A 25.0 mL sample of 0.100 M NH3 (Kb = 1.8 · 10-5) is titrated with 0.100 M HCI. What is the pH at the equivalence point? Report your answer to two decimal places ____. Which of the following indicators would have the closest end point color change for the previous titration? a) Methyl red b) All of these indicators would be fine. c) Alizarin Yellow R d) Cresol red e) Bromthymol blue

The net ionic equation for the reaction between sodium chloride and mercury(I) nitrate is (option D) Hg22+(aq) + 2CH(aq) – Hg2Cl2(s).

A net ionic equation shows only the chemical species that are involved in the reaction and excludes spectator ions, which are ions that do not participate in the reaction. In this case, the spectator ions are Na+ and NO3-.

The balanced equation for the reaction shows that 2Na+ ions from NaCl combine with 2NO3- ions from Hg2(NO3)2 to form 2NaNO3 molecules, leaving behind the precipitate Hg2Cl2. The net ionic equation for this reaction therefore only shows the relevant chemical species involved in the formation of Hg2Cl2, which are Hg22+ and Cl-. Answer is option D.

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Answer: A concentrated solution of a strong acid

Explanation: The definition of a concentrated solution is one in which there is a large amount of solute relative to the solvent. In this case, there is 1 g of hydrogen chloride dissolved in 1 dm³ of water, meaning that it is a concentrated solution. Additionally, because hydrogen chloride is a strong acid, the entire molecule will dissociate into ions when added to water.

Answer:

The activation energy increases how quickly the reaction will  progress.

Explanation:

The activation energy of a chemical reaction is intimately linked to its rate. Particularly, the greater the activation energy, the slower the chemical reaction will be. The reason is: molecules can only finish the reaction as soon as they have reached the peak of the activation energy barrier. Many reactions possess such huge activation energies that they practically don't advance at all without an input of energy.

The activation energy of a particular reaction determines the rate at which it will proceed. The higher the activation energy, the slower the chemical reaction will be.

The mean free path between HI molecules at 300 K and 1.00 atm is approximately X units, and the binary number of collisions per liter per second is approximately Y.

In a gas, molecules are constantly moving and colliding with each other. The mean free path refers to the average distance a molecule travels between successive collisions. To calculate it, we need to consider the properties of the gas and its conditions.

At 300 K and 1.00 atm, we can assume the gas follows the ideal gas law. The collision diameter, represented by σ, is a measure of the effective size of the molecules. It plays a crucial role in determining the mean free path.

The mean free path (λ) can be calculated using the following formula:

λ = (1 / (√2) * (π * σ^2 * N)) / (π * d^2)

where N is the Avogadro's number and d is the number density of the gas.

To determine the binary number of collisions per liter per second, we need to consider the mean free path and the average speed of the molecules. The binary collision rate (Z) is given by:

Z = (n * v * σ)

where n is the number density of the gas and v is the average speed of the molecules.

By plugging in the appropriate values for the given conditions, we can calculate the mean free path and the binary collision rate. These values provide insight into the molecular behavior of the HI gas at the specified temperature and pressure.

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The standard reaction entropy of N2(g) + 3 H2(g) → 2 NH3(g) is -196.3 J/K·mol.

What do you mean by standard reaction entropy?

Standard reaction entropy (ΔS°) is a measure of the disorder or randomness of a chemical reaction at a constant temperature and pressure. It is defined as the change in the entropy of the system when a reaction occurs under standard conditions. The standard state for a substance is its pure form at a pressure of 1 bar and a temperature of 25°C (298 K).

The standard reaction entropy (ΔS°) of a reaction can be calculated using the standard molar entropies (S°) of the reactants and products. The formula to calculate the standard reaction entropy is:

ΔS° = ΣS° (products) - ΣS° (reactants)

To calculate the standard reaction entropy for the reaction: N2(g) + 3 H2(g) → 2 NH3(g)

S° (N2) = 191.8 J/K·mol

S° (H2) = 130.6 J/K·mol

S° (NH3) = 192.5 J/K·mol

ΔS° = [2(S° (NH3)) - (S° (N2) + 3(S° (H2))]

ΔS° = [2(192.5) - (191.8 + 3(130.6))] J/K·mol

ΔS° = -196.3 J/K·mol

Hence, the standard reaction entropy of N2(g) + 3 H2(g) → 2 NH3(g) is -196.3 J/K·mol.

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Answer:

9000J

Explanation:

Given parameters:

Mass of the jet fighter  = 5kg

Velocity  = 60m/s

Unknown:

Kinetic energy of the jet fighter  = ?

Solution:

The kinetic energy of a body is the energy due to motion of the body.

It is mathematically expressed as;

    K.E  = \(\frac{1}{2}\) m v²

m is the mass

v is the velocity

 So;

     K.E  =  \(\frac{1}{2}\)  x 5 x 60²  = 9000J

The transition within an atom that is not possible is an electron begins in an excited state and then gains enough energy to become ionized. Option D is correct.

An excited electron already has excess energy above its ground state energy level. If it gains more energy, it can transition to a higher energy level or even become ionized by being ejected from the atom. However, an electron that has already been excited and has reached its highest energy level cannot gain any more energy from the atom and therefore cannot be ionized further.

Once an electron is in its highest energy level, it is said to be in the ionization continuum and cannot be further excited or ionized by the atom. Therefore, the transition of an electron beginning in an excited state and then gaining enough energy to become ionized is not possible. On the other hand, the other three transitions listed are possible and occur naturally in many physical and chemical processes, such as atomic emission and absorption spectra. Option D is correct.

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Answer:

Cassiterite is an ore of Sn.It is also called tinstone and has molecular formula of SnO

2 . It is heavy, metallic, hard tin dioxide that is the major ore of tin. It is colourless when pure, but brown or black when iron impurities are present.

Answer:

b be a pure substance

Explanation:

Answer:

atomic number

Explanation:

Answer:

number of electrons and number of neutrons

The heat of formation of PbS is -234.6 kJ/mol.

We can use Hess's law to solve for the heat of formation of PbS:

PbO (s) + SO₂ (g) → PbSO₃ (s) ∆H₁°

2 PbSO₃ (s) → 2 PbS (s) + 2 SO₂ (g) + O₂ (g) ∆H₂° = -828.4 kJ/mol

To cancel out SO₂, we reverse the first reaction and multiply it by 2:

2 PbSO₃ (s) → 2 PbO (s) + 2 SO₂ (g) + O₂ (g) ∆H₁° = -2(OSO2) - O₂

Adding the two reactions together, we get:

2 PbS (s) + 3 O₂ (g) → 2 SO₂ (g) + 2 PbO (s) ∆H° = -828.4 kJ/mol

2 PbSO₃ (s) → 2 PbO (s) + 2 SO₂ (g) + O₂ (g) ∆H₁° = -2(OSO2) - O₂

2 PbS (s) → 2 PbSO₃ (s) ∆H = -828.4 - (-2(OSO2) - O₂) = -828.4 + 593.8 = -234.6 kJ/mol

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When an imine is reduced to an amine, a hydrogen signal is observed in the nuclear magnetic resonance (NMR) spectrum that is indicative of the newly formed amine group.

Specifically, a broad singlet peak is typically observed in the NMR spectrum at around 2-3 ppm, which corresponds to the protons attached to the nitrogen atom in the amine.

This peak is distinct from the peak observed for the protons attached to the carbon atoms in the molecule, which typically appear as sharp peaks at around 0-2 ppm in the NMR spectrum.

Additionally, the chemical shift of the amine proton peak is typically lower than that of the imine proton peak, which is typically observed at around 6-8 ppm in the NMR spectrum.

Therefore, the presence of a broad singlet peak at around 2-3 ppm in the NMR spectrum is strongly indicative that the imine has been successfully reduced to the amine.

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Answer:

42 L

Explanation:

de los parámetros en la pregunta;

V1 = 358L

T1 = 152 ° C + 273 = 425 K

P1 = 470 mmHg × 1 atm / 760 mmHg = 0.6atm

V2 =?

P2 = 6 atmósferas

T2 = 500 K

P1V1 / T1 = P2V2 / T2

P1V1T2 = P2V2T1

V2 = P1V1T2 / P2T1

V2 = 0,6 × 358 × 500/6 × 425

V2 = 107400/2550

V2 = 42 L

Answer:

1mole

Explanation:

The concentration of a substance is the amount of the solute present in a given quantity of solution. It is the number of moles of the solute in 1 L of the solution. Here the number of moles is 4.

One mole of a substance is defined as that quantity of it which contains as many entities as there are atoms exactly in 12 g of carbon - 12. The formula used to calculate the number of moles is:

Number of moles = Given mass / Molar mass

The equation connecting concentration, volume and the number of moles is:

n = C / V

n = Number of moles

C = Concentration

V = Volume

1L = 1000 mL

500 mL = 0.5 L

n = 2.0 / 0.5 = 4

Thus the number of moles is 4.

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Answer:

The answer to the question is option D

Nitroglycerin is indeed a dangerous and powerful explosive that violently decomposes when it is shaken or dropped.  The Nobel Prizes, established by Nobel's will, are prestigious international awards given annually in recognition of outstanding achievements in various fields.

Nitroglycerin is an extremely hazardous and potent explosive that undergoes violent decomposition when subjected to physical shock, such as shaking or dropping. This breakthrough allowed for controlled explosions and enhanced the efficiency and safety of construction projects. In his will, Nobel designated the establishment of the Nobel Prizes, which are internationally recognized awards presented annually in recognition of extraordinary achievements in various fields, including physics, chemistry, medicine, literature, and peace. Through his contributions, Nobel left a lasting impact on both science and humanitarian efforts.

Nitroglycerin, a highly dangerous and potent explosive, undergoes violent decomposition when exposed to physical shock. This hazardous substance was utilized by the Swedish chemist Alfred Nobel, who established the Nobel Prizes. Nobel's invention, dynamite, consisted of a mixture containing nitroglycerin and inert ingredients. Controlled explosions became possible, significantly improving the efficiency and safety of construction projects. Nobel's success and wealth from dynamite led him to establish the Nobel Prizes through his will. These prestigious awards are presented annually, recognizing exceptional achievements in various fields, such as physics, chemistry, medicine, literature, and peace. Nobel's contributions had a lasting impact on both scientific advancements and humanitarian endeavors.

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We need the structure (Refer to the attachment)

Answer:

I think we should study science in school becuase it will help us to undertsand the world more. Our knowledge as humans have progressed due to science research; at one time we didn't know how trees produce oxygen.

Explanation:

KI - Ionic compound, KCl -Ionic compound,

C₆H₁₂O₆ - Covalent compound, C₆H₄Cl₂ - Covalent compound,  

KNO₃ - Ionic compound, C₆H₅COOH - Covalent compound

CH₃COOH - Covalent compound, Paraffin wax - Covalent compound

HCl - Covalent compound

Ionic compounds are formed from the interaction between cation ions and anions. A cation of an atom can be described as an electropositive ion and can donate valence electrons. Similarly, anions of an atom are electronegative ions and can accept electrons.

In an ionic compound, there is a complete transfer of electrons in the formation of an ionic bond, therefore, there exists an electrostatic force of attraction between the ions that forms a strong bond.

In a covalent compound, there is the mutual sharing of electrons in the covalent bonds. The shared electrons are hard to give away as nuclei of two atoms together share the electrons and create a bond stronger.

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Answer:

I want to say E or B

Explanation:

The 0.125 of original atoms are remaining after 3 half cycles

Half life of a radioactive element is the time in which its radioactive atoms reduce to half of its original value.

It is given that we have three half lives after which number of  carbon atoms is to be found

After one half cycle, the number of carbon-14 atoms remaining will be 1/2 or 0.5

After the second half cycle , the number carbon 14 atoms remaining will be 1/2 of 1/2 which is equal to 1/4 or 0.25

After the third half cycle number of carbon-14 atoms remaining will be

1/2 of 1/4 which is 1/8 or 0.125

This can be easily found out using the formula of number of half cycles as \((1/2)^{n}\)

where n is the number of half cycles after which number is to be found

Hence 0.125 of original atoms are remaining after 3 half cycles

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To calculate the heat of atomization of C2HCl5, we need to break all the bonds in the molecule and convert it into individual atoms. The bond energies given in the table are the energies required to break the respective bonds.

C2HCl5 can be written as:

C-C-C-C-C
|   |   |
Cl  Cl  Cl

The total bond energies required to break all the bonds in C2HCl5 are:

5 x C-C = 5 x 347 kJ/mol = 1735 kJ/mol
2 x C-Cl = 2 x 339 kJ/mol = 678 kJ/mol
1 x C=C = 1 x 611 kJ/mol = 611 kJ/mol
Total bond energy = 3024 kJ/mol

The heat of atomization is defined as the enthalpy change for the conversion of one mole of a substance in its standard state into its constituent atoms in the gas phase. Since C2HCl5 is not in its standard state (which is the most stable state of the substance at 25°C and 1 atm pressure), we need to correct for the enthalpy of formation of C2HCl5. The enthalpy of formation of C2HCl5 is -318.8 kJ/mol.

Therefore, the heat of atomization of C2HCl5 can be calculated as:

Heat of atomization = Total bond energy + Enthalpy of formation
Heat of atomization = 3024 kJ/mol + (-318.8 kJ/mol)
Heat of atomization = 2705.2 kJ/mol

Therefore, the heat of atomization of C2HCl5 is 2705.2 kJ/mol, expressed in dimensions of enthalpy.

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The measure of the total energy radiated by a star in one second is called luminosity.

Luminosity represents the intrinsic brightness of a star and is a measure of the total power output in terms of energy. It is an important characteristic of a star that indicates its size and temperature.

Luminosity is typically expressed in units of watts or solar luminosities (the luminosity of our Sun). Flux, on the other hand, refers to the amount of energy received per unit area per unit time, and it is influenced by the distance between the star and the observer. Apparent magnitude and absolute magnitude are measures of a star's brightness as observed from Earth and at a standard distance, respectively, and they are related to luminosity but not the direct measure of energy radiated.

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Answer:

245

Explanation:

BECAUSE THERE ENERGY THEY GIVES THE IMPRESSION OF THE TURKISH

Hydrogens are removed from polyprotic acids through a stepwise dissociation process. Each hydrogen ion (H+) removed one at a time, resulting in formation of successive conjugate bases.

Strength of acid decreases with each removal of a hydrogen ion. The Ka (acid dissociation constant) of a polyprotic acid represents the equilibrium constant for the dissociation of the first hydrogen ion. The Ka value is related to the acidity of the acid. As the Ka value increases, the acid is stronger and more likely to donate its hydrogen ion. In the case of polyprotic acids, the Ka value decreases with each successive dissociation of a hydrogen ion. This is because the dissociation of subsequent hydrogen ions becomes progressively more difficult as the acid loses its positive charge and the electron density on the remaining oxygen atoms decreases.

The Kb (base dissociation constant) values are related to the Kb values of the conjugate bases of the polyprotic acids. The relationship between Ka and Kb is defined by the equation Ka x Kb = Kw, where Kw is the ion product of water. Knowing the Kb value of the conjugate base, one can determine the Ka value of the corresponding acid by using this equation. The relationship between Ka and Kb values reflects the principle of equilibrium. In an acid-base reaction, the equilibrium constant for the forward reaction (Ka) is inversely proportional to the equilibrium constant for the reverse reaction (Kb). Therefore, if the Kb value of a conjugate base is known, one can calculate the Ka value of the acid by using the equation Ka = Kw / Kb.

Overall, the relationship between Ka, Kb, and the stepwise dissociation of polyprotic acids provides insights into the acidity of the acid, the strength of its conjugate base, and the equilibrium between the acid and its conjugate base.

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Answer:

the water displaced will not help the student find the correct volume because you can not accurately calculate it. you have to get the water when it is settled then you place the wood in.

Explanation:

True, an electron loses energy in the transition from a 4f subshell to a 6s subshell

Orbitals of lower energies fill up first. The pattern of filling is 1s, 2s, 2p, 3s, 3p, 4s, 3d, etc. An full subshell of a specific orbital type must be filled before going on to the next subshell with a higher energy level since all of the orbitals inside a subshell are degenerate (of equal energy).

The orbitals are filled in accordance with the (n+1) rule, which states that even if an orbit's n value is greater, the orbits with a higher (n+1) value will be filled first.

Here, the (n+1) of the 6s orbital is 6, whereas the (n+1) of the 4f orbital is 7, filling the 4f orbital before the 6s orbital.

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Answer:

6 Watts

Explanation:

From the question given above, the following data were obtained:

Current (I) = 0.05 A

Voltage (V) = 120 V

Power (P) =?

Electrical power is defined by the following equation

The power consumption while the TV is in standby can be obtained as follow:

Power (P) = Current (I) × Voltage (V)

P = IV

With the above formula, we can obtain the power consumption while the TV is in standby. This can be obtained as follow:

Current (I) = 0.05 A

Voltage (V) = 120 V

Power (P) =?

P = IV

P = 0.05 × 120

P = 6 Watts

Therefore, the power consumption while the TV is in standby is 6 Watts.

Answer:

0.215 L HCl

Explanation:

Using the relationship (M1 x V1 = M2 x V2) between Molarity (M) and Volume (v or L), we can find the volume of the 2nd volume amount.

First we rearrange our relationship equation to: \(V_2 = \frac{M_1 * V_1 }{M_2}\)

Now, plug in the values. \(V_2 = \frac{0.2 * 2.8}{2.6}\)

Calculating these values, we end up with the answer:

0.215 L HCl