The energy stored in the solenoid when the current is 0.5 A is 0.001J.
The energy stored in a solenoid can be calculated using the formula:
E = (1/2) * L * I^2
where E is the energy stored in joules (J), L is the inductance of the solenoid in henries (H), and I is the current flowing through the solenoid in amperes (A).
The inductance of a solenoid can be calculated using the formula:
L = (μ * N^2 * A) / l
where L is the inductance in henries, μ is the permeability of free space (4π x 10^-7 H/m), N is the number of turns, A is the cross-sectional area of the solenoid, and l is the length of the solenoid.
In this case, the solenoid has 300 turns, a radius of 5 cm (0.05 m), and a length of 20 cm (0.2 m), so:
A = π * r^2 = 3.14 * 0.05^2 = 0.00785 m^2
l = 0.2 m
N = 300
μ = 4π x 10^-7 H/m
Therefore, the inductance of the solenoid is:
L = (4π x 10^-7 H/m) * (300^2) * (0.00785 m^2) / 0.2 m = 0.00925 H
Now we can use the formula for energy to calculate the energy stored in the solenoid when the current is 0.5 A:
E = (1/2) * L * I^2 = (1/2) * 0.00925 H * (0.5 A)^2 = 0.00115 J
to know more about solenoid refer here:
https://brainly.com/question/15576393#
#SPJ11
To find the energy stored in the solenoid, we'll need to calculate its inductance first and then use the formula for energy storage in an inductor.
1. Calculate the inductance (L) of the solenoid:
L = (μ₀ * N² * A) / l, where μ₀ is the permeability of free space (4π x 10⁻⁷ Tm/A), N is the number of turns, A is the cross-sectional area, and l is the length of the solenoid.
A = πr² = π(0.05 m)² = 0.00785 m² (radius converted to meters)
L = (4π x 10⁻⁷ Tm/A * 300² * 0.00785 m²) / 0.2 m = 0.0353 H (henries)
2. Calculate the energy stored (E) in the solenoid:
E = (1/2) * L * I², where I is the current.
E = (1/2) * 0.0353 H * (0.5 A)² = 0.0044125 J (joules)
So, the energy stored in the 300-turn solenoid with a radius of 5 cm, a length of 20 cm, and a current of 0.5 A is approximately 0.0044 J (joules).
Learn more about current here:
https://brainly.com/question/2424523
#SPJ11
let's say you push two wheelbarrows at exactly the same speed. which wheelbarrow will require more force to push at that constant speed.
If we push to wheelbarrow at exactly the same speed then the heavier wheelbarrow will require more force to push at that constant speed.
According to galileo's Law of Inertia and the first law of motion proposed by Newton,
If a body is in the state of rest or in the state of motion it will continue to do so, until and unless an external force is applied on the body to change it state of motion or state of rest.
According to Galileo, everybody possess some inertia.
Inertia can be defined as the property of the body that allows the body to regain its current state of rest or motion.
Inertia of a body is directly proportional to the mass of the body.
Hence we can conclude here, that the heavier wheelbarrow will require more force to push at a constant speed because we are trying to change the state of the wheelbarrow.
To know more about inertia, visit,
https://brainly.com/question/14460640
#SPJ4
oxygen moves between the respiratory system and the circlatory system when it transfers from.. to...
Oxygen moves between the respiratory system and the circulatory system when it transfers from the bronchi to the capillaries. The correct option is d.
What is the respiratory system?The capillaries (small blood vessels) lining the alveolar walls allow oxygen to diffuse from the alveoli to the blood throughout this process.
Hemoglobin in red blood cells absorbs oxygen as it enters the bloodstream. Where the blood and lungs exchange gases are known as the "alveoli." Bronchi are the air passage of the lungs. It is a large passage that passes from the trachea to the lung.
Therefore, the correct option is d. bronchi, capillaries.
To learn more about the respiratory system, visit here:
https://brainly.com/question/8754264
#SPJ1
The question is incomplete. The missing options are given below:
alveoli, capillaries
bronchi, trachea
capillaries, veins
bronchi, capillaries
why can't you get all the dust off your car by just squirting water from a hose onto it? why can't you simply remove dust just by blowing across a surface? why does dust cling to a fast rotating fan? how can a leaf stay on a car moving at high speed?
It all happens because of the law of Inertia.
The Newton's first law which is also called the law of inertia states that when a body is moving or at rest, it tends to be in the same state state until an external force is applied to it.
The dust particles can't be removed just by squirting water as the water may become stagnant and the dust particles will get mixed up with water by making a heterogenous mixture and they can remain there. Thus, a large pressure should be applied with a large amount of force which can remove the particles.
The same goes with other dust particles, they can't be removed until an external force is applied so that they leave the surface and fall off. Here, newton's first and second law works.
The leaf remains on the car because the force applied by the air on the opposite is more to make the leaf stay or sometimes they get stuck in a part of a car from where it can't be flown until a great amount of force is applied. Here, Newton's third law works.
Therefore, everything is controlled by the Newton's laws of motion.
To know more about the Newton's Law, refer: https://brainly.com/question/18452581
#SPJ4
The magnitude of a force is:
A) How fast an object moves when it is pushed
B) How far an object moves when it is pushed
C) how hard an object is pushed or pulled
D) how long it takes to push or pull an object
Answer:
c
Explanation:
force is how hard it is pulled or pushed
problem 3. a ramp of mass m is at rest on a horizontal surface. a small cart of mass m is placed at the top of the ramp and released. what are the velocities of the ramp and the cart relative to the ground at the instant the cart leaves the ramp?
At the instant where the cart leaves the ramp, the velocities of the ramp and the cart are relative to the ground as \((mgh/m+M)^{1/2}\) and \((2gh(m+M)/3m)^{1/2}\) respectively.
The velocities of the ramp and cart relative to the ground at the instant the cart leaves the ramp can be calculated using conservation of energy and momentum. The velocity of the cart relative to the ground can be found using conservation of energy as follows:
mgh = 1/2mv² + 1/2Iw²
where m is mass of cart, g is acceleration due to gravity, h is height of ramp, v is velocity of cart relative to ground, I is moment of inertia of ramp about its center of mass and w is angular velocity of ramp about its center of mass.
The velocity of ramp relative to ground can be found using conservation of momentum as follows:
mv = (m+M)V
where M is mass of ramp and V is velocity of ramp relative to ground.
Solving these equations simultaneously gives:
\(V = mgh/(m+M)^{1/2}\)
\(v = 2gh(m+M)/(3m)^{1/2}\)
where h = height of ramp.
Therefore, at the instant when cart leaves the ramp, velocity of cart relative to ground will be \((2gh(m+M)/(3m))^{1/2}\) and velocity of ramp relative to ground will be \((mgh/(m+M))^{1/2}\).
To know more about relation between velocity and ground, refer:
https://brainly.com/question/20237
#SPJ4
the crab pulsar is pulsing in visible light 30 times per second. why?
The Crab Pulsar, also known as PSR B0531+21, is a highly magnetized, rapidly rotating neutron star located in the Crab Nebula, the remnant of a supernova explosion that occurred in the year 1054.
A pulsar is a type of neutron star that emits beams of electromagnetic radiation from its magnetic poles. These beams are not aligned with the rotational axis of the pulsar but instead sweep across space as the star rotates. When one of these beams of radiation points towards the Earth, we observe a pulse of light.
In the case of the Crab Pulsar, it rotates incredibly rapidly, with a period of around 33 milliseconds (approximately 30 times per second). The fast rotation, combined with the strong magnetic field of the pulsar, results in the emission of beams of radiation that sweep past the Earth at regular intervals, causing the observed pulsing effect
learn more about pulsar here:
https://brainly.com/question/31673777
#SPJ11
PLS HELP THIS IS DUE IN 10 MINUTES Describe at least 3 uses of ultraviolet radiation and discuss whether the benefits outwheigh the risk.
Answer:
Three uses that ultraviolet radiation is used for is for cleaning tools like for doctors or dentists, suntanning, and photo therapy. This can be okay and worth the risk if used carefully and with protection. Otherwise, it can cause cancer or blindness
Explanation:
what is a limitation of the electron cloud model theory that a law about electrons would not have? the theory describes electrons in experiments, but
The theory describes electrons in experiments, but the electron cloud model theory has limitations in its ability to provide precise information about the exact position and trajectory of electrons in an atom.
This is due to the inherent probabilistic nature of electron behavior, as described by quantum mechanics. The electron cloud model represents the probability distribution of finding electrons in certain regions around the nucleus but does not provide specific information about the precise paths or orbits they follow.
On the other hand, a law about electrons would typically focus on the observed behavior or relationships of electrons rather than attempting to describe their precise positions or trajectories.
Laws, such as the law of conservation of charge or the law of electric current, provide general principles or rules that govern electron behavior within a given context. They are empirical observations derived from experimental evidence rather than detailed theoretical models.
To know more about electrons refer to-
https://brainly.com/question/12001116
#SPJ11
A self-driving car traveling along a straight section of road starts from rest, accelerating at 2.00 m/s- until it reaches a speed of 25.0 m/s. Then the vehicle travels for 85.0 s at constant speed until the brakes are applied, stopping the vehicle in a uniform manner in an additional 5.00 s. (a) How long is the self-driving car in motion in s)? (b) What is the average velocity of the self-driving car for the motion described? (Enter the magnitude in m/s.)
The self-driving car is in motion for 102.5 seconds.
The average velocity of the self-driving car for the described motion is approximately 23.80 m/s.
(a) To find the total time the self-driving car is in motion, we need to sum up the time it takes to accelerate, the time it travels at a constant speed, and the time it takes to decelerate.
Given:
Acceleration (a) = 2.00 m/s²
Final speed (vf) = 25.0 m/s
Time to decelerate (t_deceleration) = 5.00 s
Time at constant speed (t_constant) = 85.0 s
Time to accelerate:
We can use the formula of motion to find the time it takes to accelerate from rest to a final speed:
vf = vi + at
Since the initial velocity (vi) is 0 m/s:
25.0 m/s = 0 m/s + (2.00 m/s²)t
Solving for t:
t = 25.0 m/s / 2.00 m/s²
t ≈ 12.5 s
Total time in motion:
The total time in motion is the sum of the time to accelerate, the time at constant speed, and the time to decelerate:
Total time = t_acceleration + t_constant + t_deceleration
Total time = 12.5 s + 85.0 s + 5.00 s
Total time = 102.5 s
Therefore, the self-driving car is in motion for 102.5 seconds.
(b) To find the average velocity of the self-driving car, we need to calculate the total displacement and divide it by the total time.
Total displacement consists of two parts: the distance covered during acceleration and deceleration and the distance covered at constant speed.
Displacement during acceleration and deceleration:
We can use the formula of motion to find the displacement during acceleration:
vf = vi + at
Since the initial velocity (vi) is 0 m/s:
25.0 m/s = 0 m/s + (2.00 m/s²)t
Solving for t:
t = 25.0 m/s / 2.00 m/s²
t ≈ 12.5 s
Using the formula for displacement during uniform acceleration:
d = vi * t + (1/2) * a * t²
Where:
vi is the initial velocity (0 m/s)
t is the time (12.5 s)
a is the acceleration (2.00 m/s²)
d_acceleration = 0 * 12.5 + (1/2) * 2.00 * (12.5)²
Simplifying the equation:
d_acceleration = (1/2) * 2.00 * 156.25
d_acceleration = 156.25 m
The displacement during deceleration is the same as during acceleration:
d_deceleration = 156.25 m
Displacement at constant speed:
The displacement at constant speed can be calculated using the formula:
d_constant = v * t
Where:
v is the constant speed (25.0 m/s)
t is the time at constant speed (85.0 s)
d_constant = 25.0 m/s * 85.0 s
d_constant = 2125 m
Total displacement:
The total displacement is the sum of the displacements during acceleration, deceleration, and at constant speed:
Total displacement = d_acceleration + d_constant + d_deceleration
Total displacement = 156.25 m + 2125 m + 156.25 m
Total displacement = 2437.5 m
Finally, we can calculate the average velocity:
Average velocity = Total displacement / Total time
Average velocity = 2437.5 m / 102.5 s
Calculating the average velocity gives us:
Average velocity ≈ 23.80 m/s
Therefore, the average velocity of the self-driving car for the described motion is approximately 23.80 m/s.
To know more about average velocity, visit:
https://brainly.com/question/28512079
#SPJ11
How much energy is required to heat 40. 7 g of water (H2O) from −10∘C to 70∘C? Your answer should have three significant figures. Where: cice=2. 06 J/g∘C cwater=4. 18 J/g∘C ΔHfus=334 J/g
The energy required to heat 40.7 g of water (H2O) from -10°C to 70°C can be calculated as follows;Mass of water = 40.7 gTemperature change = 70 - (-10) = 80 °C Specific heat of ice = 2.06 J/g °CSpecific heat of water = 4.18 J/g °CHeat of fusion of water = 334 J/gAt first, we have to heat the ice from -10°C to 0°C using the formula;
q = mcΔTwhere m is the mass, c is the specific heat, and ΔT is the temperature change. For ice, c = 2.06 J/g °C, and the temperature change is 0 - (-10) = 10°C;
q1 = (40.7 g)(2.06 J/g °C)(10°C) = 839.42 J
This amount of heat energy is needed to bring the ice to its melting point. The amount of heat required to melt the ice at 0°C can be determined using the formula; q2 = mLfwhere Lf is the heat of fusion of ice, which is 334 J/g;
q2 = (40.7 g)(334 J/g) = 13590.8 J
Now, we have 40.7 g of water at 0°C.
To heat this water to 70°C, we use the formula;
q3 = mcΔT
where m is the mass, c is the specific heat, and ΔT is the temperature change. For water, c = 4.18 J/g °C, and the temperature change is 70 - 0 = 70°C;
q3 = (40.7 g)(4.18 J/g °C)(70°C) = 12123.94 J
The total energy required is;
\(q_total = q1 + q2 + q3 = 839.42 J + 13590.8 J + 12123.94 J = 26554.16 J\)
Thus, the energy required to heat 40.7 g of water (H2O) from −10∘C to \(70∘C is 2.66 x 10^4 J or 26.6 kJ\).
To know more about energy visit :
https://brainly.com/question/1932868
#SPJ11
Through what potential difference ΔV must electrons be accelerated (from rest) so that they will have the same wavelength as an x-ray of wavelength 0.150 nm ? Use 6.63×10−34 J⋅s for Planck's constant, 9.11×10−31 kg for the mass of an electron, and 1.60×10−19 C for the charge on an electron. Express your answer using three significant figures.
Answer is 66.9V
Part B
Through what potential difference ΔV must electrons be accelerated so they will have the same energy as the x-ray in Part A?
Use 6.63×10−34 J⋅s for Planck's constant, 3.00×108 m/s for the speed of light in a vacuum, and 1.60×10−19 C for the charge on an electron. Express your answer using three significant figures.
Electrons must be accelerated through Part A: a potential difference of 66.9 V to have the same wavelength as an x-ray of wavelength 0.150 nm. Part B: Electrons must be accelerated through a potential difference of 41.8 V.
Part A: The de Broglie wavelength of a particle can be calculated using the equation:
λ = h / √(2 * m * e * ΔV),
where λ is the wavelength, h is Planck's constant, m is the mass of an electron, e is the charge on an electron, and ΔV is the potential difference.
We can rearrange this equation to solve for ΔV:
ΔV = (h / λ)² / (2 * m * e).
Substituting the given values, we get:
ΔV = (6.63×10⁻³⁴ J⋅s / (0.150×10⁻⁹ m))² / (2 * 9.11×10⁻³¹ kg * 1.60×10⁻¹⁹ C).
Evaluating this expression, we find that ΔV is approximately 66.9 V.
Part B: The kinetic energy of an electron can be calculated using the equation:
E = (1/2) * m * v²,
where E is the energy, m is the mass of an electron, and v is the velocity.
The velocity of an electron can be found using the equation:
v = √(2 * e * ΔV / m),
where ΔV is the potential difference.
Substituting the given values, we have:
v = √(2 * 1.60×10⁻¹⁹ C * ΔV / 9.11×10⁻³¹ kg).
To find the potential difference ΔV that gives the same energy as the x-ray in Part A, we need to equate the kinetic energy of the electron to the energy of the x-ray, which is given by E = hc / λ, where c is the speed of light in a vacuum.
Setting these two expressions equal to each other and solving for ΔV, we find:
ΔV = (h * c)² / (2 * e * λ).
Substituting the given values, we get:
ΔV = (6.63×10⁻³⁴ J⋅s * 3.00×10⁸m/s)² / (2 * 1.60×10⁻¹⁹ C * 0.150×10⁻⁹ m).
Calculating this expression, we find that ΔV is approximately 41.8 V.
To know more about Electrons, refer here:
https://brainly.com/question/13599825#
#SPJ11
Two 0.55-kg basketballs, each with a radius of 19 cm , are just touching. You may want to review (Pages 399 - 401) . Part A How much energy is required to change the separation between the centers of the basketballs to 1.4 m ? (Ignore any other gravitational interactions.)
Answer:
ΔU = - 9,179 10-11 J
Explanation:
For this exercise the two basketballs are linked by gravitational interaction, so we can use gravitational energy
U = - G m₁m₂ / R
In this case the mass is equal and the initial distance is r₁ = 19 cm = 0.19 m
U₁ = - G m² / r₁
let's calculate
U₁ = - 6.67 10⁻¹¹ 0.55² / 0.19
U₁ = - 10,619 10⁻¹¹ J
when its centers are separated it is at r₂ = 1.4 m
U₂ = - 6.67 10⁻¹¹ 0.55² / 1.4
U₂ = - 1.44 10-11 J
the energy between these two points is
ΔU = U₂ - U₁
ΔU = (-1.44 +10.619) 10-11
ΔU = - 9,179 10-11 J
determine the magnitude of the gravitational force mars would exert on your body if you were on the surface of mars.
The magnitude of the gravitational force mars would exert on your body if you were on the surface of mars 252.6 N.
Why is it called gravitational force?Because it consistently attempts to pull objects together rather than pushing them apart, the gravitation force is known as attractive. It is obvious that the gravitational force directly relates to the masses of the two interacting objects; larger, more massive stars will pull apart with a stronger gravitational force. Because of size of the Earth and how far out from its core humans are on its surface, attraction (or the acceleration caused by gravity) equals 9.81 m / sec squared on Earth's surface.
Briefing:Newton's Law of Gravitation is used to mathematically determine the force between two bodies.
\($F=G \frac{M m}{r^2}$\)
\($F=6.674 * 10^{-11} * \frac{68 * 6.42 * 10^{23}}{3396000^2}=252.6 \mathrm{~N}$\)
To know more about gravitational force visit:
https://brainly.com/question/12528243
#SPJ4
The complete question is-
Determine the magnitude of the gravitational force Mars would exert on man if he was on the surface of Mars. The mass of the man is 68.0 kg . The mass of the Mars is 6.42×1023kg and its radius is 3396 km
An object with a mass of 10kg accelerates 16 m/s2 when an unknown force is
applied to it. What is the amount of force?
160 N
9.8 m/s2
165.8 kg
1.6 N
Answer:
The answer is 160 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 10 × 16
We have the final answer as
160 NHope this helps you
A long, thin solenoid has 500 turns per meter and radius 5.0 cm. The current in the solenoid is increasing at a uniform rate of 60 space A over s. What is the magnitude of the induced electric field at a point near the center of the solenoid and 2cm from the axis of the solenoid
The magnitude of the induced electric field at a point near the center of the solenoid and 2 cm from the axis is approximately 0.000589 T*m²/s.
The magnitude of the induced electric field at a point near the center of the solenoid can be calculated using the formula for the magnetic field inside a solenoid. The induced electric field is directly proportional to the rate of change of the magnetic field with respect to time. First, let's calculate the magnetic field at the given point near the center of the solenoid. The formula for the magnetic field inside a solenoid is given by B = μ₀ * n * I, where B is the magnetic field, μ₀ is the permeability of free space (4π * 10⁻⁷ T*m/A), n is the number of turns per unit length (500 turns/m), and I is the current (60 A/s).
The magnetic field at the given point can be calculated as follows:
B = μ₀ * n * I = (4π * 10⁻⁷ T*m/A) * (500 turns/m) * (60 A/s) = 0.075 T
Next, we can calculate the induced electric field at the given point using the formula E = -dΦ/dt, where E is the induced electric field and Φ is the magnetic flux. The magnetic flux is given by Φ = B * A, where A is the area perpendicular to the magnetic field.
The area at the given point can be calculated as follows:
A = π * r² = π * (0.05 m)² = 0.00785 m²
Now, we can calculate the induced electric field:
E = -dΦ/dt = -(d(B * A)/dt) = -A * dB/dt = - (0.00785 m²) * (0.075 T/s) = -0.000589 T*m²/s
To know more about magnetic flux please refer:
https://brainly.com/question/29221352
#SPJ11
which of these is not a unit of volume?
Answer:
kilograms
Explanation:
kilograms is a measurement of weight, not volume
a racing car accelerates uniformly from rest along a straight track. this track has markers spaced at equal distances along it from the start, as shown in the figure. the car reaches a speed of 140 km/h as it passes marker 2. where on the track was the car when it was traveling at 70 km/h?
The car was at a distance of one marker when it was traveling at 70 km/h. This means it was at marker 1.
A racing car accelerates uniformly from rest, which means its initial velocity (v0) is 0 km/h. It reaches a speed of 140 km/h (v1) as it passes marker 2. We want to find the position of the car when it was traveling at 70 km/h (v2).
Since the acceleration is uniform, the ratio of the velocities will be equal to the ratio of the distances covered. Therefore, we can write:
v2 / v1 = distance to reach 70 km/h (d2) / distance to reach 140 km/h (d1)
Now, let's plug in the given velocities:
70 km/h / 140 km/h = d2 / d1
0.5 = d2 / d1
Since the markers are spaced at equal distances, let's assume the distance between each marker is x. Then, the distance to reach 140 km/h (d1) is 2x (from the start to marker 2). Now we can find d2:
0.5 = d2 / (2x)
d2 = x
So, the car was at a distance of one marker when it was traveling at 70 km/h. This means it was at marker 1.
To know more about accelerates visit:-
https://brainly.com/question/2303856
#SPJ11
What should be the initial potential energy of a pile driver ram so that when it strikes piles, it delivers a kinetic energy of 20 KJ?
Answer:
the initial potential energy should be 20 kJ.
Explanation:
Based on law of conservation of energy, the kinetic energy delivered by the pile driver when it strikes the piles, should be equal to the initial potential energy.
Since the final kinetic delivered is given as 20 kJ, then the initial potential energy should be 20 kJ.
Therefore, the initial potential energy should be 20 kJ.
If you have a Corvette with a mass of 1,054 kg and a velocity of 48m/s, find the kinetic energy in J.
Kinetic energy of Corvette with a mass of 1,054 kg and a velocity of 48m/s is 12,14,208 J
What is kinetic energy?Kinetic energy is a type of power that an item or particle possesses as a result of motion. An object accelerates and acquires kinetic energy when it undertakes work—the transfer of energy—by being subjected to a net force. Kinetic energy is one of the properties of a moving object or particle, which depends on both mass and speed. The type of motion can be any combination of vibration, rotation on an axis, and translation (or transit along a path from one spot to another).
A body's translational kinetic energy is equal to 1/2mv2, or one-half of the product of its mass, m, and square of its velocity, v.
Here,
m = 1,054 kg
v = 48 m/s
KE = ?
KE = 1/2 mv²
KE = \(\frac{1}{2}\) × 1054 × 48²
KE = 0.5 × 1054 × 2304
KE = 12,14,208 J
To know more about kinetic energy, visit:
https://brainly.com/question/26472013
#SPJ13
If your muscles didn't generate opposing forces, in what specific ways would that limit us?.
If our muscles did not generate opposing forces, we would not be able to perform many of the everyday tasks we take for granted, such as:
We would be unable to move our limbs, change direction or stop suddenly. We would not be able to maintain our balance or upright posture. We would not be able to support our body weight and would not be able to lift or carry objects.We would not be able to generate the power necessary for activities such as running, jumping or throwing.What are muscles?Muscles are tissues in the body that enable you to move. They are made up of bundles of fibres that contract and relax to create movement in the body. Muscles are also responsible for maintaining posture and generating heat.
Learn more about the Muscles:
https://brainly.com/question/13920046
#SPJ4
A downhill skier reaches the steepest part of a trail. Her speed increases from 9 m/s to 18 m/s in 3 seconds. What is her average acceleration
Answer:
3m/s²
Explanation:
final velocity - initial velocity
______________________ = Acceleration
elapsed time
A downhill skier reaches the steepest part of a trail. Her speed increases from 9 m/s to 18 m/s in 3 seconds. Her average acceleration is 3 m/sec².
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.
Average acceleration = (18 -9)/3 = 3 m/sec²
A downhill skier reaches the steepest part of a trail. Her speed increases from 9 m/s to 18 m/s in 3 seconds. Her average acceleration is 3 m/sec².
To learn more about acceleration refer to the link:
brainly.com/question/12550364
#SPJ2
which obsevation would be evidence that heat was transferred by radiation?
PLEASE HELP WILL MARK AND 5 stars
What is the average repetition or time for High Knees
a block is resting on an slope. (figure 3) which of the following forces act on the block?
The forces that act on the block that is at rest on the slope are:
weightstatic frictionnormal forceWhat is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Static Friction: What Is It?A force that holds an object at rest is called static friction. The definition of static friction is: The resistance people feel when they attempt to move a stationary object across a surface without actually causing any relative motion between their body and the surface they are moving the object across.
A contact force is a normal force. A normal force cannot be applied to two surfaces that are not in contact.
Read more on force here:https://brainly.com/question/388851
#SPJ1
question
A block is resting on an slope. (Figure 3) Which of the following forces act on the block?
Check all that apply.
weight
static friction
normal force
kinetic friction
I am having a bit of difficulty with this lab question:
_________________________________________
The passage of an occluded front may be accompanied by widespread precipitation and little temperature change at ground level. This is because occluded fronts are a combination of (1). [one / two / three] cold/cool air mass(es), which shifts a (2). [cold / warm / hot] air mass (3). [aloft / sideways / downwards].
_________________________________________
Currently, I have my answers as follows:
1. two cool/cold air masses
2. warm
3. downwards
Could someone help me out and let me know if I am correct? Thanks!
This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.
When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.
In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.
Learn more about occluded fronts, here:
https://brainly.com/question/11718564
#SPJ4
A bus traveled 2.5 hours in 150 km. What was its average speed?
s=d/t
v=D/t
a=(v-v.)lt
Answer:
Average speed = 60km/hr
Explanation:
Given the following data;
Time = 2.5 hrs
Distance = 150km
To find the average speed;
Average speed = distance/time
Substituting into the equation, we have
Average speed = 150/2.5
Average speed = 60km/hr
Explain how to make a simple astronomical observation that would determine your latitude.
To determine your latitude using a simple astronomical observation, you can rely on the altitude of the North Star, Polaris.
Find a clear night sky location away from obstructions and artificial lights. Locate the North Star, Polaris, which is positioned almost directly above the North Pole. Use a compass or an app to determine the direction of true north. Observe the altitude of Polaris above the horizon using a sextant, or astrolabe, or by estimating it with your hand. Record the angle between the horizon and Polaris. Consult reference tables or charts that correlate the observed angle with latitude. Compare your recorded angle to the corresponding latitude to determine your approximate location.
By measuring the angle between the horizon and Polaris, you can estimate your latitude. This method is based on the fact that Polaris is located almost directly above the North Pole, making its altitude above the horizon directly proportional to your latitude.
By comparing your measured altitude with reference tables or charts, you can determine your approximate latitude. For precise latitude measurements, more advanced tools and techniques are necessary.
For more details regarding astronomical observation, visit:
https://brainly.com/question/919045
#SPJ4
Load calculations for circuits supplying lighting units with ballasts are based upon _____\.\*
The load calculations for circuits supplying lighting units with ballasts are based upon the total wattage of the lighting units.
This includes both the wattage of the lamps and the ballasts. The ballast wattage is typically specified by the manufacturer and should be included in the calculations. It's important to consider the maximum wattage of the lamps and ballasts that will be connected to the circuit in order to determine the appropriate wire size and circuit breaker rating.
In general, the total wattage of the lighting units should not exceed the maximum load capacity of the circuit. This ensures safe and efficient operation. Remember to consult local electrical codes and regulations for specific requirements in your area.
To know more about circuits visit:
https://brainly.com/question/12608491
#SPJ11
How does the number of fins affect energy transfer?
Answer:
Because the more coolant passed through the fins, the more energy can be emitted
why does mass decrease when acceleration increases?
Answer:
Since the mass does not change as the acceleration increases, we can say that force is equal to acceleration. Therefore, if you double the force you double the acceleration. If you increase the mass at a given force the rate of acceleration slows. Therefore, mass is inversely proportional to acceleration.