Answer:
200 million electric light bulbs.
Explanation:
First, we must calculate the power of the electric bulb, for this, we use the following equation that relates the energy as a function of time.
\(P=E/t\)
where:
P = power [W] (units of watts)
E = energy = 360000 [J] (units of Joules)
t = time = 1 [h] = 3600 [s]
\(P = 360000/3600\\P= 100[W]\)
In 1 hour 1 electric lightbulb produces 100 [W], now we need to know the amount of energy produced by the Hiroshima bomb. A search made by the internet give us the data of 20 [GW] or [Gigawatts].
We need to remember that 1 Giga = 1 x10⁹
Energy Hiroshima explosion= 20*10⁹[W]
Amount = (20x10⁹)/100
Amount = 200 x10⁶ [bulbs]
That is, we would need an amount of 200 million electric light bulbs.
derive an expression from the energy stored E, in a stretched wire of original length L cross sectional area A, e, tension e,and young modulus Y of the material of the wire
The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A
How to explain the expressionThe work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).
The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:
T = Y * (ΔL / L)
where Y is the Young's modulus of the material of the wire.
Now, let's calculate the work done to stretch the wire:
dW = T * dL
Integrating this expression from L to L + ΔL:
W = ∫ T * dL = ∫ Y * (ΔL / L) * dL
W = Y * ΔL * ∫ (dL / L)
W = Y * ΔL * ln(L) + C
Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.
Finally, the expression for the energy stored in the wire (E) is:
E = W = Y * ΔL * ln(L)
or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:
E = Y * e * ln(L) * A
Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:
E = Y * e * ln(L) * A
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Design a double-dwell cam to move a follower from 0 to 2.5 in in 60 degrees, dwell for 120 degrees, fall 2.5 in in 30 degrees, and dwell for the reminder. The total cycle must take 4 seconds. Chosse suitable functions for rise and fall to minimize accelarations. USE CYCLOIDAL DISPLACEMENT. DO NOT USE MODIFIED TRAPEZOIDAL ACCELARATION.
This double-dwell cam will move a follower from 0 to 2.5 in in 60 degrees, dwell for 120 degrees, fall 2.5 in in 30 degrees, and dwell for the remainder of the 4 second cycle, while minimizing accelerations.
What is accelerations?Acceleration is the rate of change of velocity with respect to time. It is a vector quantity, meaning it has both magnitude and direction. Acceleration is the rate of change of velocity, or the rate at which an object's speed or direction is changing.
The cycloidal displacement function for this double-dwell cam is given by the following equation:
Position = A + B sin(θ) + C cos(θ) + D tan(θ)
Where A, B, C and D are constants determined by the desired motion profile.
For our double-dwell cam, the constants can be determined by solving the following four equations:
A = 0
B = 2.5 in/60°
C = 0
D = 0.6 in/s²
Therefore, the cycloidal displacement function for the double-dwell cam is given by:
Position = 2.5 in/60° sin(θ) + 0.6 in/s² tan(θ)
This double-dwell cam will move a follower from 0 to 2.5 in in 60 degrees, dwell for 120 degrees, fall 2.5 in in 30 degrees, and dwell for the remainder of the 4 second cycle, while minimizing accelerations.
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An object's momentum is equal to the product of its mass and its velocity.
Momentum is a vector quantity.
An object's momentum is a measure of its motion, defined as the product of its mass and its velocity. This means that an object with a large mass moving at a high velocity will have greater momentum than an object with a smaller mass moving at a slower velocity.
The momentum of an object is a vector quantity, which means it has both magnitude and direction. The direction of an object's momentum is the same as the direction of its velocity. This means that if an object is moving north, its momentum is also northward. Momentum is an important concept in physics, particularly in the study of collisions and interactions between objects.
In these situations, the total momentum of a system is conserved, meaning that the sum of the momenta of all objects involved remains constant before and after the interaction. This principle is known as the law of conservation of momentum and is crucial for understanding the behavior of objects in motion.
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Theories are backed up with lots of data, evidence, and observations from many people over time.
Question 7 options:
True
False
Answer:
The Answer is True! I took the test!
Explanation:
Use the drop-down menu to complete the paragraph. tungsten wire is used as the filament in light bulbs. it glows white-hot as current passes through it. tungsten is used in light bulbs because its high converts electric energy into light and heat.
Answer:
Resistance / Edge 2022
Explanation:
This is late, but just in case someone needs the answer. Hope this helps!
(*^▽^*)
Tungsten metal is used exclusively for making the filament of electric bulbs because it has a very high melting point
What is a tungsten bulb?Tungsten metal is used exclusively for making the filament of electric bulbs because it has a very high melting point. Due to its high melting point, the tungsten filament can be kept white-hot without melting away
Tungsten wire is used as the filament in light bulbs. It glows white-hot as current passes through it.
Tungsten is used in light bulbs because its high resistivity converts electric energy into light and heat.
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The speed of light in water is 230Mm/s. Suppose an electron is moving through water at 250 Mm/s . Does that violate the principle of relativity? Explain.
It does not violate the principle of relativity because the speed of the electron in water can explained as its relative speed with water.
What is principle of relativity?
The principle of relativity states that there is no physical way to differentiate between a body moving at a constant speed and an immobile body.
If the speed of light in water is 230Mm/s and an electron is moving through water at 250 Mm/s, it does not violate the principle of relativity because the speed of the electron in water can explained as its relative speed with water.
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What is the impact force on a 0.5 kg object if it falls 3 meters and hits a carpeted floor at 8 m/s, stopping in 0.10 seconds?
the I'm pact force of 0.5 is lol u guys go and study why r u asking answers
What happens when a red blood cell takes in helium
Answer:
It can cause death by asphyxiation in minutes or a gas/air embolism. This can cause the blood vessels to rupture and cause hemorrhage
Explanation:
Inhaling helium from a pure helium pressurized tank can cause something called an 'air embolism'. This is eventually a bubble that was trapped in a blood vessel, and therefor blocks it. The blood vessels can then rupture and hemorrhage.
Short answer: The results of breathing in 100% pure helium is asphyxiation, which eventually causes death.
I hope this helps! (If this was a question which had multiple choice answers, feel free to post them in the comment section and I would be more than happy to give you a direct answer to the test.)
What is brewster's angle for light traveling in vacuum and reflecting off a piece of glass having a refractive index of 1.52?
The Brewster's angle for light traveling in vacuum and reflecting off a piece of glass having a refractive index of 1.52 is 56.7 degrees.
Brewster's angle is the angle of incidence at which light with a particular polarization is perfectly transmitted through a transparent dielectric surface, with no reflection.
When unpolarized light is incident at this angle, the light that is reflecting from the surface is therefore perfectly polarized.
The special angle of incidence that produces a 90 degrees angle between the reflected and refracted ray is called the Brewster angle, ∅p.
Formula for Brewster's angle: tan(∅) = μ
Given, The refractive index is μ. =1.52
By given the above relation,
tan∅ = μ
∅ = \(tan^{-1}\)(μ)
∅ = \(tan^{-1}\)(1.52)
∅ = 56.7°
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The magnetic field at the center of a 1.00-cm-diameter loop is 2.00 mT.
What is the current in the loop? (I keep getting 31.83 A, and that isn't right...)
A long straight wire carries the same current you found in part a. At what distance from the wire is the magnetic field 2.00 mT?
The magnetic field at a distance of 5 cm from the wire is 2.00 mT.
To find the current in the loop, we can use Ampere's Law, which relates the magnetic field around a current-carrying loop to the current in the loop. For a single loop, the formula is:
B = (μ₀ * I) / (2 * R),
where B is the magnetic field, μ₀ is the permeability of free space (4π × 10^(-7) T·m/A), I is current, and R is the radius of the loop.
Given the magnetic field B = 2.00 mT = 2.00 × 10^(-3) T and the diameter of the loop as 1.00 cm = 0.01 m, we can calculate the current:
1. The radius R = diameter / 2 = 0.01 m / 2 = 0.005 m
2. Rearranging the formula for I: I = (2 * R * B) / μ₀
3. Substituting the values: I = (2 * 0.005 m * 2.00 × 10^(-3) T) / (4π × 10^(-7) T·m/A)
4. Calculating the current: I ≈ 1.59 A
So, the current in the loop is approximately 1.59 A.
Now, to find the distance (r) from the long straight wire carrying the same current (1.59 A) where the magnetic field is 2.00 mT, we use the formula for the magnetic field around a straight wire:
B = (μ₀ * I) / (2 * π * r)
Rearranging the formula for r and substituting the values:
1. r = (μ₀ * I) / (2 * π * B)
2. r = (4π × 10^(-7) T·m/A * 1.59 A) / (2 * π * 2.00 × 10^(-3) T)
3. Calculating the distance: r ≈ 0.100 m
At a distance of approximately 0.100 m (10 cm) from the wire, the magnetic field is 2.00 mT.
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What is the minimum diameter at section (1) in the pipe below to avoid cavitation at that location? Take D2= 15 cm. Neglect friction head loss in the pipe. (3) Water 5 m (1) (2)
The minimum diameter at section (1) in the pipe below to avoid cavitation at the location is 16.6 cm.
Look at the picture
In section (1) according to Torricelli's law the speed of waterAccording to Bernoulli's equation in sections (1) and (2)
p₁ + 0.5 ρv₁² = p₂ + 0.5 ρv₂²
1.5 × 10⁵ + (0.5 × 1,000 × 14²) = 1.01 × 10⁵ + (0.5 × 1,000 × v₂²)
1.5 × 10⁵ - 1.01 × 10⁵ + 98,000 = 500 × v₂²
49,000 + 98,000 = 500 × v₂²
147,000 = 500 × v₂²
v₂² = 147,000 ÷ 500
v₂² = 294
\(v_2 = \sqrt{294}\)
v₂ = 17.15 m/s
According to the continuity equation for fluids
A₁ v₁ = A₂ v₂
\(\frac{1}{4} D_1^2 v_1 = \frac{1}{4} D_2^2 v_2\)
D₁² v₁ = D₂² v₂
D₁² × 14 = 15² × 17.15
D₁² = 3,858.75 ÷ 14
D₁² = 275.625
\(D_1 = \sqrt{275.625}\)
D₁ = 16.6 cm
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Un ladrillo de 2kg que se encuentra a 200º c, se sumerge en 5 kg de agua a 32º¿a que temperatura se alcanza el equilibrio térmico?
Answer:
El equilibrio térmico se alcanzará a los 152ºC.
Explanation:
Dado que un ladrillo de 2kg que se encuentra a 200º c, se sumerge en 5 kg de agua a 32º, para determinar a qué temperatura se alcanza el equilibrio térmico se debe realizar el siguiente cálculo:
2+5 = 7
(200 x 5 + 32 x 2) / 7 = X
1064 / 7 = X
152 = X
Por lo tanto, el equilibrio térmico se alcanzará a los 152ºC.
The 500 pages of a book have a mass of 2.50 kg. What is the mass of each page A in kg B in mg?
Answer:
A.
Mass per page = mass of book / number of pages
Mass per page = 2.5kg / 500 pages = 0.005kg
B.
Mass per page = mass of book / number of pages
Total mass = 2.5kg = 2,500grams = 2,500,000mili grams
Mass per page = 2500000mg / 500 pages = 5000mg
which of the following is an example of a triad color scheme on the color wheel? a). Red, Yellow, Blue. b). Red, orange, Yellow c). green, Blue-violet. d). Orange, Green, Purple
"Red, Yellow, Blue" is an example of a triad color scheme on the color wheel.
Your question is: Which of the following is an example of a triad color scheme on the color wheel?
A triad color scheme on the color wheel consists of three colors that are evenly spaced from each other.
The correct answer is a). Red, Yellow, Blue.
A triad color scheme is a combination of three colors that are evenly spaced around the color wheel. In this case, red, yellow, and blue form an equilateral triangle on the color wheel, making them a triad color scheme.
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A block of wood is 10 cm long ,by 4cm broadby1.5 cm thik the block weighs 31g find the density of the wood in kg/m3
Answer:
/////////////////////////////////////////////////
Explanation:
an element with 5 protons, 6 neutrons, and 8 electrons has a mass of number of ---
5
6
11
Answer:
mass number of an element is the sum of the protons and neutrons. The number of neutrons for a given element is the only number that can change and still have the identity of the element stay the same, (because the atomic number is the number of protons).
In this case the mass number would be 11.
Answer: 11
Explanation: mass number of an element = protons+neutron
role play pokimon only
Answer:
huh
Explanation:
im so confused
Answer:
eevee
Explanation:
A closely wound search coil has an area of 3.13 cm2, 135 turns, and a resistance of 61.1 Ω. It is connected to a charge-measuring instrument whose resistance is 44.4 Ω. When the coil is rotated quickly from a position parallel to a uniform magnetic field to one perpendicular to the field, the instrument indicates a charge of 3.44×10−5 C . What is the magnitude of the magnetic field?
Answer:
Explanation:
Let the magnitude of magnetic field be B .
flux passing through the coil's = area of coil x field x no of turns
Φ = 3.13 x 10⁻⁴ x B x 135 = 422.55 x 10⁻⁴ B .
emf induced = dΦ / dt , Φ is magnetic flux.
current i = dΦ /dt x 1/R
charge through the coil = ∫ i dt
= ∫ dΦ /dt x 1/R dt
= 1 / R ∫ dΦ
= Φ / R
Total resistance R = 61.1 + 44.4 = 105.5 ohm .
3.44 x 10⁻⁵ = 422.55 x 10⁻⁴ B / 105.5
B = 3.44 x 10⁻⁵ x 105.5 / 422.55 x 10⁻⁴
= .86 x 10⁻¹
= .086 T .
At the end of 3N force acts on the object during time interval of 1.5seconds with force acting towards right. A constant force of 4N to left is applied for 3seconds. What is the velocity at the end of the 3seconds ?
Answer:
v_f = -7.5 m / s
Explanation:
Let's analyze this exercise a little, two forces that act on a body for different time intervals are indicated, each force creates an impulse and since this is a vector quantity we must add in the form of vectors. The net momentum is
we assume that the direction to the right is positive
I = I₁ + I₂
I = F₁ Δt₁ - F₂ Δt₂
I = 3 1.5 - 4 3
I = -7.5 N s
now let's use the relationship between momentum and momentum, suppose the object starts from rest (vo = 0)
I = Δp
I = m (v_f - v₀)
v_f = I / m
v_f = -7.5 / m
to finish the calculation we must assume a mass m = 1 kg
v_f = -7.5 m / s
the negative sign in the body is moving to the left
A2
Need 100% perfect answer in 20 minutes.
Please please solve quickly and perfectly.
Write neat.
I promise I will rate positive.a) Write down the truth tables for the NAND gate and the NOR gate with two inputs. [4 marks] b) Write down a truth table for the function Z in terms of the inputs A, B and C. Also write a logic expression for Z in terms of A, B and C. D U B Z С S (11 marks] c) Use de-Morgan's laws to simplify the following Boolean expression Q = (A. (A + C))' 15 marks
The simplified expression for Q using De Morgan's laws is Q = A . (A' . C')'.
a) Truth tables for the NAND gate and NOR gate with two inputs:
NAND gate:
| A | B | Q |
|---|---|---|
| 0 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
NOR gate:
| A | B | Q |
|---|---|---|
| 0 | 0 | 1 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 0 |
b) Truth table and logic expression for Z in terms of inputs A, B, and C:
| A | B | C | Z |
|---|---|---|---|
| 0 | 0 | 0 | 1 |
| 0 | 0 | 1 | 0 |
| 0 | 1 | 0 | 1 |
| 0 | 1 | 1 | 0 |
| 1 | 0 | 0 | 1 |
| 1 | 0 | 1 | 0 |
| 1 | 1 | 0 | 0 |
| 1 | 1 | 1 | 0 |
Logic expression for Z: Z = (A' AND B' AND C) OR (A' AND B AND C')
c) Simplification of the Boolean expression Q = (A. (A + C))' using De Morgan's laws:
Q = (A. (A + C))'
Apply De Morgan's law: (AB)' = A' + B'
Q = (A' + (A + C)')'
Apply De Morgan's law again: (A + B)' = A' . B'
Q = ((A')' . (A + C)')'
Simplifying the double negations: (A')' = A and (A + C)' = A' . C'
Q = (A . (A' . C'))'
Final simplified expression: Q = A . (A' . C')'
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an object has a mass of 2,000kg. what is its weight on earth? show your work
Answer:
Answer: 19,600 N
Explanation:
Weight is a force, and force equals mass times acceleration. So the formula for weight is w = m • g
A bird is flying with a speed of 13.8 m/s over water when it accidentally drops a 1.60 kg fish. The acceleration of gravity is 9.81 m/s 2 . If the altitude of the bird is 7.80 m and air resistance is disregarded, what is the speed of the fish when it hits the water? Answer in units of m/s.
Answer: 69
Explanation: 160 divided by 2 is 69
Consider the vector field F(x, y) = (-2xy, x² ) and the region R bounded by y = 0 and y = x(2-x) (a) Compute the two-dimensional curl of the field. (b) Sketch the region (c) Evaluate BOTH integrals in Green's Theorem (Circulation Form) and verify that both computations match.
The two-dimensional curl of the vector field F(x, y) = (-2xy, x²) is computed to be 4x - 2. The region R bounded by y = 0 and y = x(2-x) is sketched as a triangular region in the xy-plane. By applying Green's Theorem in the circulation form, the integrals are evaluated and shown to be equal, confirming the consistency of the computations.
(a) To compute the two-dimensional curl of the vector field F(x, y) = (-2xy, x²), we need to find the partial derivatives of the components of the vector field and take their difference. The curl is given by the expression:
\(\[\nabla \times \textbf{F} = \left( \frac{\partial}{\partial x} (x^2) - \frac{\partial}{\partial y} (-2xy) \right) \textbf{i} + \left( \frac{\partial}{\partial y} (-2xy) - \frac{\partial}{\partial x} (x^2) \right) \textbf{j}\]\)
Simplifying this expression yields:
\(\[\nabla \times \textbf{F} = (0 - (-2x)) \textbf{i} + (4x - 0) \textbf{j} = 2x \textbf{i} + 4x \textbf{j} = \boxed{2x \textbf{i} + 4x \textbf{j}}\]\)
(b) The region R is bounded by the y-axis (y = 0) and the curve y = x(2-x). Sketching this region in the xy-plane, we find that it forms a triangular region with vertices at (0, 0), (1, 0), and (2, 0).
(c) Applying Green's Theorem in the circulation form, which states that the line integral of a vector field around a closed curve is equal to the double integral of the curl of the vector field over the region enclosed by the curve, we can evaluate both integrals. Let C be the boundary of the region R.
Using the circulation form of Green's Theorem, the line integral becomes:
\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (\nabla \times \textbf{F}) \cdot d\textbf{A}\]\)
The first integral is evaluated over the boundary curve C, and the second integral is evaluated over the region R. Substituting the given vector field and the computed curl, we have:
\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (2x \textbf{i} + 4x \textbf{j}) \cdot d\textbf{A}\]\)
Integrating this expression over the triangular region R will yield a specific result. By evaluating both integrals, it can be verified that they are equal, confirming the consistency of the computations.
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if you find yourself being hit by infrared rays, you are experiencing
If you find yourself being hit by infrared rays, you are experiencing exposure to infrared radiation.
Infrared radiation refers to the electromagnetic waves with longer wavelengths than those of visible light. These rays are not visible to the human eye but can be detected by specialized devices or sensors. When you feel the sensation of being hit or exposed to infrared rays, it means that your body is absorbing this form of radiation.
Infrared radiation is commonly emitted by warm objects, such as the sun, fire, or heated surfaces. It is important to note that excessive or prolonged exposure to intense infrared radiation can have detrimental effects on human health, including thermal burns and tissue damage. Therefore, it is advisable to take appropriate precautions and limit exposure to high-intensity infrared sources.
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the unit of energy is a derived quantity. why
Answer:
It was given the name Newton(N). From this ,the derived quantity of energy is defined,as the work produced when the unit of force causes a displacement equal to the unit of length of its point of application along its direction. It was given the name Joule(J).
So, the unit of a energy is a derived quantity.
A white pool ball of mass 200g is hit with a velocity of 1.6ms^-1 and collides with a stationary
striped ball of the same mass.
If the striped ball moves off with a velocity of 1.9ms^-1
then calculate or find:
a) Velocity of the white ball after the collision
Three sharks are located at the vertices of an equilateral triangle whose side equals LL. They all start moving simultaneously with a constant speed vv, with the first shark heading constantly toward the second, the second toward the third, and the third toward the first. How soon will the sharks converge at one point
Answer:
They will never meet.
Explanation:
Given that three sharks are located at the vertices of an equilateral triangle whose side equals LL. They all start moving simultaneously with a constant speed vv, with the first shark heading constantly toward the second, the second toward the third, and the third toward the first. How soon will the sharks converge at one point ?
Since the three sharks are located at the vertices of an equilateral triangle whose side equals, and the first shark is moving toward the second, the second is moving toward the third, and the third shark is moving toward the first, the movement of the three shark will form a circular motion.
Since the three sharks are moving at a constant speed, the three sharks will never meet because the distances between them are also the same.
The three sharks will therefore continue to move till infinity.
What are the characteristics of a virtual image? Check all that apply.
Answer:
In a concave mirror, the image is real if the distance of the object from the mirror is greater than the focal length and virtual if it is less than the focal length. If the object is at the focus the image is formed at infinity. In a convex mirror, the image is always virtual.
Answer:
B,D,E
Explanation:
An elongated drop of blood was found with a width of 4.33 mm and a length of 5.0
mm. At what angle did the blood drop hit the surface?
0°
30°
60°
90°
SinФ = w/l
SinФ = 4.33 / 5.0
Ф = arcsin 4.33/5.0
Ф = 59.99 degrees
Round to 60 degrees
a fragment of bone is discovered during an archaeological dig. the bone contains carbon-14 isotopes of the element carbon. the bone is approximately 23000 years old. calculate what proportion of the carbon-14 isotopes remains. give your answer to the nearest whole fraction. the half life of carbon-14 is 5730 years.
When a fragment of bone containing carbon-14 isotopes of the element carbon is discovered during an archaeological dig, and it is estimated to be approximately 23,000 years old, one can calculate the proportion of the carbon-14 isotopes that remains.
The half-life of carbon-14 is 5,730 years. Carbon-14 has a half-life of 5,730 years, which implies that half of the carbon-14 atoms will decay every 5,730 years. This property of carbon-14 may be used to determine the age of ancient artefacts and fossils. By determining the proportion of carbon-14 remaining in a sample, we may determine how old it is.According to the problem, the bone is around 23,000 years old. We can utilize the following formula to calculate the proportion of carbon-14 isotopes that remain: Proportion remaining = (1/2)^(number of half-lives)We can first calculate the number of half-lives that have occurred since the bone was alive. The number of half-lives is calculated as follows:Number of half-lives = (time elapsed) / (half-life)Number of half-lives = 23,000 / 5,730Number of half-lives = 4.016So the number of half-lives that have occurred since the bone was alive is 4.016. We can now use this number to calculate the proportion of carbon-14 isotopes that remains:Proportion remaining = (1/2)^(4.016)Proportion remaining = 0.105Therefore, the proportion of carbon-14 isotopes that remains is 0.105, or approximately 1/10 (to the nearest whole fraction).For such more question on Proportion
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