A 25 -turn circular coil of wire has diameter 1.00m. It is placed with its axis along the direction of the Earth's magnetic field of 50.0µT and then in 0.200s is flipped 180⁰. An average emf of what magnitude is generated in the coil?

The block will rise to a maximum height of 0.145 meters above the point of release.

To determine the maximum height, we can use the conservation of mechanical energy. Initially, the block has potential energy stored in the compressed spring, and when released, this potential energy is converted into the block's gravitational potential energy as it rises.

The potential energy stored in the compressed spring is given by the equation:

PE_spring = (1/2) k x^2

where k is the spring constant and x is the compression of the spring. Substituting the given values, we have:

PE_spring = (1/2) × 4925 N/m × (0.099 m)^2 = 24.37 J

The maximum height reached by the block is equal to the potential energy it gains. Considering the block's mass m and acceleration due to gravity g, we have:

PE_gravity = mgh

where h is the maximum height. Equating the potential energies, we have:

PE_spring = PE_gravity

24.37 J = 0.257 kg × 9.8 m/s^2 × h

h = 0.145 m

Therefore, the block rises to a maximum height of 0.145 meters above the point of release.

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A ideal spring has an equilibrium length.  If a spring is compressed, then a force with magnitude proportional to the decrease in length from the equilibrium length is pushing each end away from the other.  If a spring is stretched, then a force with magnitude proportional to the increase in length from the equilibrium length is pulling each end towards the other.

Using Hooke's Law,

F = -kx.

The proportional constant k is called the spring constant.  It is a measure of the spring's stiffness.

Given,

mass = 100 g = 0.1 kg

To find the weight,

We will multiply mass with gravitational acceleration

= 0.1 * 9.8

= 0.98

This is also the value of Force

Force = 0.98 N

With the help of the chart, the extension is found to be 170 mm.

Therefore, the extension of the spring with mass 100 g is 170 mm.

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According to the principle of continuity, the velocity of a fluid multiplied by the cross-section through which it flows at one point will equal the product of velocity and cross-section at another point.

The principle of continuity, also known as the continuity equation, is the fluid mechanic's principle. Simply put, what flows into a defined volume over a specified period of time minus what flows out of that volume over that specified period of time must accumulate in that volume. The substance in that volume is depleted if the accumulation's sign is negative.

This is so that our eyes, once they start to follow anything, will keep moving in that direction until they come across another thing or object. A line with an arrow at the end of it, for instance, is a great illustration of the continuity concept.

Note that three conditions must be met for a function to be continuous at a point: At that time, the limit must exist.

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Answer: 472.556m⋅s−1

Explanation: λ=7.83cm=7.83⋅(1cm)=7.83⋅(1cm×0.01m1cm)=0.0783m

It would take approximately 2.4688 × 10^17 seconds or 7.82 million years for gas to travel from the core of the galaxy to the end of the jet, assuming a constant speed of 5000 km/s.

To calculate the time it would take for gas to travel from the core of the galaxy to the end of the jet, we need to use the formula: time = distance / speed.

Given that the jet in NGC 5128 is traveling at 5000 km/s and is 40 kpc (kiloparsecs) long, we first need to convert the distance from kpc to km. 1 kpc = 3.086 × 10^16 meters, which means 1 kpc = 3.086 × 10^19 km.

Therefore, the length of the jet in kilometers is 40 x 3.086 × 10^19 km = 1.2344 × 10^21 km.

Now we can calculate the time it would take for gas to travel from the core of the galaxy to the end of the jet as follows:

time = distance / speed
time = 1.2344 × 10^21 km / 5000 km/s
time = 2.4688 × 10^17 seconds

So, it would take approximately 2.4688 × 10^17 seconds or 7.82 million years for gas to travel from the core of the galaxy to the end of the jet, assuming a constant speed of 5000 km/s.

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The correct answer is The two forces are equal.

This is because the tension force exerted by the string on the 250 N block is equal to the tension force exerted by the string on the 350 N block. This is due to Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction. In this case, the action is the tension force exerted by the string on the 250 N block, and the reaction is the tension force exerted by the string on the 350 N block.

Therefore, the tension force on both blocks is equal, regardless of the difference in their weights. This is also true in the absence of friction, as there are no external forces acting on the system that would cause the tension forces to be different.

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When a brick (brickA) is resting on a rough incline, the friction force acting on the brick along the incline depends on a few factors. First, let's discuss the forces acting on the brick (brickA). The weight of the brick acts vertically downward due to gravity, and this force can be represented as the weight vector. We can decompose the weight vector into two components: one parallel to the incline (weight_parallel) and one perpendicular to the incline (weight_perpendicular).

The friction force acting on the brick (brickA) along the incline is opposing the component of the weight vector parallel to the incline (weight_parallel). The force of friction is determined by the product of the normal force (which in this case is equal to weight_perpendicular) and the coefficient of friction between the brick and the incline (brickC).
Now, let's analyze the given options:
A. Equal to the weight of the brick - This is incorrect, as the friction force is only equal to the weight_parallel component, not the entire weight of the brick.
B. Less than the weight of the brick - This is correct. The friction force acting on the brick along the incline is opposing the weight parallel component, which is always less than the total weight of the brick.
C. Greater than the weight of the brick - This is incorrect, as the friction force is only acting against the weight parallel component and cannot be greater than the total weight of the brick.
D. Zero - This is incorrect. Since the brick is on a rough incline, there will be a friction force acting against the weight parallel component.
So, the correct answer is B. The friction force acting on the brick along the incline is less than the weight of the brick.

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The three main approaches to the identification of unknown bacteria are as follows:Phenotypic identification, Molecular identification and Biochemical identification

1. Phenotypic identification

Phenotypic identification involves the physical and chemical characteristics of the bacterial colonies and cells. In this method, bacterial cells are studied through microscopy, their ability to grow on various types of media, cellular morphology, and other factors that are easy to observe.

2. Biochemical identification

Biochemical identification is based on the biochemical reactions of bacteria. This method involves the use of different chemical and biochemical tests to identify the bacteria. The tests are designed to identify specific enzymes or metabolic pathways. The results of the tests are then used to identify the bacteria.

3. Molecular identification

Molecular identification involves the use of DNA analysis to identify bacteria. In this method, the DNA of the bacterial cells is isolated and analyzed. This method has become popular in recent years due to its accuracy and speed.

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Answer:b

Explanation:

im in fifth grade so i guessd. gl tho heh.

The answer will be an option C. The momentum would be eliminated for the running back.

The collision in which the object bounces off after the collision is called the elastic collision. The one condition is given in the question that after the collision the running back bounces back and the linebacker stops

A linebacker runs at 3 m/s and collides with a running back running toward him at 3.2m/s. If the running back bounces back and the linebacker stops it means that the collision is elastic. And all the momentum is transferred to the other person.

Therefore the answer will be an option C. The momentum would be eliminated for the running back.

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Answer:

Copper Cu

Lead Pb

Phosphorus P

Arsenic As

Barium Ba

Answer:

fretillization

because when the sperm meets the egg it fertilize the egg.

Answer:

The 1930 FIFA World Cup was the inaugural FIFA World Cup, the world championship for men's national association football teams. It took place in Uruguay from 13 to 30 July 1930.

Explanation:

hope it helps if so pls give it the brainliest answer

Answer:

\(\huge\boxed{Uruguay\hookleftarrow}\)

⎇ The first FIFA World Cup Championship took place in Uruguay from from 13 July 1930 to 30 July 1930.

Answer:

50.63 ft/s (2dp)

Explanation:

Speed = Distance/Time

80/1.58 = 50.63291139

= 50.63 ft/s (2dp)

Both the assertion and the reason given are true.If the mass of the object is less, the acceleration produced by the force will be more. Hence, the acceleration produced by the force is directly proportional to the magnitude of the force and inversely proportional to the mass of the object.

The given assertion: When astronauts throw something in space, that object would continue moving in the same direction and with the same speed; and the given reason: The acceleration of an object produced by a net applied force is directly related to the magnitude of the force, and inversely related to the mass of the object are both correct.Astronauts are capable of throwing objects in space because they are beyond Earth's gravity and do not have to deal with any significant air resistance. In the absence of other forces like friction or air resistance, the initial velocity will be conserved, and the object will continue to move with the same speed and direction. The object would continue to move in a straight line with the same speed because no external force acts on it to change the object's state of motion.Newton's second law states that the force of an object is directly proportional to its acceleration, but inversely proportional to its mass. F=ma, where F is force, m is mass, and a is acceleration. Therefore, if the mass of the object is less, the acceleration produced by the force will be more. Hence, the acceleration produced by the force is directly proportional to the magnitude of the force and inversely proportional to the mass of the object.

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Answer:

Third option

Explanation:

IF you ignore air resistance, they will fall at the same rate due to the effect of gravity being the same on both ....BUT the third option seems to be correct as air friction is taken into account....   the bowling ball will be affected by air resistance too, bul less so..

The car’s acceleration in g’s is equal to 0.67 m/s² and the centripetal force acting on is equal to 4033.47 Newton.

Since the car’s acceleration is given as 6.61 m/s², we would simply divide it by the acceleration due to gravity (9.8 m/s²) to calculate the car’s acceleration in g’s as follows:

Acceleration, g = 6.61/9.8

Acceleration, g = 0.67 m/s².

Mathematically, the centripetal force acting on this car can be calculated by using this formula:

Fc = mv²/r

Fc = (610 × 54²)/441

Fc = 1778760/441

Fc = 4033.47 Newton.

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The time period for the given question would be 1/40 seconds.

Determining time period:

The frequency is 40 Hz. To find the period, t, we can use the formula: T = 1/f where T is the period and f is the frequency. Therefore, T = 1/40 seconds. An explanation is given below with the terms such as period, harmonic oscillations, amplitude, and wave.

What is the time period?

A time period is defined as the time that a wave takes to complete one full cycle of harmonic oscillations. It is the reciprocal of the frequency. The time period is a measure of time taken by a wave to complete one cycle of its motion. The amplitude of a wave is the maximum displacement of the wave from its equilibrium position. It is a measure of the strength of the wave.

What is a wave?

The wave is a disturbance that transfers energy through a medium. Waves are characterized by their frequency, wavelength, and amplitude. Harmonic oscillations are the regular and repeated motion of a system about its equilibrium position. They are periodic motions in which the system moves back and forth with a fixed frequency and amplitude.

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The net force acting on the crate is determined as 176 N to the left.

The net force acting on the crate is calculated as follows;

∑F = F1 + F2 + F3 + F4

F(net) = -440y + 176x + 440y - 352x

F(net) = -176 x

The resultant force is pointing in negative x direction.

Thus, the net force acting on the crate is determined as 176 N to the left.

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Answer:

Explanation:

Given:  

c₁ = 2100 J / (kg·°C)

c₂ = 4200 J / (kg·°C)

λ₁ = 3.4·10⁵ J / kg -

t₁ = -24.2°C

t₀ = 0°C

t₂ = 78.3°C

t = 40.0°C

m₂ = 0.350 kg

___________

m₁ - ?

Ice is heated to 0°C:

Q₁ = c₁·m₁·(t₀ - t₁) = 2100·m₁·(0 - (-24.2)) = 50 820·m₁  J

The ice is melting:

Q₂ = λ·m₁ = 340 000·m₁  J

Cold water is heated:

Q₃ = c₂·m₁·(t - t₀)  = 4200·(40.0 - 0)·m₁ = 168 000 J

Hot water is cooling down:

Q₄ = c₂·m₂·(t₂ - t) = 4200·0,350·(78.3 - 40.0) = 56 300 J

Thermal badance equation:

Q₁ + Q₂ + Q₃ = Q₄

m₁·(50820 + 340 000 + 168 000) = 56 300

m₁·(3 620 000) = 56 300

Mass of ice:

m₁ = 56 300 / 3 620 000 ≈  0,016 kg  or  16 g

Answer:

Here you go..

hope it helps..!

Explanation:

So since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force, so as the mass of either object increases, the force of gravitational attraction between them also increases.

Each occupant must have ready access to overcurrent protective devices protecting the conductors supplying that occupancy unless otherwise permitted in 240.24(B)(1) and (B)(2).

In electrical installations, overcurrent protective devices such as circuit breakers or fuses are used to protect conductors from excessive current. According to the National Electrical Code (NEC) in the United States, Section 240.24 addresses the accessibility requirements for these protective devices.

NEC 240.24(B)(1) states that overcurrent devices shall be readily accessible to occupants. This means that occupants should have easy access to the location where the overcurrent protective devices are installed.

NEC 240.24(B)(2) provides exceptions to the general accessibility requirement. It allows for specific cases where the overcurrent protective devices may be located in other areas, as long as certain conditions are met. These conditions include the use of remote-controlled devices, locked electrical equipment rooms, or the use of dedicated electrical equipment accessible only to qualified personnel.

According to the National Electrical Code (NEC) 240.24, each occupant must have ready access to overcurrent protective devices protecting the conductors supplying that occupancy, unless exceptions outlined in 240.24(B)(1) and (B)(2) are met. This ensures the safety and convenience of occupants by allowing them to easily reach and operate these protective devices when needed.

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Answer:

Peach and Apple will take the same time as the gravitional pull acting on both of them is equal.

height of peach=initial velocity*time+1/2*gravitional pull*(time^2)

1.8=0*time+1/2*9.8*time^2

1.8=0+1/2*9.8*time^2

1.8=1/2*9.8*time^2

3.6/9.8=time^2

taaking value of gravitional pull approx to 10

3.6/10=time^2

0.36=time^2

0.6=time

therefore, the time taken is 0.6sec

Explanation:

The time it takes the peach to reach the ground is 0.61 sec

From the question,

We are to determine how long it would take the peach to reach the ground.

From one of the equations of kinematics for free falling objects,

We have that

\(H = ut + \frac{1}{2}gt^{2}\)

Where

H is the height

u is the initial velocity,

t is the time

and g is the acceleration due to gravity ( g = 9.8 m/s²)

Since the object is dropped with no velocity, then the initial velocity is 0 m/s

From the given information

H = 1.8 m

u = 0 m/s

Putting the parameters into the formula,

We get

\(1.8 = 0(t) + \frac{1}{2}(9.8)t^{2}\)

This becomes

\(1.8 = 0 + 4.9t^{2}\)

\(1.8 = 4.9t^{2}\)

Then,

\(t^{2} = \frac{1.8}{4.9}\)

\(t^{2} = 0.367347\)

∴ \(t =\sqrt{0.367347}\)

t = 0.60609 sec

t ≅ 0.61 sec

Hence, the time it takes the peach to reach the ground is 0.61 sec

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A possible value for the force of static friction when  Jamie applied 75.1 Newtons of force on the box is 75.1N. Option B is correct.

For the box sitting on a horizontal surface, the formula for calculating the force on the box along the horizontal based on Newton's law is expressed as;

Since the forces acting along the horizontal are the frictional force and moving force, the formula above will become;

Since the body is static, hence \(a_x=0m/s^2\), the equation becomes;

Given the force Jamie apply on the box to be 75.1Newtons, this shows that the moving force is 75.1N. Hence;

Hence a possible value for the force of static friction when  Jamie applied 75.1 Newtons of force on the box is 75.1N

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I'm sorry, but you have not provided the options for the different bins to sort the astronomical measurements into. Please provide the full question with all the necessary information so I can assist you better.
To categorize each astronomical measurement based on the type of telescope used, it's important to understand the two main types of telescopes: refracting telescopes and reflecting telescopes. Refracting telescopes use lenses to bend light while reflecting telescopes use mirrors to reflect light.

1. Refracting Telescope:
- Measurements requiring high contrast, such as observing planets or the Moon
- Measurements of bright objects, where light-gathering power is less important

2. Reflecting Telescope:
- Measurements that require large light-gathering power, such as observing faint galaxies or nebulae
- Measurements needing high resolution, like imaging fine details on distant celestial objects

Remember to consider the specific requirements of each measurement when determining the appropriate telescope type. Refracting telescopes are often used for planetary observations while reflecting telescopes are more suitable for deep-sky objects.

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So, the vehicle's acceleration approximately 6.03 m/s².

Hi ! I will help you to solve a problem about "acceleration in a straight line movement". When an object experiences an acceleration, the object will experience a change in the value of the velocity in a certain time interval. When experiencing a change in speed, of course, objects will move. This movement will be written as "s" (shift or displacement).

The formula that you can use to solve this question is:

\( \boxed{\sf{\bold{(v_t)^2= (v_0)^2 + 2 \times a \times s}}} \)

With the following condition :

We know that :

What was asked ?

Step by step :

\( \sf{(v_t)^2= (v_0)^2 + 2 \times a \times s} \)

\( \sf{(17.36)^2= (0)^2 + 2 \times a \times 24.99} \)

\( \sf{301.37 \approx 49.98 \times a} \)

\( \sf{a \approx \frac{301.37}{49.98}} \)

\( \boxed{\sf{a \approx 6.03 \: m/s^2}} \)

So, the vehicle's acceleration approximately 6.03 m/s².

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The equation F=ma, where F is the net force, m is the mass, and an is the acceleration, can be used. . Rearranging the formula to solve for mass, we get m=F/a. Substituting the given values, we get m=12 N/48 m/s^2 = 0.25 kg. Therefore, the answer is A) 0.25 kg.

To solve this problem, you can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). In this case, the net force (F) is 12 N, and the acceleration (a) is 48 m/s². You are asked to determine the mass (m) of the hockey puck.

Using the equation F = ma, you can rearrange it to find the mass: m = F/a

Plug in the given values: m = 12 N / 48 m/s²

Calculate the mass: m = 0.25 kg

The mass of the hockey puck is 0.25 kg, which corresponds to option A.

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Answer:

20m/s

Explanation:

Given parameters:

Distance of throw = 50m

Time  = 3s

Unknown:

Average speed  = ?

Solution:

Average speed is distance divided by time;

  Average speed  = \(\frac{distance }{time}\)

Insert the parameters and solve;

  Average speed  = \(\frac{50}{3}\)   = 16.66667m/s  = 20m/s

Answer:

\(\huge\boxed{\sf a = 2.5 \ m/s\²}\)

Explanation:

Mass = m = 1000 kg

Force = F = 2500 N

Acceleration = a = ?

F = ma (Newton's second law of motion)

F = ma

Solve for a.

a = F / m

a = 2500 / 1000

\(\rule[225]{225}{2}\)

Answer:

The distance travelled in the next 5 seconds is 20 m.

Explanation:

The distance travelled is given by the formula,

\(s=ut+\frac{1}{2} at^{2}\)

Where,

u is the initial velocity in m/s

t is the time in s

a is the acceleration in \(m/s^{2}\)

As per the given data,

u= 9 m/s

t= 5 s

a= -2 \(m/s^{2}\) (The negative sign indicates the deceleration)

Substituting the values,

\(s=(9) * (5) +\frac{1}{2} (-2) (5)^{2}\)

=45-25

=20

So, a runner travels 20 m in the next 5 seconds.

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\( \huge \underline \mathtt \colorbox{cyan}{E=mc squared}\)

(E=mc^2)

m is mass

And c is a constant for speed of light

Answer:

One of the most famous and well-known equations in all of human history, E = mc^2, translates to "energy is equal to mass times the speed of light squared." In other words, wrote PBS Nova, energy (E) and mass (m) are interchangeable. They are, in fact, just different forms of the same thing.

Explanation:

this is right answer