A 30 hp 460v 3-phase motor requires 35 amps at full load. the power factor is 0.86 determine the efficiency of the motor.

Earth's mean distance from the Sun is 1.495x108 kilometres, and its orbital period is 365 days. In 365.256 days (1 sidereal year), the Earth completes one orbit, covering 940 million kilometres (584 million mi).

One rotation of the Earth takes 24 hours, while that of Mars takes 25. The gas giants spin quite quickly. Jupiter's revolution takes only 10 hours to complete. Neptune takes 16 hours, Saturn 11 hours, and Uranus 17 hours. The length of time it takes an astronomical object to complete one orbit around another object is known as the orbital period (also known as the revolution period). In astronomy, it typically refers to bodies like planets or asteroids revolving about the Sun, as well as moons circling other stars, exoplanets, and double stars.

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Answer:

Please translate this into Spanish! Sorry I can't :(

Explanation:

Disadvantages of Friction:

Friction produces unnecessary heat leading to the wastage of energy.

The force of friction acts in the opposite direction of motion, so friction slows down the motion of moving objects.

Forest fires are caused due to the friction between tree branches.

1/second Equals 1.99 x 10-7 radians. Earth rotates at a rate of 1.99 x 10-7 per second.

If the angles were not approximately 1 one of, then the radius times the angle's measurement in radians, or the width of a arc s = r, would be the ratio of the distance by the point located on the circle. The result of substituting into the linear speed formula is v = r t or v = r t.

A pseudovector used in physics to express how quickly the angular location or orientation of an item changes over time is called an angular velocity or rotational velocity.

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The average speed is 47.8mi/h.

The overall distance the object covers in a given amount of time is its average speed. A scalar value represents the average speed. It has no direction and is indicated by the magnitude.

The formula for an object's general average speed is [Average Speed = Total Distance Traveled /Total Time Taken].

So, \(V_{av}\) = d / t

           = 215 / 4.5

           = 47.8mi/h

Therefore, average speed is 47.8mi/h.

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Answer:

C according to me

Explanation:

ITS HARD

Answer:

Please find the answer in the explanation

Explanation:

When you calculate the SLOPE of a line segment, what does the SLOPE represent? (Choose all that apply) the Distance traveled the Displacement the Velocity the Acceleration None of the above

The slope of any time graph can not give you distance or displacement except for position - time graph.

When you plot either distance or displacement against time, that is, distance time graph or displacement time graph, you can get speed or velocity as the slope of the line segment.

You can only acceleration as a slope in a line of best fit if velocity is plotted against time. That is, in a velocity time graph.

In order to prevent deer from crossing the highway, the experiment involved placing sound-emitting equipment at the perimeter.

A procedure used to confirm or deny a hypothesis, as well as assess the effectiveness or likelihood of something that has never been tried before, is called an experiment. By showing what happens when a particular factor is manipulated, experiments shed light on cause-and-effect relationships. Experiments have a wide range of objectives and sizes but always rely on a repeatable process and a logical analysis of the outcomes. Additionally, there are experiment conducted in nature.

While teams of scientists may spend years conducting methodical research to advance their understanding of a phenomenon, a child may conduct simple experiment to understanding how things fall to the ground. In the science classroom, students benefit greatly from experiments and other hands-on activities. Experiments can improve test results and increase student engagement.

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Answer:

density=mass/volume

density=19.3

mass=x

volume=100

we are looking for mass so we have to change the subject formula to m=dv

which means mass is equals to density multiplied by volume

m= 19.3 x 100

which is 1930.

Answer:

The Equivalence Principle of Gravity

Explanation:

The fact that objects fall to earth at the same speed is called the Equivalence Principle of Gravity.

According to the Equivalence Principle of Gravity, all things fall at the same rate when there is little to no air resistance. The value of the acceleration caused by gravity is demonstrated by the force of gravity equation to be a constant that is independent of the mass of the item.

According to Einstein's equivalence principle, it is unnecessary to distinguish between gravitational and inertial forces because they are comparable in nature.

Therefore, the Equivalence Principle of Gravity states that all objects descend to Earth at the same rate.

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The moon has a gravitational field strength one-sixth that of earth's. If a person has a mass of 60kg on Earth. Weight on moon = 10kg.

The weight of an object is the force exerted on it by gravity, which is proportional to its mass and the strength of the gravitational field. The gravitational field strength on the moon is one-sixth that of Earth's, meaning that the force of gravity pulling on objects is weaker on the moon.

To calculate the weight of a person on the moon, we need to multiply their mass by the gravitational field strength of the moon, which is 1/6 or 0.1667 of the Earth's. Therefore, the weight of a 60kg person on the moon would be:

Weight on moon = mass x gravitational field strength on moon

Weight on moon = 60kg x 0.1667

Weight on moon = 10kg

The person would weigh 10kg on the moon, which is significantly less than their weight on Earth. This is because the gravitational pull on the moon is much weaker than that on Earth. It's important to note that the person's mass remains the same regardless of where they are, while their weight varies depending on the strength of the gravitational field.

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Answer:

Hello, I'm here to help you.

↬ 78%

Explanation:

↬ Think that about 70% of the area of the earth is covered by the ocean.

↬ So the precipitation that falls on it is a smiliar percentage.

A patient is referred to a physical therapist for treatment of chronic neck pain. During the examination, the therapist notices that the patient has a marked ulnar drift.

Step 1: The physical therapist will assess the patient's neck pain, range of motion, strength, and posture to develop an appropriate treatment plan.

Step 2: Since ulnar drift is observed, the therapist will also evaluate the patient's hand and wrist function, as ulnar drift is a deformity typically seen in the hands.

Step 3: The treatment plan will address both the chronic neck pain and the ulnar drift, using techniques such as manual therapy, stretching, strengthening exercises, and postural education.

Step 4: The physical therapist may recommend adaptive equipment or splints to support the patient's hand and wrist and help reduce ulnar drift progression.

Step 5: Regular follow-ups with the physical therapist will be important to monitor progress, adjust the treatment plan as needed, and ensure the patient is effectively managing their neck pain and ulnar drift.

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Answer:

a wire carrying a currents creates a magnetic field this can interact with another magnetic field causing a force that pushes the wire at right angles. This is called the motor effect

Answer: \(2520\)¢

Explanation:

Given

Company charges \(10\)¢ per cubic inch

The dimension of the box is \(9\ in.\times 7\ in.\times 4\ in.\)

The volume of the box is

\(V=9\times 7\times 4\\V=252\ in.^3\)

Therefore cost associated with it is

\(\Rightarrow C=10\times 252\\\Rightarrow C=2520\)

Thus, the cost is \(2520\)¢.

Answer:

25.20

Explanation:

The coefficients of friction for this scenario are μs = 0.4 and μk = 0.2.

The coefficient of static friction (μs) is the ratio of the maximum force of static friction (Fs max) that can be overcome between two solid surfaces in contact with each other, while the coefficient of kinetic friction (μk) is the ratio of the force of kinetic friction between two solid surfaces in contact with each other that are in motion. Both coefficients can be used to describe the amount of friction between two surfaces, which is dependent on the type of material and surface finish. The equation F = μN is used to calculate frictional forces, where F is the force of friction, μ is the coefficient of friction, and N is the normal force, which is equal to the weight of the object in question.

The normal force N, which is equal to the weight of the object, is determined using the equation N = mg, where m is the mass of the object and g is the acceleration due to gravity. Using this information, the coefficients of friction can be calculated. In this case, the block weighs 200 N and requires 80 N of force to overcome the static friction to get it moving. The normal force is equal to the weight, which is 200 N, so the coefficient of static friction is:

μs = Fs max /N= 80 N/200 N= 0.4. For the kinetic coefficient of friction, 40 N of force is required to keep the block moving at a constant velocity. Since the block is already moving, the maximum force of static friction does not apply, so the force of kinetic friction is used. Thus, the coefficient of kinetic friction can be calculated as follows: μk = kinetic friction/N = 40 N/200 N = 0.2

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From the given situation we conclude that the plant with the smooth seeds is homozygous for the dominant trait.

There is no possibility of having children with wrinkly seeds. Only when the parent plant with smooth seeds is homozygous for the dominant characteristic is this conceivable. As a result, the parents plants' offspring will only exhibit the smooth characteristic, and there won't be any possibility of wrinkled seeds.

Gregor Mendel, an Austrian monk, developed a novel theory of inheritance based on his experimental work with pea plants in the 1860s. Most people thought heredity resulted through the blending of parental "essences" before Mendel, much as how combining blue and yellow paint will yield a green hue. Mendel, on the other hand, thought that each distinct unit (or gene) in an individual's genome acted independently to produce heredity, which is the product of discrete units of inheritance. This Mendelian idea holds that it is through the transmission of these units that a characteristic is passed on. An individual receives one gene for every parent, resulting in a pair of two genes for any given trait.

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Answer:

the answerrrrrr is d

Explanation:

edmentum

Answer:

A. 25.08 s

B. 3082.53 m

C. 3×10⁵ m/s²

Explanation:

A. Determination of the time.

This can be obtained as illustrated below:

Acceleration (a) = –9.8 m/s²

Initial velocity (u) = 245.8 m/s

Final velocity (v) = 0 m/s

Time (t) =.?

v = u + at

0 = 245.8 + (–9.8 × t)

0 = 245.8 – 9.8t

Collect like terms

0 – 245.8 = – 9.8t

– 245.8 = – 9.8t

Divide both side by –9.8

t = –245.8 / –9.8

t = 25.08 s

Therefore, it will take 25.08 s for the car to come to a complete stop.

B. Determination of the distance travelled by the car.

Acceleration (a) = –9.8 m/s²

Initial velocity (u) = 245.8 m/s

Final velocity (v) = 0 m/s

Distance (s) =?

v² = u² + 2as

0² = 245.8² + (2 × –9.8 × s)

0 = 60417.64 – 19.6s

Collect like terms

0 – 60417.64 = – 19.6s

– 60417.64 = – 19.6s

Divide both side by –19.6

s = –60417.64 / –19.6

s = 3082.53 m

Thus, the car travelled a distance of 3082.53 m before stopping completely.

C. Determination of the acceleration of the object.

Initial velocity (u) = 0 m/s

Final velocity (v) = 600 m/s

Distance (s) = 0.6 m

Acceleration (a) =?

v² = u² + 2as

600² = 0² + (2 × a × 0.6)

360000 = 0 + 1.2a

360000 = 1.2a

Divide both side by 1.2

a = 360000 / 1.2

a = 300000 = 3×10⁵ m/s²

Rutherford  conducted the experiment that showed that atoms were mostly made up of empty space.

Rutherford done an experiment in which he allowed alpha particle to bombard on gold foil . Which shows  that the atom is mostly empty space with a tiny, dense, positively-charged nucleus. Based on these results, Rutherford proposed the nuclear model of the atom.

The observations made by Rutherford led him to conclude that: A major fraction of the α-particles bombarded towards the gold sheet passed through the sheet without any deflection, and hence most of the space in an atom is empty.

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The eccentricity is 0.333.

The orbital speeds at periapse and apoapse is 7,550 m/s

The period of the orbit is 8.49 hours

The specific energy of the orbit is -3.74 × 10⁷ km²/s²

a. The semimajor axis of the orbit can be calculated as the average of the apoapse and periapse altitudes.

The semimajor axis is

(800 km + 300 km)/2 = 550 km.

The eccentricity of the orbit can be calculated using the formula

e = (apoapse - periapse)/(apoapse + periapse).

The eccentricity is (800 km - 300 km)/(800 km + 300 km) = 0.333.

b. The orbital speed at periapse can be calculated using the formula

Vp = √((2GM)/(r + ap)),

where G is the gravitational constant, M is the mass of the Earth, and r is the radius of the Earth. The orbital speed at apoapse can be calculated using the formula

Vp = √((2 * 6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻² * 5.972 × 10²⁴ kg)/((6,371 km + 300 km) * 1000))

    = 10,235 m/s

Va = √((2GM)/(r + aa)),

where aa is the apoapse altitude. Using the given altitudes, the orbital speeds at periapse and apoapse can be calculated.

Va = √((2 * 6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻² * 5.972 × 10²⁴ kg)/((6,371 km + 800 km) * 1000))

    = 7,550 m/s

c. The period of the orbit can be calculated using the formula

T = 2π√((a³)/(GM)),

where a is the semimajor axis and G is the gravitational constant.

T = 2π√(((550 km * 1000)³)/((6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻² * 5.972 × 10²⁴ kg)))

  = 8.49 hours

d. The specific energy of the orbit can be calculated using the formula

E = -GM/(2a),

where G is the gravitational constant and a is the semimajor axis.

E = -(6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻² * 5.972 × 10²⁴ kg)/(2 * 550 km * 1000)

  = -3.74 × 10⁷ km²/s²

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Explanation:

1. Force is something that pushes or pulls you

2. The 150 lbs person accelerated faster because they had less force pushing or pulling them down.

The resistance of a cylindrical germanium rod is r. The new resistance is R/3, and the right response is C. It gets reshaped into a cylinder that is one-third the size of its original shape while maintaining its volume.

A conductor's resistance is determined by its length, cross-sectional area, and substance. The resistance of a conductor is linearly related to its length for a given material and cross-sectional area. As a result, the new resistance of a cylindrical germanium rod with resistance r that has been reshaped into a cylinder with a length of one third of its original can be calculated using the following equation: R = (L)/A

where L is the conductor's length, A is its cross-sectional area, R is the conductor's resistance, and is the material's resistivity.

Since the cylinder's volume doesn't change, we can state: L1A1 = L2A2.

where the rod's initial length L1, its initial cross-sectional area A1, its new length L2, and its new cross-sectional area A2 are all given.

L2 equals L1/3 if the new length is one-third of the initial length. A2 = 3A1 as well since the volume stays constant.

These numbers are substituted in the resistance formula to provide the following results: R' = (L2)/(3A1) = (1/3) (L1/A1) = (1/3) r

The new resistance is R/3 as a result, and C is the right response.

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Answer:

hope this answer helps you.

Answer:

Molar mass of CrF3, Chromium(III) Fluoride is 108.9913096 g/mol

51.9961+18.9984032·3

Mass percentage of the elements in the composition

Element Symbol Atomic Mass Number of Atoms Mass Percent

Chromium Cr 51.9961 1 47.707%

Fluorum F 18.9984032 3 52.294%

Notes on using the Molar Mass Calculator

Chemical formulas are case-sensitive.

Enter subscripts as simple numbers.

The converter uses a simple dot instead of using a midpoint typographic dot (·) in formulas for adduct molecules, such as water of hydration.

Example: type CuSO4.5H2O instead of CuSO₄·5H₂O.

Explanation:

please mark my answer in brainlist plz

Answer:

The current through all of the resistors will add up to 10 A.

Explanation:

An ectopic heartbeat is an irregular heartbeat that happens when the heart's sinoatrial node (SA node), which is its normal heartbeat pacemaker, is disrupted. Ectopic beats originate from a location outside of the SA node, disrupting the normal heart rhythm. When it comes to the various types of ectopic beats, the most common is premature ventricular contraction (PVC).

If the ectopic impulse arises from the middle of the right atrium, the P wave will be abnormal. This occurs when the heart's ventricles experience an unexpected electrical impulse, causing them to contract prematurely. The P wave is a wave that appears on an electrocardiogram (ECG) and represents the electrical activity of the atria. The sinoatrial node generates a normal P wave, which spreads through both atria and then travels to the atrioventricular node, which slows the impulse and transmits it to the ventricles. P’ waveIf the ectopic impulse arises from the middle of the right atrium, the P' wave is abnormal.

As a result, the ECG can display the following:P waves with a single, smooth contour that are narrower than normal, P waves that have a pointed apex and are taller than normal, and P waves that merge with other waves, making them indistinguishable on the ECG.P prime waves, which are visible on an ECG, are related to supraventricular beats. They're usually seen in the early part of a supraventricular tachycardia event, which is a fast heart rate originating from the atria.

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Answer:

Student science investigatory projects provide students practical experience in using the scientific method and help stimulate their interest in scientific inquiry. Given the benefits society can realise from professional scientific inquiry, such goals in themselves have importance.

Answer:

Greta scored high in knowledge and vocabulary on the IQ test.

Explanation:

This statement highlights Greta's strengths in knowledge and vocabulary specifically, indicating that she performed well in these areas during the test. However, it does not provide information about her overall IQ score or her performance in other cognitive domains that may have been assessed in th