts to the right (products) and the concentration of NH₃ increases (option C)

A French scientist (Chatelier) postulated a principle which helps us to understand a chemical system in equilibrium.

The principle states that If a an external constraint such as change in temperature, pressure or concentration is imposed on a system in equilibrium, the equilibrium will shift so as to neutralize the effect.

According to Chatelier's principle a decrease in concentration of the products will favor the forward (right) reaction.

From the above principle, we can conclude that when H₂S gas is removed from the system at equilibrium, the reaction shifts to the right (products) and the concentration of NH₃ increases.

Thus, the correct answer to the question is option C

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Based on the stoichiometry of the reaction, If the mass of sodium azide used was far greater than 1424 g, the volume of nitrogen gas produced will be far greater than 736 L.

However, If the mass of sodium azide used was far less than 1424 g, the volume of nitrogen gas produced will be far less than 736 L.

Sodium azide is the chemical found in automobile airbags.

Automotive air bags inflate when an electrical charge triggered by automobile impact causes sodium azide, NaN3, to rapidly decompose to its component elements, nitrogen gas and sodium

The equation of the reaction is given below:

According to the equation of reaction, 2 moles of sodium azide produces 3 moles of nitrogen gas.

1 mole of Nitrogen gas has a volume of 22.4 L

Molar mass of sodium azide is 65 g

Moles of sodium azide in 1424 g = 1424/65 = 21.9077 moles

21.9077 moles of sodium azide will produce 21.9077 * 3/2 moles of nitrogen gas = 32.86 moles of nitrogen gas

32.86 moles of nitrogen gas will occupy a volume of 32.86 * 22.4 = 736 L

If the mass of sodium azide used was far greater than 1424 g, the volume of nitrogen gas produced will be far greater than 736 L.

If the mass of sodium azide used was far less than 1424 g, the volume of nitrogen gas produced will be far less than 736 L.

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Explanation:

Concentrated solution Dilute solution

A concentrated solution is a liquid with a high solute concentration. A dilute solution is a liquid having a lower solute content.

As more solute is added to a solution, the solution becomes more concentrated. The dissolved salt in drinking water from a well is a dilute solution.

A concentrated solution contains a substantial volume of water. The concentration of a solution can be further reduced and diluted by adding more water.

The solute that would have the greatest effect on the freezing point of water is B) 4 mol CO2, which would lower the freezing point by 7.44°C. Option B

The effect of a solute on the freezing point of a solvent is described by the equation:

∆ \(T_f\)= Kf × m

Where ∆ \(T_f\)is the freezing point depression, Kf is the freezing point depression constant, and m is the molality of the solution, which is defined as the number of moles of solute per kilogram of solvent.

Since all the given options have the same number of moles of solute, the one that will have the greatest effect on the freezing point of water will be the one with the highest Kf value.

Kf values depend on the properties of the solvent, but for water, the Kf value is 1.86 °C/m.

Now, calculating the molality for each option:

A) 1 mol KBr in 1 kg of water gives a molality of 1 mol/1 = 1 m

∆ \(T_f\)= 1.86 × 1 = 1.86°C

B) 4 mol CO2 in 1 kg of water gives a molality of 4 mol/1 kg = 4 m

∆ \(T_f\)= 1.86 × 4 = 7.44°C

C) 3 mol CaF2 in 1 kg of water gives a molality of 3 mol/1 kg = 3 m

∆ \(T_f\)= 1.86 × 3 = 5.58°C

D) 2 mol CH4 in 1 kg of water gives a molality of 2 mol/1 kg = 2 m

∆ \(T_f\)= 1.86 × 2 = 3.72°C. Option B

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True. For example, the reference table of vibrational modes and their wavenumbers for several functional groups was published by the National Institute of Standards and Technology (NIST) in 1986.

This table provides information on the vibrational modes of different functional groups such as alcohols, amines, ketones, and carboxylic acids, as well as their wavenumbers. This is important for spectroscopy studies since the wavenumbers of different functional groups can be used to identify certain compounds and to study their structure.

The NIST also publishes an updated version of this table, which includes additional functional groups. This table can be used as an important reference for researchers in the field of spectroscopy.

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Answer:

covalent

Explanation:

In the event, that we use exactly 5.62 mL of hot water to dissolve benzoic acid and then try to  cool it in an ice-water bath, we can see a clear  recovery of 372 mg. Therefore, for the given question Option C is the correct answer.

The given expected recovery when 382 mg of benzoic acid is crystallized  can be calculated using the solubility of benzoic acid in water

Considering the Solubility of benzoic acid inside water at

95°C = 6.80 g/100 mL

0°C = 0.18 g/100 mL

The minimum amount of hot water required to dissolve 382 mg of benzoic acid can be calculated using

Let x be the volume of water required in mL

At the solubility of 95°C

 6.80 g/100 mL

= 382 mg / x

Calculating for x

 x = (382  x 100) / (6.80 )

= 5.62 mL

In the event, that we use exactly 5.62 mL of hot water to dissolve benzoic acid and then try to  cool it in an ice-water bath, we can see a clear  recovery of 372 mg. Therefore, for the given question Option C is the correct answer.

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The percentage of plants showing phototropism is the dependent variable, and the color of the light is the independent variable. Therefore, the correct answer is: "the percentage of plants showing phototropism is the dependent variable, and the color of the light is the independent variable."

The dependent variable is the variable that is being measured or observed, and its value depends on the independent variable, which is the variable that is being manipulated or changed in the experiment. In this experiment, the percentage of plants showing phototropism is being measured, which means that it is the dependent variable. The color of the light is being manipulated, which means that it is the independent variable.

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The oxidation number of chromium is +6. In the reaction, it is reduced, meaning its oxidation number decreases. The final oxidation number of chromium is +3.

In the reaction represented by the Cr₂O₇²⁻ ion, the element chromium (Cr) is reduced. Its oxidation number changes from +6 to +3.

In the Cr₂O₇²⁻  ion, each oxygen (O) atom has an oxidation number of -2. The overall charge of the ion is 2-, which means the total oxidation numbers of all the atoms should add up to -2. Since there are seven oxygen atoms, their total oxidation number is (-2) × 7 = -14.

To determine the oxidation number of chromium (Cr), we can set up the following equation;

2(Cr) + 7(-2) = -2

Simplifying the equation, we have;

2Cr - 14 = -2

By solving for Cr, we get;

2Cr = 12

Cr = 6

Initially, the oxidation number of chromium is +6. In the reaction, it is reduced, meaning its oxidation number decreases. The final oxidation number of chromium is +3.

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Answer:

pls writ question well

Explanation:

I don't get

If the amount of vinegar is less than the amount of the other reactant(s), then vinegar is the limiting reactant.

For example, consider the reaction between vinegar (acetic acid, CH3COOH) and baking soda (sodium bicarbonate, NaHCO3):
CH3COOH + NaHCO3 → CH3COONa + H2O + CO2
If there are 0.1 moles of CH3COOH and 0.2 moles of NaHCO3, then the amount of CH3COOH is less than the amount of NaHCO3, and therefore CH3COOH is the limiting reactant. In this case, the value of x for which vinegar is the limiting reactant is 0.1.
In general, to determine the values of x for which vinegar is the limiting reactant, you need to compare the amounts of vinegar and the other reactant(s) present in the reaction and find the values of x for which the amount of vinegar is less than the amount of the other reactant(s).

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Explanation:

It belongs to the oxygen family, also called the chalcogens. It consists of the elements found in Group 16 of the periodic table and is considered among the main group elements, namely Oxygen (O), Sulfur (S), Selenium (Se), Tellurium (Te), Polonium (Po), and Livermorium (Lv). This is the answer!

Reduction potential is a measure of the ability of a substance to be reduced

Reduction potential (Eo) can simply be defined as as that tendency of a chemical species or a substance to be reduced by gaining an electron.

Generally, the reduction potential of any chemical species can be determined by subtracting the standard reduction potential for the reaction occurring at the anode from the standard reduction potential for the reaction occurring at the cathode.

So therefore, reduction potential is a measure of the ability of a substance to be reduced

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Answer: c. a measure of the ability of the substance to be reduced

Explanation:

Answer:

Bases are substances that dissolve in water to release hydroxide ions ... Chalk and oven cleaner are examples of familiar products that contain bases

Given,

Mass required to trigger a mouse trap =157grams

Mass of mouse = 4 ounces (oz)

we need to find the largest mass of cheese a mouse should carry to not set off the trap-

Firstly, we need to convert oz into grams

⇒ 4 x 28.3 = 113.2 grams

∴Mass of cheese in grams = 113.2

For the mouse to not set off the trap, mass of mouse + mass of cheese should be less than 157 grams.

⇒113.2 + mass of cheese < 157

⇒ Mass of cheese < 157 - 113.2

Mass of cheese < 43.8 gm

Hence, the mouse should carry a cheese of 43.8 grams to not set off the trap.

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The mouse should carry a 43.8 grams block of cheese in order to avoid setting off.

Given,

A mouse trap requires 157 grams of mass to set off.

Mouse weight is 4 ounces (oz)

To avoid setting off the trap, we need to determine how much cheese a mouse should be able to carry.

First, we must change an ounce into grams.

4 x 28.3 equals 113.2 grams.

The mass of cheese is 113.2 grams.

Mass of mouse plus mass of cheese must be less than 157 grams for the mouse to avoid setting off the trap.

113.2 +  cheese mass equals 157.

157 cheese mass - 113.2= 43.8 g of cheese total.

Hence, In order to avoid setting off the trap, the mouse should carry a 43.8-gram block of cheese.

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Answer:

Melted ionic compounds have freely moving ions while solid ionic compounds do not.

Explanation:

A melted ionic compound has freely moving ions where electrons can be   transfered because the elements of the ionic compounds have broken there bonds and have dissociated into their ions. Compared to a solid ionic compound where it's still in the crystal lattice and the elements will stick in place and the ions will not move because it's in a solid state and they haven't dissocated into their ions.

ANSWER

The approximate volume of the gas is 0.13L

EXPLANATION

Given data

The number of moles of the gas = 0.600 mol

The temperature of the gas = 15.00 degrees Celcius

The pressure of the gas = 1.10 atm

To find the volume of the gas, follow the steps below

Step 1: Assume the gas is an ideal gas

Since the gas is assumed as an ideal gas, hence we can use the ideal gas equation to find the volume of the gas.

The equation is written below as

Where,

P is the pressure of the gas'

V = volume of the gas

n is the number of moles

T is the temperature of the gas

R is the universal gas constant

Step 2: Convert the temperature to Kelvin

Step 3: Substitute the given data into the formula in step 1

Hence, the approximate volume of the gas is 0.13L

Answer:

c

Explanation:

I think that's the answer

Answer:

Have to give me more a little more information

Explanation:

Answer:

answer in picture

Explanation:

If we burn 33.5 grams of c4h10 with 83.2 grams of oxygen,  -2,901,700 J will the amount of heat in joules produced by the reaction

To answer this question, we need to first write out the balanced chemical equation for the combustion of C₄H₁₀ with oxygen:
C₄H₁₀ +  O₂ ⇒ 4 CO₂ + 5 H₂O
From the equation, we can see that 13/2 moles of oxygen are required to react with 1 mole of C₄H₁₀.
We can use this information to calculate the amount of oxygen required to react with 33.5 grams of C₄H₁₀:
33.5 g C₄H₁₀ × (1 mole C₄H₁₀ / 58.12 g C₄H₁₀) × (13/2 moles O₂ / 1 mole C₄H₁₀) × (32 g O₂ / 1 mole O₂) = 168.3 g O₂
Since we have 83.2 grams of oxygen, we have enough oxygen to completely react with the 33.5 grams of C₄H₁₀.
Now we can use the balanced equation to calculate the amount of heat produced by the reaction:
4 moles CO₂ × (-393.5 kJ/mol) + 5 moles H₂O × (-241.8 kJ/mol) = -2901.7 kJ
Converting to joules:
-2901.7 kJ × 1000 J/kJ = -2,901,700 J
Therefore, the amount of heat produced by the reaction is -2,901,700 J. Note that the negative sign indicates that the reaction is exothermic, meaning that heat is released.

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Answer:

artic is correct please give brainliest please??

Answer: 0.25 atm

Explanation:

Answer:

65.21 percent

Explanation:

We are to find the percentage yield

We have this equation,

2no+o2 -->2no2

Such that 1500 kilograms/30grams

= Mno2/46

=1500/30 = mno2/46

We cross multiply from here

1500x46 = 30xMnO2

69000 = 30Mno2

69000/30 = MnO2

2300 = Mno2

The percentage yield would be

1500/2300 *100

= 0.6521 x 100

= 65.21%

This answers the question

Answer: It’s C

Explanation:

a) The sphere emits thermal radiation at a rate of 139.75 Watts.

b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.

c) The sphere's net rate of energy exchange is 102.09 Watts.

To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.

a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:

Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))

Plugging in the given values:

Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)

Emitting Rate ≈ 139.75 Watts

b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:

Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))

Plugging in the given values:

Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)

Absorbing Rate ≈ 37.66 Watts

c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:

Net Rate = Emitting Rate - Absorbing Rate

Net Rate = 139.75 Watts - 37.66 Watts

Net Rate ≈ 102.09 Watts

Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.

Note: The units for all the rates are Watts.

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