a 10.00 ml sample of a solution of hydrofluoric acid, hf, is diluted to500.00 ml. a 20.00 ml sample of the diluted solution requires 13.51 ml of a0.1500 m naoh solution to be titrated to the equivalence point. what is themolarity of the original hf solution?

Answer:

2KOH + 3co2 ------->2ксоз + 2Н20

Answer:

it may be +1 or -1 hope this help

An atom is a kind of stuff that cannot be further decomposed chemically. Therefore, the charge on a single proton is +1.

The building block of an element is an atom. An atom is a kind of stuff that cannot be further decomposed chemically. The three main components of an atom are protons, neutrons, plus electrons.

Some substances are either bigger or smaller than atoms. Instances of chemical species that aren't commonly regarded as atoms include protons, neutrons, and electrons, which are atom-related particles. Atoms make up molecules and compounds, however they are not actual atoms. Salt is an example of a molecule and a compound (NaCl). The charge on a single proton is +1.

Therefore, the charge on a single proton is +1.

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At physiological pH (pH 7.4), the charge observed on the tripeptide KHR would be +2.

This is because both lysine (K) and arginine (R) have positively charged side chains at this pH. Lysine's amino group (NH3+) and arginine's guanidinium group (NH2+) would both be protonated and carry a positive charge. Histidine's charge is dependent on its protonation state, and at pH 7.4, it can exist in both a protonated (positive charge) and deprotonated (no charge) form.

Since the specific protonation state of histidine in KHR is not provided, we cannot determine its charge contribution. However, considering the positive charges from lysine and arginine, the overall charge of the tripeptide would be +2.

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The equilibrium constant for the reaction 4NO(g) + 2O₂(g) ⇌ 4NO₂(g) at the same temperature would be the square of the equilibrium constant of the reaction 2NO₂(g) ⇌ 2NO(g) + O₂(g), which is (2×10⁻⁶)² or 4×10⁻¹².

The equilibrium constant expression for the reaction 2NO₂(g) ⇌ 2NO(g) + O₂(g) is given as K1 = [NO]²[O₂]/[NO₂]², where square brackets indicate the concentration of the species in the mixture.

According to the stoichiometry of the balanced equation, the reaction 4NO(g) + 2O₂(g) ⇌ 4NO₂(g) involves the same species as the reaction 2NO₂(g) ⇌ 2NO(g) + O₂(g).

Therefore, the equilibrium constant expression for the reaction 4NO(g) + 2O₂(g) ⇌ 4NO₂(g) can be written as K2 = [NO₂]⁴/[NO]⁴[O₂]².

By substituting K1 into K2, we get K2 = (K1)², which is (2×10⁻⁶)² or 4×10⁻¹² at the given temperature.

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Answer:

d

Explanation:

it just makes sense

Answer:

Cold temperatures!

Explanation:

Both planets are very far from the sun, now to explain how the other answers would fit or just dont make sense, No rings, the answer isn't the best fitting answer for this question, 27 moons, this is wrong because neptune has 14 moons, only uranus has 27. No axis tilt, this answer is wrong because both planets have an axis.

is a protected artificial or natural lake that is used to store water for human use is known as an Reservoir .

To determine the order of the reaction with respect to each reactant, we must compare how the reaction rate changes when its concentration changes.

We have in experiment one the same concentration of reactants and a speed equal to 8.0x10^-4 mol/(L.s).

Now, in the second experiment, the concentration of BrO3 doubles, and the rest of the reagents remain the same. The speed is also doubled since 8.0x10^-4 x 2 = 1.6 x 10^-3.

The same happens with Br-, in the third experiment. The rate doubles as the Br concentration doubles.

So for these two reactants, the rate of reaction will be first-order, since as the concentration increases the rate increases in the same proportion.

Now, for H+ we have that by doubling the concentration the rate quadruples. This means that the reaction order is second order. When changing the concentration, the speed changes in order equal to 2

Answer:

the order of reaction will be:

Respect BrO3-: First order

Respect Br-: First order

Respect H+: Second order

Answer:

mass spectrometers separate ions by time without the use of a magnetic field.  All ions are accelerated by an electric field

The species would be an anuran (an amphibian)

We need to answer this in English.

Here we want to find "A species that mates on the surface and then deposits its eggs in the water to be surrounded by sperm"

This would be known as a species of amphibian called an anuran, specifically a frog or toad.

Frogs and toads belong to the order Anura and have a characteristic reproductive cycle that involves external fertilization. During reproduction, the male releases his sperm into the water, and the female deposits her eggs in the water as well. The eggs are externally fertilized by sperm that swim around them. This process is known as external or external fertilization.

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The half-life of a reaction is the time it takes for half of the initial concentration of the reactant to be consumed. The first three successive half-lives can be used to calculate the rate constant (k) of the reaction.

The first half-life (t1/2) is given as 48 min, which means that after 48 min, [A] = [A]0/2 = 2.0 M. The second half-life is 96 min, which means that after 96 min, [A] = [A]0/2^2 = 1.0 M. The third half-life is 192 min, which means that after 192 min, [A] = [A]0/2^3 = 0.5 M. The rate law for a first-order reaction is: rate = k[A], where [A] is the concentration of the reactant at any given time. The integrated rate law for a first-order reaction is: ln([A]t/[A]0) = -kt, where [A]t is the concentration of the reactant at time t.

Using the concentrations and times for the first three half-lives, we can set up the following equations:

ln(2.0 M/4.0 M) = -k(48 min)
ln(1.0 M/4.0 M) = -k(96 min)
ln(0.5 M/4.0 M) = -k(192 min)

Simplifying these equations, we get:
ln(1/2) = -k(48 min)
ln(1/4) = -k(96 min)
ln(1/8) = -k(192 min)

Now, we can use these equations to solve for k. Taking the first equation, we get:
ln(1/2) = -k(48 min)
k = -ln(1/2)/48 min
k = 0.0145 min^-1

Similarly, we can solve for k using the second and third equations:
k = 0.00723 min^-1
k = 0.00362 min^-1
Taking the average of these three values, we get:
k = (0.0145 + 0.00723 + 0.00362)/3
k = 0.00845 min^-1

Therefore, the rate constant (k) for the given reaction is 0.00845 min^-1.

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The number of moles of NaCl contained in 5 L of a 2.2 M solution is 11 moles

The molarity of a solution gives a relationship between volume and mole of substance. The mathematical relationship is given below:

Molarity = number of mole / Volume

With the above formula, we can determine the number of mole of NaCl in the solution. Details below:

Molarity = number of mole / Volume

Cross multiply

Number of mole = molarity × volume

Number of mole of NaCl = 2.2 × 5

Number of mole of NaCl = 11 moles

Thus, the number of moles of NaCl is 11 moles

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The concentration of A decreases and then levels out. Option A

In many chemical reactions, a reactant is consumed as the reaction progresses, leading to a decrease in its concentration over time. The reactant molecules are transformed into products, and as the reaction proceeds, the concentration of the reactant gradually diminishes.

At equilibrium, the concentrations of both reactants and products remain relatively constant over time, although they can coexist.

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The most reliable way of sanitizing impure water  choices is boiling the water. This method kills bacteria and other harmful microorganisms, making the water safer for consumption. Option a is correct.

When air pressure rises, the boiling and melting points also rise. Water has a melting point of 0°C and a boiling temperature of 100°C at a pressure of 1 atm.

Gases are more or less soluble depending on the pressure. We may infer that the boiling point and melting point rise as atmospheric pressure rises because an increase in pressure causes an increase in solubility, whereas a drop in pressure causes a decrease in solubility.

There are several types of carbonated water available, including soda impure water, sparkling water, and seltzer. However, when it comes down to it, carbonated water of all varieties is created when water is infused with carbon dioxide gas under pressure, which causes the development of those small, recognisable bubbles.

Unlike club soda or seltzer, sparkling mineral water has a naturally occurring carbonation. It gets its bubbles from a spring or well where carbonation happens on its own. Water from a spring contains a variety of minerals.

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The complete question is

which of the following practices is the most reliable way of sanitizing impure water? multiple choice a. boiling the water b. freezing and thawing c. the water shaking d. the water vigorously for 1 minute adding salt to the water

Answer:

(9.03x10^-14)x(8.455x10^20)=7.634865x10^7

(5.2x10^11)/(2.10x10^-4)=2.476190x10^15

(7.67x10^12)x(3.8x10^15)=29146000000000000000000000000

(9.237x10^20)/(4.5x10^-6)=2.0526x10^26

Explanation:

Answer:

. Name a soluble compound that could be added to precipitate all of the iron ions from the solution.

Sodium Hydroxide.

Hydrogen gas makes up 25% of the total moles in a container that holds 6.4 moles of gas. Total pressure in the container is 1.24 atm. The partial pressure of hydrogen can be calculated using Dalton's law of partial pressure.Dalton's law of partial pressure states that the total pressure of a mixture of gases is the sum of the partial pressures of the individual gases present in the mixture. The partial pressure of hydrogen gas is 0.31 atm.

To find the partial pressure of hydrogen, we need to first calculate the total number of moles of gas in the container. If hydrogen makes up 25% of the total moles, then the number of moles of hydrogen gas in the container is 0.25 x 6.4 = 1.6 moles.The number of moles of the other gases in the container is 6.4 - 1.6 = 4.8 moles.Now we can use the formula:P(subscript H2) = X(subscript H2) x P(subscript total)where X(subscript H2) is the mole fraction of hydrogen gas and P(subscript total) is the total pressure of the container.

Substituting the values:X(subscript H2) = 1.6/6.4 = 0.25P(subscript total) = 1.24 atmP(subscript H2) = 0.25 x 1.24 = 0.31 atm  Therefore, the partial pressure of hydrogen gas in the container is 0.31 atm. This means that hydrogen gas exerts 0.31 atm of pressure out of the total pressure of 1.24 atm. Hence, the partial pressure of hydrogen in the container is 0.31 atm. The partial pressure of hydrogen gas is 0.31 atm.

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Answer:

79.8%

Explanation:

Percentage yield = actual yield / theoretical yield x 100%

Percentage yield = 220.0 / 275.6 x 100%

=79.8%

The percent yield of of ferrous sulfide if the actual yield is 220.0 g and the theoretical yield is 275.6 g is 79.8%.

Percent yield is defined as the ratio of actual yield to the theoretical yield multiplied by 100. If the actual and theoretical yield are same then the percent yield is 100%.If actual yield is less than the theoretical yield then the percent yield is less than 100%.Reason of this condition arising is the incompletion of reaction or loss of sample during recovery process.

In cases where percent yield is over 100% it indicates that more sample is recovered than the predicted amount.This condition arises when there are other simultaneous reactions taking place leading to the formation of product. It can also arise if there is incomplete removal of impurities from the sample .

In the given example, percent yield can be found out by substituting values in mentioned formula. percent yield,=220/275.6×100=79.8%.

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The balanced chemical equation for the reaction of oxygen and carbon dioxide is:

2CO2 + O2 → 2CO2

From the equation, we can see that for every 1 mole of oxygen that reacts, 2 moles of carbon dioxide are produced.


Using the mole ratio from the balanced equation, we can set up a proportion to find the number of moles of carbon dioxide produced when 8 moles of oxygen react:

1 mol O2 : 2 mol CO2 = 8 mol O2 : x mol CO2

Solving for x, we get:

x = (8 mol O2)(2 mol CO2 / 1 mol O2) = 16 mol CO2

Therefore, when 8 moles of oxygen react, 16 moles of carbon dioxide are produced.

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In the following question, among the given options, The statement that is false regarding Kw is the following: (d.) "The value of Kw shows that water is a weak acid."

What is Kw? Kw is the ion product constant of water. It is a special type of equilibrium constant. The equilibrium in question is the self-ionization of water. The chemical equation for the self-ionization of water is the following:2 H2O(l) ⇌ H3O+(aq) + OH-(aq)Kw = [H3O+][OH-]Here, [H3O+] is the concentration of hydronium ions and [OH-] is the concentration of hydroxide ions. The value of Kw at 25C is 1.0 x 10^-14. This value of Kw is only valid at 25C.pKw and is defined as follows:pKw = -log10(Kw) = 14.00 at 25C. The statement that is false regarding Kw is d. The value of Kw shows that water is a weak acid. The value of Kw does not suggest that water is a weak acid. Water is a neutral compound, neither acidic nor basic.

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Familiar substances that sublime readily include iodine , dry ice , menthol, and camphor. Sublimation is occasionally used in the laboratory as a method for purification of solids, for example, with caffeine.

Explanation:

B → Boron → Atomic number 5

Be → beryllium → Atomic number 4

B - Hybridization → 1S² 2S² 2P¹

\( \sf Boron - \boxed{↿↾} \: \boxed{↿↾} \: \boxed{ \small↾ }\huge\boxed{ }\huge\boxed{ }\)

Be - Hybridization → 1S² 2S²

\( \sf Beryllium →\boxed{↿↾} \: \boxed{↿↾} \: \huge\boxed{ }\huge\boxed{ }\huge\boxed{ }\)

from above data we can see that the outermost orbital of Beryllium i.e. 2S is fully filled & that of boron have 1 electron in 2P orbital. It will require more energy to remove one electron from beryllium Because it will disturb the stability, on other hand the boron will lose one electron easily to attain full filled outermost electron hence it will require less energy for 1st ionization.

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A solution is a homogenous mixture of two or more pure substances whose composition can vary within certain limits. A solution generally consists of two components, they are called solute and solvent.

A solution is called the supersaturated one which contains more dissolved solute than required for preparing the saturated solution and it is generally prepared by heating the saturated solution, adding more solute and then cooling it gently.

A supersaturated solution is unstable. Adding a small amount of the solute, a seed crystal will cause excess solute to rapidly precipitate or crystallize.

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Answer:

it is an endothermic reaction

Explanation:

This is because there is a rise in temperature from 20 to 46. this means that the reaction takes in heat from the suuroundings

The particle represented as X in the given nuclear equation

\(\frac{{^{19}_{10}\text{{Ne}}}}{{\longrightarrow}} X + \frac{{^{19}_{11}\text{{Na}}}}\) is an electron.

In nuclear equations, the symbol X is commonly used to represent an unknown or unspecified particle. In this case, the particle X represents an electron. Electrons, denoted as e⁻, are negatively charged subatomic particles with a mass of approximately 9.11 x 10^-31 kilograms. They are typically found in the electron cloud surrounding the nucleus of an atom.

\(\frac{{^{19}_{10}\text{{Ne}}}}{{\longrightarrow}} X + \frac{{^{19}_{11}\text{{Na}}}}\) is an electron.

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Sodium benzoate 0.20 M has a pH of 8.80.

To calculate the pH of 0.20 M sodium benzoate, we need to consider the dissociation of the sodium benzoate into its conjugate base, benzoate \((C_6H_5COO^-)\), and sodium ion\((Na^+)\).

\(C_6H_5COO^- + H_2O\) ⇌\(C_6H_5COOH\)+ \(OH^-\)

The equilibrium constant for this reaction is given by the Ka value provided, which is 6.5 x 10-5.

We can use the equation for the Ka expression to find the concentration of the benzoic acid, \(C_6H_5COOH\), produced:

\(K_a = [C_6H_5COOH][OH^-]\) / \([C_6H_5COO^-]\)

We know that the concentration of \(C_6H_5COO^-\) is 0.20 M, so we can rearrange the equation to solve for\([C_6H_5COOH]\):

\([C_6H_5COOH] = K_a\) x \([C_6H_5COO^-] / [OH^-]\)

We need to find the concentration of hydroxide ions,\(OH^-\), in order to solve for \([C_6H_5COOH]\). Since we are dealing with a base, we can use the equation for the base dissociation constant, \(K_b\), to find the concentration of \(OH^-\):

\(Kb = [C_5COOH][OH^-] / [C_6H_5COO^-]\)

We can rearrange the equation to solve for [OH-]:

\([OH^-] = \sqrt{(Kb x [C_6H_5COO^-] / [C_6H_5COOH])}\)

The Kb value for the conjugate acid, benzoic acid \((C_6H_5COOH)\), can be found using the equation:

\(K_w = K_a\) x \(K_b\)

Where Kw is the ion product constant for water, which is 1.0 x \(10^-^1^4\) at 25°C.

\(K_w\) = 1.0 x\(10^-^1^4\) = \(K_a\) x \(K_b\)

\(K_b = K_w\) /\(K_a\)= 1.0 x\(10^-^1^4\) / 6.5 x \(10^-^5\)= 1.54 x\(10^-^1^0\)

Now we can substitute the values we know into the equation for\([OH^-]\):

\([OH^-] = \sqrt{(K_b x [C_6H_5COO^-] / [C_6H_5COOH])}\)
\([OH^-] = \sqrt{(1.54 x 10^-^1^0 x 0.20) = 6.27 x 10^-^6 M}\)

Using the equation for the dissociation of water, we \(10^-^1^0\) can find the concentration of H+ ions:

\(K_w\)=\([H^+][OH^-]\)= 1.0 x \(10^-^1^4\)

\([H^+] = K_w\) / \([OH^-]\) = 1.0 x \(10^-^1^4\) / 6.27 x\(10^-^6\) = 1.59 x \(10^-^9\)M

Finally, we can calculate the pH:

pH = \(-log[H^+]\)= -log(1.59 x \(10^-^9\)) = 8.80

Therefore, the pH of 0.20 M sodium benzoate is 8.80.

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We must establish the relative proportions of each element present in the sample in order to calculate the empirical formula of the compound.

From the masses supplied, we can determine the number of moles of each element in a 100 g sample of the compound:

Moles of carbon = 165 g / 12.01 g/mol = 13.74 mol

Moles of hydrogen = 27.8 g / 1.01 g/mol = 27.52 mol

Moles of oxygen = 220.2 g / 16.00 g/mol = 13.76 mol

The empirical formula uses the compound's simplest whole number atom ratio. We divide each of the mole values by the smallest mole value, in this case 13.74 mol, to get the following ratio:

Carbon: 13.74 mol / 13.74 mol = 1

Hydrogen: 27.52 mol / 13.74 mol = 2

Oxygen: 13.76 mol / 13.74 mol = 1

Therefore, the empirical formula of the compound is \(CH_{2} O\).

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there is a change from vapour to liquid