The final velocity of the smaller object after the collision is 1.725 meters per second to the west.
An elastic collision can be described by the principle of linear momentum conservation, whose model for these case is:
Principle of linear momentum conservation
\((2.40\,kg) \cdot \left(4\,\frac{m}{s} \right) = (2.40\,kg)\cdot v + (6\,kg)\cdot \left(2.29\,\frac{m}{s} \right)\)
Where \(v\) is the final velocity of the smaller object, in meters per second.
Then, the final velocity of the object is:
\(v = -1.725\,\frac{m}{s}\)
The final velocity of the smaller object after the collision is 1.725 meters per second to the west.
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On what part of the eye are rods and cones found?
Answer:
retina.
Explanation:
You pass 633 nm laser light through a narrow single slit of width 0.24 mm and observe the diffraction pattern on a screen 6.0 m away. If the intensity at the central bright is Io , what is the intensity at a point on the screen 3.0 mm from the center of the pattern?
Answer:
The intensity is \( I = 0.0175I_o \)
Explanation:
From the question we are told that
The wavelength is \(\lambda = 633 \ nm = 633*10^{-9} \ m\)
The width of the slit is \(d = 0.24 \ mm = 0.00024 \ m\)
The distance from the screen is \(D = 6.0 \ m\)
The distance of the position considered from the center is \(y = 3.0 \ mm = 0.003 \ m\)
Generally the intensity from at a point on the screen 3.0 mm from the center of the pattern is
\(I = I_o * \frac{sin^2 [\frac{\pi d * y}{ \lambda D } ]}{[\frac{\pi d * y }{\lambda D} ]^2}\)
Here \(I_o\) is the intensity of the central bright fringe
=> \( I = I_o * \frac{sin^2 [\frac{3.142 * 0.00024 * 0.003}{ 633*10^{-9} * 6 } ]}{[\frac{3.142*0.00024 * 0.003 }{633*10^{-9} * 6} ]^2}\)
=> \( I = 0.0175I_o \)
a current of a 6 flows through a light bulb for 12 s, how many coulombs of charge pass through the light bulb during this time
A current of a 6 flows through a light bulb for 12 s. The total charge that passes through the light bulb during the given time is 72 coulombs.
To calculate the total charge that passes through the light bulb, we need to use the formula Q = I * t, where Q represents the charge in coulombs, I represents the current in amperes, and t represents the time in seconds.
Step 1: Identify the known values:
Current (I) = 6 amperes
Time (t) = 12 seconds
Step 2: Calculate the charge using the formula:
Q = I * t
Step 3: Substitute the known values into the formula:
Q = 6 amperes * 12 seconds
Q = 72 coulombs
Therefore, the total charge that passes through the light bulb during the given time is 72 coulombs.
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The evaporation of water is an example of a change in ______
Answer:
The evaporation of water is an example of a change in Pysical Change .
How much work is required to move a 1 nC charge from an electric potential of 0 V to a potential of 18V?
a) 56 µJ
b) No work is required by an external force because this is the natural movement of the charge.
c) 18 J
d) 56 MJ
e) 18GJ
f) 18 nJ
The work required to move a 1 nC charge from an electric potential of 0 V to a potential of 18 V is 18 nJ (Option f).
When moving a charge in an electric field, the work done can be calculated using the formula W = qΔV, where W is the work done, q is the charge, and ΔV is the change in electric potential.
In this case, the charge is\(0.36V * 1600 kg/m^3 = 0.36 * 0.088 m^3 * 1600 kg/m^3 = 88 kg.\)) and the change in potential is 18 V. Plugging these values into the formula, we get\(W = (1 × 10^-9 C)(18 V) = 18 × 10^-9 J = 18 nJ.\)
Therefore, the correct answer is option f. No other options accurately represent the work required to move the charge in this scenario.
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My 2nd Question Asked:
If the universe is expanding, what is it expanding into?
Answer:
even more space than it already encompassed.
Explanation:
it is expanding into nothingness or it might it expanding in and of itself
Planets A and B have the same size, mass, and direction of travel, but planet
A is traveling through space at half the speed of planet B. Which statement
correctly explains the weight you would experience on each planet?
A. You would weigh the same on both planets because their masses
and the distance to their centers of gravity are the same.
O B. You would weigh the same on both planets because your mass
would adjust depending on the planet's speed.
O C. You would weigh less on planet B because it is traveling twice as
fast as planet A.
D. You would weigh more on planet B because it is traveling twice as
fast as planet A
(a) When an object's acceleration vector points in the same direction as its velocity, which of the following is true?
A. the object speeds up without turning.
B. the object slows down without turning.
C. the object turns without changing speed.
A. When an object's acceleration vector points in the same direction as its velocity, the object speeds up without turning.
What is acceleration vector?
The average acceleration vector is defined as the rate at which the velocity changes with time.
When an object is slowing down, the acceleration of the object is in the opposite direction as the velocity.
Also, when an object is speeding up, the acceleration of the object is in the same direction as the velocity.
Thus, when an object's acceleration vector points in the same direction as its velocity, the object speeds up without turning.
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A spacecraft has a momentum of 20,000 kg-m/s, and a mass of 250 kg. What is the magnitude of its velocity?
A. 80 m/s
B. 800 m/s
C. 400 m/s
D. 40 m/s SUBMIT
Answer:
A. 80 m/sExplanation:
The velocity of the spacecraft can be found by using the formula
\(v = \frac{p}{m} \\ \)
p is the momentum
m is the mass
From the question we have
\(v = \frac{20000}{250} = \frac{2000}{25} \\ \)
We have the final answer as
80 m/sHope this helps you
please i dont understand
A star has the solar mass of 14. Eventually, that star is going to explode. After the
explosion there is NOT a lot of mass left over. What is the star called?
White dwarf
Black hole
Neutron Core
Red Giant
The exploded star is called a black hole.
The time horizon of the black hole is an area of spacetime where gravitational pull is so intense that nothing, not even light or other electromagnetic waves, have the energy to pass through it.
It is believed that the first black holes appeared shortly after the big bang, in the beginning of the cosmos. When the core of an extremely massive star is collapsed on itself, stellar black holes are created.
A supernova, also known as an exploding star, is also brought on by this collapse and sends a portion of the star into space.
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The low pressure area near Earth's equator is filled by cool air moving in from
А
Europe and South America
B
the North and South Pole
с
the Prime Meridian
D
the Atlantic and Pacific Ocean
The best leaper in the animal kingdom is the puma, which can jump to a height of 3.7 m when leaving the ground at an angle of 45°. With what speed must the animal leave the ground to reach that height?_____ m/s
Given:
The puma jumps to the height of: h = 3.7 m
The angle made by puma with the ground is: θ = 45°
To find:
The speed of the puma when it leaves the ground.
Explanation:
We consider only the vertical motion of the puma.
The puma jumps to the height of 3.7 m and its speed at this height will be zero.
Thus, v = 0 m/s.
The initial speed "u" can be calculated by using the following kinematical equation.
\(v^2=u^2+2ah\)Here, a = - g. The negative sign indicates that the puma jumps against the acceleration due to gravity.
Taking g = 9.8 m/s² and substituting the values in the above equation, we get:
\(\begin{gathered} (0\text{ m/s\rparen}^2=u^2+2\times(-9.8\text{ m/s}^2)\times3.7\text{ m} \\ \\ 0=u^2-72.52\text{ m}^2\text{/s}^2 \\ \\ u^2=72.52\text{ m}^2\text{/s}^2 \\ \\ v=\sqrt{72.52\text{ m}^2\text{/s}^2} \\ \\ u=8.51\text{ m/s} \end{gathered}\)Now, the vertical component of the speed of the puma is given as:
\(u=u_0sin\theta\)Here, u0 is the speed with which the puma leaves the ground.
Substituting the values in the above equation, we get:
\(\begin{gathered} 8.51\text{ m/s}=u_0sin45\degree \\ \\ u_0=\frac{8.51\text{ m/s}}{sin45\degree} \\ \\ u_0=\frac{8.51\text{ m/s}}{0.707} \\ \\ u_0=12.03\text{ m/s} \\ \\ u_0\approx12\text{ m/s} \end{gathered}\)Final answer:
The speed of the puma with which it leaves the ground is 12 m/s.
Please don't round any possible answers
Note the rate at which oil is flowing is: 7.19 m³/s . See the computation below.
What is the rationale for the above response?We can use the principle of continuity of flow to solve this problem. According to this principle, the mass flow rate of the oil is:
m_dot = rho * A * v: where:
rho is the density of the oil,
A is the cross-sectional area of the pipe, and
v is the velocity of the oil.
The cross-sectional area of the pipe before the constriction is:
A1 = (pi/4) * d1² = (pi/4) * (0.978 m)² = 0.7526 m²
The cross-sectional area of the pipe after the constriction is:
A2 = (pi/4) * d2² = (pi/4) * (0.5868 m)² = 0.2701 m²
The velocity of the oil can be calculated using the principle of continuity of flow:
A1 * v1 = A2 * v2
where v1 is the velocity before the constriction and v2 is the velocity after the constriction.
Solving for v1, we get:
v1 = (A2/A1) * v2 = (0.2701 m^2 / 0.7526 m^2) * v2 = 0.3590 * v2
The pressure difference across the constriction is:
deltaP = P1 - P2 = 7600 N/m² - 5700 N/m² = 1900 N/m²
Using Bernoulli's equation, we can relate the pressure difference to the velocity difference:
deltaP = (1/2) * rho * (v2² - v1²)
Substituting the expression for v1, we get:
deltaP = (1/2) * rho * (v2² - 0.1290 * v2²)
Solving for v2, we get:
v2 = sqrt(2 * deltaP / rho * (1 - 0.1290)) = 20.16 m/s
Finally, the mass flow rate of the oil is:
m_dot = rho * A1 * v1 = 821 kg/m³ * 0.7526 m² * 0.3590 * 20.16 m/s
= 5904.4 kg/s
Converting to cubic meters per second, we get:
Q = m_dot / rho = 5904.4 kg/s / 821 kg/m³ = 7.19 m³/s
Therefore, the rate at which oil is flowing is 7.19 m³/s
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Please help
Which statement is true in this situation?
Answer:
b
Explanation:
because the of F frick is the same of the size of F app
An ambulance needs to reach an
accident scene in 10 minutes.
Report a Problem
At what rate of speed must the ambulance travel?
if the accident is 12 kilometres away?
60 km/h
66 km/h
O 72 km/h
O88 km/h
Answer:
72 km/h. that the speed it's need
Answer:
Explanation:
Given:
t = 10 min = (1/6) h
D = 12 km
______________
V - ?
V = D / t = 12 / (1/6) = 12·6 = 72 km/h
A ball is thrown horizontally from the top of a building 100m high. The ball strikes the ground at a point 120 m horizontally away from and below the point of release. What is the magnitude of its velocity just before it strikes the ground?
26.54 m/s is the magnitude of its velocity just before it strikes the ground
h=100m,v=20m/s,g=9.8m/s
time it takes to reach the ground,
\([t=\sqrt2h/g],[=\sqrt2*100/9.8=4.51s]\)
x= 120m
t= 4.52
v= x/t
v= 120/4.52
v= 26.54 m/s
The "speed at which an object changes its location" can be expressed using a vector number called velocity. Consider a person who moves swiftly while taking two steps forward and two steps back while remaining in one location. Velocity is a vector quantity. Therefore, velocity is cognizant of direction. The direction must be taken into account when determining an object's velocity. A speed of 55 mph is not enough information. The direction must be used to appropriately depict the item's velocity. Simply said, the direction of the velocity vector indicates the direction of motion of an object.
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A motorcycle travels 90.0 km/h. How many seconds will it take the motorcycle to cover 2100 km
1 hour = 3600 seconds
Find the number of hours it takes by dividing total distance by speed:
2100 km / 90 km/h = 23 1/3 hours
Multiply total hours by 3600:
231/3 x 3600 = 84,000 seconds
It will take the motorcycle 84 seconds to cover 2100 km at a speed of 90.0 km/h. The correct answer is 84 seconds.
Given:
Speed = 90.0 km/h
Distance = 2100 km
The time it takes for the motorcycle to cover 2100 km at a speed of 90.0 km/h, you can use the formula:
Time = Distance / Speed
Convert the speed to meters per second
1 km = 1000 m
1 hour = 3600 seconds
The speed in meters per second:
Speed = 90.0× (100 / 1 ) × (1 / 3600 )
Speed = 25 m/s
The formula to calculate the time:
Time = Distance / Speed
Time = 2100 / 25
Time = 84 seconds
It will take the motorcycle 84 seconds to cover 2100 km at a speed of 90.0 km/h.
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Does the weight of the projectile affect the horizontal range?
Answer:
no
Explanation:
This downward force and acceleration results in a downward displacement from the position that the object would be if there were no gravity. The force of gravity does not affect the horizontal component of motion; a projectile maintains a constant horizontal velocity since there are no horizontal forces acting upon it.
Which part of the diagram indicates the amplitude of the wave?
The left vertical line part of the diagram indicates the amplitude of the wave.
The amplitude of a wave or vibrating body is defined as the maximum displacement or distance generated by a point on the wave or body compared to its position of equilibrium. It is the same as the length of the vibration path divided by half.
The wave's amplitude is shown by the left vertical line in the figure, which depicts the highest displacement or distance that a spot on a wave or moving body can make compared to its equilibrium position. So the left vertical line part of the diagram indicates the amplitude of the wave.
The figure of the question is attached.
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What body system,
respiratory system
Circulatory system
Digestive system
Nervous system
Affects ulcer disease and heartburn.
Please do this quick it is due please. I will make brainlest and give out extra points
Affects ulcer disease and heartburn.
Please do this quick it is due please. I will make brainlest and give out extra points!
Answer:
Digestive system
Explanation:
ulcer affect anywhere in the digestive system
Digestive system.
Since the acids in your food break down with the chemicals in your stomach, it can give you heartburn and also, ulcer disease happens in your stomach so the only correct answer would be Digestive System. I would like to say that the person with the profile name BigPapa who commented on my answer deserves a lot of credit, and thanks if you see this.
-R3TR0 Z3R0
Pls see attached photo
A rubber band has a spring
constant of 23.6 N/m. How far
must you stretch it to store 1.25 J
of PEe?
(Unit = m)
Enter
Given: Spring constant(k) = 23.6 N/m
Elastic potential energy(P) = 1.25J
To find: Extension(x)
Solution: We know that,
\(P= \frac{1}{2}kx^{2}\)
i.e. \(1.25 = \frac{1}{2}(23.6)x^{2}\)
\(x^{2} =0.1059\)
\(x = \sqrt{0.1059}\)
\(x = 0.3254 m\)
The rubber band should be stretched 0.3254 m apart
Help yea I need help
the efficiency of combine double pulley is 60 how much load is lifted using 50n effort
The amount of load lifted by the pulley when the efficiency is 60% and effort is 50 N is determined as 30 N.
What is the amount of load lifted?The amount of load lifted by the pulley is calculated by applying the formula for efficiency of a machine as follows;
E = L / E x 100%
where;
L is the load overcome or output workE is the effort applied or the input workThe amount of load lifted by the pulley is calculated as;
60 = L / 50 x 100%
60 = 100L / 50
100L = 50 x 60
100 L = 3000
L = 3000 / 100
L = 30 N
Thus, the amount of load lifted by the pulley is 30 N.
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To save energy and money, Jackie Smith replaced the 122 Watt incandescent light bulb in her house with a 18 Watt CFL bulb. The expected life of incandescent and CFL bulbs is 1,000 and 10,000 hours respectively. The purchase price of an incandescent bulb is $0.51 and for the CFL it is $5.88. The cost of electricity is 0.06 $ per kWh. What is her total savings over the lifetime of the CFL
Answer:
Note: 1 watt * 1000 hrs = 1 kWh
1 watts * 10,000 hrs = 10 kWh
Incandescent for 1000 hrs
Original cost = .51
Usage = 122 W * .06 = 7.32
Total cost for 1000 hrs 7.32 + .51 = 7.83
Total cost for 10,000 = 78.3
CFL Bulb for 10,000 hrs
Original cost = 5.88
Usage = 18 * .06 / kWh * 10 kWh = 10.8
Total cost = 5.88 + 10.8 = 16.68
Gives a total savings of 78.3 - 16.68 = 61.62
Another way of looking at this:
Note: the cost of electricity for the incandescent bulb is:
122 W * 1000 hr * .06 / kWh = 122 kWh * 06 = 7.32 for each KWh
That is 73.2 for 10 kWh and 5.1 for bulb cost = 78.3
The CFL bulb uses in 10,000 hrs
18 kWh * 10 * .06 = 10.8 cost of electricity
bulb cost = 5.88 for a total cost of 16.68
If the purchase price of an incandescent bulb is $0.51 and for the CFL it is $5.88. The cost of electricity is 0.06 $ per kWh, then her total savings over the lifetime of the CFL would be 61.62 $.
What is power ?The rate of doing work is known as power. The Si unit of power is the watt.
Power = work/time
As given in the problem to save energy and money, Jackie Smith replaced the 122 Watt incandescent light bulb in her house with an 18 Watt CFL bulb. The expected life of incandescent and CFL bulbs is 1,000 and 10,000 hours respectively. The purchase price of an incandescent bulb is $0.51 and for the CFL it is $5.88. The cost of electricity is 0.06 $ per kWh
The original cost of the incandescent bulb = 0.51
Cost in the electricity usage of incandescent bulb = 122 × 0.06 = 7.32
Total cost for 1000 hrs 7.32 + 0.51 = 7.83
Total cost for 10,000 with the use of the incandescent bulb = 78.3
CFL Bulb Is used for 10,000 hrs
The original cost of the CFL = 5.88
Cost associoated with the Electricity usage of the CFL = 18 * .06 / kWh * 10 kWh = 10.8
Total cost of the CFL = 5.88 + 10.8 = 16.68
78.3 - 16.68 = 61.62
Total savings over the lifetime of CFL would be 61.62 $.
Thus, her total savings over the lifetime of the CFL would be 61.62 $.
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The diagram below shows the velocity vectors for two cars that are moving
relative to each other.
45 m/s west
25 m/s east
Car 1.
Car 2
From the frame of reference of car 2, what is the velocity of car 1?
OA. 70 m/s east
B. 20 m/s west
OC. 70 m/s west
OD. 20 m/s east
SUBMIT
The velocity of the car 1 can be seen from the calculation as 20 m/s West
What is relative motion?
A coordinate system or point of view used to observe motion is known as a frame of reference. It can be used as a guide when describing an object's position, speed, and acceleration. Different frames of reference may result in various motion observations.
The relative velocity is the velocity of an object or observer as observed from a particular frame of reference.
We can see that the velocity of the car 1 is;
45 m/s - 25 m/s
= 20 m/s West
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Nonreflective coatings on camera lenses reduce the loss of light at the surfaces of multilens systems and prevent internal reflections that might mar the image. Find the minimum thickness of a layer of magnesium fluoride (n = 1.38) on flint glass (n = 1.66) that will cause destructive interference of reflected light of wavelength 480 nm near the middle of the visible spectrum.
The minimum thickness of the magnesium fluoride layer that will cause destructive interference of reflected light with a wavelength of 480 nm is 86.9 nm
How do we sole for the minimum thickness that will cause destructive interference ?To find minimum thickness of a non-reflective coating that causes destructive interference we use the formula t = (mλ) / (4n)
The wavelength (λ) of the light is 480 nm
the refractive index (n) of magnesium fluoride is 1.38,
we can calculate the minimum thickness (t) by saying
t = 0 × 480 / 4 × 1.38
t = 0 nm
t = 1 × 480 nm / 4 × 1.38
t = 480 nm / 5.52
t = 86.96 nm
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What type of force is jumping a trampoline?
Answer:
Tension
Explanation:
give pressure loss Darcy weisbach equation
Answer:
Multiply the friction factor by pipe length and divide by pipe diameter. Multiply this product by the square of velocity. Divide the answer by 2.
Explanation:
Multiply the friction factor by pipe length and divide by pipe diameter. Multiply this product with the square of velocity. Divide the answer by 2.
Hope this answer helps you