In a perfectly elastic collision, both momentum and kinetic energy are conserved. To solve this problem, we can apply the principles of conservation of momentum and kinetic energy.
Apologies for the incomplete response. Let's continue with the conservation equations to find the velocities of the pucks after the collision
Now, we can solve these equations simultaneously to find the velocities v1' and v2' after the collision.Now we can solve the equations simultaneously to find the velocities of the pucks after the collision.
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A car travels 3500 m in 200 seconds what is the car speed
Answer:
17.5 m/s
Explanation:
We can calculate the meters per second by dividing the distance by time. 3500 divided by 200 is 17.5, therefore the speed is 17.5 meters per second.
1) A 1,600 kilogram car is also traveling in a straight line. Its momentum is 32,500 kg*m/s. What is the
velocity of the car?
Answer:
v = 20.31 m/s
Explanation:
p = mv -> v = p/m = 32,500 kg*m/s / 1,600 kg = 20.31 m/s
Which of these objects are malleable? Check all that apply.
tin fork and knife from a camping set
antique ceramic vase
steel pole fence post
marble sculpture
glass tabletop
copper coin
Answer:
The tin fork and knife, the copper coin, and the steel fence pole.
Explanation:
Those are both what people would call soft metals so they are malleable to the extent of probably not needing heavy duty equipment. It depends on you description of malleable because the steel fence pole could be malleable with the correct equipment and not snap in half if bent slowly enough.
The definition of malleable: (of a metal or other material) able to be hammered or pressed permanently out of shape without breaking or cracking.
But the glass table, marble sculpture and antique ceramic vase are nowhere near malleable because if you tried bending them they wouldn't bend but would shatter and break into pieces.
The tin fork and knife, the copper coin, and the steel fence pole are malleable, the correct option is A, C, and F.
What are malleable objects?A malleable material is one that can be easily formed into a thin sheet by hammering. The most malleable metal is gold. In contrast, ductility is a solid material's ability to deform under tensile stress.
Metals are malleable because when a force is applied, layers of ions can slide over each other. Metallic bonding allows metal to change shape without breaking.
Gold, iron, aluminum, copper, silver, and lead are examples of malleable metals. Ductility and malleability do not always correlate; for example, gold is both ductile and malleable, whereas lead is only malleable.
Tin fork and knife, copper coin, and steel fence pole are all malleable.
Thus, the correct options are A, C, and F.
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A 18 kg box slides from rest down a ramp inclined at 25° to the horizontal onto a spring with a spring constant 740 N/m
as shown in the diagram. The spring is compressed 0.32 m before the box stops. Determine how far along the ramp the
box will slide before it stops. Assume friction is negligible.
The distance traveled by the box along the ramp is 0.51 m.
Distance traveled by the box
Apply the principle of conservation of energy;
Potential energy of the box at top of incline = Elastic potential energy at bottom
mgh = ¹/₂kx²
where;
h is the height of the incline m is mass of the boxx is the compression of the springk is spring constanth = L sinθ
where;
L is length of the incline = distance traveled by the boxmg(L sinθ) = ¹/₂kx²
(18)(9.8)(L sin25) = ¹/₂(740)(0.32)²
74.55 L = 37.89
L = 37.89 / 74.55
L = 0.51 m
Thus, the distance traveled by the box along the ramp is 0.51 m.
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THIS IS THE EXPERIMENT:
The students, working in pairs, will obtain ten sealed vials. DO NOT OPEN THE VIALS! Having the vials preloaded saves chemicals, time, and minimizes the possibility of exposure. These vials are labeled with their contents. Nine of the vials will contain knowns, while the last vial will be an unknown. This unknown will be one of the previous nine. Zero the analytical balance, then place the magnet on the balance and record its apparent mass; the magnet can be found next to the balance. The term apparent mass is used since there will be some interaction between the magnet and the balance altering the measurement. Record this value in the data sheet. Elevate the vial containing the sample approximately 0.5 cm above the magnet. Do not allow the vial to touch the balance or the magnet for this will alter the reading. Record the newly displayed mass in the data sheet. If the apparent mass has decreased in the presence of the sample, then the sample is attracting 4 the magnet, and the sample is paramagnetic. If the apparent mass has increased in the presence of the sample then the sample is being repelled by the magnet; consequentially the magnet is also being repelled, and the sample is diamagnetic. Perform two measurements then return to your lab bench and calculate the number of unpaired electrons for those two samples based on the oxidation numbers of the elements. Repeat until all samples have been measured.
THIS IS THE QUESTION:
This same experiment is performed on the international space station. What is the primary issue with performing this experiment in the absence of gravity? Design an experiment to compensate for this. As always, you do have duct tape
The primary issue with performing this experiment in the absence of gravity on the International Space Station (ISS) is the lack of a consistent downward force or orientation. In the original experiment on Earth, the vial containing the sample was elevated above the magnet, ensuring that the sample did not touch the balance or the magnet. However, in microgravity conditions, there is no fixed "up" or "down" direction, and objects can freely float and move in any direction.
To compensate for the absence of gravity, the experiment can be modified as follows:
Secure the vial and the magnet: Instead of relying on gravity to keep the vial and magnet in place, they should be secured using a suitable mechanism. This can be achieved by attaching them to a stable apparatus or using clamps that can hold them in position.
Controlling the distance between the vial and the magnet: Instead of elevating the vial above the magnet, a fixed and controlled distance should be maintained between the vial and the magnet. This can be achieved by using a mechanical setup or a device with adjustable arms to keep the vial at a consistent height.
Measuring the magnetic interaction: Rather than relying on the apparent mass change on the balance, a different method should be employed to measure the magnetic interaction between the sample and the magnet. One approach could be using a magnetic field sensor or a Hall effect sensor to directly measure the magnetic field strength or changes in the magnetic field caused by the sample.
Data analysis and interpretation: The recorded measurements and data should be analyzed differently since the concept of apparent mass may not be applicable in microgravity. The focus should be on quantifying the strength of the magnetic interaction between the sample and the magnet using the measured magnetic field values or changes.
By implementing these modifications, the experiment can be adapted to account for the absence of gravity on the International Space Station, allowing for accurate measurements and analysis of the magnetic properties of the samples. And yes, if needed, duct tape can be used to secure the apparatus in place in the microgravity environment.
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roseeldavis
2 hours ago
Physics
High School
answered
Please help me with this question soon.
Block A - 19.3 Kg/L
Block B - 0.64 Kg/L
Block C - 0.70 Kg/L
Block D - 0.917 Kg/L
Block E - 3.53 Kg/L
1) Which block has the greatest density?
Block A
Block B
Block C
Block D
Block E
2) Which block has the lowest density?
Block A
Block B
Block C
Block D
Block E
3) Submit your data table and identify the substance each block is made of.
Answer: Block A - 19.3
Block B - 0.64
Block C - 0.70
Block D - 0.917
Block E - 3.53
Explanation: i hope this helps you a little
Work and power are different because
work involves force and distance while power involves force and velocity
work involves distance and mass while power involves distance and time
work involves energy and time while power involves force and mass
work involves velocity and time while power involves energy and force
NO LINKS OR YOU WILL REPORTED THAT NO BITLY
A) Work involves force and distance while power involves force and velocity
Hope this helps
Exercise 2.4.9: When attached to a spring, a 2 kg mass stretches the spring by 0.49 m. a) What is the spring constant of this spring? Use 9.8 m/s2 as the gravity constant. b) This mass is allowed to come to rest, lifted up by 0.4m and then released. If there is no damping, set up and solve an initial value problem for the position of the mass as a function of time. c) For a next experiment, you attach a dampener of coefficient 16 Ns/m to the system, and give the same initial condition. Set up and solve an initial value problem for the position of the mass. What type of "dampening" would be used to characterize this situation?
The spring constant is calculated by dividing the force required to stretch or compress a spring by the lengthening or shortening of the spring.
Thus, It is used to identify whether a spring is stable or unstable, and consequently, what system it should be employed in.
It is stated mathematically as k = - F/x, which reworks Hooke's Law. Where x is the displacement caused by the spring in N/m, F is the force applied over x, and k is the spring constant.
Only in the range where the force and displacement are proportionate does Hooke's law adequately explain the linear elastic deformation of materials. Whatever the mass, a spring's elasticity will revert to its initial shape once the external force is eliminated. A characteristic is the spring constant.
Thus, The spring constant is calculated by dividing the force required to stretch or compress a spring by the lengthening or shortening of the spring.
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During take off, a plane leaves the ground and
travels in a straight line until it reaches a
height of 10 km. The distance the plane flies
during take off should be in the range 57 km
to 62 km.
What is the smallest possible angle that the
path of the plane could make with the ground?
Give your answer in degrees to 1 d.p.
Not drawn accurately
Explanation:
please mark as brainliest answer
The smallest possible angle that the path of the plane could make with the ground is 18.9 degrees.
We are given that the plane travels a distance of 57 km to 62 km during take off, and that it reaches a height of 10 km. We want to find the smallest possible angle that the path of the plane could make with the ground.
The smallest possible angle will occur when the plane travels the maximum distance of 62 km..
To calculate the angle, we can use the following formula:
sin(theta) = opposite / hypotenuse
sin(theta) = 10 / 62
theta = sin⁻¹(10/62) = 18.9 degrees
As a result, the least conceivable angle that the plane's path might create with the ground is 18.9 degrees.
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In your own words explain why the thickness and length of a wire could effect the flow of electrons
Answer:
(you can use my exact words) The length and thickness would make it so that the electrons move differently than they would a shorter and thinner wire because with the wire being longer the electrons would have a longer trip and with the wire being thicker the electrons would be more spread out and move be able to move more freely
what is the work requird to lift a 215 kg mass a distance of 5.65 m using a machine that is 72.5% efficient?
The maximum work required by the machine is 16420 J.
What is work?Work is energy transferred to or from an object via the application of the force along with the displacement. Work is the standard mechanical quantity. In its simple form, for a constant force aligned with it direction of motions the work equals the product of the forced by the strength and to the distance traveled.
Here mass M is 215 kg
And the height lifted H is 5.65
The energy or workdone needed to lift is W= MgH = 215(9.8)(5.65)= 11904.5 J
The minimum efficiency of to the machine is 72.5 %
So we can write that
The workdone by machine is
11904.5(100/72.5) = 16420 J ( approx)
So the workdone by machine is 16420 J
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at a track and field meet, the best long jump is measured as 8.20 m. the jumper took off at an angle of 39.0 to the horizontal. what was the initial speed of the jumper
The initial speed of the jumper can be calculated using the formula for horizontal velocity, Vx = V0 × cos(θ), where θ is the angle of take-off and V0 is the initial speed. The initial speed of the jumper was approximately 9.988 m/s.
What is initial speed?When you hear the term initial velocity, your first thought is that it refers to the speed at which an object was traveling when it initially started moving. Normally, we make this error, but in truth, what matters is the object's velocity at a certain point in time (which can be assumed) before it was affected by acceleration after that point in time.
When gravity first exerts a force on an object, its initial velocity defines how quickly the object moves. The final velocity, on the other hand, is a vector number that gauges a moving body's speed and direction after it has reached its maximum acceleration.
v = u + at
s = ut + 1/2 a
= 2as
Given that the angle of take-off is 39.0 degrees, we can use the following calculation:
Vx = V0 × cos(39)
V0 = Vx / cos(39) = 8.20 / cos(39)
cos(39) is approximately 0.825. Therefore:
V0 = 8.20 / 0.825 = 9.988 m/s
So, the initial speed of the jumper was approximately 9.988 m/s.
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A soccer player kicks a ball, applying a force of 1,000 newtons over a distance of 0. 2 meter. The ball travels 50 meters down the field before another player stops the ball. How much work was done during the kick?.
The ability for a muscle to work against a resistance for an extended period of time is.
Muscular Endurance refers to the ability for a muscle to work against a resistance for an extended period of time
Endurance :-
Perseverance is connected with the capacity to perform work over a drawn out timeframe. Youngsters, for instance, can play effectively for hours. Endurance can be impacted by a singular muscle, a muscle bunch, or the complete body. Muscle perseverance mirrors the capacity to support rehashed muscle compression and is connected with muscle strength.
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When you pedal really fast on a bike, you can feel the wind slowing you down.
Which force causes this?
O
A. Strong nuclear force
B. Magnetic force
O
OD. Gravity
C. Air resistance
Answer:
the answer is the option C
Which of the following is qualitative information?A.20 degreesB.15 gramsC.25 secondsD.Blue sky
From the given list, let's determine the given qualitative information.
Qualitative data can be said to be data that are represented without determining a value.
This type of data are uncountable.
It is data that can be observable in nature and they cannot be measured.
From the given list, the qualitative data is blue sky.
Other information given are that of quantitative data because they are measured values.
Therefore, the qualitative information is blue sky.
ANSWER:
D. Blue sky
There are 2 rocks sitting on 2 cliffs. One rock is sitting on a cliff that is 25 m high. The
other rock is sitting on a cliff that is 12 m high. Which rock has the greater gravitational
potential energy?
Explain.
The rock sitting on the cliff that is 25 m high has the gratest gravitational potential energy.
How do I determine the rock that has a greater potential energy?Potential energy is defined as the energy of an object by virtue of it's location. Mathematically, it is written as:
PE = mgh
Where
PE is the potential energym is the mass g is the acceleration due to gravityh is the heightTo determine the rock with the grater potential energy, we shall determine the potential energy of both rock assuming they have the same mass. Details below:
For rock sitting at 25 m high:
Mass (m) = 10 KgHeight (h) = 25 mAcceleration due to gravity (g) = 9.8 m/s² Potential energy (PE) = ?PE = mgh
PE = 10 × 9.8 × 25
PE = 2450 J
For rock sitting at 12 m high:
Mass (m) = 10 KgHeight (h) = 12 mAcceleration due to gravity (g) = 9.8 m/s² Potential energy (PE) = ?PE = mgh
PE = 10 × 9.8 × 12
PE = 1176 J
From the above calculation, we have:
Potential energy of rock at 25 m high = 2450 JPotential energy of rock at 12 m high = 1176 JThus, we can conclude that the rock sitting at 25 m high, has the gratest potential energy.
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A 5 Kg mass has an initial speed of 5m/s. After 3 sec, it has come to a speed of 70 m/s.
a. What is the acceleration of the mass?
b. What net force is acting on the mass during those 3 seconds?
Answer:
a
\(a = 21.7 \ m/s^2\)
b
\(F = 108.5 \ N\)
Explanation:
From the question we told that
The mass is m = 5 kg
The initial speed \(u = 5 m/s\)
The time taken to attain \(v = 70 \ m/s\) is t = 3 s
Generally from kinematic equation we have that
\(v = u + at\)
=> \(70 = 5 + a * 3\)
=> \(a = 21.7 \ m/s^2\)
Generally the force acting is mathematically represented
\(F = m * a\)
=> \(F = 5 * 21.7\)
=> \(F = 108.5 \ N\)
A ball is thrown upward with an initial velocity of 22.0 m/s. If
the gravitational acceleration is –9.81 meters per second
squared, what is the maximum height the ball will reach?
Select one:
2.24 m.
24.7 m.
4.48 m.
49.4 m.
The maximum height reached by the ball during the upward motion is 24.7 m.
The given parameters;
initial velocity of the ball, u = 22 m/sThe maximum height reached by the ball is determined using the third kinematic equation as shown below;
v² = u² - 2gh
where;
v is the final velocity of the ball at the maximum height = 0h is the maximum height attained by the ball0 = u² - 2gh
2gh = u²
\(h = \frac{u^2}{2g} \\\\h = \frac{22^2}{2(9.8)} \\\\h = 24.7 \ m\)
Thus, the maximum height reached by the ball during the upward motion is 24.7 m.
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A spring with a constant K is pulled back a distance X and allowed to oscillate with a period T on a horizontal frictionless surface. As the mass passes through the equilibrium positions the force of the spring is
As the mass passes through the equilibrium positions the force of the spring is increasing.
Simple harmonic motion is a specific kind of periodic motion of a body that arises from a dynamic equilibrium between an inertial force that is proportional to the body's acceleration away from the static equilibrium position and a restoring force on the moving object that is directly proportional to the magnitude of the object's displacement and acts towards the object's equilibrium position. Oscillating spring perform SHM.
as the mass passes through the equilibrium position, at the equilibrium position the force is zero and it increases with increase in displacement x according to the relation F = kx.
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what is mass measured in; what is weight measured in; is mass measured in newtons; what is the difference between mass and weight with examples; what are the five differences between mass and weight; is mass measured in newtons or kg; how are mass and weight related; measured in kilograms mass or weight
Mass is measured in kilograms (kg), while weight is measured in newtons (N). Mass and weight are distinct concepts, with mass representing the amount of matter in an object, while weight is the force exerted on an object due to gravity. The two are related through the gravitational acceleration and can be calculated using the equation weight = mass × gravitational acceleration.
Mass is a fundamental property of matter and is measured in kilograms (kg). It represents the amount of matter an object contains and remains constant regardless of its location in the universe. Mass can be thought of as the measure of inertia or resistance to changes in motion. For example, a 1 kg object will require a greater force to accelerate than a 0.5 kg object.
Weight, on the other hand, is the force exerted on an object due to gravity and is measured in newtons (N). The weight of an object depends on both its mass and the strength of the gravitational field it is in. Weight can vary depending on the location in the universe because gravitational acceleration differs on different celestial bodies. For instance, an object that weighs 9.8 N on Earth would weigh only about 1.6 N on the Moon.
Five key differences between mass and weight are:
1. Mass is a scalar quantity, while weight is a vector quantity with magnitude and direction.
2. Mass remains constant, while weight can change depending on the gravitational field.
3. Mass is measured in kilograms, while weight is measured in newtons.
4. Mass is an intrinsic property of an object, while weight depends on the gravitational force acting upon it.
5. Mass can be directly measured using a balance, while weight requires the use of a scale or a force meter.
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A student heated 25 mL of water from 10°C to 20°C.
4a. How much energy did she use to heat the water? Remember:
cal = m × ΔΤ.
Answer:
250 calories
Explanation:
To calculate the amount of energy used to heat the water, you need to know the mass of the water and the change in temperature.
Assuming that the water has a density of 1 gram/milliliter, we can calculate the mass of the water by multiplying the volume (25 mL) by the density (1 g/mL), which gives us a mass of 25 grams. The change in temperature, ΔΤ, is the difference between the final temperature and the initial temperature, which in this case is 20°C - 10°C = 10°C.
Now that we have the mass and the change in temperature, we can plug these values into the formula to calculate the amount of energy used to heat the water: cal = 25 g × 10°C = 250 cal.
Therefore, the student used 250 calories of energy to heat the water from 10°C to 20°C.
Un globo de helio se utiliza para elevar una carga de 110 N. El peso de la cubierta del globo
es de 50 N y su volumen cuando está totalmente hinchado es de 32 m3
. La temperatura del
aire es de 0 °C, y la presión atmosférica es de 1 atm. El globo se infla con el gas helio
suficiente para que la fuerza neta sobre él y su carga sea de 30 N. Despreciar los cambios de
temperatura con la altura.
A. Encuentre una expresión para la densidad de un gas ideal.
B. Usando la expresión anterior y la ecuación d
d
= −, encuentre una expresión para
la variación de la presión de la atmósfera considerando que toda la atmósfera tiene
una temperatura uniforme de 0 °C, y una masa molecular = 28,8×10-3
kg/mol.
C. Encuentre el volumen del globo a una presión de 1 atm capaz de levantar el globo
con la una fuerza de 30 N. (aire = 1,293 kg/m3 y He = 0,179 kg/m3
).
D. Encuentre el número de moles de helio que debe contener el globo para flotar con las
condiciones del inciso c).
E. Explique que debe de pasar con el globo al comenzar a subir, si la temperatura gas se
mantiene constante e igual a la temperatura de la atmósfera.
F. Encuentre la presión y la altitud en la que el globo se encuentra totalmente hinchado.
G. Explique que debe de pasar con la densidad de un gas ideal al disminuir la presión.
Es posible que el globo se detenga a alguna altura o simplemente se va a escapar de
la atmósfera
The net force acting on the helium balloon is 3603.2 N.
Calculate the weight of the load and the balloon cover:
Weight = Mass x Gravity
Weight of load = 110 N
Weight of balloon cover = 50 N
Calculate the buoyant force:
Buoyant force = Density x Gravity x Volume
Since helium is lighter than air, it will displace a volume of air equal to its own volume. Therefore, we can use the density of air instead of helium.
Buoyant force = 1.2 kg/m3 x 9.8 m/s2 x 32 m3 = 3763.2 N
Calculate the net force:
Net force = Buoyant force - Weight
Net force = 3763.2 N - 110 N - 50 N = 3603.2 N
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--The completely accurate question is , What is the net force acting on the helium balloon if it is used to lift a load of 110 N and the weight of the balloon cover is 50 N, and its volume when fully inflated is 32 m3? --
determine which part of the electromagnetic spectrum each of the following waves lies in. waves with a frequency f = 10.0 khz.
a. UV
b. Microwave
c. IR
d. X-ray
e. Visible
f. Radio
The waves with a frequency f = 10.0 kHz lie in the radio part of the electromagnetic spectrum.
The electromagnetic spectrum is the range of all types of electromagnetic radiation. It includes radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. The position of a wave on the spectrum is determined by its frequency and wavelength. The waves with a frequency f = 10.0 kHz have a wavelength of approximately 30,000 meters, which falls within the radio part of the spectrum.
Radio waves have the longest wavelengths and the lowest frequencies in the electromagnetic spectrum. They are used for broadcasting and communications, such as radio and TV signals. Therefore, the waves with a frequency f = 10.0 kHz belong to the radio part of the electromagnetic spectrum.
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in a series-fed hartley oscillator, if the frequency value-determining capacitance is increased, the oscillator frequency will
In a series-fed Hartley oscillator, if the frequency value-determining capacitance is increased, the oscillator frequency will decrease.
1. A Hartley oscillator is a type of LC oscillator that uses an inductor and two capacitors to generate an oscillating signal at a specific frequency.
2. In a series-fed Hartley oscillator, the frequency of oscillation is primarily determined by the values of the inductor (L) and the capacitors (C1 and C2).
3. The frequency of oscillation can be calculated using the formula: f = 1 / (2π√(L(C1 || C2))), where f is the frequency, π is a mathematical constant, and "||" represents the parallel combination of capacitors.
4. When the frequency value-determining capacitance is increased, it means either C1 or C2 or both capacitors are being increased.
5. Increasing the capacitance in the oscillator circuit will decrease the resonant frequency because the capacitance has an inverse relationship with the frequency.
6. As the capacitance increases, the denominator in the frequency formula becomes larger, resulting in a smaller overall value for the frequency.
7. Therefore, if the frequency value-determining capacitance is increased in a series-fed Hartley oscillator, the oscillator frequency will decrease.
8. This change in frequency can be utilized in electronic circuits where a variable capacitance element can be employed to tune the oscillator to different frequencies.
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Which statement is the best interpretation of the ray diagram shown below?
A. A concave lens forming a larger, virtual image
B. A concave lens forming a larger, real image
C. A concave mirror forming a larger, virtual image
O D. A concave mirror forming a larger, real image
Answer:
a concave lens forms a smaller, real image. { a p e x :)) }
Explanation:
hey, friend! this is the answer, but make sure that, next time, you include the diagram to make it easier for us to help you, okay?
A concave lens forming a larger real or virtual image and Concave mirrors form both real and virtual images. therefore all statements are correct. Therefore these can be interpreted by using Ray diagram.
What is Ray diagram ?A ray diagram is a diagram that shows path taken by light in order to see a point on the image of an object. Ray diagram uses lines with arrows to show reflected and incident ray.
A concave lens is a lens that diverges a straight light beam from the source to a diminished, upright, virtual image. It can form both real and virtual images. concave lens has curve on both side. The lens having only one side plane and other is curved inside, the les is called as planoconcave lens.
Concave mirror can form both virtual and real image that depends on the distance between the mirror and object. We get virtual and magnified image When the object is placed very close to the mirror. when distance between the object and mirror is increased, image gets diminished and real.
Both concave lens and mirror form both real and virtual images that's depend on the distance.
Hence all statements are correct.
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The force of gravity acts to pull any two objects with mass together. The force that pulls the moon toward the Earth also pulls the Earth toward the moon.
Why doesn’t the Earth orbit the moon?
The earth does not orbit the moon because that is a difference in their masses.
Why the earth does not orbit the moonThe Earth and the Moon are both pulled towards each other by the force of gravity. However, the reason that the Earth orbits around the Moon, rather than the other way around, is due to the difference in their masses.
The mass of the Earth is much larger than the mass of the Moon, so it has a stronger gravitational force than the Moon. As a result, the Moon is pulled toward the Earth with a greater force than the Earth is pulled toward the Moon.
This difference in the gravitational force causes the Moon to move in a curved path around the Earth, while the Earth moves in a relatively straight path. This curved path of the Moon around the Earth is what we refer to as an orbit.
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A 0.57 kg rubber ball has a speed of 2.2 m/sat point A and kinetic energy 8.0 J at pointB. Finda) the ball’s kinetic energy at A.Answer in units of J.015 (part 2 of 3) 10.0 pointsb) the ball’s speed at B.Answer in units of m/s.016 (part 3 of 3) 10.0 pointsc) the total work done on the ball as it movesfrom A to B.Answer in units of J.
Given that the mass of the ball is m = 0.57 kg.
The speed of the ball is
\(v_A=2.2\text{ m/s}\)A) The kinetic energy at point A will be
\(\begin{gathered} K\mathrm{}E._A\text{ =}\frac{1}{2}m(v_A)^2 \\ =\frac{1}{2}\times0.57\times(2.2)^2 \\ =1.38\text{ J} \end{gathered}\)B) Given that the kinetic energy,
\(K\mathrm{}E._B=\text{ 8 J}\)The ball's speed at point B will be
\(\begin{gathered} K\mathrm{}E._B=\frac{1}{2}m(v_B)^2 \\ v_B=\sqrt[]{\frac{2K.E._B}{m}} \\ =\sqrt[]{\frac{2\times8}{0.57}} \\ =5.298\text{ m/s} \end{gathered}\)C) The total work done on the ball to move from point A to B is
\(\begin{gathered} W=K\mathrm{}E._B-K.E._A \\ =8-1.38\text{ } \\ =6.62\text{ J} \end{gathered}\)how is the internal energy of the particles in the brake pads affected by the increase in temperature?
Answer:
increasedExplanation:As the temperature is increased the more the energy store
Study the vector diagram.
What is the magnitude of vector K?
8 m
16 m
60 m
136 m
Answer:
k= 8 m
Explanation:
L²=K²+J²
(10)²=K²+(6)²
100= K²+ 36
K²= 100-36
K²= 64
K=8 m
Answer:
8
Explanation: