a 1200 pound chandelier is to be suspended over a large ballroom; the chandelier will be hung on a cable whose ends will be attached to the ceiling, 16 feet apart. the chandelier will be free hanging so that the ends of the cable will make equal angles with the ceiling. if the top of the chandelier is to be 16 feet from the ceiling, what is the minimum tension the cable must be able to endure?

(Option C) The car is stopped on a hill. When a car is stopped on a hill, a net force is acting on the car due to gravity.

When a car is stopped on a hill, it is experiencing a net force due to gravity. This force is the result of the downward pull of gravity and the car's brakes, which counteract the gravity and keep the car from rolling down the hill. The car is essentially in a state of equilibrium since the opposing forces of gravity and the brakes are equal and opposite, meaning the net force on the car is zero. However, if the brakes were to suddenly fail, then the net force on the car would be the downward pull of gravity, causing the car to roll down the hill.

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Answer:

Periods indicate that a new period at a new principal energy level which is filled with electrons. Groups indicate that the elements share similar properties because their shells are filled with the same number of valence electons.

Explanation:

e see that starting at period 2 Li has a  +1 charge , He has +2 charge, B has +3 charge, C has the potential to have a +4 charge or -4 charge (because it can gain or loose electrons) and N has a -3 charge, etc. Groups however, have similar properties and every element in a 1A - 8A has the same number of valence electrons. All except the noble gases in which He only needs 2 electrons to be in a perfect state. This is its octet as it would be a completely different element if it had more than 2 electrons in its shell. An example of the groups sharing similar properties is if we were to look at group 1A. In group 1A we find H, Na, K, etc. These are all highly unstable elements when alone (not in a compound) and they are very reactive. If you were to put Na for instance in water, it would light up and you'd see a flame sitting on top of the water. A scientist could do that with the rest of the elements in the group and they would see this increasing in reactivity as you go down the periods. Francium isn't visible long enough to be able to see this happen though. It's more of that kind of element that scientists prove that it exists, but not a very common element to get to learn much about.

Answer:

-1+√251/5 s

Explanation:

The most appropriate equation of motion for this question is; s= ut+(at^2)/2

t=-1+√251/5 s

Answer:

false

Explanation:

most prototypes are and perfect and they are build to find our mistakes

Answer:

Three Laws

Newton's Three Laws of Motion. Sir Isaac Newton: The Universal Law of Gravitation. Sir Isaac Newton and the Unification of Physics & Astronomy.

Explanation:

Explanation:

Solubility is the ability to dissolve within a solvent to form a mixture called a solution

If a substance is soluble, it dissolves in water
If a substance is insoluble in water -  it does not dissolve
Boling point - the temperature at which a substance in its liquid state
converts into the same substance in its gas state.
Water boils at 100 degree centigrade.
Melting point - the temperature at which a substance in its solid state
converts into the same substance in a liquid state.
Ice melts at 0 degree centigrade.
Water freezes at 0 degree centigrade.
How much matter (mass) is packed into a specific space (volume).

Answer:La verdad no tengo conocimiento alguno pero solo te puedo decir que las opciones que te dan en la hoja te pueden ayudar

Explanation:

Answer:

respiratory

Explanation:

Answer:

3. 1.8A

Explanation:

Given the following data;

Quantity of charge, Q = 650C

Time = 6 minutes to seconds = 6 * 60 = 360 seconds.

To find the current l;

Quantity of charge = current * time

Substituting into the equation, we have;

650 = current * 360

Current = 650/360

Current = 1.8 Amperes

The force required to compress the second bone with twice the length but the same cross-sectional area as the first bone would be twice as much.

This means that the same force that compressed the first bone by 1.0 mm would compress the second bone by 0.5 mm.To understand why this is the case, we can look at the equation for strain, which is defined as the change in length divided by the original length. If we assume that the force remains constant, then the strain will be proportional to the change in length.Since the second bone has twice the length of the first bone, it will have twice the original length. Therefore, if the force is the same for both bones, the strain in the second bone will be half of the strain in the first bone. And since strain is proportional to the change in length, the compression of the second bone will also be half of the compression of the first bone.In summary, the same force that compresses the first bone by 1.0 mm would compress the second bone by 0.5 mm, because the second bone has twice the length but the same cross-sectional area as the first bone.

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The resultant vector A + B + C is approximately 5.1 m at an angle 74 degrees north of east.

To find the resultant vector A + B + C, we need to break down each vector into its horizontal (x) and vertical (y) components, and then add them together.

Given:

Vector A: magnitude = 8.0 m, angle = 30 degrees north of east

Vector B: magnitude = 6.0 m, angle = 30 degrees west of north

Vector C: magnitude = 5.0 m, angle = 30 degrees west of south

Let's calculate the x and y components for each vector:

For Vector A:

A_x = 8.0 m × cos(30°)

A_x = 8.0 m × 0.866

A_x ≈ 6.928 m

A_y = 8.0 m × sin(30°)

A_y = 8.0 m ×0.5

A_y = 4.0 m

For Vector B:

B_x = 6.0 m × sin(30°)

B_x = 6.0 m × 0.5

B_x = 3.0 m

B_y = 6.0 m × cos(30°)

B_y = 6.0 m × 0.866

B_y ≈ 5.196 m

For Vector C:

C_x = 5.0 m × sin(30°)

C_x = 5.0 m ×0.5

C_x = 2.5 m

C_y = 5.0 m × cos(30°)

C_y = 5.0 m × 0.866

C_y ≈ 4.33 m

Now, let's add up the x and y components:

Resultant x component = A_x + B_x + C_x

Resultant x component = 6.928 m + 3.0 m + 2.5 m

Resultant x component ≈ 12.428 m

Resultant y component = A_y + B_y + C_y

Resultant y component = 4.0 m + 5.196 m + 4.33 m

Resultant y component ≈ 13.526 m

Finally, we can find the magnitude and angle of the resultant vector:

Resultant magnitude = sqrt((Resultant x component)² + (Resultant y component)²)

Resultant magnitude = sqrt((12.428 m)^2 + (13.526 m)^2)

Resultant magnitude ≈ 18.015 m

Resultant angle = arctan(Resultant y component / Resultant x component)

Resultant angle = arctan(13.526 m / 12.428 m)

Resultant angle ≈ 48.413°

Considering the answer choices provided:

A) 2.1 m at an angle 66 degrees east of north.

B) 5.9 m at an angle 74 degrees north of east.

C) 2.7 m at an angle 74 degrees north of east.

D) 5.1 m at an angle 74 degrees north of east.

E) 4.8 m at an angle 74 degrees east of north.

The closest match to our calculated result is:

D) 5.1 m at an angle 74 degrees north of east.

Therefore, the resultant vector A + B + C is approximately 5.1 m at an angle 74 degrees north of east.

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Answer:

Mass

Explanation:

Answer:

mass

Explanation: less room is taken up

To solve this problem, we can analyze the forces acting on the ladder using the principle of torque equilibrium. The torque equilibrium condition states that the sum of the torques acting on an object must be zero for rotational equilibrium.

Let's assume the counterclockwise direction is positive for torques. Considering the forces acting on the ladder, we have:

Weight of the ladder: The weight acts downward at the center of gravity, which is at the center of the ladder. Since the weight is acting at the center of gravity, it does not create any torque.

The force exerted by the hydraulic piston (F⃗): The force is applied at point C and makes an angle of 40° with the ladder. We need to calculate the torque created by this force.

To calculate the torque, we use the equation:

Torque = Force * Perpendicular Distance

The perpendicular distance between the force and the pivot point A is 8.0 m, as given in the problem.

The torque exerted by the hydraulic piston = F * d * sinθ

where F is the magnitude of the force, d is the perpendicular distance, and θ is the angle between the force and the ladder.

Now, let's substitute the given values into the equation:

Torque exerted by the hydraulic piston = F * 8.0 m * sin(40°)

Since the ladder is in equilibrium, the sum of the torques must be zero. Therefore, the torque exerted by the hydraulic piston should be equal and opposite to the torque exerted by the ladder's weight.

The torque exerted by the ladder's weight = 0 (since it acts at the center of gravity)

Therefore, we can set up the equation:

The torque exerted by the hydraulic piston = Torque exerted by the ladder's weight

F * 8.0 m * sin(40°) = 0

Solving for F:

F = 0 / (8.0 m * sin(40°))

F = 0

This means that the force exerted by the hydraulic piston must be zero for the ladder to be in equilibrium. However, in practical situations, a force would be required to lift and hold the ladder in position. This calculation assumes idealized conditions without considering external factors such as friction, structural constraints, or additional forces.

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The maximum height travelled by the ball before returning to the ground is 8.62 m.

The maximum height travelled by the ball before returning to the ground is calculated by applying the following kinematic equation as shown below.

H = (u²sin²θ) / 2g

where;

H = (26² (sin 30)²) / (2 x 9.8)

H = 8.62 m

Thus, the maximum height travelled by a projectile depends on the initial velocity and angle of projection.

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624 N  force is needed to accelerate a 60.0 kg cart and rider from rest to 4.2 m/s.

The trade-in incline attitude does not have an effect on the ordinary forces but does have an effect on the friction. as the attitude will become steeper, the binder has an extra propensity to transport down the slope, therefore there may be much less friction. Friction and regular force are related by means of the relation: Ff=μFN.

calculation:-

mass = 60 kg

v = u + at

4.2 = 0 + a× 2.5

a = 4.2/2.5

a = 1.68 m/s²

Friction force = 24 N

Normal force (N) = 600N

Net Force = 600 - 24 N

          = 576 N  

a =    576 N / 60

acceleration    = 9.6 m/s²

Force needed to accelerate 60 kg cart = 600 + 24 = 624 N

There's kinetic friction between the block and inclined aircraft. If the block slides downhill, then the kinetic friction appearing on it points uphill. by Newton's 0.33 regulation, the willing aircraft will experience a friction force pointing downhill, within the direction of the block's pace/acceleration.

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Answer:

Below:

Explanation:

The most common method used by the USGS for measuring velocity is with a current meter. However, a variety of advanced equipment can also be used to sense stage and measure streamflow. In the simplest method, a current meter turns with the flow of the river or stream.

Hope it helps...

It's Ms-Muska

Answer:

Below

Explanation:

384 400 km / 300 000 km/s = 1.28 seconds

The total dissolved salt content of the soil is approximately 10.06 mg/g.

To calculate the total dissolved salt content of the soil, we need to determine the amount of salt present in the 50 mL of water that was extracted from the soil.

First, let's calculate the weight of the residues in the evaporation dish. The initial weight of the dish is 35.2300 g, and the final weight after evaporation is 35.4815 g. Therefore, the weight of the residues is 35.4815 g - 35.2300 g = 0.2515 g.

Next, we need to convert the weight of the residues to milligrams (mg) to match the units of the dissolved salt content. The weight of the residues is 0.2515 g, which is equal to 251.5 mg.

Now, we can calculate the dissolved salt content per gram of soil. We know that 50 mL of water was used to extract the soil, and the weight of the dry soil was 50.0 g. So, the dissolved salt content per gram of soil is given by:

(251.5 mg / 50 mL) * (100 mL / 50.0 g) = 5.03 mg/g

Therefore, the correct answer is approximately 10.06 mg/g.

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The weight of the car is 14308 Newtons and the net force acting on it is 230 N. The free body diagram is attached with the answer.

A drag is force that opposes the motion of an object by acting in the direction opposite to its motion.

Given is a car on the freeway that is traveling north at 55 mph on a straight and flat part of the road. The mass of the car is 1460 kg. The engine is pushing the car forward with a force of 760 N. while the drag on the car is 530 N.

PART - A

The free body diagram is attached with the answer. The following equations will help in mathematical analysis.

F[engine] - F[drag] = ma

a = {F[engine] - F[drag]}/m

and

W = N = mg

PART - B

The weight of the car can be calculated as follows -

W = mg = 1460 x 9.8 = 14308 Newton

PART - C

Net force on the car [F] = Force provided by engine {F[E]} - drag force {F[D]}

F = 760 - 530 = 230 N

The direction of force is towards north.

Therefore, the weight of the car is 14308 Newtons and the net force acting on it is 230 N. The free body diagram is attached with the answer.

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The satement is true.

This comes from the fact that, according to Einstein:

and since c² is a very large number then, if we find a way to convert all the mass in energy a small amount will produce a large amount of energy.

The answer is the field vector is perpendicular to the surface.

The electric field's angle with the equipotential surface is always 90 degree. The electric field is always perpendicular to the equipotential surface.

What is electric field?

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thats a hella slow plane

Answer:

work done=0 when angel between 2 objects is 90 degree

Explanation:

George Darwin, the son of Charles Darwin, indeed predicted that the moon is receding from the earth. Recent measurements have confirmed that he was correct! The current rate of recession is estimated to be approximately 3.8 centimeters per year.

This is caused by the tidal forces exerted by the moon on the earth's oceans, which causes a transfer of momentum from the earth's rotation to the moon's orbit.

This recession is caused by the tidal interactions between the Earth and the Moon. As the Earth rotates, its tidal bulges, created by the Moon's gravitational pull, are slightly ahead of the Moon due to the Earth's rotation. This causes the Moon to be pulled forward, which adds energy to the Moon's orbit and causes it to slowly move away from the Earth

This transfer of momentum causes the moon to gradually move away from the earth. I hope that helps!
This recession is caused by the tidal interactions between the Earth and the Moon. As the Earth rotates, its tidal bulges, created by the Moon's gravitational pull, are slightly ahead of the Moon due to the Earth's rotation. This causes the Moon to be pulled forward, which adds energy to the Moon's orbit and causes it to slowly move away from the Earth.

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Answer:

\( \huge{ \boxed{ \bold{ \sf{90 \: joule}}}}\)

✑ First , Let's know what kinetic energy is :

⇾ The energy possessed by a body by the virtue of it's motion is called kinetic energy of the body. A flying bird , a moving car , running water , wind , a bullet fired from a gun , an arrow left from a bow , rolling stone etc are some examples of kinetic energy.

The Kinetic energy of a moving body is determined by the formula :

\( \boxed{ \underline{ \sf{KE= \frac{1}{2} m {v}^{2} }}}\)

Here ,

--------------------------------------------------------------

☇ Now , Let's solve :

☄ Given :

☄ To find :

⤿ \( \boxed{ \sf{KE= \frac{1}{2} m {v}^{2} }}\)

Plug the values and simplify :

→ \( \sf{ \frac{1}{2} \times 20 \times {(3)}^{2} }\)

→ \( \sf{ \frac{1}{2} \times 20 \times 9}\)

→ \( \boxed{ \bold{\sf{90 \: joule}}}\)

Hope I helped !

Have a wonderful day ! ツ

~TheAnimeGirl ♡

Answer:

\(5.2\ \text{m/s}\)

\(70^{\circ}\) south of east

Explanation:

\(v_a\) = 3 m/s

\(\theta_a\) = \(20^{\circ}\) north of east

\(v_b\) = 6 m/s

\(\theta_b\) = \(40^{\circ}\) south of east = \(360-40=320^{\circ}\) north of east

x and y component of \(v_a\)

\(v_{ax}=v_a\cos \theta\\\Rightarrow v_{ax}=3\times \cos 20^{\circ}\\\Rightarrow v_{ax}=2.82\ \text{m/s}\)

\(v_{ay}=v_a\sin\theta\\\Rightarrow v_{ay}=3\times \sin20^{\circ}\\\Rightarrow v_{ay}=1.03\ \text{m/s}\)

x and y component of \(v_b\)

\(v_{bx}=v_b\cos \theta\\\Rightarrow v_{bx}=6\times \cos 320^{\circ}\\\Rightarrow v_{bx}=4.6\ \text{m/s}\)

\(v_{by}=v_b\sin\theta\\\Rightarrow v_{by}=6\times \sin320^{\circ}\\\Rightarrow v_{by}=-3.86\ \text{m/s}\)

\(\Delta v=v_b-v_a\\\Rightarrow \Delta v=(4.6-2.82)\hat{i}+(-3.86-1.03)\hat{j}\\\Rightarrow \Delta v=1.78\hat[i}-4.89\hat{j}\)

Magnitude

\(|\Delta v|=\sqrt{(-4.89)^2+1.78^2}\\\Rightarrow \Delta v=5.2\ \text{m/s}\)

Direction

\(\theta=\tan{-1}|\dfrac{-4.89}{1.78}|\\\Rightarrow \theta=70^{\circ}\)

The magnitude of the change in velocity vector is \(5.2\ \text{m/s}\) and the direction is \(70^{\circ}\) south of east.

The change in velocity will be  \(\Delta V=5.2\ \frac{m}{s}\) and the direction will be \(70^o\) South to east.

Any quantity which is defined by its magnitude and direction both are called as the vector quantities.

Now the data given in the question will be given as:

\(V_a\) = 3 m/s

\(\theta\) = \(20^o\) north of east

\(V_b\) = 6 m/s

\(\theta\) =  \(40^o\)south of east =  360-40=320 north of east

Now we will find the x and y component of \(V_a\)

\(V_{ax}=V_acos\theta\)

\(V_{ax}=3\times Cos20\)

\(V_{ax}=2.82\ \frac{m}{s}\)

\(V_{ay}=V_aSin\theta\)

\(V_{ay}=3\times Sin20\)

\(V_{ay}=1.03\ \frac{m}{s}\)

Now we will find the x and y component of \(V_b\)

\(V_{bx}=V_bcos\theta\)

\(V_{bx}=6\times cos\320\)

\(V_{bx}=4.6\ \frac{m}{s}\)

\(V_{by}=V_bSin\theta\)

\(V_{by}=6\times Sin320\)

\(V_{by}=-3.86\ \frac{m}{s}\)

Now change in velocity will be

\(\Delta V=V_b-V_a\)

\(\Delta V=(4.6-2.82)i+(-3.86-1.03)j\)

\(\Delta V=1.78i-4.89j\)

The magnitude can be find out as follows:

\(\Delta V=\sqrt{(-4.89^2+(1.78^2)}\)

\(\Delta V=5.2\ \frac{m}{s}\)

The direction of the vector will be

\(\theta= tan^{-1}(\dfrac{-4.89}{1.78})\)

\(\theta=70^o\)

Thus the change in velocity will be  \(\Delta V=5.2\ \frac{m}{s}\) and the direction will be \(70^o\) South to east.

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Answer:

8.33 m/s^2

Explanation:

The equation for force is Force = mass * acceleration. The force is 500 N, and the mass is 60 kg, so substituting those into the equation you get that 500 = 60 * acceleration. Divide 500 by 60 to get the acceleration, which is 8.33 m/s^2.

Hope this helps! Let me know if you have any confusion!

The final velocity of the coconut when it falls for 2.00 seconds from rest at the top of its tree is approximately -19.62 m/s.

The final velocity of the coconut can be calculated using the equation for constant acceleration:
v = u + at

Where:
v = final velocity
u = initial velocity (0 m/s, as it falls from rest)
a = acceleration due to gravity (-9.81 m/s^2)
t = time (2.00 seconds)

Plugging in the values:
v = 0 + (-9.81) * 2.00
v = -19.62 m/s

Therefore, the final velocity of the coconut when it falls for 2.00 seconds from rest at the top of its tree is approximately -19.62 m/s.

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To determine the current flowing through a resistor, you need to use Ohm's Law, which states that the current (I) is equal to the voltage (V) divided by the resistance (R), or I = V/R.

In this formula, the voltage is the potential difference across the resistor, and the resistance is the value of the resistor in ohms (Ω). By calculating the current using Ohm's Law, you will determine the flow of current through the resistor. A positive current value indicates that the current flows from left to right through the resistor, as stated in your question.

To find the current flowing through a resistor, apply Ohm's Law (I = V/R) using the voltage across the resistor and its resistance. The resulting positive value will show the current flowing from left to right through the resistor.

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Answer:

everything is perished isn't it?

hope it helps.

Answer:

isn't it is the answer of your question

hope it is helpful to you