A 4.0-mF capacitor initially charged to 50 V and 6.0-mF capacitor charged to 30 V are connected to each other with the positive plate of each connected to the negative plate of the other. what is the final charge of the 6.0-mF capacitor?

a. 20 mC
b. 8.0 mC
c. 10 mC
d. 12 mC
e. 230 mC

Answer:

Ps eso me salio

Physical education, sports education or sports education are terms that refer to the teaching and learning of physical exercises whose main objective is education and health. This has been the decisive reason for the introduction of physical exercises in elementary school in the 19th century.

Explanation:

Answer:

Webbed feet

Explanation:

Ducks are a species of birds that usually spend most of their time in water. The feed and breed around waterbodies such as lakes, marshes, rivers and streams. To enable them thrive in their water environment, ducks have developed several structures. One of such structure is the webbed design of their feet. This design enables them to swim much better and faster in order to hunt for food or to avoid predators. Recent research have discovered that while swimming, ducks push both backward and downward with each stroke of their webbed feet. This provides a combination of lift and thrust, assisting them to move through water with greater speed and efficiency.

Other important features of the duck include the preen gland (uropyial gland) which produces oil that keeps the ducks feather from getting wet while in water, thus assisting them to float; hollow bones which makes them lightweight, etc.

Answer:

130n on the 2nd horizontal

Explanation:

Answer:

2156 J

Explanation:

From the question,

Work done = Combined mass of the bucket and water×height×gravity.

W = (M+m)hg............................. Equation 1

Where M = mass of water, m = mass of the bucket, h = height, g = acceleration due to gravity.

Given: M = 20 kg, m = 2 kg, h = 10 m

Constant: g = 9.8 m/s²

Substitute these  value into equation 1

W = (20+2)×10×9.8

W = 22×98

W = 2156 J

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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E. A graph of the Q as a function of N will be a straight line. is a correct hypothesis for this experiment

A straight line is a line that has no curves or bends. It is the shortest distance between two points, and is often used as a basic element in geometry. Straight lines can be found in a variety of contexts, including in art and architecture. In mathematics, a straight line is a type of line that has only one dimension and extends infinitely in two directions. Straight lines are used to form shapes such as squares, rectangles, and triangles, and to solve many mathematical problems. Straight lines are also used in engineering and construction to represent the most efficient and economical way to build a structure. Straight lines are used in physics to study the motion of objects, and they can be used to calculate the speed of an object or the acceleration due to gravity. Straight lines are also used in everyday life, such as when drawing a line on a piece of paper or walking in a straight line.

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The acceleration of Thomas is 0.233 m/s^2.

Acceleration is the rate of change of velocity. Thomas the Train chugs along at a velocity of 2 m/s.

Thomas needs to go faster so more coal is shoveled into his engine and he accelerates for 10 seconds until he is going 4.33 m/s.

We are to find the acceleration of Thomas.

The formula for acceleration is given as :

acceleration = (final velocity - initial velocity) / time

In the given problem, the initial velocity of Thomas, u = 2 m/s.

The final velocity of Thomas, v = 4.33 m/s The time for which Thomas accelerates, t = 10 s.

Therefore, the acceleration of Thomas will be given as:

a = (v - u) / ta = (4.33 - 2) / 10s => 2.33 / 10s => 0.233 m/s^2

Thus, the acceleration of Thomas is 0.233 m/s^2.

To summarize, the acceleration of Thomas is 0.233 m/s^2.

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Answer:

Because the "colored" bathroom was 1/2 mile away, and colored people were not allowed to use the white people's bathroom.

The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.  

Thus, Waveforms with periodic variations are those that recur consistently at set intervals.

The phrase is typically used in electronics to describe periodically changing voltages, currents, or electromagnetic fields. It is typically used in acoustics to describe constant periodic sounds caused by changes in air pressure or other media.

In these situations, the signal's frequency, amplitude, or phase shift have no bearing on the waveform, which is a characteristic. Additionally, non-periodic signals like chirps and pulses can be referred to by this name.

Thus, The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.  

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Her inertia moment reduced and When she draws in the crowds, her muscles do useful work and No change in her angular momentum occurs.

A measurement of how much matter is present in or makes up a physical body. In classical mechanics, an object's mass is crucial to Newtonian mechanics because it influences the force needed to accelerate it and, consequently, how much inertia it has.

Although the terms "mass" and "weight" are sometimes used interchangeably, they have quite distinct meanings. No of where you are in the cosmos, your mass remains constant; nevertheless, your weight varies. The mass of protons and neutrons is determined by the energy of this contact between quarks and gluons.

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The magnitude of the impulse of the truck is equal to 4000 Kg.m/s.

Impulse can be described as the integral of a force over the time interval for which it acts. Impulse is also a vector quantity since force is a vector quantity. Impulse can be applied to an object that generates an equivalent vector change in its linear momentum.

The S.I. unit of impulse is N⋅s and the dimensionally equivalent unit of momentum is kg⋅m/s. A resultant force gives acceleration and changes the velocity of an object for as long as it acts.

Given the mass of the truck, m= 2000 Kg

The initial speed of the truck, u = 6 m/s

The final speed of the truck, v = 4 m/s

The change in the linear momentum is equal to the impulse.

I = ΔP = mv - mu

I = 2000 ×4 - 2000 × 6

I = 8000 - 12000

I = - 4000  Kg.m/s²

Therefore, the magnitude of the impulse is  4000 Kg.m/s².

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Two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then  the magnitude of the resultant force is 15 N and the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

The acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

The magnitude of the acceleration of the object is 3  \(m/s^{2}\).

To find the magnitude and direction of the resultant force, we need to add the two given forces together.

Given:

f1 = (8i + 3j) N

f2 = (4i + 6j) N

To find the resultant force (\(F_res\)), we simply add the corresponding components:

\(F_res\) = f1 + f2

= (8i + 3j) + (4i + 6j)

= (8 + 4)i + (3 + 6)j

= 12i + 9j

The magnitude of the resultant force (\(|F_res|\)) can be found using the Pythagorean theorem:

\(|F_res|\)= \(\sqrt{(12^2) + (9^2)}\)

= \(\sqrt{144 + 81}\)

= \(\sqrt{225}\)

= 15 N

So, the magnitude of the resultant force is 15 N.

To find the direction of the resultant force, we can use trigonometry. The direction can be represented by the angle θ between the positive x-axis and the resultant force vector. We can calculate θ using the inverse tangent function:

θ = arctan(9/12)

= arctan(3/4)

≈ 36.87 degrees

Therefore, the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

Now let's calculate the acceleration of the object in the x and y components. We know that force (F) is related to acceleration (a) through Newton's second law:

F = ma

For the x-component:

\(F_x\)= 12 N

m = 5 kg

Using  \(F_x\)= \(ma_x\), we can solve for \(a_x\):

12 N = 5 kg * \(a_x\)

\(a_x\)= 12 N / 5 kg

\(a_x\) = 2.4 \(m/s^{2}\)

For the y-component:

\(F_y\) = 9 N

m = 5 kg

Using \(F_y\) = \(ma_y\), we can solve for \(a_y\):

9 N = 5 kg * \(a_y\)

\(a_y\) = 9 N / 5 kg

\(a_y\)= 1.8  \(m/s^{2}\)

So, the acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

To find the magnitude of the acceleration (|a|), we can use the Pythagorean theorem:

|a| = \(\sqrt{(a_x^2) + (a_y^2)}\)

= \(\sqrt{(2.4^2) + (1.8^2}\)

= \(\sqrt{5.76 + 3.24}\)

= \(\sqrt{9}\)

= 3  \(m/s^{2}\)

Therefore, the magnitude of the acceleration of the object is 3  \(m/s^{2}\)

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Answer:

Cold water slows down dissolving

Cold water slows down dissolving. Hence, option (A) is correct.

The basic relationship between solubility and temperature is as follows: A solid will dissolve more readily at higher temperatures.

Likewise, a solid element dissolves more slowly at lower temperatures. This is all due to the solvent becoming more and more excited by the heat, making it easier for it to split or break apart entirely.

for while in gases The solubility of gases decreases more rapidly as temperature rises. A gas is more soluble in water when the temperature is lower.

Henry's law, which states that the gas becomes more soluble as the pressure above the liquid solution increases, summarizes another characteristic of gas solutes.

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Answer:

50 N

Explanation:

W = Fd

F = W/d

first convert cm → m:  50 cm x 1 m/cm = 0.50 m

F = (25 J) / (0.50 m) = 50 N

The density of the liquid as measured by the student is 1.9473 g/ml

Definition of density: A material's density is determined by how closely it is packed. As the mass per unit volume, it has that definition. Symbol for Density: D or Density

Given Data

Mass = 2.22g ± 0.05g

Volume = 1.14 ± 0.04 ml

We know that the expression for density is given as

Density = Mass/Volume

Substituting our given data into the expression above, we have

Density = 2.22/1.14

Density = 1.9473 g/ml

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If a 5kg mass starts from rest at xo = -1 and moves under the action of a variable force F(x) = √1-x² to point xf = 1. Then the total work done by the force is equal to π/2 + 1.

To calculate the total work done by the force in this scenario, we can use the formula for work:

Work = ∫F(x) dx

where F(x) is the force as a function of position and dx represents an infinitesimal displacement.

In this case, the force is given by F(x) = √(1 - x²), and we need to find the total work done as the object moves from xo = -1 to xf = 1.

Let's break down the calculation step by step:

Write the integral for work:

Work = ∫F(x) dx

Substitute the given force:

Work = ∫√(1 - x²) dx

Integrate with respect to x:

To integrate the square root of (1 - x²), we use the trigonometric substitution. Let's substitute x = sin(θ) and dx = cos(θ) dθ.

Work = ∫√(1 - sin²(θ)) cos(θ) dθ

Simplify the integrand:

Using the trigonometric identity sin²(θ) + cos²(θ) = 1, we can rewrite the integrand as cos²(θ).

Work = ∫cos²(θ) dθ

Apply the power-reducing formula:

The power-reducing formula states that cos²(θ) = (1 + cos(2θ)) / 2. We can use this formula to simplify the integrand further.

Work = ∫(1 + cos(2θ))/2 dθ

Integrate the terms separately:

Work = (1/2) ∫dθ + (1/2) ∫cos(2θ) dθ

The first integral, ∫dθ, is simply θ, and the second integral, ∫cos(2θ) dθ, can be calculated as sin(2θ)/2.

Work = (1/2) θ + (1/2) (sin(2θ)/2) + C

Evaluate the integral limits:

To find the total work done, we need to evaluate the integral at the upper and lower limits of integration.

At xf = 1, the angle θ is π/2, and at xo = -1, the angle θ is -π/2.

Work = (1/2) (π/2) + (1/2) (sin(2(π/2))/2) - [(1/2) (-π/2) + (1/2) (sin(2(-π/2))/2)]

Simplifying further:

Work = π/4 + (1/2) - (-π/4 + (1/2))

Work = π/4 + 1/2 + π/4 + 1/2

Work = π/2 + 1

Therefore, the total work done by the force is equal to π/2 + 1.

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Answer:

Upton Sinclair's:The Jungle

Explanation:

The novel portrayed the harsh conditions of immigrants in the United States in industrialized cities.

Answer:

Explanation:

This is an RL circuit, therefore:

Impedance; z = \(\mathbf{\sqrt{R^2+L^2}}\)

\(\mathbf{z = \sqrt{R^2+(Lw)^2}}\)

Current amplitude

\(\mathbf{I_o = \dfrac{V_o}{z}} \\ \\ \mathbf{I_o = \dfrac{V_o}{\sqrt{R^2+L^2\omega ^2}}}\)

a)

Given that:

\(V_o = 1.9 \ V \\ \\ \omega= 51 \ rad/s\\\\ R = 21 \Omega \\ \\ L = 0.52 H\)

∴

\(I_o= \dfrac{1.9}{\sqrt{21^2+(0.52\times 51)^2}}\)

\(\mathbf{I_o= 0.0562} \\ \\ \mathbf{I_o = 56.2 \ mA}\)

b)

Phase constant :

\(tan \ \phi = \dfrac{L \omega}{R } \\ \\ tan \ \phi = \dfrac{0.52 \times 51}{21} \\ \\ tan \phi = 1.263\)

\(\text{Phase constant : }\phi = tan^{-1} (1.263) \\ \\ \phi = 51.6^0\\ \\\text{To radians} \phi = 51.6 \times \dfrac{\pi}{180} \\ \\ \phi = 0.287 \pi \\ \\ \mathbf{\phi = 0.9 \ rad}\)

(a)The value of current amplitude will be 56.2 milliamperes.

(b)The value of the phase constant will be 0.9 rad.

RL Circuits often known as RL networks or RL filters are a form of a circuit that uses a mix of inductors and resistors and is powered by a source of electricity.

The given data in the problem is;

I₀ is the current amplitude =?

V₀= 1.9 V

ω is the angular velocity = 51 rad/s

R is the resistance in the circuit = 21 Ω

Ф is the phase constant=?

(a) The value of current amplitude will be 56.2 milliamperes.

The formula for the current amplitude is given as;

\(\rm I_0= \frac{V_0}{\sqrt{R^2+L^2 \omega^2} } \\\\\)

\(\rm I_0= \frac{1.9}{\sqrt{(21)^2+(0.52\times 51)^2} } \\\\\)

\(\rm I_0 = 0.0562 \ A \\\\ \rm I_0 =56.2 mA\)

Hence the value of the current amplitude will be 56.2 milliamperes.

(b)The value of the phase constant will be 0.9 rad.

The formula for phase constant is given by;

\(\rm tan\phi=\frac{L\omega}{R} \\\\ \rm tan\phi=\frac{0.52\times 51}{21} \\\\ \rm tan\phi=1.263 \\\\ \rm \phi = tan^{-1}(1.263) \\\\ \phi= 51.6 ^0\)

To convert degree into radian the following formula is used;

\(1 \pi =180^0 \\\\ 1^0=\frac{\pi}{180} \\\\ 51.6^0=51.6 \times \frac{\pi}{180} \\\\ \phi=0.9 \ rad\)

Hence the value of the phase constant will be 0.9 rad.

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The motion of the car between the first and last stops is divided in three parts:

• The motion where the car speeds up with acceleration of 4m/s^2.

• The motion without acceleration (when the car coasts for 2 seconds).

• The motion where the car slows down with acceleration of 3 m/s^2.

To determine how far apart the stop signs are we need to calculate how much distance the car traveled in each part. Let's analyze each situation.

First part of the motion.

For this part of the motion of the car we have a constant acceleration, this means that we have an uniform accelerated motion. To determine the distance traveled in this part we can use the equation:

where x is the final position, x0 is the initial position, v0 is the initial velocity, a is the acceleration and t is the time.

In this case the initial position is zero (in here we are putting the origin of the motion at the stop sign), the initial velocity is zero (since the car starts from rest), the acceleration is 4 m/s^2 and the time is 6 seconds; plugging this values in the equation above we have that:

Hence, in this part of the motion the car travelled 72 meters.

We will need the final velocity for this part of the motion in order to calculate the distance traveled in the second part of the motion so let's calculate it. The final velocity can be obtained from the equation:

plugging the values we know and solving for the final velocity we have that:

Therefore the car is traveling at 24 m/s when it starts to coast.

Second part of the motion.

In this part of the motion the car coasts, this means that it is not accelerating, and for this reason, the car does not change its velocity. For this reason we have an uniform rectilinear motion. The change in position in a rectilinear motion is given by:

Changing our origin of the motion to where the car starts to coast we have that the initial position is zero, the velocity is 24 m/s (the velocity in which the car stopped accelerating) and the time is 2 seconds. Plugging this values in the equation we have that:

And then, we conclude, the car travelled 48 meters in this part of the motion.

Third part of the motion.

In here we know that the car is slowing down with an acceleration of 3 m/s^2 until it stops in the next stop sign. Since the acceleration is constant once again we have an uniform accelerated motion. To determine the distance the car traveled in this part we can use the equation:

In this case we know that the final velocity is zero (since the car stops), the initial velocity is 24 m/s (since the car was moving in an uniform rectiliniar motion in the previous part of the motion) and that the acceleration is -3 m/s^2 (we have to use a negative sign since the car is slowing down, this means that the acceleration is negative); plugging the values we have that:

Hence in this part in the motion the car travelled 96 meters.

Finally, now that we know how much the car travelled in each part of the motion, we can calculate how far apart the stop signs are; to do this we add the distance the car travelled in each part, then we have:

Therefore, the stops signs are 216 meters apart.

Answer:

Option C, The magnetic domains inside the material must be aligned

Explanation:

Magnetic domains determine the magnetic behavior of any substance. Most of the magnetic substances have disoriented magnetic domains due to which they do not behave as magnets until unless an external force is applied to change the orientation of their domains and align them properly.

Hence, option C is correct

Answer:

The answer is 8829 joules

Explanation:

The equation for finding potential energy is

P.E = m*g*h

M (mass in kg)

g (gravity= 9.81)

h (height above the ground)

So

P.E = 30*9.81* 30 = 8829 joules

If I were an astronaut, the first job I would do on the International Space Station (ISS) would be to familiarize myself with the station and its systems.

I would need to learn how to operate the various equipment and how to maintain the station in good working order. I would also need to learn the procedures for conducting experiments and for performing spacewalks.

Once I had a good understanding of the station and its systems, I would begin working on my assigned tasks. These tasks could include conducting experiments, performing maintenance, or teaching other astronauts new skills. I would also take the opportunity to conduct research on my own and to learn more about the space environment.

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Answer:

32J

Explanation:

Heat H = MC∆T = 4 × 1.0 × 8 = 32J

The tax rate you will pay is displayed in tax brackets for each category of taxable income.

Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.

Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.

As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.

Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.

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Answer:

The atomic number of the element in this notation is 15.

Explanation:

The X notation for an atom provides information about its atomic number and mass number. The atomic number is the number of protons in the nucleus of an atom, which determines its chemical properties and identity as an element. The mass number is the sum of the number of protons and neutrons in the nucleus.

In the notation "32 on 15 X", the number on the top (32) represents the mass number of the atom, which is the total number of protons and neutrons in the nucleus. The number on the bottom (15) represents the atomic number of the atom, which is the number of protons in the nucleus.

Therefore, the atomic number of the element in this notation is 15.