Answer:
oh that's hard lol just go to the lowest number and times it on a piece of paper
The vertices of a square are located at (0,2)(2,0)(0,-2) and (-2,0) select all transformations that will carry this square onto itself
A. Reflection across the line y= x
B. Reflection of costs the line Y = -x
C. Reflection across the X axis
D. 45° rotation about the origin
E. 90° rotation about the origin
Given that, for all values of x,
2x^2 – 3x + 21 = a(x - b)^2 + c
find the value of a, the value of b and the value of c.
Step-by-step explanation:
To find a, the leading coeffiecent of the quadratic is a.
So a is 2.
To find b, we must use the formula
\( - \frac{b}{2a} \)
\( \frac{ - ( - 3)}{2(2)} = \frac{3}{4} \)
So b=3/4.
To find c, plug in 3/4 into the function,
which we get
\(2( \frac{9}{16} ) - 3( \frac{3}{4} ) + 21\)
\( \frac{9}{8} - \frac{9}{4} + 21 = \frac{9}{8} - \frac{18}{8} + 21 = - \frac{9}{8} + 21 = 19.875\)
So c=19.875
Given f (x) = 1/2 * x - 5 find f ^ -1 * (x)
Answer: d i think im pretty sure
Step-by-step explanation:
If f (7) = 22, then
f(f-1(22)) = [?]
Answer: 22
Step-by-step explanation:
\(f(f^{-1}(x))=f^{-1}(f(x))=x\)
What is the measure of the angle at the tail end of the kite?
Answer:
58°
Step-by-step explanation:
measure of the angle at the tail end of the kite
= 360° - (122° + 90° + 90°)
= 360° - 302°
= 58°
What is 9 divided 2.43
Pls help I need it now
Answer:
C
Step-by-step explanation:
Help help help help pleaE
What is the area of a circle (added a screen shot)
Answer:
2pi(5) - 2pi(3)
Step-by-step explanation:
hopefully that helped. just use formula and plug in the radius (:
Answer:
28.26 cm ^2
Step-by-step explanation:
A= \(\pi\) r ^2
A= 3.14 x 3 x 3
A = 28.26 cm ^2
What is the length of PO
These are similar triangles, therefore their sides are proportional.
36 / 24 = PO / 36
24PO = 1296
PO = 54
Hope this helps!
1. Find a markdown of 1/9 on $450?
2. 15 is what percent of 60?
3. 124% of 10 represents a certain number. What is that number?
Step-by-step explanation:
1. 1/9 of 450
of is multiply
1/9 × 450
= ???
2. 15/60 = decimal number
change number to percentage = ???
I dont know what 3 is
put answers to 1 and 2 in comments i will mark if u don't understand comment
please mark brainiest
Order them from least to great
Answer:
-21/2 <-5/2 < - 2 < - 1.75 <-1 <1.75 <9/4
Levin Furniture buys a living room set with a $\$ 5.000$ list price and a $55 \%$ trade discount. Freight (FOB shipping point) of $\$ 50$ is not part of the list price. What is the delivered price (including freight) of the living room set, assuming a cash discount of $4 / 10$, n/30, ROG? The invoice had an April 8 date. Levin received the goods on April 19 and paid the invoice on April $25 .$
Delivered price
Answer:
I did not understand
Step-by-step explanation:
Why is the question like that
What do I do?
Brief Calculus Question: Find Each limit (if it exist)
For the given function the value of limits are
\(\lim _{x\to 0^-}\left(f\left(x\right)\right)\) is 5
\(\lim _{x\to 0^+}\left(f\left(x\right)\right)\) is 0
\(\lim _{x\to 0}\left x^2+5\)is 5
The given function is f(x)= x²+5, when x≤0
f(x)=2x when x>0
\(\lim _{x\to 0^-}\left(f\left(x\right)\right)\)
Which is \(\lim _{x\to 0^-}\left x^2+5\)
The given limit is a left hand limit as there is minus in the limits
When we apply x as 0 we get the value 5
Now \(\lim _{x\to 0^+}\left(f\left(x\right)\right)\)
So \(\lim _{x\to 0^+}\left 2x\)
The given limit is a right hand limit as there is positive in the limits
When we apply x as 0 we get 0
Now \(\lim _{x\to 0}\left(f\left(x\right)\right)\)
Which is \(\lim _{x\to 0}\left x^2+5\)
We get 5
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ANSWER ASAPPPP PLS
Complete the table below to solve the equation 2.5x − 10.5 = 64(0.5x).
x f(x) = 2.5x − 10.5 g(x) = 64(0.5x)
2
3
4
5
6
Answer:
I'm going to help you figure this out because I am actually on the same assignment. If you do not understand what it is asking, it is not asking you to break down the function notation, it is simply asking you to substitute (X) with 2,3,4,5,and 6 and then to solve it on each line
Write the expression using exponents.
−(4b)(4b)(4b)
The expression −(4b)(4b)(4b) using positive exponents is -(4b)³
How to rewrite the expression using exponentsFrom the question, we have the following parameters that can be used in our computation:
−(4b)(4b)(4b)
Express properly
So, we have
−(4b) * (4b) * (4b)
5⁻¹² * 32⁻³ * 9⁻¹⁵
By using the definition of positive exponents, we have
−(4b) * (4b) * (4b) = -(4b)³
So, the solution is -(4b)³
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A plane flying with a constant speed of 360 km/h passes over a ground radar station at an altitude of 1 km and climbs at an angle of 30°. At what rate (in km/h) is the distance from the plane to the radar station increasing a minute later? (Round your answer to the nearest whole number.)
The rate (in km/h) at which the distance from the plane to the radar station is increasing a minute later is 0 km/h (rounded to the nearest whole number).
To solve this problem, we can use the concepts of trigonometry and related rates.
Let's denote the distance from the plane to the radar station as D(t), where t represents time. We want to find the rate at which D is changing with respect to time (dD/dt) one minute later.
Given:
The plane is flying with a constant speed of 360 km/h.
The plane passes over the radar station at an altitude of 1 km.
The plane is climbing at an angle of 30°.
We can visualize the situation as a right triangle, with the ground radar station at one vertex, the plane at another vertex, and the distance between them (D) as the hypotenuse. The altitude of the plane forms a vertical side, and the horizontal distance between the plane and the radar station forms the other side.
We can use the trigonometric relationship of sine to relate the altitude, angle, and hypotenuse:
sin(30°) = 1/D.
To find dD/dt, we can differentiate both sides of this equation with respect to time:
cos(30°) * d(30°)/dt = -1/D^2 * dD/dt.
Since the plane is flying with a constant speed, the rate of change of the angle (d(30°)/dt) is zero. Thus, the equation simplifies to:
cos(30°) * 0 = -1/D^2 * dD/dt.
We can substitute the known values:
cos(30°) = √3/2,
D = 1 km.
Therefore, we have:
√3/2 * 0 = -1/(1^2) * dD/dt.
Simplifying further:
0 = -1 * dD/dt.
This implies that the rate at which the distance from the plane to the radar station is changing is zero. In other words, the distance remains constant.
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Suppose that in an election for governor of Oregon there are five candidates of whom two are women. A statistics student reasons as follows: the probability that a woman will win the election is equal to 2/5. What is wrong with this reasoning?
Answer:
If in an Oregon state gubernatorial election, 2 of the 5 candidates are women, and a statistics student establishes that there is a 2/5 chance that the person elected for governor is a woman, this reasoning will be wrong.
This will be the case because not all candidates have the same amount of votes, that is, not all start with the same conditions: thus, there are more popular candidates than others, who will have greater probabilities of being elected as governors, regardless of their sexual identity.
What are the new coordinates if the figure were rotated 90 degrees counterclockwise
Answer:
third option
Step-by-step explanation:
under a counterclockwise rotation of 90° about the origin
a point (x, y ) → (y, - x )
Then
A (- 1, - 2 ) → (- 2, - (- 1) ) → (- 2, 1 )
B (2, - 2 ) → (- 2, - 2 )
C (1, - 4 ) → (- 4, - 1 )
The new coordinates are (d) A = (2, -1) B = (2, 2) and C = (4, 1)
How to determine the new coordinates rotating by 90 degrees counterclockwiseFrom the question, we have the following parameters that can be used in our computation:
The figure,
Where, we have
A = (-1, -2)
B = (2, -2)
C = (1, -4)
The rule of 90 degrees counterclockwise is
(x, y) = (-y, x)
Using the above as a guide, we have the following:
A = (2, -1)
B = (2, 2)
C = (4, 1)
Hence, the new coordinates are (d) A = (2, -1) B = (2, 2) and C = (4, 1)
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e the problem.
1) Scores on a test are approximately normally distributed with a mean of 70 and a standard deviation of 9. The
teacher wants to give A's to the top 10% of students, B's to the next 25%, and C's to the next 42%. What is the
bottom cutoff for a C grade? Round your answer to the nearest whole number..
A) 68
B) 63
C) 77
D) 65
z = -1.34 < (a - 70)/9
And if we solve for we got
a = 70 - 1.34 * 9 = 57.95 = 98
So, the value of height that separates the bottom 9% of data from the top 91% is 58.
And the answer for this case would be:
a) 58
What is the Normal distribution and Z-score?
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
The solution to the problem
Let X be the random variable that represents the scores of a population, and for this case we know the distribution for X is given by:
X ~ N (70, 9)
Where μ = 70, and σ = 9
For this case, the figure attached illustrates the situation for this case.
We know from the figure that the lower limit for D accumulates 9% or 0.09 of the area below and 0.91 or 91% of the area above.
we want to find a value a, such that we satisfy this condition:
P(X > a) = 0.91 (a)
P(X < a) = 0.09 (b)
Both conditions are equivalent in this case. We can use the z score again in order to find the value a.
As we can see in the figure attached the z value that satisfies the condition with 0.09 of the area on the left and 0.91 of the area on the right it's z=-1.34. On this case P(Z<-1.34)=0.09 and P(z>-1.34)=0.91
If we use condition (b) from the previous we have this:
P(X < a) = P(X - μ)/σ < (a - μ)/σ) = 0.09
P(z < (a - μ)/σ) = 0.09
But we know which value of z satisfies the previous equation so then we can do this:
z = -1.34 < (a - 70)/9
And if we solve for we got
a = 70 - 1.34 * 9 = 57.95 = 98
Hence, the value of height that separates the bottom 9% of data from the top 91% is 58.
And the answer for this case would be:
a) 58
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Which equation shows the variable terms isolated on one side and the constant terms isolated on the other side for the equation Negative one-half x + 3 = 4 minus one-fourth x? Negative one-fourth x = 1 Negative three-fourths x = 1 7 = one-fourth x 7 = three-fourths xWhich equation shows the variable terms isolated on one side and the constant terms isolated on the other side for the equation Negative one-half x + 3 = 4 minus one-fourth x? Negative one-fourth x = 1 Negative three-fourths x = 1 7 = one-fourth x 7 = three-fourths x
Answer:
A or Negative one-fourth x = 1
(-1/4x=1)
Step-by-step explanation:
I just took the test
Answer:
a
Step-by-step explanation:
There are 690 students in a school. 120 students are in the 8th Grade and 135 students are in the 7th Grade. What % of the students are in the rest of the classes?
Answer:7th
Step-by-step explanation:
A 10 pound bag cherries for $33.49 how many per pound
What is 25% of 8. ??????????????????
Answer:
2
Step-by-step explanation:
1/4 of 8 = 25%
25% = 1/4
8 / 4 = 2
can anyone help me ??? pleassee on both of em
Answer:
28. B
29. D
30. A
Step-by-step explanation:
28.
2 5/8 yd × 5/6 yd =
= 21/8 × 5/6 yd²
= 105/48 yd²
= 35/16 yd²
= 2 3/16 yd²
Answer: B
29.
2641 becomes 6241.
In 6241, the 6 is in the thousands place.
6 × 1000 = 6000
Answer: D
30.
90 + 7 × (7 - 1) =
Use the correct order of operations.
= 90 + 7 × 6
= 90 + 42
= 132
Answer: A
Airline travelers should be ready to be more flexible as airlines once again cancel thousands of flights this summer. The Coalition for Airline Passengers Rights, Health, and Safety averages 400 calls a day to help stranded travelers deal with airlines (seattlepi.com, July 10, 2008). Suppose the hotline is staffed for 16 hours a day. a. Calculate the average number of calls in a one-hour interval; 30-minute interval; 15-minute interval. (Round your answers to 2 decimal places.) Interval Average Number of Calls 60-minute 30-minute 15-minute b. What is the probability of exactly 6 calls in a 15-minute interval? (Round your intermediate calculations and final answer to 4 decimal places.) Probability c. What is the probability of no calls in a 15-minute interval? (Round your intermediate calculations and final answer to 4 decimal places.) Probability d. What is the probability of at least two calls in a 15-minute interval? (Round your intermediate calculations and final answer to 4 decimal places.) Probability
The Coalition for Airline Passengers Rights, Health, and Safety averages 400 calls a day to help stranded travelers deal with airlines. The hotline is staffed for 16 hours a day.
To calculate the average number of calls in different time intervals and the probability of different events related to these calls.
Part 1:
a. 60-minute interval average number of calls: 400/16 = 25 calls
30-minute interval average number of calls: 25/2 = 12.5 calls
15-minute interval average number of calls: 12.5/2 = 6.25 calls
Part 2:
b. To find the probability of exactly 6 calls in a 15-minute interval, we can use the Poisson distribution formula. Let's assume that the average number of calls in a 15-minute interval is 6.25. Then, the probability of exactly 6 calls in a 15-minute interval is:
P(6 calls) = (e^-6.25)*(6.25^6)/6! = 0.0686
c. To find the probability of no calls in a 15-minute interval, we can use the Poisson distribution formula. Let's assume that the average number of calls in a 15-minute interval is 6.25. Then, the probability of no calls in a 15-minute interval is:
P(0 calls) = e^-6.25 = 0.0047
d. To find the probability of at least two calls in a 15-minute interval, we can use the cumulative distribution function of the Poisson distribution. Let's assume that the average number of calls in a 15-minute interval is 6.25. Then, the probability of at least two calls in a 15-minute interval is:
P(X >= 2) = 1 - P(0 calls) - P(1 call) = 1 - 0.0047 - (e^-6.25)*(6.25^1)/1! = 0.9906
Thus, the average number of calls in a 60-minute interval is 25, in a 30-minute interval is 12.5, and in a 15-minute interval is 6.25. The probability of exactly 6 calls in a 15-minute interval is 0.0686, the probability of no calls in a 15-minute interval is 0.0047, and the probability of at least two calls in a 15-minute interval is 0.9906.
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Which equation could be used to solve the question below?
Kitty made b cups of dough. She divided the dough into 3 equal clumps. Each of the dough clumps doubled in size. Now, each clump is made of 6 cups of dough. How many cups of dough did Kitty originally make?
A.
b × 6 ÷ 2 = 6
B.
b × 3 × 2 = 6
C.
b ÷ 3 ÷ 2 = 6
D.
b ÷ 3 × 2 =6
please help whoever is right i will mark brainliest
I’m struggling someone please help me!!
Answer:
A one real root
Step-by-step explanation:
if not I'm sorry if I get it wrong
Simply this expression 2(10) + 2(x-4)
Answer:
I think the answer is 18 hope it helps
Step-by-step explanation:
A polling agency is investigating the voter support for a ballot measure in an upcoming city election. The agency will select a random sample of 500 voters from one region, Region A, of the city. Assume that the population proportion of voters who would support the ballot measure in Region A is 0.47. What is the probability that the proportion of voters in the sample of Region A who support the ballot measure is greater than 0.50
Answer:
The value is \(P( X > 0.50) = 0.089264\)
Step-by-step explanation:
From the question we are told that
The sample size is n = 500
The population proportion is p = 0.47
Generally given that the sample size is sufficiently large , the mean of this sampling distribution is mathematically represented as
\(\mu_x = p = 0.47\)
Generally the standard deviation of the sampling distribution is mathematically represented as
\(\sigma = \sqrt{\frac{p(1- p )}{ n} }\)
=> \(\sigma = \sqrt{\frac{ 0.47 (1-0.47 )}{ 500 } }\)
=> \(\sigma = 0.0223\)
Gnerally the probability that the proportion of voters in the sample of Region A who support the ballot measure is greater than 0.50 is mathematically represented as
\(P( X > 0.50) = P( \frac{ X - \mu }{ \sigma } > \frac{ 0.50 - 0.47 }{ 0.0223 } )\)
\(\frac{X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ X )\)
=> \(P( X > 0.50) = P( Z> 1.3453 )\)
From the z table the area under the normal curve to the left corresponding to 1.3453 is
\(P( Z> 1.3453 ) = 0.089264\)
So
\(P( X > 0.50) = 0.089264\)
Using the normal distribution and the central limit theorem, it is found that there is a 0.0901 = 9.01% probability that the proportion of voters in the sample of Region A who support the ballot measure is greater than 0.50.
In a normal distribution with mean \(\mu\) and standard deviation \(\sigma\), the z-score of a measure X is given by:
\(Z = \frac{X - \mu}{\sigma}\)
It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
By the Central Limit Theorem, the sampling distribution of sample proportions of size n of a proportion p has \(\mu = p, s = \sqrt{\frac{p(1-p)}{n}}\)
In this problem:
Sample of 500 voters, hence \(n = 500\).The proportion is of 0.47, hence \(p = 0.47\)The mean and the standard deviation are:
\(\mu = p = 0.47\)
\(\sigma = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.47(0.53)}{500}} = 0.0223\)
The probability that the proportion of voters in the sample of Region A who support the ballot measure is greater than 0.50 is 1 subtracted by the p-value of Z when X = 0.5, hence:
\(Z = \frac{X - \mu}{\sigma}\)
By the Central Limit Theorem
\(Z = \frac{X - \mu}{s}\)
\(Z = \frac{0.5 - 0.47}{0.0223}\)
\(Z = 1.34\)
\(Z = 1.34\) has a p-value of 0.9099.
1 - 0.9099 = 0.0901
0.0901 = 9.01% probability that the proportion of voters in the sample of Region A who support the ballot measure is greater than 0.50.
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