the air molecules gained approximately 0.5 J of energy from the falling coffee filter.
Energy possessed by air molecules due to the falling coffee filter is calculated as follows:
The potential energy of the coffee filter when it was dropped can be calculated by the formula;
Potential energy = mgh
where; m = mass of coffee filter = 1.0 gh = height from which the coffee filter was dropped = 0.5 g = acceleration due to gravity = 9.81m/s²Substituting the given values in the above equation,
Potential energy = 1.0 x 0.5 x 9.81= 4.905 J
When the coffee filter reaches a terminal speed, its kinetic energy is equal to its potential energy.
Thus;
Kinetic energy = 4.905 J
The energy gained by the air molecules from the falling coffee filter is approximately equal to the kinetic energy of the filter, i.e.,
Kinetic energy = 4.905 J ≈ 0.5 J (approx)
Therefore, the air molecules gained approximately 0.5 J of energy from the falling coffee filter.
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The seed planted at extreme cold or in the region of frozen ice do not germinate, why?
Answer:
yes
The the seed planted at Extreme cold or in the region of frozen I did not germinate because the amount of moisture of the seed is too high which results in lack of air of the sea in the frozen ice
In fact, a soil temperature below 50°F might be problematic for many garden plants. Seeds will quickly absorb water at 40°C, but they won't begin to grow. This presents a risk for rot and disease, which may cause damping-off or subpar growth.
What is germination of seed?The formation of the seedling is the consequence of germination, which is often the growth of a plant inside a seed. It is also the process of the seed's metabolic machinery being reactivated, which causes the radicle and plumule to emerge. A vascular plant's seed is a little bundle that develops in a fruit or cone as the result of the union of the male and female reproductive cells.
Given the need for particular internal or external stimuli to resume growth, dormant seeds are viable seeds that do not germinate. When the right circumstances are present, the seed starts to germinate and the embryo starts to grow again, eventually becoming a seedling.
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WILL GIVE BRAINLIEST
Explain the stages of complete and incomplete metamorphosis, provide examples for each. (Counts 20% of your lesson grade.)
Metamorphosis refers to the process of development and change in the body form of certain animals as they grow from juveniles to adults.
Explain the types of metamorphosis?
Metamorphosis is classified into two types: complete and incomplete.
1. Complete metamorphosis:
Complete metamorphosis is a developmental process in which the juvenile form of an animal goes through four distinct stages: egg, larva, pupa, and adult. In this type of metamorphosis, the juvenile form looks completely different from the adult form in terms of appearance, behavior, and habitat.
Animals that undergo complete metamorphosis include:
a) Butterflies and moths: The egg hatches into a caterpillar (larva) that feeds and grows rapidly. The larva then forms a pupa or chrysalis, where the body undergoes a complete transformation into an adult butterfly or moth.
b) Flies: The egg hatches into a worm-like maggot (larva) that feeds and grows. The maggot then transforms into a pupa, and finally, an adult fly emerges.
c) Beetles: The egg hatches into a grub (larva) that feeds and grows. The grub then transforms into a pupa, and finally, an adult beetle emerges.
Incomplete metamorphosis:
Incomplete metamorphosis is a developmental process in which the juvenile form (nymph) of an animal resembles the adult in appearance and habitat, but is smaller and lacks wings. The nymph goes through several stages of growth and molting before reaching adult form.
Animals that undergo incomplete metamorphosis include:
a) Grasshoppers: The egg hatches into a nymph that resembles the adult grasshopper but lacks wings. The nymph goes through several molts and growth stages before developing wings and reaching the adult stage.
b) Cockroaches: The egg hatches into a nymph that resembles the adult cockroach but lacks wings. The nymph goes through several molts and growth stages before developing wings and reaching the adult stage.
c) Dragonflies: The egg hatches into a nymph that lives in water and resembles the adult dragonfly but lacks wings. The nymph goes through several molts and growth stages before developing wings and emerging from the water as an adult dragonfly.
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a ball is tossed vertically into the air. when the ball reaches its highest point, what is its acceleration
Answer:
9.81 m/s^2 downwards
Explanation:
At the top only weight acts on the ball. Therefore,
\(net \: force = ma \\ weight = ma \\ mg = ma \\ a = g \\ a = 9.81 {ms}^{ - 2} \)
what produces magnetic fields
Answer:
B is the answer
Explanation:
Magnetic fields are produced by moving electric charges and the intrinsic magnetic moments of elementary particles associated with a fundamental quantum property, their spin.
at the instant shown, rank these six scenarios on the basis of the magnitude of the current in the light bulb.
At the instant shown, the six scenarios can be ranked in terms of the magnitude of current in the light bulb as follows:
1) Scenario 1 - Here, the battery is directly connected to the light bulb without any other resistors in the circuit. Therefore, the current flowing through the bulb will be the maximum among all the scenarios.
2) Scenario 3 - In this case, the battery is connected to the light bulb through a resistor. However, the resistance is less compared to other scenarios, so the current will be higher than in other cases.
3) Scenario 4 - Here, the battery is connected to the light bulb through a higher resistance compared to scenario 3. This will result in a lesser current in the bulb.
4) Scenario 5 - In this scenario, the battery is connected to the light bulb through a much higher resistance than in the previous two scenarios. Therefore, the current flowing through the bulb will be lower.
5) Scenario 6 - Here, the battery is connected to the circuit in such a way that the current will bypass the light bulb. Therefore, the bulb will not light up and the current flowing through it will be zero.
6) Scenario 2 - This scenario is similar to scenario 6 where the switch is open, so the circuit is not complete, and hence there will be no current flowing through the light bulb.
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A coin has a mass of 7.0g. It is made of a metal alloy of density 5.6g/cm3. Calculate the volume of the coin.
\(\text{Density,}\\\\~~~~~~~~\rho = \dfrac mV\\\\\\\implies V = \dfrac m{\rho}\\\\\\\implies V = \dfrac{7 \times 10^{-3}~ \text{kg}}{\tfrac{5.6 \times 10^{-3}~ \text{kg}}{ 10^{-6} ~\text{m}^3} }\\\\ \\\implies V = \dfrac{7 \times 10^{-3}~ \text{kg}}{5.6 \times 10^{-3} \times 10^6~~ \text{kg}~ \text{m}^{-3}}\\\\\\ \implies V = 1.25 \times 10^{-6}~ \text m^3\\\\\\\implies V =0.00000125~ \text m^3\\\\\text{Hence the volume of the coin is 0.00000125}~ \text m^3\)
You throw a ball straight up into the air. the ball starts from rest and has a speed of 7.60 m/s when it leaves your hand. in the process of throwing the ball, you move your hand through a vertical distance of 1.02 m. if the ball has a mass of 0.150 kg and undergoes constant acceleration during the throw, calculate the magnitude of the force that you exert on the ball during the throwing process. hint: remember newton's 2nd law - an object's acceleration is due to the net force acting on it.
The force exerted on the ball is 28.88 N.
We need to know about force to solve this problem. According to second Newton's Law, the force applied to an object will be proportional to mass and acceleration. Hence, it can be written as
F = m . a
where F is force, m is mass and a is acceleration
From the question above, we know that
vo = 0 m/s
vt = 7.6 m/s
s = 1.02 m
m = 0.15 kg
Find the acceleration
vt² = vo² + 2as
7.6² = 0² + 2.a.0.15
a = 57.76 / 0.3
a = 192.53
Find the force exerted
F = m .a
F = 0.15 . 192.53
F = 28.88 N
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_______ is a huge reddish loops of gas that often link different parts of sunspot regions.
Solar Prominence is a huge reddish loop of gas that often link different parts of sunspot regions.
What is a Solar Prominence?
A solar prominence is a large, loop-like structure of plasma that extends from the Sun's surface into its outer atmosphere. Prominences are often associated with sunspot regions and can span hundreds of thousands of kilometers. They are composed of charged particles, primarily hydrogen and helium, that are held in place by the Sun's magnetic field. The reddish color is due to the emission of light in the hydrogen alpha spectral line. Solar prominences are dynamic structures that can erupt and release huge amounts of energy into space, in the form of coronal mass ejections.
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.
(ii) (a) a 2.80 cm high insect is 1.30 m from a 135 mm focal length lens. where is the image, how high is it, and what type is it? (b) what if / 135 mm?
When a 2.80 cm high insect is positioned 1.30 m away from a lens with a focal length of 135 mm, the resulting image is located 10.07 cm from the lens, has a height of 0.22 cm, and is a virtual and upright image.
(ii) (a) Given:
Object height (h₁) = 2.80 cm
Object distance (u₁) = 1.30 m = 130 cm
Focal length of the lens (f₁) = 135 mm = 13.5 cm
Using the lens formula: 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance.
Substituting the given values:
1/13.5 = 1/v - 1/130
Solving for v, the image distance formed by the lens:
1/v = 1/13.5 + 1/130
1/v = (10 + 1)/135
1/v = 11/135
v = 135/11 ≈ 12.27 cm
M₁ = -v/u₁
M₁ = -(12.27/130)
M₁ ≈ -0.094
formula: h₂ = |M₁| * h₁
h₂ = |-0.094| * 2.80
h₂ ≈ 0.263 cm
The height of the image (h₂) is approximately 0.263 cm.
Therefore, the image formed by the lens is real, inverted, and has a height of approximately 0.263 cm. It is located at a distance of approximately 12.27 cm from the lens
(ii) (b) If the focal length of the lens is changed to 135 mm (0.135 m), we can repeat the calculations using the new focal length.
Object height (h₁) = 2.80 cm
Object distance (u₁) = 1.30 m = 130 cm
Focal length of the lens (f₁) = 0.135 m = 13.5 cm
1/13.5 = 1/v - 1/130
Solving for v, the image distance formed by the lens:
1/v = 1/13.5 + 1/130
1/v = (10 + 1)/135
1/v = 11/135
v = 135/11 ≈ 12.27 cm
The image distance (v) and the magnification (M) remain the same as in part (a) because the object distance (u₁) and the focal length (f₁) are unchanged. Therefore, the image would still be located at approximately 12.27 cm from the lens, have a height of approximately 0.263 cm, and be real, inverted.
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Why VR of second class lever is greater than 1?
Second class lever has mechanical advantage always more than one as load is in between fulcrum and effort making the effort arm longer than the load arm. It multiplies force. ... It does not multiply force but changes the direction of force.
The angular position of an object that rotates about a fixed axis is given by:
θ(t) = θ0 e^(βt), where β = 2 s^−1, θ0 = 0.7 rad, and t is in seconds.
What is the magnitude of the total linear acceleration at t = 0 of a point on the object that is 8.5 cm from the axis?
The magnitude of the total linear acceleration at t = 0 for a point on the object 8.5 cm from the axis is 11.9 cm/s².
To find the linear acceleration, we first need to determine the angular acceleration (α) and angular velocity (ω) at t = 0.
1. Differentiate θ(t) with respect to time to find the angular velocity: ω(t) = d(θ(t))/dt = βθ0 * \(e^\beta^t\)
2. Differentiate ω(t) to find the angular acceleration: α(t) = d(ω(t))/dt = β²θ₀ * \(e^\beta^t\).
3. Plug in t = 0 into both equations: ω(0) = βθ₀ and α(0) = β²θ₀.
4. Calculate the radial (ar) and tangential (at) linear accelerations: ar = rω² and at = rα.
5. Add ar and at in quadrature to find the total linear acceleration: a_total = √(ar² + at²).
With the given values of β = 2 s⁻¹, θ₀ = 0.7 rad, and r = 8.5 cm, the total linear acceleration is 11.9 cm/s².
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Write one example situation of Newton's Third Law involving mass that are different.
Answer:
when we throw a ball on the wall so it will comes back in this there is third law of motion means every action has equal reaction
What might you be doing if you measure your heart rate and find that it beats 100 times in a minute?
Answer:
Rigorous exercise
Explanation:
For your heart rate is been around 100 bpm you should be doing a rigorous exercise . but if ain't doing any rigorous exercise and your heart rate is constantly above 100 bpm you should consult your doctor.
An average heart is between 60 bpm to 100 bpm.
any three methods to increase efficiency of a simple machine?
Answer:
lubricant (decrease friction).
control production speed.
use only when required.
A charge of 8.4 × 10–4 C moves at an angle of 35° to a magnetic field that has a field strength of 6.7 × 10–3 T.
If the magnetic force is 3.5 × 10–2 N, how fast is the charge moving?
9.1 × 10–5 m/s
1.3 × 10–4 m/s
7.6 × 103 m/s
1.1 × 104 m/s
Answer:
the correct answer is D
Explanation:
What is the distance from one peak to the next peak called?
Answer:
wavelength
Explanation:
Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.
Generally, the most commonly used electromagnetic wave technology in telecommunications is radio waves.
Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.
Basically, as a result of radio waves having long wavelengths, they are mainly used in long-distance communications such as the carriage and transmission of data.
The distance from one peak to the next peak is called wavelength. This distance is also equal to the distance from one trough of a wave to another.
Mathematically, wavelength is calculated using this formula;
\( Wavelength = \frac {speed}{frequency} \)
an electric field can be applied to keep particle a moving in a straight line through the magnetic field. calculate the magnitude of this electric field and state its direction by showing the electric field lines.
To calculate the magnitude of the electric field of a particle A moving in a straight line through the magnetic field, we'll use the equation:
E = B * v
where,
E is the magnitude of the electric field.
B is the magnitude of the magnetic field.
v is the velocity of particle A.
The direction of the electric field should be such that the force acting on the particle due to the electric field :
F_ electric = q * E
where,
q is the charge of the particle is equal and opposite to the force acting on the particle due to the magnetic field
F_magnetic = q * v * B * sin(Ф)
where,
Ф is the angle between the velocity and the magnetic field.
In this case, theta is 90 degrees, so sin(Ф) = 1.
To ensure the net force is zero, the electric field lines must be perpendicular to the magnetic field lines and the direction of the particle's velocity.
This way, the forces due to the electric and magnetic fields cancel each other out, keeping the particle moving in a straight line.
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a hemisphere of ice with radius r rests so with its flat surface fixed to the ground. a block starts at rest at the top of the hemisphere and is given a nudge so that it slides (without friction) down the slope. how high above the ground will the block be when it looses contact with the ice (hint: what has to be zero when the block loses contact with the ice)?
The height of the block from ground is when block loses contact with the ice. This can be solved by using energy conservation and centrifugal force.
Initially the block is placed at a height of r because the height of the hemisphere would be the radius.
So total energy would be = mgr
when it is going to leave the surface, there will be some kinetic and static energy,
so total energy = 1/2 x m x v^2 + m x g x rcosФ
from conservation of energy theorem, we can write
Total energy before = total energy after
mgr = 1/2 x m x v^2 + m x g x rcosФ
2 gr = v^2 + 2 x g x rcosФ
Again, when the object is loosing the contact, that time the centrifugal force will be equal to the vertical force,
(m x v^2)/r = mgcosФ
=> v^2 = grcosФ
putting the values in the above equation
2gr = grcosФ + 2grcosФ
cosФ = 2/3
Also, we can find that when object is losing the contact, the height of the object would be = rcosФ
= r x 2/3
= 2r/3
Hence the height of the object when it is losing the contact is 2r/3.
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Prove that the two equations shown below are equivalent.
F = ma and F = p/t
Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.
\(\Delta p = mv - mu \\\\\implies \Delta p = m(v-u) \\\\F = \dfrac{\Delta p}{\Delta t} = \dfrac{m(v-u)}{\Delta t} = ma\)
F = ma is the formula of Newton’s Second Law of Motion.
To prove Newton's second law of motion,
Given Force F = Δp/Δt
What is relation between F = ma and F = Δp/Δt?Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. The second law of Newton can be described as the acceleration of an object which produces a net force is directly proportional to the magnitude of the net force, in the same path i.e., direction as the net force, and inversely proportional to the mass of the object.As the acceleration has its magnitude and direction it is a vector quantity.Proof for F=ma
Let us consider an object of mass m, moving along a straight line with an initial velocity u, final velocity v and it has some particular time t and thus Momentum can be related as,
For initial velocity u, p1 = m × u
The final velocity v, p2 = m × v
The change in momentum can be expressed as
p2 – p1 = (m × v) – (m × u)
p2 – p1 = m (v – u)
Here, we know that the rate of change of momentum with respect to time is proportional to the applied force.
The applied force F,
F ∝ [m (v – u)]/t
F ∝ m × a
As acceleration (a) is the rate of change of velocity with respect to time.
F = k × m × a
F = ma
where k can be the constant.
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What would happen if you went through a black hole. I will give brainliest for a correct answer.
Answer:
You would get spagettified. Streched into a very long noodle version of yourself.
An electric motor has an effective resistance of 29. 4 ω and an inductive reactance of 42. 6 ω. When working under load. the rms voltage across the alternating source is 442 v. Calculate the rms current
An electric motor has an effective resistance of 29. 4 ω and an inductive reactance of 42. 6 ω. When working under load. the rms voltage across the alternating source is 442 v. The rms current will be 8.54 A
AC stands for “Alternating Current,” meaning voltage or current that changes polarity or direction, respectively, over time. AC electromechanical generators, known as alternators, are of simpler construction than DC electromechanical generators.
RMS or root mean square current/voltage of the alternating current/voltage represents the D.C current/voltage that dissipates the same amount of power as the average power dissipated by the alternating current/voltage. For sinusoidal oscillations, the RMS value equals peak value divided by the square root of 2.
I (RMS) = RMS voltage / \(\sqrt{R^{2}+ X_{L} { ^{2} }\)
= 442 / \(\sqrt{29.4^{2} + 42.6^{2} }\)
= 442 / \(\sqrt{864.36 + 1814.76}\)
= 442 / \(\sqrt{2679.12}\)
= 8.54 A
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which are considered noble gases
Answer:Argon
Neon
Helium
Krypton
Xenon
14. The average speed of a car was 60 m/s by the time it reached the finish line. The car moved in a straight line and traveled from the starting
line to the finish line in 8.0 sec. How far was the finish line?
A train is moving with the velocity 10 m/s. It attains an acceleration of 4 m/s² after 5 seconds. Find the distance covered by the train in that time.
The train covers a distance of 100 meters in the given time.
To find the distance covered by the train in the given time, we can use the equations of motion.
S = ut + (1/2)at²
The equation S = ut + (1/2)at² is derived from the basic equations of motion. The first term (ut) represents the distance covered in the initial velocity u multiplied by time t. The second term (1/2)at² represents the distance covered due to the acceleration a during time t.
The initial velocity (u) of the train is 10 m/s, and the acceleration (a) is 4 m/s². We are given that this acceleration is attained after 5 seconds, so the time (t) is also 5 seconds. We need to find the distance covered (S).
Substituting the given values:
S = (10 m/s)(5 s) + (1/2)(4 m/s²)(5 s)²
S = 50 m + (1/2)(4 m/s²)(25 s²)
S = 50 m + 50 m
S = 100 m
It's important to note that the given problem assumes a constant acceleration throughout the entire time interval.
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If a falling object gains 10 m/s each second that it falls, its acceleration (assumed positive downwards) is:__________
Acceleration refers to the rate of change in velocity, and by the info in the given problem, conclusion can be made that the velocity change by 10 m/sec every second.
That is : 10 m/sec by 1 sec = 10 m/s²
Hope it helps -',...,'-If a falling object gains 10 m/s each second that it falls, its acceleration is 1 m/sec².
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.
The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.
Acceleration = velocity /time
= 10/1
= 10 m/sec²
If a falling object gains 10 m/s each second that it falls, its acceleration is 1 m/sec².
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If the distance between two spherical charged objects increases by a factor of two, then the electrical force between the objects
Answer:a repulsive electrical force. ... postulates that an electric field surrounds each charged object. If the distance between two spherical charged objects increases by a factor of two, then the electrical force between the objects. decreases by a factor of four.
Explanation: does this help
Calculate the speed of a bus that travels a distance of 55 miles in 0.75 hours.
You are moving at 30 km/s with respect to the sun because the Earth ismoving. So is the chair you are sitting in. If you stood up and jumped, thechair wouldn't move out from under you because:A) The inertia of you and the chair carry both of you with the speed of the EarthB)The chair is stuck to the ground because of frictionC) You didn’t jump high enough for that speed to matterD) You have inertia that keeps you gravitationally attracted to the chair
Given that both the chair and the person are affected by Earth's movement, we can deduct that both have inertia due to Earth's speed.
Therefore, the answer is A.the temperature in degrees farenheight in times square during a day in aguast can be predicted by the function t(x)
The given statement is that the temperature in degrees Fahrenheit in times square during a day in August can be predicted by the function t(x).
Hence, it can be stated that the function t(x) provides a prediction for the temperature in degrees Fahrenheit in Times Square for a given value of x. Here, x represents the input variable.
It is important to note that the input variable must be provided in the correct units and format as required by the function t(x).The content loaded refers to the data that has been previously collected and is available for analysis. In the context of predicting temperature using function t(x),
the content loaded can refer to temperature data collected in Times Square during August on previous days or years. This data can be analyzed and used to develop the function t(x) that predicts temperature for a given input variable x.
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A gas contains 75.0 wt % propane, 13.0 wt% n-butane, and the balance water. a)Calculate the molar composition of this gas on both a wet and a dry basis and the ratio (mol H2O/mol dry gas). b) If 100 kg/h of this fuel is to be burned with 25% excess air, what is the required air feed rate (kmol/h)? How would the answer change if the combustion were only 65% complete? 4.68. Butane is burned with air. No carbon monoxide is present in the combustion products. a)Use a degree-of-freedom analysis to prove that if the percentage excess air and the percentage conversion of butane are specified, the molar composition of the product gas can be determined. b) Calculate the molar composition of the product gas for each of the following three cases: (i)theoretical air supplied,100% conversion of butane; (ii)30% excess air,100% conversion of butane; and (iii)30% excess air, 90% conversion of butane.
a) On a wet basis, the molar composition of the gas is approximately 0.813 mol propane, 0.055 mol n-butane, and 0.132 mol water. The ratio of mol H₂O to mol dry gas is 0.162 mol H₂O/mol dry gas.
b) The required air feed rate is approximately 65.9 kmol/h. If the combustion were only 65% complete, the required air feed rate would increase to approximately 101.4 kmol/h.
a) To calculate the molar composition on a wet basis, we convert the weight percentages to mole fractions using the molar masses of propane, n-butane, and water. The molar composition is determined by dividing the weight percentage by the respective molar mass and normalizing the values to sum up to 1. The ratio of mol H₂O to mol dry gas is determined by dividing the mol water by the sum of mols of propane and n-butane.
b) To calculate the required air feed rate, we use the stoichiometry of the combustion reaction between butane and air. The balanced equation shows that 1 mol of butane reacts with 13.5 mol of air. Considering the 25% excess air requirement, we multiply the stoichiometric air requirement by 1.25. If the combustion is only 65% complete, the remaining butane requires additional air to achieve complete combustion. Therefore, the required air feed rate increases to account for the unreacted butane.
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