Answer:
B
Step-by-step explanation:
What is the relationship between the value for degrees of freedom and the shape of the t distribution? Explain in detail. What happens to the critical value of t for a particular alpha level when df increases in value? Explain why t distributions tend to be flatter and more spread out than the normal distribution.
The relationship between the distribution values and the t-distribution as per the question with relation to degrees of freedom, the answer will be as follows:
1. When the sample size is small or the population standard deviation is unknown, the t-distribution is a probability distribution that is utilized in hypothesis testing and confidence interval estimates. The degrees of freedom (df), which is a gauge of sample size, determine the form of the t-distribution.
2. The t-distribution gets increasingly symmetric as df rises and becomes closer to a normal distribution. In other words, the t-distribution becomes more like the regular normal distribution and less dependent on the sample standard deviation as the sample size grows. This is so that the population standard deviation may be estimated with greater accuracy thanks to the increased sample size.
3. Since they have thicker tails than the normal distribution, t-distributions tend to be flatter and more dispersed. This results in a broader distribution since there is a larger likelihood that the sample may contain extreme values.
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here are 10 brown, 10 black, 10 green, and 10 gold marbles in bag. A student pulled a marble, recorded the color, and placed the marble back in the bag. The table below lists the frequency of each color pulled during the experiment after 40 trials..
Outcome Frequency
Brown 13
Black 9
Green 7
Gold 11
Compare the theoretical probability and experimental probability of pulling a green marble from the bag.
The theoretical probability, P(green), is 50%, and the experimental probability is 11.5%.
The theoretical probability, P(green), is 25%, and the experimental probability is 25%.
The theoretical probability, P(green), is 25%, and the experimental probability is 17.5%.
The theoretical probability, P(green), is 50%, and the experimental probability is 7.0%.
Note that where the above conditions are given, the theoretical probability, P(green), is 25%, and the experimental probability is 17.5%. (Option C)
How is this so?The theoretical probability of pulling a green marble form th back =
Number of green marbles/total number of marbles in the bag
= 10/40 = 25%
The experimental probablity is:
frequency of green marbles pulled / total number of trials
= 7/40 = 17.5
Thus, the theoretical probability is 25% while the experimental probability is 17.5% (Option C)
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Find x
………….. ………….. …………..
Answer : 5
Refer to the attachment
I hope this helps you...
the route used by a certain motorist in commuting to work contains two intersections with traffic signals. the copyright 2016 cengage learning. all rights reserved. may not be copied, scanned, or duplicated, in whole or in part. due to electronic rights, some third party content may be suppressed from the ebook and/or echapter(s). editorial review has deemed that any suppressed content does not materially affect the overall learning experience. cengage learning reserves the right to remove additional content at any time if subsequent rights restrictions require it. 66 chapter 2 probability probability that he must stop at the first signal is .4, the analogous probability for the second signal is .5, and the probability that he must stop at at least one of the two signals is .7. what is the probability that he must stop a. at both signals? b. at the first signal but not at the second one? c. at exactly one signal?
The probability that the motorist must stop at both signals is 0.2, at the first signal but not the second is 0.3, and at exactly one signal is 0.7.
The probability that the motorist must stop at both signals is calculated by multiplying the probability of stopping at the first signal (0.4) and the probability of stopping at the second signal (0.5). This gives a probability of 0.2 that the motorist must stop at both signals. The probability of stopping at the first signal but not the second one is calculated by subtracting the probability of stopping at the second signal (0.5) from the probability of stopping at the first signal (0.4). This gives a probability of 0.3 that the motorist must stop at the first signal but not the second one. The probability that the motorist must stop at exactly one signal is calculated by subtracting the probability of stopping at both signals (0.2) from the probability of stopping at at least one of the two signals (0.7). This gives a probability of 0.7 that the motorist must stop at exactly one signal.
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David makes a pizza with 8 slices of equal size . He covers 5 of the 8 slices with pepperoni. What percentage of the pizza is covered with pepperoni
Answer:
5/8 * 100 = 62.5 %
For what value of c is the relation a function?
{(2,8). (12,3).(0,4).(-1,8).(0,3)}
Answer:
c is 2,7
Step-by-step explanation:
Convert 6.350 to a fraction
Answer:
\(6 \frac{350}{1000}\) Is the answer, if you want it simplified then, \(6 \frac{7}{20}\)
Step-by-step explanation:
Answer:
\({ \sf{ \underline{answer \: is \: \: 6 \frac{7}{20} }}}\)
Step-by-step explanation:
Hope you got the idea in previous answer.
\(6.350 = \frac{6350}{1000} \)
reduce the fraction by 10:
\( = \frac{6350 \div 10}{1000 \div 10} \\ \\ = \frac{635}{100} \)
then reduce it by 5:
\( = \frac{635 \div 5}{100 \div 5} \\ \\ = \frac{127}{20} \)
in mixed fraction mode:
\( = 6 \frac{7}{20} \)
Estimate ΔyΔy using differentials.
y=cos(5x),=/30,x=0.055
(Give your answer to three decimal places.)
The estimated change in yy using differentials is -0.00679. This means that if xx is increased by 0.005, then yy is estimated to decrease by 0.00679. The differential of yy is dy=-5sin(5x)dxdy=−5sin(5x)dx. We are given that y=cos(5x)=π/30y=cos(5x)=π/30 and x=0.055x=0.055.
We want to estimate ΔyΔy, which is the change in yy when xx is increased by 0.005. We can use the differential to estimate ΔyΔy as follows:
Δy≈dy≈dy=-5sin(5x)dx
Plugging in the values of y, x, and dxdx, we get:
Δy≈-5sin(5(0.055))(0.005)≈-0.00679
Therefore, the estimated change in yy using differentials is -0.00679.
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A
B
-6
Find the distance, d, of AB.
A = (-7, 9) B = (-5, 3)
-4 -2
10
8
6
4
2
d = √x2-x1² + y2 - Y₁|²
d = [?]
Round to the nearest tenth.
Distance
Enter
The distance between A and B is √40.
We know the coordinates of the two points A and B.
We will use the distance formula to find the distance between A and B.
Distance Formula:
d = √(x2 - x1)² + (y2 - y1)²,
where (x1, y1) and (x2, y2) are the coordinates of the two points.
Given, the coordinates of points A and B as
A = (-7, 9)B = (-5, 3)
Using the distance formula,
d = √(x2 - x1)² + (y2 - y1)²
Substituting the values of x1, x2, y1, y2,
d = √(-5 - (-7))² + (3 - 9)²
= √2² + (-6)²
= √4 + 36
= √40
Therefore, the distance between A and B is √40, which is approximately equal to 6.3 (rounded to the nearest tenth).
d = √40 ≈ 6.3
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Which equation represents the vertical asymptote of the graph?
Ox=0
Oy=0
Ox=12
Oy=12
The equation of the vertical asymptote is:
x = 12
The correct option is the third one.
Which equation represents the vertical asymptote?The vertical asymptote of the graph is at the line where the graph tends at positive infinite and negative infinite at the same time.
You can see that it happens in the right side of the graph.
You can see that it is a vertical asymptote, so it will be represented by a vertical line, these are of the form x =a.
By looking at the graph, you can see that it is located at x = 12, so that is the equation of the vertical line. The correct option is the third one.
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suppose that the mean daily viewing time of television is hours per household. use a normal probability distribution with a standard deviation of hours to answer the following questions about daily television viewing per household.
The probability that a household views television more than 6 hours is approximately 0.0668.
Given that the mean daily viewing time of television is μ = hours per household and the standard deviation is σ = hours per household.
We need to use the normal probability distribution to answer the following questions about daily television viewing per household.
The probability of a household viewing television more than 6 hours can be found using the standard normal distribution as follows:
Z = (x - μ)/σ
We need to find P(x > 6)P(x > 6) = P(Z > (6 - μ)/σ) = P(Z > (6 - μ)/σ) = P(Z > (6 - μ)/σ) = P(Z > (6 - μ)/σ)
The mean daily viewing time of television is given as μ = 4.8 hours per household, and the standard deviation is given as σ = 0.8 hours per household.
The standardized value of 6 is:
Z = (6 - 4.8) / 0.8 = 1.5
Thus, we need to find the area under the standard normal curve to the right of 1.5 using the standard normal table or technology.P(Z > 1.5) = 0.0668
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this is for the brainlist winner
What is an equation of the line that passes through the points(-1,1) and (-2,-4)?
Answer:
The equation of a line passing through the points (-1, 1) and (2, -4) is
5x + 3y + 2=0
2) Slove the equation .2x + 1.2 = .5x
0 .2 x + 1.2 = 0 .5 x
collecting like terms, we have :
0. 5 x - 0 . 2 x = 1 . 2
0. 3 x = 1. 2
Divide both sides , we have:
x = 1 . 2 / 0. 3
x = 4
PLSSS HELP IF YOU TURLY KNOW THISSS
Answer: multiply both sides by 2
What is the simplest form of
18ab3
18b4
162ab3
162ab4
Answer:
Step-by-step explanation:
it is A - 18ab3
Answer:
question 1. A question 2. C
0.7686 ÷ -0.14 can someone answer this within 1 min for five star answer
Answer:
-5.49
Good Luck!!!
length of a rectangular grarden is Im and the breadth is 6m. calculate its area in mm2
CALCULATE THE AREA
=LENGTH X BREADTH
=6M X 1M
\(6 {m}^{2} \)
NOW CHANGE THE METRES TO MILLIMETRES
=1000MM=1M
SO,IF 1M=1000MM
THEN 6M=MORE
IF MORE LESS WILL DIVIDE
GIVING YOU
\( \frac{6}{1} \times 1000mm\)
\(6000mm\)
select the correct answer
which function represents the inverse of function f below
Answer: D
Step-by-step explanation:
draw the line of symmetry of a line segment 8.6 cm long
A line segment of length 8.6 cm, when bisected the length of each half is 4.3cm.
Draw a straight line and mark two points A and B that are 8.6 cm apart.
With A as centre and radius more than half of AB, draw arcs on both sides of AB.
With the same radius and B as centre, draw arcs on the both sides of AB, cutting the previous two arcs.
Label the intersection points of the two arcs as E and F.
Draw a straight line connecting points E and F. This is the line of symmetry and bisects the line segment AB.
The length of each part of the bisected line segment is equal. To measure the length of each part, we can use a ruler to measure the distance from point A to the intersection point C and from point B to the intersection point D. Each of these distances should be approximately 4.3 cm, which is half the length of the original segment.
we get: AC=BC=4.3 cm.
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____The given question is incomplete, the complete question is given below:
Draw a line segment of length 8.6 cm. Bisect it and measure the length of each part.
Solve the inequality. Give the solution set in both interval and graph forms; -8≤x+1<15
The solution of the inequality is:
-9 ≤ x < 14
And the graph can be seen on the image at the end.
How to solve the inequality?Here we want to solve the inequality:
-8 ≤ x + 1 < 15
To solve this, we need to isolate the variable, if we subtract 1 un all the parts we will get.
-8 - 1 ≤ x< 15 - 1
-9 ≤ x < 14
To graph this we need to draw a closed circle at x = -9 and a line that extends to the right, until it ends at an open cirlce at x = 14.
The graph is below.
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factor completely 25d^8 -80d^4 +64
Answer:
Step-by-step explanation:
(5d^4 - 8)^2
This is a perfect square.
Note an exponent multiplied by an exponent is the addition of them so
d^4 X d^4 = d^8
or
(d^4)(d^4)=d^8
a XYZ in which XY = 4.5cm YZ = 6cm and ZX = 7cm. 2) Construct a PQR such that PQ = 7cm, PR = 5cm and ,PQR = 60° 3) Construct a ABC given that XY = 6cm, pls answer fast tomorrow is my exam so pls answer this question
To measure length ABAC=3.5 cm, open the compass,=3.5cm is a positive value because. Hence, BD will be higher than BC. Cut an arc on ray BX using point B as the center. Let D be where the arc crosses BX.
What are angles?A point where two lines meet produces an angle.
The breadth of the "opening" between these two rays is referred to as a "angle". It is depicted by the figure.
Radians, a unit of circularity or rotation, and degrees are two common units used to describe angles.
By connecting two rays at their ends, one can make an angle in geometry. The sides or limbs of the angle are what are meant by these rays.
The limbs and the vertex are the two main parts of an angle.
The common terminal of the two beams is the shared vertex.
According to our question-
draw perpendicular bisector of CD
A where perpendicular bisector intersects BD
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What is the simplified expression for 2(x-5)?
2x
-10x
2x-10
2x+5
Answer:
2x-10
Step-by-step explanation:
2(x) - 2(5) = 2x - 10
I WILL GIVE BRAINLIEST TO CORRECT ANSWER
-x<-x+7(x-2)
Answer:
x>2
Step-by-step explanation:
0<7x-14
-7x<-14
x>2
hope that's right
Answer:
x > 2
Step-by-step explanation:
-x < -x+7(x-2)
0 < 7(x-2)
0 < x-2
x > 2
(edited)
if a vector a has components ax < 0, and ay > 0, then the angle that this vector makes with the positive x-axis must be in the range group of answer choices 180° to 270° 0° to 90° 270° to 360° it cannot be determined without additional information. 90° to 180°
The angle vector 'a' makes with the positive x-axis is 90° to 180°.
What is a vector?A vector is a quantity that has magnitude as well as direction one such example of this is velocity where we describe speed and direction also.
Given a vector a with two components one in the x direction and another one in the y direction.
The x component of the vector ax < 0 which is on the 2nd quadrant and the y component of the vector is ay > 0 which we join to the tail of the component ax.
∴ The angle it makes with the positive x-axis is 90° to 180° as it is on the second quadrant.
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17. Who am I? ___ Collection of one or more different types of variables, including arrays and pointers, that have been grouped under a single name for each manipulation.
a) template
b) array
c) structure
d) local variables
You are c) a structure. A structure is a collection of one or more different types of variables, including arrays and pointers, that have been grouped under a single name for each manipulation.
A structure is a user-defined data type that allows you to group together related data. For example, you could create a structure to store the name, age, and address of a person. The structure would have three variables, each of a different type: a string variable for the name, an integer variable for the age, and a string variable for the address.
The advantage of using a structure is that it allows you to treat the related data as a single unit. This makes it easier to manipulate the data and to pass the data to functions.
The other answer choices are incorrect. A template is a blueprint for creating a generic class or function. An array is a collection of elements of the same type. Local variables are variables that are declared within a function and that are only accessible within the function.
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what dose a and x equal
2³x 5- (√-1) a+ 5a - 3÷ x³
The terms in which value of x when substituted leaves final value of p(x) = "0".
Here, x - 2 is factor. So value of x is 2.
Substituting value of x we get,
p(x) = x3 - 3x + 5a
p(2) = 2*3 - 3(2) + 5a
0+ 8-6 + 5a
-2 = 5a
a= -0.4
Plz mark me as brainliest
Solve for the value of v
Answer:
v=31
Step-by-step explanation:
when the sum of the lowest data value and the highest data value is divided by 2, the measure is called the .
The lowest and greatest values in the dataset, divided by two, make up the Mid-range. Thus, this provides us with the midrange value.
What do we mean by the Mid-range?The mid-range or mid-extreme is the arithmetic mean of the highest and minimum values of the data set and is used in statistics as a measure of a sample's central tendency.
The difference between the greatest and minimum values, which is a measure of statistical dispersion, is strongly related to the mid-range.
The two measurements are complementary in that one can determine the sample's maximum and minimum values by knowing the range and the midpoint.
Therefore, the lowest and greatest values in the dataset, divided by two, make up the Mid-range. Thus, this provides us with the midrange value.
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