The required maximum mass that the beam can bear without slipping is 14.163 kg.
The maximum mass that a 4.0 m long steel beam with a cross-sectional area of 1.0 × 10²m² and a Young's modulus of 2.0 × 10' N/m² can bear without slipping when wedged horizontally between two vertical walls and compressed by 0.020 mm, assuming a coefficient of static friction of 0.70, is calculated as follows,
Force of friction = coefficient of static friction × normal force = Area of beam × Young's modulus × compression
Therefore, the force of friction = 0.70 × (1.0 × 10² m²) × (2.0 x10' N/m²) × 0.020 mm
Maximum mass = (force of friction) / (acceleration due to gravity)
Therefore, the maximum mass that the beam can bear without slipping is (0.70 × (1.0 × 10² m²) × (2.0 × 10' N/m²) × 0.020 mm) / (9.81 m/s²) = 14.163 kg.
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In a telescopic observation of a field of stars, you see an irregular dark patch. this is most likely?
if you see an irregular dark patch in a telescopic observation of a field of stars, it is likely a dark nebula or a molecular cloud. These dense regions of interstellar dust and gas block the light from the stars behind them, resulting in the appearance of an irregular dark patch.
In a telescopic observation of a field of stars, if you see an irregular dark patch, it is most likely a dark nebula or a molecular cloud. These are dense regions of interstellar dust and gas that block the light from the stars behind them. Dark nebulae are often seen against a brighter background of stars, and they appear as irregular, dark patches.
Dark nebulae are composed mainly of small solid particles, such as dust grains, which absorb and scatter the light passing through them. This absorption and scattering of light make the dark nebulae appear darker than the surrounding stars.
The presence of dark nebulae can indicate the presence of star-forming regions. Molecular clouds, which are a type of dark nebula, are often the birthplaces of new stars. The dense regions within these clouds can collapse under their own gravity, leading to the formation of stars.
In summary, if you see an irregular dark patch in a telescopic observation of a field of stars, it is likely a dark nebula or a molecular cloud. These dense regions of interstellar dust and gas block the light from the stars behind them, resulting in the appearance of an irregular dark patch.
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what is the modern symbol for the element Bo
Answer:
Bo (modern symbol B) = Boron
Explanation:
Hope this helps
A thermometer is taken from a room where the temperature is 19
∘
C to the outdoors, where the temperature is −5
∘
C. After one minute the thermometer reads 11
∘
C. (a) What will the reading on the thermometer be after 3 more minutes? (b) When will the thermometer read −4
∘
C ? minutes after it was taken to the outdoors.
The reading on the thermometer after 3 more minutes will be -13∘C. The thermometer will never read -4∘C after being taken outdoors.
To solve this problem, we can assume that the rate of change in temperature follows a linear pattern.
Let's first calculate the rate of change in temperature per minute:
Rate of change = (Final temperature - Initial temperature) / Time
a) After one minute:
Rate of change = (11∘C - 19∘C) / 1 minute = -8∘C/minute
To find the reading on the thermometer after 3 more minutes, we can multiply the rate of change by the time:
Change in temperature = Rate of change × Time
After 3 more minutes:
Change in temperature = -8∘C/minute × 3 minutes = -24∘C
The initial temperature was 11∘C, so the final temperature after 3 more minutes will be:
Final temperature = Initial temperature + Change in temperature = 11∘C - 24∘C = -13∘C
b) To find when the thermometer will read -4∘C, we need to determine the time it takes for the temperature to change from -5∘C to -4∘C.
Rate of change = (-4∘C - (-5∘C)) / Time
Rate of change = 1∘C / Time
We can rearrange the equation to solve for time:
Time = 1∘C / Rate of change
Substituting the given rate of change:
Time = 1∘C / (-8∘C/minute) = -1/8 minute
Since time cannot be negative, we can conclude that the thermometer will never read -4∘C after being taken outdoors.
Please note that this calculation assumes a linear rate of change in temperature, which might not hold true in all situations.
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A 3 kg ball is moving at 2.0 m/s to the right. It runs into a 1 kg ball moving at 0.5 m/s to the left. The balls bounce off each other.
Q. If the 3 kg ball moves at 1 m/s to the left after the collision, how fast must the 1 kg ball be going after the collision? Show the equation and work
Answer:
The Answer Is O.5 m/s
Explanation:
we have an equation:
m1u1 + m2u2=m1v1 + m2v2(u is for before collison and v is for after collision)
rearrange,
m1u1 + m2u2 - m1v1 ÷ m2 = v2Put values and answer will be 0.5m/s
Answer:
3.5
Explanation:
we have an equation:
m1u1+m2u2=m1v1+m2v2 where, m=mass
v=final velocity
u=intial velocity
then this means:
v2=m1u1+m2u2-m1v1÷m2
when we substitute on the equation:
v2=3×2.0+1×0.5-3×1÷1
=6+0.5-3
=6.5-3
=3.5
Which characteristics of an area could best identify the type of biome it is
Answer: average annual rainfall, average annual temperatures, types of plants and animals native to the area
Explanation: the best way you can identify a biome is by telling which animal or species are native to the certain area
In the hydrogen atom, what is the electric potential energy of the electron when it is found in the n = 2 state?
Hint: refer to the derivation of the total energy for energy proportions.
In the hydrogen atom, the electric potential energy of the electron when it is found in the n = 2 state can be derived using the equation for total energy, which is equal to the sum of the kinetic and potential energies.
The potential energy is dependent on the distance between the electron and the nucleus, and the kinetic energy is dependent on the velocity of the electron. When the electron is in the n = 2 state, its potential energy is -3.4 electron volts (eV). This negative value indicates that the electron is bound to the nucleus and that energy must be inputted to remove it from the atom. Hydrogen is a valuable source of energy because it can be used in fuel cells to produce electricity through the reaction of hydrogen with oxygen.
This process releases energy in the form of electricity, making hydrogen a clean and efficient source of energy.
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the explosive tnt has a heat of combustion of 3406 kj/mol. is this higher or lower than sugar?
TNT has a heat of combustion of -3406 kJ/mol compared to sugar's -5639 kJ/mol.
what is heat of combustion?
The quantity of heat released when a specific amount of a substance undergoes burning is known as the heat of combustion, also known as the calorific value or the energy value. In most cases, the terms "heat of combustion" and "calorific value" are interchangeable. Calorific value is the term used to describe the total amount of energy released during the complete combustion of a given mass of a substance in the presence of (an adequate amount of) oxygen under typical conditions of pressure and temperature.
TNT has a heat of combustion of -3406 kJ/mol compared to sugar's -5639 kJ/mol.
TNT is an explosive because it explodes more quickly due to its lower heat of combustion. Sugar is not explosive and will take a lot longer to heat up or burn.
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Please help!! :)
For this circuit, what will be the voltage drop across R1?
A. 21.3 V
B. 14.2 V
C. 45.0 V
D. 9.47 V
Answer:
Option D. 9.47 V
Explanation:
We'll begin by calculating the equivalent resistance of the circuit. This can be obtained as follow:
Resistor 1 (R₁) = 20 Ω
Resistor 2 (R₂) = 30 Ω
Resistor 3 (R₃) = 45 Ω
Equivalent Resistance (R) =?
R = R₁ + R₂ + R₃ (series connections)
R = 20 + 30 + 45
R = 95 Ω
Next, we shall determine the current in the circuit. This can be obtained as follow:
Voltage (V) = 45 V
Equivalent Resistance (R) = 95 Ω
Current (I) =?
V = IR
45 = I × 95
Divide both side by 95
I = 45 / 95
I = 0.4737 A
Finally, we shall determine, the voltage across R₁. This can be obtained as follow:
NOTE: Since the resistors are in series connection, the same current will pass through them.
Current (I) = 0.4737 A
Resistor 1 (R₁) = 20 Ω
Voltage 1 (V₁) =?
V₁ = IR₁
V₁ = 0.4737 × 20
V₁ = 9.47 V
Therefore, the voltage across R₁ is 9.47 V.
Answer:
9.47
Explanation:
Just Took the Test
(b) 32g of dry ice was added to 200g of water at 25°C in a beaker of negligible heat
capacity. When all ice had melted the temperature of water was found to be 10°C. 9 (Take specific
heat capacity of water to be 4.0J/gk)
(i) Calculate the heat lost by water
The heat lost by water is equal to the heat gained by ice here. The heat lost from water for a temperature change of 25 to 10 degree Celsius is 12300 J.
What is calorimetric ?Calorimetry is an analytical technique used to determine the heat energy absorbed or evolved by a system. The calorimetric equation relating the heat energy q with the mass m, specific heat c and the temperature difference ΔT is :
q = m c ΔT
Here, the heat energy gained by the dry ice is equal to the heat lost from water.
temperature difference for water = 25- 10 °C = 15°C
thus, 15°C is lost from water.
mass of water = 200 g
q =200 g × 4.12 J/°C g × 10°C = 12300 J
Therefore, the heat energy lost from water is 12300 J.
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(THIS IS ASTRONOMY)
A group of older stars that cluster together in a spherical shape and can contain up to one million stars per cluster is called:
A globular cluster
Open clusters
Spherical clusters
Accretion
Answer:
the answer to this question is A globular cluster
blake is 20m behind a flagpole when he starts to run forward to catch up to his friend denise, who is standing 30m in front of the same flagpole. if he meets denise 10 seconds after he starts running, write an equation that describes Blake's position as a function of time, assuming blake runs at a constant speed
Blake's position, x as a function of time, t, is x = 5t
What is the position of Blake with respect to time?The position of Blake is the distance of Blake from the reference point of Denise.
The total distance from Blake to Denise = 20 + 30 = 50 m
Time taken by Blake to meet up with Denise = 10 seconds
Assuming that he runs at constant speed;
speed = 50/10
speed = 5 m/s
Distance = speed * time
Let Blake's position be x
Let time be t
Blake's position as a function of time, will be x = 5t.
In conclusion, distance or position is the product of velocity and time.
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what is the diameter of the football players' piston if the football players are held to a height 0.800 m above the cheerleader?
Diameter of the football players' piston if the football players are held to a height 0.800 m above the cheerleader is 53 cm
mass of the cheerleader is, m1=51.0kg
mass of each football player is, m2=110kg
diameter of the piston for cheerleader is, d1=18.0cm=0.18m
W1=m1g
W1=51.0kg×9.8m/s²
W1=500.31N
W2=4316.4N
P1=W1/(π/4d1²)
P1=500.31N/(π/4×(0.18m)²
P1=19660.94Pa
P2=5495.81/d2²Pa
P1=P2
19660.94Pa=5495.81/d2²Pa
d2=0.53 m
d2=53cm
so, the diameter of the football players piston is 53cm
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Two college students push a broken down, 711 kg car to a mechanic. If the first student pushes with a force of 638 N and the second student pushes with a force of 573 N, what is the magnitude of acceleration of the car?
The magnitude of acceleration of the car is 1.70 \(m/s^{2}\) .
Acceleration is the rate of change of velocity with respect to time.
Also it is the capacity of the vehicle to gain speed.Mass of the car = 711 kg
Force exerted by the Student 1 = \(F_1\) = 638 N
Force exerted by the Student 2 = \(F_2\) = 573 N
Total force exerted on the car = F = \(F_1\) + \(F_2\)
F = 638 + 573
F = 1,211 N
As we know that, Force is the product of mass and acceleration i.e.
F = m * a
\(a = \frac{F}{m}\)
a = \(\frac{1211}{711}\)
a = 1.70 \(m/s^{2}\)
The magnitude of acceleration of the car is 1.70 \(m/s^{2}\) to push it to a car mechanic.
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11. A ball rolls across a table of height 1.2 meters, leaves the table with a speed of ve, and lands 0.69m
from the edge of the table.
vo
1.2 m
-0.69 m
a. Find the time it takes the ball to fall from the edge of the table and reach position A in the picture
above.
Answer:
sorry don't know i just need points
Explanation:
a parallel-plate air capacitor has a capacitance of 400.0 pf&a charge of magnitude point 250km each plate the place rp-600m em apart what is the potential difference between the plate
The potential difference between the plates of the parallel-plate air capacitor is 0.625 × \(10^{(-7)}\)volts, which can be written as 6.25 × \(10^{(-8)}\)volts or 62.5 nV.
The potential difference between the plates of a parallel-plate air capacitor, we can use the formula:
C = Q / V
Where C is the capacitance, Q is the charge, and V is the potential difference. Rearranging the formula to solve for V, we have:
V = Q / C
The capacitance (C) is 400.0 pF and the charge (Q) is 0.250 mC (converting 250 km to 0.250 m), we can substitute these values into the formula:
V = 0.250 mC / 400.0 pF
To perform the calculation, we need to ensure that the units are consistent. Converting 400.0 pF to Farads (F), we have:
V = 0.250 mC / 0.400 nF (1 nF = \(10^{(-9)}\) F)
V = 0.250 mC / 0.400 ×\(10^{(-9)}\) F
Simplifying the expression, we have:
V = 0.625 ×\(10^{(-7)}\)) C / F
Therefore, the potential difference between the plates of the parallel-plate air capacitor is 0.625 × 1\(10^{(-7)}\) volts, which can be written as 6.25 × \(10^{(-8)}\) volts or 62.5 nV.
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An ant on a picnic table travels 7.3 cm eastward, then 7.5 cm northward. What is the magnitude of the ant's displacement relative to its original position? Please respond rounded to one decimal place.
Answer:
10.466
Explanation:
I used pythagorean theorem. It is A^2 + B^2 = C^2 then square root of C^2 to find C which was 10.466.
A point charge (q1) has a magnitude of 3x10-6 C. A second charge (q2) has a magnitude of -1. 5x10-6 C and is located 0. 12 m from the first charge. Determine the electrostatic force each charge exerts on the other
The electrostatic force each charge exerts on the other is 2.81N .\(q_{1} =\) \(3\) × \(10^{-6} C\)\(\\q_2}\) \(= - 1.5\) × \(10^{-6} C\) They are separated by a distance \(r = 0.12m\)
Electrostatic force is \(F =\) \(\frac{kq_{1} q_{2} }{r^{2} }\)
\(F = 2.81N\)
The term "scalar" refers to a category of quantities that may be fully defined by a single magnitude. Quantities called vectors can be fully represented by their direction as well as their magnitude.
How do you define a vector's magnitude?
A vector's length is considered to be its magnitude. The letter "a" stands for the dynamic array magnitude. For further information about a vector's magnitude, go to its introduction. This article deduces formulas for vectors magnitude in considerations of their coordinates in three and two dimensions, respectively.
Magnitude is simply "distance or amount," according to the definition given in physics. It illustrates the either the absolute or relative size or velocity direction for an item.
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which investigator is credited for discovering brownian motion
The investigator credited for discovering Brownian motion is Robert Brown, a Scottish botanist and biologist.
Brown first observed the phenomenon in 1827 while studying pollen grains suspended in water under a microscope. He noticed that the pollen grains moved randomly and irregularly, which he attributed to the motion of molecules in the surrounding water.
However, it wasn't until the early 20th century that the scientific community fully understood the significance of Brown's discovery, which led to the development of the kinetic theory of matter and contributed to the understanding of atomic and molecular structures. Brownian motion also played a key role in the validation of Albert Einstein's theory of Brownian motion, which he developed in 1905.
Overall, Robert Brown's discovery of Brownian motion was a significant milestone in the history of science, contributing to our understanding of the microscopic world and leading to new discoveries in fields ranging from chemistry to physics to biology.
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PLEASE HELP—ITS PHYSICS AND I NEED ANSWERS ASAP
Use the drop-down menus to identify the order of these images for the formation of our solar system. A collapsed nebula flattens into a disc. A collapsed solar nebula. An image of our solar system. nebula. An image of our solar system.
Answer: 2 1 3
is your answer
Explanation:
your'e welcome
Answer:
First one = 2
Second one = 1
Third one = 3
Explanation:
2 1 3
can i get brainliest I need it please
A 3-kg bowling ball rolls at a speed of 5 m/s on the roof of the building that is 75 m tall.
Circle one: KE / GPE / both
Show your work for finding the values of each type of energy the object has:
The potential energy and kinetic energy of the bowling ball are 2,205 J and 37.5 J respectively.
What is the gravitational potential energy of the bowling ball?The bowling ball at the given position and speed possess gravitational potential energy and kinetic energy.
The potential energy and kinetic energy of the bowling ball is calculated as follows;
P.E = mgh
where;
m is the mass of the objecth is the heightg is acceleration due to gravityP.E = (3 x 9.8 x 75 )
P.E = 2,205 J
The kinetic energy of the bowling ball is calculated as;
K.E = ¹/₂ mv²
where;
v is the speed of the bowling ballK.E = ¹/₂ ( 3 ) x (5²)
K.E = 37.5 J
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Why does the weight of water pulls the central part of the surface down?
Answer:
Buoyancy or Upthrust
Explanation:
This is an upward force exerted by a fluid that opposes the weight of a partially or fully immersed object.
in situ quantification of the active sites turnover frequency and stability of ni-fe oxy hydrooxide for the oxygen evolution reaction
The intrinsic catalytic characteristics of nanoscale electro catalysts requires quantification of the active site count and site-specific turnover frequency (TOF).
How does turnover frequency and stability of ni-fe oxy hydroxide for the oxygen evolution reaction?Understanding the intrinsic catalytic characteristics of nanoscale electro catalysts requires quantification of the active site count and site-specific turnover frequency (TOF).
The understanding of Ni-Fe (oxy)hydroxides' electro catalytic activity and stability is hampered by the lack of efficient methods for measuring the Fe active site number and the intrinsic turnover frequency per active Fe site (TOFFe), despite the fact that Fe has been proposed as one of the most active noble-metal-free electro catalysts for the alkaline oxygen evolution reaction (OER).
The direct in situ quantification of the electrochemically active Fe site number and associated TOFFe values of Ni-Fe (oxy)hydroxides using previously unstudied Fe2+/3+ redox electrochemistry in alkaline solutions is described in this article.
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A: How far did she travel?
B: How long did she take?
Which term describes a long-term weather pattern?
air mass
climate
humidity
front
Answer:
Explanation:
The answer is Climate
Answer:
climate
Explanation:
Climate is defined as an area's long-term weather patterns. The simplest way to describe climate is to look at average temperature and precipitation over time.
A car travels 100 kilo metre due east in 2 hours. it then travels 50 kilo metre south in hour. what is its average velocity?
calculate the magnitude of the centripetal force acting on earth as it orbits the sun
The magnitude of the centripetal force acting on Earth as it orbits the Sun can be calculated using Newton's law of universal gravitation and the principles of circular motion.
According to Newton's law of universal gravitation, the force of gravity between two objects is given by the equation F = G * (m1 * m2) / r^2, where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers of mass.
In the case of Earth orbiting the Sun, Earth's mass (m1) is much smaller than the Sun's mass (m2), so we can consider Earth as the smaller mass. The centripetal force acting on Earth is provided by the gravitational force between Earth and the Sun.
The centripetal force can be expressed as Fc = m1 * (v^2) / r, where m1 is the mass of Earth, v is the velocity of Earth in its orbit, and r is the distance between the centers of Earth and the Sun.
Since the centripetal force is provided by the gravitational force, we can equate the two equations: Fc = F. Therefore, m1 * (v^2) / r = G * (m1 * m2) / r^2.
Simplifying the equation, we find that (v^2) / r = G * m2 / r^2.
The magnitude of the centripetal force can be obtained by rearranging the equation as Fc = m1 * (v^2) / r = (m1 * G * m2) / r^2.
Therefore, the magnitude of the centripetal force acting on Earth as it orbits the Sun is given by (m1 * G * m2) / r^2, where m1 is the mass of Earth, m2 is the mass of the Sun, G is the gravitational constant, and r is the distance between their centers.
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which person is known as the father of modern rocketry?
The person who is known as the father of modern rocketry is Robert H. Goddard.
The world's first liquid-fueled rocket was developed and built by Robert Hutchings Goddard, an American engineer, lecturer, and inventor who lived from October 5, 1882, to August 10, 1945. Goddard's rocket was successfully launched on March 16, 1926, ushering in an era of invention and space travel. Between 1926 and 1941, he and his team fired 34 rockets, reaching speeds of up to 885 km/h (550 mph) and heights of up to 2.6 km (1.6 mi). Many of the innovations that would enable spaceflight were foreseen in Goddard's work as an engineer and thinker.
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Which law best describes contact force
A.
second law
B.
third law
C.
law of gravity
D.
first law
Answer:
b is the answer the third law
Explanation:
B because Newton's second law, which states that the force F acting on a body is equal to the mass m of the body multiplied by the acceleration a of its centre of mass, F = ma, is the basic equation of motion in classical mechanics.
How do you test hydrogen gas
Explanation:
A splint is lit and held near the opening of the tube, then the stopper is removed to expose the splint to the gas. If the gas is flammable, the mixture ignites. This test is most commonly used to identify hydrogen, which extinguishes with a distinctive 'squeaky pop' sound.
Answer:
You can test for hydrogen gas by putting a burning splinter near the gas. The splinter will gives out a 'pop' sound (mini explosion) if it is hydrogen gas