The power developed by the bicyclist while climbing a hill at a constant speed of 2.5 m/s by applying an average force of 85 N is approximately 212.5 W.
Given:Mass of the bicyclist, m = 45 kg. Speed of the bicyclist, v = 2.5 m/sAverage force applied by the bicyclist, F = 85 NPower is given by the formula:
P = Fv = 85 N × 2.5 m/s = 212.5 W.
The power of an object is the rate at which energy is transferred or work is done.
In this problem, we can calculate the power developed by the bicyclist by multiplying the force applied and the speed at which the bicyclist is moving.
The mass of the bicyclist is given as 45 kg and the speed at which the bicyclist is moving is given as 2.5 m/s.
The average force applied by the bicyclist is 85 N. Using the formula for power,
we can calculate that the bicyclist develops approximately 212.5 watts (W) of power.
Therefore, the power developed by the bicyclist while climbing a hill at a constant speed of 2.5 m/s by applying an average force of 85 N is approximately 212.5 W.
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Calculate the amount of horizontal force needed to make a 0.4 kg soccer ball accelerate at 250 m/s2when kicked.
Answer:
100N
Explanation:
Force = Mass x Acceleration
Force = 0.4 kg x 250 m/s2
Force = 100N
Give reasons: Magnet attracts nails but not copper vessels
Answer:
Explanation:
Magnet attracts nails because nails are made of iron and magnets are attracted to iron. Copper is not magnetic, therefore it does not attract to magnets.
A bar magnet that holds a chain of nails illustrates
a. magnetic induction b. magnetic field displacement c. electromagnetic induction.
A bar magnet that holds a chain of nails illustrates "a. magnetic induction."
Magnetic induction occurs when a magnetic field induces magnetism in a nearby material. In this case, the magnetic field produced by the bar magnet induces magnetism in the nails, causing them to become temporarily magnetized and stick to the magnet. This is due to the alignment of the magnetic domains in the nails with the magnetic field of the bar magnet, creating an attraction force between them. This phenomenon is also known as ferromagnetism, which is the ability of certain materials to become magnetized in the presence of a magnetic field.
A magnetic field is the area surrounding a magnet where its magnetic force is exerted. In this scenario, the bar magnet produces a magnetic field that affects the nails. Magnetic induction refers to the process where a magnet's magnetic field induces magnetism in nearby ferromagnetic materials, such as the nails. As a result, the nails become temporarily magnetized and attract each other, forming a chain.
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A photon with a frequency of 5.23 E14 Hz strikes a photoemissive surface whose work function is 1.75 eV. Planck's constant is 4.14 E−15 eV*s. Calculate the energy of the photon. Calculate the maximum kinetic energy of the ejected photoelectron. Calculate the threshhold frequency for the material
The energy of the photon will be 2.1652 Joules and the maximum kinetic energy of the ejected photoelectron from the atom will be 0.415 Joules. The threshold frequency will be same as the frequency of incident photon.
What is the energy of a photon?Photon energy is the energy which is carried by a single photon particle. The amount of energy is directly proportional to the photon's electromagnetic frequency and thus, it is inversely proportional to the wavelength of the photon. The higher the photon's frequency, the higher will be the energy.
Frequency = 5.23 × 10¹⁴ Hz
E = hf
h = 4.14 × 10⁻¹⁵
E = 4.14 × 10⁻¹⁵ × 5.23 × 10¹⁴
E = 21.652 × 10⁻¹
E = 2.1652 Joules
Maximum kinetic energy = hf - Ф
Ф is the work function
Max. KE = (4.14 × 10⁻¹⁵ × 5.23 × 10¹⁴) - 1.75
Max. KE = 2.165 - 1.75
Max. KE = 0.415 Joules
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Detoxification, which requires a large amount of energy, occurs in the ________. One will find a large collection of cells with mitochondria in this type of tissue to provide this energy.
Detoxification, a high-energy process, takes place in a specific type of tissue. This tissue is characterized by an abundance of cells containing mitochondria, which supply the required energy for detoxification.
The liver is the primary site where detoxification occurs in the body. It is a complex organ responsible for various vital functions, including metabolism and detoxification. The liver contains a large number of cells called hepatocytes, which play a crucial role in the detoxification process.
These hepatocytes are rich in mitochondria, which are often referred to as the powerhouses of the cell. Mitochondria generate adenosine triphosphate (ATP), the primary energy currency of cells, through oxidative phosphorylation.
This ATP production is essential for the energy-intensive processes involved in detoxification, such as the breakdown and elimination of harmful substances like drugs, alcohol, and toxins. Therefore, the high presence of mitochondria in liver cells supports the energy demands required for efficient detoxification processes to take place.
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Using F=mXa
1.
Maria's bicycle has a mass of 18.0 kg. What is the net force needed to attain the
acceleration of 1.62 m/s2?
Answer:
29.16 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 18 × 1.62
We have the final answer as
29.16 NHope this helps you
question 1: Ethanol has a specific latent heat of evaporation of 855kJ/kg. Calculate the energy required to boil 0.60kg of ethanol.
question 2:A piece of gold has a volume of 2.00 x 10-5m3 and a mass of 0.386kh. Calculate the density of gold
1. The energy required is 513 kJ to boil 0.60kg of ethanol.
2. The density of gold is 19,300 kg/\(m^3\) if it has a volume of 2.00 x \(10^-^5\)\(m^3\) and a mass of 0.386kh.
Question 1: The energy required to boil a substance can be calculated by multiplying the mass of the substance by its specific latent heat of evaporation. In this case, the specific latent heat of evaporation for ethanol is given as 855 kJ/kg, and the mass of ethanol to be boiled is 0.60 kg.
Energy required = Mass × Specific latent heat of evaporation
Energy required = 0.60 kg × 855 kJ/kg
Energy required = 513 kJ
Therefore, the energy required to boil 0.60 kg of ethanol is 513 kJ.
Question 2: The density of a substance is calculated by dividing its mass by its volume. In this case, the volume of the gold is given as 2.00 x\(10^-^5\) \(m^3\) and the mass of the gold is 0.386 kg.
Density = Mass / Volume
Density = 0.386 kg / 2.00 x \(10^-^5\) \(m^3\)
Density = 19300 kg/\(m^3\)
Therefore, the density of gold is 19300 kg/\(m^3\).
In summary, the energy required to boil 0.60 kg of ethanol is 513 kJ, and the density of gold is 19300 kg/m^3.
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shows an oil tank that has a rectangular base of dimensions 2.4 m by 1.5 m. oil depth of oil 2.4 m 1.5 m
The tank is filled with oil of density 850 kg / m3 to a depth of 1.5 m.what is the force exerted by the oil on the base of the tank.
Answer:
45 000 N
Explanation:
\(pressure \: = \frac{force}{area} \\ density \times g \times height = \frac{force}{area} \\ (850)(9.81)(1.5) = \frac{force}{(2.4)(1.5)} \\ force \: = 45000n \: (3sf)\)
The pressure the oil exerts on the base of the tank is required.
The oil exerts a force of 45027.9 N on the base of the tank.
The dimensions of the tank base are 2.4 m by 1.5 m.
h = The height of the tank = 1.5 m
\(\rho\) = Density of oil = \(850\ \text{kg/m}^3\)
g = Acceleration due to gravity = \(9.81\ \text{m/s}^2\)
F = Force
A = Area of base
Pressure is given by
\(P=\rho gh\)
\(P=\dfrac{F}{A}\)
So,
\(\rho gh=\dfrac{F}{A}\\\Rightarrow F=\rho ghA\\\Rightarrow F=850\times 9.81\times 1.5\times (2.4\times 1.5)\\\Rightarrow F=45027.9\ \text{N}\)
Hence, the oil exerts a force of 45027.9 N on the base of the tank.
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water flowing through a garden hose of diameter 2.76 cm fills a 20.0-l bucket in 1.15 min. (a) what is the speed of the water leaving the end of the hose? incorrect: your answer is incorrect. m/s
The Speed of water flowing by 2.76 diameter is 0.1634m/s.
Given -
Diameter= 2.76cm
Amount = 20l
time= 1.15 min
The flow of water is continuous and remains unaffected with distribution of mass.
To compute the speed of the water leaving the end of the hose-
V= 2.76 + 1= 3.76cm
For 20 l equivalent length is 3.76cm
For 1 l equivalent length(x) = 3.76/20
x= 0.188
\(Speed = distance /time\)
= 0.188/1.15
=0.1634m/s
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A camera lens used for taking close-up photographs has a focal length of 23.5 mm. The farthest it can be placed from the film is 33.0 mm. (a) What is the closest object that can be photographed? (b) What is the magnification of this closest object?
The closest object that can be photographed is 81.63mm and the magnification of this closest object is -0.404.
The focal length of a lens is determined when the lens is focused at infinity. It is obtained from the reciprocal of objects' distance and image distance. Magnification is the enlarged image that is formed over the object size.
From the given,
focal length (f) = 23.5mm
object's distance (u) = 33mm
imagen distance(v) =?
Focal length, (1/f) = 1/u + 1/v
1/v = 1/f - 1/u
=1/23.5 - 1/33
1/v = 12.2mm
v = 1/12.2 mm
= 81.96mm
Thud, the image distance is v= 81.96mm.
Magnification (M) = -v/u
M = -33 / 81.96
= - 0.402.
Thus, the magnification is -0.402.
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How do you think population variables would affect the economic impact of an environmental hazard?
Effects of Population Growth on The Economy Population growth may have a positive effect on the economy.
How does population affect the economy?Human population growth bounces the Earth's system in a variety of ways, involving Increasing the extraction of resources from the environment. Rapid population growth built it more difficult for low-income and lower-middle-income countries to supply the increase in public expenditures. Population growth, along with increasing use, of the economy tends to increase emissions of climate-changing greenhouse gases.
On a facile level, the relationship between growth in population and growth in per capita income is clear. After all, per capita income equals total income divided by population. The growth rate of per capita income forcefully equals the difference joining the growth rate of income and the growth rate of population.
So we can conclude that Population size, growth, age structure, and geographic issues influence economies.
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If the device produces 9.5 kW of power on a day when the waves are 1.45 m high, how many kilowatts will it produce when they are 0.625 m high
The power generated by the device is dependent on the height of the waves. Assuming a linear relationship between wave height and power output, we can use a proportional relationship to determine the power produced when the waves are 0.625 m high.
First, we need to establish the relationship between wave height and power. Let's assume that the power (P) is directly proportional to the square of the wave height (H). Therefore, P ∝ \(H^{2}\).
Now we can set up a proportion using the given values:
(9.5 kW) / (1.45 \(m^{2}\)) = x / (0.625 \(m^{2}\))
Solving for x, we get:
x = (9.5 kW) * (0.625 \(m^{2}\)) / (1.45 \(m^{2}\))
Calculating this expression, we find the power produced when the waves are 0.625 m high.
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When the waves are 0.625 m high, the device is estimated to produce approximately 4.069 kilowatts (kW) of power.
To determine how many kilowatts the device will produce when the waves are 0.625 m high, we need to find the relationship between wave height and power output.
Given:
Power output when waves are 1.45 m high: 9.5 kW
Wave height when power output is unknown: 0.625 m
Assuming a linear relationship between wave height and power output, we can use the following proportion:
(Power output 1) / (Wave height 1) = (Power output 2) / (Wave height 2)
Substituting the known values:
9.5 kW / 1.45 m = (Power output 2) / 0.625 m
Now, let's solve for (Power output 2):
(Power output 2) = (9.5 kW / 1.45 m) * 0.625 m
(Power output 2) = 4.069 kW
Therefore, when the waves are 0.625 m high, the device is estimated to produce approximately 4.069 kilowatts (kW) of power.
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Two different sources of radiation give the same dose equivalent in Sv. Does this mean that the radiation from each source has the same RBE
The product of the dosage Gy and relative biological efficiency yields a radiation dose equivalent Sv (RBE).
Sv =dose in Gy * RBE Sv=dose in GyRBE
The quantity of ionising energy absorbed by 1 text kg1 kg of tissue is defined as a radiation dose Gy. While RBE is a measure of a specific dose's biological effect relative to the biological effect of an equal quantity of X rays.
What is radiation?Radiation is energy that moves through space at the speed of light from a source. This energy is coupled with an electric and magnetic field, and it exhibits wave-like qualities. Radiation is sometimes known as "electromagnetic waves."
Nature has a diverse variety of electromagnetic radiation. One example is visible light.
X-rays and gamma rays are extremely energetic. They may take electrons from atoms when they engage with them, causing the atom to become ionised.
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Suggest a reason why the cell is switched off between measurements for the practical determining emf and internal resistance of a cell.
Answer:
Explanation:
One possible reason for switching off the cell between measurements when determining its electromotive force (emf) and internal resistance is to prevent any external influences or interference during the measurement process. Here's a more detailed explanation:
Minimizing external factors: Switching off the cell during measurements helps minimize the impact of external factors such as electromagnetic fields, stray currents, or fluctuations in the power supply. These external factors can introduce noise or errors into the measurements, making it difficult to obtain accurate results.
Avoiding self-discharge: Some types of cells, particularly rechargeable batteries, have a tendency to self-discharge over time, even when not in use. By switching off the cell between measurements, you can reduce the self-discharge rate and ensure that the cell's energy remains relatively stable throughout the measurement process. This helps maintain consistent and reliable readings.
Preserving battery life: If the cell being measured is not rechargeable or has limited capacity, switching it off between measurements helps conserve its energy. Constantly leaving the cell connected or in an active state could drain its power unnecessarily, leading to a shorter overall lifespan or the need for more frequent replacements.
Eliminating circuit effects: When a cell is connected to a circuit, it interacts with the circuit's components, including wires, resistors, and other elements. These interactions can affect the cell's behavior and introduce additional resistance into the circuit, potentially leading to inaccuracies in the measurement of the cell's internal resistance. By disconnecting the cell between measurements, you can isolate it from the circuit and obtain more precise results.
Classify the organisms in each photo below as plankton, nekton, or benthos. I need to get it done right now .. can someone please help me with it
Answer:
A. Benthos. B. Nekton
Explanation:
Benthos refers to organisms living on the bottom or associated with substrata.
Nekton or necton refers to the actively swimming aquatic organisms in a body of water.
Why does a small piece of steel rod sinks while a large steel oil tanker floats?
Plss help thanks! pls include EXPLANATION and EXAMPLES that I can proof to people that has no knowledge
Answer:
Too what i know its because of the air
Explanation:
The steel rod is more dense and doesnt have air whil'st the oil tanker is less dense with lots of air
Who discovered the nucleus by bombarding gold foil with positively charged particles and noting that some particles were widely deflected?.
Answer:
Ernest Rutherford (later Lord Rutherford)
Why is a combined wave more powerful than a transverse or longitudinal wave even when they all have the same amplitude, frequency, tension, and density?
The combined wave is more powerful and can cause more damage to the medium through which it travels.
What makes a combined wave more powerful than transverse or longitudinal waves?A combined wave, which is also known as a surface wave or a seismic wave, is more powerful than a transverse or longitudinal wave because it combines the motion of both types of waves. In other words, it has components of both transverse and longitudinal waves.
What is the difference between transverse and longitudinal waves in terms of the direction of energy propagation?A transverse wave moves perpendicular to the direction of the wave's energy propagation, while a longitudinal wave moves parallel to the direction of the wave's energy propagation.
When a surface wave travels through a medium, it causes both up-and-down and back-and-forth motions, which result in a more complex motion that covers a larger area of the medium.
This larger area of motion causes a greater disturbance in the medium, and therefore, a greater transfer of energy.
In other words, the amplitude of the surface wave is larger than that of either a transverse or longitudinal wave alone, even when they all have the same amplitude, frequency, tension, and density.
Therefore, the combined wave is more powerful and can cause more damage to the medium through which it travels.
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List the six zones or layers of the sun in order from the centermost to the outermost layer.
4. Explain A girl is jumping on a trampoline. When she is at the top of her jump, her mechanical energy is in what form? Explain why.
Mechanical energy is of two types,
1. Kinetic energy
2. Potential energy
When the girl is at the top of her jump, the speed of the girl becomes zero.
Thus, the kinetic energy of the girl at the top of her jump is,
\(K=\frac{1}{2}mv^2\)where m is the mass of the girl and v is her speed,
Substituting the known values,
\(K=0\text{ J}\)Thus, the kinetic energy of the girl is zero at the top of her jump.
The potential energy of the girl at the top of her jump is,
\(U=\text{mgh}\)where g is the acceleration due to gravity and h is the height of the girl,
Thus, the potential energy of the girl at the maximum height is maximum.
Hence, the mechanical energy of the girl at the top is in potential energy form because her kinetic energy is zero at the top of her jump.
Round your final answer to two decimal places. A plane at an altitude of 359 meters wants to drop supplies to a specific location plane has a horizontal velocity of 232 m/s,how far away from the target should tl supplies in order to hit the target location? (Hint: Use the y-equation to determine the time of flight,then use the x-equation far the supplies will drift.)
To the nearest meter,the plane should be meters away from the target.
The kinematic equations of motion and the acceleration due to gravity indicates that the distance when the supply is to be dropped by the plane
The plane should be 1985 meters away from the target What is acceleration due to gravity?Acceleration due to gravity is the acceleration a body experiences when falling near the surface of a body, such as the moon, or a planet.
The kinematic equations of motion indicates that we get the y-equation for the vertical motion as follows;
y = u·t + 0.5·g·t²
Where;
y = The height of the plane = 359 meters
u = The initial vertical velocity of the supplies = 0 m/s
t = The duration
g = The acceleration due to gravity ≈ 9.81 m/s²
Therefore;
359 = 0 × t + 0.5 × 9.81 × t²
t = √(359/(0.5 × 9.81)) ≈ 8.56 seconds
The x-equation, which is the horizontal distance traveled by the supplies before it reaches the ground, can be found from the equation for the speed of the plane as follows;
Distance, x = Velocity × time = v × t
v = 232 m/s, therefore;
x ≈ 232 × 8.56 ≈ 1985
The horizontal distance from the target the supplies should be dropped in order to hit the target kis about 1,985 meters
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If a kiloparsec (kpc) is equal to 1000 parsecs, how many light years is a kiloparsec
equal to?
(1 point)
O 3, 260 light years
O 3.26 light years
O 3 million light years
O 2, 260 light years
If a kiloparsec (kpc) is equal to 1000 parsecs, light years is a kiloparsec equal to: 3, 260 light years.
What is light years?The distance that light travels in a light-year is one year. At 186,000 miles (300,000 kilometres) per second and 5.88 trillion miles (9.46 trillion kilometres) per year, light travels through interstellar space.
Since a light-year is the maximum distance light can travel in one year and nothing can move faster than that, the answer appears to be 13.8 billion light-years.
Thus, 3,260 many light years is a kiloparsec.
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what is the maximum height reached by the ball? 400 correct: your answer is correct. ft what is the velocity of the ball when it is 384 ft above the ground on its way up? (consider up to be the positive direction.) 32 correct: your answer is correct. ft/s what is the velocity of the ball when it is 384 ft above the ground on its way down? (no response) ft/s when will the ball hit the ground? t
The primary indicator of an object's position and speed is its velocity.It is the distance that an object travels in one unit of time.The displacement of the item in one unit of time is the definition of velocity.
what is the maximum height reached by the ball?Smax = 400 feet.
c) v = 32 ft/s
c) v = - 32 ft/s
(a)
The following is the function provided for ball height:
s = 160 t - 16 t²
Therefore, we must take the derivative with respect to t and make it equal to zero in order to get the time to reach maximum height (in-flexion point):
So, 160 - 32 t = 0, 32 t = 160 t, and 160/32 t = 5 sec.
As a result, the maximum distance is covered every 5 seconds.
Smax = (160)(5) - (16)(5)²
Smax = 800 - 400
Smax=400 feet
b)First, we determine the speed at which the ball travels 384 feet.
384 = 160 t - 16 t
16 t² - 160 t + 384 = 0
Quadratic Equation Solving:
Either:
t = 6 sec
or t = 4 seconds
Since it takes 5 seconds to reach the highest point,
t then equals 5 seconds.
t then equals 4 seconds.
Now, by taking a derivative of ods with respect to t at 4 sec, we can find velocity:
v = 160 - 32 t
v = 160 - (32)(4)
v = 32 ft/s
c,Because t = 6 s > 5 s
The second number of t = 6 sec must represent the point in the ball's downward motion when it is 384 feet above the earth.
So, at that moment, velocity will be:
v = 160 - (32)(6)
v = -32 ft/s
downward motion is a bad sign.
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The solubility of barium nitrate is 9.02 g/100 g H2O at 20°C. A 15.2 g sample of barium nitrate is added to 200.0 g of water at 20°C. Is the solution saturated, unsaturated, or supersaturated?
Answer:
The solution is unsaturated.
Explanation:
Saturated solutions are those solutions with the maximum amount of solute completely dissolved by the solvent. This indicates that although more solute is added, it does not dissolve. In this case the amount of solute is equal to the solubility coefficient.
The supersaturated solution is one in which the amount of solute exceeds the solubility of the solvent, that is, it has a greater amount of dissolved solute than that which it admits at that temperature. In this case a solution contains solute above the solubility coefficient.
A solution is considered to be unsaturated if the mass of dissolved solute is less than that corresponding to that of saturation. This indicates that it is possible to add more solute and that it dissolves. In this case the solution contains solute below the solubility coefficient.
The solubility of barium nitrate is 9.02 g/100 g H₂O at 20°C.
A 15.2 g sample of barium nitrate is added to 200.0 g of water at 20°C. This is: 15.2 g /200 g H₂O. Dividing by two you get: 7.6 g /100 g H₂O
Comparing with the solubility of barium nitrate, you can see that the mass of dissolved solute is less than the corresponding one. This indicates that the solution is unsaturated.
A 0.6 kg object moves at a constant velocity of 2 m/s, traveling a total distance of 30 m. Using the work-energy theorem, what is the net work on the object? (1 point)
A. 2.4 J
B. 0 J
C. 1.2 J
D. 36 J
Answer: B. 0 J
Explanation:
Online Seller satisfaction rating (1-5 stars) What type of variable and classification is this?
Product or Satisfaction rating using number of stars is a a qualitative or categorical variable which falls under the Ordinal variable classification.
When variables used in measurement aren't numerical, such variables are called categorical or qualitative variables, stars are not numerical, hence (rating of 1 - 5 stars) are categorical variables. When categorical variables follow a particular order or rank, with the difference between the orders or ranks not being explicit, such variables are belong to the Ordinal class. Satisfaction level will increase from 1 star up to five being the highest, which shows that sellers with 3 stars are less satisfied than those with 4 stars. However, the difference between each level cannot be explicitly measured.Therefore, use of star rating to depict online customer satisfaction is a categorical Ordinal variable.
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a recognizable group of stars that's smaller than a constellation is known as what?
A recognizable group of stars that is smaller than a constellation is known as an asterism.
An asterism can be a recognizable pattern or shape formed by a few bright stars within a constellation, such as the Big Dipper in the constellation Ursa Major. While constellations are officially recognized by the International Astronomical Union and have specific boundaries, asterisms are not officially recognized and can vary based on cultural and regional interpretations of the stars in the sky.
Some well-known examples of asterisms include the Big Dipper, which is part of the Ursa Major constellation, and the Pleiades or Seven Sisters, which is located within the Taurus constellation. These easily identifiable groupings of stars serve as valuable celestial landmarks for amateur stargazers and professional astronomers alike.
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A car horn creates a 595 Hz tone at rest. Two cars pass on the street, each going 20.0 m/s; the first car honks. What frequency does the other car hear before they pass each other?
Doppler frequency, the other car hear before they pass each other is 668.68 Hz.
What is frequency?Frequency is the number of occurrences of a repeating event per unit of time.
What is Doppler EFFECT?The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source.
According to the Doppler Effect, the frequency observed is
\(fo=fs\frac{v+v_{o} }{v-v_{s} }\)
\(f_{o}=595\frac{343+20 }{343-20 }\\f_{o} = 668.68 Hz\)
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What are three disadvantages of making and using plastic?
It pollutes the land and water.
It requires cutting down trees for raw materials.
It takes an incredibly long time to break down.
It freely conducts heat and electricity.
It isn’t easy to recycle.
Three disadvantages of making and using plastic are pollution, resource depletion, and poor recyclability. Plastic pollution poses a significant threat to the environment, as it can contaminate land and water bodies, harming wildlife and ecosystems. Additionally, plastic production relies on the extraction and processing of fossil fuels, contributing to resource depletion and climate change. Moreover, plastic takes an incredibly long time to decompose, leading to persistent waste accumulation.
Plastic production contributes to pollution through various stages of its life cycle, including extraction, manufacturing, and disposal. The improper disposal of plastic waste can result in land and water pollution, impacting habitats and biodiversity.
Furthermore, the extraction and processing of raw materials, such as oil and gas, for plastic production contribute to greenhouse gas emissions and climate change.
Plastic's dependence on fossil fuels also leads to resource depletion and contributes to the finite availability of these non-renewable resources.
Additionally, plastic's long decomposition time, which can range from hundreds to thousands of years, results in a build-up of plastic waste in landfills, oceans, and other environments.
Moreover, plastic recycling presents challenges due to the wide variety of plastic types, each with different properties and recycling processes. This complexity makes it difficult to efficiently and effectively recycle plastic, leading to a significant portion of plastic waste ending up in landfills or being incinerated, further exacerbating environmental issues.
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3. What exerts a greater force on the table of 2 kg book lying flat or a 2 kg book on its
side? Which applies greater pressure? If the book measures .3m x.2 m x.05m Calculate
the pressure applied in each situation.
Answer:
A book on its side exerts a greater force.
Explanation:
Pressure = Force / Area
Assuming that 1kg = 10N
2kg = 20N
Area of book lying flat = 0.3m × 0.2m
= 0.6m²
Pressure of book lying flat = 20N / 0.6m²
= 30Pa (1 s.f.)
Area of book on its side = 0.2m × 0.05m
= 0.01m²
Pressure of book on its side = 20N / 0.01m²
= 2000Pa (1 s.f.)
Since 2000Pa (1 s.f.) > 30Pa (1 s.f.), a book on its side applies greater pressure than lying flat.