A 3.20 kg fish is attached to the lower end of a vertical spring that has negligible mass and force constant 850 N/m . The spring initially is neither stretched nor compressed. The fish is released from rest.What is its speed after it has descended 0.0490 m from its initial position?

Answer:

A force of attraction that exists between any two masses, bodies, or particles.

Explanation:

Answer:

The gravitational force is a force that attracts any objects with mass. You, right now, are pulling on every other object in the entire universe! This is called Newton's Universal Law of Gravitation. ... And if you triple the distance between two objects, you reduce the force to a ninth.

Explanation:

So the right answer is 0.98 watt.

look at the attached picture

Hope it will help you

Answer: a + b = (-2,5)

Explanation: I'm assuming that these are 1-dimensional matrices or vectors.

So,

a + b = [ a(x) + b(x), a(y) + b(y) ]

        = [ (3) + (-5) , (2) + (3) ]

        = [ (-2) , (5) ]

a +b = (-2,5)

Answer:

Explanation:

When spheres or objects come into contact and then move apart, it is typically due to the presence of an external force or energy imparted to the system. There are a few possible reasons for spheres to move apart after contact:

Elasticity: If the spheres are made of elastic materials, such as rubber or certain metals, they can deform upon contact and then regain their original shape when the external force is removed. This elasticity causes the spheres to move apart.

Repulsive forces: If the spheres have like charges or magnetic properties, they can experience repulsive forces when brought close together. These repulsive forces push the spheres apart once the external force is no longer present.

Conservation of momentum: If the spheres are initially at rest and then pushed together with an external force, the conservation of momentum requires them to move apart after the force is removed. This is due to Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.

Overall, the specific reason for spheres moving apart after contact depends on the properties of the spheres and the nature of the external force or energy involved.

Answer:

45 kg is the mass of a table that weights 441 newton.

Answer:

45 kg

__________________________________________________________

Explanation:

We are given:

weight of the object = 441 N

Solving for the mass of the object:

We know that the weight of an object is the force applied by gravity to pull it towards the ground. So, we can say that:

Weight = Mg

[where M is the mass of the object and g is the gravitational constant]

replacing the variables with given values

441 = M(9.8)                                                     [since g = 9.8 m/s²]

Dividing both sides by 9.8

M = 441 / 9.8

M = 45 kg

Hence, the object has a mass of 45 kg

Answer:

F' = F

Explanation:

The gravitational force of attraction between two objects can be given by Newton's Gravitational Law as follows:

\(F = \frac{Gm_1m_2}{r^2}\)

where,

F = Force of attraction

G = Universal gravitational costant

m₁ = mass of first object

m₂ = mass of second object

r = distance between objects

Now, if the masses and the distance between them is doubled:

\(F' = \frac{G(2m_1)(2m_2)}{(2r)^2}\\\\F' = \frac{Gm_1m_2}{r^2}\)

F' = F

After the collision, the combined fish are moving at 36 cm/s.

The rate and direction of an object's motion are described by the vector quantity of velocity. It measures how quickly an object shifts in relation to time. Speed, a scalar term that merely defines how quickly an object is traveling without taking into account its direction, is distinct from velocity.

The law of conservation of momentum, which states that the sum momentum of a closed system remains constant before and after a collision, can be used to complete the table.

The big fish's momentum is: before collision.

Big Fish: Momentum Before collision = mass x velocity

Big Fish: Momentum before collision = 1 kilogram x 45 cm/s

Big Fish: Momentum before collision = 45 kg/s.

The little fish is at rest, thus it has no momentum prior to the collision.

Before the collision, the total kinetic energy is:

Total - Momentum Before Collision = the sum of the momentum of the large and little fish before the collision.

Total - Momentum before to Collision = 45 kg/s + 0

Total - Momentum before to Collision = 45 kg cm/s.

Both the huge and little fish will continue to travel at the same speed after the accident. Assume that the combined fish are moving at a speed of v.

Following the collision, the combined fish have the following momentum:

Combined Fish - Momentum after collision = Mass of big fish + mass of the small fish) x Velocity .

Combined Fish - Momentum after collision = (1 kg + 0.25 kg) x v

Momentum after collision for combined fish = 1.25 kg x v.

The total momentum after the collision must match the total momentum before the collision since the law of conservation of momentum is in effect. Therefore:

Total - Momentum before the collision = total - momentum after the collision.

Combined fish - Momentum after collision = 45 kg cm/s.

When we make the following substitution for the expression for the combined fish's momentum following the collision:

1.25 kg x v = 45 kg cm/s

To solve for v, we obtain:

v = 36 cm/s

As a result, the combined fish's speed after the collision is 36 cm/s.

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Answer: 6.08 m/s

Explanation:

w=mg---> (9.8)(0.3)=2.94

Fc=mv^2/r ---> Fc=r(FT+w)/m

V=sqrt(r(FT+w)/m)

sqrt(2(2.6+2.94)/0.3= 6.08 m/s  

hope this helps :>

Answer:

height is 78.4m

Explanation:

h=u.t + 0.5.g.t^2

= 0 + 0.5x9.8x4^2

= 78.4m

Answer:

Explanation:

To solve this problem, we can use the following equations for the addition of two sinusoidal waves:

y1 = A1 sin(ωt + φ1)

y2 = A2 sin(ωt + φ2)

where A1 and A2 are the amplitudes of the waves, ω is the angular frequency, t is time, and φ1 and φ2 are the initial phase angles.

(a) To find the resultant amplitude of the two waves, we can use the following equation:

Ar = √(A1^2 + A2^2 + 2A1A2cos(φ2 - φ1))

where Ar is the resultant amplitude.

Substituting the given values, we get:

Ar = √((3.0 × 10^(-6))^2 + (4.0 × 10^(-6))^2 + 2(3.0 × 10^(-6))(4.0 × 10^(-6))cos(150° - 60°))

Ar ≈ 5.03 × 10^(-6) m

Therefore, the resultant amplitude is approximately 5.03 × 10^(-6) m.

(b) To find the resultant's initial phase angle, we can use the following equation:

tan(φr) = (A1sin(φ1) + A2sin(φ2))/(A1cos(φ1) + A2cos(φ2))

where φr is the initial phase angle of the resultant wave.

Substituting the given values, we get:

tan(φr) = (3.0 × 10^(-6)sin(60°) + 4.0 × 10^(-6)sin(150°))/(3.0 × 10^(-6)cos(60°) + 4.0 × 10^(-6)cos(150°))

φr ≈ 142.85°

Therefore, the resultant's initial phase angle is approximately 142.85°.

(c) The circle of reference and the time graph for the sine waves can be drawn as follows:

Sine Waves

The blue and red arrows represent the maximum displacement of the waves. The black arrow represents the displacement of the resultant wave. The time graph shows the displacement of each wave and the resultant wave over time.

Hi there!

Recall the equation for work given a potential difference and charge:
\(\large\boxed{W = qV}\)

W = Work (J)
q = charge (C)
V = Potential difference (V)

The work is equivalent to the change in KINETIC ENERGY, and only depends on the particle's charge and the potential difference that it experiences. Mass has no impact on this.

Thus:

\(W' = (2Q)(V) = 2W\)

This is equivalent to:

\(\large\boxed{2W = \text{ d) } 2K}}\)

Answer:

equator

Explanation:

in south & north pole you could have 20+ hours daylight or night, everyday!

A metal has a work function of 3.68 eV. then the maximum kinetic energy of the ejected electrons is 3.57 × 10⁻¹⁹ J, when electromagnetic waves with a wavelength of 209 nm.

Maximum kinetic energy of the ejected electrons is given by,

Kinetic energy (K.E.) = Energy of incident photons - Work function

Given,

Workfuction = 6.68 eV

wavelength = 209 nm = 209 × 10⁻⁹ m

energy of the incident photons is given by

Energy = Planck's constant × (speed of light / wavelength)

E = (6.626 × 10^-34 J·s) × (3 × 10^8 m/s) / (2.09 × 10^-7 m)

E ≈ 9.46 × 10⁻¹⁹ J

the maximum kinetic energy of the ejected electrons is

K.E. = 9.46 × 10^-19 J - 3.68 eV

So, the work function is 3.68 eV × (1.602 × 10^-19 J/eV) ≈ 5.89 × 10^-19 J.

Substituting this value into the equation:

K.E. = 9.46 × 10^-19 J - 5.89 × 10^-19 J ≈ 3.57 × 10^-19 J

Therefore, the maximum kinetic energy of the ejected electrons

3.57 × 10⁻¹⁹ J.

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The net force on an object will be equal to 27.1 N. The net force is in the right direction.

Force can be described as the influence that changes the state of the body of motion or rest. The SI unit of force is Newton and force is a vector quantity. Force can change the direction as well as the speed of the moving object.

The force can be calculated from the product of the mass (m) and acceleration (a) of an object. The mathematical equation of the second law of motion for force is written as:

F = ma

The force P is acting in the left direction or pulling the object in the left direction. The force Q pulls the object in the right direction.

The net force  \(=F_{P} -F_{Q}\) = 12.5 - 39.6

The net force = 27.1 N   in the right direction.

Therefore, the net force of 27.1 N  on the object is pulling the object in the right direction.

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Your question is incomplete, most probably complete question was,

An object is pushed to the left with a force of P and pushed to the right with a force of Q. where P = 12.5 and Q = 39.6.

What is the net force on the object? If the net force is to the right, enter a positive value and if it is to the left, enter a negative value.

Answer:

the same

Explanation:

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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Answer:

1. Photosynthesis releases oxygen gas as a product.

2. Subtracting cellular respiration from gross primary productivity

3. True

Explanation:

1. Photosynthesis is the process by which autotrophic organisms synthesize their food in form of sugars in the presence of sunlight. Photosynthetic process combines carbon dioxide (CO2) and water (H2O) to form glucose (C6H12O6) and oxygen gas as products. The equation is as follows:

6CO2 + 6H2O → C6H12O6 + 6O2

2. Net primary productivity, denoted by NPP, refers to the amount of biomass present in an ecosystem. It can be calculated by subtracting the amount of CO2 lost via cellular respiration from the amount produced called Gross primary productivity (GPP). That is;

NPP = GPP - cellular respiration

3. The process by which organic matter is synthesized from inorganic ones by organisms called AUTOTROPHS or PRIMARY PRODUCERS is called PRIMARY PRODUCTIVITY. Examples of autotrophic organisms are green plants, algae etc. Hence, in an ecosystem that have a high primary productivity, there would be a rapid rate of conversion of solar energy to biomass via PHOTOSYNTHESIS.

Answer:

kilogram

Explanation:

Answer:

kilogram!

Explanation:

Heya!!

For calculate aceleration, lets applicate formula:

                                                   \(\boxed{a=\frac{V-V_o}{t} }\)

                                                   Δ   Being   Δ

                                          V = Final Velocity = 5 m/s

                                         Vo = Initial Velocity = 2 m/s

                                          a = Aceleration = ? m/s²

                                                   t = Time = 7 s

⇒ Let's replace according the formula:

\(\boxed{a=\frac{5\ m/s - 2 \ m/s}{7\ s} }\)

⇒ Resolving

\(\boxed{ a=0,428\ m/s^{2}}\)

Result:

The aceleration of the object is 0,428 m/s²

Good Luck!!

Answer:

Ksasdasd

Explanation:

Answer:

Gravitational force

Explanation:

Hope this helps :)

Answer:

\(1.357\times 10^{-12}\)

Explanation:

Relevant Data provided

Area which indicates A = 2.3 cm^2 = 2.3 x 10^-4 m^2

Distance which indicates d = 1.50 x 10^-3 m

Voltage which indicates V = 12 V

According to the requirement, the computation of value of its capacitance is shown below:-

\(Capacitance, C = \frac{\epsilon oA}{D}\)

\(= \frac{= 8.854\times 10^{-12}\times 2.3\times 10^{-4}}{(1.5 \times 10^{-3})}\)

= \(1.357\times 10^{-12}\)

Therefore for computing the capacitance we simply applied the above formula.

1) The starting temperature of the gas is 288 K

b) When the pressure is doubled, the temperature is 576 K

We know that we have to use the ideal gas equation so as to be able to obtain the temperature of the starting of the gas and we know that;

Pressure = 200 kPa or 1.97 atm

Volume =  3000 cm3  or 3 L

Temperature = ?

Number of moles = mass/molar mass = 7 g/28 g/mol = 0.25 moles

Then we have;

PV = nRT

T = PV/nR

T =  1.97 * 3/0.25 * 0.082

T = 5.91/0.0205

T = 288 K

If the pressure doubles and we have;

P1/T1 = P2/T2

P1T2 = P2T1

T2 = 2(1.97) * 288/1.97

T2 = 576 K

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The rock comes to a complete stop at maximum height, so velocity is zero. Gravity is responsible for the acceleration. As a result, at the top of its path, its velocity is zero and its acceleration is 9.81 m/s2, which is approximately 10 m/s2.

When an object thrown straight upwards gets to the top of its path, Its velocity is zero because it moves opposite to gravity and acceleration is 10 m/s2 , due to the rate of change of velocity of an object with respect to time.

Projectile motion is the movement of an object in which the vertical acceleration is g and the horizontal acceleration is zero. A projectile motion is used to throw a stone into the air. It rises against a deceleration of size g, which slows it down until it reaches the maximum height.

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Answer:

Transational Motion

Explanation:

The answer is that the time the diver was in the air is 1.13 seconds.

To determine the time the diver was in the air, we can use the kinematic equation:

Δy = viΔt + 1/2at²,

where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0

m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²

Simplifying, we get:

4.9t² + 5.5t - 3.0 = 0

We can solve for t using the quadratic formula:

t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s

Since time cannot be negative, the time the diver was in the air is 1.13 seconds.

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In proposal writing here are a few tips and an example of how to write one financial and Marketing Consultancy.

Proposal for Financial and Marketing Consultancy Services

Dear Abagpay Fantic Company,

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Abagpay Fantic Company has the potential to become a leader in the market, but it requires strategic planning and effective marketing strategies to achieve its goals. My expertise in financial management and marketing will provide the necessary guidance to achieve these objectives.

As a financial consultant, I will analyze your financial statements and provide recommendations for managing your cash flow, reducing costs, and increasing revenue. I will also help you develop a financial plan that aligns with your company's goals.

As a marketing consultant, I will develop a comprehensive marketing plan that will increase brand awareness, attract new customers, and retain existing ones. I will also analyze your target market and develop strategies that will increase your market share and profitability.

Our contributions to your organization will include providing regular financial reports and monitoring your company's financial performance. We will also provide market research and analysis to keep you informed of industry trends and competitor activities.

In the short term, our goals are to increase your company's revenue and profitability by implementing effective financial management and marketing strategies. We will also work towards increasing customer satisfaction and loyalty through excellent customer service and effective marketing campaigns.

Our consultancy fees will be reasonable and competitive, and we are open to negotiation based on the specific needs of your organization. Our remuneration will be based on an agreed-upon hourly rate or a project-based fee.

In conclusion, I am confident that my expertise in financial management and marketing will provide your organization with the necessary guidance to achieve its goals. I look forward to the opportunity to discuss this proposal with you in further detail.

Thank you for considering my proposal.

Sincerely,

[Your Name]

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Newton's second law allows concentrating that the response for maximum acceleration of the system is equal to the acceleration of gravity (a = g)

Newton's second law states that the net force is proportional to the product of the mass and the acceleration of the body  

         F = m a

The bold letters indicate vectors, F is the force, m and the mass and acceleration of the body, respectively.

The reference system is a coordinate system with respect to which measurements are made, in this case let's set a system where the x-axis is horizontal and the positive part is in the direction of movement, the y-axis is vertical.

In the attached we can see a diagram of the indicated system, as it indicates that there is no friction force, we write the equations for each part

truck

              T = Ma

Hanging masses

              T- m g = m a

for the rope to stay taut, the acceleration must be the same. We solve the system

             M a - m g = m a

             a = \(\frac{m}{m+ M}\)  g

This is the acceleration of the truck. Let's analyze the different cases to shrink the maximum acceleration:

              a = g

       a = \(\frac{1}{1 + \frac{M}{m} }\) g

       a = ( \(1 + \frac{M}{m}\) )⁻¹  g

The \(\frac{M}{m}\) value is  much greater than the integer, we despise it the integer

      a = \(\frac{m}{M}\) g

Since the truck mass is greater than the hanging mass, this acceleration is less than the acceleration of gravity.

       a <g

In conclusion, using Newton's second law we can concentrate that the response for maximum acceleration of the system is equal to the acceleration of gravity (a = g)

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