A 2-meter-long pendulum, is set in motion, at 1.2 m/s, when the pendulum arm is at an angle of 25° from the vertical. Find the speed of the pendulum when it reaches the bottom of its swing.

Yes, if only one external force acts on a particle, it can change the particle's kinetic energy.

The change in kinetic energy depends on the magnitude and direction of the force applied. The main answer is that a single external force can alter the particle's kinetic energy. When a force acts on a particle, it can either increase or decrease its velocity. If the force is applied in the direction of motion, it will increase the particle's kinetic energy. On the other hand, if the force is applied in the opposite direction of motion, it will decrease the particle's kinetic energy.

In summary, the presence of a single external force can indeed lead to a change in the particle's kinetic energy, depending on the direction and magnitude of the force.

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Answer:

the elephant encounters a smaller fourth air resistance than the feather so it would fall faster.

Explanation:

his elephant has a greater acceleration of gravity and the feather and so that makes it fall faster.

Answer: The mechanical advantage of the crowbar  9

Answer:

9

Explanation:

50N-load

450N-effort

m.a=load÷effort

450÷50=9

The value of distance 'd' is 53.2 meters, measured from the wall, to where the block strikes the ground.

weight = 10 kg

g = 9.8m/s²

x = 5

Using the principle of work and energy,

T₁ +∑U₁-₂ = T₂

0 + 1/2kx² -wh = 1/2 w/g V²

Substituting, we have

0 + 1/2 * 100 * 5² - (10 * 3) = 1/2 * (10/9.8)V²

170 = 0.15528V²

V² = 170/0.15528

V²     = 1094.796

V = √1094.796

V = 48.89/s

But tan ∅ = 3/4

∅ = tan⁻¹3/4

  = 36.87°

From uniform acceleration,

S = S₀ + ut + 1/2gt²

It can be written as

S = S₀ + Vsin∅*t + 1/2gt²

Substituting, we have

0 = 3 + 33.09 * sin 36.87 * t -(1/2 * 9.8 *t²)

19.85t - 16.1t² + 3 = 0

16.1t² - 19.85t - 3 = 0

Solving it quadratically, we obtain t = 1.36s

The distance measure from the wall is given by the formula

d = VCos∅*t

Substituting, we have

d = 48.9 * cos 36. 87 * 1.36

d = 53.2 m

So the value of distance is 53.2 meter.

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Complete question:

The 10-kg block is pressed against the spring so as to compress it 5 m when it is at a point A. If the plane is smooth, determine the distance d, measured from the wall, to where the block strikes the ground. Neglect the size of the block.

Answer:

b  The force is perpendicular to the displacement of the object.

Explanation:

Work is done when a force is applied on a body causing it to move in a particular direction.

  Work done  = Force x displacement

For work to be done, a force must applied on a body to move it through a specific distance in direction.

When force is perpendicular to the displacement of the object, the component vector resolution is 0 and the work done is 0.

Answer: i do not know

Explanation: i do not know either

Answer:

It would be balanced

Explanation:

Answer:  2.67 m/s2

Explanation:

W = mg = (22.4 kg)(9.8 m/s2) = 219.52 N

Wx = (219.52 N)(sin 22) = 82.2 N

Wy = (219.52 N) (cos 22) = 203.5 N

Wy = N (normal force on the block) = 203.5 N

Ff (force of friction) = (coeff. friction)(N) = (0.11)(203.5 N) = 22.4 N

Sum the forces in the x-direction (direction of motion down the ramp):

Fnet = Wx - Ff = 82.2 N - 22.4 N = 59.8 N

a = F/m = 59.8 N / 22.4 kg = 2.7 m/s2

ANSWER

Normal force

EXPLANATION

We want to determine what FN would represent on a force diagram.

On a force diagram, FN represents the component of a contact force that acts perpendicular to the surface with which an object makes contact. It is exerted by surfaces and prevents objects from passing through each other.

This force is known as the normal force.

That is the answer.

Answer:

A person or object may have stored energy because of its....

potential energy

A person or object may have stored energy because of its position and the energy is called potential energy.

The relative positions of different system components determine the potential energy, which is stored energy. When a spring is compressed or stretched, its potential energy increases.

If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy. It is capable of performing more work when raised.

Potential energy is a characteristic of systems rather than of particular bodies or particles; for instance, the system made up of Earth and the elevated ball has more potential energy as they become further apart.

In systems having components whose forces on one another rely on their configuration, or relative positions to one another, potential energy is generated.

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a) The weight of the box of textbooks can be calculated as follows;

Weight of

box= mass × acceleration due to gravity

Where mass= 55 kg

Acceleration due to

gravity= 9.8 m/s²Thus, the weight of the box of textbooks is given by;

Weight of

box= 55 kg× 9.8 m/s²= 539 N

the weight of the box of textbooks is 539 N.

b) The coefficient of friction can be calculated using the formula;Coefficient of friction= frictional force/ Normal forceWhere, frictional force is the force required to keep the box moving at constant velocity and normal force is the force acting on the box perpendicular to the surface on which the box is resting.

The force F of the student pushing the box can be resolved into its horizontal and vertical components as follows;

F_x= 320 N (this is the horizontal component of the force)F_y=

(This is the vertical component of the force)Thus, the normal force on the box is given by;

F_y= Normal forceNormal force= weight of box= 539 NThe frictional force is given by.

F_f= F_x= 320 NThe coefficient of friction is given by;Coefficient of friction= frictional force/ Normal forceCoefficient of friction= F_f/ F_yCoefficient of friction= 320 N/ 539 NCoefficient of friction= 0.593Therefore, the coefficient of friction is 0.593.

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Answer:

B They react with all metals producing hydrogen.

Please find attached photograph for your answer. Please do comment whether it is helpful or not.

A thousand kilo meters length of cable is laid between two power stations. If the conductivity of the material of the cable is 5.9 x 10⁷ Q-¹ m-¹ and its diameter is 10 cm, the resistance of the cable is 113.69 Ω.

If the free electron density is 8.45 x 10²⁸ m-³ and the current carried is 10000A, the drift velocity of the electrons is 0.298 m/s.

Their mobility is 262.41 m²/(V s). and the power dissipated in the cable is 113.69 x 10⁶ W.

To calculate the resistance of the cable, we can use the formula:

Resistance (R) = (ρ * L) / A

where ρ is the resistivity of the material, L is the length of the cable, and A is the cross-sectional area of the cable.

Length of the cable (L) = 1000 km = 1000 * 1000 m

Conductivity of the material (σ) = 5.9 x 10⁷ Q⁻¹ m⁻¹

Diameter of the cable (d) = 10 cm = 0.1 m

First, let's calculate the cross-sectional area (A) of the cable:

A = π * (d/2)²

A = π * (0.1/2)²

A = π * (0.05)²

Now, we can calculate the resistance (R) of the cable:

R = (ρ * L) / A

R = (1/σ * L) / A

R = (1 / (5.9x10⁷) * (1000 * 1000)) / (π * (0.05)²)

Calculating this expression, we get:

R ≈ 113.69 Ω.

Next, let's calculate the drift velocity (\(v_d\)) of the electrons in the cable. The drift velocity is given by the formula:

\(v_d\) = I / (n * A * q)

where I is the current carried, n is the free electron density, A is the cross-sectional area, and q is the charge of an electron.

Current carried (I) = 10000 A

Free electron density (n) = 8.45 x 10²⁸ m⁻³

Cross-sectional area (A) = π * (0.05)²

Charge of an electron (q) = 1.6 x 10⁻¹⁹ C

Substituting these values into the formula, we get:

\(v_d\) = 10000 / (8.45 x 10²⁸ * π * (0.05)² * 1.6 x 10⁻¹⁹)

Calculating this expression, we get:

\(v_d\) = 0.298 m/s.

Next, let's calculate the mobility (μ) of the electrons. The mobility is given by the formula:

μ = \(v_d\) / E

where E is the electric field strength.

Since the power dissipated in the cable is not given, we cannot directly calculate the electric field strength. However, if we assume that the power dissipated in the cable is equal to the power input (P), we can use the formula:

P = I² * R

Substituting the given values, we get:

P = 10000² * 113.69

Calculating this expression, we get:

P = 113.69 x 10⁶ W

Now, assuming this power is evenly distributed over the length of the cable, we can calculate the electric field strength (E) using the formula:

P = E * I * L

Substituting the values, we get:

113.69 x 10⁶ = E * 10000 * (1000 * 1000)

Simplifying this expression, we find:

E ≈ 1.137 x 10⁻³ V/m

Finally, we can calculate the mobility (μ):

μ = \(v_d\) / E

μ = 0.298 / (1.137 x 10⁻³)

Calculating this expression, we get:

μ ≈ 262.41 m²/(V s).

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Answer:

22236 mi

Explanation:

Eliminate b by combining b + a and b - a, and solve for a :

(b + a) - (b - a) = (5i - j) - (i - 7j)

2a = 4i + 6j

a = 2i + 3j

Now compute the magnitude and direction.

mag: ||a|| = √(2² + 3²) = √13

dir: tan(θ) = 3/2   ⇒   θ = arctan(3/2) ≈ 56.3°

The exact speed of the combined trucks after a completely inelastic collision is 55 mi/h.

To calculate the speed of the combined trucks, we need to use the conservation of momentum equation, which states that the total momentum before the collision is equal to the total momentum after the collision. Since the trucks have the same mass, the momentum equation simplifies to:

(mass of truck 1 * velocity of truck 1) + (mass of truck 2 * velocity of truck 2) = (total mass of combined trucks * final velocity of combined trucks)

Plugging in the values, we have:

(50 mi/h * mass) + (60 mi/h * mass) = (2 * mass * final velocity)

Simplifying the equation, we find:

110 mi/h * mass = 2 * mass * final velocity

Canceling out the mass, we have:

110 mi/h = 2 * final velocity

Solving for the final velocity, we get:

final velocity = 55 mi/h

In summary, after a completely inelastic collision between two trucks with the same masses and initial speeds of 50 mi/h and 60 mi/h, the combined trucks will have a resulting speed of 55 mi/h.

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Answer:

friction

the rubbing of the surfaces create friction, giving off heat

Answer:

heat is produced by rubbing our hands  together which cause friction and during the process you can feel heat.

To explain the tangent plane to the surface, `z = 53 − x² − 2y²` at the point `(3, 2, 6)`, let us first determine the partial derivatives of `z` with respect to `x` and `y`.

Partial derivative of `z` with respect to `x`, `∂z/∂x = -2x`Partial derivative of `z` with respect to `y`, `∂z/∂y = -4y`Now, let's find the gradient vector `grad z` at `(3, 2, 6)` and the value of `z` at `(3, 2)`.gradient vector `grad z = (-2x, -4y, 1)`gradient vector `grad z = (-6, -8, 1)` at `(3, 2, 6)`.Value of `z` at `(3, 2)` is given by `z = 53 - 3² - 2(2)² = 39`.

Therefore, the equation of the tangent plane to the surface `

z = 53 − x² − 2y²` at `(3, 2, 6)` is:

`z - 6 = -6(x - 3) - 8(y - 2)`

which can be written as:`6x + 8y + z = 50`Thus, the equation of the tangent plane to the surface `z = 53 − x² − 2y²` at the point `(3, 2, 6)` is `6x + 8y + z = 50`.

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The answer is b. Newton's 2nd Law of Motion. They provide a framework for understanding the behavior of physical objects,  and are essential for many areas of science and engineering.

This law states that the force acting on an object is directly proportional to its mass and acceleration, and can be mathematically expressed as F = m*a (force equals mass times acceleration). This means that the more massive an object is, the greater force is required to move it. Newton's 2nd Law of motion is a fundamental principle in physics, and is used to understand how objects move and interact with each other. By applying this law, we can predict how much force is needed to accelerate an object, or how much force is exerted on an object when it collides with another object.

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Answer:

personality disorder

Explanation:

Certain family dynamics, such as abusive parenting, can increase the susceptibility of someone developing a(n) personality disorder.

A disorder is diagnosed when these personality traits are significantly “deviated” from others and are very inflexible, impairing a person's adaptation to everyday situations and causing distress and discomfort in their personal relationships and other areas of life.

Personality disorders are generally pervasive and persistent patterns of thinking, perceiving, reacting, and relating that cause significant distress or functional impairment.

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Answer:

Objects S and T

Explanation:

Gravitational Force F is directly proportional to the product of the masses and inversely proportional to the square of the distances between them

F ∝ m₁ m₂/r²

where  m₁ m₂ are the masses of the two objects

r = distance between them

This means the larger the masses the greater the force

The more the distance, the less the force

Looking at the table we see that the greatest mass is 2 kg for each object so m₁ = m₂ = m and m₁ \cdot m₂= m²
There are 2 distances for this mass 1 and 2. Choose the lower distance ie r = 1 m

Therefore this combination of masses and distance yields the greatest attraction
Greatest Force is between Objects S and T

OR

we can rewrite the proportionality relationship as an equation

\(F = k\cdot \dfrac{m^2}{r^2}\)

Plugging in values for m = 2, r = 1 yields the greatest value:
\(F = k\cdot \dfrac{2^2}{1^2} = 4k\)

Therefore this combination of masses and distance yields the greatest attraction

Objects S and T

Answer:

a. Pure white

b. Pure black

c. Hybrid

Answer:

Ub = 221.99m/s

Explanation:

(Ma x Ua)+(Mb x Ub) = (Ma + Mb)V

(331 x 3.87)+(208 x Ub) = (331 + 208)88

(1257.8) + (208 x Ub) = 47432

(208 x Ub) = 47432 - 1257.8

(208 x Ub) = 46174.2

Ub = 46174.2/208 = 221.99m/s

Ub = 221.99m/s

Answer:

4.75

Explanation:

M1V1 + M2V2 = M1V3 + M2V4

[(331*3.87) , 90°] + 0 = [(331*0.888) , 90°] + M2V4

M2V4 = 987.042 , 90°

divide through by M2

V4 = 4.75 m/s east

Answer:

gases.

Explanation:

gases have the highest volume. if you compress (increase pressure) a gas, the volume decreases and it will take up less space as a liquid, and if you compress more, the liquid will become a solid.

additionally info: this is generally true, but as you get into more difficult subjects, this rule does not hold. for example, some substances cannot obtain a certain phase of matter when they are a certain temperature and or pressure. but that could be way more out of this questions league.

According to the question content loaded torque can be calculated by multiplying the force ( nnn ) applied the torque on the lever is 30 N·m.

The torque on a lever can be calculated by multiplying the force applied at 90 degrees to the lever arm by the distance from the pivot point. The unit for torque is Newton-meter (N·m).

In this case, the force applied at 90 degrees to the lever arm is 15 N and it is applied at a distance of 2.0 m from the pivot point. To calculate the torque, we multiply the force by the distance:

Torque = Force × Distance

       = 15 N × 2.0 m

       = 30 N·m

Therefore, the torque on the lever is 30 N·m.

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The item would have a terminal velocity of 19 m/s.

Using the formula below, you can determine an object's final velocity given its starting velocity, acceleration, and time interval:

Final speed (v) equals the starting speed (u) plus acceleration (a) multiplied by time (t).

We'll enter the values into the formula now:

The starting speed (u) is 4 m/s.

Acceleration (a) equals 3 m/s2

Time (t) equals five seconds.

Final velocity (v) = 4 m/s + 3 m/s2 * 5 s

How to figure out the equation's right-hand side:

(15 m/s) plus (4 m/s) is the final velocity (v).

Simplifying:

Final speed (v) is equal to 19 m/s.

The object's terminal speed would be 19 m/s as a result.

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Answer:

gravity

Explanation:

gravity pulls anything with with weight towards the earth.

Answer

The reason why this occurs is because if there is any apparent wind being pushed towards the direction of the door, there will be an attempt of equalizing pressure and thus it will slam, or close very loudly when you even just push it shut with some effort.

Explanation

This has happened to me a variety of times, I would have the garage open, and it would be a little bit windy, and when I tried to close it, it would slam shut.

Airflow is a significant factor in the pressure appliance.

Your question at the end is correct (Differences in air pressure.)

Apologies for the late response, but I was interested in this as well.