A 135-lb person absorbs 3.3X10⁻⁷ J of energy from radioactive emissions.(a) How many rads does she receive?

-22°C + 273.15 = 251.15K

206°C + 273.15 = 479.15K

50°C + 273.15 = 323.15K

8°C + 273.15 = 281.15K

13 moles of barium sulfide (BaS) would be required to make a 10.0 M solution with a volume of 1.3 x 10^3 mL.

To calculate the number of moles of barium sulfide (BaS) required to make a 10.0 M solution, we need to use the equation:

Molarity (M) = moles of solute / volume of solution (in liters)

First, we need to convert the given volume of the solution from milliliters (mL) to liters (L):

Volume of solution = 1.3 x 10^3 mL = 1.3 L

Next, we rearrange the equation to solve for moles of solute:

moles of solute = Molarity (M) * volume of solution (in liters)

Substituting the values:

moles of BaS = 10.0 M * 1.3 L = 13 moles

Therefore, 13 moles of barium sulfide (BaS) would be required to make a 10.0 M solution with a volume of 1.3 x 10^3 mL.

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Glutamic amino acid is the non-essential amino acid and an excitatory neurotransmitter. When Glu is found in the core then the pKa of the side chain group increases.

pKa is the acid strength or the estimate that shows whether the solution is weak or strong acid. pKa less than zero is a strong acid and portrays the bonding of the proton by the acids.

In the Glu amino acid, the value of the pKa of the side chain functional groups increases as the amino acid is found in the interior of the water-soluble folded protein structure.

Therefore, the pKa of the side-chain increases.

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No, I would not consider using a 5mm electrode for vertical up-root runs in a 6g (hl045) fixed-position pipe.

This is because a 5mm electrode is too large for this type of welding, and can result in a lack of penetration and a weak weld. Instead, a smaller electrode, such as a 3.2mm or 2.5mm, would be a better choice for this application. These smaller electrodes allow for better control and penetration, resulting in a stronger weld. Additionally, it is important to use the correct welding technique and travel speed when performing vertical up-root runs in a 6g (hl045) fixed-position pipe to ensure a strong and secure weld.

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Mass of NH4NO3 use for every 100 g of water is 32.56g.

Calculation:-

m = 100.0 g

dT = 50 -25 = 25 oC

Cp = 4.184 J / oc g

Q  = m Cp dT

Q = 100 x 4.184 x 25

Q = 10460 J

Q = 10.46 kJ

delta H = Q / n

25.7  = 10.46 / n

n = 10.46 /25.7

n = 0.407

moles of NH4NO3 = 0.407

mass of NH4NO3 = moles x molar mass

= 0.407 x  80

= 32.56 g

mass of NH4NO3 needed = 32.56 g

If you are using an already-used instant cold pack strain the liquid and evaporate until dry. The crystals are ammonium nitrate. Dissolve 80 grams of ammonium nitrate in 70 milliliters of hot water. This will take some time, so please be patient. Adding ammonium nitrate to water cools the mixture, a good example of an endothermic chemical reaction. An endothermic reaction occurs at the moment the substances come into contact with each other.

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1. To find the volume of a gas at STP, we can use the ideal gas law, which is an equation that relates the pressure, volume, temperature and amount of a gas. The equation is:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant and T is the temperature.

We can rearrange this equation to find V:

V = nRT/P

We need to make sure that we use consistent units for P, V, T and R. Since we are given P in kPa and T in °C, we can use R = 8.31 J/(K⋅mol) and convert T to K by adding 273.15.

We also need to find n, which is the number of moles of hydrogen gas. We can use the molar mass of hydrogen, which is 2.02 g/mol, to convert the given mass of 5.0 mL to moles. Since 1 mL of gas at STP has a mass of 0.0899 g, we have:

5.0 mL × 0.0899 g/mL ÷ 2.02 g/mol = 0.00222 mol

Now we can plug in the values into the equation for V:

V = (0.00222 mol)(8.31 J/(K⋅mol))(273.15 + 18) K / (97.5 kPa)

V = 0.00507 m^3

To convert m^3 to L, we multiply by 1000:

V = 5.07 L

Therefore, the volume of hydrogen gas at STP is about 5.07 L.

2. To balance the equation for the reaction of hydrogen and nitrogen to form ammonia, we need to make sure that the number of atoms of each element is equal on both sides of the equation. We can do this by adjusting the coefficients (the numbers in front of each compound) until they match.

One possible way to balance the equation is:

3H2 + N2 → 2NH3

A. This type of reaction is called a synthesis reaction or a combination reaction, because two or more substances combine to form a single product.

B. The number of moles are conserved in the balanced equation, because there is no change in the total number of molecules involved in the reaction. According to the balanced equation, three moles of hydrogen react with one mole of nitrogen to produce two moles of ammonia.

C. The balanced equation supports the law of conservation of mass, which states that mass cannot be created or destroyed in a chemical reaction. According to the balanced equation, the total mass of the reactants is equal to the total mass of the product, because each atom has a fixed mass and no atoms are lost or gained in the reaction.

D. To find how many moles of ammonia can be produced from 4.0 liters of hydrogen at 50°C and 1.2 atm of pressure with excess nitrogen, we need to use the ideal gas law again to find how many moles of hydrogen are present:

PV = nRT

n = PV/RT

n = (1.2 atm)(4.0 L) / ((0.082 L⋅atm)/(K⋅mol))(273 + 50) K)

n = 0.19 mol

Since we have excess nitrogen, hydrogen is the limiting reactant, meaning that it will be completely consumed in the reaction and determine how much ammonia can be produced.

According to the balanced equation, three moles of hydrogen produce two moles of ammonia, so we can use this ratio to find how many moles of ammonia are produced from 0.19 mol of hydrogen:

(2 mol NH3 / 3 mol H2) × 0.19 mol H2 = 0.13 mol NH3

Therefore, about 0.13 moles of ammonia can be produced from 4.0 liters of hydrogen at 50°C and 1.2 atm with excess nitrogen.

Answer:

The scientists and all test subjects involved in the investigation work for the company that sells the medication.

Explanation:

The options are as below:

A. The investigation compared a group that took the medication to a control group that did not take the medication.

B. The scientists and all test subjects involved in the investigation work for the company that sells the medication.

C. The weight loss medication worked for 95 out of the 100 test subjects, while only 15 of the 100 control subjects lost weight.

D. The weight loss results were replicated by scientists conducting a study at an independent institution

The correct option would be that the scientists and all test subjects involved in the investigation work for the company that sells the medication.

When selecting the test subjects for research, the selection must be as random as possible so as to ensure an unbiased outcome and increase the reliability of the research.

Limiting the test subjects to those that work in the company that sells the medication will generally reduce the reliability of the outcome because of element of bias that can be introduced either knowingly or unknowingly.

The test subjects must have been selected from the general population of target users for the medication and not limited to just the employees of the manufacturing company.

Correct option: B

Answer:

C. Boiling water

Explanation:

Boiling water is a physical change only; the H20 molecules are moving from a liquid state to a gas state and not turning into a new substance.

Answer:

As more potassium sulfate dissolves in the water, the mixture becomes

Explanation:

As more potassium sulfate dissolves in the water, the mixture becomes

i think A but if I'm wrong sorry

then if increasing then becoming spread out so letter A

Answer:

I believe it will still be 4.00

Explanation:

0.714g of Helium is contained in the balloon

STP stands for standard temperature and pressure. STP refers to a specific pressure and temperature used to report on the properties of matter.

According to IUPAC( International Union of Pure and Applied Chemistry), it is defined as -

It is generally needed to test and compare physical and chemical processes where temperature and pressure plays an important role as they keep on varying from one place to another.

One mole of a gas under STP conditions occupies a volume of 22.4L.

Given,

Volume = 4L

1 mole of a gas occupies 22.4L of volume at STP.

Thus, 1L of a gas occupies = 1 / 22.4 moles

so, 4 L will occupy = 4 / 22.4 moles

                               = 0.178 moles

Moles = mass / atomic mass

Mass =  moles × atomic mass of He

             = 0.178 × 4

              = 0.714g

Therefore, 0.714g of Helium is contained in the balloon.

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The reaction given is 2a + 2b → 4c. From the reaction, we can determine that for every 2 moles of a and 2 moles of b that react, 4 moles of c are produced.

Given that 5 moles of a are consumed per minute, we can use this information to calculate the number of moles of c produced per minute. Since the reaction ratio is 2:4 for a:c, we can set up a proportion to solve for the number of moles of c produced: 2 moles of a : 4 moles of c = 5 moles of a : x moles of c

By cross-multiplying, we get: 2 * x = 5 * 4
Simplifying further:
2x = 20
Dividing both sides by 2: x = 10
Therefore, for every 5 moles of a consumed per minute, 10 moles of c are produced per minute in this reaction.

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For the given reaction 2a 2b→4c, 2 moles of 'a' react to produce 4 moles of 'c'. Therefore, if 5 moles of 'a' are consumed per minute, 10 moles of 'c' are produced per minute, as the ratio of 'a' to 'c' is 1:2.

In this chemical reaction, the stoichiometry shows that 2 moles of 'a' react to produce 4 moles of 'c'. Therefore, for every mole of 'a' that reacts, 2 moles of 'c' are produced. With this ratio, we can determine that if 5 moles of 'a' are consumed per minute, double that amount, or 10 moles of 'c', are produced per minute.

The relationship is derived from the coefficients of the balanced chemical equation. This is a fundamental aspect of chemical reactions and stoichiometry, allowing us to predict how much of each reactant is needed and how much of each product will be produced.

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Answer: I think its C or B

Explanation: Hope this was helpful....

The main reservoirs of the carbon cycle are the atmosphere, oceans, land (including vegetation and soils), and fossil fuels. In these reservoirs, carbon exists in both inorganic and organic forms.

The inorganic carbon cycle involves the exchange of carbon dioxide (CO2) between the atmosphere and oceans through processes like photosynthesis and respiration.

Organic carbon, on the other hand, is found in living organisms, dead organic matter, and soil organic matter. It is cycled through processes such as decomposition and consumption by organisms. The interactions between the inorganic and organic carbon cycles occur primarily in the biosphere, where photosynthesis converts inorganic carbon into organic carbon compounds. While inorganic carbon is primarily in the form of CO2, organic carbon is present in complex organic molecules. Both forms of carbon play crucial roles in energy transfer, nutrient cycling, and climate regulation.

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The concentration of the HF solution is  0.03.

We know that the concentration has to do with the amount of the substance that is present in the system. We know that what we have is an acid hence we can only talk about the concentration of the acid if we can obtain the amount of the hydrogen ion.

We know that the acid is defined as any substance in which there is the presence of the hydrogen ion is what we call and acid. Since the hydrogen fluoride does have the hydrogen, we can say that the substance that we are dealing with here is an acid.

Thus;

pH = 14 - pOH

pOH = hydroxide ion concentration

pH = hydrogen ion concentration

pH = 14 - 12.5

= 1.5

[HF]  = Antilog (-1.5)

= 0.03

The acid would have a concentration of  0.03.

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The deactivation rate constant is 0.04999 min^(-1) and the Ct factors to achieve deactivation of coliforms of 2-log10 (99%), 3-log10 (99.9%) and 4-log10 (99.99%) using disinfectant D are 3, 30, and 300, respectively.

The concentration of the disinfectant "o" was 10 mg/L at 20°C and in water without demand for D.

Time (min): 0 2 4 6 10 15 20

Coliform (colonies/ml): 100000, 35000, 8000, 2250, 180, 20, 1

(a) Calculation of the rate constant

K = - (1/N) (dN/dt)

N0 = 100000 (at t = 0)N = 1 (at t = 20 min)

dN/dt = (N - N0)/(t - t0)

dN/dt = (1 - 100000)/(20 - 0)

dN/dt = -4999 colonies/mL per min

K = - (1/N) (dN/dt)

K = -(-4999/100000)

K = 0.04999 min^(-1)

Therefore, the deactivation rate constant assuming (pseudo)-first-order decay kinetics is 0.04999 min^(-1).

(b) Calculation of Ct factor for disinfectant D

At 20°C, the Z value for coliforms is 10°C Ct = C x t

Where,

C is the concentration of disinfectant D in mg/Lt is the contact time in minutes

For 2-log10 (99%) deactivation:

2-log10 (99%)

deactivation = 99% - 90% = 9% effective reduction

Therefore, Ct value = 3

For 3-log10 (99.9%) deactivation:

3-log10 (99.9%)

deactivation = 99.9% - 90% = 9.9% effective reduction

Therefore, Ct value = 30

For 4-log10 (99.99%) deactivation:

4-log10 (99.99%)

deactivation = 99.99% - 90% = 9.99% effective reduction

Therefore, Ct value = 300

Therefore, the Ct factors to achieve deactivation of coliforms of 2-log10 (99%), 3-log10 (99.9%) and 4-log10 (99.99%) using disinfectant D are 3, 30, and 300, respectively.

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The balanced chemical equation for the given reaction is:

2 Li + Sn(SO3)2 → Li2SO3 + Sn

In this reaction, lithium (Li) reacts with tin(IV) sulfite (Sn(SO3)2) to form lithium sulfite (Li2SO3) and tin (Sn).

Lithium is a highly reactive metal that belongs to group 1 of the periodic table. It has one valence electron that it can readily lose to form a cation. Tin(IV) sulfite is a salt of tin and sulfite ion, which has a -2 charge. In this reaction, the tin in Sn(SO3)2 is in the +4 oxidation state.

During the reaction, the lithium metal donates one electron to the tin in Sn(SO3)2. This causes the tin to be reduced from +4 to +2 oxidation state, while the lithium gets oxidized to Li+ cation. The sulfite ion from Sn(SO3)2 combines with the lithium ion to form lithium sulfite (Li2SO3), and the tin cation combines with the remaining SO3^2- ion to form tin.

Therefore, the product formed in the reaction is lithium sulfite and tin.

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Answer:

Bromine is found in Group 17, Period 4 on the periodic table.

Answer:

Cellular differentiation

Explanation:

Answer:

cellular differentiation

Explanation:

Answer:

A is true NaCl

B is false K2Br

C is true

D false its only 0.03 percent

E is true

It is the charterer's duty to hire a ship for a certain period of time to transport cargo or passengers.

The charterer's job is to hire a ship for a set amount of time to transport goods or people. They are in charge of negotiating the charter conditions with the vessel owner or broker, setting up the required licences and paperwork, and ensuring the timely and safe delivery of cargo or passengers. Broker: The broker's job is to make it easier for the charterer and the vessel owner to come to an agreement. They serve as middlemen, using their connections and market expertise to identify suitable vessels and agree upon conditions of charter that are acceptable to both sides. A appropriate vessel must be provided by the vessel owner in order to satisfy the charterer's needs. They keep the vessel seaworthy, adhere to pertinent laws, and guarantee effective operations throughout the charter.

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Syrus has always done well in school and enjoys science and the correct option is (B) i.e. He won't have to pick his classes as they will be laid out for him.

Pursuing a science major in college would help Syrus because he would not have to pick his classes as they will be laid out for him. When Syrus declares a science major, he will be given a specific curriculum to follow, which will ensure that he takes all the necessary classes to achieve his degree. This takes the pressure off of Syrus to choose his own classes and ensures that he is on the right track towards his career goals. While there may be some flexibility in choosing elective courses within the science major, the core courses will be predetermined.

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Answer:

Explanation:

I believe there is a mistake in the temperature values provided in your question. Water cannot exist at a temperature of 283.0°C or 303.0°C, as it boils at 100°C and freezes at 0°C under standard conditions.

If you meant to say that the initial temperature of the water was 283.0K and the final temperature was 303.0K, then we can use the formula:

q = m * c * ΔT

where q is the amount of energy absorbed, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature.

The specific heat capacity of water is approximately 4.18 J/g*K.

Using the values given, we have:

m = 20.0 g

c = 4.18 J/g*K

ΔT = 303.0K - 283.0K = 20.0K

Plugging in these values, we get:

q = 20.0 g * 4.18 J/g*K * 20.0K = 1672 J

Therefore, 20.0 g of water must absorb 1672 J of energy to increase its temperature from 283.0K to 303.0K.

Crude oil is taken directly from the ground, without artificial chemical alteration. Option A is correct

Crude oil is the correct term for oil taken directly from the ground, without artificial chemical alteration. It is a naturally occurring, unrefined petroleum product composed of hydrocarbon deposits and other organic materials.

Crude oil is a nonrenewable resource and the primary source of energy for the world.

Crude oil is a naturally occurring, unrefined petroleum product composed of hydrocarbon deposits and other organic materials. It is typically found in underground reservoirs and extracted through drilling. Crude oil is the primary source of energy for many industrial processes and is refined into various products such as gasoline, diesel fuel, heating oil, and lubricants. It is a nonrenewable resource and its availability and price can fluctuate based on supply and demand.

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Answer:

A.Hypothesis

Explanation:

Answer:

Yes

Explanation:

Hypothesis: If i increase the number of hours i practice, then i will score more goals in soccer.

Set up. I would have two people who don't play soccer. One will be practicing for one hours every day, and the other will be practicing three hours every day. Based on my hypothesis, the person that is training three hours every day will score more goals than the person training one hour a day.

The elements that have the same number of energy levels as Magnesium are Calcium (Ca) and Strontium (Sr).

Magnesium, classified as an alkaline earth metal, has an atomic number of 12, indicating that it possesses 12 protons and 12 electrons. These electrons occupy different energy levels. Specifically, Magnesium has 2 electrons in its first energy level, 8 electrons in its second energy level, and 2 electrons in its third energy level.

Calcium (Ca) and Strontium (Sr) are elements positioned directly below Magnesium on the periodic table. Both Calcium and Strontium exhibit electron configurations similar to Magnesium, with 3 energy levels containing electrons arranged as 2, 8, 8, 2.

Therefore, Calcium and Strontium share the same number of energy levels as Magnesium, which is three. This similarity in the electron configurations of these elements contributes to their comparable chemical properties within the alkaline earth metal group.

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Because Group 16 elements only have six valence electrons and require two more to have eight, they typically only form two covalent bonds.

The number of electrons in the complete valence shell less the number of valence electrons determines the number of bonds for a neutral atom. This approach is effective because every covalent link an atom makes increases its valence shell by one electron without increasing its charge.

Simple molecules are held together by intermolecular forces. The powerful covalent bonds in molecules are far stronger than the intermolecular forces. These modest intermolecular interactions are overcome when simple molecular compounds melt or boil. Covalent bonds are kept intact.

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