Answer: 46 meters
Explanation:
The maximum height reached by the base ball is 45.9 meters.
To find the maximum height the given values are,
Mass = 25 Kg
speed v = 30 meters per second.
What is the height of baseball reached?As the ball goes up, it acts due to the gravity.
The gravity slows an upward-moving object,
Acceleration due to gravity = 9.8 m/s every second,
the baseball reaches its greatest height in (30/9.8) = 3.06 seconds.
At that instant, its speed is zero.
The baseball's average speed from toss to peak is
(1/2) (30 + 0) = 15 m/s .
The baseball average speed = 15 m/s
And the time for greatest height = 3.06 seconds.
Substituting the given values,
The ball rises can be calculated as
(15 x 3.06) = 45.9 meters.
Thus, the baseball reached the maximum height approximately is 45.9 meters.
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A hungry rabbit sprints... what is the average velocity of the rabbit between the times t = 2 s and t = 12 s
Answer: -0.10m/s
Explanation:
khan academy
in a garage, a mechanic has a hydraulic Jack that allows him to lift heavy objects. If a vehicle of 1500kg is placed on a surface area of 10m squared, calculate the force the mechanic will have to apply to the surface area of 0.05m squared
The mechanic will have to apply a force of 73.575 N to lift the vehicle using the hydraulic Jack.
What is the force applied by the mechanic?To calculate the force the mechanic will have to apply, we first need to determine the pressure exerted by the weight of the vehicle on the surface area.
Pressure is defined as force per unit area, so we can use the formula:
Pressure = Force / Area
The weight of the vehicle is 1500kg, which is equivalent to a force of:
Force = mass x gravity
where;
gravity is the acceleration due to gravity, which is approximately 9.81 m/s².Force = 1500 kg x 9.81 m/s²
Force = 14,715 N
The pressure exerted by the weight of the vehicle on the surface area of 10m² is:
Pressure = Force / Area
Pressure = 14,715 N / 10 m²
Pressure = 1471.5 Pa
Now we can calculate the force the mechanic will have to apply to the surface area of 0.05m² using the same formula:
Pressure = Force / Area
We know the pressure and the area, so we can rearrange the formula to solve for the force:
Force = Pressure x Area
Force = 1471.5 Pa x 0.05 m²
Force = 73.575 N
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Block A, mass 250 g , sits on top of block B, mass 2.0 kg . The coefficients of static and kinetic friction between blocks A and B are 0.34 and 0.23, respectively. Block B sits on a frictionless surface. What is the maximum horizontal force that can be applied to block B, without block A slipping
Answer:
F = 69.3 N
Explanation:
For this exercise we use Newton's second law, remembering that the static friction force increases up to a maximum value given by
fr = μ N
We define a reference system parallel to the floor
block B ( lower)
Y axis
N - W₁-W₂ = 0
N = W₂ + W₂
N = (M + m) g
X axis
F -fr = M a
for block A (upper)
X axis
fr = m a (2)
so that the blocks do not slide, the acceleration in both must be the same.
Let's solve the system by adding the two equations
F = (M + m) a (3)
a =\(\frac{F}{ M+m}\)
the friction force has the formula
fr = μ N
fr = μ (M + m) g
let's calculate
fr = 0.34 (2.0 + 0.250) 9.8
fr = 7.7 N
we substitute in equation 2
fr = m a
a = fr / m
a = 7.7 / 0.250
a = 30.8 m / s²
we substitute in equation 3
F = (2.0 + 0.250) 30.8
F = 69.3 N
A 12 inch-wide conveyor unloads 5000 bushels of wheat per hour. At this speed, how many bushels per hour will an 18-inch-wide conveyor unload?
12-inch wide conveyor unloads 5000 bushels of wheat per hour. At this same speed, the number of bushels that will be unloaded per hour by an 18-inch wide conveyor can be calculated below
\(\begin{gathered} 12\text{ = 5000} \\ 18=\text{?} \\ u\text{nload amount=}\frac{5000\times18}{12}=\frac{90000}{12}=7500\text{ bushels per hour } \end{gathered}\)When heat is added or removed from a substance, it's temperature and thermal energy will be ______.
Directly Proportional
Temperature is directly proportional to heat. The more the heat more the temperature there are a number of scales like degree Celsius, Fahrenheit, and Kalvin (SI Unit) of temperature which is calculated by the mercury.
As on high heat, mercury expands and on its expansion, we measure on a scale which simply means more the heat more the expansion, and more the temperature on the scale, and wise- versa.
And if we talk about thermal energy(Q) is also directly proportional to a change in temperature (negative when temperature decreases and increases on increasing the temperature). where Q = mc*(change in temperature). where m for the mass, and C is the constant for the type of substance we are taking to transfer the heat.
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The Complete Question is -
How Heat is related to temperature and thermal energy?
In the circuit shown below, 0.25 A of current flows through a 20-Ω resistor. How much voltage is needed to produce this current?
A. 80 V
B. 0.013 V
C. 19.75 V
D. 5 V
Answer:
5 V
Explanation:
V = IR
V = .25A * 20 Ohms = 5 V
can some please help me
7 risk factors for heart attack
7 risk factors for stroke
Answer:
high blood pressure, high low-density lipoprotein (LDL) cholesterol, diabetes, smoking and secondhand smoke exposure, obesity, unhealthy diet, and physical inactivity.
Explanation:
question is shown is in the pictures.
please solve for 100pt
The type of dispersion in the Debye model is linear.
When it is at the longer wavelength limit, the density of states is referred to as quadratic.
D(ω) = [3ω²/2π²c³] s rad⁻¹m⁻³
This has a maximum frequency ωD, known as the Debye frequency. In the three dimensions, there are 3 degrees of freedom per atom.
So, the number of phonon modes present here is 3n.
3n = (0→ωD)∫D(ω)dω
Where n is known as the atomic density of the phonon.
We know that, for a frequency that is above the Debye frequency there will be no phonon modes present.
The Debye frequency,
ω³D = 6π²nc³
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As a result of friction, the angular speed of a wheel c hanges with time according to d θ d t = ω0 e −σ t , where ω0 and σ are constants. The angular speed changes from an initial angular speed of 2.88 rad/s to 1.38 rad/s in 3.92 s. (a) Determine the magnitude of the angular acceleration after 1.88 s. Answer in units of rad/s 2 . (b) How many revolutions does the wheel make after 2.6 s ? Answer in units of rev. (c) Find the number of revolutions it makes before coming to rest.
poste en français s’il vous plaît
How much impulse is imparted on a 0.14 kg baseball initially traveling at 32 m/s when it is struck by a baseball bat and begins to travel in the opposite direction at 49 m/s
ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:
Impulse = Change in momentum
The momentum of an object is given by the product of its mass and velocity:
Momentum = mass × velocity
In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.
Therefore, the change in momentum is given by:
Change in momentum = (mass × final velocity) - (mass × initial velocity)
Change in momentum = mass × (final velocity - initial velocity)
Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))
Change in momentum = 0.14 kg × (49 m/s + 32 m/s)
Change in momentum = 0.14 kg × 81 m/s
Change in momentum = 11.34 kg·m/s
So, the impulse imparted on the baseball is 11.34 kg·m/s.
you are flying a plane at a rate of 8m/s north. the wind is blowing 6m/s south. What is your resultant
Your resultant velocity will be along the + y - direction or north direction and has magnitude of 2 m/s.
What are vector quantities?The quantities that have both magnitude and direction are called vector quantities. Example - velocity, acceleration, force etc.
Given in the question is a plane flying at a rate of 8m/s north and the wind is blowing 6m/s south.
In order to find the resultant, refer to the diagram attached. The north direction is represented by +y axis and south direction is represented by -y axis.
The velocity vector representing you will be [v1] = 8 j
The velocity vector representing the wind will be [v2] = - 6 j
Resultant vector [v] = v1 - v2 [Opposite and unequal vectors]
v = 8 j - 6 j
v = 2 j
Therefore, you resultant velocity will be along the + y - direction or north direction and has magnitude of 2 m/s.
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Barbara's teacher wants her to design an oven that can be powered by a renewable resource. Which of the following energy sources could Barbara use?
A
coal
B
gasoline
C
uranium
D
sunlight
Barbara's teacher wants her to design an oven that can be powered by a renewable resource. Barbara can use D) sunlight to power an oven .
A renewable resource can replenish itself at the rate it is used, a renewable resource of energy can be regenerate itself naturally , while a nonrenewable resource has a limited supply as it can extinct .
Coal , gasoline and uranium generate high energy , hence are used where there is a need of more energy . As far as sunlight is concerned , it can be concentrated and can be used to generate power for small used such as heating an oven or cooker which are called solar oven and solar cooker . Solar ovens trap light particles, called photons, to generate heat.
hence , correct option is
D) sunlight
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Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?
The near point of a human eye is about a distance of 25 cm.
The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.
This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.
The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.
In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.
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Consider a graphical representation (figure) of simple harmonic motion as described mathematically in equation x(t) A cos(ur-d). When the particle is at point, P, on the graph (red dot), what can you say about its position, velocity and acceleration?
a. The position is positive, and the velocity is negative
b. The position is negative, and the velocity is positive
c. The position and velocity are both negative
d. The position and velocity are both positive
e. The acceleration is positive
f. The acceleration is negative
Consider a graphical representation (figure) of simple harmonic motion as described mathematically in equation x(t) A cos (wt+Φ). When the particle is at point, P, on the graph, then:
velocity will be negative.
acceleration 'a' is also negative.
What is acceleration?Anything that causes a change in velocity is referred to as an acceleration. You can only accelerate by changing your speed, direction, or both as velocity is a function of both speed and direction.
Equation of the graph is given by:
x(t) = A cos (wt+Φ)
differentiating with respect to t, we get-
dx/dt = - A sin (wt+Φ) w
or, v = - Aw sin (wt+Φ)
differentiating again with respect to t, we get-
d²x/dt² = -A w² cos (wt+Φ) = a (acceleration)
or, a = -A w² cos (wt+Φ)
Now, at position P,
A (amplitude) is positive.
(distance) x is positive.
velocity will be negative as A is positive, acceleration 'a' is also negative.
correct options are: a, f.
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The complete question is as follows:
What is the primary difference between the states of matter?
(Edge 2028-2020)
color of the substance
mass of the substance
number of atoms in the substance
amount of movement of atoms in the substance
CORRECT CHOICE IS D
Answer:
Solids have a definite shape and volume. Liquids have a definite volume.Gases have no definite volume.
What do we call the distance between the start point and the end point ?
Car P travels due East along a straight highway at a constant speed of 30 m/s. At 9:00
a.m., P passes Exit 17. At precisely the same moment, car Q passes Exit 16, traveling due
West at a constant 26 m/s. Slightly later, car P and car Q pass the same point. Knowing
the exits are exactly 7 km apart, determine how many minutes past 9:00 a.m. the cars pass
each other.
Knowing the exits are exactly 7 km apart, the cars pass each other at 9:29 and 15 seconds a.m.
How to calculate time?The relative velocity of the cars is 30 m/s - 26 m/s = 4 m/s.
The distance between the cars is 7 km = 7000 m.
The time it takes for the cars to pass each other is 7000 m / 4 m/s = 1750 seconds.
1750 seconds is 29 minutes and 15 seconds.
To calculate the time in minutes;
Let:
v_p = the speed of car P (m/s)
v_q = the speed of car Q (m/s)
d = the distance between the cars (m)
t = the time it takes for the cars to pass each other (s)
Given that:
v_p = 30 m/s
v_q = 26 m/s
d = 7000 m
Use the equation for relative velocity to find the velocity of the cars relative to each other:
v_r = v_p - v_q
v_r = 30 m/s - 26 m/s = 4 m/s
Use the equation for distance to find the time it takes for the cars to pass each other:
d = v_r × t
7000 m = 4 m/s × t
t = 7000 m / 4 m/s = 1750 s
Convert 1750 seconds to minutes and seconds:
1750 s = 29 minutes and 15 seconds
Therefore, the cars pass each other at 9:29 and 15 seconds a.m.
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plzzzzzzzzzzz help meeeeee
Explanation:
The answer is C thick carpet
PLEASE MARK ME AS BRAINLIEST
Answer:
it is C
Explanation:
At what distance will a 80 W lightbulb have the same apparent brightness as a 120 W bulb viewed from a distance of 40 m
Answer:
32.6mm
Explanation:
Using area of a sphere(bulb) = 4πr²
So A is proportional to radius²
So the Energy will be proportional to r²
But 120/80 = 1.5 is the energy factor so
Using
1.5/d² = 1/r²
1.5/40²= 1/r^2
r = √( 40²/ 1.5)
r = 32.6m
Calculate the spring constant of the spring in a child's pogo stick if the child has a mass of 32 kg and bounces once every 2.7 seconds
Answer:
The spring constant is 173.12 N/m.
Explanation:
mass, m = 32 kg
Period, T = 2.7 s
let the spring constant is K.
Use the formula of period,
\(T = 2\pi\times \sqrt \frac{m}{K}\\\\2.7 =2\times 3.14\sqrt\frac{32}{K}\\\\K = 173.12 N/m\)
Light travelling in air striked a flat piece of uniformly thick glass at an incident of 60. If the index refraction of the glass is 1.50 what is the angle of refraction in the glass
Answer:
30.81°
Explanation:
Angle of refraction= sin⁻¹ 0.5122 = 30.81°.
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If an object has a mass of 47 kg and it is moved 27 meters in 60 seconds, how much power was used?
Answer: 207 W
Explanation: I assumed here that the object is moved vertically. If that is the case, the work done on the object is equal to its change in gravitational potential energy:
where
m = 47 kg is the mass of the object
g = 9.8 m/s^2 is the acceleration of gravity
is the change in height
Substituting,
Now we can calculate the power used, which is given by
Hope this helps I'm sorry if i'm wrong but I tried :(
A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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An electron is accelerated through 2400 V from rest and then enters a region in which there is a uniform 1.70 T magnetic field. What are (a) the maximum and (b) the minimum magnitudes for the magnetic force this charge can experience
Answer:
Explanation:
Let v be the velocity acquired by electron in electric field
V q = 1/2 m v²
V is potential difference applied on charge q , m is mass of charge , v is velocity acquired
2400 x 1.6 x 10⁻¹⁹ = .5 x 9.1 x 10⁻³¹ x v²
v² = 844 x 10¹²
v = 29.05 x 10⁶ m /s
Maximum force will be exerted on moving electron when it moves perpendicular to magnetic field .
Maximum force = Bqv , where B is magnetic field , q is charge on electron and v is velocity of electron
= 1.7 x 1.6 x 10⁻¹⁹ x 29.05 x 10⁶
= 79.02 x 10⁻¹³ N .
Minimum force will be zero when electron moves along the direction of magnetic field .
(a) The maximum force on the electron due to the magnetic field will be F= 79.02 x 10⁻¹³ N .
(b) Minimum force will be zero when electron moves along the direction of magnetic field .
What is magnetic force?Whenever a current is passes through a wire then the magnetic fields are generated around the wire and if any other charged particle comes under the influence of this magnetic field then the magnetic force is applied in the charge.
Let v be the velocity acquired by an electron in electric field
\(Vq=\dfrac{1}{2}mv^2\)
V is potential difference applied on charge q ,
m is mass of charge ,
v is velocity acquired
2400 x 1.6 x 10⁻¹⁹ = .5 x 9.1 x 10⁻³¹ x v²
v² = 844 x 10¹²
v = 29.05 x 10⁶ m /s
Maximum force will be exerted on the moving electron when it moves perpendicular to the magnetic field .
Maximum force = Bqv , where B is magnetic field , q is charge on an electron and v is velocity of electron
F=Bqv
F= 1.7 x 1.6 x 10⁻¹⁹ x 29.05 x 10⁶
F= 79.02 x 10⁻¹³ N .
Minimum force will be zero when electron moves along the direction of magnetic field .
Hence the maximum force on the electron due to the magnetic field will be F= 79.02 x 10⁻¹³ N and the Minimum force will be zero when electron moves along the direction of magnetic field .
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Using atleast 4 sentences. Please share three facts you have learned this year in Physical Education and how you will adapt what you have learned to your everyday life.
Three facts I have learned this year in Physical Education are:
a) The importance of stretching before and after exercising.
b) The benefits of cardiovascular exercise.
c) The importance of staying hydrated during exercise.
Firstly, I have learned the importance of stretching before and after exercising. Stretching helps prevent injury and improves flexibility. I will make sure to incorporate stretching into my daily routine, whether it's through a short stretching session in the morning or by taking a few minutes to stretch before and after a workout.
Secondly, I have learned the benefits of cardiovascular exercise. Cardiovascular exercise, such as running or cycling, helps improve heart health and endurance. I will try to incorporate more cardiovascular exercise into my daily routine, such as going for a run or bike ride after work.
Lastly, I have learned the importance of staying hydrated during exercise. Dehydration can lead to fatigue and muscle cramps, so it's important to drink plenty of water before, during, and after exercise. I will make sure to carry a water bottle with me throughout the day and refill it regularly to ensure that I am staying hydrated.
In summary, by incorporating stretching, cardiovascular exercise, and staying hydrated into my daily routine, I hope to improve my overall physical health and well-being.
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A hypothesis that is non-falsifiable is ___________. A. true B. scientific C. fasle D. not scientific
your question:
A hypothesis that is non-falsifiable is ___________. A. true B. scientific C. fasle D. not scientific
answer:
non-falsifiable means it is almost impossible to say it is false because there is not enough evidence but there also isn't enough evidence to say it is completely true.
A. True , would be your answer.
A hypothesis that is non-falsifiable is not scientific . The correct option is: D. In the realm of science, hypotheses are subjected to empirical testing to determine their validity.
A hypothesis is considered non-falsifiable when it cannot be proven wrong through experimentation or evidence. This goes against the fundamental principles of the scientific method, which relies on falsifiability as a means of distinguishing between valid scientific hypotheses and mere unfalsifiable claims. For a hypothesis to be scientifically meaningful, it must be open to the possibility of being disproven or shown to be incorrect based on observable data and evidence. Non-falsifiable hypotheses lack this crucial criterion and are therefore not considered scientifically rigorous. Hence option D is correct.
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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A computer monitor accelerates electrons between two plates and sends them at high speed to form an image on the screen. If the elec- trons gain 4.1 * 10-15 J of kinetic energy as they go from one accelerat- ing plate to the other, what is the voltage between the plates?
The voltage between the plates is 3.9 × \(10^-^3\) V.
The work-energy theorem states that the delta in the equation equals the change in kinetic energy plus the change in potential energy. Here, a charge's potential energy is expressed as qV, where V is the position's electric potential. The greater the change in voltage per unit distance, the greater the electric field.
The kinetic energy of the electrons = 4.1 × \(10^-^1^5\) J
Charge of the electron = 1.602 × \(10^-^1^9\) coulomb
Using,
ΔU = q × ΔV
4.1 × \(10^-^1^5\) = 1.602 × \(10^-^1^9\) × ΔV
ΔV = 3.9 × \(10^-^3\) V
Therefore, the voltage between the plates is 3.9 × \(10^-^3\) V.
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What is true of the bottom layer of the ocean
Answer:
well i tough it was infinte but its not an the layer is a d i c k
Explanation:
A school bus is moving 26.8 m/s on
flat ground when it begins to
accelerate at 4.73 m/s². How much
time does it take to travel 95.1 m?
(Unit=s)
Watch your minus signs!
time (s)
Enter
The time taken for the bus to travel 95.1 m is 2.8 s
How to determine the final velocityInitial velocity (u) = 26.8 m/sAcceleration (a) = 4.73 m/s²distance (s) = 95.1 mFinal velocity (v) = ?v² = u² + 2as
v² = 26.8² + (2 × 4.73 × 95.1)
v² = 1617.886
Take the square root of both sides
v² = √1617.886
v = 40.2 m/s
How to determine the timeInitial velocity (u) = 26.8 m/sAcceleration (a) = 4.73 m/s²Final velocity (v) = 40.2 m/sTime (t) = ?
v = u + at
40.2 = 26.8 + (4.73 × t)
Collect like terms
4.73 × t = 40.2 - 26.8
4.73 × t = 13.4
Divide both side by 4.73
t = 13.4 / 4.73
t = 2.8 s
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