Answer:
1.65
Explanation:
I showed my work in the picture attached.
*Note that in this problem the astronaut is traveling in the opposite direction of the spaceship. This means when you plug in the velocity of the astronaut into your formula, you will have to make the value negative. I almost made this mistake when answering (on left in picture).
This web page helped me solve this problem and understand inelastic collisions a little better:
https://byjus.com/physics/inelastic-collision/
how to find work done under AB? can anyone teach me with detail ?
Scientifically painting finished components might be given as, W = F * d. In this example, the pressure exerted at the block is regular, however, the path of force and the direction of displacement encouraged by using this pressure is one-of-a-kind. right here, force F reacts at an attitude θ to the displacement d.
The work accomplished through pressure is defined to be the product of the aspect of the force in the path of the displacement and the importance of this displacement. formulation. work may be calculated by multiplying force and Distance inside the route of force as follows. W = F × d.
The work W is equal to the pressure f instances the distance d, or W = fd. If the force is being exerted at a perspective θ to the displacement, the work accomplished is W = FD cos θ.
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The first human-made satellite, Sputnik I, had a mass of 83.4 kg and a momentum with a magnitude of 660,730 kg·m/s. What was the satellite’s speed? Round your answer to the nearest whole number.
The satellite’s speed is 7922.4 m / s if the Sputnik I, had a mass of 83.4 kg and a momentum with a magnitude of 660,730 kg·m/s.
p = m v
p = Momentum
m = Mass
v = Velocity
m = 83.4 kg
p = 660730 kg m / s
v = p / m
v = 660730 / 83.4
v = 7922.4 m / s
Momentum can be described as a mass in motion. It is the product of the object's mass and its velocity. It can also be described as the power held by a moving body that it can exert on another body.
Therefore, the satellite’s speed is 7922.4 m / s
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Calculate Time
d
12. A vehicle drives a distance of 26000 m at a speed of 65m/s, calculate the time taken for
this journey.
13. A train travels at a speed of 16 m/s and travel a distance of 3200 m, calculate the time it
takes the train to complete this journey.
urs 14. Calculate the time it takes to travel a distance of 672 km at a speed of 96 km/h.
15. A beetle travels at a speed of 0.09 m/s, it travels a distance of 1.08 m before it is caught
in a jar. Calculate the time taken for the beetle to run.
16. Carlisle is a distance of 35 miles away from Lockerbie. If I travelled at a constant speed
5147
deudate the time takon for this journey
12. The time taken for the journey is 400 s
13. The time taken for the train is 200 s
14. The time taken is 7 h
15. The time taken for the beetle is 12 s
16. The time taken for the journey is 0.0068 h
How do i determine the time taken?The time taken in each case as given by the question can be obtain as follow:
12. The time taken for the journey
Distance traveled = 26000 mSpeed = 65 m/s Time taken =?Time taken = Distance / Speed
Time taken = 26000 / 65
Time taken = 400 s
13. The time taken for the train
Distance traveled = 3200 mSpeed = 16 m/s Time taken =?Time taken = Distance / Speed
Time taken = 3200 / 16
Time taken = 200 s
14. The time taken to travel
Distance traveled = 672 kmSpeed = 96 Km/h Time taken =?Time taken = Distance / Speed
Time taken = 672 / 96
Time taken = 7 h
15. The time taken for the beetle
Distance traveled = 1.08 mSpeed = 0.09 m/s Time taken =?Time taken = Distance / Speed
Time taken = 1.08 / 0.09
Time taken = 12 s
16. The time taken for the journey
Distance traveled = 35 milesSpeed = 5147 mile per hourTime taken =?Time taken = Distance / Speed
Time taken = 35 / 5147
Time taken = 0.0068 h
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HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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Two microwave signals of nearly equal wavelengths can generate a beat frequency if both are directed onto the same microwave detector. In an experiment, the beat frequency is 170MHz . One microwave generator is set to emit microwaves with a wavelength of 1.410cm.
If the second generator emits the longer wavelength, what is that wavelength?
Answer:
The wavelength of the wave is 1.419 cm.
Explanation:
wavelength emitted by the one micro wave = 1.41 cm
beat frequency = 170 M Hz
Let the frequency of the wave is f.
\(f=\frac{c}{\lambda }\\\\f =\frac{3\times 10^8}{0.0141}\\\\f = 2.13\times 10^{10} Hz\)
Let the frequency of the other wave is f'.
\(f' = 2.13\times 10^{10}-170\times10^6\\\\f' = 21130\times 10^6 Hz\)
The wavelength is given by
\(f' = 21130\times 10^6 Hz\\\lambda = \frac{3\times 10^8}{21130\times 10^6}\\\\\lambda = 0.01419 m = 1.419 cm\)
Write the differences between rest and motion
Answer:
Depends on position
Explanation:
Rest:
A body is said to be at rest, if it does not change its position with respect to its surroundings.
Motion:
A body is said to be in motion, if it changes its position with respect to its surroundings.
The state of rest and motion is relative
NEED HELP ASAP I WILL MARK YOU BRAINLIEST!!
Determine the small gravitational force F which the copper sphere exerts on the steel sphere. Both spheres are homogeneous, and the value of r is 65 mm. Express your result as a vector.
Answer:
\(F=3.665 \times 10^{-7} N\) acting along the line joining both the sphere and always attractive in nature.
Explanation:
The given radius of both the sphere, r= 65 mm = 0.065 m
So, the volume of the spheres, \(v= \frac 4 3 \pi r^3\)
\(v= \frac 4 3 \pi (0.065)^3 = 1.150 \times 10^{-3} m^3\)
The density of steel, \(\rho _s = 7850 kg/m^3\)
and the density of copper, \(\rho_c= 8940 kg/m^3\)
Let M be the mass of the copper ball and m is the mass of the steel ball.
So, \(M=\rho_c v= 8940\times 1.150 \times 10^{-3} = 10.281\) kg
\(m=\rho_s v= 7850\times 1.150 \times 10^{-3} = 9.0275\) kg
The gravitational force, F, between the two objects having masses M and m and separated by distance d is
\(F=\frac{GMm}{d^2}\)
Where \(G= 6.674 30 x 10^{-11} m^3 kg^{-1} s^{-2}\) is the universal gravitational constant.
When both the sphere touches each other, d = 2r= 2 x 0.065 = 0.13 m
Hence, the gravitational force between both the sphere,
\(F= \frac {6.674 30 x 10^{-11}\times 10.281 \times 9.0275}{0.13^2} \\\\F=3.665 \times 10^{-7} N\)
The nature of gravitational force is always attractive and acting along the line joining the center of both the sphere.
If magma is defined as molten rock material,do you need to melt rocks to form magma?
Explanation: Magma is molten rock found below the earth's surface. ... On the other hand, if the rocks are under greater pressure, they will require higher temperatures to melt. Melting of rocks typically occurs in the lower lithosphere or upper asthenosphere. The earth gets hot pretty quickly as you dig down from the earth's surface.
Rewire each of the following using the correct prefix using 2 decimal places where applicable.
a.0.00000123N
b. 417 000 000 kg
c. 246800
d. 0,00088 mm
Answer:
a. 1.2×10^-6
b. 0.42×10^9
c. 246.8×10^3
d. 88
Step 7: Explore the Effect of Adding More Mass to the String.
Calculate the average time it took the car to travel 0.25 and 0.50 meters with the three washers attached to the pulley. Record the averages, rounded to two decimal places, in Table C of your Student Guide.
What is the average time it took the car to travel 0.25 meters? _____ seconds.
What is the average time it took the car to travel 0.50 meters? _____ seconds.
Answer:
1.92
2.61
Explanation:
The average time taken by the car to cover a distance of 0.25 meters and 0.50 meters which is based on the three trial times are :
Distance of 0.25 meters = 2.23 seconds
Distance of 0.50 meters = 3.13 seconds
What is Distance?Distance is defined as a numerical or sometimes a qualitative measure of how far objects or points are. Distance can be described as a physical length or as an approximation based on other criteria.
It can be calculated by:
Distance= Speed x time
Where, Distance is in Meter or kilometer
Speed is in meter per second or km/min
Time is in seconds or minutes
From the above formula, we can also calculate the time like for above given information,
Average travel time to cover 0.25 meters :
(Trial 1 time + Trial 2 time + Trial 3 time) ÷ 3
(2.24 + 2.21 + 2.23) ÷ 3
(6.68 ÷ 3) = 2.226667 = 2.23 seconds
Average travel time to cover 0.50 meters :
(Trial 1 time + Trial 2 time + Trial 3 time) ÷ 3
(3.16 + 3.08 + 3.15) ÷ 3
9.39 ÷ 3 = 3.13 seconds
Thus, the average time taken to cover 0.25 and 0.50 meters are 2.23 and 3.13 seconds respectively
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If a 9000kg water flows in a minute through a pipe of cross sectional area 0.3m², what is the speed of water in the pipe?
Answer:
5 m/s
Explanation:
We are given that 9000 kg of water flows through the pipe in 1 minute. Mass flow rate = mass/time
So, mass flow rate = 9000 kg / 1 minute = 150 kg/s
We know the cross sectional area of the pipe is 0.3 m2. From continuity equation, mass flow rate = density * area * velocity
So, 150 = 1000 * 0.3 * v (Density of water is approximately 1000 kg/m3)
Solving for v (velocity):
v = 150/(1000*0.3) = 5 m/s
Therefore, the speed of water in the pipe is 5 m/s.
give pressure loss Darcy weisbach equation
Answer:
Multiply the friction factor by pipe length and divide by pipe diameter. Multiply this product by the square of velocity. Divide the answer by 2.
Explanation:
Multiply the friction factor by pipe length and divide by pipe diameter. Multiply this product with the square of velocity. Divide the answer by 2.
Hope this answer helps you
How many significant figures does 0.09164500561 have?
Answer:
10 Sig Figs
Explanation:
Just start counting at the first non zero after the decimal so in this case the nine, and count all of the numbers including zeros after that.
A 9-volt battery is used to power two lightbulbs in a series circuit. The first light bulb has a
resistance of 3 ohms and the second has a resistance of 2 ohms.
What is the power output of the battery?
Please show work if possible!
Explanation:
Total Resistance: 3+2 = 5 ohms
V=9V
Power = V²/R
=9²/5
=81/5
=16.2 W
Jason took 6 hours to travel 540 km. For the first 140 km, he
took 2 hours. What was his average speed for the rest of the
journey?
km/h
Answer: 100
Explanation:
An object completes 50 cycles in 150 s.
a. What is the period of its rotation?
b. What is the frequency of its rotation?
Answer:
a. 3 seconds
b. 0.33 Hz
Explanation:
a. Period is defined by how long, in seconds, it takes for an object to complete one revolution, or cycle. If the object completes 50 cycles in 150 seconds, then it must complete one cycle every 150/50 = 3 seconds. Therefore, the period of the object is \(\boxed{3\text{ seconds}}\).
b. Frequency is given by \(f=\frac{1}{T}\) where \(T\) is the period, in seconds. Since we just found that the period is 3 seconds, plug in \(T=3\):
\(f=\frac{1}{3}\approx \boxed{0.33\text{ Hz}}\)
a method of reducing friction
Answer:
Lubrication
Explanation:
People oil/lubricate bicycle chains because the chain turns around the cogs and rub together so this help with friction.
Hope this helps :)
Answer:
The method of reducing friction are :
i) In moving parts of machine friction can be reduced by using a ball bearing between the moving surfaces
ii) The bodies of aeroplane ,ship ,boat etc are made streamlined to reduce friction.
iii) Friction can be reduced by polishing rough surfaces. For example : carrom boards are highly polished to reduce friction.
I hope this help you:)
A car travels 50. meters due north in 15
seconds. Then the car turns around and
travels 20. meters due south in 5.0
seconds. What is the magnitude of the
average velocity of the car during this
20. second interval? [2]
The average velocity of the car during this 20 sec interval is 1.5 m/s.
Given that,
A car travels 50 metres due north in 15 seconds then car turns around the and travels 20 metres due south in 5 second.
To find :
The magnitude of the average velocity of the car during this 20 seconds interval.
Initial velocity
u = 50 metres/15 = 3.33 m/s
Final velocity
v = 20 metres/5 = 4 m/s
Displacement of car is
Displacement = 50 - 20 = 30 metres
Let V is the velocity of the car during this 20 sec interval. We know that the average velocity is given by :
V = d/t
V = 30 metres/20 = 1.5 m/s
So, the average velocity of the car during this 20 sec interval is 1.5 m/s.
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The same amount of thermal energy was added to two equal masses of Aluminum and Iron. The specific heat of Aluminum is double the specific heat of iron. If the temperature of the Aluminum's mass changes by /\T, what is the change in the Iron's mass temperature?
Answer:
it is double the temperature change of iron
If a lightbulb uses 65 W of electricity, but only uses 45 W to become light energy and uses 20 W as heat energy, how efficient m is the light bulb?
Answer:
Explanation:
the 40-watt bulb is going to require less energy to power.
A rocket fires two engines simultaneously. One produces a thrust of 725Ndirectly forward while the other gives a 513N thrust at 32.4° above the forward direction. Find the magnitude and direction (relative to the forward direction) of the resultant force which these engines exert on the rocket.
The magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.
What is the resultant force the two engines exert on the rocket?The resultant force on the rocket is calculated thus:
The 513N thrust is resolved into vertical and horizontal components;
Horizontal component: 513N cos(32.4°) = 433.14 N
Vertical component: 513N sin(32.4°) = 274.88 N
Total forward force on the rocket = 725 N + 433.14 N = 1,158.14 N
Total force at right angles:
0 + 274.88 N = 274.88 N
The resultant force (F) is then given as follows:
F² = a² + b²
F² = (1158.14 N)² + (274.88 N)²
F = √1,416,847.27
F = 1,190.3
To find the direction:
tan X 274.88 N / 1,158.14 N
X = tan⁻¹ 0.237346089419241
X = 13.35°
Therefore, the magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.
In conclusion, the resultant force is obtained by resolving the forces into vertical and horizontal components.
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What is the electric potential energy of the group of charges in the figure? (Figure 1)
that the relative placements of the charges as well as their multiples affect a set of ions' potential energy. When the specific charge have the same sign or have equal signs, the energy is positive. Or else, it is negative.
How is potential energy calculated?The force acting just on two objects affects the potential energy formula. The formula for gravitational force is P.E. (= mgh, where g seems to be the acceleration caused by gravity (9.8 m/s2 at the earth's surface) while h represents the elevation in metres.
What is a system with two charges' potential energy?As a result, the system's potential energy equals the sum of a work that was done to set up the entire system of two counts. The potential energy that exists in the combination of two charges in such an external field can be stated as follows: q1V(r1) = q2V(r2) + (q1q2/4or12).
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A ball is Thrown straight up with a speed of 30 M/S, and air resistance is negligible what is its velocity after 4.2s
Answer:
11.2 m/s
Explanation:
We need to first figure out how long it took to reach the ball's max height:
Vf = 0
Vi = 30 m/s
a = -9.81 m/s^2
t = ?
---------------
Vf = Vi + at
0 = 30 + (-9.81)t ---> -30 = -9.81t ---> 3.058 = t
t = 3.058 s
---------------
We can now solve the problem by subtracting the given time (4.2s) by the max height time (3.058s) and plugging that into a kinematic equation for Vf:
Vi = 0
a = 9.81 m/s^2
t = (4.2s - 3.058s) = 1.142 s
Vf = ?
---------------
Vf = Vi + at
Vf = 0 + (9.81)*(1.142) ---> Vf = 11.203
---------------
The velocity of the ball after 4.2s is 11.2 m/s
What are the dimensions of F = ma?
Answer:
F=[m] x [L¹T-²] = m¹L¹T²
What is my acceleration when I travel at a constant speed of 10 m/s for 50 seconds on a straight street?
Answer:
there is no acceleration
Explanation:
acceleration only occurs when the speed changes for example if you were to start at 10m/s and after ten seconds be at 50m/s then there would be acceleration but because speed is constant there is no acceleration
What are some guidelines for preventing quackery and fraud when shopping? Select
all that appy.
Select 4 correct answer(s)
Be suspicious of a sales pitch that promises results too good to be true.
Be wary of advisors who sell products.What are some guidelines for preventing quackery and fraud when shopping? Select
all that appy.
Select 4 correct answer(s)
-Be suspicious of a sales pitch that promises results too good to be true.
-Be wary of advisors who sell products. -Don’t do any research before shopping. -Be cautious of mail-order and internet sales. -Be wary of product claims. -If a celebrity or athlete promotes it-it must be good
The steps/guidelines for preventing quackery and fraud when shopping are :
Be suspicious of a sales pitch that promises results too good to be trueBe cautious of mail-order and internet sales Be wary of product claims Be wary of advisors who sell products What is Quackery and FraudQuackery involves the claim of knowledge and provision of a fake and dishonest service to unsuspecting customers or clients and this is very common in medicine.
Fraud is the false representation of a material or service in order to cause loss of money or pain to an unsuspecting client or customer. some steps to prevent fraud are as follows :
If a sales pitch is too good to be true one should keep off from such product/service.when making internet sales and mail-order customers should be careful as there are a lot of imposters on the internet.Hence we can conclude that The steps/guidelines for preventing quackery and fraud when shopping are as listed above
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You decide to go skiing but fall over. As you are attempting to get back up, you see a child start to head down the hill straight for you. If the coefficient of friction between the child and the snow is assumed to be 0, and the child appears to be 20 m above you when they start down the mountain, and the incline of the mountain is 31 degrees, how long do you have to get up and out of the way before you and the child collide?
The time taken to get up and out of the way before you and the child collide is 2.82 s.
What is the time taken to get up?The time taken to get up and out of the way before you and the child collide is calculated as follows;
s = v + ¹/₂at²
s = v + ¹/₂(g sin (31)t²
where;
v is the initial velocitys is the displacementt is the time of motionThe time taken to get up is calculated as;
20 = 0 + ¹/₂(9.8 sin (31)t²
20 = 2.524t²
t² = 20/2.524
t² = 7.925
t = 2.82 s
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Solve for x, where M is molar and s is seconds.
x=(8.9 x 10³ M-2s-¹)(0.30 M)³
Enter the answer. Include units.
Answer:
the solution for x is 0.2403 M-1s-¹
Explanation:
To solve for x, we simply need to plug in the given values and simplify:
x = (8.9 x 10³ M-2s-¹)(0.30 M)³
x = 8.9 x 10³ M-2s-¹ x (0.30 M)³
x = 8.9 x 10³ M-2s-¹ x 0.027 M³
x = 0.2403 M-1s-¹
Therefore, the solution for x is 0.2403 M-1s-¹.
A helicopter (mass = 5000 kg) lifts 1475 kg of stuff (two people and packages). Let’s say initially the helicopter is hovering (v = 0 m/s). What thrust (force) is necessary for the helicopter to hover?
While it's carrying the passengers and packages, its total mass is 5000 kg + 1475 kg = 6475 kg, so that its weight is
(6475 kg) g = 63,455 N
In order to hover, the helicopter's thrust should match this weight.