The specific heat of the aluminum : c = 0.9 J/g °C
Further explanationGiven
25 g Aluminum
Temperature from 18°C to 175 °C
Heat = 3.533 J
Required
The specific heat of the aluminum
Solution
Heat can be formulated :
Q = m . c . Δt
Input the value :
c = Q / m . Δt
c = 3,533 / 25 x (175 - 18)
c = 3533/3925
c = 0.9 J/g °C
14. 87 moles of Magnesium should form 14. 87 moles of Magnesium Chloride. 14. 77 moles of Hydrochloric acid should form 7. 97 moles of Magnesium Chloride. Only 1. 78 moles of Magnesium chloride is obtained. What is the percent yield?
PLEASE HELP and teach please
The Percent yield is 11.99%
The amount of magnesium chloride that can be produced from 4.87 moles of magnesium is:
4.87 moles Mg x (1 mole MgCl2 / 1 mole Mg) = 4.87 moles MgCl2
The amount of magnesium chloride that can be produced from 14.77 moles of hydrochloric acid is:
14.77 moles HCl x (1 mole MgCl2 / 2 moles HCl) = 7.385 moles MgCl2
The percent yield is calculated as follows:
percent yield = (actual yield / theoretical yield) x 100%
percent yield = (1.78 moles / 4.87 moles) x 100% = 36.54%
Therefore, the percent yield of the reaction is 36.54%, which is approximately equal to 11.99 when rounded to two significant figures.
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What kind of intermolecular forces act between a hydrogen molecule and an argon atom? a. Dipole-dipole interaction
b. Interaction c. Hydrogen-bonding d. Dispersion forces e. lon-dipole interaction
The kind of intermolecular forces that act between a hydrogen molecule and an argon atom is dispersion forces (option D).
Intermolecular forces are the attractive forces that act between molecules or atoms. The strength of these forces determines the physical properties of substances such as boiling points, melting points, and solubility. The five main types of intermolecular forces are: Dispersion forcesDipole-dipole interactionsHydrogen bondingIon-dipole interactionsIn the given case, a hydrogen molecule is a nonpolar molecule consisting of two hydrogen atoms sharing electrons equally between them. An argon atom is also a nonpolar atom because it has a complete octet of electrons and no permanent dipole moment.
Therefore, the only intermolecular force that can act between them is the dispersion force. Dispersion forces are caused by temporary dipoles that are induced in nonpolar molecules or atoms when they come close to each other. These temporary dipoles cause the electron distribution in adjacent molecules or atoms to become distorted, leading to a weak attraction between them. Since hydrogen molecules and argon atoms are both nonpolar, they experience dispersion forces when they come close to each other. Hence, option D is the correct answer.
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Time such as minutes, days, and months will always
be a(n) ___
variable when
graphing.
Controlled
Independent
Dependent
Extraneous
1
Can someone help me with this? Only Answer if you know!
in double replacement reactions, why will two metals not combine with each other when products are formed?
In double replacement reactions, the two metals will not combine with each other when products are formed because the atoms of metals contain less than half the full complement of electrons in their outermost shell.
What is Double replacement reaction?This is referred to as a type of reaction in which the positive and negative ions of two compounds exchange places to form two new products or substances.
The two metals will not combine with each other when products are formed because of their atoms having less than the required electrons which is needed to complement those in the outermost shell.
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We fell hot,sour and fried during ant bite why
We may feel hot, sour, and fried sensations during an ant bite due to the chemical composition of the ant's venom.
Ants inject venom into their prey or attackers through their mandibles or stingers. The venom is composed of various chemicals, including formic acid, which can cause a burning or stinging sensation. The venom also contains alkaloids, histamines, and other compounds that can cause an inflammatory response in the body, leading to redness, swelling, and itching.
The hot sensation may be due to the inflammatory response caused by the venom, which can increase blood flow and raise the temperature of the affected area. The sour sensation may be due to the acidity of formic acid in the venom. The fried sensation may be due to the burning or stinging sensation caused by the venom.
It is important to clean the affected area and apply a cold compress to reduce swelling and discomfort. If symptoms persist or are severe, medical attention may be necessary.
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PLEASE HELP!! click c, and then o in the periodic table. Finding beauty carbon dioxide in view, all the available vibrational modes of Michael. The table below, record the names of these vibrational modes in describe the vibration of the molecule in each mode.
The vibrational modes of CO2 are the symmetric stretch, the asymmetric stretch and two bending modes.
What are the vibrational modes of CO2?The question has to do with a simulation of the vibrational modes of CO2 and I would summarize that as the details of the simulation are missing.
A molecule's normal modes determine its vibrations. In a vibrational spectrum, each absorption corresponds to a normal mode. The four typical carbon dioxide modes.
These modes of vibration of the compound can be observed by the use of the infra red spectroscopy as we know.
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Some analytes must be derivatized to increase their column retention or detectability. Derivatization means Group of answer choices altering the chemical structure of the analyte to increase detection and specificity. adding fluorescent labels or combining the analyte with chiral reagents or other chemicals to increase detectability. removing dissolved gases in the solvent to produce a clear chromatogram. using multiple detectors to assist in identification.
Derivatization means adding fluorescent labels or combining the analyte with chiral reagents or other chemicals to increase detectability.
Some analytes must be derivatized to increase their column retention or detectability.
Retention time can be referred to as the amount of time a solute spends in the stationary and mobile phases of a column.
Detectability is the ability of an analyte to get detected in the mobile phase of chromatography.
The refractometer, fluorescence detector, and UV detector are the three most popular liquid chromatography detectors. These detectors increase the detectability.
For derivatization, the fluorescence detector are used.
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in the synthesis of dansylalanine, the boc group on compound 1 most likely functions to:
It is stable to most peptide synthesis conditions, such as acidic or basic conditions, allowing for the synthesis of long peptide chains without unwanted side reactions.
Dansylalanine is synthesized by reacting N-dansyl chloride with the amine group of Boc-L-alanine.
The Boc group on compound 1 in the synthesis of Dansylalanine most likely functions to protect the α-amine group of L-alanine from N-dansylation.
The α-amine group of L-alanine is a nucleophilic center that is highly reactive.
It readily reacts with electrophiles such as the N-dansyl group in N-dansyl chloride, which could have led to the formation of unwanted products if left unprotected.
The presence of the Boc group in Boc-L-alanine shields the α-amine group, making it less reactive towards electrophiles.
Therefore, when N-dansyl chloride is added to Boc-L-alanine, it reacts selectively with the carboxylate group, forming a stable amide bond with the α-amine group protected.
Once the reaction is complete, the Boc group can be removed by treating the product with an acid, unmasking the α-amine group and revealing the desired dansylalanine.
The use of the Boc group as a protecting group in peptide synthesis has become prevalent because of its stability and ease of removal.
It is stable to most peptide synthesis conditions, such as acidic or basic conditions, allowing for the synthesis of long peptide chains without unwanted side reactions.
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What is the rate constant of a first-order reaction that takes 490 secondsseconds for the reactant concentration to drop to half of its initial value
The rate constant of a first-order reaction that takes 555 seconds for the reactant concentration to drop to half of its initial value is 1.2 x 10^-3 sec^-1.
A first-order reaction refers to a chemical reaction in which the rate of reaction is proportional to the concentration of the reactant. In other words, doubling the reactant concentration doubles the reaction rate.
The time taken that is taken for original population of radioactive atoms to decay to half of initial value is called the half-life. The half-life of a first-order reaction is a constant that is related to the rate constant (k) for the reaction given by: t1/2 = 0.693/k. Radioactive decay reactions are first-order reactions.
According to the provided information, t1/2 = 555 seconds
Hence,
555 = 0.693/k
k = 0.693/555 = 0.0012486 = 1.2 x 10^-3 sec^-1
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The goal of this experiment is to separate a mixture of two unknown compounds into individual components and to identify the compounds. Answer the questions below. More than one answer may be possible. Why do we need to be especially careful when working with diethyl ether?
O because it is highly acidic and can burn the skin
O because it is extremely volatile and flammable
O Fumes can cause drownsiness & dizziness, and in high concentration, loss od consciousness
Because it is extremely volatile and flammable. Diethyl ether is a highly volatile and flammable organic solvent.
It has a low boiling point and can easily form explosive vapor-air mixtures. Therefore, it is crucial to handle diethyl ether with caution and ensure proper ventilation in the laboratory. Its flammability presents a significant fire hazard, and any ignition source, such as an open flame or electrical spark, can lead to a dangerous situation. Additionally, diethyl ether has a characteristic strong odor, and its vapors can cause drowsiness, dizziness, and in high concentrations, loss of consciousness, making it important to minimize exposure and work in a well-ventilated area.
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A ruby has a mass of 7.5 g and a volume of 1.9 cm^3. What is the density of this ruby ?
Answer: 3.94736842105
Explanation:
Density = mass/volume
Density = 7.5/1.9
Density = 3.94736842105
when using a spectrophotometer, if the pathlength is increased
When using a spectrophotometer, increasing the pathlength can affect the absorbance measurements.
A spectrophotometer measures the amount of light absorbed by a sample as it passes through a specific pathlength. According to Beer-Lambert Law, absorbance (A) is directly proportional to the pathlength (l) and the concentration (c) of the substance in the sample.
The formula for Beer-Lambert Law is: A = εlc, where ε represents the molar absorptivity of the substance. If the pathlength is increased, the absorbance will also increase, assuming the concentration and molar absorptivity remain constant. This is because the light has to travel through a longer distance in the sample, allowing more opportunities for the substance to absorb the light.
In summary, when the pathlength is increased in a spectrophotometer, the absorbance value will typically increase, which can be useful for detecting lower concentrations of a substance. However, it's important to ensure that the pathlength is kept constant and properly calibrated to ensure accurate and consistent results.
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answer for the rate please help me with my chemistry homework thank you so much
Answer:
Rate cup 1: 36.00 tsp/h.
Rate cup 2: 59.50 tsp/h.
Rate cup 3: 70.13 tsp/h.
Explanation:
Based on the given example, the units must be in tsp/hour. To do this we just have to divide tsp by seconds and then convert it to hours remembering that 1 hour equals 3600 seconds.
Let's calculate each case:
- Cup 1: 1 tsp, 1 minute 40 seconds. Remember that 1 minute equals 60 seconds, so 1 minute and 40 seconds equals 100 seconds. The calculation of the rate will look like this:
\(\frac{1\text{ tsp}}{100\text{ s}}\cdot\frac{3600\text{ s}}{1\text{ h}}=36.00\frac{tsp}{h}.\)The rate of cup 1 is 36.00 tsp/h.
- Cup 2: 2 tsp, 2 minutes 1 second. As we saw before 1 minute equals 60 seconds, so 2 minutes equals 120 seconds. 2 minutes and 1 second equals 121 seconds. The rate of cup 2 will be calculated as:
\(\frac{2\text{ tsp}}{121\text{ s}}\cdot\frac{3600\text{ s}}{1\text{ h}}=59.50\frac{tsp}{h}.\)The rate of cup 2 is 59.50 tsp/h.
- Cup 3: 3 tsp, 2 minutes 34 seconds. 2 minutes are the same that 120 seconds, so 2 minutes 34 seconds equals 154 seconds. The rate of cup 3 is calculated as follows:
\(\frac{3\text{ tsp}}{154\text{ s}}\cdot\frac{3600\text{ s}}{1\text{ h}}=70.13\frac{tsp}{h}.\)The rate of cup 3 is 70.13 tsp/h.
Which of these forms due to the force of compression?
Answer:
A. Anticline
Explanation:
Answer:A
Explanation:
Classify the following size particle: 4.2cm
I need an answer no explanation needed
Particle size is typically measured in units such as micrometers (µm) or nanometers (nm), which represent very small lengths on the order of thousandths or millionths of a meter, respectively.
What is the classification of the particle?4.2 cm is much larger than the typical size of particles and is more in the range of everyday objects.
For example, 4.2 cm is roughly the size of a golf ball or a small tomato. If you have additional information about the particle's size, such as its shape or the material it is made of, I may be able to provide more specific guidance.
Also, a particle that is 4.2 nanometers (nm) in size falls in the range of nanoscale particles, which are typically much smaller than everyday objects and are invisible to the nakεd eye.
The size of the particle can provide some clues about its potential identity or classification, but additional information about its properties, composition, and context is needed to determine its specific identity.
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fill in the blank. "Molality is defined as the __________.
a. moles solute/moles solvent
b. moles solute/kg solvent
c. moles solute/kg solution
d. moles solute/liters solution
e. none (dimensionless"
b. moles solute/kg solvent
Molality is defined as the "moles solute/kg solvent." Therefore, the correct option is (b).
What is Molality?
Molality (m) is a measure of the concentration of a solute in a solution, and is defined as the number of moles of solute per kilogram of solvent.
The equation for molality is:
m = moles of solute / mass of solvent in kg
Concentration is the ability to focus one's attention and mental effort on a specific task or activity. It involves filtering out distractions and staying attentive to the task at hand. The level of concentration can vary depending on the person, the task, and the environment.
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because of our belief in the law of conservation of mass, it seems reasonable that
Because of our belief in the law of conservation of mass, it seems reasonable that matter cannot be created or destroyed, only changed in form or transferred from one substance to another.
This law is fundamental to our understanding of the physical world, and it has many practical applications in fields like chemistry, physics, and engineering. It helps us to predict the outcomes of chemical reactions, to balance equations, and to understand the behavior of materials under different conditions.
The law of conservation of mass is a fundamental principle that underlies much of what we know about the world around us, and it will continue to play an important role in scientific research and development for years to come.
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why is edta used to determine the hardness of water
EDTA (ethylenediaminetetraacetic acid) is commonly used to determine the hardness of water due to its ability to form complexes with metal ions, particularly calcium and magnesium ions.
Water hardness refers to the concentration of calcium and magnesium ions present in water. These ions can cause scaling, reduce the effectiveness of soaps, and have other negative effects. EDTA acts as a chelating agent, meaning it can bind to metal ions and form stable complexes.
In the process of determining water hardness, a known amount of EDTA solution is added to a water sample. The EDTA molecules form complexes with the calcium and magnesium ions present in the water.
The endpoint of the titration is reached when all the metal ions are complexed by the EDTA, resulting in a color change or an indicator reaching a specific endpoint.
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if matter cant be created nor be destroyed so how was the universe was formed
Answer: By the very laws of the universe, matter cannot be created or destroyed, the Big Bang cannot have happened by its own power. There was a creator involved.
The final electron acceptor in aerobic respiration is....... NAD water oxygen pyruvate O hydrogen . Answer al Question 16 Which of the following processes generate carbon dioxide? Hint There are more than one. Glycolysis Oxidative Phosphorylation The Link Reaction (pyruvate oxidation) The Citric Arid Cycle Lactic Acid Fermentation Alcoholic Fermentation
The final electron acceptor in aerobic respiration is oxygen (O2).The electron transport chain (ETC) in cellular respiration relies on a final electron acceptor to help oxygen get reduced into water. This is why oxygen is considered the final electron acceptor in cellular respiration.
During cellular respiration, glucose is broken down into pyruvate. Pyruvate is then transformed into acetyl CoA and enters the citric acid cycle, where it is oxidized and generates ATP, NADH, and FADH2. The final stage of aerobic respiration involves the electron transport chain, in which electrons from NADH and FADH2 are passed through a series of proteins and coenzymes in the inner mitochondrial membrane, ultimately reducing oxygen to form water.
This process is known as oxidative phosphorylation.In conclusion, the final electron acceptor in aerobic respiration is oxygen (O2), and carbon dioxide is generated in the link reaction (pyruvate oxidation) and the citric acid cycle.
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Give an example of an amorphous solid.... PLS HELP ON THIS
Please someone help me out thank you I’ll give brainlist :))
Answer:
Ionization energy increases going left to right across a period and increases from bottom to top in a group
Electron affinity increases when going up a group
If we are excluding noble gases (aka group 8/18), Chlorine is the element that has the greatest electron affinity. This is because Fluorine's 2p orbital is limited and packed which doesn't quite allow sharing of the orbital with extra electrons easily, while Chlorine has a 3p orbital allowing more space for electrons, where the orbital electrons would be inclined to do so.
Helium is the element with the greatest ionization energy since it's at the top and energy (from Oganesson to Helium) increases when going across a period (from Hydrogen to Helium).
The blending of one s atomic orbital and two p atomic orbitals produces A) three sp hybrid orbitals B) two sp2 hybrid orbitals C) three sp3 hybrid orbitals D) two sp' hybrid orbitals E) threesp2 hybrid orbitals
The blending of one s atomic orbital and two p atomic orbitals produces three sp hybrid orbitals.
When an s orbital and two p orbitals combine, they undergo hybridization to form three sp hybrid orbitals. This hybridization occurs when an atom is bonded to three other atoms in a trigonal planar arrangement. The process involves mixing one s orbital and two p orbitals to form three equivalent hybrid orbitals.
These sp hybrid orbitals have a linear shape with an angle of 180 degrees between them. The term "sp" indicates that the hybrid orbitals are a combination of one s orbital and one p orbital. This type of hybridization is commonly observed in molecules with triple bonds or in the central atom of trigonal planar molecules.
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what assumptions are we making when using the methods described for this experiment in your lab manual? select all that apply group of answer choices the concentrations of the reactants do not change while heating we make no assumptions in this lab the a factor of the arrhenius equation remains constant water bath temperature fluctuations (1-2 oc) do not significantly affect the rate of the reaction
When using the methods described for this experiment in your lab manual, the assumptions made are: option (A) and option (C) - "The concentrations of the reactants do not change while heating", and "the A factor of the Arrhenius equation remains constant".
This experiment's methods are to prepare a reaction mixture, determine the reaction rate, and determine the activation energy of the reaction. The assumptions made while using the methods described in the lab manual are listed below:
1- The concentrations of the reactants do not change while heating
2- The A factor of the Arrhenius equation remains constant
3- Water bath temperature fluctuations (1-2 oc) do not significantly affect the reaction rate
While using these methods, you should also take care of the following things:
1- Don't discard the reactants or products down the sink without asking the instructor.
2- In some cases, they need to be disposed of in hazardous waste containers.
3- Wear goggles and aprons at all times when working with chemicals.
4- Do not touch the equipment until you have been instructed on how to use it.
5- It's important to read the lab manual carefully and understand the risks and precautions involved.
6- Follow the given instructions properly and perform the experiment with the appropriate equipment and materials.
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What is the volume of these gases atSTP A-3. 20x10^-3mol CO2
So, the volume of the gases at STP is approximately \(2.54 * 10^{-5} m^3.\)
The volume of a gas at STP (standard temperature and pressure) can be calculated using the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.
To find the volume of \(CO_2\) at STP, we need to know its molar volume at STP, which is approximately 8.08 x 10^-6 m^3/mol.
Therefore, the volume of \(3.20 * 10^{-3\) mol \(CO_2\) at STP can be calculated as follows:
V = nRT / P
V =\((3.20 * 10^{-3} mol) * (8.08 * 10^{-6} m^3/mol) * (8.314 J/(mol*K)) * (273.15 K) / (1 atm)\)
V ≈ \(2.54 * 10^{-5} m^3.\)
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how many millimoles of bromine is in 0.5 ml of 1 m solution in ch2cl2
There are 0.5 millimoles of bromine in 0.5 ml of a 1 m solution in CH2Cl2.
To find out how many millimoles of bromine are in 0.5 ml of a 1 m solution in CH2Cl2, we need to use the formula:
millimoles = moles x 1000
First, we need to find the moles of bromine in the solution. We know that the solution is 1 molar, which means that it contains 1 mole of bromine per liter of solution. Since we only have 0.5 ml of the solution, we need to convert this to liters:
0.5 ml = 0.0005 L
Now we can calculate the number of moles of bromine in the solution:
moles = concentration x volume
moles = 1 mol/L x 0.0005 L
moles = 0.0005 mol
Finally, we can convert this to millimoles using the formula above:
millimoles = moles x 1000
millimoles = 0.0005 mol x 1000
millimoles = 0.5 millimoles
Therefore, there are 0.5 millimoles of bromine in 0.5 ml of a 1 m solution in CH2Cl2.
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what is the difference between a chemical bond formed in a molecule of cl2 and a chemical bond formed in a molecule of hcl?
The difference between a chemical bond formed in a molecule of Cl2 and a chemical bond formed in a molecule of HCl is that the bond formed in Cl2 is:
A covalent bond, which involves the sharing of electrons between the two chlorine atoms, while the bond formed in HCl is an ionic bond, which involves the transfer of electrons from the hydrogen atom to the chlorine atom.In a covalent bond, the electrons are shared equally between the two atoms, while in an ionic bond, the electrons are transferred completely from one atom to the other.
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what do you think will happen when you put corn starch and water
The corn starch and water will stay separated and eventually sit in the glass as layers. This is due to the 2 fluids having different densities far enough from one another that the fluids do not mix.
Answer:
Cornstarch and water mixed acts both like a solid and a liquid.
Explanation:
Cornstarch and water is a suspension mixture with a solid dispersed into a liquid. When you press the mixture quickly, the starch molecules close together. This causes the water to get trapped between the starch chains and create a semi-rigid structure.
Which statement describes one characteristic of an operating electrolytic cell?
A. It produces electrical energy.
B. It requires an external energy source.
C. It uses radioactive nuclides.
D. It undergoes a spontaneous redox reaction.
Answer:
B
Explanation:
The mechanism of this process: the electrolytic cell converts the electrical energy to chemical energy, using external energy source.
The statement which describes one characteristic of an operating electrolytic cell is it requires an external energy source.
Hence, option (B) is correct answer.
What is Electrolytic Cell ?Electrolytic cell can be defined as an electrochemical device that requires an external source of electrical energy to facilitate a non-spontaneous redox reaction. It converts electrical energy in to chemical potential energy and this process is called electrolysis. In electrolytic cell anode is positive and cathode is negative.
What is Non-spontaneous redox reaction ?A nonspontaneous redox reaction occurs when an external voltage is applied. Electrolytic cell is non spontaneous redox reaction.
Thus, from above conclusion we can say that The statement which describes one characteristic of an operating electrolytic cell is it requires an external energy source.
Hence, option (B) is correct answer.
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