A 120 mL solution of sea water had 2.7x1022 sodium ions. What is the concentration of sodium in mol/L?

The mole ratio of acid to base when neutralizing hydrochloric acid with sodium hydroxide is 1:1. A mole of NaOH would completely neutralize one mole of HCl.

The mole ratio would be 2:1 if the hydrochloric acid and barium hydroxide were to be combined instead. Assuming they react in a 1:1 ratio in accordance with the balanced neutralization equation, the moles of acid and base are identical at the equivalence point in a neutralization. Using the reaction between solutions of hydrochloric acid and sodium hydroxide as an example, let's examine how a neutralization reaction creates both water and a salt. This reaction's general equation is NaOH + HCl H2O and NaCl.

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Answer:

Gravity

Explanation:

Sorry If i was late lol

Gravity is the natural force helps sedimentary rock form over many years. Hence option 3 is correct.

Natural force is defined as those in nature that arise as a result of natural events and not because of any outside forces. Weak nuclear force, electromagnetic force, nuclear force, and gravitational force are the four fundamental forces of nature. The weak and strong forces are dominant only at the level of subatomic particles and are only effective across very small distances.

Sedimentary rock production is primarily a result of weathering, dissolution, precipitation, and lithification in the earth's crust. Erosion and weathering include the effects of wind and rain, which progressively break large stones into smaller ones.

Thus, gravity is the natural force helps sedimentary rock form over many years. Hence option 3 is correct.

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Answer:

b.exothermic and entropy is decreasing

Answer: Molecules can be represented with a chemical formula which shows the types of atoms in the molecule, and, uses subscripts, ti show how many of each type of atom is present. such as parentheses, dashes, brackets, commas and plus (+) and minus (−) signs.

H2O (water)

N2 (nitrogen)

O3 (ozone)

CaO (calcium oxide)

C6H12O6 (glucose, a type of sugar)

NaCl (table salt)

Explanation:

Answer:

1.09

Explanation:

Keep in mind that the volume of the solution changes during this titration, so to compute the amount of hydronium that is neutralized during this addition of base (in order to calculate the final pH of the solution), we must calculate the moles of all species in solution initially present. Because both NaOH and HCl ionize completely:initial mol OH−=mol NaOH=(0.0050 L)(0.10 molL)=0.00050 mol OH−initial mol H3O+=mol HCl=(0.050 L)(0.10 molL)=0.0050 mol H3O+The acid is in excess, so all of the OH− present will neutralize an equivalent amount of H3O+, forming water. Thus we simply subtract the moles of hydroxide from the moles of hydronium in solution to find the resultant moles of H3O+ after this neutralization:final mol H3O+= initial mol H3O+−initial mol OH−final mol H3O+=0.0050 mol−0.00050 mol=0.0045 mol H3O+We now calculate the total volume of the solution by adding the volumes of acid and base initially combined: 0.050 L+0.0050 L=0.055 LTo get [H3O+], we divide the final moles of hydronium by the final solution volume:[H3O+]=final mol H3O+ total volume=0.0045 mol0.055 L≈0.08181molLFinally, to find pH:pH=−log[H3O+]=−log(0.08181)=1.09Since the hydronium concentration is only precise to two significant figures, the logarithm should be rounded to two decimal places.

Answer: put 45 mm

Explanation:

The energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

To calculate the energy of combustion for one mole of butane (C4H10), we need to use the information provided and apply the principle of calorimetry.

First, we need to convert the mass of the butane sample from grams to moles. The molar mass of butane (C4H10) can be calculated as follows:

C: 12.01 g/mol

H: 1.01 g/mol

Molar mass of C4H10 = (12.01 * 4) + (1.01 * 10) = 58.12 g/mol

Next, we calculate the moles of butane in the sample:

moles of butane = mass of butane sample / molar mass of butane

moles of butane = 0.367 g / 58.12 g/mol ≈ 0.00631 mol

Now, we can calculate the heat released by the combustion of the butane sample using the equation:

q = C * ΔT

where q is the heat released, C is the heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that the heat capacity of the bomb calorimeter is 2.36 kJ/°C and the change in temperature is 7.73 °C, we can substitute these values into the equation:

q = (2.36 kJ/°C) * 7.73 °C = 18.2078 kJ

Since the heat released by the combustion of the butane sample is equal to the heat absorbed by the calorimeter, we can equate this value to the energy of combustion for one mole of butane.

Energy of combustion for one mole of butane = q / moles of butane

Energy of combustion for one mole of butane = 18.2078 kJ / 0.00631 mol ≈ 2888.81 kJ/mol

Therefore, the energy of combustion for one mole of butane is approximately 2888.81 kJ/mol.

In conclusion, by applying the principles of calorimetry and using the given data, we have calculated the energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

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Answer:

C

Explanation:

there's no need to rush just calm down baby!!!

We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.

Here's an overview of the catalytic cycle, including the necessary details:

i. Chemical structure of the catalyst:

Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]

ii. Molecular geometry of the catalyst:

The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.

iii. Type of reactions involved:

The catalytic cycle involves several reactions, including:

iv. Starting material, reagent, and solvent:

The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).

v. Major and minor end-products:

The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.

vi. Intermediates:

The intermediates in the catalytic cycle include:

These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.

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The molecular orbitals for each of the required molecules has been shown in the images attached.

An illustration of a molecule's molecular orbitals and the corresponding energy levels is called a molecular orbital (MO) diagram. MO diagrams are used to illustrate how the atomic orbitals in a molecule combine to generate the molecular orbitals.

The diagram shows the internuclear distance between the two atoms on the horizontal axis and the relative energy of the atomic orbitals on the vertical axis.

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The equilibrium constant at this temperature is Kc= 4.17 x 10⁻⁶.

Since the equilibrium constant depends on the equilibrium concentration of both the reactants and the products of the chemical reaction.

Balanced reaction equation

2CH₄(g)⇌C₂H₂(g)+3H₂(g)

The initial concentration of the CH₄ = 0.093 M

The equilibrium concentration of the H = 0.017 M

Equilibrium constant = ?

Let's make the ice table

2CH₄(g) ⇌ C₂H₂(g) + 3H₂(g)

0.093 M 0 0

-2x +x +3x

0.093-2x x 0.017 M

3x = 0.017 M

Therefore, x =0.017 M /3 = 0.00567 M

Therefore, the equilibrium concentration of CH₄ =

0.093 M – 2x = 0.093 M – (2 x 0.00567 M) = 0.0817 M

Equilibrium concentration of the C₂H₄ = x = 0.00567 M

Let's write the equilibrium constant expression

Kc= [C₂H₄[H2]³/[CH₄]²

Let's put the values in the formula

Kc= [0.00567][0.017]³/[0.0817]²

Kc= 4.17 x 10⁻⁶

Therefore, the equilibrium constant is 4.17 x 10⁻⁶.

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According to Arrhenius definition of acids, \(NH4^+\) is an acid.

According  to Arrhenius  definition of acids and bases, acid is any substance that produces hydrogen ion in solution as its only positive ion.

Following this definition, let us now consider what happens when \(NH4^+\) is introduced into a water;

\(NH4^+\)(aq)-------> NH3(aq) + \(H^+\)(aq)

Hence, according to Arrhenius definition of acids, \(NH4^+\) is an acid.

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Answer:

If you add bromine water, an aqueous solution of bromine, to the test tubes, you can tell which is propene, the alkene. The bromine reacts with and saturates the double bonds in alkenes, and so decolourises.

please give brainly

Answer:

C

Explanation:

According to the activity series, Li can displace Zn to give LiCO3

The pH of a solution with a concentration of 5.77 x 10-⁷ M is 6.24.

pH refers to the quantitative measure of the acidity or basicity of aqueous or other liquid solutions.

The pH of a substance can be calculated using the following expression:

pH = -log H

Where;

According to this question, the concentration of a solution is 5.77 × 10-⁷M. The pH can be calculated as follows:

pH = - log 5.77 × 10-⁷M

pH = 6.24

Therefore, 6.24 is the pH of the solution

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The section that represents the phase of water with the highest kinetic energy is the gas phase or vapor phase.

Gas phase or vapor phase section is above the boiling point curve, which separates the liquid and gas phases. At this point, the temperature is at or above 100°C (at standard atmospheric pressure), and the kinetic energy of the water molecules is sufficient to overcome the intermolecular forces holding them in the liquid phase and escape into the gas phase. The gas phase has the highest kinetic energy because the water molecules in this phase are more widely separated and move more rapidly than in the liquid or solid phases. The gas phase is also characterized by the highest entropy or disorder, as the molecules are free to move in any direction and occupy a large volume. The section that represents the phase of water with the highest kinetic energy is  gas phase or vapor phase.

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The number of moles of oxygen produced is 0.065 mol.

The molarity of a chemical compound is largely decided in chemistry by trying to divide the mass of a sample of that compound by the amount of substance of that compound, which corresponds to the number of moles in that specimen, evaluated in moles. A substance's molar mass is a bulk property rather than a molecular one. A substance's molar mass is its mass in grams per mole of the compound. A mole is the measurement of the quantity of atoms, molecules, or ions in a substance. A mole is 6.022 1023 molecules of any given substance.

The total mass of all the atoms in a molecule expressed in grams per mole is known as the molar mass.

The mass of the oxygen gas produced = 2.1 g

The molar mass of oxygen gas  , \(O_{2}\) = 2 × 16 g/mol

= 32 g/mol

The formula for the calculation of moles

= mass taken /  molar mass

Thus,

Moles = 2.1 / 32

= 0.065 mol

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Answer:

A: Both models represent atoms with the same atomic number.

Explanation:

The atomic number equals the number of protons.

The correct statement is that both models represent atoms with the same atomic number.

Isotopes are those molecules which are having the same atomic numbers but different atomic masses.

In the given model both they have the same number of electrons and protons it means they are not ions, but are having different atomic masses as number of neutrons are different.

Hence both models represent atoms with the same atomic number.

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The amount of copper in moles in the 27.5 g pure copper sheet is approximately 0.433 moles.

To calculate the amount of copper in moles in a pure copper sheet, we need to use the molar mass of copper and the given mass of the sheet.

The molar mass of copper (Cu) is approximately 63.55 g/mol. This value represents the mass of one mole of copper atoms.

Given that the mass of the pure copper sheet is 27.5 g, we can calculate the number of moles using the following formula:

moles = mass / molar mass

Substituting the values:

moles = 27.5 g / 63.55 g/mol

moles ≈ 0.433 mol

Therefore, the amount of copper in moles in the 27.5 g pure copper sheet is approximately 0.433 moles.

To arrive at this result, we divided the given mass of the sheet (27.5 g) by the molar mass of copper (63.55 g/mol). This calculation allows us to convert the mass of the sheet into the corresponding number of moles of copper.

The result tells us that the 27.5 g pure copper sheet contains approximately 0.433 moles of copper atoms. This conversion to moles is useful in various chemical calculations and allows for easier comparison and analysis of quantities on a molecular scale.

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Answer:

Mainly nitrogen, carbon, hydrogen, and oxygen.

Explanation:

Amino acids are organic compounds composed mainly of nitrogen, carbon, hydrogen, and oxygen. Your body needs 20 different amino acids to grow and function properly. While all 20 of these are important for your health, only 9 are classified as essential

(I'm sorry if I'm wrong)

The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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Answer: 3 qualitative: the word pharmacology is written in blue, the stairs are gray, the tile on the first floor is yellow. 3 quantitative: there are four people wearing yellow, there are Four pink boxes, there are two floors.

Inference: there are many people performing experiments so it’s a lab.

Explanation:

Answer:

Qualitive - The bars are yellow, The floor is green, and the floor has pharmacology on it.

Quantitative - There are 8 support bars, There is 3 gray coats, and there is 27 pills that I can see on that picture.

Inference - There are many people doing experiments because the word pharmacology is on the floor.

Explanation:

This picture tells you that pharmacology is a form of study of medicine and drugs.

Answer:

Title: Determination of Chloride Concentration in Water

Abstract:

This lab report presents a method for determining the chloride concentration in water samples. The analysis is based on the principle of titration using a silver nitrate solution. By titrating the water sample with the silver nitrate solution, the endpoint is determined using a silver chromate indicator, indicating the completion of the reaction between chloride ions and silver ions. From the volume of silver nitrate solution required to reach the endpoint, the chloride concentration in the water sample can be calculated.

Introduction:

Chloride is a common anion found in water and its concentration is important for various purposes, including environmental monitoring, drinking water quality assessment, and industrial processes. This lab aims to determine the chloride concentration in a water sample using a titration method.

Materials and Equipment:

1. Water sample

2. Silver nitrate solution (standardized)

3. Sodium chromate indicator

4. Burette

5. Erlenmeyer flask

6. Pipettes

7. Volumetric flask

8. Distilled water

9. White tile

Procedure:

1. Preparation of Silver Nitrate Solution:

  - Prepare a standard silver nitrate solution with a known concentration.

  - Ensure the solution is properly labeled and stored in a dark bottle to minimize exposure to light.

2. Sample Preparation:

  - Collect a representative water sample in a clean container.

  - If necessary, filter the water sample to remove any particulate matter.

  - Transfer an appropriate volume of the water sample (usually 50 mL) into a clean and dry Erlenmeyer flask.

3. Titration:

  - Add a few drops of sodium chromate indicator to the water sample in the flask.

  - Fill the burette with the standardized silver nitrate solution.

  - Slowly add the silver nitrate solution from the burette into the water sample, while swirling the flask.

  - Continue the addition of silver nitrate solution until the appearance of a reddish-brown color, indicating the endpoint of the titration. Record the volume of silver nitrate solution used.

4. Blank Determination:

  - Perform a blank titration using distilled water instead of the water sample.

  - Follow the same procedure as described in step 3 to determine the volume of silver nitrate solution used.

5. Calculation:

  - Calculate the chloride concentration in the water sample using the formula:

    Chloride concentration (mg/L) = (V - V0) x M x 35.45 / V1

    Where:

    - V is the volume of silver nitrate solution used for the water sample (mL)

    - V0 is the volume of silver nitrate solution used for the blank (mL)

    - M is the molarity of the silver nitrate solution (mol/L)

    - V1 is the volume of the water sample used (L)

Results and Discussion:

- Record the volumes of silver nitrate solution used for both the water sample and the blank.

- Calculate the chloride concentration in the water sample using the provided formula.

- Discuss any sources of error and potential improvements in the procedure.

- Compare the obtained chloride concentration with relevant guidelines or standards to assess the water quality.

Conclusion:

In this lab, the chloride concentration in a water sample was successfully determined using a titration method with silver nitrate solution. The results obtained can be used for water quality assessment and further analysis. It is important to follow proper laboratory techniques and precautions while performing this experiment.

Explanation:

Answer:

 -47749.69 joule energy release.

Explanation:

Given data:

Mass of water = 777.1 g

Initial temperature = 57.3°C

Final temperature = 42.6 °C

Energy change = ?

Solution:

Specific heat capacity of water is 4.18 J/g.°C

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 42.6 °C - 57.3°C

ΔT = -14.7°C

Q = 777.1 g × 4.18J/g.°C ×  -14.7°C

Q =  -47749.69 J

 -47749.69 joule energy release.

Answer:

Chemical properties of food are those properties that cannot be measured without altering the chemical composition of the food material.

Explanation:

Answer:

There are two types of reactions

The most charged oxygen atom that exists in the molecule of water (H2O) is covalently joined to hydrogen. As a result, the hydrogen nucleus on one water molecule interacts with that of oxygen on another water molecule via a dipole.

Hydrogen ties form between nearby oxygen and hydrogen atoms liquid adjacent water molecules in this instance of water. A bond called a hydrogen bond, it is generated via an attraction among two water molecule molecules.

Water exhibits H-bonding because it includes oxygen. Because hydrogen bonds are not present in the acid hydrochloric, it lacks oxygen, nitrogen, and fluorine. Therefore, option (d) — hydrochloric acid — is the correct response.

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The species produced at the cathode in this electrolysis reaction is Ag(s). During electrolysis, the cathode is the electrode at which reduction occurs.

The standard reduction potential is a measure of the tendency of a species to gain electrons and be reduced. A species with a more negative reduction potential is more likely to be reduced than a species with a less negative reduction potential.

Given the species in the mixture, the only species that can be produced at the cathode is silver (Ag). This is because silver has the most negative reduction potential of all the species in the mixture. Copper (Cu), magnesium (Mg), and nickel (Ni) all have more positive reduction potentials and will not be reduced at the cathode.

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Answer:

2.9 atm

Explanation:

We are given the unbalanced molecular equation. So first we will have to balance it:

AgNO₃ (aq) + K₂CrO₄ (aq) ⟶ Ag₂CrO₄ (s) + KNO₃ (aq)

We have two atoms of Ag on the right side and just one atom of it on the left. So we can change the coefficient for AgNO₃ and write a 2 there.

2 AgNO₃ (aq) + K₂CrO₄ (aq) ⟶ Ag₂CrO₄ (s) + KNO₃ (aq)

Now we have 2 atoms of K on the left and 2 ions NO₃- on the left, but just one of them on the right. If we change the coefficient for KNO₃ we will balance the equation.

Molecular equation:

2 AgNO₃ (aq) + K₂CrO₄ (aq) ⟶ Ag₂CrO₄ (s) + 2 KNO₃ (aq)

Now we can split these compounds into their ions to determine the total ionic equation.

Total ionic equation:

2 Ag⁺ (aq) + 2 NO₃⁻ (aq) + 2 K⁺ (aq) + CrO₄²⁻ (aq) -----> Ag₂CrO₄ (s) + 2 K⁺ (aq) + 2 NO₃⁻ (aq)

With this equation we can find the spectator ions. They are the ones that are repeated on both sides of the equation.

If we look at the equation we will see that K⁺ and NO₃⁻ are on both sides.

Answer: the spectator ions are K⁺ and NO₃⁻.